The radius of the circular path of an ion in a mass spectrometer is given by r=1/B √2Vaccelm/q. Use this equation to explain how a mass spectrometer is able to separate ions of different masses.
The mass spectrometer separates ions of different masses by utilizing the relationship between the strength of the magnetic field, the accelerating voltage, the charge-to-mass ratio of the ions, and the resulting radius of the circular path
What is the mass spectrometer?From the formula in the question;
B is a symbol for the magnetic field's intensity as it is applied to the mass spectrometer.
The accelerating voltage used to move the ions is called Vaccelm.
The charge of the ion, specifically its charge-to-mass ratio (q/m), is represented by the letter q.
The mass spectrometer may selectively alter the radius of the circular route for various ions by varying the magnetic field's intensity (B). This makes it possible to spatially segregate ions with various masses based on their various radii. The ions' locations and masses can then be measured using detectors placed along the journey.
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how are dams made do they just freeze time?
Answer:
Gravity dams are so named because they are held to the ground by gravity – they weigh a lot, and are typically made from concrete or stone. Engineers must de-water the river where the dam is meant to be built. This is done by diverting the river through a tunnel that runs around the intended construction zone.
Answer:First, they dug tunnels from below the dam to above the dam. Then, they put the cofferdam in place, and opened the tunnels. The water flowed around the site where the permanent dam would be built until they were done, at which point the cofferdam was removed.
Explanation:hope this helped
When discussing you will be defending your thoughts of the following questions:
1. Children’s appetites and willingness to eat are strongly influenced by the mealtime environment. Identify and briefly discuss several features that can be used to create an atmosphere that encourages children to eat.
2. Review the My Plate food guide and suggest appropriate snack foods from each food group that would be appropriate for school-age children.
3. In what ways can adults help children learn to enjoy nutritious food and establish healthy eating habits?
To encourage children to eat, create a pleasant and distraction-free mealtime environment, serve a variety of visually appealing and small portions of favorite foods, involve them in meal planning and preparation, provide a relaxed and comfortable atmosphere, and avoid using food as a reward or punishment. Appropriate snack foods from each food group for school-age children can be selected from fruits, vegetables, grains, protein, and dairy. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food choices, and avoiding using food as a reward or punishment.
1. To create an atmosphere that encourages children to eat, several features can be used, such as:
A pleasant and inviting mealtime environment that is free of distractions such as television, mobile phones, or tablets.
Serve a variety of colorful, visually appealing foods in small portions, making sure to include favorite foods of the child.
Involve children in meal planning and preparation, giving them the opportunity to select foods and participate in simple meal preparation tasks.
Provide a relaxed and comfortable atmosphere by allowing enough time for meals and offering positive reinforcement for good eating behaviors.
Avoid using food as a reward or punishment and ensure that mealtimes are stress-free and enjoyable for children.
2. MyPlate is a visual representation of the five food groups that form a healthy and balanced diet. Appropriate snack foods from each food group for school-age children could include:
Fruits: apple slices, berries, bananas, or orange wedges.
Vegetables: carrot sticks, cherry tomatoes, cucumber slices, or celery sticks.
Grains: whole-grain crackers, granola bars, rice cakes, or air-popped popcorn.
Protein: hard-boiled eggs, cheese sticks, nut butter, or hummus.
Dairy: yogurt, milk, or cheese cubes.
3. Adults can help children learn to enjoy nutritious food and establish healthy eating habits by:
Modeling healthy eating behaviors and food choices themselves.
Encouraging children to try new foods and flavors, involving them in grocery shopping, and meal planning.
Making meals enjoyable and fun by creating a positive mealtime environment and involving children in meal preparation tasks.
Providing healthy food choices and limiting the availability of unhealthy options at home and school.
Offering regular mealtimes and avoiding using food as a reward or punishment.
Hence, Encourage children to eat by providing a pleasant and distraction-free mealtime environment, serving a variety of visually appealing and small portions of favorite foods, involving them in meal planning and preparation, providing a relaxed and comfortable environment, and avoiding using food as a reward or punishment. Fruits, vegetables, grains, protein, and dairy are examples of appropriate snack foods from each food group for school-age children. Adults can assist children in learning to enjoy nutritious food and develop healthy eating habits by modeling healthy eating behaviors, involving children in grocery shopping and meal planning, making meals enjoyable and fun, providing healthy food options, and avoiding using food as a reward or punishment.
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it is required that an object weighing 8N be moved up ward at an acceleration of 2m/s what is the upward force needed
Answer:
F = 1.6 N
Explanation:
Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:
F = ma
where,
F = Force Required to Move the Object Upward = ?
m = mass of object
a = upward acceleration = 2 m/s²
but, we know that weight of object is given as:
Weight = mg
8 N = m(9.8 m/s²)
m = 0.8 kg
using values in the equation:
F = (0.8 kg)(2 m/s²)
F = 1.6 N
Approximately how many times louder is a 150-dB sound than a 80-dB sound?
a 150-dB sound is approximately 10 million times louder than an 80-dB sound.
What is the range of sound?Provide instances of the differences between the audible, ultrasonic, and infrasonic frequency ranges. Three sorts of sound waves, each covering a distinct frequency range, are used. These are what they are:
Waves that fall inside the ear's sensitivity range are referred to be audible waves.Infrasonic waves are those whose frequencies fall below the range of human hearing. Ultrasonic waves are those with frequencies higher than those of sound.The difference in decibels between two sounds is related to the ratio of their intensities (or power) by the following formula:
dB₂ - dB₁ = 10 log10(I₂ / I₁)
where dB₁ and dB₂ are the decibel levels of the two sounds, and I₁ and I₂ are their intensities (or power).
Using this formula, we can find the ratio of the intensity of a 150-dB sound to that of an 80-dB sound:
150 dB - 80 dB = 10 log10(I₁₅₀ / I₈₀)
70 = 10 log10(I₁₅₀ / I₈₀)
7 = log10(I₁₅₀ / I₈₀)
10^7 = I₁₅₀ / I₈₀
I₁₅₀ = 10^7 * I₈₀
This shows that the intensity of a 150-dB sound is 10 million times greater than that of an 80-dB sound.
Therefore, a 150-dB sound is approximately 10 million times louder than an 80-dB sound.
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Using the information from the movie champions what is one conclusion about the history of the sports
One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.
What is Champions about?From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.
The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.
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2. A tennis ball machine launches balls horizontally with an initial speed of 5.3 m/s, from a height of 1.2 m.
a) What will the time of flight be for a tennis ball launched by the ball machine? (3)
b) What will the range of the tennis ball be? (2)
c) What will be the final velocity of the ball with which it reaches the ground? (3)
(a) The time of flight be for a tennis ball launched by the ball machine is 0.19 s.
(b) The range of the tennis ball be is 1.01 m.
(c) The final velocity of the ball with which it reaches the ground is 7.16 m/s.
Time of flight of tennis ballThe time of flight of the tennis ball is calculated as follows;
h = vt + ¹/₂gt²
1.2 = 5.3t + 0.5(9.8)t²
1.2 = 5.3t + 4.9t²
4.9t² + 5.3t - 1.2 = 0
a = 4.9, b = 5.3, c = 1.2
solve using quadratic formula
t = 0.19 s
Thus, the time of flight be for a tennis ball launched by the ball machine is 0.19 s.
Range of the tennis ballThe range of the tennis ball is calculated as follows;
R = vt
R = 5.3 x 0.19
R = 1.01 m
Final velocity of the ballThe final velocity of the ball with which it reaches the ground is calculated as follows;
vf = vo + gt
vf = 5.3 + 9.8(0.19)
vf = 7.16 m/s
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At t = 0, one toy car is set rolling on a straight track with initial position 13.0 cm, initial velocity -3.6 cm/s, and constant acceleration 2.20 cm/s2. At the same moment, another toy car is set rolling on an adjacent track with initial position 11.5 cm, initial velocity 5.40 cm/s, and constant zero acceleration. (a) At what time, if any, do the two cars have equal speeds? (Enter NA if the cars never have equal speeds.) s (b) What are their speeds at that time? (Enter NA if the cars never have equal speeds.) cm/s (c) At what time(s), if any, do the cars pass each other? (If there is only one time, enter NA in the second blank. If there are two times, enter the smaller time first. If they never pass, enter NA in both blanks.) s s (d) What are their locations at that time? (If there is only one position, enter NA in the second blank. If there are two positions, enter the smaller position first. If they never pass, enter NA in both blanks.) cm cm (e) Explain the difference between question (a) and question (c) as clearly as possible.
Answer:
that's too much to read
II. Understanding Concepts
Skill: Hypothesizing
1. The dots in the balloon represent particles of air. Use what you know about
pressure, temperature, volume, and the kinetic theory of matter to write a
hypothesis explaining what will happen to the volume of the balloon if
pressure is kept constant and the temperature is lowered.
Answer in complete sentences
As the temperature of the balloon is lowered, its volume will decrease as well.
What is kinetic theory of matter?
The kinetic theory of matter says that all matter consists of many, very small particles which are constantly moving or in a continual state of motion.
According to Charles law, the volume of a fixed mass of a gas is directly proportional to its absolute temperature.
Based on Charles law, as the temperature of the balloon is lowered, its volume will decrease as well because the average kinetic energy of the gas molecules has reduced, the rate of gas collision decreased, which will cause a drop in the volume of the balloon.
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(100 POINTS AND BRAINLIEST)
1. What are the four groups of carbon compounds found in living things?
2. Classify each substance as either sugar, starch, protein, or nucleic acid.
a. the major compound that makes up the skin
b. glucose
c. the major compound in potatoes
d. DNA
3. What is the difference between saturated and unsaturated fat? Why are partially hydrogenated fats useful for making potato chips but not particularly healthy for humans to eat?
1. carbohydrates, lipids, proteins, and nucleic acids.
2. a is protein b is sugar c is starch and d is nuclear acid
3. What is the difference between saturated and unsaturated fat? it's that Saturated fats have the maximum number of hydrogens possible, while unsaturated fats have a double bond between two of the carbons. part 2. Why are partially hydrogenated fats useful for making potato chips but not particularly healthy for humans to eat? I was not able to find a different answer for it than part 1.
Can someone explain how to do the algebra for this question? I know everything else, I just don’t know how to rearrange the question to solve for v.
Answer:
Refer to the step-by-step Explanation.
Step-by-step Explanation:
Simplify the equation with given substitutions,
Given Equation:
\(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2\)
Given Substitutions:
\(\omega=v/R\\\\ \omega_{_{0}}=v_{_{0}}/R\\\\\ I=(2/5)mR^2\)\(\hrulefill\)
Start by substituting in the appropriate values: \(mgh+(1/2)mv^2+(1/2)I \omega^2=(1/2)mv_{_{0}}^2+(1/2)I \omega_{_{0}}^2 \\\\\\\\\Longrightarrow mgh+(1/2)mv^2+(1/2)\bold{[(2/5)mR^2]} \bold{[v/R]}^2=(1/2)mv_{_{0}}^2+(1/2)\bold{[(2/5)mR^2]}\bold{[v_{_{0}}/R]}^2\)
Adjusting the equation so it easier to work with.\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the left-hand side of the equation:
\(mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
Simplifying the third term.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2} \Big[\dfrac{2}{5} mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{2}\cdot \dfrac{2}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v}{R} \Big]^2\)
\(\\ \boxed{\left\begin{array}{ccc}\text{\Underline{Power of a Fraction Rule:}}\\\\\Big(\dfrac{a}{b}\Big)^2=\dfrac{a^2}{b^2} \end{array}\right }\)
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2 \cdot\dfrac{v^2}{R^2} \Big]\)
"R²'s" cancel, we are left with:
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5}mv^2\)
We have like terms, combine them.
\(\Longrightarrow mgh+\dfrac{1}{2} mv^2+\dfrac{1}{5} \Big[mR^2\Big]\Big[\dfrac{v^2}{R^2} \Big]\\\\\\\\\Longrightarrow mgh+\dfrac{7}{10} mv^2\)
Each term has an "m" in common, factor it out.
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)\)
Now we have the following equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac12mv_{_{0}}^2+\dfrac12\Big[\dfrac25mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\)
\(\hrulefill\)
Simplifying the right-hand side of the equation:
\(\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac12\cdot\dfrac25\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}}{R}\Big]^2\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\Big]\Big[\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15\Big[mR^2\cdot\dfrac{v_{_{0}}^2}{R^2}\Big]\\\\\\\\\Longrightarrow \dfrac12mv_{_{0}}^2+\dfrac15mv_{_{0}}^2\Big\\\\\\\\\)
\(\Longrightarrow \dfrac{7}{10}mv_{_{0}}^2\)
Now we have the equation:
\(\Longrightarrow m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
\(\hrulefill\)
Now solving the equation for the variable "v":
\(m(gh+\dfrac{7}{10}v^2)=\dfrac{7}{10}mv_{_{0}}^2\)
Dividing each side by "m," this will cancel the "m" variable on each side.
\(\Longrightarrow gh+\dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2\)
Subtract the term "gh" from either side of the equation.
\(\Longrightarrow \dfrac{7}{10}v^2=\dfrac{7}{10}v_{_{0}}^2-gh\)
Multiply each side of the equation by "10/7."
\(\Longrightarrow v^2=\dfrac{10}{7}\cdot\dfrac{7}{10}v_{_{0}}^2-\dfrac{10}{7}gh\\\\\\\\\Longrightarrow v^2=v_{_{0}}^2-\dfrac{10}{7}gh\)
Now squaring both sides.
\(\Longrightarrow \boxed{\boxed{v=\sqrt{v_{_{0}}^2-\dfrac{10}{7}gh}}}\)
Thus, the simplified equation above matches the simplified equation that was given.
what is the process that creates wind.
Answer:
Winds are caused by differences in air pressure. Unequal heating of Earth’s surface creates areas of different pressure. Cooler areas have higher air pressure. Warmer areas have lower pressure. This causes air to move from high pressure to low pressure. This movement is the wind we feel.
plz mark me as brainliest.
Which is the correct sequence of transfers in a typical coal fired power plant?
To find
Which is the correct sequence of transfers in a typical coal fired power plant?
Explanation
The coal is heated which converts the chemical energy to heat.This heat works as thermal energy which helps in rotation of the turbine which is the kinetic energy. This kinetic energy then works as a mechanical energy which prioduces electricity which is the electric energy
Conclusion
The correct sequence is
A. chemical-thermal-kinetic-mechanical-electrical
Activity
In this activity, you will solve the following problems using the rules for adding and subtracting and multiplying and dividing with significant
figures
Part A
28.97 + 45.876
Explanation:
We need to add 28.97 and 45.876.
Here, the first no is 28.97 and other no is 45.876
Here, 28.97 is the least precise value and 45.876 is most precise.
28.97 + 45.876 = 74.846
We need to write the final answer such that there is two digit after the decimal. So, 28.97 + 45.876 = 74.85 because 6 is more than 5 i.e. we add 1 to 4.
Answer:
28.97
+ 45.876
74.846
Explanation:
Because 28.97 has only two decimal places, round off the answer to two decimal places: 74.85.
In the electric of capacitance 4 ,3 and 2 microfaradas, respectively, are connected in senes to a battery of 260 V , calculate the charge?
The total charge in the circuit is 240 microcoulombs.
To calculate the total charge in a series circuit with capacitors, we need to use the formula Q = CV, where Q represents the charge, C is the capacitance, and V is the voltage.
In this case, we have three capacitors connected in series with capacitances of 4 μF, 3 μF, and 2 μF, respectively. The voltage across the circuit is 260 V.
To find the total capacitance (C_total) in a series circuit, we use the reciprocal rule: 1/C_total = 1/C1 + 1/C2 + 1/C3. Plugging in the values, we get 1/C_total = 1/4 + 1/3 + 1/2.
Simplifying this equation gives us 1/C_total = (3 + 4 + 6)/12 = 13/12. Taking the reciprocal, we find C_total = 12/13 μF.
Now, we can calculate the total charge (Q_total) using Q = C_total × V. Substituting the values, we get Q_total = (12/13) μF × 260 V.
Calculating the numerical value, Q_total = (12/13) × 260 = 240 μC (microcoulombs).
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A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magnetic field at the center of this loop is...?
The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.
Current in the wireThe current in the wire is calculated as follows;
V = IR
I = V/R
I = 16.7/0.251
I = 66.53 A
Magnetic field at the center of the loopThe magnetic field at the center of the circular loop is calculated as follows;
\(B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T\)
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When the dried-up seed pod of a scotch broom plant bursts open, it shoots out a seed with an initial velocity of 2.65 m/s
at an angle of 30.0 ∘ below the horizontal. The seed pod is 0.460 m
above the ground.
How long does it take for the seed to land?
t= ? sec
What horizontal distance does it cover during its flight?
x=? M
Answer:
To solve this problem, you'll need to break the initial velocity of the seed into its horizontal and vertical components, then use the equations of motion to find the time of flight and horizontal distance.
The initial velocity (v) of the seed is 2.65 m/s. The angle it's launched at (θ) is 30.0 degrees below the horizontal. The height (h) it's launched from is 0.460 m.
First, calculate the horizontal (v_x) and vertical (v_y) components of the velocity. Because the seed is launched downward, the vertical component will be negative:
v_x = v * cos(θ) = 2.65 m/s * cos(30.0) = 2.29 m/s
v_y = v * sin(θ) = -2.65 m/s * sin(30.0) = -1.325 m/s
Next, use the equation of motion to find the time it takes for the seed to hit the ground:
h = v_y * t + 0.5 * g * t^2
Where g is the acceleration due to gravity, which is approximately 9.8 m/s². Solving the equation for t gives:
t = (-v_y - sqrt((v_y)^2 - 4 * 0.5 * g * (-h))) / (2 * 0.5 * g)
Plugging in the values:
t = (1.325 + sqrt((-1.325)^2 - 4 * 0.5 * 9.8 * (-0.460))) / (2 * 0.5 * 9.8)
t = 0.182 seconds
Finally, use the horizontal velocity and time of flight to find the horizontal distance the seed covers:
x = v_x * t = 2.29 m/s * 0.182 s = 0.417 m
So, the seed lands after approximately 0.182 seconds and travels approximately 0.417 meters horizontally.
1 If electromagnetic radiation acted like particles in the double-slit experiment, what would be observed?
a The screen would remain dark because no radiation would reach the screen.
b One bright band would appear in the center of the screen.
c A series of light and dark bands would appear on the screen.
d Two bright bands would appear on the screen in line with the slits.
2 Which statement about the interference behavior of electromagnetic radiation seen in the double-slit test experiment is true?
a Waves that make up the radiation collide with each other so that they add together or cancel each other out.
b Particles that make up the radiation collide with each other and scatter randomly.
c Particles that make up the radiation collide with each other so that they add together or cancel each other out.
d Waves that make up the radiation do not interact with each other.
3 Which statement about the observed results of the double-slit experiment is true?
a Waves that are out of phase constructively interfere to create bright bands.
b Waves that are in phase destructively interfere to create bright bands.
c Waves that are out of phase constructively interfere to create bright bands.
d Waves that are in phase constructively interfere to create bright bands.
4 Which statement about the observed results of the double-slit experiment is true?
a Waves that are in phase constructively interfere to form dark bands.
b Waves that are out of phase constructively interfere to form dark bands.
c Waves that are in phase destructively interfere to form dark bands.
d Waves that are out of phase destructively interfere to form dark bands.
5 A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true about the new interference pattern seen on the screen compared to the original interference pattern?
a The spacing between the dark fringes will increase.
b The spacing between the bright fringes will increase.
c The spacing between the bright fringes will decrease.
d The spacing between the dark fringes will remain the same.
6 Consider the two-slit interference experiment. Electromagnetic radiation passes through the two slits that are a distance of 0.0170 nm apart. A fourth-order bright fringe forms at an angle of 8.0 degrees relative to the incident beam. What is the wavelength of the light?
a 789 nm
b 420 nm
c 581 nm
d 591 nm
Answer:
1. Two bright bands would appear on the screen in line with the slits.
2. Waves that make up the radiation collide with each other so that they add together or cancel each other out.
3. Waves that are in phase constructively interfere to create bright bands.
4. Waves that are out of phase destructively interfere to form dark bands.
5. The spacing between the bright fringes will decrease.
6. 581 nm
Explanation:
A certain electric dipole consists of charges + and − separated by distance , oriented along the -axis as shown in the figure. Find an expression for the magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole. Assume that is much greater than . Enter your answer in terms of , , , and 0.
I've seen other questions like this but the answers are coming back as incorrect or they have it with k included. Please help!
The magnitude of the electric field of the dipole at a point far away in the -direction, a distance away from the midpoint of the dipole is given by
|E| = |-(p * k) / r^3|
What is magnitude of the electric field?Generally, The electric field of an electric dipole at a point far away from the midpoint of the dipole is given by the following expression:
E = (p * k) / r^3 * (3 *cos(theta) * i^ + sin(theta) * j^)
where:
p is the magnitude of the dipole moment, equal to q * d (q is the charge and d is the distance between the charges)
k is the Coulomb constant (9 x 10^9 N * m^2/C^2)
r is the distance from the dipole to the point where the electric field
is being calculated theta is the angle between the vector pointing from the dipole to the point where the electric field is being calculated and the dipole moment vector (in this case, the -axis) i^ and j^ are the unit vectors in the x and y directions, respectively.
Since the dipole is oriented along the -axis and the point where the electric field is being calculated is far away in the -direction,
theta = pi and the expression for the electric field becomes:
E = (p * k) / r^3 * (3 *cos(pi) * i^ + sin(pi) * j^)
E = -(p * k) / r^3 * (i^)
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help
1. Calculate the Energy of skater at all the positions shown. Position C is the highest point the skater reaches
The energy of the skater at each position is:
A: 1920 JB: 1764 JC: 3528 JHow to calculate conservation of energy?At position A, the skater is at the lowest point, so the PE is zero. The KE can be calculated using the formula KE = (1/2)mv², where m is the mass of the skater and v is the velocity:
KE = (1/2)(60 kg)(8 m/s)²
KE = 1920 J
Therefore, at position A, the skater has 1920 J of kinetic energy and 0 J of potential energy.
At position B, the skater has gained some height, so there is some potential energy. The KE can be calculated as before, and the PE can be calculated using the formula PE = mgh, where m is the mass of the skater, g is the acceleration due to gravity (9.81 m/s²), and h is the height:
KE = (1/2)(60 kg)(8 m/s)²
KE = 1920 J
PE = (60 kg)(9.81 m/s²)(3 m)
PE = 1764 J
Therefore, at position B, the skater has 1920 J of kinetic energy and 1764 J of potential energy.
At position C, the skater has reached the highest point, so the KE is zero. The PE can be calculated as before:
PE = (60 kg)(9.81 m/s²)(6 m)
PE = 3528 J
Therefore, at position C, the skater has 0 J of kinetic energy and 3528 J of potential energy.
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Si la masa es 15.0 kg y la aceleración es 3.0 m/s^2, halla la fuerza en Newton.
By applying Newton's Second Law of Motion, the force acting on the mass is 45.0 Newton.
Given the following data:
Mass = 15.0 kilogramsAcceleration = 3.0 \(m/s^2\)To determine the force acting on the mass in Newton, we would apply Newton's Second Law of Motion:
Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on the physical object or body, and inversely proportional to its mass.
Mathematically, Newton's Second Law of Motion is given by this formula;
\(Force = mass \times acceleration\)
Substituting the given parameters into the formula, we have;
\(Force = 15.0 \times 3.0\)
Force = 45.0 Newton
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Answer:
(A) By reducing friction
Answer:
A
Explanation:
A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A constant tangential force of 290 N applied to its edge causes the wheel to have an angular acceleration of 0.854 rad/s2.
(a) What is the moment of inertia of the wheel?
kg · m2
(b) What is the mass of the wheel?
kg
(c) If the wheel starts from rest, what is its angular velocity after 5.80 s have elapsed, assuming the force is acting during that time?
rad/s
Answer:
c
Explanation:
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A roller coaster is at a peak of 20m and has a mass of 900kg. What is the potential energy of the roller coaster?
O 100000 J
10000 J
O 9.8 J
O 176400 J
The potential energy of the roller coaster is 176,400 J (joules).
The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.
In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).
Using the formula, we can calculate the potential energy:
PE = mgh
= (900 kg)(9.8 \(m/s^2\))(20 m)
= 176,400 J
Therefore, the potential energy of the roller coaster is 176,400 J (joules).
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A man has a mass of 66 kg on earth. What’s his weight in pounds?
Answer:
646.8 N
Explanation:
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Answer:
I'm not 100% sure, but I think the answer would be the first one because there's a force pushing the object in every direction, so they would cancel eachother out and make the object stay in the same place.
Explanation:
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Which of the following is NOT part of the grain group?
Answer:
Any food made from wheat, rice, oats, cornmeal, barley, or another cereal grain is a grain product. Anything else is not
Explanation:
Select the correct answer.
A boat moves 60 kilometers east from point A to point B. There, it reverses direction and travels another 45 kilometers toward point A. What are the total
distance and total displacement of the boat?
O A.
OB.
O C.
O D.
The total distance is 105 kilometers and the total displacement is 45 kilometers east.
The total distance is 60 kilometers and the total displacement is 60 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east.
The total distance is 60 kilometers and the total displacement is 45 kilometers east.
The total distance is 105 kilometers and the total displacement is 15 kilometers east. Option C
How to solve for the total distanceTo calculate the total distance, we add the distances traveled in each leg of the journey: 60 kilometers (from A to B) + 45 kilometers (from B back to A) = 105 kilometers.
However, displacement refers to the change in position of an object in a straight line from its starting point to its ending point. In this case, since the boat starts and ends at the same point (A), the total displacement is zero.
Hence The total distance is 105 kilometers and the total displacement is 15 kilometers east.
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(I) A car slows down from 28 m????s to rest in a distance of 88 m. What was its acceleration, assumed constant?
Answer:
The value is \(a = - 4.45 m/s^2\)
Explanation:
From the question we are told that
The initial speed is \(u = 28 \ m/s\) at a distance of \(s_1 = 0 \ m\)
The final speed is \(v = 0 \ m/s\) at a distance of \(s_2 = 88 \ m\)
Generally from the kinematic equation we have that
\(v^2 = u^2 +2as\)
=> \(a = \frac{v^2 - u^2 }{ 2(s_2 - s_1 )}\)
=> \(a = \frac{0 - 28^2 }{ 2(88 - 0 )}\)
=> \(a = - 4.45 m/s^2\)
The negative sign shows that it is decelerating
a plane wall is 250mm thick and it's wall area is 4.5m^2. if the thermal conductivity is 9.35w/m°c and surface temperature are steady at 150°c and 40°c. calculate the heat flow across the plane wall and the temperature gradient in the flow direction
The temperature gradient in the flow of direction is 294525 W.
What is Temperature gradient?A temperature gradient is the gradual variance in temperature with distance. The slope of the gradient is consistent within a material. A gradient is established anytime two materials at different temperatures are in physical contact with each other.
Q= T/( L/ KA)
Q= ( 1500 − 450) / 0.15 / 9.35v * 4.35)
= 294525 W
Units of measure of temperature gradients are degrees per unit distance, such as °F per inch or °C per meter.
Many temperature gradients exist naturally, while others are created. The largest temperature gradient on Earth is the Earth itself. Q= T/Ka.
Therefore, The temperature gradient in the flow of direction is 294525 W.
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