A refrigerator has a 1000 W compressor, but the compressor runs only 20% of the time. If electricity costs 0.13 dollars/kWh, what is the monthly (30 day) cost of running the refrigerator? Express your answer using two significant figures.

Answer:

C. seismographs

Explanation:

Theirs another name for seismographs but c is correct

The expression for the electric potential energy of a particle of charge q in a uniform electric field is given by the following formula: U = q Ed where U is the electric potential energy, q is the charge of the particle, E is the strength of the electric field, and d is the distance between the particle and the reference point in the field.

The electric potential energy of a particle in an electric field is the energy that the particle has due to its position in the field. The amount of energy depends on the strength of the field, the charge of the particle, and the distance between the particle and the reference point in the field.

The electric potential energy can be used to calculate the work done by an electric field on a charged particle. When a charged particle is moved in an electric field, the field does work on the particle, and this work is equal to the change in the electric potential energy of the particle. Thus, the electric potential energy is an important concept in understanding the behavior of charged particles in electric fields.

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If the normal force of the bow on the string is 0. 75 N ,The string be pulled before it slips if the string static friction is bowed at its center is 0.60mm.

The normal force exerted by the bow on the string is the force perpendicular to the surface of contact between them. In this case, the normal force is given as 0.75 N. The string can be pulled before it slips when the applied force reaches the maximum static friction force between the string and the bow.

The maximum static friction force is determined by the coefficient of static friction (μs) between the string and the bow, multiplied by the normal force. The coefficient of static friction represents the interaction between the two surfaces and their tendency to resist relative motion. The maximum normal force force can be calculated using the equation Fmax = μs * N, where Fmax is the maximum static friction force, μs is the coefficient of static friction, and N is the normal force.

Fmax=0.8×0.75

Fmax=0.60mm

The distance to which the string can be pulled before it slips depends on the relationship between the applied force and the maximum static friction force. Once the applied force exceeds the maximum static friction force, the string will start to slip. The specific distance at which this occurs would require additional information about the coefficient of static friction and the applied force.

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c. The tissue has a negative charge, and the balloon has a positive charge.

Due to the opposing charges of both things, the tissue paper repels the balloon. In this instance, it is likely that the balloon has a positive charge whereas the tissue paper has a negative charge. While like charges repel one another, opposite charges attract.

The fact that the balloon is repelled by the tissue paper leads us to conclude that both items have opposing charges. The tissue paper has a negative charge, but the balloon is most likely to have a positive charge.

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Answer:

7 meters away

Explanation:

12 x 1.5 = 18

25 - 18 = 7

Therefore, the period of the system is 2.513 s and the amplitude of the motion is 1.591 m.

1. In order to calculate how much you will weigh at Big Bear lake, we need to take into account the effect of gravity. The force of gravity depends on the mass of the two objects involved and the distance between them. The mass of the Earth is much larger than our own mass, so we can assume that it does not change significantly. However, the distance between us and the center of the Earth does change as we move higher up.

Using the formula for the force of gravity (F = G * m1 * m2 / r^2), where G is the gravitational constant (6.6743 × 10^-11 N*m^2/kg^2), m1 is the mass of the Earth, m2 is our own mass, and r is the distance between us and the center of the Earth, we can calculate the force of gravity acting on us at each location.
At the beach near San Diego, the force of gravity acting on us is F1 = G * m1 * m2 / r1^2 = (6.6743 × 10^-11) * (5.97 × 10^24) * (58) / (6,371,000)^2 = 570.09 N.
At Big Bear lake, the force of gravity acting on us is F2 = G * m1 * m2 / r2^2 = (6.6743 × 10^-11) * (5.97 × 10^24) * (58) / (6,373,000)^2 = 567.60 N.
Therefore, our weight at Big Bear lake is approximately 567.60 N, which is slightly less than our weight at the beach near San Diego.
2. The period of an oscillating spring-mass system is given by the formula T = 2π * √(m/k), where T is the period, m is the mass of the object attached to the spring, and k is the spring constant.
In this case, m = 0.20 kg and k = 0.50 N/m, so we can calculate the period as T = 2π * √(0.20/0.50) = 2.513 s.
The amplitude of the motion is the maximum displacement from the equilibrium position. We can find this value by using the formula Umax = A * ω, where Umax is the maximum speed achieved by the mass, A is the amplitude of the motion, and ω is the angular frequency (which is equal to 2π/T).
Rearranging this formula, we get A = Umax / ω = Umax / (2π/T) = Umax * T / (2π) = 2.0 * 2.513 / (2π) = 1.591 m.
Therefore, the period of the system is 2.513 s and the amplitude of the motion is 1.591 m.

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a. Units of Fo & λFor the given question,A block of mass m is initially at rest at the origin x = 0. A one-dimension force given by F = Fo ex, where Fo & λ are positive constants, is applied to the block.a. What are the units of Fo & λ?The unit of force F = Fo ex is N (newton). Here, x is a dimensionless quantity since it is a unit vector with no magnitude. Hence, the dimension of Fo is N.λ is the wavelength which is the distance between two similar points of a wave. It is measured in meters (m). Therefore, the dimension of λ is m.

b. Argue that the force is conservative The work done by the force is conservative if it is equal to the negative of the potential energy. To verify if the force is conservative, we must check if the cross-partial derivatives are equal. Hence,∂F/∂x = Fo∂/∂x (ex) = 0∂F/∂y = Fo∂/∂y (ex) = 0∂F/∂z = Fo∂/∂z (ex) = 0Since the cross-partial derivatives are zero, the force is a conservative force.

c. Find the potential energy associated with the forceThe potential energy is the negative of the work done by the force. Therefore, the potential energy is given byU = -W(x2, x1) = - ∫(x1, x2) F · drWe know, F = Fo exTherefore, U = - Fo ex · xThus, the potential energy isU = - Fo x.d. Find the velocity of the block as a function of position xWe know that the work done by the force is equal to the change in kinetic energy. Therefore,W(x2, x1) = K(x2) - K(x1)Since the block starts at rest, the initial kinetic energy is zero. Hence,K(x1) = 0Therefore,W(x2, x1) = K(x2)Solving for velocity,v(x) = [2/m ∫(0,x) F dx]^(1/2)We know that F = Fo exTherefore,v(x) = [2/m ∫(0,x) Fo ex dx]^(1/2)v(x) = [2Fo/m ∫(0,x) ex dx]^(1/2)v(x) = [2Fo/m (ex)|0x]^(1/2)v(x) = [2Fo/m (e^(x) - 1)]^(1/2)

e. Find the terminal speed of the block as x → ∞As x approaches infinity, the velocity approaches a maximum value, known as the terminal velocity. Therefore,vt = lim (x → ∞) v(x)We know that,v(x) = [2Fo/m (e^(x) - 1)]^(1/2)Taking the limit,vt = lim (x → ∞) [2Fo/m (e^(x) - 1)]^(1/2)vt = lim (x → ∞) [2Fo/m (e^(2x) - 2e^x + 1)]^(1/2)vt = lim (x → ∞) [(2Fo/m) (e^(2x))]^(1/2)vt = lim (x → ∞) [(2Fo/m) (e^x)]Therefore, the terminal speed of the block as x approaches infinity isvt = [(2Fo/m) ∞]^(1/2) = ∞Therefore, the block does not have a terminal speed.

Potential energy is energy that affects objects because of the position of the object, which tends to go to infinity with the direction of the force generated from the potential energy. The SI unit for measuring work and energy is the Joule. What are the uses of potential energy? Potential energy is energy that is widely used to generate electricity. Even so, there are two objects that are used to store potential energy. These objects, namely water and fuel, are used to store potential energy. In general, water can store potential energy like a waterfall.

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Answer:

Normal force

Explanation:

Calculating :-

We know

\(\boxed{\sf F_c=\dfrac{mv^2}{r}}\)

\(\\ \sf\longmapsto F_c=\dfrac{20(10)^2}{4}\)

\(\\ \sf\longmapsto F_c=\dfrac{20(100)}{4}\)

\(\\ \sf\longmapsto F_c=\dfrac{2000}{4}\)

\(\\ \sf\longmapsto F_c=500N\)

The final speed of the UFO after experiencing a constant acceleration for 63 seconds is 351.3 m/s.

Acceleration is the rate at which an object increases its speed, velocity or rate of change. It is the rate of change of velocity over time, or the rate of change of the position of an object. Acceleration can be either positive, when the speed of an object is increasing, or negative, when the speed of an object is decreasing.

The final speed of the UFO can be determined by using the equation, v = u + at, where u is the initial velocity, a is the acceleration, and t is the time. So, in this case, v = 64 + (21,892.5/63) = 351.3 m/s. Therefore, the final speed of the UFO after experiencing a constant acceleration for 63 seconds is 351.3 m/s.

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(a) To find the magnification, we first need to determine the image distance (q). We can use the lens formula:
1/f = 1/p + 1/q

where f is the focal length (0.140 m), p is the object distance (0.240 m), and q is the image distance. Rearranging the formula to solve for q:
1/q = 1/f - 1/p
1/q = 1/0.140 - 1/0.240
1/q = 0.00714
q = 1/0.00714 ≈ 0.280 m
Now, we can find the magnification (M) using the formula:
M = -q/p
M = -0.280/0.240
M = -1.17
The magnification is -1.17.
(b) To find the image height (h'), we can use the magnification formula:
h' = M × h
where h is the object height (0.064 m). Plugging in the values:
h' = -1.17 × 0.064
h' ≈ -0.075 m
The image height is approximately -0.075 meters. The negative sign indicates that the image is inverted.

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Answer:

the net force is 10 and it is pushing to the right

Explanation:

The net force is the total and sonce the 20N is overpowering the 10N it will have 10N which will put the 20N ahead

Answer:

Speed of the satellite V = 6.991 × 10³ m/s

Explanation:

Given:

Force F = 3,000N

Mass of  satellite m = 500 kg

Mass of earth M = 5.97 × 10²⁴

Gravitational force G = 6.67 × 10⁻¹¹

Find:

Speed of the satellite.

Computation:

Radius r = √[GMm / F]

Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)

Radius r = 8.146 × 10⁶ m

Speed of the satellite V = √rF / m

Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500

Speed of the satellite V = 6.991 × 10³ m/s

Answer:4.96\(cm^{3}\)

Explanation: Density is \(\frac{Mass}{Volume}\)

so you are now looking for volume.

Volume= Density x Mass so

Volume = (5.78g) x(1.15g/ \(cm^{3} \frac{x}{y}\)) =4.96\(cm^{3}\)

Since energy cannot be destroyed nor created but it can only be transformed from one form to another, the three possibilities energy transformations will be:

Conservation of energy state that energy cannot be destroyed nor created but it can only be transformed from one form to another.

When a fast moving roller coaster finishes its ride, before this, the roller coaster will be experiencing maximum kinetic energy. when it is trying to come to rest, the maximum energy = kinetic energy + potential energy and when it finally comes to a stop, the maximum energy will be equal to potential energy.

Therefore, the three possibilities energy transformations will be Kinetic energy, kinetic energy + potential energy and potential energy.

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Answer:

gas

Explanation:

Solids are compact together, liquida arent compact but are still close, and gases are free roaming and may be very far apart from eachother.

Answer:

The Answer is Gas.

Explanation:

Answer:

Work = Force × distance

= m × g × d

= 12 × 9.8 × 0.5

= 58.8 N

If in the case , you need any help pleasee leg me know! [ you'll have to pay btw]

The environment was quite different. Based on the sediment in the rock sample (photograph X), it is likely that this area was once covered by a shallow sea or ocean. The presence of fine-grained sediment, such as silt and clay, suggests that the water was relatively calm and quiet.

About 290 million years ago, during the Paleozoic era, Kansas was covered by a shallow sea known as the Permian Sea. The sedimentary rocks found in Kansas, including limestone, sandstone, and shale, were deposited in this sea over millions of years.

The environment in which sediment is deposited can provide clues about the conditions of the area at the time. Based on the type of rock you mentioned, it is likely that the sediment was deposited in a marine environment, such as a shallow sea or a shoreline. The limestone could have been formed from the accumulation of shells and other organic material from marine organisms, while the sandstone and shale could have been deposited by erosion and transport of sediment from nearby land.

In terms of the landscape, it is possible that the area that is now Kansas was a low-lying coastal plain, with rivers and streams carrying sediment into the sea. The rolling hills and farm fields seen today are a result of more recent geologic processes, such as erosion and deposition by wind and water.

Overall, the sediment in the rock sample you mentioned was likely deposited in a marine environment in what is now Kansas, during the time period of the Permian Sea.

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The tension in the cable on the right is 550 lbs, and the tension in the cable on the left is also 550 lbs when supporting the 1100-lb weight.

For determining the tension in each cable, consider the given weight of 1100 lbs. Since the weight is supported by two cables, assume that each cable shares an equal portion of the load.

Denote the tension in the cable on the right as \(T_1\) and the tension in the cable on the left as \(T_2\). Since the weight is balanced and the cables are vertical, the total tension in both cables should be equal to the weight.

Therefore, have the equation:

\(T_1 + T_2 = 1100 lbs\)

Since both cables share the weight equally, can set up another equation:

\(T_1 = T_2\)

By substituting the value of \(T_1\) from the second equation into the first equation:

\(T_2 + T_2 = 1100 lbs\\2T_2 = 1100 lbs\\T_2 = 550 lbs\)

Since \(T_1\) is equal to \(T_2\), can conclude that the tension in each cable is 550 lbs.

In conclusion, the tension in the cable on the right is 550 lbs, and the tension in the cable on the left is also 550 lbs when supporting the 1100-lb weight.

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Answer:

A force is a push or pull upon an object resulting from the object's interaction with another object.

Explanation:

Answer:  force is a push or pull upon an object resulting from the object's interaction with another object.

Explanation: Hope this helps and it also on googIe

Answer:

heyyy

May I Know the full question

Answer:

B.

Explanation:

The amount of momentum that an object has is dependent upon two variables: how much stuff is moving and how fast the stuff is moving. Momentum depends upon the variables mass and velocity. In terms of an equation, the momentum of an object is equal to the mass of the object times the velocity of the object.

The change in momentum is the mass and the change in velocity. Option E is correct.

To determine the change in an object's momentum, you need to know the object's mass and the change in its velocity. The momentum of an object is termed as the product of its mass as well as velocity. Mathematically, momentum (p) is expressed as:

p = m × v

Where:

p is the momentum,

m is mass of the object, and

v is the velocity of the object.

The change in an object's momentum (∆p) is given by the difference between its initial momentum (p₁) and its final momentum (p₂):

∆p = p₂ - p₁

Since momentum is dependent on both mass and velocity.

Hence, E. is the correct option.

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--The given question is incorrect, the correct question is

"Which quantities do you need to know in order to determine the change in an object's momentum? A. Change in time and force B. Velocity and change in time C. Acceleration and change in direction  D. Change in speed and force E)  Mass and change in velocity."--

The femur can withstand a compression of about 4.1945 mm before breaking.

We can use the formula for compressive stress to calculate the amount of compression that the femur bone can withstand before breaking:

Stress = Force / Area

where the force is the force applied to the bone and the area is the cross-sectional area of the bone.

To find the cross-sectional area of the femur bone, we can assume that it has a circular cross-section and use the formula:

Area = πr^2

where r is the radius of the cross-section.

Since the length of the femur bone is 0.5 m, we can assume that the cross-sectional area remains constant along its length.

Let's assume that the force required to break the bone is the maximum compressive stress that it can withstand, which is 1.51 × 10^8 Pa. We can rearrange the stress formula to solve for the force.

We can use the equation for strain under compression:

strain = stress / Young's modulus

where stress is the maximum stress the bone can withstand before breaking, and Young's modulus is a measure of the stiffness of the material. The strain is a measure of how much the bone compresses under stress.

To find the compression distance, we can rearrange this equation to solve for the compression distance:

compression distance = strain x original length

where the original length is the length of the bone before compression

Substituting the given values:

stress = 1.51 × 10^8 Pa

Young's modulus = 1.8 × 10^10 Pa

original length = 0.5 m

First, we can calculate the strain:

strain = stress / Young's modulus = (1.51 × 10^8 Pa) / (1.8 × 10^10 Pa) ≈ 0.008389

Next, we can calculate the compression distance:

compression distance = strain x original length = (0.008389) x (0.5 m) = 0.0041945 m

Finally, we can convert the result to millimeters:

compression distance = 0.0041945 m x (1000 mm/m) = 4.1945 mm

Therefore, the femur can withstand a compression of about 4.1945 mm before breaking using Stress = Force / Area

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Answer:

That they must die

Explanation:

Stick = Die

The distance travelled by the car after the first four hours of the trip is 370 km and the average speed for the first four hours of the trip is 92.5 kmph

v ( t ) = d ( t ) / t

v ( t ) = Velocity with respect to time

d ( t ) = Distance with respect to time

t = Time

For the first four hours, the following details are taken from the graph shown.

d ( 4 ) = 370 km

t = 4 hr

v ( 4 ) = 370 / 4

v ( 4 ) = 92.5 kmph

Average velocity can also be calculated using the formula V = ( u + v ) / 2 if the initial and final velocities are given. u represents initial velocity and v represents the final velocity.

Therefore,

Distance travelled in first 4 hours = 370 km

Average speed in first four hours = 92.5 kmph

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The statement that is true is that in turbulent flow, streamlines can begin or end at any point: streamlines are perpendicular to the velocity of the fluid at every point.

At any given point of time, when the flow of water is constant with respect of time then it is called streamline flow. Streamline flow occurs when there are sharp edge obstacles in the path of a fast-moving fluid. Streamline flow is explained by Pascal's principle. In steady flow, the liquid velocity at any particular point is the same. In steady flow of water, we can consider that the two layers of water cannot meet or merge with each other and it will flow continuously without any interruption. The high viscosity index number  of any fluid describes many things about that fluid like high viscosity number describes about the rigidity of that fluid with respect to the flowing area. Streamline flow of any fluid means its smooth flow after passing through a cut edge without disturbing its path.

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The frequency of the photon released when the electron transitions from the second orbit to the first orbit is 2.5 x 10^15 Hz.

The energy of a photon is given by the equation \(E=hf\) where E is energy, h is Planck's constant, and f is frequency.

According to Bohr's model of an atom, the energy of an electron in an orbit is given by the equation \(E= (-13.6eV/n^2)\),

where n is the orbit number, and the negative sign represents the fact that the electron is bound to the nucleus and has potential energy. The initial orbit number is 2, and the final orbit number is 1, and we need to find the frequency of the photon that is emitted.

To calculate the frequency of the photon, we need to find the energy difference between the initial and final orbit.

The energy of the electron in the second orbit is given by:

E₂ = (-13.6 eV/2²) = -3.4 eV

The energy of the electron in the first orbit is given by: E₁ = (-13.6 eV/1²) = -13.6 eV.

The energy difference (ΔE) between the two orbits is given by:

\(ΔE = E₂ - E₁\)

= -3.4 eV - (-13.6 eV)

= 10.2 eV.

Using the equation E=hf, we can calculate the frequency of the photon:

\(f = E/h\)

where E is the energy difference, and h is Planck's constant, which is 6.626 x 10^-34 J s.

Therefore: f = (10.2 x 1.6 x 10^-19 J)/(6.626 x 10^-34 J s)

f = 2.5 x 10^15 Hz

Therefore, the frequency of the photon released when the electron transitions from the second orbit to the first orbit is 2.5 x 10^15 Hz.

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At constant velocity, the crate would be in equilibrium, so that Newton's second law tells us

p + (-f ) = 0

where p and f denote the magnitudes of the added pushing force and friction force, respectively.

The friction force is proportional to the normal force by a factor of µ, the coefficient of friction. There's no vertical movement going on, so Newton's second law says

n + (-w) = 0

where n and w are the magnitude of the normal force and the weight of the crate, respectively.

Compute n :

n = w = (25 kg) (9.80 m/s²) = 245 N

Use this and µ = 0.45 to compute f :

f = µ n = 0.45 (245 N) = 110.25 N

Solve for p :

p + (-110.25 N) = 0

p = 110.25 N ≈ 110 N

The force i.e required to move the crate at a constant velocity across the floor is 110 N.

At the same velocity, the crate should be in equilibrium, so as per Newton's second law, the following formula should be used:

p + (-f ) = 0

p means the magnitudes of the added pushing force

f means the friction force

n = w = (25 kg) (9.80 m/s²) = 245 N

Now

force should be

= µ n

= 0.45 (245 N)

= 110.25 N

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The net displacement is obtained to be 3.6 m.

We know that distance is a scalar quantity and displacement is a vector quantity. Based on this fact, a scalar has a magnitude but lacks direction while vector has both magnitude and direction.

We know that the total distance could be obtained algebraically since distance is a scalar quantity hence we have the total distance as; 2 m + 3m + 4m = 9 m

The net displacement must be obtained geometrically;

Horizontal component of displacement = 4 m - 2m = 2m

Vertical component of displacement = 3m

Net displacement = √2^2 + 3^2

= 3.6 m

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Answer:

They are buried in the ground due to weathering and erosion

Explanation:

Answer:

They are buried in the ground due to weathering and erosion.