A child pulls on wagon with force of 20 N if the wagon models a total of 10 M in four seconds what is the average power generated by the child in watts

Answers

Answer 1

Answer:

\(power = \frac{(force \times distance)}{(time)} \\ power = \frac{(20 \times 10)}{4} \\ power = \frac{200}{4} \\ power = 50 \: watts\)


Related Questions

physics as a subject involves measurement and estimation,giving examples of everyday life situations, explain the meaning and what is done in each case​

Answers

Answer:

57

Explanation:

Put the events in order to explain how radios work.
Radio waves are converted to sound waves
Sound waves are changed into electrical
Radio waves are released by transmitter
by radios
signals by microphones.
towers.

Answers

Answer:

1. Sound waves are changed into electrical

2. Radio waves are released by transmitter

by radios

3. Radio waves are converted to sound waves

Explanation:

Answer:

The person in front of me is right

Explanation:

There’s my proof

Put the events in order to explain how radios work.Radio waves are converted to sound wavesSound waves

a box sliding to the right across a frictinonless surface begins with a kinetic energy of 12 j. if the box then encounters a rough spot on the floor which applies a frictional force of 2 n to the left over a 0.25 m distance, what is the kinetic energy of the box after it has slid through the rough spot?

Answers

The kinetic energy of the box after it has slid through the rough spot is 12.5 J.

The initial kinetic energy of the box is 12 J.

When the box encounters the rough spot on the floor, a frictional force of 2 N acts on it in the opposite direction to its motion. The work done by this frictional force is:

work done by friction = force x distance x cos(theta)

where "theta" is the angle between the force and the displacement, which is 180 degrees in this case (since the force is opposite to the direction of motion). Therefore, cos(theta) = -1.

Plugging in the values, we get:

work done by friction = 2 N x 0.25 m x (-1) = -0.5 J

Since the work done by the frictional force is negative, it reduces the kinetic energy of the box. Therefore, the final kinetic energy of the box is:

final kinetic energy = initial kinetic energy - work done by friction

final kinetic energy = 12 J - (-0.5 J) = 12.5 J

Therefore, the kinetic energy of the box after it has slid through the rough spot is 12.5 J.

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A brick, milk, and ice cubes are all examples of matter.​

Answers

true because

brick: solid

milk: liquid

ice cube: solid

This would be true. All liquids, solids, are gases are matter. :)

You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.

Answers

In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.

However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.

It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.

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You arrive in my class 45 seconds after leaving math which is 90 meters away. How fast did you travel?

Answers

Answer:

2m/s

Explanation:

speed = distance÷time

speed =90÷45=2m/s

a 30 kg cart is travelling in a zero friction environment at a constant velocity of 5m/s. It's about to go up a very steep hill. How high will the cart be when the velocity changes to zero? PLEASE HELP

Answers

Answer:

1.27551m

Explanation:

This is a simple energy convertion problem. Since there is no friction, and assuming no air drag and other external factors, mechanical energy should be conserved in this system.

Thus, we get:

\(KE_{initial} + PE_{initial} = KE_{final} + PE_{final}\)

We also know that the gravitational potential energy is equal to mgh, while the KE can be calculated using \(\frac{1}{2}mv^2\)

One thing to note here, is that the final KE will be 0, as there is no velocity at the end. Furthermore, we also can set the initial PE as 0 as we are looking at relative height, and at the start it is at h=0.

\(KE_{initial} = PE_{final}\)

Plugging in:

\(\frac{1}{2}*30*5^2 = 30*9.8*h\)

Solving for h, we get 1.27551m

A barrel of oil contains roughly 6.1×109 J. How many kW-hr is this? Answer in units of kW-hr

Answers

Answer: 1.6958*10^3 kW-hr

Explanation:

The barrel of oil contains around 6.1*10^9 J of energy.

We want this energy expressed in kW-hr.

We know that:

1J = 2.78*10^(-7) kW-hr

Then  6.1*10^9 J will be equal to 6.1*10^9  times the above amount.

This is:

E =  (6.1*10^9)*(2.78*10^(-7) kW-hr) = (6.1*2.78)*(10^9*10^(-7)) kW-hr

  = 16.958*10^(9 - 7) kW-hr

  =  16.958*10^2 kW-hr

  = 1.6958*10^3 kW-hr

Energy is the ability to do work. There are a few types of energy, these types are as follows:-

Heat enegyWind energyLight energy

The barrel of oil contains around 6.1*10^9 J of energy.  We want this energy expressed in kW-hr.

One joule of energy has   1J = 2.78*10^(-7) kW-hr .

Therefore, the \(6.1*10^9\)J will be equal to \(6.1*10^9\) times the above amount.

Hence, the energy will be

E =  \((6.1*10^9)*(2.78*10^7 )\)  

 =\(16.958*10^9-7\)

=  \(1.6958*10^3 kW-hr\)

Hence, the correct option is    \(1.6958*10^3 kW-hr\)

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A tap supplies water at 26°c while another supplies at 82°c. If a man wishes to bath with water at 40°c, what is the ratio of the mass of hot water to that of cold water

Answers

Where a tap supplies water at 26°c while another supply at 82°c. If a man wishes to bath with water at 40°c, then the ratio of the mass of hot water to that of cold water is: 1/3.

What is the rationale for the above response?

The ratio of the mass of hot water to that of Cold water is determined as follows:

M₁C (82  40) = M₂C (40-26)

Where M₁C is the Mass of Tap 1; and

M₂C is the Mass of Tap 2.

Thus,

M₁C (82  40) = M₂C (40-26)

M₁/M₂ = 14/42

= 1/3

Thus, it is right to state that the ratio of the mass of hot water to that of cold water is: 1/3.

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A load of 20N on a wire of cross sectional area 8*10-7m2 produces an extension of 10-4m. Calculate the Young's modules for the material of the wire if its length is 3m

Answers

Young's modulus is defined as the ratio of the tensile or compressive stress to the longitudinal strain of a body.  Young's modulus of the wire is 1.5 x 10¹¹ N/m².

The symbol for Young's modulus is Y or E, and its unit is N/m² or Pascal (Pa). The formula to calculate Young's modulus is given by:E = (F/A) / (ΔL/L)whereF is the tensile or compressive force appliedA is the cross-sectional area of the wireΔL is the extension or compression of the wireL is the original length of the wireFrom the given question, we have:F = 20 NA = 8 x 10⁻⁷ m²ΔL = 10⁻⁴ mL = 3mSubstituting the given values in the formula of Young's modulus:E = (F/A) / (ΔL/L)E = (20 N / 8 x 10⁻⁷ m²) / (10⁻⁴ m / 3 m)E = (20 N / 8 x 10⁻⁷ m²) x (3 m / 10⁻⁴ m)E = 1.5 x 10¹¹ N/m²Therefore, the Young's modulus of the wire is 1.5 x 10¹¹ N/m².

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when considering capacitors in series and in parallel, which values stay the same throughout the circuit? select all that are true.

Answers

When capacitors are connected in series or in parallel, the following values remain the same: Voltage across capacitors in parallel, Charge on capacitors in series. Both the options are true.

When capacitors are connected in parallel, they are connected to the same two points in the circuit, which means that they have the same potential difference or voltage across them. This is because the voltage across each capacitor is determined by the voltage of the power source that is connected to the circuit.

On the other hand, when capacitors are connected in series, they have the same charge on them. This is because in a series circuit, there is only one path for the current to flow through, which means that the same amount of charge has to pass through each capacitor.

The charge on a capacitor is directly proportional to the voltage across it, and since the voltage across capacitors in series is divided among them according to their capacitance, the charge on each capacitor is the same.

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The probable question may be:

when considering capacitors in series and in parallel, which values stay the same throughout the circuit? select all that are true. Voltage across capacitors in parallel, Charge on capacitors in series.

Mr. Bari drops a 3 kg ball from 1 feet above the glass. Find the velocity of the ballwhen it hits the glass. Use appropriate significant figures.

Answers

We have that the velocity of the ball when it hits the glass.Using the appropriate significant figures is

V=4.43ft/s

From the question we are told that

Mr. Bari drops a 3 kg ball from 1 feet above the glassthe velocity of the ball when it hits the glass

Generally the equation for the Velocity  is mathematically given as

\(V^2=2as\\\\Therefore\\\\V=\sqrt{2*9.8*1}\\\\V=4.43ft/s\)

Therefore

the velocity of the ball when it hits the glass.Using the appropriate significant figures is

V=4.43ft/s

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Which career may be a good fit for you if you enjoy planning meals and learning about proper nutrition?
A.
fitness instructor
B.
physical therapist
C.
medical researcher
D.
registered dietician

Answers

Answer:

D. Registered dietitian

Answer:

D

Explanation:

Boron (B) has an atomic number of 5 and an atomic mass of 11. Boron has _____.

5 electrons
6 electrons
11 electrons
16 electrons

Answers

Answer:

the answer is 5 electrons

Explanation:

because its the same name as the amount of protons

The answer is 5 electrons

what are the types of waves

Answers

Waves come in two kinds, longitudinal and transverse. Transverse waves are like those on water, with the surface going up and down, and longitudinal waves are like of those of sound, consisting of alternating compressions and rarefactions in a medium

i hope this helps :)

A tank circuit in a radio transmitter is a series RCL circuit connected to an antenna. The antenna broadcasts radio signals at the resonant frequency of the tank circuit. Suppose that a certain tank circuit in a shortwave radio transmitter has a fixed capacitance of 1.6 x 10-11 F and a variable inductance. If the antenna is intended to broadcast radio signals ranging in frequency from 4.8 MHz to 9.0 MHz, find the (a) minimum and (b) maximum inductance of the tank circuit.

Answers

a. The minimum inductance of the tank circuit is 56.85 H

b. The maximum inductance of the tank circuit is 199.86 H

Resonant frequency

The resonant frequency of a series RLC circuit is given by

f = 1/2π√LC where

L = inductance and C = capacitance

Making L subject of the formula, we have

L = (2πf)²/C

a. Minimum inductance in the tank circuit

The minimum inductance of the tank circuit is 56.85 H

To find the minimum inductance, we substitute the value of

f = frequency = 4.8 MHz = 4.8 × 10⁻⁶ Hz and C = capacitance = 1.6 × 10⁻¹¹ F into the equation, we have

L = (2πf)²/C

L = (2π × 4.8 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (9.6π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (30.159 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = 909.583 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F

L = 568.489 × 10⁻¹ H

L = 56.8489 H

L ≅ 56.85 H

The minimum inductance of the tank circuit is 56.85 H

b. Maximum inductance in the tank circuit

The maximum inductance of the tank circuit is 199.86 H

To find the maximum inductance, we substitute the value of

f = frequency = 9.0 MHz = 9.0 × 10⁻⁶ Hz and C = capacitance = 1.6 × 10⁻¹¹ F into the equation, we have

L = (2πf)²/C

L = (2π × 9.0 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (18π × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = (56.549 × 10⁻⁶ Hz)²/1.6 × 10⁻¹¹ F

L = 3197.75 × 10⁻¹² Hz²/1.6 × 10⁻¹¹ F

L = 1998.59 × 10⁻¹ H

L = 199.859 H

L ≅ 199.86 H

The maximum inductance of the tank circuit is 199.86 H

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Underground caves can form in limestone through deposition.
A.) False
B.) True

Answers

Answer:

I think the answer is option B

I believe The answer is false

Explain why a Merry-Go-Round and a Ferris Wheel have a constant acceleration when they are moving.
Answer must be at least two sentences and contain words such as velocity and acceleration.

Answers

Explanation:What is centripetal acceleration?

Can an object accelerate if it's moving with constant speed? Yup! Many people find this counter-intuitive at first because they forget that changes in the direction of motion of an object—even if the object is maintaining a constant speed—still count as acceleration.

Acceleration is a change in velocity, either in its magnitude—i.e., speed—or in its direction, or both. In uniform circular motion, the direction of the velocity changes constantly, so there is always an associated acceleration, even though the speed might be constant. You experience this acceleration yourself when you turn a corner in your car—if you hold the wheel steady during a turn and move at constant speed, you are in uniform circular motion. What you notice is a sideways acceleration because you and the car are changing direction. The sharper the curve and the greater your speed, the more noticeable this acceleration will become. In this section we'll examine the direction and magnitude of that acceleration.

The figure below shows an object moving in a circular path at constant speed. The direction of the instantaneous velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity, which points directly toward the center of rotation—the center of the circular path. This direction is shown with the vector diagram in the figure. We call the acceleration of an object moving in uniform circular motion—resulting from a net external force—the centripetal acceleration

a

c

a

c

a, start subscript, c, end subscript; centripetal means “toward the center” or “center seeking”.

In the drawing below, R1 has a resistance of 6.8 Ω and R2 has a resistance of 1.9-Ω. Determine the current (magnitude and direction) in the 6.8 and 1.9-Ω resistors in the drawing.

In the drawing below, R1 has a resistance of 6.8 and R2 has a resistance of 1.9-. Determine the current

Answers

For the 6.8 Ω resistors, the voltage across it is V1 = 4.0 V, so the current through it is I1 = V1 / R1 = 4.0 V / 6.8 Ω = 0.588 A

For the 1.9 Ω resistors, the voltage across it is V2 = 12 V, so the current through it is:

I2 = V2 / R2 = 12 V / 1.9 Ω = 6.32 A, directed from the negative terminal of V2 to the positive terminal.

Therefore, the current in the 6.8 Ω resistor is 0.588 A directed from the positive terminal of V1 to the negative terminal, and the current in the 1.9 Ω resistor is 6.32 A directed from the negative terminal of V2 to the positive terminal.

What are resistors?

Resistors are electronic components used in electrical circuits to provide a specific amount of resistance to the flow of electric current. They are designed to impede the current flow and reduce the amount of voltage flowing through a circuit.

What does a circuit consist of?

An electrical circuit consists of a closed loop of conductive material through which electric current can flow. A circuit typically includes a power source, wires to connect the components, and various components such as resistors, capacitors, inductors, diodes, and transistors, among others.

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A bus starts to move from rest. If it is accelerated by 0.8m/s2, calculate the velocity and distance traveled after 8 s.

Answers

We are given:_______________________________________________

Initial velocity (u) = 0 m/s

acceleration (a) = 0.8 m/s²

time interval (t) = 8 seconds

final velocity (v) = v m/s

distance travelled (s) = s m

Solving for the final velocity:___________________________________

We know that:

v = u + at                                [first equation of motion]

v = 0 + (0.8)(8)                       [replacing the variables]

v = 6.4 m/s

Hence, the final velocity is 6.4 m/s

Solving for the distance travelled:_______________________________

We know that:

s = ut + 1/2(at²)                     [second equation of motion]

s = (0)(8) + 1/2(0.8)(8)(8)      [replacing the variables]

s = 1/2(6.4*8)

s = 25.6 m

Hence, the distance travelled is 25.6 m

An automobile of mass 1500kg moving at 25.0m/s collides with a truck of mass 4500kg at rest. The bumpers of the two vehicles lock together during the crash. Compare the force exerted by the car on the truck with that exerted by the truck on the car during the collision.

Answers

The force exerted by the car on the truck is equal to 7500 N, and the force exerted by the truck on the car is equal to -7500 N.

According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Therefore, during the collision between the car and the truck, the force exerted by the car on the truck is equal in magnitude but opposite in direction to the force exerted by the truck on the car.

To determine the force exerted by the car on the truck, we can use the formula for impulse, which is the change in momentum of an object over a given period of time:

Impulse = Force x Time = Δp

where Δp is the change in momentum of the object and t is the time interval during which the force is applied.

In this case, the bumpers of the car and truck lock together, which means that they move as a single unit after the collision. Therefore, we can apply the law of conservation of momentum, which states that the total momentum of an isolated system remains constant.

Initially, the car has a momentum of:

p_car_initial = m_car * v_car_initial = 1500 kg * 25.0 m/s = 37500 kg m/s

Since the truck is at rest initially, its momentum is zero:

p_truck_initial = 0

After the collision, the two vehicles move together as a single unit with a common final velocity. Let the final velocity of the car-truck system be v_final.

Using conservation of momentum:

p_car_initial + p_truck_initial = (m_car + m_truck) * v_final

37500 kg m/s + 0 = (1500 kg + 4500 kg) * v_final

v_final = 5.0 m/s

Therefore, the momentum of the car-truck system after the collision is:

p_final = (1500 kg + 4500 kg) * 5.0 m/s = 30000 kg m/s

The change in momentum of the car-truck system during the collision is:

Δp = p_final - p_car_initial = 30000 kg m/s - 37500 kg m/s = -7500 kg m/s

Since the time interval during which the force is applied is not given in the problem, we cannot calculate the exact values of the forces exerted by the car on the truck and the truck on the car during the collision. However, we know that the forces are equal in magnitude but opposite in direction according to Newton's third law of motion.

Therefore, the force exerted by the car on the truck is equal to 7500 N, and the force exerted by the truck on the car is equal to -7500 N.

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4. A chandelier brightens a ballroom after a waiter moves a switch

Answers

Answer:

because switch moves after a waiter

Explanation:

Suppose a space probe of mass m1 = 4200 kg expels m2 = 3300 kg of its mass at a constant rate with an exhaust speed of vex = 1.95 × 103 m/s.
(a) What is the formula for the increase in speed, of the space probe, in terms of the variables given above? (You may assume the gravitational force is negligible at the probe's location.)
(b) Calculate the increase in speed, in meters per second, of the space probe.

Answers

(a)The formula for the increase in speed of the space probe in terms of the variables given in the question is Δv = vex ln [m1/(m1 - m2)]

(b) The increase in speed, in meters per second, of the space probe Δv = 3.00 × 10³ m/s.

Assuming the gravitational force is negligible at the probe's location, Rocket propulsion can be defined by the conservation of total momentum which state that the total momentum of a system remains conserved. Hence force acting on the probe will be

m × dv/dt = vex × dm/dt

integrating the above equation, we get

Δv = vex ln [m1/(m1 - m2)]

putting the given values m1 = 4200 kg,

m2 = 3300 kg, and

vex = 1.95 × 10³ m/s in the above equation,

we get the increase in speed, in meters per second, of the space probe

Δv = 1.95 × 10³ × ln [4200/(4200 - 3300)]

Δv = 1.95 × 10³ × ln [4.667]

Δv = 1.95 × 10³ × 1.539

Δv = 3.00 × 10³ m/s.

Therefore, the formula for the increase in speed of the space probe in terms of the variables given in the question is v = vex ln [m1/(m1 - m2)], and the increase in speed, in meters per second, of the space probe Δv = 3.00 × 10³ m/s.

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suppose we i9ncrease the tension in a rope, keeping the frquency of osciliation of the end of the rope the same. what effect does this have on the wavelength of the wave produced

Answers

Increasing the tension in a rope while keeping the frequency of oscillation constant will decrease the wavelength of the wave produced.

The speed of a wave on a rope is proportional to the square root of the tension in the rope, and inversely proportional to the square root of the linear density of the rope. Since the frequency of oscillation is held constant, the speed of the wave remains constant. Therefore, an increase in tension will result in a decrease in wavelength, as given by the formula λ = v/f, where λ is the wavelength, v is the speed of the wave, and f is the frequency of oscillation. This relationship between tension, frequency, and wavelength is known as the wave equation, and is a fundamental concept in wave mechanics.

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A system consists of multiple objects connected by ropes. How many equations need to be written to solve this problem?

A) two for each object
B) one or two for each object
C) one for each object
D) two for the system

Answers

Answer:

the correct answer is B

Explanation:

To solve the system they must have the same amount of unknowns as equations,

a) If the system does not have friction, we must write the x-axis equation for each body, therefore we need to write N equations

b) if the system has friction, two equations are needed for each particle

therefore the correct answer is B

Is this right?? Please help me. IT IS SOCIOLOGY!

Answers

where is the picture???

A 130 g ball moves horizontally with velocity for t > 0 s.
a) What is the velocity of the ball at t = 1 s? (5 points, out of which 2 points are for a sketch representing the problem on a coordinate system).
b) What is the acceleration of the ball at t = 1 s. (5 points, out of which 3 points are for showing all the steps clearly when taking the derivative, and 1 point is for the answer to two significant figures with the units).
c) What is the net force on the ball at t = 1 s. (5 points, out of which 2 points are for the equation being used and its name and 1 point is for the answer to two significant figures with the units).

Answers

To determine the velocity at t = 1 s, we need to know the equation or function that describes the ball's motion. Once we have this equation, we can substitute t = 1 s into it and solve for the velocity.

The velocity of an object is the rate of change of its position with respect to time. To find the velocity of the ball at t = 1 s, we need more information such as the equation or function that describes the motion of the ball.

Without this information, it is not possible to provide a specific numerical value for the velocity at t = 1 s. However, we can discuss how to calculate the velocity using the given information.
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1. What is the angle of inclination of the Earth’s axis?
2. Which hemisphere is tilted toward the Sun?
3. Which hemisphere is tilted away from the Sun?
4. Which hemisphere receives greater amount of sunlight?
5. Why do places that receive direct rays of the Sun have warmer temperature?

1. What is the angle of inclination of the Earths axis?2. Which hemisphere is tilted toward the Sun?3.

Answers

Answer:

What is the angle of inclination of the Earth’s axis?

The earth's axis of rotation is tilted 66.5 degrees with respect to its orbital plane around the sun and its axis of rotation is inclined 23.5 degrees from the perpendicular, with respect to this plane. The tilt of the earth affects the angle between the sun beam and the normal over a surface.

Which hemisphere is tilted toward the Sun?

Earth orbits at an angle, so half the year, the Northern Hemisphere is tilted toward the Sun — this is summer in the Northern Hemisphere, and winter in the Southern Hemisphere. The other half of the year, the Northern Hemisphere is tilted away from the Sun, creating winter in the north and summer in the south.

Which hemisphere is tilted away from the Sun?

When the Earth's axis is tilted toward the sun for the Northern Hemisphere, the people in the Northern Hemisphere experience summer, while at the same time, the Southern Hemisphere is tilted away from the sun and the people there experience winter.

Which hemisphere receives greater amount of sunlight?

The Northern Hemisphere receives the maximum intensity of the sun's rays, while the angle of sunlight decreases in the Southern Hemisphere.

Why do places that receive direct rays of the Sun have warmer temperature?

When the sun's rays strike Earth's surface near the equator, the incoming solar radiation is more direct (nearly perpendicular or closer to a 90˚ angle). Therefore, the solar radiation is concentrated over a smaller surface area, causing warmer temperatures.

Here is your answer please mark as brainlest answer!!

Answer:

xfxy naa

Explanation:

dhdhuciffbfjfufu

1
An object has a gravitational potential energy of
41772.5J and has a mass of 1550kg. How high is
it above ground?

Answers

Answer:

h = 2.78 m

Explanation:

Potential Energy(PE)

Mass(m)

Gravity(g) which is approximately equal to 10.

Height (h)

PE = mgh

41772.5 = 1500 * 10 * h

41772.5 = 15000h

h = 41772.5/15000

h = 2.78 m

ACTIVITY 4
Applying the equation learned, answer the following problems:

1. A bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s. What is its momentum? p = m/s. What Is Its Momentum?

Given:

Find:

Formula:

Solution:

2. A skateboard is rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s. What is its mass?

Given:

Find:

Formula:

Solution:

3. A pitcher throws a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s. What is its velocity?

Given:

Find:

Formula:

Solution:​

Subject Is Science

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ACTIVITY 4Applying the equation learned, answer the following problems: 1. A bowling ball whose mass

Answers

Answer:

1)  10 kg-m/s

2)  2 kg

3)  20 m/s

Explanation:

The momentum of an object can be calculated using the equation:

\(\large\boxed{p=mv}\)

where:

p is momentum (measured in kilogram meters per second).m is mass (measured in kilograms).v is the velocity (measured in meters per second).

\(\hrulefill\)

Question 1

For this question we need to find the momentum of a bowling ball whose mass is 4.0 kg is rolling at a rate of 2.5 m/s.

Given values:

m = 4.0 kgv = 2.5 m/s

Substitute the given values into the momentum formula and solve for p:

\(p=4.0\;\text{kg} \cdot 2.5\;\text{m/s}\)

\(p=10\;\text{kg m/s}\)

Therefore, the momentum of the bowling ball is 10 kg-m/s.

\(\hrulefill\)

Question 2

For this question we need to find the mass of a skateboard rolling at a velocity of 3.0 m/s with a momentum of 6.0 kg-m/s.

Given values:

p = 6.0 kg-m/sv = 3.0 m/s

As we want to find mass, rearrange the momentum formula to isolate m:

\(\large\boxed{m=\dfrac{p}{v}}\)

Substitute the given values into the formula and solve for m:

\(m=\dfrac{6.0\; \text{kg m/s}}{3.0\; \text{m/s}}\)

\(m=2\;\text{kg}\)

Therefore, the mass of the skateboard is 2 kg.

\(\hrulefill\)

Question 3

For this question we need to find the velocity of a baseball with a mass of 0.5 kg and a momentum of 10 kg-m/s.

Given values:

p = 10 kg-m/sm = 0.5 kg

As we want to find velocity, rearrange the momentum formula to isolate v:

\(\large\boxed{v=\dfrac{p}{m}}\)

Substitute the given values into the formula and solve for v:

\(v=\dfrac{10\; \text{kg m/s}}{0.5\; \text{kg}}\)

\(v=20\;\text{m/s}\)

Therefore, the velocity of the baseball is 20 m/s.

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