Answer:
50 x 3000 = 150000/4000 = 37.5
37.5 I think.
Explanation:
Hope this helps!
A 3000 kg truck travelling at 50km/hr strikes a stationary 1000 kg car, locking the two vehicles together, the final velocity of the two vehicles after the collision is approximately 10.43 m/s.
We may use the concept of conservation of momentum to calculate the final velocity of the two vehicles after the collision.
The total initial momentum (P_initial) is given by:
P_initial = (mass of truck) * (initial velocity of truck) + (mass of car) * (initial velocity of car)
P_initial = (3000) * (50) + (1000) * (0)
The velocity:
Vt = 50 * (1000/3600) = 13.9 m/s
Vc = 0 = 0 m/s
P_initial = (3000) * (13.9) + (1000) * (0 )
P_initial = 41700 kg·m/s
P_initial = P_final
41700 kg·m/s = (3000 kg + 1000 kg) * Vf
41700 kg·m/s = 4000 kg * Vf
Now Vf:
Vf = 41700 kg·m/s / 4000 kg
Vf ≈ 10.43 m/s
Therefore, the final velocity of the two vehicles after the collision is approximately 10.43 m/s.
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A600kg car is acted force of 1200N starting from rest.how travel in 10 seconds?
Answer:
x= 100 m
Explanation:
m= 600 kg
t= 10 s
F= 1200N
v0= 0
-----
F=ma
a=F/m
x= (v0)t + (1/2)(a)(t^2)
x= (1/2)(F/m)(t^2)
x= (1/2)(1200/600)(10^2)
x= 100m
Which of the following statements about vectors and scalars are true? Choose all that apply.
A. Scalar quantities and vector quantities both have magnitude.
B. The quantity +16 miles is a scalar quantity.
C. A scalar quantity depends only on the initial and final values.
D.
A horizontal force is a vector quantity but the force of gravity is a scalar quantity.
E. A vector quantity is described with a direction while a scalar quantity is not.
F. The quantity 20 m/s north is a vector quantity.
G. Speed is a scalar quantity while velocity is a vector quantity.
H. A vector quantity is a larger quantity while a scalar quantity is a smaller quantity.
Answer:
A, E, and G is the answer
Explanation:
Hope it helps
what is nuclear energy and write down it's two applications of this type of energy?
Background: Nuclear energy can be used for various industrial applications, such as seawater desalination, hydrogen production, district heating or cooling, the extraction of tertiary oil resources and process heat applications such as cogeneration, coal to liquids conversion and assistance in the synthesis of chemical ...
About how many kwh does the solana parabolic trough solar array generate in a month?
An array of this size can produce an average of 350-850 kWh of AC energy per month.
Solar technologies convert sunlight into electrical energy either through photovoltaic (PV) panels or through mirrors that concentrate solar radiation. This energy can be used to generate electricity or be stored in batteries or thermal storage.
Solar panel systems are measured in terms of kW. A common size solar panel array is usually around 5kW. An array of this size can produce an average of 350-850 kWh of AC energy per month.
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why do think chopping of wood is a physical change but burning of wood is a chemical change
Answer: Burning of wood is a chemical change while cutting of wood is a physical change because during burning, new substances are formed. After burning, we cannot get original substance, (i.e. wood) back. Cutting of wood into small pieces is a physical change because no new substance is formed.
What is the difference between static and dynamic flexibility ?
Static stretches are those in which you remain in a single position—standing, sitting, or lying still—for up to 45 seconds. Dynamic stretches are regulated motions that get your ligaments, muscles.
Stretches that are static versus those that are dynamic:Movement is included into dynamic stretches, such as lunges with a torso twist. As opposed to dynamic stretches, static stretches include holding a stretched position for a while. Stretches that are static include the triceps stretch and the butterfly stretch.
A swimmer might, for instance, circle their arms before entering the water. A series of movements to get the body moving before engaging in any kind of exercise can also be considered dynamic stretches.
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Describe three more examples of energy transformations in sentences--what was
the starting energy, and what did it transform into
--what were the demos we did in class last week? (examples: buzzer,
glowstick, hand crank light, tv, computer, cell phone)
1.
2.
3.
Energy transformation is the process of changing one form of energy into another form. It involves the conversion of energy from one form to another, such as mechanical energy to electrical energy or chemical energy to thermal energy. This process is fundamental to the functioning of the universe, and it occurs in natural and man-made systems alike.
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Identity ten devices that use cells or batteries. What types of cells or batteries are used in each device? Are the cells or batteries used the best choice?
Ten devices that use batteries are: smartphones, laptops, flashlights, digital cameras, portable speakers, electric toothbrushes , remote controls, electric shavers, handheld game consoles, and electronic toys
What are the batteries?
Here are ten devices that use cells or batteries:
Smartphones - most smartphones use rechargeable lithium-ion batteries.Laptops - laptops use rechargeable lithium-ion batteriesDigital cameras - digital cameras use rechargeable lithium-ion batteries or disposable alkaline batteriesElectric toothbrushes - electric toothbrushes typically use rechargeable nickel-metal hydride (NiMH) batteriesFlashlights - flashlights often use disposable alkaline batteries, although some models use rechargeable lithium-ion batteriesRemote controls - remote controls typically use disposable alkaline batteriesPortable speakers - portable speakers usually use rechargeable lithium-ion batteriesCalculators - calculators often use button cell batteries, such as the CR2032 lithium batteryWatches - watches use a variety of batteries, including button cell batteries like the SR626SW silver oxide battery or the CR2032 lithium batteryToys - many toys use disposable alkaline batteriesWhether or not the cells or batteries used in these devices are the best choice depends on various factors such as the device's power requirements, energy efficiency, cost, and environmental impact.
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you are on the management team of a company that is considering purchasing a tanker truck. the truck you want has a volume of 28,000 liters and an empty mass/weight of 15,500 kg. however, the route you wish to travel has a bridge with a weight limit of 25 tons. if you purchase the truck and fill it to capacity with a liquid whose density is 0.90 kg/l, what will the mass of the truck be?
For getting the mass of the truck, we have to just multiply the volume with the liquid density given and then add up the empty truck mass with it.
What is liquid density?A liquid's density is a gauge of how heavy it is relative to the amount being measured or in simpler terms, the density of any kind of liquid is a measure of how much heavy it is for the amount measured.
Any kind of liquid that weighs heavier is termed denser if you weigh two liquids with similar volumes or amounts. A substance which is less dense than water will float if it is gently put on the water's surface.
Just like any kind of solid, the density of a liquid will be equal to the mass of the liquid divided by its volume. i.e., D = m/v.
Mass of the truck = (Volume x liquid density) + empty mass of the truck
= (28,000 x 0.90) + 15,500 kg
= 25,200 + 15,500
= 40,700 kg
Thus the mass of tge truck can be calculated as 40,700 kg.
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4. Calculate the momentum for each scenario:
a. .02 kg mass moving at 300 m/s
b. 2 kg mass moving at 40 m/s
c. 200 kg mass moving at 4 m/s
a) Answer:
Momentum = 6 kgm/s
Explanation:
Momentum = mass × velocity
Given that,
mass = 0.02 kg velocity = 300 m/s
Therefore, momentum = (0.02 × 300)kgm/s
Momentum = 6 kgm/s
b) Answer:
Momentum =80 kgm/s
Explanation:
Momentum = mass × velocity
Given that,
mass = 2 kg velocity = 40 m/s
Therefore, momentum = (40 × 2)kgm/s
Momentum = 80 kgm/s
c) Answer:
Momentum = 800 kgm/s
Explanation:
Momentum = mass × velocity
Given that,
mass = 200 kg velocity = 4 m/s
Therefore, momentum = (200 × 4)kgm/s
Momentum =800 kgm/s
in the book example concerning the figure above, a force of 0.086 n from an external agent was required to keep the rod moving at a constant speed. suppose the light bulb in the figure is unscrewed from its socket. how much force would now be needed to keep the rod moving at a constant speed? justify your answer.
The correct answer is 0 N.
There will be no current in the rod and thus no magnetic force resisting the motion. Without any resistance, it will keep moving until acted on by an outside force according to Newton's first law.
What is motion?
Numerous physical systems, including objects, bodies, matter particles, matter fields, radiation, radiation fields, and radiation particles, as well as curvature and space-time, are affected by motion. One can also talk about how borders, shapes, and pictures move. A physical system's configuration or locations continuously changing in space is what is often meant by the term "motion." For instance, one can discuss the motion of a wave or a quantum particle, where the configuration is made up of the probabilities that the wave or particle would occupy particular places.To know more about motion, click the link given below:
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A negatively charged particles in an atom that orbit around the nucleus are called:
a. compound
b. mixture
c.element
d.atom
Answer:
electrons
Explanation:
Electrons orbit the nucleus while the protons an nuetrons are inside.
A reheat Rankine cycle operates with water as the working fluid. Steam enters the first turbine at 8 MPa and 450°C and exits at 0.8 MPa. It is then reheated to 400°C before entering the second turbine, where it exits at 10 kPa. If the amount of work into the pump is 8.04 kJ/kg and the net work per cycle produced is 1410.25 kJ/kg, determine the thermal efficiency of the cycle
Answer:
The thermal efficiency, \(\eta _{reheat}\), of the Rankine cycle with reheat is 36.81%
Explanation:
p₁ = 8 MPa = 80 Bars
T₁ = 450°C = 723.15 K
From steam tables, we have;
v₁ = 0.0381970 m³/kg
h₁ = 3273.23 kJ/kg
s₁ = 6.5577 kJ/(kg·K) = s₂
The p₂ = 0.8 MPa
T₂ = Saturation temperature at 0.8 MPa = 170.414°C = 443.564 K
h₂ = 2768.30 kJ/kg
\(T_{2'}\) = 400°C = 673.15 K
\(h_{2'}\) = at 400°C and 0.8 MPa = 3480.6 kJ/kg
p₃ = 10 kPa = 0.1 Bar
T₃ = Saturation temperature at 10 kPa = 45.805 °C = 318.955 K
h₃ = 2583.89 kJ/kg
h₄ = \(h_{3f}\) = 191.812 kJ/kg
The thermal efficiency, \(\eta _{reheat}\), of a Rankine cycle with reheat is given as follows;
\(\eta _{reheat} = \dfrac{\left (h_{1}-h_{2} \right )+\left (h_{2'}-h_{3} \right )-W_{p}}{h_{1}-\left (h_{4}+W_{p} \right )+\left (h_{2'}-h_{2} \right )}\)
Therefore, we have;
\(\eta _{reheat} = \dfrac{(3273.23 -2768.30 ) + (3480.6 -2583.89 ) - 8.04)}{(3273.23 -(191.812 + 8.04) + (3480.6 -2768.30 ) } = 0.3681\)
Which in percentage is 36.81%.
Q4 you A bird begins to accelerate at a constant 0.3 m/s for 3 s. Its change in
velocity is
A. 0.9 m/s B. 1.5 m/s C. 1.95 m/s D.2.4 m/s
Answer:
• From first newtons equation of linear motion:
\({ \boxed{v = u + at}}\)
• from that equation, let's get the relation for the change in velocity;
\((v - u) = at \\ { \boxed{ \boxed{\delta v = at}}}\)
• a is the acceleration, a = 0.3 m/s and t is time, t = 3s
\( \delta v = (0.3 \times 3) \\ { \underline{ \underline{ \delta v = 0.9 \: \: m {s}^{ - 1} }}}\)
Answer: A. 0.9 m/s
A gun can fire a bullet at 540 m/s. If the gun is aimed at an angle of 55o above the horizontal and fired, what will be the horizontal and vertical components of the gun's velocity?
Answer:
Explanation:
The initial vertical velocity is 540sin55° = 442.342103... 442 m/s
The initial horizontal velocity is 540cos55° = 309.731275... 310 m/s
In the real world, both initial velocities would be reduced by air resistance and vertical velocity will be altered by gravity.
A ball rolls off a table and it traveling with a horizontal velocity of 2 m/s and 1 point
has a final vertical velocity of 3 m/s just before it hits the ground. How far
from the base of the table did the ball hit the ground?
Answer:
The velocity when the ball hits the ground is obtained using v2. 2 = v1. 2 + 2 g Dy with v1=0 and Dy=h. Thus solving for v2 yields 17.1 m/s v2 = 2 g h =.
21 pages·330 KB
Answer:
I e jofh ndoj eohe nc n very nic e
can somone pls help me??!! i’m very stuck
Answer:
graph b
Explanation:
graph a isnt constant
graph c is slower (less steep slope)
graph d is slowing down (starts high ends low)
How is the earth a cracked hard boiled egg
unbalanced forces make an object:
A.accelerate
B.move at a constant speed
C.explode
D.come to rest
Answer:
i would have to say B makes the most sense
Explanation:
when you grip the steering wheel, you should place your hands on the steering wheel at the 3 and 9 or 4 and 8 o'clock positions to allow room for air bags to deploy.
According to the information we can infer that it is true that when we grip the steering wheel, we should place our hands on the steering wheel at the 3 and 9 or 4 and 8 o'clock positions to allow room for airbags to deploy.
How to determine if the declaration is true?To determine if the declaration is true we have to look for some information related with the position of our hands while we drive a car. In this case we can conclude that when gripping the steering wheel some experts recommend to place your hands at the 3 and 9 o'clock positions or the 4 and 8 o'clock positions.
The main reason to use these positions is because these allow us to get a better control and also ensure that there is enough space for the airbags to deploy in case of an accident.
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A woman stands in a boat at rest on a calm lake. She throws a 10 kg anchor off the front of the boat, which has a mass of 1,000 kg
What is the initial momentum of the anchor-boat system?
A)1,000 kg m/s
B)zero because both objects are at rest.
C)1,010 kg m/s
D)10,000 kg m/s
PLEASE HELP!! I don’t understand
Answer: B) zero because both objects are at rest
Explanation:
Given the following :
Mass of anchor = 10kg
Mass of boat = 1000kg
Note : both boay and anchor are at rest, this gives a Velocity of zero
The momentum of a body is given as the product of Mass and velocity, that is,
Momentum = mass × velocity
Initial Momentum of anchor-boat system =
(mass of boat× initial velocity of boat) + (mass of anchor × initial velocity of anchor)
Initial Velocities of boat and anchor = 0
Therefore,
Initial momentum = (1000 × 0) + (10 × 0)
Initial momentum = (0 + 0) = 0
This is ecause both objects are at rest.
Does anyone just ever question their gender. But you get scared out of wanting and feeling like the opposite gender.
Yeah it feels weird, it gives me goosebumps. Im a boy actually, but when I think my self as a girl it just cringes me. But I also wonder how would my life would change.
A 1 200 kg car travels along the road. Calculate its kinetic energy at: 54 km.h-¹
Answer:
Explanation:
Given:
m = 1 200 kg
V = 54 km/h = 15 m/s
___________
Wk - ?
Wk = m·V² / 2
Wk = 1200·15² / 2 = 270 000 J or Wk = 270 kJ
is acceleration the slope of a velocity-time graph?
Answer:
Yes!
Explanation:
The slope of a velocity-time graph is indeed equal to the object's acceleration.
Can a 20 N force and 40 N force ever produce a resultant with magnitude of 27 N?
Sure ,Let's find angle between forces
Vectors be A and B and resultant be R\(\\ \sf\longmapsto R^2=A^2+B^2+2ABcos\theta\)
\(\\ \sf\longmapsto 27^2=20^2+40^2+2(20)(40)cos\theta\)
\(\\ \sf\longmapsto 729=400+1600+1600cos\theta\)
\(\\ \sf\longmapsto 729=2000+1600cos\theta\)
\(\\ \sf\longmapsto 1600cos\theta=-271\)
\(\\ \sf\longmapsto cos\theta=-0.169\)
\(\\ \sf\longmapsto \theta=cos^{-1}(-0.169)\)
\(\\ \sf\longmapsto \theta=80.2°\)
When a wave passes from a less dense medium to a denser one, most of the
wave energy is
A. reflected.
B. diffracted.
C. absorbed.
D. refracted.
Answer:
D. Refracted
Explanation:
At the point when light passes from a less thick to a more thick substance, (for instance passing from air into water), the light is refracted (or bowed) towards the ordinary. The bowing happens on the grounds that light voyages all the more gradually in a denser medium. The answer is D, refracted.
Which new idea did copernicus introduce that significantly modified the geocentric model of the universe?.
Copernican heliocentrism was a novel concept that fundamentally altered the geocentric view of the universe.
What fresh concept did Copernicus bring that fundamentally altered the geocentric model?The father of modern astronomy is Nicolaus Copernicus, a Polish astronomer and mathematician. The heliocentric hypothesis of the solar system, which he initially put forth, states that Earth and other planets rotate around the sun.
Nicolaus Copernicus created the Copernican heliocentrism astronomical theory, which was first presented in print in 1543. This theory put the Sun in the center of the cosmos, stationary, and had Earth and the other planets orbit it at uniform speeds in circular orbits modified by epicycles.
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the near point (the smallest distance at which an object can be seen clearly) and the far point (the largest distance at which an object can be seen clearly) are measured for six different people.
The four individuals' lenses range in power from 0.7 D to 1.5 D to 2.0 D and 2.75 D, respectively.
What is hyperopia?The farsighted people are those with near point greater than 25 cm. A converging lens is needed to correct farsightedness, or hyperopia, therefore, the focal length, f, is positive. The image formed is virtual and on the same side of the lens. Thus, the image distance is negative. From the lens formula, 1/f = 1/v+1/u; but v is negative.
Here,
Therefore, 1/f = 1/u - 1/v
But, power of a lens = 1/f in meters.
Therefore, P = 1/u - 1/v
They include Avishka, Berenice, Edouard and Francisca.
For Avishka, u = 25 cm or 0.25 m, v = 0.4 m
P = 1/ 0.25 - 1/0.4 = 1.5 D
For Berenice, u = 0.25 m, v = 0.3 m
P = 1/0.25 - 1/0.30 =0.7 D
For Edouard, u = 0.25 m, v = 0.80 m
P = 1/0.25 - 1/0.80 =2.75 D
For Francesca, u = 0.25 m, v = 0.50 m
P = 1/0.25 - 1/0.5 = 2.0 D
The order of power of lens of 4 people is from smaller to greater is 0.7 D<1.5 D<2.0 D<2.75 D.
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what is the minimum height h of a slope that must be constructed in order for a rider in the cart with a combined mass m to complete a loop of radius r?
The minimum height h of a slope for a rider in a cart with combined mass m to complete a loop of radius r is h=5r.
The minimum height of the slope can be calculated by using the principle of conservation of energy and centripetal force. At the top of the loop, the rider and the cart have maximum potential energy, and at the bottom of the loop, they have maximum kinetic energy.
The minimum height of the slope is the point where the rider just completes the loop without falling off the track. To achieve this, the potential energy at the top of the loop must be equal to the kinetic energy at the bottom of the loop.
Hence, the minimum height of the slope required to complete a loop of radius r is given by h=5r. This ensures that the rider has enough speed to complete the loop without falling off. Additionally, the mass of the rider and the cart should be taken into account, as this affects the amount of force required to maintain the circular motion.
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two out-of-tune flutes play the same note. one produces a tone that has a frequency of 262 hz, while the other produces 266 hz. when a tuning fork is sounded together with the 262 hz tone, a beat frequency of 1 hz is produced. when the same tuning fork is sounded together with the 266-hz tone, a beat frequency of 3 hz is produced. what is the frequency of the tuning fork?
When the same tuning fork is sounded together with the 266-hz tone, a beat frequency of 3 hz is produced, the frequency of the tuning fork is: 264 Hz.
When two out-of-tune flutes play the same note, and one produces a tone that has a frequency of 262 Hz, and the other produces 266 Hz. The beat frequency of 1 Hz is produced when a tuning fork is sounded together with the 262 Hz tone, and the same tuning fork is sounded together with the 266-Hz tone.
In this case, the frequency of the tuning fork is required. The formula for beat frequency is expressed as follows: Beat frequency = frequency 2 − frequency 1
The frequency of the tuning fork can be determined by subtracting the frequency of the 266 Hz tone from that of the 262 Hz tone (i.e. 266 - 262 = 4 Hz).
This implies that the tuning fork is 4 Hz higher than the 266 Hz tone. The beat frequency of 3 Hz when the same tuning fork is sounded together with the 266 Hz tone implies that the tuning fork's frequency is 3 Hz lower than the 269 Hz tone. The average of these two frequencies is 264 Hz (i.e. 266 Hz - 2 Hz). Therefore, the frequency of the tuning fork is 264 Hz.
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