A hollow cylinder (hoop) is rolling on a horizontal surface at speed v = 4.3 m/s when it reaches a 15° incline. How far up the incline will it go, and how long will it be on the incline before it arrives back at the bottom?
Answers
The hoop will go up the incline 1.25 m and will be on the incline for 0.67 s before arriving back at the bottom.
Find the velocity of the hoop as it starts up the incline using conservation of energy:
(1/2)mv^2 = (1/2)Iω^2 + mgh
where m is the mass of the hoop, v is its initial velocity, I is the moment of inertia, ω is the angular velocity, and h is the height it will reach. Since it's a hoop, I = mr^2 where r is the radius. Solving for ω and using v = rω, we get ω = v/r and
h = (v^2/2g)(1 - cos θ) = 1.25 m.
Find the time it takes to travel up and back down the incline:
t = 2(vsin θ)/(gcos θ) = 0.67 s.
So hoop will go up the incline 1.25 m and will be on the incline for 0.67 s before arriving back at the bottom.
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A rocket in deep space is travelling at 83 m/s [Right]. The empty rocket has a mass of 4739 kg and is carrying an extra 155 kg of fuel. The rocket needs to have a final velocity at an angle of [Right 16 Up]. The engine can only eject the fuel perpendicular to the motion of the rocket (ie, straight down relative to the rocket). How fast must the 155 kg of fuel be ejected to achieve the desired course?
Answers
The fuel must be ejected at a speed of 27.9 m/s [Down] to achieve the desired course.
Let's denote the velocity of the rocket after the fuel is ejected as v_r and the velocity of the ejected fuel as v_f. The total mass of the system is M = 4739 kg + 155 kg = 4894 kg.
Before the fuel is ejected, the momentum of the system is:
p1 = M * v1 = (4739 kg + 155 kg) * 83 m/s = 408332 kg m/s [Right]
After the fuel is ejected, the momentum of the system is:
p2 = M * v2 = 4739 kg * v_r + 155 kg * v_f
The direction of the final velocity is [Right 16 Up], which means that the vertical component of the velocity is v_r * sin(16) and the horizontal component is v_r * cos(16).
Using the conservation of momentum, we have:
p1 = p2
408332 kg m/s [Right] = (4739 kg * v_r + 155 kg * v_f) * v_r * cos(16)
Solving for v_r, we get:
v_r = sqrt(408332 kg m/s [Right] / ((4739 kg * cos^2(16) + 155 kg) * cos(16)))
v_r = 88.5 m/s [Right 16 Up]
Now, we need to find the velocity of the ejected fuel v_f. Since the engine can only eject the fuel perpendicular to the motion of the rocket, the horizontal component of v_f is zero. The vertical component of v_f is equal to the vertical component of v_r:
v_f * sin(90) = v_r * sin(16)
v_f = v_r * sin(16)
v_f = 27.9 m/s [Down]
Therefore, the fuel must be ejected at a speed of 27.9 m/s [Down] to achieve the desired course.
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Your roof radiates heat away at night. At what net rate does the heat radiate from a 275 m² black roof on a night when the roof temperature is 33°C in the surrounding temperature is 14°C? The emissivity of the roof is 0.900.
Answers
We are asked to determine the net rate of radiation of a roof given its area and its emisivity. To do that we will use the following formula:
\(P_{net}=\sigma eA(T_0^4-T^4)\)Where:
\(\begin{gathered} P_{net}=\text{ net rate of radiation} \\ \sigma=\text{ Stefan-Boltzmann's constant} \\ e=\text{ emisivity} \\ A=\text{ area} \\ T_0=\text{ surrounding temperature} \\ T=\text{ temperature of the roof} \end{gathered}\)The Stefan-Boltzmann's constant is given by:
\(\sigma=5.67\times10^{-8}\frac{W}{m^2K^4}\)Now, we need to convert the temperature to Kelvin. To do that we use the following:
\(T_K=T_c+273.15\)Where:
\(\begin{gathered} T_K=\text{ temperature in Kelvin} \\ T_C=\text{ temperature in Celsius} \end{gathered}\)For the 33°C we have:
\(T_k(33)=33+273.15=306.15\)For the 14°C:
\(T_K(14)=14+273.15=287.15\)Now, we substitute the values:
\(P_{net}=(5.67\times10^{-8}\frac{W}{m^2K^4})(0.9)(275m^2)((287.15K)^4-(306.15K)^4)\)Solving the operation:
\(P_{net}=-27870.84W\)Therefore, the net rate of radiation is -27870.84 Watts.
find the line segement in the distance vs time graph that has the greatest slope. this will tell you when runner reached their maxium velocity
Answers
To locate the line segment with the highest slope in a distance vs time graph, first determine the rate of change between the two locations on the line. Because the slope depicts the runner's velocity.
the line segment with the greatest slope shows the moment at which the runner attained their maximum velocity. To compute the slope of a line segment, take the distance difference (y) and divide it by the time difference (x). The slope is therefore defined as y/x. The higher the velocity, the steeper the slope. To locate the line segment with the highest slope, calculate the slope for each line segment on the graph and select the highest one. This will provide you the time when the runner attained their top speed.
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The two processes which produce nuclear changes are _____ and _____.
fizzing
fission
nucleation
fusion
Answers
How could we change the design so the voltage remains closer to 5v when the load is connected? how would this affect the life of the battery?
Answers
Changing the design to maintain voltage closer to 5V can involve using a voltage regulator, increasing power supply capacity, and optimizing load resistance. This may impact battery life, but careful design choices can help minimize this effect.
To change the design so the voltage remains closer to 5V when the load is connected, there are a few possible approaches:
1. Use a voltage regulator: Incorporate a voltage regulator circuit in the design. A voltage regulator helps maintain a constant output voltage despite variations in the input voltage or changes in the load. This can help keep the voltage closer to 5V even with a connected load.
2. Increase the power supply capacity: If the load is drawing more current than the power supply can handle, the voltage may drop. Increasing the power supply capacity by using a higher-rated battery or power source can ensure that the voltage remains stable.
3. Optimize the load resistance: Adjusting the load resistance can help keep the voltage closer to 5V. By matching the load resistance to the source impedance, the voltage drop can be minimized.
Changing the design to maintain voltage closer to 5V when the load is connected can affect the battery life. If the load draws more current, the battery may drain faster, reducing its overall lifespan. Using a higher capacity battery or optimizing the load can help mitigate this effect. Additionally, a voltage regulator can help ensure that the battery's voltage remains stable, potentially extending its lifespan.
In summary, changing the design to maintain voltage closer to 5V can involve using a voltage regulator, increasing power supply capacity, and optimizing load resistance. This may impact battery life, but careful design choices can help minimize this effect.
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Calculate the time to fatigue and record in Lab Data Time: Force(kg): Number of Active motor Units: 0s 48 4 15s 43 3 30s 38 3 45s 30 2 60s 24 2 70s 19 1
Answers
The time to fatigue calculated from the given record in Lab data is preferably 60 seconds.
Time to fatigue is the time that is taken for muscle contraction to decrease by 50% of its maximum strength.
Force is the one that is measured by weight here. Here, as time progresses force is seen to come down.
When force is seen to come down, there is a decrease in the number of motor units that get employed as well.
Time to fatigue is the one where this force expressed as weight reaches half of the maximum.
Here, the maximum force expressed as kg is 48kg at 0 sec.
Half of 48kg is 24kg. This is the point where time to fatigue happens with a decreased number of motor units.
Here, we can see that at the 60th second , 50% decay which is 24 kg force happens with the help of only 2 motor units.
Hence, our time to fatigue here is preferably 60 seconds.
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A student wants to determine the coefficient of static friction between a long, flat wood board and a
small wood block.
(a) Describe an experiment for determining the coefficient of static friction between the wood board
and the wood block. Assume equipment usually found in a school physics laboratory is available.
i. Draw a diagram of the experimental setup of the board and block. In your diagram,
indicate each quantity that would be measured and draw or state what equipment would
be used to measure each quantity.
ii. Describe the overall procedure to be used, including any steps necessary to reduce
experimental u
Answers
The experiment involves measuring the coefficient of static friction between a wood board and a wood block using a spring balance. The procedure includes cleaning surfaces, tilting the board, and calculating the friction coefficient.
The experiment for determining the coefficient of static friction between the wood board and the wood block is given below:
Clean the surface of the wood board and the wood block.Keep the wood board flat and place the wood block on the board slowly.Start to tilt the board slowly until the block just starts to slide.Measure the angle of inclination \($\theta$\) with the horizontal.Repeat the above step and average the results to obtain more accuracy.Note the weight of the block, \($W$\), with a spring balance, the weight of the board, \($W_2$\), with the spring balance, and the force, \($F$\), required to just move the block when it is on the point of slipping.Draw a free-body diagram of the forces acting on the block.Use the free-body diagram to calculate the coefficient of static friction \($\mu$\) between the block and the board. It is given by \($\mu = \frac{F}{W}$\).Learn more about static friction: brainly.com/question/13680415
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Sodium is a metal and chlorine is a gas. Is sodium chloride (table salt) is there a gas or a metal like the elements it's made of?
A. Yes
B. No, it has completely different properties
Answers
Answer:
B. No, it has completely different properties
Explanation:
Sodium Chloride itself is not an element, but an ionic compound composed of two different elements.
An object on the end of a spring is oscillating in simple harmonic motion. If the amplitude of oscillation is doubled, how does this affect the object’s maximum speed?
Answers
Answer:
The maximum speed of the oscillating object doubles as well.
Explanation:
The oscillatory motion of the object on the spring can be modelled using this equation below:
\(Vmax= A\omega\)
Where
Vmax = the maximum speed of the oscillating object.
A = Amplitude of the oscillating object.
\(\omega\) = angular velocity of the oscillating object.
If the amplitude, A becomes doubled, the new amplitude will be = 2A.
As a result, \(Vmax = 2 A \omega\)
This shows that the maximum speed has doubled in its value
if three cars, each of mass 1350 kg , occupy the ne, se, and sw corners, determine the coordinates of the cm of the loaded ferryboat relative to the center of the raft. take east as positive x direction, and north as positive y direction. each car is 5.0 m long and 2.0 m wide with the cm at the center.
Answers
The coordinates of the CM of the loaded ferryboat are (x CM,y CM)=(0 m,0 m).
What is center of mass?The center of mass (CM) of the loaded ferryboat can be determined by finding the vector sum of the 3 cars' masses and locations.
Let's call the cars A, B and C. The mass of each car is 1350 kg. The coordinates of Car A are (xA,yA)=(-2.5 m,2.5 m), the coordinates of Car B are (xB,yB)=(2.5 m,2.5 m) and the coordinates of Car C are (xC,yC)=(2.5 m,-2.5 m).
The coordinates of the CM are given by:
xCM = (1350 kg × xA + 1350 kg × xB + 1350 kg × xC) ÷ (1350 kg + 1350 kg + 1350 kg)
yCM = (1350 kg × yA + 1350 kg × yB + 1350 kg × yC) ÷ (1350 kg + 1350 kg + 1350 kg)
If three cars, each of mass 1350 kg, occupy the ne, se, and sw corners, we need to determine the coordinates of the cm of the loaded ferryboat relative to the center of the raft, taking east as the positive x-direction and north as the positive y-direction.
Each car is 5.0 m long and 2.0 m wide with the cm at the center.
Given,
Mass of each car, m = 1350 kg
Length of each car, l = 5.0 m
Width of each car, w = 2.0 m
Center of mass of each car is at the center. The center of mass of each car will coincide with the center of each car.
The position of the center of mass of the 1st car relative to the center of the raft is (-1.5l, -w/2) = (-7.5 m, -1 m)
The position of the center of mass of the 2nd car relative to the center of the raft is (-1.5l, w/2) = (-7.5 m, 1 m)
The position of the center of mass of the 3rd car relative to the center of the raft is (1.5l, 0) = (7.5 m, 0)
Therefore, the total mass of the system is 3 × 1350 kg = 4050 kg. Let the position of the center of mass of the system be (X, Y) m relative to the center of the raft.
Now,
X = [(-7.5) × 1350 kg + (-7.5) × 1350 kg + (7.5) × 1350 kg]/4050 kg = 0 m
Y = [(-1) × 1350 kg + (1) × 1350 kg + 0]/4050 kg = 0 m
The position of the center of mass of the system relative to the center of the raft is (0 m, 0 m).Therefore, the coordinates of the cm of the loaded ferryboat relative to the center of the raft are (0 m, 0 m).
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How would a small bar magnet be oriented when placed at position X?
Answers
Based on the document attached, the small bar magnet will be oriented when placed at position X is option d:
What is the magnet position about?The orientation of the magnets is known to be one that do affect its magnetic force. Atoms atoms, such as iron, are known to often gives a stronger magnetic force when compared to other atoms.
These atoms can be seen as tiny magnets, that has the north and south of each pole. If the poles is known to be oriented in all directions, the material will not bring about a net magnetic force.
Therefore, Based on the document attached, the small bar magnet will be oriented when placed at position X is option d because the shapes of the magnetic field lines in regards to the bar magnet are said to be closed.
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A spaceship is floating through space at 500 m/s, initially has a total mass of 6000 kg. How much fuel is needed to increase the spaceship's velocity from 500 m/s to 600 m/s if the exhaust velocity of the fuel is 1.5 km/s
Answers
To calculate the amount of fuel needed, we can use the concept of conservation of momentum. The change in velocity can be achieved by expelling mass at a specific exhaust velocity.
First, let's calculate the initial momentum of the spaceship:
Initial momentum = mass * velocity
Initial momentum = 6000 kg * 500 m/s
Initial momentum = 3,000,000 kg·m/s
To achieve a final velocity of 600 m/s, the spaceship needs to increase its momentum by:
Change in momentum = mass * change in velocity
Substituting the given values:
Change in momentum = mass * (final velocity - initial velocity)
Change in momentum = 6000 kg * (600 m/s - 500 m/s)
Change in momentum = 6000 kg * 100 m/s
Change in momentum = 600,000 kg·m/s
Now, let's determine the amount of fuel needed by considering the exhaust velocity. The change in momentum is equal to the momentum gained by the expelled fuel:
Change in momentum = expelled mass * exhaust velocity
Substituting the given values:
600,000 kg·m/s = expelled mass * 1.5 km/s
To convert the exhaust velocity to m/s:
1.5 km/s = 1500 m/s
Now we can solve for the expelled mass:
expelled mass = change in momentum / exhaust velocity
expelled mass = 600,000 kg·m/s / 1500 m/s
expelled mass = 400 kg
Therefore, the spaceship would need 400 kg of fuel to increase its velocity from 500 m/s to 600 m/s with an exhaust velocity of 1.5 km/s.
1. A 0.1 mm diameter glass tube is inserted into a ethyl alcohol at 20 degree centigrade in a cup. How much does the Glycerin rise in the tube. The angle of alcohol with tube is 0 degree. D=0.1 mm=0.001 m 0∘ alcohol angel 20∘ ethyl alcohol η=1.1×10^−3 N⋅sec/ m^2sg=.0.79
Answers
A 0.1mm diameter glass tube is inserted into an ethyl alcohol at 20 degrees centigrade in a cup. The angle of alcohol with the tube is 0 degrees. D = 0.1 mm = 0.001m, alcohol angle is 0 degrees, ethyl alcohol
\(η=1.1×10^-3 N⋅sec/ m², s_g\)
=0.79.
We have to determine how much glycerin rises in the tube. The force that moves the liquid through the tube is the difference between the downward force of gravity on the liquid column and the upward capillary force produced by the surface tension of the liquid against the walls of the tube.
The height to which the fluid rises in a capillary tube may be measured by balancing the capillary force against the force of gravity on the column.
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You own a geotechnical engineering firm in central California and your company has been hired to conduct a slope stability analysis. Consider a 10.0 m-thick mass of regolith (note that this is already measured perpendicular to the slope – so pay attention where you might change the cosine term) sitting on top of a bedrock surface with a slope of 14 degrees. A home is located at the top of this slope (and set back from the edge only 20 m). Upon an initial visit, you determine that the regolith is unsaturated. You also estimate the following additional parameters for this site:
regolith cohesion = 1100 N/m2
regolith angle of internal friction = 15 degrees
density of regolith = 2200 kg/m3 (density of water = 1000 kg/m3 )
a. What is the value for the Factor of Safety? Show your work. Would you consider the slope currently stable? Explain your answer. 4 pts
b. How does the factor of safety change if the water depth increases by 2 m? Does the slope become more or less stable, and by how much? How does this compare to the example above (Part a.)? 3 pts
c. How does the factor of safety change if the angle of internal friction increases by a factor of 2 (this would be the equivalent of changing the material from loose sand to semi-consolidated sediment)? Does the slope become more stable or less stable? 3 pts
d. How does the factor of safety change if the slope is steeper by a factor of 2? Does the material become more or less likely to fail? 3 pts
e. What advice would you give to the homeowners regarding the safety of their home? What remediation can you suggest if any is needed? 3 pts
Answers
The factor of safety for the slope stability analysis needs to be determined for a regolith slope in central California. The parameters provided include regolith cohesion, angle of internal friction, and regolith density. The analysis involves evaluating the stability of the slope under different conditions, such as changes in water depth, angle of internal friction, and slope steepness. Recommendations for the homeowners regarding the safety of their homes and potential remediation measures will also be provided.
To calculate the factor of safety, we need to consider the forces acting on the slope. The driving force is the weight of the regolith, which can be calculated by multiplying the density of the regolith by the volume of the slope. The resisting force is the shear strength of the regolith, which is determined by the cohesion and angle of internal friction. The factor of safety is the ratio of the resisting force to the driving force.
a. To determine the factor of safety, we can use the given parameters and calculate the driving force and resisting force. By dividing the resisting force by the driving force, we can obtain the factor of safety. If the factor of safety is greater than 1, it indicates that the slope is stable. If it is less than 1, the slope is considered potentially unstable.
b. If the water depth increases by 2 m, it adds additional weight to the slope, increasing the driving force. This decrease in the factor of safety suggests a less stable slope compared to the initial scenario.
c. If the angle of internal friction increases by a factor of 2, it enhances the shear strength of the regolith. This increase in the factor of safety indicates a more stable slope.
d. If the slope becomes steeper by a factor of 2, it increases the driving force. This decrease in the factor of safety suggests a less stable slope.
e. Based on the analysis, it is important to advise the homeowners that the slope is currently unstable, considering the factor of safety is less than 1. Remediation measures may include slope stabilization techniques such as installing retaining walls, soil reinforcement, or drainage systems to manage water infiltration and reduce driving forces. It is recommended to consult with a geotechnical engineer to develop a comprehensive slope stability plan for the safety of the home.
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As a way of determining the inductance of a coil used in a research project, a student first connects the coil to a 5.62 V battery and measures a current of 0.698 A. The student then connects the coil to a 35.1 V(rms), 93.1 Hz generator and measures an rms current of 0.36 A. What is the inductance
Answers
Answer:
Its inductance L = 166 mH
Explanation:
Since a current, I = 0.698 A is obtained when a voltage , V = 5.62 V is applied, the resistance of the coil is gotten from V = IR
R = V/I = 5.62/0.698 = 8.052 Ω
Since we have a current of I' = 0.36 A (rms) when a voltage of V' = 35.1 V (rms) is applied, the impedance Z of the coil is gotten from
V₀' = I₀'Z where V₀ = maximum voltage = √2V' and I₀ = maximum current = √2I'
Z = V'/I' = √2 × 35.1 V/√2 × 0.36 V = 97.5 Ω
WE now find the reactance X of the coil from
Z² = X² + R²
X = √(Z² - R²)
= √(97.5² - 8.05²)
= √(9506.25 - 64.8025)
= √9441.4475
= 97.17 Ω
Now, the reactance X = 2πfL where f = frequency of generator = 93.1 Hz and L = inductance of coil.
L = X/2πf
= 97.17/2π(93.1 Hz)
= 97.17 Ω/584.965 rad/s
= 0.166 H
= 166 mH
Its inductance L = 166 mH
A recurrent nova could eventually build up to a:
Select one:
A. planetary nebula.
B. quasar.
C. Type I supernova.
D. Type II supernova.
E. hypernova.
Answers
Option C. is correct. The recurrent nova has the potential to build up its mass over time and eventually reach the critical threshold for a Type I supernova.
Recurrent novae are binary star systems where a white dwarf accretes material from a companion star. When the accreted material reaches a critical mass, a thermonuclear explosion occurs on the surface of the white dwarf, resulting in a nova outburst. Unlike classical novae, recurrent novae experience multiple eruptions over time.
As a recurrent nova continues to accrete material, the mass of the white dwarf gradually increases. If the mass surpasses the Chandrasekhar limit of about 1.4 times the mass of the Sun, a Type I supernova can occur. In a Type I supernova, the white dwarf undergoes a catastrophic explosion, completely destroying the star.
Therefore, the recurrent nova has the potential to build up its mass over time and eventually reach the critical threshold for a Type I supernova.
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llison wants to calculate the speed of a sound wave.which formula should she use?iceairwooda drill laying on its sidea nail stuck into a piece of wooda hammer hitting a metal cupa wrench locked in place around a bolt
Answers
Allison can use the formula v = fλ to calculate the speed of a sound wave, where v is the speed, f is the frequency, and λ is the wavelength.
The medium through which the sound wave is traveling, such as ice, air, or wood, will affect the speed of the wave.
The other items listed, such as a drill, nail, hammer, and wrench, are not relevant to calculating the speed of a sound wave.
To calculate the speed of a sound wave, Alison should use the formula:
speed = distance / time
The other terms mentioned (ice, air, wood, a drill laying on its side, a nail stuck into a piece of wood, a hammer hitting a metal cup, and a wrench locked in place around a bolt) are not directly related to calculating the speed of a sound wave.
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A skater of mass 45 kg is travelling in a circle of radius 4 m at a constant speed. What is their speed if the horizontal force they exert on the ground to prevent them from slipping is 1125 N
A 10 m/s
B. 20 m/s
C. 5 m/s
D. 100 m/s
E. The speed cannot be determined since we don't know
the time interval.
Answers
The skater moves at a 10 m/s speed. The right answer is A.
We must examine the forces operating on the skater in order to calculate their speed. The horizontal force applied to the ground creates the centripetal force, which is pointed in the direction of the circular path's center.
The centripetal force is calculated using the formula F = (mv2) / r, where m is the skater's mass, v is the speed, and r is the circle's radius.
We may convert the skater's horizontal force of 1125 N to the centripetal force as follows:
1125 N = (45 kg * v^2) / 4 m.
We rearrange the equation to find v:
1125 N * 4 m = 45 kg * v^2.
4500 N*m = 45 kg * v^2.
If you multiply both sides of the equation by 45 kg, you get:
100 N*m = v^2.
Taking the square root of both sides gives:
v = 10 m/s.
Therefore, the skater's speed is 10 m/s. The correct option is A.
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the magnetism of a permanent magnet results from __________.
Answers
Answer:
Explanation:
The magnetism of a permanent magnet results from the magnetic moments of electrons in the material making up the magnet interactions with Earth's magnetic field the magnetic moments of nuclei in the material making up the magnet electric currents inside the magnet.
A wire 43.7 cm long carries a 0.450 a current in the positive direction of an x axis through a magnetic field with an x component of zero, a y component of 0.000360 t, and a z component of 0.00830 t. find the (a) x, (b) y, and (c) z components of the magnetic force on the wire.
Answers
The magnetic force on a wire carrying a current through a magnetic field is given by the equation:
F = ILBsin(theta)
where F is the magnetic force, I is the current, L is the length of the wire, B is the magnetic field strength, and theta is the angle between the wire and the magnetic field.
In this case, we are given the x, y, and z components of the magnetic field, as well as the length of the wire and the current. We can use the following equations to calculate the x, y, and z components of the magnetic force:
Fx = ILBxsin(theta)
Fy = ILBysin(theta)
Fz = ILBzsin(theta)
Plugging in the values given in the problem, we get:
Fx = (0.450 A) * (43.7 cm) * (0 T) * sin(theta) = 0
Fy = (0.450 A) * (43.7 cm) * (0.000360 T) * sin(theta) = 0.01614 N
Fz = (0.450 A) * (43.7 cm) * (0.00830 T) * sin(theta) = 0.36451 N
Thus, the x component of the magnetic force on the wire is 0,
the y component is 0.01614 N, and
the z component is 0.36451 N.
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please someone help me with the questions. I asked earlier Thank you.
Answers
Answer:
Mark me as brainliest as i need it ..
I will answer your questions
Charge Q = 3.19 nC is uniformly distributed along the y-axis from y = -a to y = a, as in the figure where a = 5.65 cm. Find the electric field magnitude (in N/C) at point P if d = 17.7 cm.
Answers
When a charge Q = 3.19 nC is uniformly distributed along the y-axis from y = -a to y = a, the magnitude of the electric field at point P is 162 N/C.
Given,
The charge Q=3.19 nC is uniformly distributed along the y-axis from y= -a to y= a, where a=5.65 cm.
The distance between charge distribution and point P is d=17.7 cm.
To find: The magnitude of the electric field at point P.
Electric field is the force per unit charge, so its unit is Newtons/Coulomb.N/C.
The Electric field at a point P can be written as E= (kQ/d)
where,
k= 9 × 10⁹ Nm²/C² is Coulomb's constant
Q= Charge
d= Distance between charge distribution and point P.
So,Electric field at point P can be written as E = (kQ/d) …… (1)
Now, we have to find the magnitude of the electric field at point P. Therefore, put the values of given quantities in equation (1), then
E = (9 × 10⁹) × (3.19 × 10⁻⁹) / (0.177 m)
E = 162 N/C
Therefore, the magnitude of the electric field at point P is 162 N/C.
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According to newton's law of gravitation, what affects the force of attraction between two objects? distance between them angle between them their shape their color
Answers
The force of attraction between two objects Mass and distance.
What is newton's law of gravitation?
Every particle in the cosmos attracts every other particle with a force that is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centres, according to Newton's law of universal gravitation.
Inductive reasoning, as described by Isaac Newton, was used to deduce this general physical law from actual facts. It was created by Newton and is a component of classical mechanics. Philosophiae Naturalis Principia Mathematica, also known as "the Principia," was originally published on July 5, 1687. In April 1686, when Newton gave Book 1 of the unpublished book to the Royal Society, Robert Hooke said that Newton had learned the inverse square law from him.
According to the law, every point mass attracts every other point mass when a force applies along the line that intersects the two points, in today's parlance. The force is inversely equal to the square of the separation between the masses and directly proportional to their product.
\(F = G\frac{m_{1} m_{2}}{r^{2} }\)
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PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST The actual subject is Science but they dont have that as a option in pick a subject
Answers
Explanation:
speed : • how fast an object changes position
• miles per hour.
• distance/time.
velocity: • speed in a direction
• miles per hour North
• distance/ time in a direction
What will most likely happen if a light wave moves from the air into a solid? A) It will increase in wavelength. B) It will decrease in speed. C) It will increase in speed. D) It will decrease in frequency.
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Answer:
it will decrease speed
Explanation:
Answer:
it's b
Explanation:
An object of height 2.3 cm is placed 27 cm in front of a diverging lens of focal length 17 cm. Behind the diverging lens, and 11 cm from it, there is a converging lens of the same focal length. A 50% Part (a) Find the location of the final image, in centimeters beyond the converging lens. A 50% Part (b) What is the magnification of the final image? Include its sign to indicate its orientation with respect to the object.
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(a) The location of the final image beyond the converging lens is 12.67 cm.
(b) The magnification of the final image is -0.82, indicating that it is inverted with respect to the object.
To find the location of the final image, we can use the lens formula for thin lenses, which is given by 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.
For the diverging lens, u = -27 cm (since the object is in front of the lens), and f = -17 cm (negative for diverging lens). Using the lens formula, we find v1 = -153 cm.
For the converging lens, the object distance is -11 cm (since it is behind the diverging lens), and f = 17 cm. Using the lens formula again, we find v2 = 12.67 cm.
The magnification of the final image can be calculated using the formula magnification = v2/v1, which gives us -0.82. The negative sign indicates that the image is inverted with respect to the object.
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Elements grouped as a column on the periodic table belong to a ______.
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2.
______ is stored energy due to its position.
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Answer:
Potential energy
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The distance of east-west highway is 1.030 x 10^6m. How much is the value of mantissa in this number?
(a) 1.030
(b) 0.030
(d) 6
(c) 10
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The mantissa distance, which is referred to as the decimal portion of a logarithm, has a value of 0.030 in this number.
Is the decimal portion of a number's logarithmic value referred to as the mantissa?A common logarithm's integral portion is known as the characteristic, and its non-negative decimal portion is known as the mantissa. If log 39.2 equals 1.5933, then 1 is the characteristic and 5933 is the logarithm's mantissa.
What is the number's logarithmic mantissa?The base-10 logarithm's mantissa, which represents the digits of the provided integer but not its magnitude, is a common logarithm's fractional component. For instance, both ㏒10201.3010 and ㏒102002.3010 have a mantissa of 0.3010.
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what effect does an unbalanced force have on an object?
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Answer:
An unbalanced force can change an object's motion. An unbalanced force acting on a still object could make the object start moving. An unbalanced force acting on a moving object could make the object change direction, change speed, or stop moving.