A car travels a distance of 540 km in 6 hours. What is the speed of the car?

Answer:

The answers are red bone marrow and blood vessels.

Explanation:

Bone marrow is made of stem cells. These stem cells make red bone marrow, which creates blood cells and platelets for your blood.

Answer:

horse

Explanation:

we have p=m.v

cheetah: p1=50.80=4000

horse: p2=500.80=40000

elephant: p3=5000.0=0

The 500 kg horse also running at 80 km/h  would have more momentum than others'.

The sum of a particle's mass and velocity is called momentum. Being a vector quantity, momentum possesses both magnitude and direction. According to Isaac Newton's second equation of motion, the force acting on the particle equals the time rate of change of momentum.

According to the question:

Momentum of 50 kg cheetah running at 80 km/h is = 50×80 kg.km/h

= 400 kg.km/h .

Momentum of a 500 kg horse running at 80 km/h is =  500×80 kg.km/h

= 4000 kg.km/h .

Momentum of a  5000 kg elephant at rest =  50×0 kg.km/h

= 0 kg.km/h .

Hence, The horse would have more momentum.

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Answer:

See below

Explanation:

All of the PE (mgh) will be converted to KE (1/2 mv^2)

mgh = 1/2 m v^2

gh = 1/2 v^2

2 gh = v^2

v = sqrt (2gh) = sqrt ( 2 * 9.81 * 45) = 29.7 m/s

Answer:

Surface density at distance r from the center is Σ(r) = (4r²n(r)dr) / (R² - z²).

Explanation:

To determine the surface density of a spherical galaxy when viewed from a great distance along the z-axis, we need to consider the stellar density profile and integrate it over the line of sight.

Let's denote the radius of the galaxy as R and the distance along the z-axis as z.

The stellar density profile, n(r), describes the number density of stars as a function of radial distance, r, from the center of the galaxy

Consider a thin spherical shell at radius r with thickness dr. The number of stars in this shell is given by dN = 4πr²n(r)dr, where 4πr² is the surface area of the shell and n(r) is the stellar density at that radius.

When we view the galaxy from the z-axis, we see the projected area of the shell onto the xy-plane. The projected area is a circle with radius R' = sqrt(R² - z²),

where R' is the projected radius of the shell. The projected area is given by dA = πR'².

The surface density, Σ(r), at distance r from the center can be calculated by dividing the number of stars in the shell by the projected area:

Σ(r) = dN / dA

Σ(r) = (4πr²n(r)dr) / (πR'²)

Σ(r) = (4r²n(r)dr) / (R'²)

To simplify the equation further, we substitute R'² = R² - z²:

Σ(r) = (4r²n(r)dr) / (R² - z²)

This is the expression for the surface density of a spherical galaxy when viewed from a great distance along the z-axis.

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The approximate average speed of the molecules in the gas If a sample of 4 mol of diatomic gas is measured to have a temperature of 290 K and the mass of the gas is 0.064 kg is 672 m/s (Option B).

To find the approximate average speed of the molecules in a sample of 4 mol of diatomic gas with a temperature of 290 K and a mass of 0.064 kg, we can use the equation:

KE_translational = (1/2)mv² = (3/2)nRT

where n is the number of moles, R is the gas constant (8.31 J/(mol·K)), and T is the temperature.

First, we find the molar mass:

molar_mass = 0.064 kg / 4 mol

= 0.016 kg/mol

Next, we solve for v²:

v² = (3 × R × T) / (molar_mass)

v² = (3 × 8.31 J/(mol·K) × 290 K) / (0.016 kg/mol)

Now, we take the square root to get the average speed:

v = √(v²)

v ≈ 672 m/s

So, the approximate average speed of the molecules in the gas is 672 m/s, which corresponds to option B.

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a) It takes you 1.893s to reach the opened door and jump in.

b) The maximum time that you can wait before starting to run and still catch the bus is 1.27s

The time which the passenger can delay and still catch the bus must be less than this.

From the question:

Distance between the passenger and the door of the bus d = 9

Acceleration of the bus a¹ = 1.0m/s²

Speed of the passenger v = 5.7m/s

Time taken for you to catch up with the bus must occur at the exact position with the bus,

Let the position = y

The time taken for you to reach the point:

t = total speed/distance

t = y + 9/5.7 ..................... eqn 1

The time taken for the bus to reach the same point;

y = vt + 1/2at²

Initial velocity of the bus is zero

y = 0.5*(1)t²

y = t²/2

t = √2y .......................eqn 2

We solve eqn (1) and (2) together:

9 + y = 5.7 * √2y

81 + y² + 18y = 64.98y

y² - 46.98y + 81 = 0

y = 45.187m or 1.792m

Now we take the smallest distance: x=1.792 m

Time taken for both to reach this point: (put x in eq. (1))

t = 1.792+9/5.7

t = 1.893s

For the maximum waiting time we find have:

Relative acceleration, ar = -1m/s⁻²since the bus is moving away from the intended

The final relative velocity for the passenger to catch it, vr = 0m/s⁻¹

Using equation of motion:

s = 9 + 1/2 * (-1)t²

also the initial relative velocity:

vr = ur + ar.t

ur = 5.7 - t

and

vr² = ur² + 2ar.s

0² = (5.7 - 1)² - 2 * 1 * (9 - 0.5t²)

t = 1.27s

Here's the complete question:

You are 9.0 m from the door of your bus, behind the bus, when it pulls away with an acceleration of 1.0 m/s2. You instantly start running toward the still-open door at 5.7 m/s.

How long does it take for you to reach the open door and jump in?

What is the maximum time you can wait before starting to run and still catch the bus?

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The shinny outer surface of an electric kettle reflects heat, which reduces energy loss. This helps to make the kettle more efficient, as it takes less energy to heat the water to the desired temperature.

What is the energy ?

Energy is the capacity for doing work. It is a fundamental concept in physics, and is defined as the ability to do work or transfer heat. It is a measurable quantity that can be converted into different forms, such as mechanical, electrical, thermal, chemical, or nuclear energy. Energy is necessary for all types of physical activities, including movement, growth, and development. It is also necessary for many natural processes, such as photosynthesis and respiration. In addition, energy is used to power many of the technologies we use in everyday life, such as computers and cars.

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Newton's law of universal Gravity:

F = G * (M1 * M2)/ r^2

Where:

G = gravitational constant = 6.674 x10^-11 Nm^2kg^2

M1 = mass 1 = 45.9 kg

M2 = mass 2 = 5.98 x 10 ^24 kg

r = Distance between the 2 objects = 6.38 x 10 ^6 m

Replacing;

F = 450.048 N

4.40 times 103 yd is not equivalent to 2.50 miles.

So, the correct answer is D.

To determine which of the given options is not equivalent to 2.50 miles, we need to convert 2.50 miles to the respective units given in the options.

2.50 miles is equivalent to 4.02 times 103 km, which rules out option (c).

Now, we need to convert 2.50 miles to ft and in to compare with options (a), (b), and (e). 2.50 miles = 1.32 times 104 ft, which matches option (a), so it is equivalent to 2.50 miles.

Finally,

2.50 miles = 1.32 times 104 ft = 1.58 times 105 in, which matches option (e).

Therefore, the answer is option (D), 4.40 times 103 yd, as it is not equivalent to 2.50 miles.

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Answer:

B. During the fall

Explanation:

There are 2 types of energies going into play when dropping something, potential energy and kinetic energy. potential energy is the height of the object before it is dropped. The ball has the most kinetic energy right before it hits the ground, then releases it when it does hit the ground.

Hmm lets see.. I think its

Mechanical---->Mechanical---->Electrical

So mechanical from the water, Then mechanical again from the wheel then through the wire which is electrical and it turns the fan on.

Answer:

this ans is 42.85

Explanation:

i dont not explain but i hipe you get it

Answer:Proton (charge of +e, in the nucleus), Neutron (0 charge, in the nucleus), and Electron (charge of –e, outside the nucleus).Nov 13, 2015

Explanation: YA

Protons are positive and in the center ( nucleus)

Neutrons have no charge and are also in the center (nucleus)

Electrons are negative and orbit around the nucleus

An ordinary flea with a mass of 220 μg weighs approximately 2.156 × 10^(-6) newtons.

To calculate the weight of the flea, we need to use the formula:

Weight = mass × acceleration due to gravity

The acceleration due to gravity on Earth is approximately 9.8 m/s².

First, let's convert the mass of the flea from micrograms (μg) to kilograms (kg):

So, the mass of the flea in kilograms is:

0.00022 grams × 0.001 kilograms/gram = 0.00000022 kilograms

Now, we need to determine the acceleration due to gravity. On Earth, this value is approximately 9.8 meters per second squared (m/s^2).

1 μg = 1 × 10^(-9) kg

Mass of the flea = 220 μg = 220 × 10^(-9) kg = 2.2 × 10^(-7) kg

Now, we can calculate the weight of the flea:

Weight = mass × acceleration due to gravity

= 2.2 × 10^(-7) kg × 9.8 m/s²

Weight = 2.156 × 10^(-6) N

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Answer:

\(F= \frac{GmM}{ {r}^{2} } \)

G= gravitational constant

F= Gravitational force

m= mass of object 1

M= mass of object 2

r= distance between two objects

Answer:

amplitude

Explanation:

amplitude of a wave is the maximum displacement of a point from its rest position.

hope you get it,

If one main-sequence star is three times as massive as another one, the ratio of their luminosities is 81:1

Massive stars are those with masses eight times or more than that of the Sun. They have higher core temperatures and densities, as well as shorter lifetimes compared to lower-mass stars.Massive stars consume their fuel at a faster rate than less massive stars. They therefore exhaust their fuel much more quickly, in just a few million years. This causes the star to expand and contract, resulting in violent outbursts such as supernovae.Expansion of the star leads to an increase in the size of its outer layers, resulting in a decrease in its surface temperature and luminosity. As a result, luminosity is not linearly proportional to mass, but rather to mass to the third power.Luminosity is determined by a star's mass, radius, and surface temperature. Luminosity (L) is proportional to the square of a star's radius (R) and the fourth power of its surface temperature (T).Luminosity = R²T⁴Therefore, if one main-sequence star is three times as massive as another one, the ratio of their luminosities is calculated as follows:Let's assume that the first star has a mass of m, a radius of r, and a surface temperature of t.

The second star has a mass of 3m, a radius of r/3, and a surface temperature of t.First star's luminosity is:L₁ = r²t⁴Second star's luminosity is:L₂ = (r/3)²(t)⁴= (r²/9) (t⁴)Luminosity ratio L₁/L₂ = r²t⁴/(r²/9)(t⁴) = 9/1Luminosity ratio L₁/L₂ = 81:1Therefore, if one main-sequence star is three times as massive as another one, the ratio of their luminosities is 81:1.

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Answer:

P V = N R T

P1 V1 = P2 V2      assuming N, R, and T remain constant

V1 = (P2 / P1) V2

V1 = (2 kPa / 4 k Pa) 3.5 m3

V1 = 3.5 m^3 / 2 = 1.75 m^3

Answer:

east

Explanation:

15km east

_______________

              X________

                    8km west

so you are where the xX is so you are still in the eastward direction

Answer:

Electric charge. A fundamental property that leads to the electromagnetic interactions among particles that make up matter.

Answer:

640

Explanation:

cause you should just add the 2

It takes 10 second the package to reach the ground.

The package reaches the ground after 10 second and  it was dropped 1500 m far from the package landing.

Given parameters:

Altitude of the plane; h = 490 m.

Initial horizontal velocity of the plane; u = 150 m/s.

We have to find; time taken by  the package to reach the ground: t =?

And,  horizontal distance covered by the package before land; d = ?

We know that a free falling object has acceleration equal to acceleration due to gravity = g = 9.8 m/s².

So,

h = 1/2gt²

⇒ t = √(2h/g) = √(2×490/9.8) second = 10 second.

In this time,

horizontal distance covered by the package before land; d = ut

= 150 m/s × 10 s

= 1500 m.

Hence, the package reaches the ground after 10 second and  it was dropped 1500 m far from the package landing.

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Answer:

The answer should be True, but it's False on Edge 2021

Explanation:

이것이 도움이 되었기를 바랍니다.

(✿◡‿◡)

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-Jiyen~

Answer:

K = (11*m*(ω*r)^2)/2

Explanation:

Not surprisingly, the formulas K = (1/2)*I*ω^2 and K = (1/2)*m*v^2 give the same result. They should, of course, since the rotational kinetic energy of a system of particles is simply the sum of the kinetic energies of the individual particles making up the system.

Since dehydration is due to lack of water, sweating excessively is Not a sign of extreme dehydration.

Dehydration is a condition in which the body lack a enough water necessary for metabolic activities.

Dehydration results in extreme physical conditions of the body such as fatigue.

Some signs of extreme dehydration include:

Therefore, sweating excessively is Not a sign of extreme dehydration.

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To find the average velocity on a velocity-time graph, you need to calculate the slope of the line connecting two points on the graph. The average velocity represents the change in velocity divided by the change in time between those two points.

To calculate the average velocity, you can use the formula:

Average velocity = (change in velocity) / (change in time)

You can determine the change in velocity by finding the difference between the final velocity and the initial velocity. The change in time is the difference in the time coordinates of the two points.

Select two points on the velocity-time graph, typically denoted by (t₁, v₁) and (t₂, v₂), where t represents time and v represents velocity. Then, substitute the values into the formula mentioned above to calculate the average velocity.

It's important to note that the average velocity provides information about the overall change in velocity over a specific time interval, rather than instantaneous velocity at a particular moment.

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The chemical reactivity of an atom is determined by the number of electrons present in its outermost shell, also known as the valence electrons.

These electrons play a key role in determining the chemical properties of an atom, such as its reactivity and bonding behavior. An atom with a full or nearly full valence shell is less likely to engage in chemical reactions, while an atom with a partially filled valence shell is more reactive and readily participates in chemical reactions. Thus, the number of electrons in the valence shell is a critical factor in determining the chemical reactivity of an atom. Chemical reactivity refers to the ability of a substance to participate in chemical reactions and form new compounds. It is determined by various factors, including the arrangement of electrons in the outermost shell (valence electrons), the stability of the electronic configuration, and the energy required to break or form chemical bonds.

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The light is brighter in a battery-powered torch, you should change the wattage or power rating of the bulb. A higher-wattage bulb will produce more light and therefore be brighter. When selecting a new bulb for the torch, make sure to choose a bulb with a higher wattage rating than the current bulb.

A battery is an electrochemical device that converts chemical energy into electrical energy through a chemical reaction. It consists of one or more electrochemical cells, each of which contains a positive electrode (cathode), a negative electrode (anode), and an electrolyte that allows ions to move between the two electrodes.

During the discharge process, a chemical reaction takes place within the battery that causes electrons to flow from the negative electrode through an external circuit to the positive electrode, generating an electrical current. This current can then be used to power a wide range of electrical devices, such as flashlights, smartphones, and cars. The chemical reaction can be reversed by recharging the battery, which involves applying an external electrical current to the electrodes to force the reaction to occur in the opposite direction.

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Since the rebound speed is one-half the speed it had just before hitting the floor, it will rise to 1/4 of the original height from which it was dropped; option C.

Rebound speed refers to the speed at which a body when it hits a surface is returned or rebounded to the original direction in which it comes from.

When objects are released from a height and allowed to hit the floor, some of the original energy of the object is converted to heat and sound, thus the object will rebound with a lesser speed and to a smaller height than from which it is released.

In the case of a rubber ball which is dropped on the floor. The rebound speed is one-half the speed it had just before hitting the floor.

Therefore, the height will be one-quarter the original height.

In conclusion, the rebounding of a ball is to a lesser height than the original height.

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Life tables summarize the probabilities of survival and mortality for individuals of different age groups within a population.

By studying the life history of endangered species, ecologists can identify critical life stages and factors influencing population declinesLife Tables show how long different age groups are likely to live, and how many people survive at each age.

By examining life tables, ecologists can:

Survivorship curves show how many individuals in a population survive over a period of time.

Ecologists who study animals that are in danger of becoming extinct, like red pandas, use life tables and survivorship curves to learn many things.

Life tables assist us in comprehending the variations in the size of a population, death rates that correspond to specific age groups, and the complete biography of a species.

Survivorship curves visually illustrate the proportion of individuals who survive at each age throughout their lives. They provide a depiction of the typical mortality trends present in a group of individuals and aid in recognizing unique approaches to survival.

Survivorship curves show how many individuals in a population survive over a period of time. They make a graph that shows how many people are still alive at each age. Survivorship curves show how many animals or people will survive or die in a population over time.

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In order to draw the ray diagram, let's draw two rays: one parallel to the lens axis, which will pass through the focus of the lens, and one passing through the center of the lens.

Drawing the ray diagram of this question, we have:

In order to calculate the magnification, first let's calculate the image position:

The magnification is given by: