A dockworker applies a constant horizontal force of 80.0 N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves 11.0 m in 5.00 s. (a) what is the mass of the block office? (b) If the worker stops pushing at the end of 5.00 s, how far does the block move in the next 5.00 s?

Answer:

see below

Explanation:

In chickenpox vaccine , weakened/killed pathogens are introduced into the body to generate immune response. The first response is slow and is called primary response while the subsequent exposure with the same pathogen generates a highly intensified immune response which is known as secondary response .

This type of immunity which generates antibody against the virus particles by introducing them into the body is called active immunity . It lasts forever in the body as the immune system has the memory of first exposure with the pathogen and after coming in contact with the same pathogen it recognises it and generates immune response.

So the correct option would be,

\(\rule{200}2\)

Related information:-

Passive immunity:-

It is the type of immunity when performed antibodies are introduced in the body . Like in case of smallpox. This doesn't last long in the body and requires repeated infusions in the body after coming in contact with the same pathogen again.

Also , it is helpful when quick reponse is required against the antigen and we don't have time to wait for generating immune response like in case of snake bites .

Answer:The answer is 36 since every second it give 6 that would be 6x6 which equal 36

Explanation:

36 Coulomb of electric charge is flowing through the wire.

Explanation:

Given that,

Current flowing in the wire, I = 6 A

Time, t = 6 seconds

To find,

The charge flowing through the wire.

Solution,

The rate of flow of electric charge per unit time is called electric current. Mathematically, the electric current is given by :

\(I=\dfrac{q}{t}\\\\q=It\)

Putting all the values,

\(q=6\times 6\\\\q=36\ C\), C is coulomb

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Answer:

42 Hz

Explanation:

Given,

Speed ( v ) = 210 m/s

Wavelength ( λ ) = 5 m

To find : Frequency ( f ) = ?

Formula : -

v = f λ

f = v / λ

= 210 / 5

f = 42 Hz

The electric field strength at a distance of 10 cm from a charge of 2 μC is 3.6 x 10⁵ N/C.

If there's a charge present in any form, an electric field is linked with every point in space. The strength and direction of the electric field are expressed by the value of E, sometimes referred to as the strength of the electrical field, electric field intensity, or simply the electric field.

The following formula determines the magnitude of the electric field generated by a point charge:

where,

E = Electrical Field Strength = ?

k = 9 x 10⁹ Nm²/C²

q = magnitude of charge

q = 2 μC = 2x 10⁻⁶ C

r = distance = 10 cm

r = 0.10 m

Therefore,

When the values are entered into the equation, we obtain:

E = 9 x 10⁹ * (2 x 10⁻⁶) / (0.1)²

E = 3.6 x 10⁵ N/C

Because of this, the electric field intensity at 10 cm from a 2 μC charge is  3.6 x 10⁵ N/C.
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Answer:

Sound is a type of energy made by a vibrating object.

Explanation:

You can create sounds by:

- A string plucked with force has greater amplitude

- A vibrating guitar string makes the sound, if you pluck the string harder, it will make a louder sound.

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer:

i really dont know im so sorry i wish i could help u out my friend

Answer:

workdone= 1/2mv^2

1/2×1500×30^2

675000J

Given data:

* The speed of the bus is 100 km/hr.

* The speed of the conductor is 6 km/hr.

Solution:

(a). If the bus and conductor are traveling in the same direction.

The net speed of the conductor relative to the road is,

where v_1 is the velocity of the conductor relative to the road, v_b is the velocity of the bus, and v_c is the velocity of the conductor inside the bus,

Substituting the known values,

Thus, the speed of the conductor relative to the road is 106 km/hr.

(b). The speed of the conductor relative to the bus is the speed of the conductor on the bus,

Thus, the speed of the conductor relative to the bus is 6 km/hr.

Answer:

Explanation:

Given that:

Charge (q) on the particle = 3 × 10⁻⁸ C

mass (m) of the particle = 6 × 10⁻⁹ kg

at a distance x = 15 cm , the velocity in the plate = 900 m/s²

For the square plate, the surface charged density σ = -8 × 10⁻⁶ C/m²

To start with calculating the electric field as a result of the square plate; we use the formula;

\(E = \dfrac{\sigma }{2 \varepsilon_o}\)

\(E = \dfrac{8 \times 10^{-6} }{2 \times 8.85 \times 10^{-12}}\)

\(E = 4.51977 \times 10^5 \ V/m\)

On the square plate; The electric force F = Eq

\(F = (4.51977 \times 10^5 \ V/m )(3\times 10^{-8} \ C)\)

\(F = 1.3559 \times 10^{-2} \ N\)

The acceleration \(a =\dfrac{ F}{m}{\)

\(a = \dfrac{1.3559\times 10^{-2} \ N}{6 \times 10^{-9} \ Kg}\)

\(a = 2.25988 \times 10^6 \ m/s^2\)

For the particle, the velocity at distance x = 7 m can be calculated by using the formula:

\((\dfrac{1}{2}) mv^2 = \Delta Vq\)

\(v^2 = \dfrac{2 Eq}{dm}\)

\(v^2 = \dfrac{2 * 4.51977 \times 10^5 \times 3 \times 10^{-8} }{0.07 \times 6\times 10^{-9} }\)

\(v^2 = 64568142.86 \ m/s\)

\(v =\sqrt{ 64568142.86 \ m/s}\)

\(\mathbf{v = 8.035 \times 10^3 \ m/s}\)

From the calculation, we realize that the charge acting between the particle and the plate is said to be "opposite".

Hence, the force is an attractive force.

Similarly, there is a gradual increase exhibited by the velocity of the particle.

Therefore, the particles get to the detector, but the detector failed to get detect due to the velocity which is greater than 1000 m/s.

Answer:

I think D?

Explanation:

Answer:

there are 1,000m in a km, so 200km is 200,000m

200,000m/10m/s = 20,000s

Explanation:

Please mark me Brainlyest

Answer:

Explanation:

ω = v / R

where ω is angular speed of a point situated at distance R from axis and having a linear speed of v .

Given v = 150 m/s ; R =.10 m

ω = 150 / .10

= 1500 radian /s .

Final angular speed is 1500 radian /s .

The vector characteristics of the electric field allow to find the result for the electric field at the point of interest is;

Given parameters.

    1) Electric charges:

    2)Charge positions

   3) Points of interest r = (0,0,1) = 1 \(\hat k\)  

To find.

the electric field at point r.

The intensity of the electric field is given by the ratio of the electric force to the positive test charge at the point of interest.

          \(E= k \frac{q}{r^2 }\)  

where E is the electric field, k the constant of Coulomb, q the charge and r the distance.

In the attached we see a diagram of the test charges and the distance to the point of interest on the z axis.

The total field is the vector addition of the fields created by each charge

          \(E_{total} = E_1 +E_2\)

Let's look for the components of each electric field.

Field created by charge q₁

          tan θ = \(\frac{z}{x}\)  

          tan θ = 1/1 = 1

          tea = 45º

x-axis

          cos 45 = \(\frac{E_{1x}}{E_1}\)

z axis

          sin 45=  \(\frac{E_{1z}}{E_1}\)  

          E₁ₓ = E₁ cos 45

          \(E_{1z}\)  = E₁ sin 45

Field created by load 2

y-axis

        cos 45 = \(\frac{E_{2y}}{E_2}\)  

z- axis

        sin 45 = \(\frac{E_{2z}}{E_2}\)  

        \(E_{2y}\) = E2 cos 45

        \(E_{2z}\) = E2 sin 45

We look for the components of the total electric field, where the signs are taken from the direction of the vectors in the attached.

    \(E_{total} = - E_{1x} \hat i + E_{2y} \hat j + ( E_{1z} - E_{2z} ) \hat k\)

Let's substitute.

         \(E_{total } = - E_1 cos 45 \hat i + E_2 cos 45 \hat j + (E_1 sin 45 - E_2 sin 45) \hat k\)

Let's find the distance for each charge to the test point using the Pythagorean Theorem.

         r₁₃² = x² + z²

         r₁₃² = 1 + 1

         r₁₃² = 2

         r₂₃² = y² + z²

         r₂₃² = 1² + 1²

         r₂₃² = 2

Let's look for the magnitud of the electric fields.

Charge q₁

        \(E_1 = k \frac{q_1}{r_{13}^2}\)  

        E₁ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₁ = 20 N / m

Charge q₂

        \(E_2 = k \frac{q_2}{r_{23}^2}\)  

        E₂ = \(9 \ 10^9 \frac{20 \ 10^{-9}}{2}\)  

        E₂ = 20 C / N

Let's substitute in the expression of the total eletric field.

         \(E_{total} = -20 \ cos45 \ \hat i + 20 \ cos 45\ \hat j + ( 20 -20) sin 45 \ \hat k\)

         \(E_{total} = 14.1 ( - \hat i + \hat j) \ \frac{N}{C}\)  

In conclusion using the vector characteristics of the electric field we can find the result for the electric field at the point of interest is;

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Assuming each trial represents 1000years, and rock samples were found, the rock sample will be given half-life of

We know that the parent Isotope remaining is given by the expression

\(\frac{1}{2}^n\)

where,

n = number of half lives passed

From the question, the parent Isotope remaining is \(25\%\) lokium

\(0.25 = \frac{1}{4} = \frac{1}{2^2} = \frac{1}{2}^2\)

Therefore,

\(\frac{1}{2}^2\) means 2 half lives have passed.

If from the question,

1 half life = 1000years

Therefore,

The rock sample's age = \(2*1000 = 2000years\)

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Explanation:

Acceleration is change in velocity over change in time.

a = Δv / Δt

a = (0 m/s − 7.2 m/s) / (12 min ×  60 s/min)

a = -0.01 m/s²

Answer:

0.3 N

Explanation:

Electromagnetic force is F= Kq1q2/r^2, where r is the distance between charges. If r is doubled then the force will be 1/4F which is 0.3 N.

The magnitude of the force exerted on Q by q when the distance between them is doubled is 0.3 N

F = Kq₁q₂ / r²

Where

From Coulomb's law,

F = Kq₁q₂ / r²

Cross multiply

Fr² = Kq₁q₂

Kq₁q₂ = constant

F₁r₁² = F₂r₂²

With the above formula, we can obtain the final force as follow:

F₁r₁² = F₂r₂²

1.2 × r² = F₂ × (2r)²

1.2r² = F₂ × 4r²

Divide both side by 4r²

F₂ = 1.2r² / 4r²

F₂ = 0.3 N

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a) It is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge.

a) Zero error refers to the deviation or discrepancy in the measurement instrument, where the indication or reading on the instrument is not zero when the quantity being measured is zero. In other words, it is the error present in the measuring instrument that causes it to register a value even when there is no input or output being measured.

Zero error can occur due to various reasons such as manufacturing defects, wear and tear, misalignment, or improper calibration of the instrument. It can be positive or negative, depending on whether the instrument reads higher or lower than the actual value.

b) An example of when you would have to allow for zero error is when using a measuring instrument like a vernier caliper or micrometer screw gauge. These instruments are commonly used to measure the dimensions of objects with high precision.

In a vernier caliper, for instance, zero error can occur when the jaws do not close perfectly when there is no object being measured. If the caliper shows a reading other than zero when the jaws are closed, it indicates the presence of zero error.

To obtain accurate measurements, the zero error needs to be accounted for and compensated. This can be done by adjusting the position of the zero on the scale or by subtracting the zero error value from the measured readings.

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Answer:

The speed of m2 just before it hits the ground is 2.1 m/s

Explanation:

mass on the ground m1 = 30 kg

mass oat rest at the above the ground m2 = 35 kg

height of m2 above the ground =2.9 m

Let the tension on the string be taken as T

for the mass m2 to reach the ground, its force equation is given as

\(m_{2} g - T = m_{2}a\)    ....equ 1

where g is acceleration due to gravity = 9.81 m/s^2

and a is the acceleration with which it moves down

For mass m1 to move up, its force equation is

\(T - m_{1} g = m_{1} a\)

\(T = m_{1}a + m_{1}g\)

\(T = m_{1}(a + g)\)    ....equ 2

substituting T in equ 1, we have

\(m_{2} g - m_{1}(a+g) = m_{2}a\)

imputing values, we have

 \((35*9.81) - 30(a+9.81) = 35a\)

 \(343.35 - 30a-294.3 = 35a\)

\(343.35 -294.3 = 35a+ 30a\)

\(49.05 = 65a\)

a = 49.05/65 = 0.755 m/s^2

The initial velocity of mass m2 = u = 0

acceleration of mass m2 = a = 0.755 m/s^2

distance to the ground = d = 2.9 m

final velocity = v = ?

using Newton's equation of motion

\(v^{2}= u^{2} + 2ad\)

substituting values, we have

\(v^{2}= 0^{2} + 2*0.755*2.9\)

\(v^{2}= 2*0.755*2.9 = 4.379\\v = \sqrt{4.379}\)

v = 2.1 m/s

Answer:

No, all supply curves do not look basically the same in terms of slope and shape. The slope and shape of a supply curve depend on the specific market conditions and the behavior of the suppliers. The supply curve can have different slopes, ranging from being perfectly elastic to perfectly inelastic. The slope of the supply curve reflects the responsiveness of the quantity supplied to changes in the price of the good or service.

In terms of shape, the supply curve can take on different forms such as being linear or curved. The shape of the supply curve depends on the behavior of the suppliers and their ability to adjust the quantity supplied to changes in the price of the good or service. For example, if suppliers can easily adjust their production levels in response to changes in price, then the supply curve may be flatter or more horizontal, indicating a more elastic supply. On the other hand, if suppliers face higher costs or constraints on their ability to increase production, the supply curve may be steeper or more vertical, indicating a less elastic supply.

Therefore, the slope and shape of a supply curve can vary depending on the market conditions and the behavior of the suppliers, and cannot be generalized as being the same for all supply curves.

The given problem can be exemplified in the following diagram:

To determine the value of the force "F" we need to add the forces in the direction of the inclined plane. Since we want the velocity to stay constant then the acceleration must be zero and therefore, the sum of the forces must add up to zero, therefore, we have:

Where:

Now we solve for the Force "F" by adding the force of friction and the component of the weight in both sides of the equation:

To determine the force of friction we will use the following equation:

Where:

The normal force can be determined by adding the forces in the perpendicular direction of the incline, we get:

Where:

Now we need to determine the components of the weight. To do that we will use the following triangle:

Using the trigonometric function cosine we get:

Now we multiply both sides by "mg":

Replacing the values we get:

Solving the operations:

Now we use the trigonometric function sine:

Now we multiply both sides by "mg":

Replacing the values:

Solving the operations:

Now we replace the perpendicular component in the formula for the normal:

Therefore, the normal force is:

Now we replace the value of the normal force in the formula for the force of friction:

Solving the operation we get:

Now we replace in the formula for the force "F":

Replacing the values:

Solving the operations

Therefore, the required force is 139.33 Newtons.

Answer:

Approximately \(3.967\; {\rm kg\cdot m\cdot s^{-1}}\).

Explanation:

Convert velocity to the standard units (meters per second):

\(\begin{aligned}v &= 246.2 \; {\rm km \cdot h^{-1}} \\ &= 246.2 \; {\rm km \cdot h^{-1}}\times \frac{1\; {\rm h}}{3600\; {\rm s}} \times \frac{1000\; {\rm m}}{1\; {\rm km}} \\ &\approx 68.389\; {\rm m\cdot s^{-1}}\end{aligned}\).

Convert mass to standard units (kilograms):

\(\begin{aligned} m &= 58\; {\rm g} \\ &= 58\; {\rm g} \times\frac{1\; {\rm kg}}{1000\; {\rm g}}\\ &= 0.058\; {\rm kg}\end{aligned}\).

When an object of mass \(m\) travels at a velocity of \(v\), momentum of that object would be \(p = m\, v\). In standard units, the momentum of this tennis ball would be:

\(\begin{aligned}p &= m\, v \\ &\approx (0.058\; {\rm kg})\, (68.389\; {\rm m\cdot s^{-1}}) \\ &\approx 3.967\; {\rm kg \cdot m\cdot s^{-1}}\end{aligned}\).

The average time it took for the tablet pieces to dissolve in room-temperature water is 42.00 seconds.

Room temperature refers to the typical temperature range that is comfortable for humans in an indoor environment. It is generally considered to be between 68°F (20°C) and 77°F (25°C). However, the exact definition of room temperature can vary depending on the context and the standards of a particular region or industry. In scientific experiments or industrial settings, room temperature may be defined more precisely and may range from 20°C to 25°C, or even narrower ranges such as 22°C to 24°C.

To calculate the average time it took for the tablet pieces to dissolve in room temperature water, we need to add up the times from all three trials and divide by the number of trials (3):

(41.00 + 44.00 + 41.00) / 3 = 42.00 seconds

Therefore, the average time it took for the tablet pieces to dissolve in room-temperature water is 42.00 seconds.

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The instantaneous current at the same moment in the RL circuit can be expressed as I = Imaxsin(150), where Imax represents the maximum current.

1. Given that the instantaneous voltage at a specific moment in the RL circuit is V = Vmaxsin(150).

2. We can express the current at the same moment using Ohm's Law, which states that V = IR, where V is voltage, I is current, and R is resistance.

3. In an RL circuit, the resistance is represented by the symbol R, and it is typically associated with the resistance of the wire or any resistors in the circuit.

4. However, the given equation does not explicitly mention resistance.

5. Since we are considering an RL circuit, it suggests the presence of inductance (L) along with resistance (R).

6. In an RL circuit, the voltage across the inductor (VL) can be expressed as VL = L(di/dt), where L is the inductance and di/dt represents the rate of change of current.

7. At any given instant, the total voltage across the circuit (V) can be expressed as the sum of the voltage across the resistor (VR) and the voltage across the inductor (VL).

8. Therefore, V = VR + VL.

9. Since the given equation represents the instantaneous voltage (V), we can deduce that V = VR.

10. By comparing V = VR with Ohm's Law (V = IR), we can conclude that I = Imaxsin(150), where Imax represents the maximum current.

The specific values of Vmax, Imax, and the phase angle have not been provided in the question, so we are working with the general expression.

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Answer: The half-life is the amount of time it takes for a given isotope to lose half of its radioactivity. If a radioisotope has a half-life of 14 days, half of its atoms will have decayed within 14 days. In 14 more days, half of that remaining half will decay, and so on.

The boiling point of a substance depends on the strength of the intermolecular forces between its molecules. In the case of the two substances you mentioned, even though they have different molecular sizes, they can still have the same boiling point if they have similar intermolecular attractions.

For example, the smaller molecule may have a higher polarity due to the presence of polar bonds, which can result in dipole-dipole interactions between molecules. The larger molecule may have a similar dipole moment even though it has more atoms, or it may have a polar functional group that contributes to its intermolecular interactions.

In addition to dipole-dipole interactions, the molecules may also have London dispersion forces, which are present in all molecules due to the random fluctuations in electron density. These forces are proportional to the size of the molecule, so the larger molecule may have a stronger dispersion force even if it is less polar than the smaller molecule.

Therefore,, it is possible for two different molecules to have the same boiling point if they have similar intermolecular attractions, such as dipole-dipole interactions and London dispersion forces. The size of the molecule may also play a role in determining the strength of these forces, but it is not the only factor.

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The vector arrow representing an acceleration of magnitude 3 m/s² and different from vector arrow representing a negative acceleration of magnitude 3 m/s² so they are perpendicular forming a 90-degree angle between each other. Hence, option C is correct.

A vector has both magnitude and direction. It is frequently depicted as an arrow with a length proportionate to the magnitude and a direction matching the magnitude of the quantity. A vector lacks position, but possesses magnitude and direction. In other words, if a vector is shifted parallel to itself, its shape remains unchanged as long as its length remains constant.

According to the question,

The acceleration of magnitude 3 m/s² and different form the vector arrow representing a negative acceleration of magnitude 3 m/s².

Hence, they are perpendicular, forming a 90-degree angle between each other.

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Answer:

Answer:

Explanation:

C looks good,  b/c antinodes are where the waves is at a max displament.

The wave has exactly three antinodes is option C.

As in all status wave styles, each node is separated through an antinode. This sample with 3 nodes and two antinodes is known as the second one harmonic and is depicted within the animation.

The other of a node is an anti-node, a factor where the amplitude of the status wave is at most. those occur midway among the nodes. In a full wavelength of a status wave, there are two loops. So, there should be  nodes midway of every of the two loops.

Wave, propagation of disturbances from location to vicinity in a ordinary and prepared manner. maximum acquainted are floor waves that journey on water, however sound, mild, and the movement of subatomic particles all exhibit wavelike residences.

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