(6x - 6.3) divided by 3

The measure of segments mAG, mAC, and mBC are 11.4, 16.1 and 7.1 respectively,

The triangle is a geometric shape that includes 3 sides and the sum of the interior angle should not be greater than 180°

Here,
Apply Pythagoras theorem in triangle ABG,

mAG = √[7² + 9²]
mAG = √[49 + 81]
mAG = √[130] = 11.4
Apply Pythagoras theorem in triangle BGC,
mBC = √[10² - 7²]
mBC = √51
mBC = 7.1

Now

mAC = mAB  + mBC
mAC = 9 + 7.1
mAC = 16.1

Thus, the segments mAG, mAC, and mBC have measures of 11.4, 11.1, and 7.1, respectively.

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The magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = −1.0 nC is at (0, 0.10 m), and charge Q3 = 5.0 nC is at (0, 0) is 6.21 N.

The value of the net electrostatic force on the 5.0-nC

charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0),

charge Q2 = −1.0 nC is at (0, 0.10 m), and

charge Q3 = 5.0 nC is at (0, 0) can be calculated as follows:

Given data,Charge Q1 = 6.0 nC is at (0.30 m, 0),

Charge Q2 = -1.0 nC is at (0, 0.10 m),

Charge Q3 = 5.0 nC is at (0, 0)

The formula to find out the force on the third charge Q3 is:

                      F = k * |Q1 * Q3| / r1^2 + k * |Q2 * Q3| / r2^2

Here, k = 8.99 × 10^9 N·m^2/C^2, Q1 = 6.0 nC, Q2 = -1.0 nC, Q3 = 5.0 nC

For the third charge Q3, the distance from Q1 is:

                                r1 = √(0.3^2 + 0^2) = 0.3 m

And the distance from Q2 is: r2 = √(0^2 + 0.1^2) = 0.1 m

Substituting all the given values in the formula:

                               F = 8.99 × 10^9 * [ (6.0 × 10^-9 * 5.0 × 10^-9) / 0.3^2 ] + 8.99 × 10^9 * [ (-1.0 × 10^-9 * 5.0 × 10^-9) / 0.1^2 ]F = 6.21 N

Therefore, the magnitude of the net electrostatic force on the 5.0−nC charge due to the other charges when the charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = −1.0 nC is at (0, 0.10 m), and charge Q3 = 5.0 nC is at (0, 0) is 6.21 N.

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The area of the sector is 128.26 square meters.

The area of a sector of a circle is given by the formula:

A = (θ/360) × π\(r^2\)

where A is the area of the sector, θ is the central angle of the sector in degrees, and r is the radius of the circle.

In this case, we are given that the radius of the circle is 14 m and the angle of the sector is 75 degrees. Therefore, we can use the formula above to find the area of the sector:

A = (75/360) × π\((14)^2\)

Simplifying and evaluating the expression, we get:

A = (5/24) × π(196)

A = (5/24) × 196 × π

A= 0.2083 × 196 × 3.1415

A ≈ 128.26 square meters

Therefore, the area of the sector of a circle with a radius of 14 m and an angle of 75 degrees is approximately 128.26 square meters.

The question was Incomplete, Find the full content below :

Find the area of the sector of a circle whose radius is 14 m and the angle of the sector is 75⁰

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The largest group of students that the study results represent is "all UCLA graduate student apartments in the three sampled buildings".

The number of graduate student apartments in the three sampled buildings can be represented mathematically as:

N = 25 * 3

Where N is the number of apartments sampled and 25 is the number of apartments randomly selected in each of the three buildings.

This expression represents the total number of apartments in the largest group that the study results represent, which is "all UCLA graduate student apartments in the three sampled buildings."

This is because the survey only included data from 25 apartments in each of the three randomly selected buildings. The results of the study cannot be generalized to represent all UCLA graduate student apartments or even all apartments in the group of seven buildings as the sample size is limited to only three buildings. The results only provide information about the energy efficiency of the apartments in the three sampled buildings.

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For the matrix the true statement is given by option d. Both A and B are false.

Let's analyze each statement of the matrix as follow,

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R⁵.

This statement is false.

The domain of the transformation T is not R⁵.

The domain of T is determined by the dimensionality of the vectors x that can be input into the transformation.

Here, the matrix A is a 3 times 5 matrix, which means the transformation T(x) = Ax can only accept vectors x that have 5 elements.

Therefore, the domain of T is R⁵, but rather a subspace of R⁵.

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto.

This statement is also false.

The transformation x → Ax can still be onto (surjective) even if A is a 3 times 2 matrix.

The surjectivity of a transformation depends on the rank of the matrix A and the dimensionality of the vector space it maps to.

It is possible for a 3 times 2 matrix to have a rank of 2,

and if the codomain is a vector space of dimension 3 or higher, then the transformation can be onto.

Therefore, as per the matrix both statements are false, the correct answer is d. Both A and B are false.

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The above question is incomplete, the complete question is:

Which of the following best characterizes the following statements:

A) If A is a 3 times 5 matrix and T is a transformation defined by T(x) = Ax, then the domain of T is R^5

B) If A is a 3 times 2 matrix, then the transformation x right arrow Ax cannot be onto

a. Only A is true

b. Only B is true

c. Both A and B are true

d. Both A and B are false

Answer:

What steps are used to solve this equation?

6f = 48

Complete each statement.

First,

✔ divide by 6

on both sides of the equation.

Next, simplify the equation to determine that the solution of the equation is

✔ f = 8

.

Check the solution by substituting

✔ 8

for f and simplifying.

Step-by-step explanation:

The solution of the given equation would be 8.

An equation is an expression that shows the relationship between two or more numbers and variables.

A mathematical equation is a statement with two equal sides and an equal sign in between.

A system of equations is two or more equations that can be solved to get a unique solution and the power of the equation must be in one degree.

We are given the equation as;

6f = 48

We have to Complete each statement.

First, divide by 6 into both sides of the equation.

f = 48/6

Next, simplify the equation to determine that the solution of the equation is

f = 8

Check the solution by substituting for f and simplifying.

6  x8 = 48

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The ordered pair that represents the solution to the system of equations is given as follows:

(-3,-0.5).

The equations of the system are given as follows:

The x-coordinate of the ordered pair representing the solution to the system of equations is given as follows:

0.5x + 1 = 1.5x + 4

-x = 3

x = -3.

The y-coordinate of the ordered pair representing the solution to the system of equations is given as follows:

y = 0.5(-3) + 1

y = -1.5 + 1

y = -0.5.

Meaning that the correct option is given by the first option.

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Answer:

19

Step-by-step explanation:

5*7 - 4*4

PEMDAS says multiply and divide first

35 - 16

Then add and subtract

19

Answer:

19 hope this helps ☜(⌒▽⌒)☞☜(ﾟヮﾟ☜)

Step-by-step explanation:

Answer:

\(\boxed{6}\times 10^{\boxed{26}}\)

Step-by-step explanation:

\((3 \times {10}^{9} ) \times (2 \times {10}^{17} ) \\ \\ = (3 \times 2) \times ( {10}^{9} \times {10}^{17}) \\ \\ = 6 \times {10}^{9 + 17} \\ \\ = \huge \boxed{ 6} \times {10}^{ \boxed{26}} \)

Answer:

11

Step-by-step explanation:

If you input the number and then solve, you should get that #=#

2(11)+9=4(11)-13

22+9=44-13

31=31

Answer: 11

Step-by-step explanation: 2(11)+9=4(11)-13, 22+9=44-13, 31=31

Answer:

24 cubic units

The sunfish adds around 2% to its present mass each day, which is the daily percent change in mass.

Based on the provided model, the daily percent change in the mass of the ocean sunfish is an addition of around 2% to its mass. By calculating the derivative of the function M(t) with respect to t, the following may be calculated:

\(M'(t) = \frac{ln(1.35)}6 * (1.35)^t\)

This indicates that the constant factor is ln(1.35)/6, or around 0.02, and therefore the rate of change of the sunfish's mass with respect to time is proportionate to the sunfish's present mass.

As a result, the sunfish's daily percent change in mass is around a 2% increase over its present mass.

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A substitute is a good or service that buyers can quickly swap out for another. For instance, a one-dollar bill can be used in place of another dollar bill.

In business and economics, a replacement, or substitutable good, is a good or service that consumers perceive as just being substantially the same as or reasonably similar to some other good. Consumers are given options and alternatives through substitutes, which also spur competition and lower prices in the market.

Here are a few examples of replacement goods:

1. A $1 bill can be exchanged for four quarters.

2. Coke against Pepsi

3. Regular vs. premium gas

4. Butter and lard

5. Tea and coffee

6. Apples and oranges

7. Comparing driving a car to riding a bike

8. Books in general and e-books

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Answer:

IT IS THE SECOND ONEE

1/m8

The division of the monomials gives \(\frac{4}{9}\) x¹²

Monomials are polynomials which includes mathematical expressions consisting of one term involving variables and coefficients.

Given are two monomials 4x⁷ and 6x.

Both are to the power of 2.

We have a rule of exponent that,

(p/q)ˣ = pˣ / qˣ

Applying the rule,

(\(\frac{4x^7}{6x}\))² = (4x⁷)² / (6x)²

        = 4²x¹⁴ / 6²x²

        = 16x¹⁴ / 36x²

Factorize the common terms and cancel it.

Firstly factorizing the coefficients with 4,

(\(\frac{4x^7}{6x}\))² = 4x¹⁴ / 9x²

Factorizing x² as the variable,

(\(\frac{4x^7}{6x}\))² = 4x¹² / 9

Hence the quotient is  \(\frac{4}{9}\)x¹² .

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A spool of thread measuring 8 3/4 inches long and 4 inches wide can be cut into 2 1/7 inch pieces.

In light of the conditions stated, come up with: \($\frac{8 \frac{3}{4}}{2 \frac{1}{7}}$\) To improper fractions, change the mixed numbers to: \($\frac{\frac{35}{4}}{\frac{15}{7}}$\) Multiply the reciprocal of a fraction to get its division: \($\frac{35}{4} \times \frac{7}{15}$\)

Mark this common element as a no-go: Multiplying \($\frac{7}{4} \times \frac{7}{3}$\) Mark the common element as absent: Multiplying \($\frac{7 \times 7}{4 \times 3}$\) . Put the following in one fraction : \($\frac{49}{12}$\) . The product or quotient should be

calculated.Find the biggest number that is greater than \($\frac{49}{12}$\) and less than or equal to it . A spool of thread measuring 8 3/4 inches long and 4 inches wide can be cut into 2 1/7 inch pieces.Otherwise, you or a device will need to count 127 turns (the irreducible repeat, independent of thread pitch), after which the half nut must be closed.

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32/8 simplified is 4. 36 divided by 4 is 9. so.. 9+7 is 16 times 14 is. 224. The answer is 224. :)

Answer:

32

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

In 2 hours they wash 8 cars total so...

8

16

24

The extra time is 15 mins for 2 cars

The dimensions of the field should be 125m by 100m to enclose the maximum area.

To solve this problem, we can use the fact that the area of a rectangle is given by A = lw, where l and w are the length and width of the rectangle, respectively. Since the field is to be subdivided into four congruent plots, we can express the width in terms of the length as w = (1/4)(l).

We can then use the fact that the total length of fencing available is 6000m to set up an equation for the perimeter of the rectangle, which is given by P = 2l + 5w. Substituting w with (1/4)(l), we get P = 2l + 5((1/4)(l)) = (9/2)l.

Solving for l in terms of P, we get l = (2/9)P. Substituting this expression for l into the equation for the area, we get A = (1/4)(l)(w) = (1/4)(l)((1/4)(l)) = (1/16)l^2.

We can now express the area in terms of P as A = (1/16)((2/9)P)^2 = (4/81)(P^2). To find the maximum area, we can take the derivative of A with respect to P and set it equal to zero, which gives dA/dP = (8/81)P = 0. This implies that P = 0 or P = 81/8. Since P cannot be zero, we have P = 81/8.

Substituting this value of P back into the equation for l, we get l = (2/9)(81/8) = 18.75. Finally, substituting l and w = (1/4)(l) into the equation for A, we get A = (1/16)(18.75)(4.6875) = 117.1875. Therefore, the dimensions of the field should be 125m by 100m to enclose the maximum area.

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The angular speed of the wheel is calculated as 52.36 radians per second

The revolution of this wheel is said to be at 500 in a minute

This is also called the frequency of this wheel.

This can be written as

500rev in 60 seconds. 500/60 = 8.333 per second

Angular speed is given as

pi = 22/7

f = 8.333

Formular for angular speed = ω = 2*pi*f

w = 2 * 22/7 * 8.333

= 52.36 radians per second

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Two of the solutions of the equation cos(x/2) = -(sqrt2/2) are 135 degrees and 225 degrees (or 3π/4 radians and 5π/4 radians).

Two of the solutions of the equation cos(x/2) = -(sqrt2/2) can be found by considering the unit circle and the properties of cosine.

Since the cosine function represents the x-coordinate of a point on the unit circle, we can look for the angles where the x-coordinate is -(sqrt2/2).

One such angle is 135 degrees (or 3π/4 radians), where the cosine is equal to -(sqrt2/2). At this angle, the x-coordinate of the corresponding point on the unit circle is -(sqrt2/2).

Another angle with the same x-coordinate is 225 degrees (or 5π/4 radians). At this angle, the cosine is also equal to -(sqrt2/2).

Two of the solutions of the equation cos(x/2) = -(sqrt2/2) are 135 degrees and 225 degrees (or 3π/4 radians and 5π/4 radians). These angles satisfy the given equation and have the desired x-coordinate on the unit circle.

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Answer:

15,90

Step-by-step explanation:

it goes by 6

(14 x 6=84) and so on and so forth

The global maximum and minimum values of the function f(x) = x³ − 3x² on the interval [−1, 3] are 0 and -8, respectively.

We need to find the global maximum and minimum values of the function f(x) = x³ − 3x² on the interval [−1, 3].

Here’s how to solve it:

To find the critical points of the function, we need to find f'(x).

Let's find f'(x) first.f(x) = x³ − 3x²f'(x) = 3x² - 6xNow, let's find the critical points by setting f'(x) = 0:3x² - 6x = 03x(x - 2) = 0x = 0, 2

These values represent the critical points on the interval [−1, 3].

Now, we need to check the function at the endpoints and critical points to determine the maximum and minimum values.

f(x) = x³ − 3x²f(-1) = (-1)³ − 3(-1)² = -2f(0) = (0)³ − 3(0)² = 0f(2) = (2)³ − 3(2)² = -8f(3) = (3)³ − 3(3)² = 0

So, we have four possible global maximum and minimum values:

Maximum values:0 and 0Minimum values:-8 and -2

The global maximum value is 0, and it occurs at x = 0 and x = 3.

The global minimum value is -8, and it occurs at x = 2.

Therefore, the global maximum and minimum values of the function f(x) = x³ − 3x² on the interval [−1, 3] are 0 and -8, respectively.

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Answer:

5a) 4

5b) 4

Step-by-step explanation:

You'll use Pythagorean theorem throughout this problem a lot. So, to find X, You have a right triangle with one leg of 6, and one leg of 2. 2 squared plus 6 squared equals c squared. 4 + 36 = c squared then you get 40 = c squared.

To get c by itself you'd square root both sides. So that leaves you with X = the square root of 40.

Now, to get Y, you have another triangle with a leg of 4, and another leg of the square root of 40. 4 squared = 16, and the square root of 40 squared is just 40. So, 16 + 40 = c squared. 56 = c squared, then again, to get the c value by itself you need to square root both sides, leaving you with Y = the square root of 56.

\(a(1) = 240 \\ a(2) = a(1) + d = 240 + 24 = 264 \\ a(3) = a(2) + d = 264 + 24 = 288 \\ a(4) = a(3) + d = 288 + 24 = 312 \\ a(5) = a(4) + d = 312 + 24 = 336 \\ a(6) = a(5) + d = 336 + 24 = 360\)

Therefore, the critical F-value for the given scenario is 3.96.

To find the critical F-value, we need to use the F-distribution table or a statistical software.

Given:

Sample size for the numerator (numerator degrees of freedom) = 16

Sample size for the denominator (denominator degrees of freedom) = 10

Two-tailed test

Significance level = 0.02

Using these values, we can consult the F-distribution table or a statistical software to find the critical F-value.

The critical F-value is the value at which the cumulative probability in the upper tail of the F-distribution equals 0.01 (half of the 0.02 significance level) since we have a two-tailed test.

Using the degrees of freedom values (16 and 10) and the significance level (0.01), the critical F-value is approximately 3.96 (rounded to 2 decimal places).

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Answer:

Greater

Step-by-step explanation:

Jody has created a systematic sampling error by forgetting to include a segment of the population that is relevant to the study.

Systematic sampling is a sampling method where every nth member of a population is selected to be part of the sample. In Jody's case, she forgot to include a specific segment of the population, which means that the sampling process was not systematic. This error can introduce bias and affect the representativeness of the sample.

No calculations are required for this type of error.

Jody's mistake in not including a relevant segment of the population has resulted in a systematic sampling error. To ensure the accuracy and validity of the study, it is important to rectify this error by including the missing segment or adjusting the sampling method accordingly.

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