700 J of heat is applied to 1 kg of an unknown solid and the temperature is observed to rise by 6 °C. Assuming equipartition holds, what is the molar mass of the solid? (a) 117 g/mol (b) 71.3 g/mol (C) 0.00857 g/mol (d) 9.95 g/mol (e) 214 g/mol

Answer:

Average speed = 53.33 km/h

Explanation:

Below is the calculation for the average speed:

Given the average speed of for first 40 km = 80km/h

Time taken to cover the first 40 km = Total Distance / average speed

Time taken to cover the first 40 km = 40 / 80 = 0.5 hours

Given the average speed of for next 40 km = 40km/h

Time taken to cover the next 40 km = Total Distance / average speed

Time taken to cover the next 40 km = 40 / 40 = 1 hours

Now the average speed of the tuck to cover total distance:

Average speed = Total distance / Total time

Average speed = (40 + 40) / (0.5 + 1)

Average speed = 53.33 km/h

Answer:

C) Power is the product of voltage and current.

Explanation:

A.pex, hope this helps:)

Answer:

The answer is C. Power is the product of voltage and current

Explanation:

I am currently taking the test right now. This is on A P E X for me.

One false statement about Einstein's General Theory of Relativity (GR) is that it explains the behavior of objects on a quantum level.

While GR provides a mathematical framework for understanding the interactions of gravity on a large scale, it does not account for the behavior of subatomic particles. Another false statement is that GR is incompatible with the theory of quantum mechanics. While the two theories have not yet been fully reconciled, there have been efforts to unify them in theories such as loop quantum gravity and string theory. Finally, it is false to say that GR applies only to objects in space. The theory applies to any object with mass, regardless of its location.
Among the following statements about Einstein's General Theory of Relativity (GR), the false one is that it predicts that time passes at the same rate everywhere in the universe. In reality, GR explains that gravity influences the passage of time, causing it to slow down near massive objects. This phenomenon is known as time dilation. The theory also encompasses the curvature of spacetime caused by mass, gravitational waves, and the expansion of the universe. It's essential to distinguish the false statement to better understand the true implications of GR on our perception of time and gravity.

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Answer:

The only time an object has NO kinetic energy is when the velocity is "Zero"

Explanation:

The object starts out with no kinetic energy and potential energy of PE = mgh where m is the mass.The kinetic energy is zero. As the object falls it loses potential energy and gains kinetic energy KE = mv2/2.

Hope I help you

(You should totally give me a Brainllest!)

It is possible that when an object is stationary and not moving, it has no kinetic energy.

Only when an item is entirely at rest does it have no kinetic energy. The energy an object possesses as a result of its motion is known as kinetic energy. It is based on the object's mass and velocity.

When an object is not moving and has no velocity, it also has no kinetic energy.

According to the kinetic energy formula,

KE = 1÷2 × mass × velocity², if the velocity is zero, the entire term involving velocity becomes zero, resulting in zero kinetic energy.

Thus, when an object is stationary and not moving, it has no kinetic energy.

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An ensemble forecast is considered robust when the following conditions are met:

1) The individual members of the ensemble produce similar forecasts.

This means that the different members of the ensemble are in agreement with each other in terms of the predicted weather pattern, temperature, or other relevant meteorological variables.

2) The ensemble mean is a good predictor of the actual outcome.

The ensemble mean is calculated by averaging the forecasts from all the members of the ensemble.

If the ensemble mean is close to the observed value, it suggests that the ensemble forecast is reliable.

4) The ensemble spread is not too large.

The ensemble spread is a measure of the variability of the different members of the ensemble.

If the spread is too large, it indicates that the model is uncertain about the forecast, and the confidence in the forecast is reduced.

However, if the spread is too small, it can indicate that the model is not capturing all the sources of uncertainty, and the forecast may be overly confident.

5) The ensemble has a good track record.

A model that has produced accurate forecasts in the past is more likely to produce reliable forecasts in the future.

Therefore, a robust ensemble forecast is one that has a proven track record of accuracy and reliability.

In summary, an ensemble forecast is considered robust when the individual members of the ensemble produce similar forecasts.

The ensemble mean is a good predictor of the actual outcome, the ensemble spread is not too large, and the ensemble has a good track record of accuracy and reliability.

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1. For an object (A) moving uniformly in the negative direction of the x-axis with a speed of 15 m/s and initial abscissa of 30 m, the time equation of its motion is X = 30 - 15*t, and its (V-1) graph is a straight line with a slope of -15 and a y-intercept of 30, and 2. When another particle (B) with a time equation of XB = 101-70 (S.1) moves on the same axis, (A) and (B) meet at time t = 2.13 s and position X = -32.7 m. The distance separating (A) and (B) at t = 8 s is 369 m.

1.a. The time equation of the motion of (A) is given by:

X = XoA + Vt

where X is the position of (A) at time t, XoA is the initial position of (A), V is the velocity of (A) and t is the time elapsed since the start of the motion.

Plugging in the given values, we get:

X = 30 - 15t

b. The (V-1) graph of (A) is a straight line with a slope of -15 (since the velocity is constant and negative) and a y-intercept of 30 (since the initial position is 30). The graph looks like this:( below)

2a. To determine the instant at which (A) and (B) meet, we need to find the time t at which their positions are equal. Equating the time equations of (A) and (B), we get:

30 - 15t = 101 - 70t

Solving for t, we get:

t = 2.13 s

To find the position at which they meet, we can plug this value of t into either of the time equations and get:

X = 101 - 70*2.13 = -32.7 m

So (A) and (B) meet at time t = 2.13 s and position X = -32.7 m.

b. To determine the distance separating (A) and (B) at t = 8 s, we need to find their positions at that time. Using the time equation of (A), we get:

Xa = 30 - 158 = -90 m

Using the time equation of (B), we get:

Xb = 101 - 708 = -459 m

The distance separating (A) and (B) at t = 8 s is:

|Xb - Xa| = |-459 - (-90)| = 369 m.

Hence, Two particles moving on the same axis, where one is uniformly moving with an initial abscissa of 30 m and a speed of 15 m/s, and the other is moving with a time equation of XB = 101-70 (S.1), meet at time t = 2.13 s and position X = -32.7 m, while the distance separating them at t = 8 s is 369 m.

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The power output of  2.00 kg object is accelerated uniformly from rest to 3.00 m/s while moving 1.5 m across a level frictionless surface is 24.09 watts.

In science, power is the time required to do work or provide energy, expressed as work done W or energy transferred divided by the time interval t - or W/t. A fixed amount of work can be done for a long time with a low-powered engine, or for a short time with a high-powered engine. The unit of power is work (or energy) per unit of time. Such as foot pounds per minute, joules (or watts) per second, and ergs per second. Force can also be expressed as the product of the force required to move an object and the object's velocity in the direction of the force. If the magnitude of the force F is measured in pounds and the velocity ν is measured in feet per minute, then the power is equal to Fν foot pounds per minute.

Given,

Mass of object (m) = 2.00 kg

Distance covered (s) = 1.5 m

Velocity of object (v) = 3.00 m/s

For calculation of acceleration:

v² = u² + 2as

3² = 0 + 2 × a × 1.5

9 = 3a

a = 2 m/s²

For calculation of time:

s = ut + ¹/₂at²

1.5 = 0 × t + ¹/₂ × 2 × t²

1.5 = t²

t = 1.22 sec.

For calculation of gravitational force:

F = mg

F = 2 × 9.8

F = 19.6 N

For calculation of work done:

W = F × s

W = 19.6 × 1.5

W = 29.4 J

For calculation of power output:

P = W/t

P = 29.4/1.22

P = 24.09 watts

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Answer:

both

Explanation:

and I'm serious he is literally both

Engineering design has to do with the overall process of the design and the production of new products.

Engineering design has to do with the overall process of the design and the production of new products. Now the process of engineering design involves many components and all these are taken into account when a new product is being designed.

As such, the stage of technological design in which each action would occur is;

Define a need and research related information- identify a problem

Establish criteria and prepare the initial design -  Design a solution

Build and test a prototype - implement a solution

Redesign and retest as necessary - Evaluate a solution

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answer: 1 design a solution 2 evaluate a solution 3 identify a problem 4 implement a solution

Explanation: i know

Answer:

After 2 seconds the velocity of the object is 0 m/s.

Explanation:

The velocity at 2 seconds later can be calculated as follows:

\( V_{f} = V_{0} - gt \)

Where:

\(V_{f}\): is the velocity at 2 seconds

\(V_{0}\): is the initial velocity = 20 m/s

g: is the gravity = 10 m/s²

t: is the time = 2 s

Hence, the final velocity is:

\( V_{f} = V_{0} - gt = 20 m/s - 10 m/s^{2}*2 s = 0 m/s \)

This value (0 m/s) means that the object has reached the maximum height.

Therefore, after 2 seconds the velocity of the object is 0 m/s.

I hope it helps you!

The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

To calculate the force on a charge in an electric field, we make use of the formula below.

Formula

F = E×Q .......................... Equation 1

Where:

From the question,

Given:

Substitute these values into equation 1

Note: The negative sign indicates that the force is in the direction negative of the electric field.

Hence, The  magnitude and direction of the force on the charge​ is -12 N opposite the electric field

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Answer: A edge 202694020

Explanation:

Answer:

7.27 m/s

Explanation:

You would be dividing 40 (distance) by 5.5 (time) to get the average velocity of 7.27 m/s .

Answer:

7.27

Explanation:

40/5.5=7.27

The force constant of the spring is 61.3 N/m of a 5.00-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. The object is set into vertical oscillations having a period of 2.70 s.

The force constant of the spring can be found using the formula:
\(k = \frac{ (4π^{2} m) }{T^{2} }\)

where k is the force constant, m is the mass of the object (5.00 kg), and T is the period of oscillation (2.70 s).
Plugging in the given values, we get:
\(k =\frac{ (4π^{2} *5.00 kg)}{(2.70 s)^{2} }\)
k = 61.3 N/m
Therefore, the force constant of the spring is 61.3 N/m.
The formula for calculating the force constant of a spring is based on Hooke's law, which states that the force exerted by a spring is proportional to the displacement of the object from its equilibrium position.

The force constant is a measure of the stiffness of the spring, and it represents the amount of force required to stretch or compress the spring by a certain distance.
We can determine the force constant of a spring by knowing the mass of the object attached to the spring and the period of oscillation of the system. In this particular case, the force constant is 61.3 N/m.

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Answer:

The lifeguard should run approximately 17.752 meters along the shore, before, jumping in the water

Explanation:

The given parameters are;

The rate at which the lifeguard runs = 5 m/s

The rate at which the lifeguard swims = 1 m/s

The horizontal distance of the child from the lifeguard = 30 meters along the shore

The vertical distance of the child from the lifeguard = 60 meters along the shore

Let x represent the distance the lifeguard runs

We have;

The distance the lifeguard swims = √((30 - x)² + 60²)

Time = Distance/Speed  

The time the lifeguard runs = x/5

The time the lifeguard swims = √((30 - x)² + 60²)/1

The total time = √((30 - x)² + 60²) + x/5

The minimum time is given by finding the derivative and equating the result to zero, as follows;

Using an online application, we have;

d(√((30 - x)² + 60²) + x/5)/dx = 1/5 - (30 - x)/(√((30 - x)² + 60²)) = 0

Which gives;

1/5 - (30 - x)/(√(x² - 60·x + 4500) = 0

(30 - x)/(√(x² - 60·x + 4500)) = 1/5

5×(30 - x) = √(x² - 60·x + 4500)

We square both sides to get;

(5×(30 - x))² = (x² - 60·x + 4500)

(5×(30 - x))² - (x² - 60·x + 4500) = 0

25·x² - 1500·x + 22500 - x² + 60·x - 4500 = 0

24·x² - 1440·x + 18000 = 0

Dividing n=by 24 gives;

24/24·x² - 1440/24·x + 18000/24 = 0

x² - 60·x + 750 = 0

By the quadratic formula, we have;

x = (60 ± √((-60)² - 4×1×750))/(2 × 1) =

Using an online application, we have;

x = (60 ± 10·√6)/(2)

x = 30 + 5·√6 or x = 30 - 5·√6

x ≈ 42.25 m and x ≈ 17.752 m

At x = 42.25

Time = √((30 - 42.247)² + 60²) + 42.247/5 ≈ 69.69 seconds

At x = 17.75

Time = √((30 - 17.752)² + 60²) + 17.752/5 ≈ 64.79 seconds

Therefore, the route with the shortest time is when the lifeguard runs approximately 17.752 meters (rounded to three decimal places) along the shore, before, diving in the water

The relationship between mass and gravity is that gravity is the force that acts on objects with mass, while the relationship between weight and gravity is that weight is the force exerted on an object by gravity and is proportional to the object's mass.

Mass and gravity are related in that gravity is the force that acts on objects with mass. The greater the mass of an object, the greater the force of gravity acting on it. This is described by Newton's law of universal gravitation

Weight and gravity are also related, as weight is the force exerted on an object by gravity. The weight of an object is equal to the force of gravity acting on it, and it is proportional to the object's mass.

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Answer:

A. from a low-temperature areas to high-temperature areas

Explanation:

it goes from low-temperature to high-temperature because it's reacting

Answer:

Explanation

one is a galaxy and one is a Star.

Answer:

Hello, I'm here to help you.

↬ 78%

Explanation:

↬ Think that about 70% of the area of the earth is covered by the ocean.

↬ So the precipitation that falls on it is a smiliar percentage.

Answer:

If this is electrical currents , make the wire longer, smaller diameter wires, heat it up

For Question 6:

The formula for momentum to express the conservation of momentum of two objects in a collision is:

m1 • v1 + m2 • v2 = m1 • v1' + m2 • v2'

m1 and m2 are the masses so

63v1 + 55v2 = 63v1' + 55v2'

v1 and v2 represent the velocities before the collision, so

(63)(0) + (55)(0) = 63v1' + 55v2'

v1' and v2' represent the velocities after the collision, so

(63)(0) + (55)(0) = (63)(3.3) + (55)v2' <-- We're looking for v2'

0 + 0 = 207.9 + 55v2'

-207.9 = 55v2'

-3.78 m/s = v2'

The answer is negative because the 55kg skater is moving to the left.

For Question 7:

The formula for momentum is p = m • v

so we have:

3.9 = .15v

26 m/s = v

The ice melts because Thermal energy from Jan’s hand is transferred to the ice.

Thermal energy is the energy due to temperature difference.

Thermal energy flows from hotter to colder bodies.

The ice Jan is holding melts because heat is transferred from his hands t the ice.

In conclusion, thermal energy flow causes melting.

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Answer:

its b

Explanation:

because the heat from your hand makes the ice melt!

Explanation:

V = S/t

s =vt

d = 20 x 5

d = 100m

The position of the ball 5 seconds after it was thrown will be 25 m below the edge of building.

What are the three equations of motion?

The three equations of motion are -

v = u + at

S = ut + 1/2at²

v² - u² = 2aS

Given is an object which is thrown straight upward from the edge of a building with a velocity of 20m/s.

Initial velocity [u] = 20 m/s

Acceleration due to gravity [g] = - 10 m/s² (Rounded off 9.8)

At maximum height, the velocity will be 0.

Assume that the time at which the ball reaches max height be T.

Using first law of motion -

v = u + aT

0 = 20 - gT

gT = 20

T = 20/g

T = 20/10

T = 2 sec

Then -

S[max] = 20 x 2 - 0.5 x 10 x 4

S[max] = 40 - 20 = 20 m

At t = 2 sec the ball will be at maximum height. Now at maximum height, the initial velocity of the ball will be 0.

We have to find the position of ball after 3 seconds as after 2 seconds it was at maximum height.

In this case initial velocity will be [u] = 0

Acceleration [a] = 10 m/s²

Time [t] = 3 sec

Using second equation of motion -

S = ut + 1/2at²

S = 0.5 x 10 x 9

S = 45 m

Position of object = [x] = 20 - 45 = - 25 m

The negative sign indicates that the object is now 25 cm below from the edge of building.

Therefore, the position of the ball 5 seconds after it was thrown will be 25 m below the edge of building.

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Answer:

stars #3

Explanation:

they didn't know it was stars

The required uniform deceleration of the car is 0.4167 m/s² and the speed of the car as it passes the light is 20.62 m/s.

Deceleration is a term used to describe the rate at which an object slows down or decreases its velocity. It is the negative acceleration, indicating a change in velocity in the opposite direction of motion. Deceleration can occur when an object is slowing down, coming to a stop, or changing its direction of motion.

Given information

Motorist's initial speed (u) = 54 km/h = 15 m/s

Distance of traffic light from the motorist (s) = 240 m

Time during which traffic light remains red (t) = 24 s

(a) To find the uniform deceleration of the car.

We have to calculate the rate of deceleration because the motion of the car is not in uniform motion. As the car is moving ahead and we have to find the rate of deceleration of the car when the motorist wishes to pass the light without stopping just as it turns green again.

Now, we can apply the first equation of motion to calculate the deceleration of the car.

The first equation of motion can be written as,

s = ut + (1/2)at²

where u = initial speed = 15 m/s

t = 24 s (time during which traffic light remains red)

s = distance covered by the car = 240 m

We know that after the car passes the traffic light, its final velocity will be zero because the car will be at rest after it passes the traffic light.

We have, final velocity of the car = 0

Putting the values in the above equation, we get

240 = 15 x 24 + (1/2) a(24)²

240 = 360 + 288a

240 - 360 = 288a

-120 = 288a

Dividing both sides by 288, we get

- 120/288 = a/2.4

a = - 0.4167 m/s²

Therefore, the rate of deceleration of the car is 0.4167 m/s²

(b) To find the speed of the car as it passes the light

As the car passes the traffic light, its final velocity will be zero because the car will be at rest after it passes the traffic light.

We can use the third equation of motion to find the speed of the car as it passes the light because the initial velocity of the car is known.

The third equation of motion can be written as:

v² = u² + 2as

where u = initial speed = 15 m/s

a = deceleration of the car = - 0.4167 m/s²

s = distance covered by the car = 240 m

v = final velocity of the car = ?

Putting the values in the above equation, we get:

v² = 15² - 2(- 0.4167) (240)

v² = 225 + 200v² = 425

v = √425

v = 20.62 m/s

Therefore, the speed of the car as it passes the light is 20.62 m/s

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Answer:

Active stretching.

Explanation:

Think about it.

The total weight of the riders lifted into air is determined as 10,290 N.

The total weight of the riders lifted into air is calculated by applying the following kinematic equation as shown below.

Mathematically, the total weight of the riders is calculated as follows;

W = Nmg

where;

W = ( 15 ) ( 70 kg ) ( 9.8 m/s² )

W = 10,290 N

Thus, the total weight lifted by the rider is a function of the individual mass of the riders.

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Answer: The color is orange, the state of matter is liquid

Explanation:

We find that the change in kinetic energy is positive and equal to 696.60 W, option d. The formula for kinetic energy is given by KE = 1/2 * mv^2, where m is the mass of the fluid and v is its velocity.

In this case, we are given the velocities at the outlet and the reactor inlet, which are 14.4 m/s and 10.7 m/s, respectively. Since the mass of the fluid is not provided, we can assume it to be constant.

The change in kinetic energy is given by the difference in kinetic energies at the outlet and the reactor inlet, which can be calculated using the formula:

ΔKE = (1/2 * m * v_outlet^2) - (1/2 * m * v_inlet^2)

Simplifying this expression, we get:

ΔKE = 1/2 * m * (v_outlet^2 - v_inlet^2)

Plugging in the given values, we have:

ΔKE = 1/2 * m * (14.4^2 - 10.7^2)

Calculating this expression, we find the answer to be approximately 696.60 W. Therefore, the correct option is d. 696.60.

In summary, the change in the rate of kinetic energy is approximately 696.60 W. This is calculated by taking the difference between the kinetic energy at the outlet and the kinetic energy at the reactor inlet using the formula ΔKE = 1/2 * m * (v_outlet^2 - v_inlet^2). Plugging in the given velocities of 14.4 m/s and 10.7 m/s, we find that the change in kinetic energy is positive and equal to 696.60 W.

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The heat transfer medium used in a hydronic heating system is water. This is circulated through pipes to transfer heat from a heat source, such as a boiler or heat pump, to the space being heated.

Hydronic heating is a popular heating system that uses water as a heat transfer medium. Water is heated in a boiler or heat pump and then circulated through pipes to transfer heat to the space being heated. The hot water can be used to provide heat to radiators, baseboard heaters, or in-floor radiant systems.
The advantages of hydronic heating include its high efficiency, quiet operation, and flexibility in terms of the types of heat emitters that can be used. It is also known for providing consistent, comfortable heat throughout a home or building.
While the initial installation cost of a hydronic heating system can be higher than other types of heating systems, the long-term energy savings and improved comfort can make it a worthwhile investment. Additionally, hydronic heating systems can be compatible with renewable energy sources such as solar thermal systems.

In conclusion, water is the heat transfer medium used in a hydronic heating system. This system offers many advantages such as high efficiency, quiet operation and flexibility in terms of the types of heat emitters that can be used.

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