Can someone help me ASAP it’s due tomorrow. I will give brainliest if it’s all done correctly. Show work.

The final distance of the port from the ship is 75.63 km and the final bearing of the port from the ship is 263.57° using cosine and sine rules.

Considering the triangle formed by the ship ∆ABC where A, B and C are the points for; the port, where the ship changes its course, and its final bearing. The final distance "a" of the port from the ship is calculated with cosine rule as follows;

a² = b² + c² - 2(b)(c)cosA

a² = 40² + 70² - 2(40)(70)cos82°

a² = 1600 + 4900 - 5600cos82°

a² = 5720.63 {take square root of both sides}

a = 75.63

For the triangle ABC, by sine rule;

a/sinA = b/sinB = c/sinC

75.63/sin82° = 70/sinC

C = sin⁻¹(70 × sin82°/75.63) {by cross multiplication}

C = 66.43

angle C = 60 + 6.43 {60° is an alternate angle with angle 30° at the point B where the ship chenged course and 6.43° is a complementary angle at the 3rd quadrant of point C}

The final bearing of the port from the ship is calculated as;

180° + (90 - 6.43)° = 263.57°

Therefore, the final distance of the port from the ship is 75.63 km and the final bearing of the port from the ship is 263.57° using cosine and sine rules.

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Answer:

y=mx+b

In the above linear equation, m is always the slope and b is always the y-intercept.

slope: 4/5

y-intercept: -1

Answer:

Slope: 4/5

Y-intercept: (0,-1)

The problem of the central planner is option A) max U(x) Subject to N x² = 100.

In a simple production economy with N goods, each of the goods is produced with the following production function where x is the good, the subscript i denotes the good, and L is labor.

The total work available is

100 x₁ = √L₁

Suppose that in this economy there is a representative agent with preferences given by the following utility function U(x).

The problem of the central planner is represented by the choice of option A) max U(x) Subject to

N x² = 100.

Where, to maximize the utility function of the representative agent, the central planner must allocate a certain amount of each good x1, x2, ..., xN to the representative agent that would help in maximizing his/her utility subject to the total production being constrained to

Nx² = 100.

Hence, the problem of the central planner is option A) max U(x) Subject to N x² = 100.

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When exploring maps using a pocket calculator, it's important to understand the concept of fixed points and cobwebs. Fixed points are values that do not change when the map is applied repeatedly. Cobweb diagrams help visualize the behavior of maps and can provide insights into the eventual pattern.

To explore a map using a pocket calculator, follow these steps:

Start with an initial number.

Apply the map by pressing the appropriate function key.

Repeat step 2 to see how the number changes with each iteration.

Observe the pattern that emerges over multiple iterations.

Repeat the above steps with a different initial number to compare the eventual patterns.

Mathematically, fixed points occur when applying the map does not change the value. In other words, if the map is f(x), a fixed point satisfies f(x) = x. By repeatedly applying the map starting from a fixed point, the value remains the same.

Cobweb diagrams are graphical representations of the iterative process, where each point on the diagram represents a value obtained from applying the map repeatedly. The diagram shows the connection between each iteration and helps visualize the behavior of the map.

By analyzing the cobweb diagrams and studying the properties of the map, one can determine whether the map has fixed points, cycles, or other interesting patterns. This analysis can be supported by mathematical reasoning and calculations.

It's important to note that the specific maps being explored are not mentioned in the question. To provide more specific insights, it would be helpful to know the particular maps and initial values being used.

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Answer:

$2539.47

10.18722679 (make sure you round this)

Step-by-step explanation:

a.)

Equation for compound interest:

\(AV=P(1+\frac{i}{n})^{n*t}\\2000(1+\frac{.04}{4})^{4*6}\\2000(1.01)^{24}\\2539.469297\\\)

which rounds to

2539.47

b.)

using the same equation we can write

\(3000=2000(1+\frac{.04}{4})^{4t}\\1.5=1.01^{4t}\\log_{1.01}1.5=4t\\log_{1.01}1.5=\frac{log(1.5)}{log(1.01)}=40.7489\\40.7489=4t\\10.18722679=t\)

not sure how to round this, so I'll leave that part up to you

The probability that either event will occur is 0.61

From the question, we have the following parameters that can be used in our computation:

Event A = 12

Event B = 10

Other Events = 14

Using the above as a guide, we have the following:

Total = A + B + C

So, we have

Total = 12 + 10 + 14

Evaluate

Total = 36

So, we have

P(A) = 12/36

P(B) = 10/36

For either events, we have

P(A or B) = 22/36 = 0.61

Hence, the probability that either event will occur is 0.61

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He is  2√19 miles far way from starting point.

Suppose Billy starts at point A, turns at point B, and ends at point D, as shown below.

If Billy turns 60◦ northward and walks six miles, then we can draw a 30 − 60 − 90 triangle whose hypotenuse is 6 miles

It follows that Billy traveled 6/2 = 3 miles eastward during these 6 miles, and that he traveled 3√3 miles northward during these 6 miles. In total, Billy traveled 4 + 3 = 7 miles  eastward and 3√ 3 miles northward.

By the Pythagorean Theorem, the distance from his starting point is q:

(7)2 + (3√3)2

=√49 + 27

= √76

= 2√19 .

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By definitions of line segment and midpoint, we find that \(\overline{TU} \cong \overline {UV}\).

In this problem we find a line segments partitioned in four parts by using midpoints, each of them are listed below:

A point within a line segment is a midpoint if and only if it partitions the line segment into two parts of equal length. If point U is the midpoint of line segment SW, then SU = UW. If point T is the midpoint of SU, then ST = TU and if point V is the midpoint of UW, then UV = VW. Finally, we get the following result by algebraic handling:

SU = UW

ST + TU = UV + VW

2 · TU = 2 · UV

TU = UV

\(\overline{TU} \cong \overline {UV}\)

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Based οn the infοrmatiοn prοvided, we can see that the prοfit earned (p) is prοpοrtiοnal tο the number οf cοοkies sοld (c).

We can write the equatiοn as:

p = 0.25c

This equatiοn means that fοr every cοοkie sοld, the prοfit earned is $0.25. We can alsο write this equatiοn in slοpe-intercept fοrm as:

y = mx + b

where y represents prοfit earned (p), x represents the number οf cοοkies sοld (c), m represents the slοpe (0.25 in this case), and b represents the y-intercept (the value οf y when x is 0, which is 0 in this case).

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This problem can be solved using the concept of the expected value of a random variable. Let X be the random variable representing the number of boxes a person needs to buy to get all four prizes.

To calculate the expected value E(X), we can use the formula:

E(X) = 1/p

where p is the probability of getting a new prize in a single box. In the first box, the person has a 4/4 chance of getting a new prize. In the second box, the person has a 3/4 chance of getting a new prize (since there are only 3 prizes left out of 4). Similarly, in the third box, the person has a 2/4 chance of getting a new prize, and in the fourth box, the person has a 1/4 chance of getting a new prize. Therefore, we have:

p = 4/4 * 3/4 * 2/4 * 1/4 = 3/32

Substituting this into the formula, we get:

E(X) = 1/p = 32/3

Therefore, the average number of boxes a person needs to buy to get all four prizes is 32/3, or approximately 10.67 boxes.

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Answer:

There is nothing here

Step-by-step explanation:

Answer:

Step-by-step explanation:

a , b & c

Answer:

C

Step-by-step explanation:

Answer:

X=2

Step-by-step explanation:

\(\frac{x}{40} =\frac{5}{100} \\\)

Cross multiply

100 x X = 5 x 40

100X=200

Divide both sides by 100

\(\frac{100x}{100} =\frac{200}{100}\)

X=2

The actual distance between Beitbridge and Musina is 3,900,000 kilometers.

To calculate the actual distance between Beitbridge and Musina, given the scale of the map and the measured distance on the map, we can use the concept of scale.

The scale of the map is given as 1:3,000,000, which means that 1 cm on the map represents 3,000,000 cm in real life.

The measured distance on the map between Beitbridge and Musina is 1.3 cm.

To find the actual distance, we can set up a proportion using the scale:

1 cm on the map / 3,000,000 cm in real life = 1.3 cm on the map / x km in real life.

Simplifying the proportion, we have:

1 / 3,000,000 = 1.3 / x.

Cross-multiplying, we get:

x = (1.3 * 3,000,000) / 1.

x = 3,900,000 / 1.

x = 3,900,000 km.

The actual distance between Beitbridge and Musina is 3,900,000 kilometers.

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1. Mean for group 1: 84.97

2. Mean for group 2: 85.89

3. Standard deviation for group 1: 5.32

4. Standard deviation for group 2: 3.29

5. T-value : -5. 39

6. No significant difference,

7. Degrees of freedom : 8

8. Critical value: ±2.10

9. Yes, we found statistical significance.

10. Yes, we rejected the null hypothesis.

Subheading: Do men and women differ significantly in their scores on a personality trait scale?

Name of group 1: Men

Scores for group 1: 78.5, 82.1, 76.9, 79.3, 81.2, 80.7, 77.8, 82.4, 79.6, 80.1

Name of group 2: Women

Scores for group 2: 85.2, 87.6, 88.1, 84.9, 85.6, 86.3, 87.9, 84.5, 86.7, 88.5

1. The mean for group 1 (Men): 80.46

2. The mean for group 2 (Women): 86.69

3. Standard deviation for group 1 (Men): 2.24

4. Standard deviation for group 2 (Women): 1.39

5. Calculated value of t: -5.39

6. Null hypothesis: There is no significant difference in the scores between men and women on the personality trait scale.

7. Degrees of freedom (df): df = n1 + n2 - 2 = 10 + 10 - 2 = 18

8. Critical value at α = 0.05 for a two-tailed t-test with 18 degrees of freedom is approximately ±2.10.

9. Yes, we found statistical significance.

10. Yes, we rejected the null hypothesis.

11. In this study, we compared the scores of men and women on a personality trait scale. The mean score for men was 80.46, while the mean score for women was 86.69. The calculated value of t was -5.39. Based on the results of the independent t-test, we found a statistically significant difference between the two groups (p < 0.05). Therefore, we rejected the null hypothesis, indicating that there is a significant difference in the scores of men and women on the personality trait scale. This suggests that gender may play a role in influencing the levels of the personality trait being measured. However, further research is needed to explore the underlying factors contributing to this difference and its implications in a broader population.

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The relation does not relate y as a function of x because point (2,2) and (3,2) have the same y value. Hence, option 2 is the correct answer.

A relation between a collection of inputs and outputs is known as a function. A function is, to put it simply, a relationship between inputs in which each input is connected to precisely one output. Each function has a range, codomain, and domain. The usual way to refer to a function is as f(x), where x is the input. A function is typically represented as y = f. (x).

We know that a function is a relationship between inputs where each input is related to exactly one output.

In the given graph (2,2) and (3,2) have the same y value that is two inputs have same output.

Hence, the relation does not relate y as a function of x because point (2,2) and (3,2) have the same y value and option 2 is the correct answer.

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Answer:

(0,16)

Step-by-step explanation:

Hi there!

The y intercept is the value in which the parabola passes through the y axis

Therefore, the value of x at the y intercept is 0

So to find the value of the y intercept, substitute x as 0 in the equation.

y=(2x-3)^2 + 7

If x=0, then:

y=(2(0)-3)^2 + 7

Multiply

y=(0-3)^2 + 7

Subtract 3 from 0

y=(-3)^2 + 7

Raise -3 to the second power

y= 9 + 7

Add 9 and 7 together

y = 16

So the y intercept is the point (0,16)

Hope this helps!

The distribution of test scores shows that most students did not do well on the test; some did fine and only a few did exceedingly well. The distribution is likely to be skewed.

What is a skewed distribution?

A skewed distribution is one in which the data is not uniformly distributed but rather concentrated on one side. In simple words, a skewed distribution is one in which one tail has a greater number of observations than the other tail, with the majority of data falling in the tail with the greater number of observations.

In a symmetric distribution, the data is uniformly distributed on both sides of the median, with half of the data lying to the right and half to the left.

Thus, the distribution of test scores shows that most students did not do well on the test; some did fine and only a few did exceedingly well. The distribution is likely to be skewed.

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Answer:

Step-by-step explanation:

Nope<3;p

Answer:

needed to add 36 non blue marbles in the bag. Sense Tome doesn't want to give the blue marbles up...

Solution:

Given the absolute value parent function below

If the function is vertically compressed by a factor of 4, the function becomes

Where

Hence, the answer is

Option A

Answer:

----------------------

According to the diagram we have:

1) Angles w and 138° form a linear pair, hence:

2) Angles 19°, x and w form a right angle, hence:

Answer:

true

Step-by-step explanation:

because there's less humidity

Answer:   12

Step-by-step explanation:

chocolate candy is 1270.00

spendinf. 12.750.00

amount. 2.750.00

47000

- : 15

12

The required number of caramel pieces is 15.

In order to find the value of the fraction of a quantity, multiply the value of the quantity to the fraction given.

A fraction can also be converted into percentage by multiplying it by 100.

The total number of candies is 150.

Then, as per the question different candies are as follows,

The number of chocolate bars is 1/3 × 150 = 50.

The number of hard candy is 2/5 × 150 = 60.

And, the number of gummy bears is 1/6 × 150 = 25.

Now, the remaining candies are as below,

150 - (50 + 60 + 25) = 15

Hence. the number of caramel pieces Maya have is 15.

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To determine the solutions to the given boundary-value problem, we must first analyze the values of L. If L is greater than 0, then we can use Sturm-Liouville theory to solve the problem.

If L is chosen in such a way that the boundary-value problem has a unique solution, then we have precisely one nontrivial solution. However, if L is chosen so that there are multiple solutions, we have more than one solution.

If L is chosen in such a way that the boundary-value problem has no solution, then there are no solutions, including the trivial solution. The trivial solution is the solution where all the unknowns are set to zero.

Therefore, it is possible to find values of L > 0 so that the given boundary-value problem has precisely one nontrivial solution, more than one solution, no solution, and the trivial solution depending on how L is chosen.

Involving values of L > 0, boundary-value problems, and nontrivial solutions. To determine whether it is possible to find values of L > 0 so that the given boundary-value problem has precisely one nontrivial solution, more than one solution, no solution, and the trivial solution, follow these steps:

1. Identify the boundary-value problem in question. This typically involves a differential equation and boundary conditions.

2. Analyze the boundary conditions and the differential equation to see if there is a possibility of finding values of L > 0 that satisfy the problem.

3. Determine if there is a trivial solution, which typically corresponds to a zero solution, where all the components of the solution are zero.

4. Check for the existence of nontrivial solutions. This may involve solving the differential equation for particular values of L > 0 and applying the boundary conditions.

5. Compare the results from steps 3 and 4 to determine if there is precisely one nontrivial solution, more than one solution, no solution, or only the trivial solution.

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