A rectangle has a length 3 times the width. What is the perimeter in terms of x?
Answers
Answer:
Perimeter is equal to all four sides added together.
Length = 3W; L=3W
So
P = 2(W) + 2(L) substitute the equation for length above you get
P = 2(W) + 2(3W) and combine
P = 2W + 6W = 8W; put in what the perimeter is and solve for W
66 = 8W, so W = 8.25
W = 8.25, L = 24.75
Related Questions
Find y' if y= In (x2 +6)^3/2
y'=
Answers
Answer:
\(\displaystyle y' = \frac{3xln(x^2 + 6)^{\frac{1}{2}}}{x^2 + 6}\)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FactoringCalculus
Derivatives
Derivative Notation
Derivative of a constant is 0
Basic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Property [Multiplied Constant]: \(\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)\)
Derivative Rule [Chain Rule]: \(\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)\)
ln Derivative: \(\displaystyle \frac{d}{dx} [lnu] = \frac{u'}{u}\)
Step-by-step explanation:
Step 1: Define
\(\displaystyle y = ln(x^2 + 6)^{\frac{3}{2}}\)
Step 2: Differentiate
[Derivative] Chain Rule: \(\displaystyle y' = \frac{d}{dx}[ln(x^2 + 6)^{\frac{3}{2}}] \cdot \frac{d}{dx}[ln(x^2 + 6)] \cdot \frac{d}{dx}[x^2 + 6]\)[Derivative] Chain Rule [Basic Power Rule]: \(\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{3}{2} - 1} \cdot \frac{d}{dx}[ln(x^2 + 6)] \cdot \frac{d}{dx}[x^2 + 6]\)[Derivative] Simplify: \(\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{d}{dx}[ln(x^2 + 6)] \cdot \frac{d}{dx}[x^2 + 6]\)[Derivative] ln Derivative: \(\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{1}{x^2 + 6} \cdot \frac{d}{dx}[x^2 + 6]\)[Derivative] Basic Power Rule: \(\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{1}{x^2 + 6} \cdot (2 \cdot x^{2 - 1} + 0)\)[Derivative] Simplify: \(\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{1}{x^2 + 6} \cdot (2x)\)[Derivative] Multiply: \(\displaystyle y' = \frac{3ln(x^2 + 6)^{\frac{1}{2}}}{2} \cdot \frac{1}{x^2 + 6} \cdot (2x)\)[Derivative] Multiply: \(\displaystyle y' = \frac{3ln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)} \cdot (2x)\)[Derivative] Multiply: \(\displaystyle y' = \frac{3(2x)ln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)}\)[Derivative] Multiply: \(\displaystyle y' = \frac{6xln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)}\)[Derivative] Factor: \(\displaystyle y' = \frac{2(3x)ln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)}\)[Derivative] Simplify: \(\displaystyle y' = \frac{3xln(x^2 + 6)^{\frac{1}{2}}}{x^2 + 6}\)Topic: AP Calculus AB/BC (Calculus I/II)
Unit: Derivatives
Book: College Calculus 10e
write an equation for the line below
Answers
Answer:
y = -X + 4 is the equation for the line below
Your investment club has only two stocks in its portfolio. $25,000 is invested in a stock with a beta of 0.8, and $40,000 is invested in a stock with a beta of 1.7. What is the portfolio's beta? Do not round intermediate calculations. Round your answer to two decimal places.
Answers
Answer:
The portfolio beta is \(\alpha = 1.354\)
Step-by-step explanation:
From the question we are told that
The first investment is \(i_1 = \$ 25,000\)
The first beta is \(k = 0.8\)
The second investment is \(i_2 = \$ 40,000\)
The second beta is \(w = 1.7\)
Generally the portfolio beta is mathematically represented as
\(\alpha = \frac{ i_1 * k + i_2 * w }{ i_1 + i_2}\)
substituting values
\(\alpha = \frac{ (25000 * 0.8) + ( 40000* 1.7 ) }{40000 + 25000}\)
\(\alpha = 1.354\)
I GIVE BRAINLIEST FOR ANSWER AND EXPLANATION
Answers
i see no shaded region here
Assume that the amounts of weight that male college students gain during their freshman year are normally distributed with a mean of μ = 1.1 kg and a standard deviation of o= 4.6 kg.
Complete parts (a) through (c) below.
b. If 25 male college students are randomly selected, find the probability that their mean weight gain during freshman year is between 0 kg and 3 kg.
The probability is
(Round to four decimal places as needed.)
Answers
The probability that their mean weight gain during freshman year is between 0 kg and 3 kg is 70%
What is Probability?It is a branch of mathematics that deals with the occurrence of a random event.
Given,
Amounts of weight that male college students gain during their freshman year are normally distributed
mean of μ = 1.1 kg and
Standard deviation of o= 4.6 kg.
Z score=x-μ/o
=25-1.1/4.6
=23.9/4.6
=5.196
Z score=x-μ/o
=25-1.1/0
=0
Z score=25-1.1/3
=23.9/3
=7.966
By observing the z table the probability that their mean weight gain during freshman year is between 0 kg and 3 kg is 70%
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A redwood tree casts a shadow that is 8 meters long. A carpool lane sign near the redwood
tree casts a shadow that is 4 meters long. If the redwood tree is 6 meters tall, how tall is the
carpool lane sign?
Answers
Answer:
Hey bro, solving this would be relatively simple. If the Redwood tree is 6 meters tall, then the height of the carpool lane sign can be easily calculated using similar triangles. Using the lengths of their respective shadows, the carpool lane sign should be 3 meters tall, because the ratio between the height of the Redwood tree and the carpool lane sign, is the same ratio as between their respective shadows (8 to 4). The based way to solve this problem would be to measure the length of the shadows, and then use the ratio to calculate the height of the carpool lane sign.
Answer:
You need to set up the problem to solve for X. X = how tall is the tree? Set up your problem in this fashion. Set up the formula then arrange to solve for X. X/9 (shadow of the tree) = 15 (how tall the building is)/6 (shadow of building) X= 15/6 * 9 To get X alone, you need to move 9 to the other side of the equation. multiply by 9 on each side. For X side, this nullifies 9 and gets 9 to the other side. X= 2.5*9 You have divided 15 by 6, now multiply by 9 to get final answer for X X=22.5 meters The tree is 22.5 meters tall.
Step-by-step explanation:
If this is not.. right ill do another answer!!
e
B
0
14. The table shows the number of inches of
rain over five months. What would be an
appropriate display of the data? Explain.
(Lesson 2)
Month
Number
of Inches
of Rain
Jan. Feb. Mar.
1.5
2.2
3.6
Apr.
5.3
May
4.8
Answers
The graph of the given function is attached.
Given is a function for the rainfall in 5 months in inches.
We need to display the data,
So, as we can see that the data is not showing any proportion or pattern,
So, it can be displayed as a line chart.
Hence the chart is attached for the function.
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For the following vectors, (a) find the dot product v•w ; (b) find the angle between v and w , (c) state whether the vectors are parallel, octagonal, or neither. V=-3i-4j, w=6i+8j
A- v•w
B-the angle between v and w is theta ^•?
C- the vectors v and w are?
Answers
B) The angle between vectors v and w can be found using the formula: cos(theta) = (v • w) / (||v|| ||w||), where ||v|| and ||w|| are the magnitudes of vectors v and w respectively.
First, we need to find ||v|| and ||w||:
||v|| = sqrt((-3)^2 + (-4)^2) = 5
||w|| = sqrt((6)^2 + (8)^2) = 10
Now, we can substitute in the values to get:
cos(theta) = (-50) / (5 * 10) = -1
theta = arccos(-1) = pi radians or 180 degrees.
Therefore, the angle between vectors v and w is 180 degrees.
C) Two vectors are parallel if their directions are the same, which can be determined by comparing their unit vectors.
The unit vector of v is:
v_hat = v / ||v|| = (-3/5)i + (-4/5)j
The unit vector of w is:
w_hat = w / ||w|| = (6/10)i + (8/10)j = (3/5)i + (4/5)j
We can see that the unit vectors are in opposite directions, which means that the vectors are anti-parallel or opposite. Therefore, the vectors v and w are neither parallel nor orthogonal.
Solve for the value of q
Answers
Answer:
\(q=45\)
Step-by-step explanation:
Notice that \((q+2)^{\circ}\) and \((3q-2)^{\circ}\) form a linear pair, that is, they sum to \(180^{\circ}\) as follows:
\((q+2)^{\circ}+(3q-2)^{\circ}=180^{\circ}\\(q+2+3q-2)^{\circ}=180^{\circ}\\(4q)^{\circ}=180^{\circ}\\4q=180\\q=\frac{180}{4}\\q=45\)
16 families went on a trip which cost them Rs 2,16,352. How much did each
family pay?
Answers
Given that 16 families went on a trip and the cost of the trip was Rs. 2,16,352.The amount paid by each family is to be determined by unitary method Hence each family paid Rs.13522
Now, let's solve this by using the method of unitary method. To find the cost of 1 family trip, we will divide the total cost of the trip by the number of families.2,16,352 / 16 = 13,522 So, the cost of the trip per family is Rs. 13,522.Hence, each family paid Rs. 13,522 for the trip.
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Answer:
Step-by-step explanation
1. The total cost of the trip for all 16 families is Rs 2,16,352.
2. To find out how much each family paid, we need to divide the total cost by the number of families: Rs 2,16,352 ÷ 16.
3. When we do the division, we get the result: Rs 13,522.
Now let's check if this result is correct:
1. If each family paid Rs 13,522 for the trip, then the total cost for all 16 families would be: 16 × Rs 13,522 = Rs 2,16,352.
2. This is exactly the same as the total cost given in the problem statement.
So we have shown that each family paid **Rs 13,522** for the trip
a closed rectangular tank measures 12 meters by 6 meters by 10 metersfind the surface area of the shape
Answers
Answer:
Just Took The Test
C!!
Step-by-step explanation:
Trust
Please help. Thank you.
Answers
Answer:
-10m-9
Step-by-step explanation:
-3(4m+3)+2m
combine like terms
-12m-9+2m
-10m-9
PLEASE HELP AS SOON AS POSSIBLE
Answers
Answer:
B
Step-by-step explanation:
Yes, because for each input there is exactly one output. You can have two of the same x values but you cannot have 2 of the same y values. if you have two of the same y values, it is not a function as it doesn't pass the vertical line test.
if y is directly porportional to x^2 and the difference in the values of y when x=1 and x=3 is 32, find the value of y when x=-2
Answers
Answer:
Step-by-step explanation:
y=kx²
y₁=k(1)²=k
y₃=k(3)²=9k
y₁-y₃=k-9k=32
-8k=32
k=-4
y=-4x²
y₋₂=-4(-2)²=-16
Which ordered pair is a solution to the system of linear equations? x + 4y = 3 y = −4x − 3 (1, 1) (1, −1) (−1, 1) (−1, −1)
Answers
Answer:
(-1,1)
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
equation form:
x=-1, y=1
have a great day and thx for your inquiry :)
By substituting each of the provided options into the given system of linear equations, it is revealed that the ordered pair (-1, 1) is a valid solution for both the equations.
The correct answer is (-1, 1)
In mathematics, a system of linear equations consists of multiple linear equations with the same variables. These equations describe various relationships among these variables, typically representing lines in a multi-dimensional space. Solving such systems involves finding values for the variables that satisfy all equations simultaneously. Methods like substitution, elimination, or matrix algebra can be used to solve these systems. These systems are fundamental in fields like physics, engineering, economics, and computer science for modeling and solving real-world problems involving multiple interconnected variables.
We can solve this problem by substituting values from the given options into the equations and checking for which option both equations are valid. The system of linear equations is: x + 4y = 3 and y = -4x - 3.
Option (1, 1): For x = 1 and y = 1, our system becomes 1 + 4*1 = 5 and y = -4*1 - 3 = -7. Both do not hold true.Option (1, -1): For x = 1 and y = -1, our system becomes 1 + 4*-1 = -3 and y = -4*1 - 3 = -7. Both do not hold true.Option (-1, 1): For x = -1 and y = 1, our system becomes -1 + 4*1 = 3 (correct) and y = -4*-1 - 3 = 1 (correct). Thus, option (-1, 1) is a solution to the system of equations.Option (-1, -1): For x = -1 and y = -1, our system becomes -1 + 4*-1 = -5 and y = -4*-1 - 3 = 1. Both do not hold true.Therefore, the ordered pair that is a solution to the system of linear equations is (-1, 1).
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A school is arranging a field trip to the zoo. The school spends 778.88 dollars on passes for 28 students and 4 teachers. The school also spends 241.64 dollars on lunch for just the students. How much money was spent on a pass and lunch for each student?
Answers
The total money spent on a pass and lunch for each student is $850.14.
What is arithmetic?In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication, and division.
here,
As mentioned in the question, Passes for 28 pupils and 4 teachers cost the school $778.88 and the school also spends $241.64 on lunch for kids only.
Total number of person = 28 + 4
= 32
Cost per pass = 778.88 / 32
= $24.34
Total passes of students = 25 × 24.34 = 608.5
Total spend on lunch of student = 241.64
Total spend on lunch = 241.64 + 608.5 = $850.14
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Is 5 a irrational number
Answers
Answer:
no.
Step-by-step explanation:
No. Because, 5 is an integer, that's why it's not irrational.
A triangle has ∠1 and ∠2 as remote interior angles with respect to exterior angle ∠3. Given that m∠1 = 50 and m∠2 = 70, Alicia reasoned that m∠3 must be 60. Is Alicia correct? If not, explain Alicia's error.
Answers
Answer:
No, 60 is the third interior angle's mesure, not the exterior ∠3.
Step-by-step explanation:
Say that ∠1=∠A=50 and ∠2=∠B=70. The remote interior angles are the angles that are not touvhing the exterior angle. So ∠3 would be the the exterior angle to ∠C. ∠C=60 as the sum of the interior angles is 180.
The exterior angle is the angle formed by extending one of the triangle's sides. A straight line has the angle 180, so∠3=180-∠C=180-60=120.
A dairy needs 258 gallons of milk containing 7% butterfat how many gallons each of milk containing 8% butterfat and milk containing 2% butterfat must be used to obtain the desired 258 gallons
Answers
Let's assume x gallons of milk containing 8% butterfat and y gallons of milk containing 2% butterfat are used.
The total amount of milk is x + y gallons, and we want it to be equal to 258 gallons.
To determine the amount of butterfat in the mixture, we can multiply the volume of each type of milk by its respective butterfat percentage and sum them up.
For milk containing 8% butterfat, the amount of butterfat is 0.08x (8% is equivalent to 0.08 as a decimal).
For milk containing 2% butterfat, the amount of butterfat is 0.02y (2% is equivalent to 0.02 as a decimal).
Since we want the final mixture to contain 7% butterfat, we can set up the following equation:
0.08x + 0.02y = 0.07(258)
Simplifying the equation, we have:
0.08x + 0.02y = 18.06
To solve for x and y, we need another equation. Since the total amount of milk is x + y = 258, we can rearrange it to y = 258 - x.
Substituting this value into the equation above, we get:
0.08x + 0.02(258 - x) = 18.06
Solving this equation will give us the values of x and y, which represent the gallons of milk containing 8% butterfat and 2% butterfat, respectively, needed to obtain the desired 258 gallons.
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Jason has 75 feet of wallpaper border. He wants to put a wallpaper border around his rectangular bedroom that measures 12 fee by 14 feet. he multiplies 12×14= 168 to get an exact answer of how much border he needs. He concludes that he does not have enough water for the whole job. Full picture below
Answers
Let's summarize the facts:
the tape is 75 feet long
the bedroom is 12 feet by 14 feet.
1. Tell how you can critique Jason’s reasoning.
If you want to Critique Jason's reasoning, you could a) ask yourself the same questions that Jason did and see if you would come with the same answers and used the same analysis or b) analyse Jason's answer to see if he did a mistake or missed an important detail and made a thought mistake
2. Critique Jason’s reasoning
I will use the option b from above:
?
Jason first multiplied 12 x 14 = 168. This multiplication is correct, but what did he get? He needed to get the perimeter of the bedroom because it was only the wallpaper border, not the wallpaper itself - so getting the perimeter was needed, but this we get by the formula (2* *(length width), not length* width - as Jason did.
So, Jason made a mistake here! his actual answer should be 2*(12+14) =2*26=52, so the tape of 75 feet would have been enough!
3. Jason uses an overestimate to decide how many rolls of wallpaper he needs for another’s room. Explain why his reasoning to use an overestimate does or does not make sense
Using an overestimate is often a good idea- in case some of the tape gets damaged, he will have some left. However, since his calculations are wrong by a lot (he multiplies rather than adds and multiplies by 2), his overestimate will be a lot higher than would be practical - he would be left with a lot of leftovers and spend too much money. So his reasoning does not make sense
WITPLE CHOICE QUESTION
Where is the decimal point ALWAYS
located?
Where is the decimal point ALWAYS located?
Answers
Answer:
It's always located right in between the tenths place and the ones place.
000.000
Each of these extreme value problems has a solution with both a maximum value and a minimum value. Use Lagrange multipliers to find the extreme values of the function subject to the given constraint.
(a) f (x, y) = x^2 - y^2; x^2 + y^2 = 1
Max of 1 at (plusminus 1, 0), min of - 1 at (0, plusminus l)
(b) f (x, y) = 3x + y; x^2 + y^2 = 10
Max of 10 at (3, 1), min of - 10 at (- 3, - 1)
(c) f (x, y) = xy; 4x^2 + y^2 = 8
Max of 2 at plusminus (1, 2), min of - 2 at plusminus (l, - 2)
Answers
Answer:
a) f(x,y) = - 1 minimum at P ( 0 ; -1 )
b) f (x,y) = 10 maximum at P ( 3 , 1 ) and f (x,y) = - 10 minimum at Q ( - 3 , - 1 )
c) Max f ( x , y ) = 2 for points P ( 1, 2 ) and T ( -1 , -2 )
Min f ( x , y ) = -2 for points Q ( 1 , - 2 ) and R ( -1 , 2 )
Step-by-step explanation:
A) f(x,y) = x² - y² subject to x² + y² = 1 g(x,y) = x² + y²- 1
δf(x,y)/ δx = 2*x δg(x,y)/ δx = 2*x
δf(x,y)/ δy = - 2*y δg(x,y)/ δy = 2*y
δf(x,y)/ δx = λ* δg(x,y)/ δx
2*x = λ*2*x
δf(x,y)/ δy = λ* δg(x,y)/ δy
- 2*y = λ*2*y
Then, solving
2*x = λ*2*x x = λ*x λ = 1
- 2*y = λ*2*y y = - 1
x² + y²- 1 = 0 x² + ( -1)² - 1 = 0 x = 0
Point P ( 0 ; -1 ) ; then at that point
f(x,y) = x² - y² f(x,y) = 0 - ( -1)² f(x,y) = - 1 minimum
b) f( x, y ) = 3*x + y g ( x , y ) = x² + y² = 10
δf(x,y)/ δx = 3 δg(x,y)/ δx = 2*x
δf(x,y)/ δy = 1 δg(x,y)/ δy = 2*y
δf(x,y)/ δx = λ * δg(x,y)/ δx ⇒ 3 = 2* λ *x (1)
δf(x,y)/ δy = λ * δg(x,y)/ δy ⇒ 1 = 2*λ * y (2)
x² + y² - 10 = 0 (3)
Solving that system
From ec (1) λ = 3/2*x From ec (2) λ = 1/2*y
Then (3/2*x ) = 1/2*y 3*y = x
x² + y² = 10 ⇒ 9y² + y² = 10 10*y² = 10
y² = 1 y ± 1 and
y = 1 x = 3 P ( 3 , 1 ) y = - 1 x = -3 Q ( - 3 , - 1 )
Value of f( x , y ) at P f (x,y) = 3*x + y f (x,y) = 3*(3) +1
f (x,y) = 10 maximum at P ( 3 , 1 )
Value of f( x , y ) at Q f (x,y) = 3*x + y f (x,y) = 3*(- 3) + ( - 1 )
f (x,y) = - 10 minimum at Q ( - 3 , - 1 )
c) f( x, y ) = xy g ( x , y ) = 4*x² + y² - 8
δf(x,y)/ δx = y δg(x,y)/ δx = 8*x
δf(x,y)/ δy = x δg(x,y)/ δy = 2*y
δf(x,y)/ δx = λ * δg(x,y)/ δx ⇒ y = λ *8*x (1)
δf(x,y)/ δy = λ * δg(x,y)/ δy ⇒ x = λ *2*y (2)
4*x² + y² - 8 = 0 (3)
Solving the system
From ec (1) λ = y/8*x and From ec (2) λ = x/2*y Then y/8*x = x/2*y
2*y² = 8*x² y² = 4*x²
Plugging that value in ec (3)
4*x² + 4*x² - 8 = 0
8*x² = 8 x² = 1 x ± 1 And y² = 4*x²
Then:
for x = 1 y² = 4 y = ± 2
for x = -1 y² = 4 y = ± 2
Then we get P ( 1 ; 2 ) Q ( 1 ; - 2)
R ( - 1 ; 2 ) T ( -1 ; -2)
Plugging that values in f( x , y ) = xy
P ( 1 ; 2 ) f( x , y ) = 2 R ( - 1 ; 2 ) f( x , y ) = - 2
Q ( 1 ; - 2) f( x , y ) = -2 T ( -1 ; -2 ) f( x , y ) = 2
Max f ( x , y ) = 2 for points P and T
Min f ( x , y ) = -2 for points Q and R
PLEASE ANSWER FAST
If n
A
-3, which expression has the least value?
n²no
n8n-5
nn
-nnn-4
B
Answers
Which relation is also a function PLEASE HELP BRAINLIEST!!!!!!!!!!!!!!!!!!! PLEASE
Answers
Answer:
Step-by-step explanation:
What was it
$150/1 sq ft x 20 sq ft
Answers
Answer:
$3000
Step-by-step explanation:
$150 / 1 sq ft * 20 sq ft
$150 / 1 sq ft = this means $150 per square feet :
Given that there area 20 Square feets, then
Cost in $ will be :
$150 * 20 sq feet
= $3000
Can somebody help me think it’s b but I’m not sure can ya help me ? Be 100%
Answers
Answer:
The answer is option 1 :)
Step-by-step explanation:
the length of a rectangle is 5 meters longer than the width. if the area is 23 square meters, find the rectangles dimensions. round to the nearest tenth of a meter
Answers
Answer:
The rectangle is 7.9 meters by 2.9 meters.
Step-by-step explanation:
Let l be the length and w be the width
l = w + 5
A = 23 m²
Formula: A = lw
Solve for the dimensions
23 = (w+5)w
23 = w² + 5w
w² + 5w - 23 = 0
Use quadratic formula to find the possible value/s of w
\(w = \frac{-b+-\sqrt{b^2-4ac} }{2a}\\ w = \frac{-5+-\sqrt{5^2-4(1)(-23)} }{2(1)} \\w = \frac{-5+-\sqrt{25+92} }{2}\\ w = \frac{-5+-\sqrt{117} }{2} \\w = \frac{-5+-\sqrt{9(13)} }{2} \\w = \frac{-5+-3\sqrt{13} }{2}\\ w = \frac{-5+3\sqrt{13} }{2} = 2.9\\ w = \frac{-5-3\sqrt{13} }{2} = -7.9\)
Since we're dealing with dimensions, take the positive value which is 2.9.
w = 2.9 m
Substitute the value to l = w + 5
l = 2.9 + 5
l = 7.9 m
A manufacturer produces two models of toy airplanes. It takes the manufacturer 20 minutes to assemble model A and 10 minutes to package it. It takes the manufacturer 25 minutes to assemble model B and 5 minutes to package it. In a given week, the total available time for assembling is 3000 minutes, and the total available time for packaging is 1200 minutes. Model A earns a profit of $10 for each unit sold and model B earns a profit of $8 for each unit sold. Assuming the manufacturer is able to sell as many models as it makes, how many units of each model should be produced to maximize the profit for the given week?
Answers
Answer:
\(\$1320\)
Step-by-step explanation:
Let \(x\) be the number of units of A
\(y\) be the number of units of B
For assembling we have
\(20x+25y\leq 3000\)
For packaging we have
\(10x+5y\leq 1200\)
Let profits earned be \(Z\) so
\(Z=10x+8y\)
We have the maximize the function.
Plotting the equations we can see that the intersection points are \((0,120),(100,40),(120,0)\)
In the question it is mentioned we have to sell both the products so \(x\) or \(y\) cannot be \(0\).
So, the point of maximiztion for the function would be \((100,40)\)
The maximum profit would be
\(Z=10\times 100+8\times 40\\\Rightarrow Z=1320\)
Number of
Accidents
Number of
People
6
1
3
1
Answers
Answer:
there would be 11 accidents of people
Step-by-step explanation:
6+3+1+1= 11
or
6+3+2= 11
or
6+5 =11
help me ples 20 point
Answers
Answer:
40%
Step-by-step explanation:
6/15 * 100 = 0.4 * 100 = 40%
Answer:
40% of the pieces of fruit in the Bowl are apples.
Step-by-step explanation:
Given the statement:- There are 15 pieces of fruit in a bowl and six of them are apples.
Total number of pieces of fruit in a bowl = 15 pieces
Number of pieces of apple in a bowl = 6 pieces.
Therefore, 40% of the pieces of fruit in the Bowl are apples.