A rock brought back from the moon contained 1/8 of the radioactive substance that was present when the rock was formed. If the half-life of this substance is 1.5 billion years, how old in the moon rock?

Answer:

energy??????????????

Answer: Atomic Nucleus

Explanation: The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom.

Explanation: Temperature Affects Density

When the same amount of water is heated or cooled, its density changes. When the water is heated, it expands, increasing in volume. ... The warmer the water, the more space it takes up, and the lower its density.

Answer:

momomomom

Explanation:

its wronh hjjvbkjgddujbxsdsssrrfghjnnkhftygdfff

Answer:

Here's a simple ordinary differential equation that describes the concentration of contamination, g:

dg/dt = -k*g

Where g is the concentration of contamination, t is time, and k is a constant representing the rate of decay of the contamination.

Explanation:

This equation states that the rate of change of contamination concentration with respect to time is proportional to the current concentration of contamination

With a negative sign indicating that the concentration is decreasing over time due to the decay process. The larger the value of k, the faster the contamination concentration will decay.

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59.78175 kPa is the pressure inside the container when a cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a 4.00 L container at 24.0°C.

An ideal gas equation states the relationship between the moles of the substance, temperature, pressure, and volume. The ideal gas equation is given as, PV=nRT

Given data:

\(P_1\)=48.0 atm

\(V_1\)=3T_1=17.0°C

\(P_2\)=?

\(V_2\)=4.00 L

\(T_2\)=24.0°C

\(\frac{P_1V_1}{T_1}\) = \(\frac{P_2V_2}{T_2}\)

\(\frac{48.0 atm X 35.0 mL}{17.0} = \frac{P_2X 4000 ml L}{24.0}\)

\(P_2\)= 0.59 atm = 59.78175 kPa

Hence, 59.78175 kPa is the pressure inside the container when a cylinder at 48.0 atm pressure and 17.0°C releases 35.0 mL of carbon dioxide gas into a 4.00 L container at 24.0°C.

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The number of grams of iron that contain the same number of atoms as 2.24 g of cobalt is 2.122 g. The mole concept is used here to obtain the mass of iron.

The term mole is known as the quantity of a substance which contains the same number of elementary particles as the number of atoms in 12 g of carbon-12 isotope.

The number of moles of a substance can be calculated as:

Number of moles = Mass of the substance ÷ Molar mass

Here the mass of cobalt is 2.24 g and the molar mass of cobalt is 58.93 g/mol.

Then the number of moles of cobalt in 2.24 g is:

2.24 g ÷ 58.93 g/mol = 0.038 mol

According to the question iron contains same number of atoms as cobalt. Thus, iron has the same number of moles.

The molar mass of iron is 55.85 g/mol. The mass of a substance can be calculated from the number of moles and molar mass by the equation:

Mass = Number of moles × Molar mass

The mass of iron is:

0.038 mol × 55.85 g/mol = 2.122 g

Thus the mass of iron is 2.122 g.

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The final answer is  1.8 × 102 L of Rn, measured at STP, are produced per day by 1.08 g of Ra.

In order to determine the amount of radon that is produced per day by 1.08 g of Ra, it is essential to calculate the number of Rn atoms that are produced per second.

In the given question, it is known that 1.00 × 1015 atoms of radium produce an average of 1.373 × 104 atoms of Rn per second.

Therefore, we can use this ratio to calculate the number of Rn atoms that are produced per day by 1.08 g of Ra. Once we know the number of Rn atoms produced per day, we can calculate the volume of Rn produced by using the ideal gas law.

The final answer is  1.8 × 102 L of Rn, measured at STP, are produced per day by 1.08 g of Ra.

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Answer:

Sorry, I don't know.

Explanation:

Answer:

It is not possible to determine whether the crystallization of sodium acetate is endothermic or exothermic simply by feeling the sides of the flask. To determine the heat of crystallization, you would need to measure the temperature of the solution before and after crystallization and compare the two values.

The heat of crystallization is defined as the heat absorbed or released during the process of crystal formation from a solution or a melt. If heat is absorbed during the process, the reaction is endothermic and the temperature of the solution or melt will decrease. If heat is released, the reaction is exothermic and the temperature will increase.

In the case of sodium acetate, it is an exothermic reaction, meaning that heat is released during crystallization and the temperature of the solution will increase. This is because the process of forming the crystal lattice requires the breaking of hydrogen bonds and other intermolecular forces, which releases energy.

Explanation:

Answer:

exothermic

Explanation:

When you crystallize the solution, sodium acetate forms a new bond from the soluble aqueous state ( Na+ and C2H3O2- ) to the solid state (NaC2H3O2). Forming bonds in chemistry is generally an exothermic reaction.

Answer:

The total amount of time elapsed during the reaction is 2.5227 × 10²s

Explanation:

The total amount of time elapsed in this reaction would be to add the (three) individual time taken together: t = t₁ + t₂ + t₃

(2.514 × 10²s) + (1.4 × 10⁻¹s) + (7.397 × 10¹s) = 252.2797 ⇔ 2.5227 × 10²s

e) If the G-C base pair at position 35 in the DNA sequence were changed to a C-G, it would result in a mutation.

f) If the A-T base pair at position 34 were deleted, it would cause a frameshift mutation

e. If the G-C base pair at position 35 in the DNA sequence were changed to a C-G, it would result in a mutation. This mutation is called a point mutation, specifically a substitution mutation. The change from G-C to C-G would lead to a different codon being formed during transcription and translation. The specific amino acid encoded by that codon would be altered. This change in amino acid sequence can potentially affect the structure and function of the resulting protein. The exact impact on the protein's structure and function would depend on the specific amino acid substitution and its location within the protein.

f. If the A-T base pair at position 34 were deleted, it would cause a frameshift mutation. This mutation would shift the reading frame of the DNA sequence during transcription and translation. As a result, all subsequent codons would be read differently, leading to a completely different amino acid sequence downstream of the mutation site. This frameshift mutation can have significant consequences as it can alter the entire protein sequence and disrupt its function. The severity of the impact would depend on the specific protein and the role of the affected region in its structure or function.

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During the Rutherford experiment of gold foil, some alpha particles were deflected by Nucleus of atom.

When Rutherford performed his famous gold foil experiment and bombarded the gold foil with the alpha particles.

While most of the particles passed straight, he concluded that most of the atom is empty.

Some particles were deflected by some small angles.

As we know, the alpha particles are quite heavy particles, so a large mass is required to collide with it in order to deflect from its path.

From this observation, he concluded that, most of the mass of the atom was concentrated in the a very small portion of the atom. This smaller portion was responsible for deflecting the path of the alpha particles.

He named this small portion as the Nucleus of the atom.

So, the Nucleus deflected the alpha particles.

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The property of matter that is conserved in chemical reactions and shown by balanced equations is known as the Law of Conservation of Mass. According to this law, mass can neither be created nor destroyed in a chemical reaction; it can only be transformed from one form to another.For instance, when two substances are combined, they react and form a new substance.

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Fluorine, Neon, and Xenon element to demonstrate the strongest London dispersion force and have the highest boiling point.

London dispersion forces are the weakest type of intermolecular forces and are present in all molecules. These forces arise from the temporary separation of positive and negative charges within a molecule, resulting in the formation of instantaneous dipoles. The strength of London dispersion forces depends on the size and shape of the molecule, as well as the distribution of electrons within the molecule. In general, larger and more polarizable molecules tend to have stronger London dispersion forces. Some examples of elements that tend to demonstrate strong London dispersion forces and have high boiling points include: Fluorine: Fluorine is a highly electronegative element with a large atomic radius, making it highly polarizable and able to form strong London dispersion forces. Fluorine has a boiling point of -188.14 °C (-307.57 °F), which is the highest among the elements. Neon: Neon is a noble gas with a relatively large atomic radius and a high electron affinity, resulting in strong London dispersion forces. Neon has a boiling point of -246.06 °C (-410.97 °F). Xenon: Xenon is a noble gas with a large atomic radius and a high electron affinity, resulting in strong London dispersion forces. Xenon has a boiling point of -108.1 °C (-162.58 °F).

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Answer:

I think its B im not sure

but i hope this helps

Answer:

6⋅10−7 m

Wavelength is speed (3×10^8 m/s) divided by frequency (5⋅16×10^14 Hz)

"the number of ions produced by one formula unit of the electrolyte," refers to the van't Hoff factor (i) in an ideal solution of a strong electrolyte. It represents the extent of dissociation of the electrolyte into ions.

In an ideal solution of a strong electrolyte, the van't Hoff factor (i) represents the number of ions that are produced when one formula unit of the electrolyte dissociates completely in the solution. It is a measure of the extent of dissociation of the electrolyte.

For example, for a strong electrolyte such as sodium chloride (NaCl), when it dissolves in water, it completely dissociates into sodium ions (Na+) and chloride ions (Cl-). In this case, the van't Hoff factor (i) would be 2 because one formula unit of NaCl produces two ions (Na+ and Cl-).

Similarly, for other strong electrolytes, the van't Hoff factor (i) can be determined based on the number of ions produced per formula unit. It is important to note that for non-electrolytes or weak electrolytes, the van't Hoff factor (i) is typically less than 1, indicating partial dissociation or no dissociation in the solution.

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Answer:

2.09 atm

Explanation:

Given: Temperature of system. volume of system, and masses of component gasses.

In order to get the mole fraction which we will use later, convert the 60.0 g CO2 and 82.1 g H20 into moles and add the number of moles you got yo 7.30.

(60.0g CO2 / 44.01 g/mole) + (82.1g H20/18.02) + 7.30 moles unknown fuel

This should work out to about 13.22 moles total. Then, plug in your numbers to the ideal gas law (PV=nRT or P=nRT/V). This will result in the total pressure of the system. p=(13.22 moles)x(0.08206 l*ATM/moles *K)x(468.2)/25.0L. This equation results in a total of 20.3 atm. According to Daltons law of partial pressure, the mole fraction (moles of a gas over total moles) of a given gas times the total pressure of the container gives the partial pressure.

(1.36/13.22) * 20.3 atm=2.09 atm

Pair 1: CH₃SH is predicted to have higher standard entropy, Pair 2: NH₃ is predicted to have higher standard entropy, Pair 3: SO₂ is predicted to have higher standard entropy, Pair 4: H₂O is predicted to have higher standard entropy, Pair 5: HCl is predicted to have higher standard entropy, Pair 6: CO₂ is predicted to have higher standard entropy, Pair 7:  C₆H₁₄ is predicted to have higher standard entropy

Given, pairs of substances with the molar amount used in the comparison are shown below: Pair 1: CH₃OH or CH₃SH, Pair 2: NH₃ or N₂H4 , Pair 3: SO₂ or SO₃, Pair 4: H₂S or H₂O, Pair 5: HCl or HBr, Pair 6: CO or CO₂, Pair 7: C₆H₁₄ or  C₆H₁₂. The standard entropy of a substance is determined by the motion of the atoms or molecules in that substance. The more ways the particles in a substance can move, the more disorder (or entropy) the substance has. The standard entropy values at 25°C (298 K) for the above-listed pairs of substances are listed above.

The reason why the first compound in each pair has higher entropy than the second compound in the pair are listed below:

1. In CH₃SH, there are more atoms that can move about freely compared to CH₃OH.

2. NH₃ has more ways the molecules can move compared to N₂H₄.

3. In SO₂, the vibrational degrees of freedom are more compared to SO₃.4. In H₂O, the rotational and translational degrees of freedom are more compared to H₂S.

5. In HCl, the vibrational degrees of freedom are more compared to HBr.

6. In CO₂, there are more degrees of freedom for the vibrations of the atoms compared to CO.

7. In C₆H₁₄, the rotational and translational degrees of freedom are more compared to C₆H₁₂.Therefore, the standard entropy values of the compounds in each pair are as listed above.

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To determine the age of a rock, you can use the fact that uranium-238 decays into lead with a known half-life of 4.47 billion years. The percentage of uranium-238 remaining in the rock can be used to calculate how many half-lives have passed since the rock formed.

In this case, since 61% of the original uranium-238 remains, it means that 39% has decayed into lead. Using the half-life of uranium-238, we can calculate that the rock is approximately 1.5 billion years old. This assumes that the rock has remained closed to outside sources of uranium-238 and lead since it formed, and that no lead has migrated into or out of the rock during this time.

Follow these steps:

1. Determine the half-life of uranium-238, which is 4.468 billion years.
2. Calculate the number of half-lives elapsed using the formula: remaining percentage = (1/2)^n, where n is the number of half-lives. In this case, 0.61 = (1/2)^n.
3. Solve for n: n = log(0.61) / log(0.5) ≈ 0.388.
4. Multiply the number of half-lives by the half-life duration: 0.388 * 4.468 billion years ≈ 1.734 billion years.

The age of the rock is approximately 1.734 billion years.

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Answer:

radio and sound

Explanation:

Because they are waves in motion

Our current understanding of the atom is based on Dalton's early 19th-century idea of atomism, which was developed from meteorological investigations. John Dalton was just a meteorologist, an expert on color blindness, and a teacher, but he will be most widely recognized for creating the idea of atomism.

A scientist is someone who meticulously gathers data and uses it to develop theories, test those hypotheses, and further knowledge and understanding. Despite the fact that the name "scientist" predates Aristotle by more than two millennia, he is frequently referred to as the first scientist. He invented the methods of reasoning, observation, inquiry, and demonstration in Greece in the fourth century BC.

Because they provide specialized explanations for how the world functions, scientists play a crucial role in society. Science is a powerful tool for survival, despite the fact that it doesn't always provide us with joy, and humans have spent considerable time starting to figure out how to do both.

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The molarity of the potassium hydroxide (KOH) solution is 0.1318 M.

Let's calculate the molarity of the potassium hydroxide (KOH) solution based on the given information:

Given:

Volume of HNO3 solution (V1) = 21.50 mL = 0.02150 L

Molarity of HNO3 solution (M1) = 0.1532 M

Volume of KOH solution (V2) = 25.00 mL = 0.02500 L

Step 1: Calculate the moles of HNO3 used in the reaction.

moles of HNO3 (n1) = M1 * V1

                  = 0.1532 M * 0.02150 L

                  = 0.003294 moles

Step 2: Calculate the moles of KOH (potassium hydroxide).

Since the mole ratio between KOH and HNO3 is 1:1, the moles of KOH (n2) is also equal to n1.

moles of KOH (n2) = moles of HNO3 (n1)

                 = 0.003294 moles

Step 3: Calculate the molarity of the KOH solution (M2).

M2 = moles of KOH / volume of KOH solution

  = n2 / V2

  = 0.003294 moles / 0.02500 L

  = 0.1318 M

Therefore, the molarity of the potassium hydroxide (KOH) solution is 0.1318 M.

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Answer:

Explanation:

electrons have a minus charge. There are more of them than protons.

8 - 11 = -3 is the charge of the ion. (at atom that has a charge is an ion).

Acetone has α-hydrogens (on both sides) and thus can be deprotonated to give a nucleophilic enolate anion. The aldehyde carbonyl is much more electrophilic than that of a ketone, and therefore reacts rapidly with the enolate.

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The volume of SO₂ formed from the reaction is approximately 35.7092 liters at STP.

To determine the volume of SO₂ formed from the reaction, we need to calculate the number of moles of SO₂ produced first. Then we can use the ideal gas law to convert the moles of SO₂ to volume at STP (Standard Temperature and Pressure).

Let's begin by balancing the chemical equation for the reaction between FeS₂ and O₂;

4FeS₂ + 11O₂ → 2Fe₂O₃ + 8SO₂

From the balanced equation, we can see that 4 moles of FeS₂ react to produce 8 moles of SO₂.

Calculate the number of moles of FeS₂;

molar mass of FeS₂ = atomic mass of Fe (55.845 g/mol) + atomic mass of S (32.06 g/mol) × 2

= 55.845 g/mol + 32.06 g/mol × 2

= 119.965 g/mol

moles of FeS₂ = mass of FeS₂ / molar mass of FeS₂

= 96.7 g / 119.965 g/mol

≈ 0.8069 mol

Calculate the number of moles of SO₂;

From balanced equation, we can see that 4 moles of FeS₂ produce 8 moles of SO₂.

Therefore, moles of SO₂ = 2 × moles of FeS₂

= 2 × 0.8069 mol

= 1.6138 mol

Convert moles of SO₂ to volume at STP

According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant (0.0821 L·atm/mol·K), and T is the temperature in Kelvin.

At STP, the temperature is 273.15 K, and the pressure is 1 atm.

Rearranging the ideal gas law equation to solve for V, we have:

V = (nRT) / P

V = (1.6138 mol × 0.0821 L·atm/mol·K × 273.15 K) / 1 atm

= 35.7092 L

Therefore, the volume of SO₂ will be 35.7092 liters at STP.

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Answer: Its B for the Study Island assignment

Explanation:

Answer:

controlled

Explanation:

awnser

The Phlogiston Theory of ordinary burning posited that the materials that were combustible all contained a material called Phlogiston.

In science, theories are often put forward to explain a phenomenon.  theory may not survive the test of time when contrary evidences begin to emerge.

The Phlogiston Theory of ordinary burning posited that the materials that were combustible all contained a material called Phlogiston  which is released when the material is burnt.

However, Lavoisier was able to show by experiment that this position was a mere speculation and the the combustion of a substance was due to its reaction with oxygen.

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The compressibility factor is 1.1.

Temperature of Nitrogen = 288 K

Pressure of Nitrogen = 8mpa

The ideal gas law's departure is compensated for by the compressibility factor (Z). An equation of state or industry correlation based on the following relationship is used to compute the compressibility factor:

                                            PV = ZRT

Z ~f (composition, P, T)

where,

Z = compressibility factor at P, T for a given composition.

P = absolute pressure.

T = temperature.

R = universal gas constant.

                             V = \(\frac{ZRT}{P}\)

                                 = (Z × 8.314 × 288) / 8 × 10⁷

                                 = (299.30 × 10⁻⁷) Z m³/kg

The reduced temperature is the ratio of the temperature of the gas to its critical temperature. Similarly, the reduced pressure is the ratio of the gas pressure to its critical pressure as described in the following equations:

\(T_r=\frac{T}{T_c} \\\\P_r=\frac{P}{P_c}\)

P – Absolute pressure of gas

T – Absolute temperature of gas

Tr – Reduced temperature

Pr – Reduced pressure

Tc – Critical temperature

Pc – Critical pressure

\(T_r= \frac{288}{126.2} = 2.3\\\\P_r = \frac{8}{3.39} = 2.3\)

Z = 1.1 (from the compressibility chart)

V = 329.23 10⁻⁷ m³/kg

Therefore, the compressibility factor is 1.1.

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