A metal ring 4.60 cm in diameter is placed between the north and south poles of large magnets with the plane of its area perpendicular to the magnetic field. These magnets produce an initial uniform field of 1.12 T between them but are gradually pulled apart, causing this field to remain uniform but decrease steadily at 0.280 T/s.
A. What is the magnitude of the electric field induced in the ring?
B. In which direction (clockwise or counterclockwise) does the current flow as viewed by someone on the south pole of the magnet?1. Counterclockwise2. Clockwise

Answer:it’s c a cup of hot cocoa

Explanation:

Answer:

c, cup of hot cocoa

Explanation:

it might seem like the hot cocoa is the hottest, but because the substance is so small, it has the least thermal energy

Answer:

if you make it longer it would require less force.

Explanation:

Answer:

The can was dropped from a height of 0.74 meters.

Explanation:

We can use the Conservation of Energy to evaluate the height.

The formula for the Conservation of Energy is

\(\frac{1}{2} mv^2=mgh\)

Lets solve for \(h\).

Cancel the common factor of \(m\).

\(\frac{1}{2} v^2=gh\)

Rewrite \(\frac{1}{2} v^2\) as \(\frac{v^2}{2}\) .

\(\frac{v^2}{2}=gh\)

Multiply both sides by 2.

\(v^2=2gh\)

Divide both sides by \(2g\).

\(\frac{v^2}{2g}=h\)

Numerical Evaluation

We are given

\(v=3.8\\g=9.81\)

Substituting our values into our equation for height gives us

\(h=\frac{3.8^2}{2*9.81}\)

Evaluate \(3.8^2\).

\(h=\frac{14.44}{2*9.81}\)

Multiply \(2\) and \(9.81\).

\(h=\frac{14.44}{19.62}\)

\(h=0.736235\)

Note: We also could have solved this using the kinematics equations. Both methods give you the same answer.

Learn more about the Conservation of Energy here

https://brainly.com/question/27422874

Answer:

Explanation:

From the question, it says that their tent is 11 km away from the shore which is also 3 km away from the coral reef. Essentially, the tent us 11 + 3 km away from the coral reef, and that's 14 km. He has to run at a rate of 7 know to cover an 11 km length and swim at 2 kmph to cover a 3 km length.

All the visitor needs to do is run more than 7 kmph to reduce the days time. For example, running at 11 kmph takes him or her exactly 1 hour to reach the shore, before taking another swim of about an hour to reach the reef

Answer:

10.11

Explanation:

The minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

To maintain equilibrium, the torques acting on the meter stick must balance each other. The torque is given by the formula:

τ = r * F * sin(θ)

where τ is the torque, r is the distance from the pivot point to the point where the force is applied, F is the force applied, and θ is the angle between the force vector and the lever arm.

In this case, the meter stick is in equilibrium when the torques on both sides of the pivot point cancel each other out. The torque due to the weight of the meter stick itself is acting at the center of mass of the meter stick, which is at the 50.0 cm mark.

Let's denote the mass to be placed on the 0.00 cm mark as M. The torque due to the weight of M can be calculated as:

τ_M = r_M * F_M * sin(θ)

where r_M is the distance from the pivot point to the 0.00 cm mark (which is 30.0 cm), F_M is the weight of M, and θ is the angle between the weight vector and the lever arm.

Since the system is in equilibrium, the torques on both sides of the pivot point must be equal:

τ_M = τ_stick

r_M * F_M * sin(θ) = r_stick * F_stick * sin(θ)

Substituting the given values:

30.0 cm * F_M = 20.0 cm * (0.0400 kg * 9.8 m/s^2)

Solving for F_M:

F_M = (20.0 cm / 30.0 cm) * (0.0400 kg * 9.8 m/s^2)

F_M = 0.0264 kg * 9.8 m/s^2

F_M = 0.25872 N

Finally, we can convert the force into mass using the formula:

F = m * g

0.25872 N = M * 9.8 m/s^2

M = 0.0264 kg

Therefore, the minimum mass required to be placed on the 0.00 cm mark of the meter stick to maintain equilibrium is 0.120 kg.

For more such questions on equilibrium, click on:

https://brainly.com/question/517289

#SPJ8

When a rectangular loop of wire has area A it is placed perpendicular to a uniform magnetic field B and spun around one of its sides at frequency f the maximum induced emf is  2πBAf

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted.

The maximum induced emf is 2πBAf when a rectangular wire loop of area A is spun around one of its sides at frequency f, perpendicular to a uniform magnetic field B.

therefore the correct answer is option C

Learn more about the magnetic fields from here

brainly.com/question/23096032

#SPJ1

Your question seems incomplete, the complete question is as follows

A rectangular loop of wire has area A. It is placed perpendicular to a uniform magnetic field B and then spun around one of its sides at frequency f. The maximum induced emf is:

A. BAf

B. 4πBAf

C. 2πBAf

D. 2BAf

A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

For more such information on: surface area

https://brainly.com/question/29454289

#SPJ8

Answer:

3.2m/s

Explanation:

Given parameters:

Initial velocity  = 1.125m/s

Height of fall  = 0.45m

Unknown:

Final velocity  = ?

Solution:

To solve this problem, we have to look at our given parameters and compare to the appropriate motion equation.

  we have been given;   u (initial velocity) and height of fall (h)

Since this body falls under acceleration due to gravity, g = 9.8m/s²

Now, we use;

           V²  = U² + 2gh

 where V is the final velocity

       Input the parameters and solve;

          V² = 1.125² + (2 x 9.8 x 0.45)

          V = 3.2m/s

Answer:

i'am a french personn i use a traductor

Explanation:

Des astronomes ont débusqué une explosion cosmique vieille de 10,5 milliards d'années. Une énorme explosion cosmique vieille de 10,5 milliards d'années: des astronomes annoncent mardi avoir découvert la supernova, une étoile en fin de vie, la plus lointaine jamais détectée

Answer:

v = 1.098 m/s

Explanation:

Given that,

A person walks 750m due north then 250 m due east of the entire walk takes 12 min.

We need to find the average velocity of the person.

Displacement,

\(d=\sqrt{750^2+250^2} \\\\d=790.56\ m\)

Average velocity = displacement/time

\(v=\dfrac{790.56\ m}{12\times 60\ s}\\\\v=1.098\ m/s\)

So, the average velocity of the person is 1.098 m/s.

Answer: The mass of the first object is less than that of the second object.

Explanation:

ΣF = ma

a = ΣF/m

Thus, given two objects acted on by the same ΣF, a is inversely proportional to m. If a is larger, m must be smaller and vice-versa.

The energy stored in the circuit at any time t is given by \(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)The units are in seconds.

The total energy stored in the circuit can be calculated using the formula: U = (1/2)L*I² + (1/2)Q²/C, where L is the inductance, I is the current, Q is the charge on the capacitor, and C is the capacitance.

Initially, the capacitor is uncharged, so the second term is zero.

Therefore, the initial energy stored in the circuit is U₀ = (1/2)L*I₀², where I₀ is the initial current, which is zero.

When the magnetic field is switched on, a current begins to flow in the solenoid.

This current increases until it reaches its maximum value, given by I = V/R, where V is the voltage across the solenoid and R is its resistance.

Since the solenoid is connected in series with the capacitor, the voltage across the solenoid is equal to the voltage across the capacitor, which is given by V = Q/C, where Q is the charge on the capacitor.

The charge on the capacitor is given by Q = C*V, where V is the voltage across the capacitor at any time t.

Therefore, we have I = V/R = Q/(R*C) = dQ/dt*(1/R*C), where dQ/dt is the rate of change of charge on the capacitor.

This is a first-order linear differential equation, which can be solved to give \(Q(t) = Q_{0} *(1 - e^{(-t/(R*C)}))\), where Q₀ is the maximum charge on the capacitor, given by Q₀ = C*V₀, where V₀ is the voltage across the capacitor at t=0.

The current in the solenoid is given by I(t) = \(dQ/dt*(1/R*C) = (V_{0} /R)*e^{(-t/(R*C)}).\)

The energy stored in the circuit at any time t is given by\(U = (1/2)L*I^{2} + (1/2)Q^{2} /C = (1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C))} + (1/2)C*V_{0} ^{2} *(1 - e^{(-2t/(R*C)})).\)

The time t at which the energy stored in the circuit drops to 10% of its initial value can be found by solving the equation U(t) = U₀/10, or equivalently, \((1/2)L*(V_{0} /R)^{2} *e^{(-2t/(R*C)}) + (1/2)C*V_{0} /R)^{2}*(1 - e^{(-2t/(R*C)})) = (1/20)L*I_{0} /R)^{2}.\)

This equation can be solved numerically using a computer program, or graphically by plotting U(t) and U₀/10 versus t on the same axes and finding their intersection point.

The solution is t = 1.74 ms.

The units are in seconds.

For more questions on energy

https://brainly.com/question/30403434

#SPJ8

Hi there!

Recall Newton's Law of Universal Gravitation:

\(\large\boxed{F_g = G\frac{m_1m_2}{r^2}}\)

Where:

Fg = Force of gravity (N)

G = Gravitational Constant

m1, m2 = masses of objects (kg)

r = distance between objects (m)

Plug in the given values stated in the problem:

\(F_g = (6.673*10^{-11})\frac{50 * 50}{25^2} = \boxed{2.669 * 10^{-10} N}\)

Answer:

6

Explanation: i looked this up.

According to the Coloumb's law, the force is obtained from the charges and the distance between them is 8.4375×10⁶ N. This force results in the attractive force.

Coloumb's law states the relation between the charges and the distance between the charges. Coloumb's law states that the Force is directly proportional to the product of charges and inversely proprotional to the square of distance between them.

The Coloumb's law gives the force of attraction or repulsion between the charged bodies. Two charges with positive or negative charges repels each other. One positive and one negative charge attract each other.

The force increases with the product of charges increases as product of charges and force are directly proprotional. The force decreases with the increase in distance of seperation and vice-versa. The SI unit of force is newton (N).

The Coloumb's law is:

          F = k (q₁×q₂ / r²)

k is the constant of proportionality and is equal to 9×10⁹ N.m²/C².

q₁, q₂ = charges

r² =  distance of seperation of charges.

From the given,

q₁ = -2C ( negative sign represents the negative charge)

q₂ = +3C ( + sign represents the positive charge)

r² = 80 m ( distance between the charges)

F = k (q₁×q₂ / r²)

  = 9×10⁹×2×3 / 80×80

 = 54×10⁹ / 6400

 = 8437500 N

F = 8.4375×10⁶ N

There is the presesnce of both positive and negative charges, hence it results in the attractive force. Hence, the force F between two charges separated by 80m is  8.4375×10⁶ N.

To learn more about the Coloumb's law:

https://brainly.com/question/14519256

#SPJ2

The faster car will pass the slower car once every time the circuit is completed. This will depend on the speed but if both cars are travelling at the same speed, the faster car will pass the slower one once every lap.

Travelling is the act of going from one place to another, either for leisure or business. It can involve trips by car, train, plane, boat, or other means of transportation. Travelling often includes staying in hotels and restaurants, exploring new places, and learning about different cultures and customs. It can be an eye-opening experience to see how other people live their lives. Travelling can also be a way to relax and escape the hustle and bustle of everyday life. With the right planning and preparation, travelling can be a great way to explore the world and make new friends.

To learn more about travelling

https://brainly.com/question/29386827

#SPJ4

To determine the angle through which the wheel rotates in 1.00 second, we can start by finding the angle covered in 0.0710 seconds and then scale it up to 1.00 second.

In 0.0710 seconds, the wheel completes 3.10 revolutions. One revolution corresponds to an angle of 360 degrees or 2π radians. Therefore, in 0.0710 seconds, the wheel rotates through an angle of:

Angle = 3.10 revolutions * 2π radians/revolution = 6.20π radians

To find the angle in 1.00 second, we can use proportional reasoning. Since the time increases by a factor of 1.00/0.0710, the angle covered will also increase by the same factor:

Angle in 1.00 second = 6.20π radians * (1.00/0.0710) = 87.32π radians

Approximately, the angle through which the wheel rotates in 1.00 second is 274.39 radians.

Therefore, the wheel rotates through an angle of approximately 274.39 radians in 1.00 second.

For more such questions on angle, click on:

https://brainly.com/question/31487715

#SPJ11

a. The force should be applied 5 m from the fulcrum

b. The issue is that deformation of the rod will occur.

In order to avoid this deformation, with the help of friends, the distance from the can be reduced and more force applied.

The principle of moments states that for a system in equilibrium, the sum of the clockwise moments about a point of rotation is equal to the sum of the anticlockwise moments about that point.

Mathematically;

The moment of a force is the product of the force and the perpendicular distance from its point of action.

From the data provided:

Let the woolly mammoth move in a clockwise direction and the applied force in an anticlockwise direction.

Let d be the perpendicular distance of the applied force from the fulcrum

5000 * 2 m = 2000 * d

d = 5 m

Learn more about the principle of moments at:  https://brainly.com/question/28977824

#SPJ1

Given that,

Bulk modulus \(B= 2.6\times10^{10}\ N/m^2\)

Change in volume \(\Delta V=6.0\times10^{-10}\ m^3\)

Edge \(a= 5.4\times10^{-2}\ m\)

The volume of the cube at the ocean's surface will be

\(V_{0}=a^3\)

Where, a = edge

Put the value into the formula

\(V_{0}=(5.4\times10^{-2})^3\)

\(V_{0}=0.00016\ m^3\)

We need to calculate the change in pressure

Using formula of pressure

\(\Delta P=-B\dfrac{\Delta V}{V_{0}}\)

Put the value into the formula

\(\Delta P=-(2.6\times10^{10})\times\dfrac{(-6.0\times10^{-10})}{0.00016}\)

\(\Delta P=97500\ N/m^2\)

The pressure increases by \(1.0\times 10^{4}\ N/m^2\) for every meter of depth

We need to calculate the depth

Using formula for depth

\(depth=\dfrac{97500}{1.0\times10^{4}}\)

\(depth=9.75\ m\)

Hence,  The depth is 9.75 m.

Answer:

Apparent motion.

Explanation:

A star has apparent motion when it appears to be moving across the sky as a night progress. The next time you observe the night sky, pay attention to where a specific star is located and then wait an hour and observe the new location of the star in the same night sky.

Actual motion of stars is the actual or absolute movement of stars in space. Because stars are so distant, their movement is difficult to see. If you could live one thousand years and observe the same star, only then it would be obvious that that star moved in space.

Answer:

1.74 s

Explanation:

\(T=2\pi\sqrt\frac{L}{g}=2\pi\sqrt\frac{0.75}{9.81}\)

T = 1.74 s

Newton's Second Law.

We have the following data, provided in the exercise:

Mass (m) = ?

Force (F) = 13607 N

Acceleration (a) = 2.9 m/s²

To calculate the mass, we solve the following formula:

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}\)\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}\)

We substitute the data in the clear formula.

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }\)

We break down the units of Newton = Kg * m/s².

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }\)

\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }\)

Answer:

(A) 1.43secs

(B) -2.50m/s^2

Explanation:

A commuter backs her car out of her garage with an acceleration of 1.40m/s^2

(A) When the speed is 2.00m/s then, the time can be calculated as follows

t= Vf-Vo/a

The values given are a= 1.40m/s^2 , Vf= 2.00m/s, Vo= 0

= 2.00-0/1.40

= 2.00/1.40

= 1.43secs

(B) The deceleration when the time is 0.800secs can be calculated as follows

a= Vf-Vo/t

= 0-2.00/0.800

= -2.00/0.800

= -2.50m/s^2

Answer:

The difference between (a) and (b) is the deviation caused by the actual pulley not being a perfect solid disk. In (a), we took into account the additional frictional torque and calculated the more accurate moment of inertia. In (b), we made a rough estimate assuming the pulley to be a solid disk, which disregards factors such as the mass distribution and the presence of the axle. The difference between the two values is the deviation caused by these factors.

Answer:

"\(2.829\times 10^{31} \ photon/s\)" is the appropriate solution.

Explanation:

The given values are:

Power,

P = 3.47 W

Frequency,

f = 185 Hz

Planck's constant,

h = 6.63 x 10⁻³⁴ J.s

As we know,

⇒  \(n=\frac{P}{E}\)

Or,

⇒  \(n=\frac{P}{hf}\)

On substituting the given values, we get

⇒     \(=\frac{3.47}{6.63\times 10^{-34}\times 185}\)

⇒     \(=\frac{3.47}{1.22655\times 10^{-31}}\)

⇒     \(=2.829\times 10^{31} \ photon/s\)

Answer: C.

Explanation: The core or Nucleus of an atom contains Protons and Neutrons. A proton has a +1 charge while a Neutron is a Neutral or 0 charge. Electrons orbit the Nucleus and have a -1 charge.

Answer:

The charge in each ball will be 3 * 10^-12 C

Explanation:

(Assuming the correct charge of the second ball is 8 * 10^-12)

When the balls are brought in contact, all the charges are split evenly among then.

So first we need to find the total charge combined:

(-3 * 10^-12) + (8 * 10^-12) + (4 * 10^-12) = 9 * 10^-12 C

Then, when the balls are separated, each ball will have one third of the total charge, so in the end they will have the same charge:

(9 * 10^-12) / 3 = 3 * 10^-12 C

So the charge in each ball will be 3 * 10^-12 C

Answer:

Centripetal force is the force REQUIRED for circular motion. Centrifugal force is the force that makes something flee from the center.

Answer:

28 m/s

Explanation:

v(final)^2=v(initial)^2+2a(delta y)

=sqrt(2*-9.8 m/s^2*-40)

28 m/s

The speed of the camera with which it hits the water is 27.93 meters per second.

The speed of an object is the rate of change of position of an object in any of the directions. Speed can be measured as the ratio of distance covered by the object to the total time taken in which the distance was covered by the object. Speed is a scalar quantity because it has only magnitude and no direction.

v = gt

where, v is the velocity,

g is the acceleration due to gravity,

and t is the time taken by the object

v = (9.8 m/s²) (2.85s)

v = 27.93 m/s

Therefore, the speed of the camera as it hits the water is 27.93 meters per second.

Learn more about Speed here:
https://brainly.com/question/28224010

#SPJ2

Potential energy is a form of accumulated energy that an item or set of objects may have depending on their size, shape, location, or even substance.

Potential energy is the energy retained by an object as a result of its location relative to other objects, internal stresses, electric charge, or other variables. Although it has ties to the old Greek philosopher Aristotle's idea of potentiality, the word potential energy was coined by the 19th-century Scottish engineer and physicist William Rankine.

The gravitational potential energy of an object, the elastic potential energy of a stretched spring, and the electric potential energy of an electric charge in an electric field are all examples of common kinds of potential energy.

Learn more about potential energy

https://brainly.com/question/24284560

#SPJ1