A NASA spacecraft measures the rate of at which atmospheric pressure on Mars decreases with altitude. The result at a certain altitude is: 1 R=0.0429 kPa km^-1 Convert R to kJ m^-4 _____ kJ m^-4

Answer: pluto

Explanation:

pluto is the smallest

Answer:

46

Explanation:

Brainlest pls :3

Answer:

46

Explanation:

In humans, each cell normally contains 23 pairs of chromosomes, for a total of 46.

Brainlist Pls!

The water level on the sides of the lake when the cannon is hanging from the boat will be option A, exactly the same as when the cannon was inside the boat.

When the cannon is inside the boat, it displaces a certain volume of water equal to its own volume, based on Archimedes' principle. This displacement creates a rise in the water level inside the boat.

When the cannon is thrown out of the boat but still attached by the chain, the overall displacement of water remains the same because the chain is still connected to the boat. The weight of the cannon is counterbalanced by the tension in the chain, preventing it from sinking to the bottom of the pond.

Since the overall displacement of water remains the same, the water level on the sides of the lake will remain unchanged. The weight of the cannon is still supported by the buoyant force of the water, just as it was inside the boat.

Therefore, the water level on the sides of the lake will be exactly the same when the cannon is hanging from the boat as it was when the cannon was inside the boat. The presence of the chain connecting the cannon to the boat does not affect the equilibrium established by the buoyant force.

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Various examples of applied and normal forces and friction are mentioned.

The normal force is the force that prevents two objects from passing through each other, while the applied force is the force that is exerted on an object by an external agent.

Friction is a force that opposes the relative motion between two surfaces in contact. It arises due to the microscopic irregularities on the surface of the objects that interlock with each other when they are in contact.

Pushing a shopping cart in a grocery store.

Throwing a ball towards a wall.

Using a broom to sweep the floor.

The force exerted by the floor on our feet when we stand still.

The force exerted by a chair on our body when we sit on it.

The force exerted by a book on a table when we keep it on it.

The force that causes a pencil to stop moving on a rough surface.

The force that helps our shoes grip the ground when we walk.

The force that prevents a car from slipping on a wet road while applying brakes.

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The base of table is "1.08856 m" far away from the ball land.

Given:

Distance travelled by ball,

Initial velocity,

Acceleration,

Constant speed,

As we know the formula,

→ \(S = ut+\frac{1}{2}at^2\)

By substituting the values, we get

→ \(1.2=\frac{1}{2}\times 9.8t^2\)

→ \(1.2 = 4.9 t^2\)

→    \(t = \sqrt{\frac{1.2}{4.9} }\)

→      \(= 0.4948 \ seconds\)

Let,

→ \(x = 2.2\times t\)

     \(= 2.2\times 0.4948\)

     \(= 1.08856 \ m\)

Thus the solution above is right.

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The time taken during uniform motion is 0.45 seconds and the velocity is 2√5 m/s.

We need to know about uniform motion to solve this problem. Uniform motion is an object's motion under acceleration. It should follow the rule

v' = v₀ + a . t

v'² = v₀² + 2a . s

s = v₀ . t + 1/2 . a . t²

where v' is final velocity, v₀ is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, the given parameters are

s = 1.0 m

a = g = 10 m/s²

v₀ = 0 m/s

Find the final velocity right before hitting the floor

v'² = v₀² + 2a . s

v'² = 0² + 2 . 10 . 1

v'² = 20

v' = 2√5 m/s

Find the time taken

v' = v₀ + a . t

2√5 = 0 + 10 . t

10t = 2√5

t = √5/5

t = 0.45 seconds

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Answer:

I mean they have the same amount of velocity

By using this formula =Diameter = Diameter = Known Field Diameter × (Known Magnification / Unknown Magnification)
, you can calculate the diameter of an unknown microscope field, allowing you to estimate the size of the objects you're observing under different magnification levels.

.To calculate the diameter of an unknown microscope field, you can use the formula:

Unknown Field Diameter = Known Field Diameter × (Known Magnification / Unknown Magnification)

Here's a step-by-step explanation of the formula:

1. Determine the known field diameter: This is the diameter of the field of view under a certain magnification, which is usually provided by the microscope manufacturer or can be measured experimentally.

2. Determine the known magnification: This is the magnification level at which the known field diameter was measured.

3. Determine the unknown magnification: This is the magnification level at which you want to calculate the unknown field diameter.

4. Plug the values into the formula and solve for the unknown field diameter.

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The percent loss of mechanical energy per cycle in this damped oscillator is approximately 70%.

To calculate the percent loss of mechanical energy per cycle in the given scenario, we first need to find the number of cycles that occur in one minute.

One cycle of a damped oscillator takes two periods, so in one minute (60 seconds), there are 60/30 = 2 cycles.

Now we can calculate the percent loss of mechanical energy per cycle:

- The percent reduction in amplitude after 1 minute is 30%, which means the amplitude has decreased to 70% of its original value.
- The mechanical energy of a simple harmonic oscillator is proportional to the square of its amplitude. Therefore, the mechanical energy of the damped oscillator after 1 minute is only (0.7)^2 = 0.49, or 49% of its original value.
- Since we have two cycles in one minute, the percent loss of mechanical energy per cycle is the square root of 0.49, which is approximately 0.7 or 70%.

Therefore, the percent loss of mechanical energy per cycle in this damped oscillator is approximately 70%.

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Answer:

The gravitational potential energy of an item is determined by its weight and height above the ground, whereas elastic potential energy is determined by the form of the object. When an elastic item is stretched or compressed, this occurs.

Reflection is the process of thinking about something and analyzing it in relation to one's own experiences and perspectives.

In the context of the law of acceleration, this means considering how this law affects our everyday lives and the decisions we make.

One way that the law of acceleration relates to my life is through my use of technology. The law of acceleration states that an object's acceleration is directly proportional to the net force acting on it and inversely proportional to its mass.

This means that as technology becomes more advanced and lighter in weight, it also becomes faster and more efficient. This directly affects my daily life, as I rely on technology for communication, entertainment, and work.

Another way that the law of acceleration relates to my life is through my experiences with transportation. Whether I am driving a car, riding a bike, or taking public transit, the law of acceleration is at play. Understanding how acceleration works allows me to make informed decisions about how to safely and efficiently get from one place to another.

Overall, the law of acceleration is a fundamental principle that affects many aspects of our daily lives. By reflecting on how it relates to my own life, I can better understand the world around me and make more informed decisions.

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Things which will be attracted to (or repelled by) a magnet are

An iron pipe

A negatively charged piece of silver

An aluminum wire carrying current

According to the "rule of attraction of magnets," magnets will attract one another when their south poles are brought near together. According to the "rule of magnet repulsion," magnets repel one another when their respective north poles are brought close to one another.

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Answer:

the answer should be: An Electromagnet, An Iron Pipe, and An Aluminum Wire Carrying Current

Explanation:

took the test

If a circuit with a battery, a 2 Ω resistor, a 16 Ω resistor, and a 24 Ω resistor in series. The total current is the system is 3.3 A. The voltage drop across the 2 Ω resistor is 6.6V.

1. Voltage drop across the 2 Ω resistor

Voltage drop across the 2 Ω resistor = current through the circuit × resistance of the resistor

Voltage drop across the 2 Ω resistor = 3.3 A * 2 Ω

Voltage drop across the 2 Ω resistor = 6.6 V

2. Voltage of the battery

Let V be the voltage of the battery

V = I * (R1 + R2 + R3)

= 1.9 A * (2 Ω + 13 Ω + 27 Ω) = V

Solving for V, we find that V = 79.1 V

3. Resistance of the unknown resistor

Let R be the resistance of the unknown resistor

0.2 A * R = 100 V - 37 Ω * 0.2 A - 37 Ω * 0.2 A

Solving for R

R = 5 Ω

4. Voltage of the battery

Let V be the voltage of the battery

V = 0.6 A * 10 Ω + 0.6 A * 10 Ω

= 12 V

5. Current through the 8 Ω resistor

Current through the 8 Ω resistor = 2.8 V / 8 Ω

Current through the 8 Ω resistor = 0.35 A

6. The total resistance of a parallel circuit

1/total resistance = 1/9 Ω + 1/15 Ω + 1/27 Ω

Solving for total resistance

Total resistance = 3.33 Ω

7. Current through the battery

Current through the battery = 7.0 V / 3 Ω + 7.0 V / 12 Ω + 7.0 V / 27 Ω.

Solving for the current

Current through the battery = 2.3 A

Therefore the voltage drop across the 2 Ω resistor is 6.6V.

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0.77 m/s2 directed 35° south of west

net force = (-17,-12)

net force = mass * acceleration

(-17,-12) = 27 * (x-acceleration,y-acceleration)

(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)

angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.

magnitude of acceleration = sqrt((-0.629629...)^2 + (-0.444...)^2) = 0.77069 (5dp)

Answer:

1. Privacy

-The state or condition of being free from being observed or disturbed by other people.

2. Commitment

-The state or quality of being dedicated to a cause, activity, etc.

3. Profile

-There are multiple answers for this word so I'm not sure which is the one you need.

4. Widow

-A woman who has lost her spouse by death and has not remarried.

5. Aristocrat

-A member of the aristocracy.

6. Affordable

-Inexpensive; reasonably priced.

7. Variable

-A symbol for a value we don't know yet. It is usually a letter like x or y.

Explanation:

Answer: 10 deibles

Explanation:

it increases by 10 each level

mark brainliest

Answer:

How is high-speed internet typically transmitted around the world? over telephone wires b. through fiber optic cables c. beamed wirelessly to homes d via satellites​

Explanation:

Answer:

Refraction is the correct option

Answer: refraction

Explanation: it is the bending of light rays as it moves from one medium to another.

The  mass of the large truck is determined as 5680 kg.

The mass of the truck is calculated as follows;

P = mv

where;

m = P/v

m = 125000/22

m = 5680 kg

Thus, the  mass of the large truck is determined as 5680 kg.

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Answer:

C. 5680

Explanation:

edg2023

Answer:

Let's define t = 0 as the moment when the ball hits the wall.

in this moment, we have a given acceleration, but if we only want to calculate the average acceleration, then let's consider the acceleration constant.

a(t) = A.

To find the velocity equation we should integrate, and the constant of integration will be the initial velocity, in this case, is 14.3m/s.

v(t) = A*t + 14.3m/s

Now we know that at t = 0.011s, the velocity is -13.5m/s (the sign is negative because the ball is moving in the opposite direction as before).

Then we can solve the equation:

v(0.011s) = -13.5m/s = A*0.011s + 14.3m/s

Now we can solve it for A, the average acceleration:

-13.5m/s - 14.3m/s = A*0.011s

(-27.8m/s)/0.011s = A = -1313.5 m/s^2

Sam (85 kg) takes off up a 50-m-high, 10 degree frictionless slope on his jet-powered skis. The skis have a thrust of 220 N. He keeps his skis tilted at 10 degree after becoming airborne. Sam lands about 109.9 meters from the base of the cliff.

To solve this problem, we can use the conservation of energy principle. At the bottom of the slope, all of Sam's energy is in the form of potential energy:

Potential energy = mgh

where m is Sam's mass (85 kg), g is the acceleration due to gravity \((9.81 m/s^2)\), and h is the height of the slope (50 m).

Potential energy = \((85 kg) \times (9.81 m/s^2) \times (50 m) = 41,287.5 J\)

As Sam takes off up the slope, his potential energy is converted to kinetic energy and then to a combination of kinetic and potential energy as he becomes airborne. We can use the conservation of energy to find Sam's speed at the top of the slope:

Potential energy at bottom = Kinetic energy at top

\(mgh = (1/2)mv^2\)

where v is Sam's speed at the top of the slope.

\(v = \sqrt{(2gh)} = \sqrt{(2 \times 9.81 m/s^2 \times 50 m)} = 31.3 m/s\)

Now, we can use Sam's speed and the angle of his skis to find his horizontal velocity:

Horizontal velocity = v cos(theta)

where theta is the angle of the skis after becoming airborne (10 degrees).

Horizontal velocity = 31.3 m/s x cos(10 degrees) = 30.2 m/s

Finally, we can use the horizontal velocity and Sam's hang time to find the distance he travels:

Distance = Horizontal velocity x Hang time

where hang time is the time Sam spends in the air. Hang time can be found using the formula:

Hang time = (2v sin(theta)) / g

Hang time = (2 x 31.3 m/s x sin(10 degrees)) / 9.81 \(m/s^2\) = 3.64 s

Distance = 30.2 m/s x 3.64 s = 109.9 m

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A light beam has a frequency of 330 MHz in a material of refractive index 1.70. In a material of refractive index 3.00,the frequency is 330MHz

The frequency of a light beam in a material with a refractive index of 3.00, given that it has a frequency of 330 MHz in a material with a refractive index of 1.70, we need to understand that the frequency of light remains constant when it passes from one medium to another.
The frequency of the light beam will remain the same, 330 MHz, in the material with a refractive index of 3.00. This is because the frequency of light does not change when it passes through materials with different refractive indices.

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The resulting velocity of the 500-g cart is 0 m/s. The resulting velocity of the 1000-g cart is 1 m/s.

Asteroids, often known as minor planets, are stony, airless leftovers of our solar system's early development about 4.6 billion years ago.

The majority of this ancient space junk may be found in the main asteroid belt, orbiting the Sun between Mars and Jupiter. Asteroids range in size from Vesta, the largest at 329 miles (530 kilometers) in diameter, to asteroids as small as 33 feet (10 meters). The cumulative mass of all asteroids is less than that of the Earth's Moon.

Answer:

________________

560 kilometers

I think this is correct.

________________

Answer:

The answer of the question is = 560.052

Kilometer.

From the calculated momenta, we can see that Car 1 and Car 2 have the same magnitude of momentum, which is 11 kg·m/s.

To determine which cars have the same magnitude of momentum, we need to calculate the momentum for each car. The momentum (p) is given by the product of the mass (m) and velocity (v):

p = m * v

Using the provided data, let's calculate the momentum for each car:

Car 1: Momentum = 5 kg * 2.2 m/s = 11 kg·m/s

Car 2: Momentum = 5.5 kg * 2 m/s = 11 kg·m/s

Car 3: Momentum = 6 kg * 1.35 m/s = 8.1 kg·m/s

Car 4: Momentum = 2006.5 kg * 1.90 m/s = 3812.35 kg·m/s

Car 5: Momentum = 7 kg * 1.35 m/s = 9.45 kg·m/s

From the calculated momenta, we can see that Car 1 and Car 2 have the same magnitude of momentum, which is 11 kg·m/s.

Therefore, the correct answer is:

Car 1

Car 2

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The work done by the man pushing the car over the given distance is 1000J.

Given the data in the question;

Work done; \(W = \ ?\)

Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;

\(Work\ done = f * d\)

Where f is force applied and d is distance travelled.

To determine the work done by the man, we first solve for the force applied F.

From Newton's Second Law; \(Force \ F = m * a\)

We substitute our given values into the expression

\(F = m * a \\\\F = 200kg * 0.5m/s^2\\\\F = 100kg.m/s^2\)

Next we substitute our values into the expression of work done above.

\(Work \ done = f * d\\\\Work \ done = 100kg.m/s^2 * 10m\\\\Work \ done = 1000kgm^2/s^2\\\\Work \ done = 1000J\)

Therefore, the work done by the man pushing the car over the given distance is 1000J.

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A black hole forms as a star collapses when it ceases emitting radiation from fusion reactions. This occurs after the star has consumed hydrogen, helium, then through iron.

Star evolution refers to the process by which stars evolve (change) over time.

A black hole can be defined as a collapsed star where the gravitational field in its nucleus becomes greater than particles cannot escape from it.

In consequence, black holes are cosmic bodies in which gravity is so powerful that nothing (i.e., particles, radiation, light, etc.) can escape from them.

Nuclear fusion refers to the energy reactions produced by the fusion of hydrogen at the core of a star, thereby becoming helium.

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Answer:

Explanation:

A) E) When the light hits a square on the CCD charge is produced

B) A) Starting in one corner the charge on each square is moved off the CCD

C) D) The charges on each square are converted into a digital signal

D) B) Light enters the camera

E) C) That signal can be stored or sent to a computer or other device

b. The delay between taking one photograph with a digital camera and taking the next photograph is due to the time it takes to capture the image and process it into a digital signal. This process includes the capturing of the light entering the camera, the conversion of the charges on each square of the CCD into a digital signal, and the storage or sending of the signal to a computer or other device.

Answer:

it is the impact of a meteorite, volcanic activity, or an explosion.