The 80% confidence interval for the mean length difference between two-year-old and one-year-old spotted flounder is [5.15, 7.83] millimeters.
How to calculate the valueFor an 80% confidence interval, we need to find the critical value associated with a two-tailed test. Since the sample sizes are large, we can use the z-distribution. The critical value for an 80% confidence interval is approximately 1.282.
ME = 1.282 * 1.0466 ≈ 1.3426
Confidence interval = Point estimate ± Margin of error
Confidence interval = 6.49 ± 1.3426
Finally, rounding to at least two decimal places:
Confidence interval = [5.15, 7.83]
Therefore, the 80% confidence interval for the mean length difference between two-year-old and one-year-old spotted flounder is [5.15, 7.83] millimeters.
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Mr. Park is using the following equation to predict a student’s final exam score, f, using the student’s current grade, g.
f=0.73g+16.8
What is the dependent variable?
Responses
the student’s current grade
the student’s current grade
the student’s final exam score
the student’s final exam score
the student’s most recent exam score
the student’s most recent exam score
the student’s most recent classwork grade
The dependent variable is "f" in the given equation f = 0.73g + 16.8.
What is the independent and dependent variable?Values that differ in respect to one another are referred to as independent and dependent variables in mathematics. Because the dependent variable is reliant on the independent variable, it will change if the value of the independent variable does.
Given:
f = 0.73g + 16.8 .....(i)
The formula used to forecast a student's final exam grade, f, based on their current grade, g.
Because the independent variable "g" and the dependent variable "f" are interdependent, the dependent variable "f" will change if the independent variable "g" changes in value.
Thus, the dependent variable is "f" in the given equation f = 0.73g + 16.8.
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ABC and QRS are supplementary angels.
If the measure of ABC = 91. What is the measure of QRS?
Answer:A normal QRS complex measures 0.06 to 0.12 seconds which is 1.5 to 3 small boxes on the EKG strip. When you measure the QRS complex you start by measuring at the END of the PR interval to the END of S-wave.
Step-by-step explanation:
3. The carrying capacity of a drain pipe is directly proportional to the area of its cross- section. If a cylindrical drain pipe can carry 36 litres per second, determine the percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second.
The percentage increase in the diameter of the drain pipe necessary to enable it to carry 60 litres per second is 28.87%.
Given that the carrying capacity is directly proportional to the area, we can write:
C1 ∝ A1 = πr₁²
Since the carrying capacity is directly proportional to the area, we have:
C2 ∝ A2 = πr₂²
To find the percentage increase in diameter, we need to find the ratio of the increased area to the initial area and then express it as a percentage. Let's calculate this ratio:
(A2 - A1) / A1 = (πr₂² - πr₁²) / (πr₁²) = (r₂² - r₁²) / r₁²
We can also express the ratio of the increased carrying capacity to the initial carrying capacity:
(C2 - C1) / C1 = (60 - 36) / 36 = 24 / 36 = 2 / 3
Since the area and the carrying capacity are directly proportional, the ratios should be equal:
(r₂² - r₁²) / r₁² = 2 / 3
Now, let's substitute r = D/2 in the equation:
((D₂/2)² - (D₁/2)²) / (D₁/2)² = 2 / 3
(D₂² - D₁²) / D₁² = 2 / 3
Cross-multiplying:
3(D₂² - D₁²) = 2D₁²
3D₂² - 3D₁² = 2D₁²
3D₂² = 5D₁²
Dividing by D₁²:
3(D₂² / D₁²) = 5
(D₂² / D₁²) = 5 / 3
Taking the square root of both sides:
D₂ / D₁ = √(5/3)
To find the percentage increase in diameter, we subtract 1 from the ratio and express it as a percentage:
Percentage increase = (D₂ / D₁ - 1) × 100
Percentage increase = (√(5/3) - 1) × 100
Percentage increase = 28.87%
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Slope and graphingY= -2x -4
y = -2x - 4
compare with y = mx + c
m = slope, c constant
so, slope m = -2
for graph,
y = - 2x - 4
put x = 0 so,the point is (0, -4)
y = -4
x = 1
y = -2(1) - 4
y = -2 - 4
y = -6 (1,60)
put x = 2 (2, -12)
y = -2(4) - 4
y = -8 -4
y = -12
NOw we can say that we point to draw, so now you draw the points on your graph, thank you
9) The cost per gallon of ice cream is $5.50. You have $55 to spendon ice cream.(a) Write an algebraic expression for the situation described above.(b) How many pints of ice cream can you buy for $55 ?
What is the value of x?
45°
m
(2x-5)
n
Answer:
x = 70
Step-by-step explanation:
The two angles are same side interior angles and same side interior angles add to 180
45+ (2x-5) = 180
Combine like terms
2x +40 = 180
Subtract 40 from each side
2x+40-40 =180-40
2x =140
Divide by 2
2x/2 = 140/2
x = 70
Answer:
x=70
Step-by-step explanation:
hope it helped! :)
have a nice day
Can somebody please help me with this? I’m very confused! I need help asap it’s due today!!
Pls help!
The complementary event of randomly selecting an orange flower is selecting an orange, red, white, or purple flower (option C).
How to identify the complementary event to selecting an orange flower?To identify the complementary event to selecting an orange flower, we must identify what other possibilities may occur if we do not select an orange flower at random.
In this case, picking an orange, red, white, or purple rose are still complementary events because they all have a probability of occurrence. In this case, the one that is most likely to occur is purple, orange, white and red due to the number of flowers of each color.
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is y = 7x - 3 proportional relationship? yes or no
Answer:
yes
Step-by-step explanation: if it goes through the orgin it is
an article reported that, in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 201 of these passed the probe. assuming a stable process, calculate a 95% (two-sided) confidence interval for the proportion of all dies that pass the probe. (round your answers to three decimal places.) ,
the 95% confidence interval for the proportion of all dies that pass the probe is [0.513,0.616].
What is sample proportion?Sampling is frequently used to estimate the percentage of population that possesses a particular attribute, such as the percentage of all faulty goods which come off an assembly line or the percentage among all buyers that enter a store and make a purchase before leaving. The population proportion is indicated p, while the sample proportion is written p. Thus, if 43% of individuals visiting a business make a purchase before departing, p = 0.43; if 78 people enter the store and make a transaction, p=78/200=0.39.
The sample proportion is a random variable because it differs from sample to sample in ways that are impossible to anticipate in advance. When seen as a random variable, it will be represented by the letter P.
How to solve?
An article reported that in a study of a particular wafer inspection process, 356 dies were examined by an inspection probe and 169 of these passed the probe.
So,p'=201/356=0.56460
The 95% confidence interval for the proportion of all dies that passed the probe will be,
p∈[p'±zα/2√p'(1−p')/n]
p∈[0.56460±1.96×√0.56460(1−0.56460)356]
p∈[0.513,0.616]
So the 95% confidence interval is [0.513,0.616].
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Twelve increased by four times a number is
negative 8. I need the equation and solution !!
x = a number
12 + 4x = -8
Subtract 12 from both sides
4x = -20
Divide both sides by 4
x = -5
find the inverse matrix if one exists 5 3 13 8
Answer:
Step-by-step explanation:
To find the inverse of a matrix, we need to put it in the reduced row echelon form (RREF) using elementary row operations. We can augment the given matrix with an identity matrix of the same size, and then apply the row operations to both matrices simultaneously until the left-hand side becomes an identity matrix. The right-hand side will then be the inverse of the original matrix.
Here are the steps:
[ 5 3 | 1 0 ]
[13 8 | 0 1 ]
R1/5 -> R1:
[ 1 3/5 | 1/5 0 ]
[13 8 | 0 1 ]
R2-13R1 -> R2:
[ 1 3/5 | 1/5 0 ]
[ 0 1/5 | -13 1 ]
R1-(3/5)R2 -> R1:
[ 1 0 | 26/5 -3/5 ]
[ 0 1 | -13 1/5 ]
So, the inverse matrix is:
[ 26/5 -3/5 ]
[-13 1/5 ]
Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.
Use the polygon tool to graph the dilated figure.
Polygon
+Move
10
9
8
7
6
5
4
3
2
1
-10-9-8-7-6-5-4-3-2-10
Undo
y
2
10
4
Redo
5
6
7
x Reset
8
00
9 10
The polygon tool to graph the dilated figure will be drawn below.
How to draw the graph of the function?The collection includes all locations on the surface of the shape (x, f(x)) that make up a function of f's graph. We may alternatively say that the graph of f is the curve of y = f. (x). As a result, the diagram of an equation is a particular instance of the graphs of functions.
It is a polygon with four sides. The total interior angle is 360 degrees. A rectangle's opposite sides are parallel and equal, and each angle is 90 degrees. Its diagonals are all the same length and intersect in the center.
Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.
The polygon tool to graph the dilated figure will be drawn below.
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There are 1000 rabbits and chickens on a farm, and together they have 3150 legs. How many rabbits and how many chickens are there on the farm?.
The number of rabbits on the farm is 575 and the number of chickens is 425.
Here we have to find the number of rabbits and the number of chickens on the farm.
Data given:
Total number of rabbits and chicken = 1000
Number of legs = 3150
Let x be the number of rabbits and y be the number of chickens.
So we have
x + y = 1000 -------(1)
4x + 2y = 3150
A rabbit has 4 legs and a chicken has 2 legs.
2x + y = 1575 ------(2)
Substrating equation (1) from (2) we have:
x = 575
Now put in equation (1) we have:
575 + y = 1000
y = 425
Therefore the number of rabbits is 575 and the number of chickens is 425.
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The table below gives the annual sales (in millions) of a product. year 1998 1999 2000 2001 2002 2003 2004 2005 2006 sales 222 276 318 348 366 372 366 348 318 What was the average rate of change of annual sales a) Between 2003 and 2004 millions of dollars/year b) Between 2003 and 2006 millions of dollars/year
Using it's concept, the average rate of change is given as follows for the intervals:
a) -6 millions of dollars per year.
b) -18 millions of dollars per year.
What is the average rate of change of a function?The average rate of change of a function is given by the change in the output divided by the change in the input. Hence, over an interval [a,b], the rate is given as follows:
\(r = \frac{f(b) - f(a)}{b - a}\)
For item a, we have that:
In 2003, the amount is of 372 million sales.In 2004, the amount is of 366 million sales.Hence:
r = (366 - 372)/1 = -6 millions of dollars per year.
For item b, we have that:
In 2003, the amount is of 372 million sales.In 2006, the amount is of 318 million sales.Hence:
r = (318 - 372)/3 = -18 millions of dollars per year.
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Please Help me please
Answer:
Line 1 and Line 2: Parallel
Line 1 and Line 3: Perpendicular
Line 2 and Line 3: Perpendicular
Step-by-step explanation:
Put it into Desmos.
It really helps. Please tell me if this is wrong.
A participant took 5. 2 hours to complete a marathon. How many minutes did the participant take to complete the marathon? use 1 hour = 60 minutes.
312 minutes the participant took to complete the marathon
Unit conversion is a process with multiple steps that involves multiplication or division by a numerical factor or, particularly a conversion factor. The process may also require selection of the correct number of significant digits, and rounding.
According to the question,
The time taken by participant to complete a marathon in hours = 5.2 hours
1 hour contains 60 minutes
so, to change hours into minutes , we have to multiple hours into 60
Time taken by participant to complete a marathon in minutes = 5.2 × 60
=> 312 minutes
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It is given that and are right angles, and . Since they contain right angles, ΔABR and ΔACR are right triangles. The right triangles share hypotenuse , and reflexive property justifies that . Since and , the transitive property justifies . Now, the hypotenuse and leg of right ΔABR is congruent to the hypotenuse and the leg of right ΔACR, so by the HL congruence postulate. Therefore, ________ by CPCTC, and bisects by the definition of bisector.
THIS IS THE COMPLETE QUESTION BELOW;
Complete the paragraph proof. Given: ∠ABR and ∠ACR are right angles AB ≅ BC BC ≅ AC Prove: bisects ∠BAC
It is given that ∠ABR and ∠ACR are right angles, AB ≅ BC and BC ≅ AC Since they contain right angles, △ABR and △ACR are right triangles. The right triangles share hypotenuse AR, and reflexive property justifies that AR ≅ AR. Since AB ≅ BC and BC ≅ AC, the transitive property justifies AB ≅ AC. Now, the hypotenuse and leg of right △ABR is congruent to the hypotenuse and the leg of right △ACR, so △ABR ≅ △ACR by the HL congruence postulate. Therefore, by CPCTC, and bisects ∠BAC by the definition of bisector.
Answer:
The answer is ∠BAR=∠CAR
Step-by-step explanation:
From the question, In the ΔABR and ΔACR , AB=AC=X
CHECK THE ATTACHMENT FOR DETAILED STEP BY STEP EXPLANATION:
Answer:
A) <BAR = <CAR
Step-by-step explanation:
Edge
The perimeter of a rectangle is 280cm. The ratio of the width to the length is 3:4. What is the length of the rectangle?
Answer:
So first we need to get the perimeter formula. P = 2(w+l). We know P but we dont know w and h.
280/2 = 140. So now we know that 140 = w+l. We also know that the length is 4/3 times greater than the width (we used the ratio). To prove this 3*4/3 = 4, just like in ratio. So we have 2 equations
140 = w+l
l = 4/3w
Now we can plug into 140
140 = w+4/3w
So if you solve algebraicly you get
60 = w.
Now we can find that the length =
80 is the answer to length..
Now to prove answer 60+80 = 140.
So the answer is
Width: 60Length: 80brainliest?The length of the rectangle is 80cm and the width is 60cm
The perimeter of the rectangle is given as 280cm and the ratio of the length to width is 3:4.
The formula of perimeter of rectangle is given as;
\(P=2(L+W)\)
This implies that
\(280=2(l + w)\\280=2l+2w\\l+w=140...equation(i)\)
LengthBut let's go back to our given ratio
3:4 = l:w
3l = 4w
make w the subject of formula
\(w = (3/4)l\)
Let's substitute this into equation (i)
\(l+w=140\\w=(3/4)l\\l+(3/4)l=140\\(7/4)l=140\)
solve for l
\(\frac{7}{4}l=140\\4*140 = 7l\\560=7l\\l= 560/7\\l=80\)
WidthSince L = 80, let's substitute it into equation (i)
\(l+w = 140\\80+w = 140\\w = 140 - 80\\w = 60\)
From the calculations above, we have the following data
length = 80cmwidth = 60cmperimeter = 280cmThe length of the rectangle is 80cm and the width is 60cm
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Please help, I’ll give brainliest
Answer:triangles always equal 180 so subtract the variable inside the triangle.
Step-by-step explanation:
Let m = x^2 - 5
Which equation is equivalent to (x^2-5)^2 - 3x^2 + 15= -2 in terms of m ?
A m^2+3m+2=0
B m^2-3m+17=0
C m^2-3m+2=0
D m^2+3m+17=0
Thanks!
The equivalent equation to the (x² - 5)² - 3x² + 15 = -2 in form of 'm' is given by option c. m² -3m + 2 = 0.
The equation is equal to,
(x² - 5)² - 3x² + 15 = -2
let the value of m be equals to x² - 5.
Simplify the equation we have,
⇒ ( x² - 5 )² - 3x² + 15 = -2
Take '3' common factor from the 3x² + 15 so that it get convert into x² - 5 we get,
⇒ ( x² - 5 )² - 3 (x² - 5 ) = -2
Now replace x² - 5 by m to get the equivalent equation,
⇒ ( m )² - 3 (m ) = -2
⇒ m² -3m + 2 = 0
Therefore, the equivalent equation to the given equation is written as option c. m² -3m + 2 = 0.
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60 students have a mean iq of 100.4 with standard deviation 5.2. we wish to estimate with 99% confidence the mean iq of all students. we should use:
To estimate the mean IQ of all students with 99% confidence, we should use a confidence interval based on the t-distribution.
Given that we have a sample of 60 students with a mean IQ of 100.4 and a standard deviation of 5.2, we can use the t-distribution to construct a confidence interval for the population mean.
Since the population standard deviation is unknown and the sample size is relatively small, the t-distribution is appropriate for this scenario. With a desired confidence level of 99%, we would use the critical value associated with a 99% confidence level from the t-distribution.
By calculating the confidence interval using the sample mean, sample standard deviation, sample size, and the appropriate critical value from the t-distribution, we can estimate the mean IQ of all students with 99% confidence.
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Simple math! Please help!!!!
\( c.\:{x}^{ - 4} \)
\(\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\orange{:}}}}}\)
\( \frac{7 {x}^{4} }{7 {x}^{8} } \\ = \frac{ {x}^{4} }{ {x}^{8} } \\ = {x}^{4 - 8} \\ = {x}^{ - 4} \)
Note:-
\( {x}^{m} \times {x}^{n} = {x}^{m + n} \\ {x}^{m} \div {x}^{n} = {x}^{m - n} \)
\(\large\mathfrak{{\pmb{\underline{\orange{Happy\:learning }}{\orange{.}}}}}\)
3. An artist is selling children's crafts. Necklace cost $2.25 each, and bracelets cost $1.50 per each. Select all the combinations of necklaces and bracelets that the artist could sell for exactly $12.00.
The artist could sell 4 necklaces and 2 bracelets or just 8 bracelets for exactly $12.
What is an equation?An equation is an expression that uses mathematical operations to show the relationship between numbers and variables. Types of equations are linear, quadratic, cubic and so on.
Let x represent the number of necklaces and y represent the number of bracelet.
Necklace cost $2.25 each, and bracelets cost $1.50 per each. The artist could sell exactly $12.00. Hence:
2.25x + 1.5y = 12
From the graph, the points (4,2) and (0, 8) satisfy this equation
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Which expression is equivalent to 1/4x+3−1/3x+(−2)?
Answer:
7/12x+5
Step-by-step explanation:
Show that the given ODE is an Exact Equation and the solve it. (2xy - 6x² + 4y) dx + (x² + 4x + y³ − 8) dy = 0
The general solution to the given exact ODE is:
x²y + 4xy + (1/4)y⁴ - 8y - 2x³ = C
where C is an arbitrary constant.
To determine if the given ordinary differential equation (ODE) is exact, we need to check if it satisfies the condition for exactness:
∂M/∂y = ∂N/∂x
Let's evaluate the partial derivatives of the given equation:
∂M/∂y = 2x
∂N/∂x = 2x + 4
Since ∂M/∂y = ∂N/∂x, the equation satisfies the condition for exactness.
To solve the exact ODE, we need to find a potential function ψ(x, y) such that its partial derivatives satisfy the equation:
∂ψ/∂x = M and ∂ψ/∂y = N
From the given ODE, we can determine ψ(x, y) by integrating M with respect to x and integrating N with respect to y. Let's perform these integrations:
ψ(x, y) = ∫ (2xy - 6x² + 4y) dx = x²y - 2x³ + 4xy + h(y)
ψ(x, y) = ∫ (x² + 4x + y³ − 8) dy = x²y + 4xy + (1/4)y⁴ - 8y + g(x)
In order for the equation to be exact, the expressions for ψ(x, y) obtained from integrating M with respect to x and N with respect to y must be equal. Therefore, we have:
x²y - 2x³ + 4xy + h(y) = x²y + 4xy + (1/4)y⁴ - 8y + g(x)
From this equation, we can conclude that:
h(y) = (1/4)y⁴ - 8y + C₁
g(x) = -2x³ + C₂
where C₁ and C₂ are constants of integration.
Finally, substituting h(y) and g(x) back into ψ(x, y), we obtain the potential function:
ψ(x, y) = x²y + 4xy + (1/4)y⁴ - 8y - 2x³
Therefore, the general solution to the given exact ODE is:
x²y + 4xy + (1/4)y⁴ - 8y - 2x³ = C
where C is an arbitrary constant.
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at a restaurant 6 hot dogs cost $8.28 and 7 hamburgers cost $9.24. which food has the lower unit price?
Answer:
hamburger
Step-by-step explanation:
9.24÷7=1.32
8.28÷6=1.38
the hamburger is lower than the hot dog
The food which has the lower unit price is hamburgers which costs $1.32 per unit.
Given that, at a restaurant 6 hot dogs cost $8.28 and 7 hamburgers cost $9.24.
What is the lower unit price?A unit price is the price for one item or measurement, such as a pound, a kilogram, or a pint, which can be used to compare the same type of goods sold in varying weights and amounts. Multiple pricing is selling two or more of the same item at a price that is lower than the unit price of a single item.
Unit price of hot dogs = 8.28/6
= $1.38
Unit price of hamburgers = 9.24/7
= $1.32
Therefore, the food which has the lower unit price is hamburgers which costs $1.32 per unit.
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a chocolate company selects 800 random packages to check their weight. It finds that 12 packages have an incorrect weight. How many packages out of 4000 should the company predict to have the incorrect weight.
Answer:
1.5% of 4000 or 60
Step-by-step explanation:
A taste test asks people from Texas and California which pasta they prefer,
brand A or brand B. This table shows the results.
A person is randomly selected from those tested.
Are being from California and preferring brand B independent events? Why or why not?
Option (C) Yes, they are independent because P(California) is 0.55 and P(California | brand B) is 0.55 is the correct answer.
What is probability?
Probability deals with the occurrence of a random event. The chance that a given event will occur. It is the measure of the likelihood of an event to occur.The value is expressed from zero to one.
For the given situation,
Total number of people in Texas = 275
Total number of people in California = 150
Total number of people in California and preferring brand B = 54
Probability of people in California,
P(California) = Number of people in California / Total number of people
⇒ \(\frac{150}{275}\)
⇒ \(0.54545\) ≈ \(0.55\)
Probability of people in California and preferring brand B
P(California | brand B) = Number of people in California and preferred brand B / Number of people preferred brand B
⇒ \(\frac{54}{99}\)
⇒ \(0.54545\) ≈ \(0.55\)
In the data provided, each event is not dependent on other events.
Thus they are independent events.
Hence we can conclude that option (C) Yes, they are independent because P(California) is 0.55 and P(California | brand B) is 0.55 is the correct answer.
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Find the missing height, when you know the area of the rectangle 9+9+?+?=126
Answer:
54
Step-by-step explanation:
First take
9 + 9 = 18
Then,
126 - 18 = 108
Then,
108 / 2 = 54
Which is the height
Hope this helps you. :)
Have a good day!
This formula counts for both height and width when you have the area.
John Barker owns a repair shop in Ontario, a province that has a 13 percent HST rate. He has asked you to calculate the HST payable or refund for the first reporting period. Given the following information, what should the repair shop’s HST payable or refund be? Amount Before HST Sales $150,000 Equipment purchased 96,000 Supplies purchased 83,000 Wages paid 19,000 Rent paid 17,000
a) A refund of $8,450 b) A payment of $6,500 c) A refund of $3,770 d) A refund of $5,980
John Barker's repair shop in Ontario is required to calculate the HST payable or refund for the first reporting period. The HST rate is 13% and the amount before HST sales is $150,000. The total HST collected from sales is $19,500 and the total ITCs are $19,790. The net HST payable/refund is $19,500 - $19,790 and the correct option is d) A refund of $5,980.
Given the following information for John Barker's repair shop in Ontario, we are required to calculate the HST payable or refund for the first reporting period. The HST rate for Ontario is 13%.Amount Before HST Sales $150,000 Equipment purchased $96,000 Supplies purchased $83,000 Wages paid $19,000 Rent paid $17,000Let's calculate the total HST collected from sales:
Total HST collected from Sales= HST Rate x Amount before HST Sales
Total HST collected from Sales= 13% x $150,000
Total HST collected from Sales= $19,500
Let's calculate the total ITCs for John Barker's repair shop:Input tax credits (ITCs) are the HST that a business pays on purchases made for the business. ITCs reduce the amount of HST payable. ITCs = (HST paid on eligible business purchases) - (HST paid on non-eligible business purchases)For John Barker's repair shop, all purchases are for business purposes. Hence, the ITCs are the total HST paid on purchases.
Total HST paid on purchases= HST rate x (equipment purchased + supplies purchased)
Total HST paid on purchases= 13% x ($96,000 + $83,000)
Total HST paid on purchases= $19,790
Let's calculate the net HST payable or refund:
Net HST payable/refund = Total HST collected from sales - Total ITCs
Net HST payable/refund = $19,500 - $19,790Net HST payable/refund
= -$290 Since the Net HST payable/refund is negative,
it implies that John Barker's repair shop is eligible for an HST refund. Hence, the correct option is d) A refund of $5,980.
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