A department store buys 300 shirts at a cost of $1,800 and sells them for $9 each. What is the percent markup? A department store buys 300 shirts at a cost of $1,800 and sells them for $9 each. What is the percent markup?

When the line to be examined's slope is known, and the provided point also serves as the y intercept, the slope intercept formula, y = mx + b, is utilized (0, b).

When should you use point-slope form?

When the slope of the line being studied is known, and the provided point is also the y intercept, the slope intercept formula, y = mx + b, is utilized (0, b). The y value of the y intercept point is represented by b in the equation.

One of the three ways we can express a straight line is using the point slope form, also known as the point-gradient form. By merely knowing one point on the line and the slope of the line, we may use this form to get the equation of the line.

The slope and y-intercept of the matching line can be rapidly determined when we have a linear equation in slope-intercept form. This enables us to graph it as well.

The equation of a line can be represented in either slope-intercept form or point-slope form.

Slope-intercept form:

The slope-intercept form of a line is given by y = mx + b, where m is the slope of the line and b is the y-intercept.

To find the equation of the line passing through the points (3,5) and (6,11) in slope-intercept form, we can use the point-slope formula to find the slope and then use one of the points to find the y-intercept.

Point-slope form:

The point-slope form of a line is given by y - y1 = m(x - x1), where m is the slope of the line and (x1, y1) is a point on the line.

To find the equation of the line passing through the points (3,5) and (6,11) in point-slope form, we can use the point-slope formula and one of the points.

Using the point-slope formula, the slope of the line is (11 - 5) / (6 - 3) = 6/3 = 2.

So, the equation of the line in slope-intercept form is:

y = 2x + b

We can use the point (3,5) to find the y-intercept:

5 = 2 * 3 + b

Solving for b, we get b = -1.

So the equation of the line in slope-intercept form is:

y = 2x - 1

In point-slope form, using the point (3,5), the equation of the line is:

y - 5 = 2(x - 3)

Both forms represent the same line, just in different ways.

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Answer:

Step-by-step explanation:

-2/5

Answer:

  q = (4r²-p)/5

Step-by-step explanation:

To solve for q, undo what has been done to it. The variable q has been multiplied by 5, added to p, the square root taken, and that divided by 2. We undo these operations in reverse order.

  \(\dfrac{\sqrt{p+5q}}{2}=r\qquad\text{given}\\\\\sqrt{p+5q}=2r\qquad\text{multiply by 2}\\\\p+5q=4r^2\qquad\text{square}\\\\5q=4r^2-p\qquad\text{subtract p}\\\\\boxed{q=\dfrac{4r^2-p}{5}}\qquad\text{divide by 5}\)

A vector orthogonal to the plane defined by points P(1,0,0), Q(1,1,1), and R(2,-1,3) is:

(4, 1, -1).

To find a vector orthogonal to the plane defined by points P(1,0,0), Q(1,1,1), and R(2,-1,3), follow these steps:

1. Find two vectors that lie in the plane by subtracting the coordinates of the given points. Let's use PQ and PR:
  PQ = Q - P = (1-1, 1-0, 1-0) = (0, 1, 1)
  PR = R - P = (2-1, -1-0, 3-0) = (1, -1, 3)

2. Calculate the cross product of PQ and PR to obtain a vector orthogonal to the plane:
  PQ x PR = (PQ_y*PR_z - PQ_z*PR_y, PQ_z*PR_x - PQ_x*PR_z, PQ_x*PR_y - PQ_y*PR_x)
           = (1*3 - 1*(-1), 1*1 - 0*3, 0*(-1) - 1*1)
           = (3 + 1, 1 - 0, 0 - 1)
           = (4, 1, -1)

Therefore, we can state that a vector orthogonal to the plane defined by points P(1,0,0), Q(1,1,1), and R(2,-1,3) is (4, 1, -1).

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line 1

3y = 4x + 5

y = 4/3x + 5/3

line 2

8x + 6y = -4

6y = -8x -4

y = -8/6x -4/6

y = -4/3x - 2/3

line 3

y = 3/4x + 6

since line 1 and 2 have different slopes, they are neither

since line 1 and 3 have different slopes, they are neither

since line 2 and 3 have the opposite slopes, they are perpendicular

Answer: The unit value of a cubic centimeter (cm^3) is the same as the metric measurement of a milliliter (mL).

This is because 1 milliliter is equal to 1 cubic centimeter. In other words, if you have a cube that measures 1 centimeter on each side, its volume would be 1 cubic centimeter, which would also be equivalent to 1 milliliter of volume.

This relationship between cm^3 and mL is commonly used in scientific and medical measurements involving liquids and gases.

The unit value of a cubic centimeter (cc) is equivalent to one milliliter (mL) in the metric system. Both cubic centimeters and milliliters are used to measure volume, and their conversion is straightforward: 1 cc = 1 mL.

The metric system uses base units such as meters, liters, and grams, and applies prefixes like kilo-, centi-, and milli- to indicate larger or smaller units of measurement.
Cubic centimeters are often used to measure the volume of solid objects or the capacity of containers, while milliliters are more commonly used to measure the volume of liquids. However, both units represent the same volume and can be used interchangeably.
It is important to understand the difference between volume measurements and other metric measurements, such as length or mass. For instance, meters are used to measure length or distance, and grams are used to measure mass or weight. These units cannot be directly converted to cubic centimeters or milliliters, as they represent different physical properties.
In summary, a cubic centimeter (cc) is a unit of volume in the metric system that is equivalent to one milliliter (mL). Both units can be used to measure volume, and they have a simple conversion of 1 cc = 1 mL. Understanding the relationship between these units and other metric measurements is essential for accurately quantifying and comparing different physical properties.

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Answer:

here you go! :))

n= 2

m=3

a= 10

q= 50

Answer:

See below

Step-by-step explanation:

The rate at which the angle between the ladder and the wall changes is 30√75 ft/sec and the rate at which the base of the ladder slides away from the wall at this instant is 13.2 ft/sec.

When a 10-foot ladder slides down a wall at a rate of 3 ft/sec, the rate at which the (acute) angle between the ladder and the wall changes when the foot of the ladder is 5 feet from the wall and the rate at which the base of the ladder slides away from the wall are required to be calculated.

Let's mark the length of the ladder as ‘l’ and the distance of the ladder from the wall as ‘x’.If the ladder has slid x feet down the wall at time t, the triangle formed by the ladder, the wall, and the ground is such that l² = x² + y². The angle is θ, then sin θ = y/l, cos θ = x/l, and tan θ = y/x.

Thus, we have the following equation:(l)² = (x)² + (y)²Differentiate with respect to t.2(l)(dl/dt) = 2(x)(dx/dt) + 2(y)(dy/dt)

Solve for dy/dt when x = 5ft and dx/dt = 3 ft/sec.dy/dt = (l/x)(dx/dt)√[l² - x²]dy/dt = (10/5)(3)√[10² - 5²]dy/dt = 30√75 ft/sec

Now, let's differentiate the equation l² = x² + y² with respect to time:2l(dl/dt) = 2x(dx/dt) + 2y(dy/dt)

We have already calculated the value of dy/dt from the previous step. Substituting, l = 10, x = 5 and dx/dt = 3, we get: 20(dl/dt) = 10(3) + 2(5)(30√75)dl/dt = 13.2 ft/sec

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Answer:

answer choice A

Step-by-step explanation:

PEMDAS

parenthesis: 3+9=12

exponents: 6*6=36

division: 36/12

quotient:3

Answer:

A

Step-by-step explanation:

hope this helps u.

I do not understand why our answer have to be 20 or more words??

Answer:

1) 267.45

2) 18.48

3) 3472

Answer:

x=133 degrees

Step-by-step explanation:

The diagram is drawn and attached below.

Now, AB is a straight line.

\(\angle ACD+ \angle DCB =180^\circ $ (Linear Postulate)\\47^\circ+x^\circ=180^\circ\\x^\circ=180^\circ-47^\circ\\x^\circ=133^\circ\)

Answer:

A

Step-by-step explanation:

the order of letter should resemble the same shape

Answer:

y=x-2

Step-by-step explanation:

x=6 and y=4, so simplest equation is y=x-2

You can have infinity lines with the point (6,4). Another example is \(y=\frac{1}{2} x+1\)

Answer:

2.19

Step-by-step explanation:

Answer:

$1.09

Step-by-step explanation:

Unit price is how much one portion or amount of a certain thing costs. In this case the unit would be kilograms. This means that we have to find the value of one kilogram.

1) Find one kilogram

To find one kilogram we have to divide 8.72 by 8, this will give us the value of 1

This means that the unit price would be $1.09

Hope this helps, have a lovely day! :)

Answer:

1.2 * 10^9

Step-by-step explanation:

Written out, the number is 1,200,000,000

We can simplify that number to 1.2 * 10^9 (ten to the ninth power)

I hope this helped, please mark Brainliest, thank you!

The Equation of circle is (x-2)² +(y+ 8)² = 7²

The standard form of a circle with center (h, k) and radius r is given by the equation:

(x-h)²  + (y-k)² = r²

In this equation, (h, k) represents the coordinates of the center of the circle, and r represents the radius of the circle.

In this case, the center of the circle is (2, -8) and the radius is 7.

Plugging these values into the equation, we have:

(x- 2)² + (y- (-8))² = 7²

Simplifying further:

(x-2)² +(y+ 8)² = 7²

So, the equation in standard form for the circle with center (2, -8) and radius 7 is:

(x-2)² +(y+ 8)² = 7²

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The height of the 10th bounce of the ball will be 0.6 feet.

A geometric sequence is a sequence in which each term is found by multiplying the preceding term by the same value.

The nth term of the geometric sequence is given by

\(\sf T_n=ar^{n-1}\)

Where,

According to the given question.

During the first bounce, height of the ball from the ground, a = 4.5 feet

And, the each successive bounce is 73% of the previous bounce's height.

So,

During the second bounce, the height of ball from the ground

\(\sf = 73\% \ of \ 10\)

\(=\dfrac{73}{100}(10)\)

\(\sf = 0.73 \times 10\)

\(\sf = 7.3 \ feet\)

During the third bounce, the height of ball from the ground

\(\sf = 73\% \ of \ 7.3\)

\(=\dfrac{73}{100}(7.3)\)

\(\sf = 5.33 \ feet\)

Like this we will obtain a geometric sequence 7.3, 5.33, 3.11, 2.23,...

And the common ratio of the geometric sequence is 0.73

Therefore,

The sixth term of the geometric sequence is given by

\(\sf T_{10}=10(0.73)^{10-1\)

\(\sf T_{10}=10(0.73)^{9\)

\(\sf T_{10}=10(0.059)\)

\(\sf T_{10}=0.59\thickapprox0.6 \ feet\)

Hence, the height of the 10th bounce of the ball will be 0.6 feet.

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Answer: 3/8

Step-by-step explanation: You have a 1 in 5 chance of pulling an orange.

5/25, or if you need to simplify then 1/5

The line with a slope of -1 is the one that is parallel to the given line.

To determine which line is parallel to the line passing through the points (-1, 2) and (5, -4), find the slope of the given line and look for other lines with the same slope.

The slope of a line  found using the formula:

slope = (change in y-coordinates) / (change in x-coordinates)

For the given points (-1, 2) and (5, -4):

slope = (2 - (-4)) / (-1 - 5)

= 6 / (-6)

= -1

So, the slope of the line passing through the points (-1, 2) and (5, -4) is -1.

Any line with a slope of -1 parallel to this line.

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Answer:

x = 4

Step-by-step explanation:

We know that the slope-intercept form of the equation of the line is:

since the y-intercept is -2, then we have that b = -2.

To find the slope, we can use the x-intercept doing the substitution of the point (3,0) on the previous equation to get the following:

now, solving for m we get the following:

now that we have that m = 2/3 and b = -2, the equation in slope-intercept form is:

Answer:

It will make 4 90° turns, because each 1/4 turn or 15 minutes is 90°.

Answer: 30,000

Step-by-step explanation:

150,000 x 0.2 = 30,000

Answer:

<BAC ≅ BCA by rule Base angle theorem

Step-by-step explanation:

What we know:

BAC = DAC

BC = BA

ΔBCA is an isosceles so ∠BCA  =  ∠DCA and ∠BAC

and we found that out by base angle theorem since

Base angle Theorem  = Two base angles of a icosceles triangle are equal.

And since ΔBCA is an isoceles then ∠A and ∠C will be equal. And so we can prove BC is a parallel to AD

The proof that BC ∥ AD from the given statements is that;

BC ∥ AD because of the definition of alternate angles

We are given;

AB = BC  

 AC is ∠ bisector of ∠BAD

Since AC is the angle bisector of ∠BAD, it means that;

∠BAC  = ∠DAC (definition of a bisected angle)

Now, since AB = BC, it means that ΔBCA is an isosceles triangle.

Thus; ∠BCA = ∠BAC  (base angle theorem)

Now, since ∠BCA = ∠BAC, and ∠BAC  = ∠DAC, we can say that;

∠BCA = ∠DAC

This means  ∠BCA and ∠DAC are alternate angles. Thus, we can say that AC is the transversal line carrying the two equal angles.

Thus, we can say that BC is parallel to AD as they are the parallel lines cut by the transversal line AC.

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