A block of weight w sits on a plane inclined at an angle θas shown. (Figure 1) The coefficient of kinetic friction between the plane and the block is μ.
Part A
What is the work Wf done on the block by the force of friction as the block moves a distance L up the incline?
Express your answer in terms of some or all of the following: μ, w, θ, L.
Part B
What is the work W done by the applied force of magnitude F?
Express your answer in terms of some or all of the following: μ, w, θ, L.
Part C
What is the change in the potential energy of the block, ΔU, after it has been pushed a distance L up the incline?
Express your answer in terms of some or all of the following: μ, w, θ, L.

Answers

Answer 1

The work W done by the applied force of magnitude F can be calculated by the following formula; W = FLcosθ - μwLsinθPart CThe change in the potential energy of the block, ΔU, after it has been pushed a distance L up the incline can be calculated by the following formula; ΔU = wLsinθ

Part AThe work Wf done on the block by the force of friction as the block moves a distance L up the incline can be calculated by the following formula;Wf = -μwLsinθPart BThe work W done by the applied force of magnitude F can be calculated by the following formula;W = FLcosθ - μwLsinθPart CThe change in the potential energy of the block, ΔU, after it has been pushed a distance L up the incline can be calculated by the following formula;ΔU = wLsinθ

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Related Questions

45°

In an attempt to make a 3-point shot from

a distance of 6.00 m, a basketball player

lofts the ball at an angle of 68° above the

horizontal. The ball has an initial velocity

of 10.0 m/s and an initial distance from

he floor of 1.50 m.

Answers

The total distance the ball travels is approximately 6.48 m when the basketball player is attempting to make a 3-point shot from a distance of 6.00 m.

The ball has an initial velocity of 10.0 m/s and an initial distance from the floor of 1.50 m.

To solve for the distance the ball travels, we need to use the equation:

distance = (initial velocity x time) + (0.5 x acceleration x time^2).

We can use the vertical component of the initial velocity to solve for the time it takes for the ball to reach its maximum height. This time can then be used to solve for the distance the ball travels horizontally using the horizontal component of the initial velocity.

The vertical velocity at maximum height is zero, and the acceleration due to gravity is \(-9.81 m/s^2\).

Using these values, we can calculate that the ball reaches its maximum height of 5.01 m after 0.51 seconds.

The horizontal component of the initial velocity is 10.0 m/s x cos(68°) = 3.25 m/s.

Using this value and the time of flight of 1.02 seconds (twice the time it takes to reach maximum height), we can solve for the distance the ball travels horizontally to be 3.32 m.

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A 1500 kg car is moving at 15m/s what is the impulse experienced by the car

*Pls put the formula of how you did it too*

Answers

Answer:

22500 Ns

Explanation:

Given,

Mass ( m ) = 1500 kg

Velocity ( v ) = 15 m/s

Formula : -

Impulse = mv

Impulse

= 1500 x 15

= 22500 Ns

Therefore,

22500 Ns is the impulse experienced by the car.

Note : -

Ns is the unit of impulse.

Impulse= mass x velocity so answer is 22500

a pumpkin is dropped from a 35 m building. what is its initial velocity​

Answers

Answer:

26.2 mps

Explanation:

Students are provided with data in which an experiment was conducted to determine the relationship between the length of the pendulum and the period of oscillation. the data include a pendulum of length 0.5m , for which it took 81 s for the pendulum bob to oscillate 10 times. however, the experiment was conducted at a location that is not near earth’s surface. the gravitational field strength where the experiment was conducted is most nearly:__________

Answers

The gravitational field strength at the location where the experiment was conducted is nearly 1.56 m/s².

In the given experiment, the length of the pendulum is 0.5m, and it took 81 seconds for the pendulum bob to oscillate 10 times.

Use of the relationship between the length of the pendulum and its period of oscillation.

The period of a simple pendulum is given by the formula:

T = 2π\(\sqrt{(L/g)}\)

Where:

T = period of the pendulum

L = length of the pendulum

g = gravitational field strength

g = (4π²L) / T²

Substituting the given values:

g = (4π² × 0.5) / (81/10)²

= 1.56 m/s²

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Does thermal energy flow from warmer objects to cooler objects

Answers

Answer:yes

Explanation:

Thermal energy is the sum of all kinetic and potential energy in a substance. He is the thermal energy that flows from a warmer object to a cooler object.

heat is the thermal energy that flows from warmer objects to cooler objects. heat only flows one way, from warmer to cooler objects. net heat transfer ends when two objects reach the same temperature. (thermal equilibrium)

help please .....

what is the effect of gravity on a falling object? write the conclusion obtained from the coin and feather experiment ?

Answers

Answer:

Pick something up with your hand and drop it. When you release it from your hand, its speed is zero. On the way down its speed increases. The longer it falls the faster it travels. Sounds like acceleration to me.

But acceleration is more than just increasing speed. Pick up this same object and toss it vertically into the air. On the way up its speed will decrease until it stops and reverses direction. Decreasing speed is also considered acceleration.

But acceleration is more than just changing speed. Pick up your battered object and launch it one last time. This time throw it horizontally and notice how its horizontal velocity gradually becomes more and more vertical. Since acceleration is the rate of change of velocity with time and velocity is a vector quantity, this change in direction is also considered acceleration.

In each of these examples the acceleration was the result of gravity. Your object was accelerating because gravity was pulling it down. Even the object tossed straight up is falling — and it begins falling the minute it leaves your hand. If it wasn't, it would have continued moving away from you in a straight line. This is the acceleration due to gravity.

In this initial experiment the bowling ball drops straight to the ground whereas the feathers float, owing to air resistance.

He alludes to the earlier experiment by Galileo that tested the same hypothesis.

"Galileo’s experiment was simple," he explains. "He took a heavy object, and a light one, and dropped them at the same time to see which fell fastest."

Although Galileo’s experiment proved two similarly shaped objects would fall at the same speed despite being different weights, he didn’t have access to a vacuum chamber in the 17th Century to conduct Professor Cox's more extravagant experiment.

Professor Cox also used the bowling ball and feather to prove a hypothesis put forward by Albert Einstein.

His Special Theory of Relativity argued that items would not be falling but standing still due to lack of force acting on them.

"Isaac Newton would say that the ball and the feather fall because there’s a force pulling them down: gravity,’ Professor Cox said.

"But Einstein imagined the scene very differently.

"The “happiest thought of his life” [as Einstein called it] was this; the reason the bowling ball and the feather fall together is because they’re not falling.

"They’re standing still. There is no force acting on them at all.

"He reasoned that if you couldn’t see the background, there’d be no way of knowing that the ball and the feathers were being accelerated towards the Earth.

"So he concluded they weren’t."

The tweaking of Newton’s earlier theory enabled Einstein to more accurately define his own theory, which regards the relationship between space and time.

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What is the converse of the statement "No pilots are mechanics"?
a. No mechanics are pilots.
b. Some mechanics are pilots.
c. All pilots are mechanics.
d. None of these

Answers

The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

The converse of a statement switches the subject and the predicate and negates both. In the original statement, the subject is "pilots" and the predicate is "mechanics."

The original statement states that there is no overlap between pilots and mechanics. In the converse statement, the subject becomes "mechanics" and the predicate becomes "pilots," and it still states that there is no overlap between the two groups.

Therefore, The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

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A duck floats backwards a distance of 3 meters in 15 seconds. What is the duck's velocity?

Answers

I think the ducks velocity is 45

During capillary action, the water will rise higher in which situation?

Answers

During capillary action, the water will rise higher in a narrower tube or channel with a smaller diameter.

This is because the smaller diameter creates a greater surface tension, which pulls the water upward against gravity. Additionally, a surface with a higher degree of attraction to the water molecules will also enhance capillary action, allowing the water to rise higher.
                                     This is because the adhesive forces between the water molecules and the tube's surface, as well as the cohesive forces between the water molecules themselves, are stronger in smaller diameter tubes, leading to a greater capillary rise.

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A Michelson interferometer consists of a 50/50 beam splitter (half of the light is transmitted, half is reflected) and two mirrors, as shown in the figure. By varying the relative path lengths, one can change the amount of light that leaves via the bottom exit 'port' of the interferometer. This enables one, e.g., to measure distances very accurately.
A 1-mW laser of wavelength λ = 360 nm, is directed into the interferometer. Initially the path lengths of the two arms are identical, so that all the light goes to the detector at the bottom (i.e., there's complete constructive interference of the waves from the two paths). How much does mirror M1 need to be moved (the minimum distance) so that no light will be detected at D1? Δx = ____ nm

Answers

Answer:

Explanation:

so its half?

________

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The minimum distance that mirror M1 needs to be moved so that no light will be detected at D1 is 180 nm

To find the minimum distance that mirror M1 needs to be moved so that no light will be detected at D1, we need to use the equation for destructive interference:

Δx = (m + 1/2)λ

Where Δx is the minimum distance, m is an integer, and λ is the wavelength of the light. In this case, we want to find the minimum distance for destructive interference, so we will use m = 0:

Δx = (0 + 1/2)(360 nm)

Δx = 180 nm

Therefore, the minimum distance that mirror M1 needs to be moved so that no light will be detected at D1 is 180 nm.

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A motorboat starting from rest travels in a straight line on a lake.(a)If the boat achieves a speed of 7.00 m/s in 15.0 s, what is the boat's average acceleration?magnitude in ____m/s2 What direction? opposite to the direction in motion or in the direction of motion? (b)If the boat continues with the same acceleration, what would be its speed after another 6.00 s? in ____m/s

Answers

Answer:

a)

Explanation:

The initial speed, u = 0 m/s (The boat starts from rest)

Th final speed, v = 7 m/s

The time, t = 15 s

To find the average acceleration, use the equation below

\(\begin{gathered} a=\frac{v-u}{t} \\ \\ a=\frac{7-0}{15} \\ \\ a=\frac{7}{15} \\ \\ a=0.47\text{ m/s}^2 \end{gathered}\)

The acceleration of the boat is in the direction of the motion

b) If the boat continues with the same acceleration for another 6 seconds:

Total time, t = 6 + 15 = 21 s

Speed = Acceration x time

Speed = 0.47 x 21

Speed = 9.87 m/s

What is true about the atom? Select all that are correct.
Is made up of protons, neutrons and electrons
Make up the matter in the universe
Are found in nonliving matter only
Is found only on Earth
a is about the same size as a cell
Smallest unit of matter that keeps its chemical properties

What is true about the atom? Select all that are correct.Is made up of protons, neutrons and electronsMake

Answers

Answer: Is made up of protons, neutrons and electrons

Make up the matter in the universe

Smallest unit of matter that keep its chemical properties

20 points y'all it's urgent

As a light’s intensity decreases...

a. its amplitude increases
b. its amplitude decreases
c. its wavelength decreases
d. its wave speed decreases

Answers

Answer:

There is an inverse relationship between distance and light intensity - as the distance increases, light intensity decreases. This is because as the distance away from a light source increases,..

Explanation:

The light intensity decreases as magnification increases. There is a fixed amount of light per area, and when you increase the magnification of an area, you look at a smaller area. So you see less light, and the image appears dimmer. Image brightness is inversely proportional to the magnification squared.

PLZ HELP. 25 POINTS!

PLZ HELP. 25 POINTS!

Answers

D...................................

Write a short skit/story about a member of the school choir or band being bullied by two cheerleaders who are jealous of her voice. Show what you would do as a bystander to help

Answers

I was walking down the halls rushing to class. I had to get there quickly or else I would be late little did I know what I was about to witness. Before turning the corner to go to the stairs I heard singing and I immediately thought that this person had a beautiful voice. But the next thing that happened was unbelievable, I saw two cheerleaders going to the stairs they stopped and started at the person who was singing. They stopped singing and got startled and then the girls looked her up and down and started saying she sung horribly and that she dressed horribly as well. They kept laughing at her and they even grabbed her folder and started throwing the papers she had in it everywhere. I knew this was wrong so I went to get a teacher and told her what was happening. We caught the two girls on time and they got in trouble and had to apologize. They even said that they only bullied her because they were jealous and that they were so sorry. The girl thanked me and I told her that her voice was amazing and that if anyone gives her trouble again to get help.





( you can change anything if you want I kinda rushed it so it may not be aMazingg)

In a heat engine, 2.00 mol of a monoatomic gas are carried through the cycle ABCDA. The segment AB represents an isothermal expansion, the segment BC is an adiabatic expansion, the segment CD is an isobaric compression, and DA is a constant volume process. The pressure and temperature at A are 5.00 atm and 600 K. The volume at B is twice the volume at A. The pressure at D is 1.00 atm.
a) What is the pressure at B?
b) What is the temperature at C?
c) Find the total work done by the gas in one cycle.

Answers

(a)The pressure at B is 0.1248 atm.

(b)The temperature at C is 727.1 K.

(c)The total work done by the gas in one cycle is -1979J

General calculation:

We can use the First Law of Thermodynamics to analyze the heat engine cycle:

ΔU = Q - W

where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system. For a complete cycle, ΔU = 0, so:

Q = W

We can also use the ideal gas law to relate the pressure, volume, and temperature of the gas:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the absolute temperature.

(a)How to find the pressure at B segment?

To find the pressure at B, we can use the fact that the segment AB is an isothermal expansion. This means that the temperature remains constant, so:

PV = nRT

PB = (nRT)/(2V) = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/(2V) = (0.0821 L·atm/mol)(600 K)/V

Since the pressure at A is 5.00 atm, we can use the fact that the temperature is constant to find the volume at A:

PV = nRT

VA = (nRT)/P = (2.00 mol)(0.0821 L·atm/mol·K)(600 K)/5.00 atm = 197.76 L

Since the volume at B is twice the volume at A, we have:

VB = 2VA = 395.52 L

Substituting into the expression for PB, we get:

PB = (0.0821 L·atm/mol)(600 K)/395.52 L = 0.1248 atm

Therefore, the pressure at B is 0.1248 atm.

(b) How to find the temperature at segment C?

To find the temperature at C, we can use the fact that the segment BC is an adiabatic expansion. This means that no heat is added or removed from the system, so:

\(PV^\gamma\)= constant

where γ is the ratio of specific heats (for a monoatomic gas, γ = 5/3). We can use the fact that the volume at C is equal to the volume at A to find the pressure at C:

\(PAV^\gamma = PCV^\gamma\)

PC =  \(PA(V/A)^\gamma\) = 5.00 atm\((1/2)^(^5^/^3^)\) = 1.556 atm

Since the segment BC is adiabatic, the temperature changes but no heat is added or removed from the system. Using the ideal gas law, we can relate the pressure, volume, and temperature:

PV = nRT

TC = (PCVC)/(nR) = (1.556 atm)(197.76 L)/(2.00 mol)(0.0821 L·atm/mol·K) = 727.1 K

Therefore, the temperature at C is 727.1 K.

(c) How to find the total work done by the gas in one cycle?

The total work done by the gas in one cycle is the sum of the work done in each segment of the cycle:

W = WAB + WBC + WCD + WDA

For segment AB, the work done is:

WAB = -QAB = -∫PdV = -nRT∫(1/V)dV = -nRT ln(VB/VA) = -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2) = -602 J

For segment BC, the work done is:

WBC = -QBC = -∫PdV = -nγRT∫(1/V)dV = -nγRT

We know that VB = 2VA and VC = 2VD, so we can express the ratio VB/VC in terms of VA/VD:

VB/VC = (2VA)/(2VD) = VA/VD

Substituting into the expression for WBC, we get:

WBC = -nγRT ln(VA/VD)

For segment CD, the work done is:

WCD = -QCD + PCDΔV = -nCpΔT + PCDΔV

where Cp is the specific heat at constant pressure, ΔT is the change in temperature, and ΔV is the change in volume. We know that the segment CD is isobaric, so ΔV = VB - VA = (2VA) - VA = VA. We can also use the ideal gas law to relate the pressure, volume, and temperature:

PV = nRTPC = (nRT)/VD

Substituting into the expression for WCD, we get:

WCD = -nCpΔT + (nRT/VD)VA = -nCp(TC - TD) + (nRT/VD)VA

For segment DA, the work done is:

WDA = -QDA + ΔU = -nCvΔT

where Cv is the specific heat at constant volume. We know that the segment DA is isovolumetric, so ΔV = 0. Using the First Law of Thermodynamics, we know that ΔU = 0 for a complete cycle, so:

QDA = -WDA = nCvΔT

Substituting into the expression for WDA, we get:

WDA = -nCvΔT

Adding up the work done in each segment, we get:

W = WAB + WBC + WCD + WDA

= -(2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(Cp)(TC - TD) + (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(Cv)(TC - TA)

We know that Cp and Cv for a monoatomic gas are related by Cp = Cv + R, so we can express Cp in terms of Cv:

Cp = Cv + R = (3/2)R + R = (5/2)R

Substituting and simplifying, we get:

W = (2.00 mol)(0.0821 L·atm/mol·K)(600 K) ln(2)- (2.00 mol)(5/3)(0.0821 L·atm/mol·K)(727.1 K) ln(VA/VD)- (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(727.1 K)+ (2.00 mol)(5/2)(0.0821 L·atm/mol·K)(600 K)

W = -966.2 J - 4957 J - 7476 J + 5154 J

    = -1979 J

Therefore, the total work done by the gas in one cycle is -1979 J

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why was the copernican model a controversial proposition

Answers

I believe this question refers to the extremely charged nature of his model. The world in his day was almost completely controlled by the Catholic Church. His heliocentric model suggested that the earth was not, indeed, the centeer of the universe, and Catholic officials and clergy took this to be a dirrect attack on the priveleged place they believed man held in God's plan.

An electron moves in a circular path with a speed of 1.26 ✕ 107 m/s in the presence of a uniform magnetic field with a magnitude of 1.90 mT. The electron's path is perpendicular to the field.
(a) What is the radius (in cm) of the circular path?
(b) How long (in s) does it take the electron to complete one revolution?

Answers

Answer:

Explanation:

To solve this problem, we can use the equation for the centripetal force experienced by a charged particle moving in a magnetic field:

F = (mv^2) / r

where:

F is the centripetal force,

m is the mass of the electron,

v is the velocity of the electron,

r is the radius of the circular path.

We also know that the centripetal force is provided by the magnetic force:

F = |q| * v * B

where:

|q| is the magnitude of the charge of the electron,

B is the magnitude of the magnetic field.

Setting the two equations equal to each other and solving for the radius (r), we have:

(mv^2) / r = |q| * v * B

Simplifying and rearranging for r:

r = (mv) / (|q| * B)

Given:

m = 9.11 x 10^-31 kg (mass of the electron)

v = 1.26 x 10^7 m/s (velocity of the electron)

|q| = 1.6 x 10^-19 C (charge of the electron)

B = 1.90 x 10^-3 T (magnetic field)

(a) Calculating the radius (r):

r = (9.11 x 10^-31 kg * 1.26 x 10^7 m/s) / (1.6 x 10^-19 C * 1.90 x 10^-3 T)

r ≈ 0.00296 m

Converting the radius to centimeters:

r = 0.00296 m * 100 cm/m

r ≈ 0.296 cm

The radius of the circular path is approximately 0.296 cm.

(b) To find the time it takes for the electron to complete one revolution, we can use the equation for the period (T) of circular motion:

T = 2πr / v

Given the radius (r) and velocity (v), we can calculate T:

T = (2π * 0.00296 m) / (1.26 x 10^7 m/s)

T ≈ 1.48 x 10^-7 s

The time it takes for the electron to complete one revolution is approximately 1.48 x 10^-7 s.

Given that An electron moves in a circular path with a speed of 1.26 ✕ 10^7 m/s in the presence of a uniform magnetic field with a magnitude of 1.90 mT. The electron's path is perpendicular to the field. The task is to find the radius (in cm) of the circular path and how long (in s) it takes the electron to complete one revolution.

(a) To calculate the radius of the circular path, we need to use the formula that is used to find the radius of the circular motion under the influence of a magnetic field.

R = mv/qBR = (1.6 x 10^-19 C)(1.26 x 10^7 m/s)/(1.6 x 10^-19 C)(1.90 x 10^-3 T)R = 5.27 x 10^-2 mConverting meter into cm.R = 5.27 x 10^-2 m x 100 cm/mR = 5.27 cm(b) We can calculate the time taken by the electron to complete one revolution using the following formula for the time period.T = 2πm/qBTT = (2 x π x m)/(qB)T = (2 x π x 9.11 x 10^-31)/(1.6 x 10^-19 C)(1.90 x 10^-3 T)T = 2.10 x 10^-7 sThus, the time taken by the electron to complete one revolution is 2.10 x 10^-7 s.

About Magnitude

The seismic magnitude scale is used to describe the overall strength or "size" of an earthquake. It is distinguished from the seismic intensity scale which categorizes the intensity or severity of ground shaking caused by earthquakes at a specific location.

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Which Combination of graphs best describes free-fall motion? [Neglect air resistance.]​

Which Combination of graphs best describes free-fall motion? [Neglect air resistance.]

Answers

The combination of the graphs that shows a free fall are A and C.

What is the description of free fall?

We know that motion has to do with the change of position with time. When an object is falling freely, the velocity of the object would remain constant because the velocity or the speed does not change.

Recall that when we throw objects down from a height, the objects would fall at the same rate irrespective of the masses of the objects. This can be understood to mean that the acceleration that acts on the objects is the same and does not change.

However, the distance that is covered by the object does change with tome and this can be seen from the graph as we have in the question. We can now see that the graph that has a flat speed time graph and a straight distance time graph can describe on object that is undergoing free fall.

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What is the effect of gravity on a falling object?​

Answers

Answer:

When objects fall to the ground, gravity causes them to accelerate.

A uniform meter stick has its center of mass exactly at 50 cm. During an experiment, it was found that the meter stick was at equilibrium when a mass of 50.0 g was hung from the 90 cm mark, and the fulcrum was placed at the 61.3 cm mark. What is the mass of the meter stick?

Answers

To solve this problem, we need to apply the principle of moments. Principle of moments states that for a body in equilibrium, the sum of the anti-clockwise moments about a point is equal to the sum of the clockwise moments about the same point.

The moments of the forces are obtained by multiplying the magnitude of the force by the perpendicular distance of its line of action from the point about which moments are being taken.Let the mass of the meter stick be m gramsThe 50 g mass is hanging from the 90 cm mark. The distance between the 90 cm mark and the center of mass (50 cm) is 40 cm. Similarly, the distance between the center of mass (50 cm) and the fulcrum (61.3 cm) is 11.3 cm. The total distance between the 90 cm mark and the fulcrum is (90 - 61.3) = 28.7 cm.According to the principle of moments, the anti-clockwise moments about the fulcrum is equal to the clockwise moments about the fulcrum.

Anti-clockwise moments = 50 × 28.7 grams.cm

\(Clockwise moments = m × 11.3 grams.cm50 × 28.7 = m × 11.3 m = (50 × 28.7) / 11.3 m = 127.4 grams\)

Therefore, the mass of the meter stick is 127.4 grams.

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who was albert einstien describe his contributions???

Answers

Answer:

Albert Einstein was from Germany he was born theoritical physicist, from childhood only he loved mechanical toys, he was highly gifted in Mathematics, He was a world citizen and a scientific genius too. His contribution were:

1) he developed the theory of relativity

2) he also discovered the process of nuclear fission

3)he developed the quantum theory of specific heat

4)theory of stimulated emission, on which laser device technology is based

5) law of photoelectric effect

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if peter expends 2,000 calories running a mile in one hour and samantha burns 1000 calories riding a bike in thirty minutes. who spent the greatest amount of energy during their exercise

Answers

Peter expended the greatest amount of energy during his exercise. He burned 2,000 calories running a mile in one hour, while Samantha burned 1,000 calories riding a bike in thirty minutes.

Peter spent the greatest amount of energy during his exercise compared to Samantha. While Samantha burned 1,000 calories riding a bike in thirty minutes, Peter burned 2,000 calories running a mile in one hour. Calories burned during exercise depend on various factors such as intensity, duration, and individual differences. In this case, Peter's exercise had a higher energy expenditure because he ran for a longer duration and covered a greater distance. Running typically requires more energy expenditure compared to biking due to the higher impact and engagement of larger muscle groups. Hence, Peter expended a greater amount of energy during his exercise session.

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What is the key difference between photoheterotrophs and photoautotrophs?.

Answers

Explanation:

What is the key difference between photoheterotrophs and photoautotrophs? Photoheterotrophs use organic compounds as their carbon source; photoautotrophs use carbon dioxide as their carbon source.

Given: NM 1 XZ
Prove: AXYZ- ANYM
N
Try 11
X
Z
M
We know that side NM is
to side
XZ. If we consider side NY the transversal for these
parallel lines, we create angle pairs. Using the
we can state
that YXZ is congruent to YNM. We know that angle
XYZ is congruent to angle
by the reflexive
property. Therefore, triangle XYZ is similar to triangle
NYM by the
similarity theorem.
F

Given: NM 1 XZProve: AXYZ- ANYMNTry 11XZMWe know that side NM isto sideXZ. If we consider side NY the

Answers

The prove of  Angle XYZ- Angle NYM is given below:

∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.

What is the triangle about?

Note that from the image given;

NM // XZNY = transversal line∠YXZ ≡ ∠YNM

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

∠XYZ is congruent to ∠NYM - reflexive property. ΔXYZ is the same with Δ NYM,- AA (angle-angle) similarity theorem.

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Answer:

1. parrael

2. corresponding angles theorem

3. NYM

4. AA

Explanation:

just took it

HURRY IM TIMED !!!!!!!!!!
Which two elements make up water?
oxygen and phosphorus
oxygen and hydrogen
hydrogen and sulfur
hydrogen and phosphorus

Answers

Answer:

The correct answer is oxygen and hydrogen

Answer:

oxygen and hydrogen

Explanation:

because h20 has 2 oxygen and 2 hydrogen

If the distance between two objects is 4.00 m and the distance is tripled, then what is the new distance? 3

Answers

If the distance between two objects is 4.00 m and the distance is tripled, then the new distance will be 12.00 m.

To find out the new distance, you need to multiply the original distance by the factor by which it is tripled, which is 3.In other words, if the distance between two objects is "d", and it is tripled, then the new distance is 3d.

Using this formula, if the original distance is 4.00 m, then the new distance will be 3 x 4.00 m = 12.00 m.

The new distance is three times the original distance.

Therefore, the new distance between the two objects will be 12.00 meters if the original distance was 4.00 meters and it was tripled.

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Abarber wants to set up asaloon in a room measuring length of 3m by 3 m. He has a simple wooden chair ,three large mirrors and one bulb. Using the knowledge of shadows and reflection, advise abarber on how to arrange a good saloon using the only items he has

Answers

To set up a good saloon, the barber should first place the wooden chair in the center of the room.

This will allow the barber to have easy access to all parts of the customer's head and face while cutting hair.Next, the barber should place one large mirror on the wall directly behind the chair so that the customer can see the back of their head while getting their hair cut. The other two mirrors should be placed on the walls on either side of the chair, angled towards the customer, so that they can see the sides of their head and face. The bulb should be placed directly above the chair, providing adequate lighting for the barber to see what they are doing.

By using reflections, the barber can ensure that the customer can see their entire head and face during the hair cutting process, leading to a better result.

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Helppp plzzzz.......A motor home starts across a lake. The lake is 7 miles long and it takes 0.5 hours to get across. What is the speed? Write a formulae and show a label.

Answers

speed=distance\time so try 14??

Question 6 of 10
A double-blind study is one in which neither the researchers nor the subjects
know which subjects are receiving the real treatment and which are receiving
the placebo. What is the purpose of this design?
A. It prevents researchers from formulating hypotheses.
B. It postpones the interpretation process.
C. It minimizes bias.
D. It minimizes subject frustration.
SUBMIT

Answers

It reduces bias if In a double-blind study, neither researchers nor the participants are aware of which interpretation method is being used, which patients are receiving the actual treatment, and which

The correct answer is C

What steps comprise the interpretation procedure?

taking in the source language, recognising the deep structural meaning, using a contextual/schema screen, formulating/practicing the target language utterance, and creating the interpretation.

What steps does a translator take?

An interpreter, as the name implies, converts high-level computer code into code that a machine can understand (machine code) or into a higher-level language that can be quickly executed. The interpreter reads every line of code before converting or directly executing it.

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