A chemical compound requires 24 oz of Chemical A and 30 oz of Chemical B. How much
Chemical A is needed of you have 12 oz of Chemical B?

Answer: False

Step-by-step explanation:

Discrete means secret and that data is not discrete as it can be acess by anyone.

True. The amount of rainfall in your state last month is an example of discrete data.

The answer to the question is True. The amount of rainfall in a state last month is an example of discrete data.

Discrete data is a type of data that can only take on specific values. In this case, the amount of rainfall can be measured in specific units, such as inches or millimeters, and cannot have values between those units.

Other examples of discrete data include the number of students in a classroom, the number of cars passing through a toll booth, or the number of coins in a piggy bank.

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Answer:

90

hope this helps!:)

Step-by-step explanation:

(a) The derivative of f(x) = 1/x - sin(x) is f'(x) = -1/x^2 - cos(x).

To differentiate the function f(x) = 1/x - sin(x), we need to find the derivative of each term separately and then combine them using the rules of differentiation.

The derivative of 1/x with respect to x can be found using the power rule for derivatives. Since 1/x can be written as x^(-1), the power rule states that the derivative is equal to -1 times the coefficient (-1) multiplied by the original power (-1-1 = -2). Therefore, the derivative of 1/x with respect to x is -1/x^2.

The derivative of sin(x) with respect to x can be found using the chain rule. The derivative of sin(x) is cos(x), and since there is no function inside the sin function, the derivative of x is simply 1. Therefore, the derivative of sin(x) with respect to x is cos(x).

Now we can combine the derivatives of the two terms. The derivative of f(x) = 1/x - sin(x) is f'(x) = -1/x^2 - cos(x).

(b) The derivative of g(x) = 2 + cos^2(x) is g'(x) = -2sin(x)cos(x).

To differentiate the function g(x) = 2 + cos^2(x), we need to apply the chain rule and the power rule for derivatives.

The derivative of the constant term 2 is 0, as the derivative of a constant is always 0.

To differentiate cos^2(x), we can rewrite it as (cos(x))^2. The power rule states that the derivative of (cos(x))^n with respect to x is n(cos(x))^(n-1) * (-sin(x)), where n is the power. In this case, n = 2, so we have 2(cos(x))^(2-1) * (-sin(x)) = 2cos(x)(-sin(x)) = -2sin(x)cos(x).

Now we can combine the derivatives of the two terms. The derivative of g(x) = 2 + cos^2(x) is g'(x) = -2sin(x)cos(x).

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Answer:

id go 48 The circumference is 16π cm, about 50.27 cm.

Step-by-step explanation:

diameter: 16 cm

circumference: 16π cm ≈ 50.27 cm

Step-by-step explanation:

The diameter is twice the radius:

 d = 2r = 2(8 cm)

 d = 16 cm

The diameter is 16 cm.

__

The circumference is pi times the diameter.

 C = πd

 C = π(16 cm)

 C = 16π cm ≈ 50.27 cm

a). The percent of phones with a battery life of at least 4 hours and 45 minutes is 25%.

b). The percent of phones with a battery life between 4.5 hours and 5.25 hours is 37.5%. and

c). The percent of phones with a battery life less than 5 hours or greater than 5.5 hours is 45%.

The distribution of talk-time battery life of the group of cell phones is approximately a normal distribution with a mean of 5 hours and a standard deviation of 15 minutes.  

a. The percent of phones with a battery life of at least 4 hours and 45 minutes is:

= (0.5) x (1 - (0.15/3))

= 0.25 or 25%.

b. The percent of phones with a battery life between 4.5 hours and 5.25 hours is:

= (0.5) x [(0.375 - 0.15)/3]

= 0.375 or 37.5%.

c. The percent of phones with a battery life less than 5 hours or greater than 5.5 hours is:

= (0.5) x (1 + (0.15/3))

= 0.45 or 45%.

Therefore, the distribution of talk-time battery life of the group of cell phones is approximately a normal distribution with a mean of 5 hours and a standard deviation of 15 minutes.  

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Answer:

e, i think 14.40

Step-by-step explanation:

Answer: 103.96

Step-by-step explanation:

The unit tangent vector T and the curvature k is √2/3

Unit Tangent Vector and Curvature are two important concepts in vector calculus that are used to describe the behavior of curves in space.

To find the Unit Tangent Vector, we must first find the derivative of the curve. The curve is defined as (t) = <9 cos t, 9 sin t, √(3) t>, so taking the derivative with respect to t, we get:

d(t) / dt = < -9 sin t, 9 cos t, √(3) >

Next, we want to normalize this vector to get the Unit Tangent Vector, T. To do this, we divide the vector by its magnitude, which is given by:

=> √((-9 sin t)² + (9 cos t)² + (√(3))²)

=> √(81 + 81 + 3) = 9 √(3)

So, the Unit Tangent Vector is given by:

T = d(t) / dt / |d(t) / dt|

T = < -9 sin t / 9 √(3), 9 cos t / 9 √(3), √(3) / 9 √(3) >

T = < -sin t / √(3), cos t / √(3), 1 / 3 √(3) >

To find the Curvature, we use the formula:

k = |dT / dt|

where T is the Unit Tangent Vector and dT / dt is the derivative of the Unit Tangent Vector. To find dT / dt, we take the derivative of T with respect to t:

dT / dt = < cos t / √(3), -sin t / √(3), 0 >

Finally, the magnitude of dT / dt gives us the Curvature:

=> √((cos t / √(3))² + (-sin t / √(3))² + (0)²)

=> √(1 / 3 + 1 / 3) = √(2 / 3) / √(3)

So, the Curvature is given by:

k = √(2 / 3) / √(3)

k = √2 / 3

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The median remains unchanged at $55,000 even after the change in the largest number.

The median is a measure of central tendency that represents the middle value in a data set when arranged in ascending or descending order. It is not affected by extreme values or outliers.

In the given scenario, we have 10 employees with salaries originally ranging from the lowest to the highest. The original median is $55,000.

If the largest number on the list is changed from $100,000 to $1,000,000, it becomes an extreme value or outlier. However, since the median is not affected by extreme values, the median remains the same as $55,000 even after the change.

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The value of the 3rd term in the expansion of (x+6) ^6 will be as follows:

540x^4

What is expansion?

Expanding brackets, also known as multiplying out, seeks to eliminate the set of brackets by multiplying each phrase inside a bracket by the term on the outside and subsequently accumulating similar phrases. When solving equations, extending brackets, which is the opposite of factorization, is frequently an essential step.

Here in the question,

We have,

(x+6) ^6

Expanding it we get:

= x^6 + 36x^5 + 540x^4 +4320x³ + 19440x² + 46656x + 46656

So, the 3rd term of the expansion is 540x^4.

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The value of the 3rd term in the expansion of \((x+6) ^6\) will be as follows: \(540x^4\). The correct answer is option (c).  \((6\ \ 4)36x^4\)

By multiplying each phrase inside a bracket by the word on the outside and then accumulating similar phrases, expanding brackets, also known as multiplying out, aims to eliminate the set of brackets. Extending brackets, which is the opposite of factorization, is frequently a crucial stage in the solution of equations.

An affine transformation termed expansion, in which the scale is expanded, is also referred to as an enlargement or dilation. It is also sometimes referred to as an enlargement and is the polar opposite of a geometric constriction.

Here in the question,

We have,

\((x+6) ^6\)

Expanding it we get:

\(= x^6 + 36x^5 + 540x^4 +4320x^3 + 19440x^2 + 46656x + 46656\)

So, the 3rd term of the expansion is \(540x^4\).

The correct answer is option (c). \((6\ \ 4)36x^4\)

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The correct statements regarding the steps Jorge could take to complete the reflection are:

1) Jorge should graph in the vertical line with values of -4 for the line of reflection.

2) Jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection.

3) Jorge could count how far each vertex of the figure is from the y-axis and count the same distance on the other side.

4) Jorge will not move any point that lies on the line of reflection.

5) Jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection.

6) Jorge could check his work by making sure that the image has the same orientation as the original.

To complete the reflection of a figure across the line y = -4, Jorge can take the following steps:

1) Jorge should graph the vertical line y = -4 as the line of reflection. This line represents the axis of reflection, and all points on this line will remain fixed in their positions after the reflection.

2) Jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection. This will help him determine the distance and direction each point should move to reflect across the line.

3) Jorge could count how far each vertex of the figure is from the y-axis and count the same distance on the other side. Since the line of reflection is y = -4, which is parallel to the y-axis, he can use the distance from the vertex to the y-axis as a guide to placing the reflected point on the other side of the line.

4) Jorge will not move any point that lies on the line of reflection. Points on the line of reflection will remain fixed in their positions as they are symmetric to themselves across the line.

5) Jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection. In a reflection, the midpoint of each line segment connecting a point and its reflection will lie on the line of reflection. Checking this property helps ensure the accuracy of the reflection.

6) Jorge could check his work by making sure that the image has the same orientation as the original. The orientation refers to the arrangement or direction of the figure's components (e.g., angles, lengths, shapes). If the image retains the same orientation as the original, it indicates a correct reflection.

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Question

Jorge needs to reflect a figure across the line y = negative 4. Which statements are correct regarding steps he could take to complete the reflection? Check all that apply.

1) Jorge should graph in the vertical line with values of –4 for the line of reflection.

2) Jorge could count how far each pre-image point is from the line of reflection along the perpendicular from the point to the line of reflection.

3) Jorge could count how far each vertex of the figure is from the y-axis and count the same distance on the other side.

4) Jorge will not move any point that lies on the line of reflection.

5) Jorge could check his work by seeing if each segment joining a pre-image point with its image has the midpoint on the line of reflection.

6) Jorge could check his work by making sure that the image has the same orientation as the original.

Answer:

33-3 = 30

30 ÷ 5 = 6

Step-by-step explanation:

Therefore, the area between the large loop and the small loop of the curve r = 2 + 4cos(3θ) is 70π/3.

To find the area between the large loop and the small loop of the curve, we need to find the points of intersection of the curve with itself.

Setting the equation of the curve equal to itself, we have:

2 + 4cos(3θ) = 2 + 4cos(3(θ + π))

Simplifying and solving for θ, we get:

cos(3θ) = -cos(3θ + 3π)

cos(3θ) + cos(3θ + 3π) = 0

Using the sum to product formula, we get:

2cos(3θ + 3π/2)cos(3π/2) = 0

cos(3θ + 3π/2) = 0

3θ + 3π/2 = π/2, 3π/2, 5π/2, 7π/2, ...

Solving for θ, we get:

θ = -π/6, -π/18, π/6, π/2, 5π/6, 7π/6, 3π/2, 11π/6

We can see that there are two small loops between θ = -π/6 and π/6, and two large loops between θ = π/6 and π/2, and between θ = 5π/6 and 7π/6.

To find the area between the large loop and the small loop, we need to integrate the area between the curve and the x-axis from θ = -π/6 to π/6, and subtract the area between the curve and the x-axis from θ = π/6 to π/2, and from θ = 5π/6 to 7π/6.

Using the formula for the area enclosed by a polar curve, we have:

A = 1/2 ∫[a,b] (r(θ))^2 dθ

where a and b are the angles of intersection.

For the small loops, we have:

A1 = 1/2 ∫[-π/6,π/6] (2 + 4cos(3θ))^2 dθ

Using trigonometric identities, we can simplify this to:

A1 = 1/2 ∫[-π/6,π/6] 20 + 16cos(6θ) + 8cos(3θ) dθ

Evaluating the integral, we get:

A1 = 10π/3

For the large loops, we have:

A2 = 1/2 (∫[π/6,π/2] (2 + 4cos(3θ))^2 dθ + ∫[5π/6,7π/6] (2 + 4cos(3θ))^2 dθ)

Using the same trigonometric identities, we can simplify this to:

A2 = 1/2 (∫[π/6,π/2] 20 + 16cos(6θ) + 8cos(3θ) dθ + ∫[5π/6,7π/6] 20 + 16cos(6θ) + 8cos(3θ) dθ)

Evaluating the integrals, we get:

A2 = 80π/3

Therefore, the area between the large loop and the small loop of the curve r = 2 + 4cos(3θ) is:

A = A2 - A1 = (80π/3) - (10π/3) = 70π/3

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Scenario 1A:

Coinsurance amount is $90

Medicare payment is $360

Provider write-off is $290

Scenario 1B:

Remaining amount for Insurance and patient to pay is $350

Coinsurance amount is $70

Total paid by patient is $170

Medicare payment is $280

Provider write-off is $370

Scenario 1A:

Submitted charge: $650

Medicare participating physician fee schedule (PFS): $450

Coinsurance amount (20% paid by patient): $

Medicare payment (80% of the PFS): $

Provider write-off: $

To calculate the missing amounts, we can use the provided information:

Coinsurance amount (20% paid by patient):

Coinsurance amount = 20% of the Medicare participating physician fee schedule (PFS)

Coinsurance amount = 0.2 * $450 = $90

Medicare payment (80% of the PFS):

Medicare payment = 80% of the Medicare participating physician fee schedule (PFS)

Medicare payment = 0.8 * $450 = $360

Provider write-off:

Provider write-off = Submitted charge - Medicare payment

Provider write-off = $650 - $360 = $290

Scenario 1B:

Submitted charge: $650

Medicare participating physician fee schedule (PFS): $450

Patient pays $100 remaining on their deductible

Remaining amount for Insurance and patient to pay: $

Coinsurance amount (20% of remaining amount): $

Total paid by patient (deductible & 20% of remaining): $

Medicare payment (80% of the remaining amount): $

Provider write-off: $

To calculate the missing amounts, we can use the provided information:

Remaining amount for Insurance and patient to pay:

Remaining amount for Insurance and patient to pay = PFS - remaining deductible

Remaining amount for Insurance and patient to pay = $450 - $100 = $350

Coinsurance amount (20% of remaining amount):

Coinsurance amount = 20% of the remaining amount

Coinsurance amount = 0.2 * $350 = $70

Total paid by patient (deductible & 20% of remaining):

Total paid by patient = remaining deductible + coinsurance amount

Total paid by patient = $100 + $70 = $170

Medicare payment (80% of the remaining amount):

Medicare payment = 80% of the remaining amount

Medicare payment = 0.8 * $350 = $280

Provider write-off:

Provider write-off = Submitted charge - Medicare payment

Provider write-off = $650 - $280 = $370

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The sides are  

6  inches,  8 inches and  10  inches

I'd suggest that the question should read 'The perimeter of a triangle is 24 inches. The longest side is 4 inches longer than the shortest side, and the shortest side is three-fourths the length of the middle side. How do you find the length of each side of the triangle?'

Then the shortest side is  

6

and the longest side is  

10

Answer:

x ≥ 2

Step-by-step explanation:

21 ≤ 3 + 9x

21 - 3 ≤ 9x

18 ≤ 9x

18 ÷ 9 ≤ x

2 ≤ x

x ≥ 2

The solution to the inequality 21 ≤ 3 + 9x by combining like terms and solving for x is, x ≥ 2.

Used the concept of inequality which states that,

A relation by which we can compare two or more mathematical expressions is called an inequality.

Given that,

The inequality is,

21 ≤ 3 + 9x

Now, simplify the inequality by combining like terms and solving for x,

21 ≤ 3 + 9x

Subtract 3 on both sides,

21 - 3 ≤ 9x

18 ≤ 9x

It can be written as,

9x ≥ 18

9x - 18 ≥ 0

Take 9 as common,

9 (x - 2) ≥ 0

x - 2 ≥ 0

Therefore, the solution of expression is,

x  ≥ 0

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Answer:

190,050

Step-by-step explanation:

362 x 525 = 190,050

brainliest pls

Answer:

b when b³ = 8

Step-by-step explanation:

Value of c when c² = 8 :-

\(c^2 = 8\\=> c = \sqrt{8} = 2\sqrt{2} = 2.828\)

Value of d when d³ = 9 :-

\(d^3 = 9 \\=> d = \sqrt[3]{9} = 2.080\)

Value of b when b³=8

\(b^3 = 8\\=> b = \sqrt[3]{8} = 2\)

Value of a when a² = 9

\(a^2 = 9\\=> a = \sqrt{9} = 3\)

Comparing all the values of a , b , c , & d ..... we find that value of b is the least

Answer:

smart

Step-by-step explanation:

Therefore, all possible values of aa that satisfy the conditions are aa such that a<34a<43​.

To find all possible values of aa such that the quadratic equation ax2+(2a+2)x+a+3=0ax2+(2a+2)x+a+3=0 has two roots with a distance greater than 1 on the number line, we can use the discriminant.

The discriminant of a quadratic equation ax2+bx+c=0ax2+bx+c=0 is given by Δ=b2−4acΔ=b2−4ac. For the equation to have two distinct real roots, the discriminant must be greater than 0.

In our case, the discriminant is Δ=(2a+2)2−4a(a+3)=4a2+8a+4−4a2−12a=−4a+4Δ=(2a+2)2−4a(a+3)=4a2+8a+4−4a2−12a=−4a+4.

For the equation to have two distinct roots with a distance greater than 1, we want Δ>12Δ>12, which simplifies to −4a+4>1−4a+4>1.

Solving this inequality, we have −4a>−3−4a>−3, which leads to a<34a<43​.

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Answer:

should be 96 degrees

Step-by-step explanation:

Answer:100

Step-by-step explanation:

Answer:

CM = 16

MD = 16

CD = 32

Step-by-step explanation:

To find the value of x

3x + 1 = 8x - 24 (we know that M is the mid point so both of the lines will be equal)

Transpose

1 + 24 = 8x - 3x

25 = 5x

x = 25/5

x = 5

CM = 3x + 1

      = 3(5) + 1

      = 15 +1

     = 16

MD = 8x - 24

       = 8(5) - 24

       = 40 - 24

       = 16

CD = CM + MD

      = 16 + 16

      = 32

5000 square feet is the largest area that can be enclosed

It is given that a rectangular plot is to be fenced off and divided into three parts/plots on land that borders a barn there are and there is 200 feet of fence that is available.

One-fourth of the perimeter = 50

The other width also equals 50.

So the length of fencing = 200 - 50 - 50 = 100

So the area = 50 x 100 = 5000 square feet.

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Answer:

It should be between 20 and 30... is there anything missing with the 24?

its d i took the test

In the given scenario, where there is one infinitely long track and overtaking is impossible, the initial situation consists of three equally spaced trains, each moving at a different speed. The trains have the capability to link up when one catches up to the other, resulting in a single train moving at the speed of the slower train.

As the trains move, they will eventually reach a configuration where the fastest train catches up to the middle train. At this point, the fastest train will link up with the middle train, forming a single train moving at the speed of the middle train. The remaining train, which was initially the slowest, continues to move independently at its original speed. Over time, the process continues as the new single train formed by the fastest and middle trains catches up to the remaining train. Once again, they link up, forming a single train moving at the speed of the remaining train. This process repeats until all the trains eventually merge into a single train moving at the speed of the initially slowest train. In summary, on this strange railway line, where trains can only link up and cannot overtake, the initial configuration of three equally spaced trains results in a sequence of mergers where the trains progressively combine to form a single train moving at the speed of the initially slowest train.

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The derivative of the function f(x) = -5e^(xsinx) is f'(x) = (-5e^(xsinx)) * (cosx + xsinx).

To find the derivative of the function f(x) = -5e^(xsinx), we can apply the chain rule. The chain rule states that if we have a composite function, we can find its derivative by multiplying the derivative of the outer function with the derivative of the inner function.

In this case, the outer function is -5e^u, where u = xsinx, and the inner function is u = xsinx.

The derivative of the outer function -5e^u is simply -5e^u.

Now, we need to find the derivative of the inner function u = xsinx. To do this, we can apply the product rule, which states that the derivative of a product of two functions is the derivative of the first function times the second function plus the first function times the derivative of the second function.

The derivative of xsinx is given by (1*cosx) + (x*cosx), which simplifies to cosx + xsinx.

Therefore, the derivative of f(x) = -5e^(xsinx) is f'(x) = (-5e^(xsinx)) * (cosx + xsinx).

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The equation you provided, (x²)(y⁵) = 2, represents a curve in the plane. To describe the set of all points (x, y) that satisfy this equation, we need to analyze the behavior of the equation and examine the properties of the curve it represents.

The equation is a product of two terms: (x²) and (y⁵). This means that for any point (x, y) on the curve, both of these terms must multiply together to equal 2. As a result, the equation does not represent a simple geometric shape like a line or a circle but rather a more complex curve.

Since the term (x²) is squared, it will always be positive or zero, regardless of the value of x. On the other hand, the term (y⁵) is raised to an odd power, which means it can take positive, negative, or zero values depending on the sign of y.

Considering the equation (x²)(y⁵) = 2, there are multiple ways for the product of (x²) and (y⁵) to equal 2. For instance, we could have (x²) = 1 and (y⁵) = 2, or (x²) = 2 and (y⁵) = 1, or even (x²) = 0.5 and (y⁵) = 4, and so on. The possibilities for x and y values are infinite.

Overall, the set of all points (x, y) in the plane that satisfy the equation (x²)(y⁵) = 2 is a complex curve with various branches and regions, where the x-coordinate squared and the y-coordinate to the power of five combine to produce a product of 2. Without further constraints or limits, it is difficult to provide a more specific description of this set of points.

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It tells you they are similar. This means the angles are the same, and the sides are proportionate.

Look at the 12 and 4 at the very bottom. This tells you the ratio of the sides. Since 12 / 4 = 3, you can find y with 2 * 3 which is 6.

From that, you also know that 3z = 3y - 2. Substitute the value of y in and you can find z.

Corresponding angles are exactly the same. which means, (3x)° = 100°

You should get x = 33 1/3, y = 6, z = 5 1/3

Answer:

x=17 degrees

Step-by-step explanation:

All 3 angles = 180 degrees

So 90 + 54 + (x+19) = 180

Combine like terms

163 + x = 180

Subtract 163 from both sides

x = 180-163

x = 17

The solution of the DTDS is xn = (0.63)^n * 41 grams, where n represents time in hours.

a) The updating function f(x) for the discrete time dynamical system (DTDS) can be derived from the given information that the body eliminates 37% of the alcohol present in the body per hour.

Since 37% of the alcohol is eliminated, the amount remaining after one hour can be calculated by subtracting 37% of the current amount from the current amount. This can be expressed as:

f(x) = x - 0.37x

Simplifying the equation:

f(x) = 0.63x

b) The initial condition for the DTDS is given as Peter having 41 grams of alcohol in his body after consuming three alcoholic drinks. Therefore, the initial condition is:

x0 = 41 grams

c) To find the solution of the DTDS with the given initial condition, we can use the updating function f(x) and iterate it over time.

For n hours, the solution is given by:

xn = f^n(x0)

Applying the updating function f(x) repeatedly for n times:

xn = f(f(f(...f(x0))))

In this case, since the function f(x) is f(x) = 0.63x, the solution can be written as:

xn = (0.63)^n * x0

Substituting the initial condition x0 = 41 grams, the solution becomes:

xn = (0.63)^n * 41 grams

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