a vehicle accelerates with 0.4 m/s. calculate tue time taken by the vehicle to increase its speed from 20m/s to 40m/s.​

Answer:

0

Explanation:

im pretty sure its 0 pls mark me as brainliest

4 hybrid sp3 orbitals

Four sp3 hybrid orbitals emerge from the hybridization of a s orbital with each of the three p orbitals (px, py, and pz).

The binding angle between the sp3 hybrid orbitals is 109.5 degrees. Tetrahedral molecular structure can be explained via sp3 hybridization. It produces four sp3 orbitals, each of which is made up of 75% p character and 25% s character, by the hybridization of the two 2s orbitals and all three of the two 2p orbitals. We shall use carbon as an example because of how important it is to organic chemistry. The three 2p orbitals and the two 2s orbitals of carbon combine to generate four sp3 orbitals. Following an sp3-s orbital overlap, these orbitals join with four hydrogen atoms to form methane. The outcome shape is tetrahedral, since that minimizes electron repulsion.

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Answer:

50 Meters North

Explanation:

Displacement is the distance/direction from the start point to

the ending point, regardless of which route you took from the start to the end.

So, you would simply subtract:

1,500 meters North- 1,450 meters South= 50 meters North

Answer:

Elements fill the lowest energy subshells first(Aufbau's rule), and the 4s subshell is lower energy than the 3d, making the labeling deceiving. In some rare situations, the electrons would rather have Hund's rule be respected more, having all electrons facing one way with no doubled up because it is more stable(these are pretty rare and usually deal with transition metals like copper).

Hope this helps!

Explanation:

As it has less energy than the 3d orbital, the 4s orbital fills next. Following the filling of the electrons, 4s has more energy than 3d. Therefore, the two electrons in the 4s are at a higher energy than they could be in the 3d since it has a vacancy. As a result, electrons transition from a higher to a lower energy orbital.

The elementary electric charge of the electron is a negative one, making it a subatomic particle. Due to their lack of components or substructure, electrons, which are part of the lepton particle family's first generation, are typically regarded to be elementary particles.

Since 4s electrons are bound by the nucleus farther away and more loosely than 3d electrons, 4s electrons are eliminated first rather than 3d electrons.

The 4s orbital should always be filled before the 3d orbitals, according to the Aufbau principle, although this isn't the case for the majority of elements. After Sc, electrons actually enter the 3d orbitals first because they have a lower energy than the 4s orbital.

Thus, electrons transition from a higher to a lower energy orbital.

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The partial pressures of NO2, O2, and N2 can be found by multiplying the total pressure by the mole fraction of each gas component. The partial pressures of NO2, O2, and N2 are 0.60 atm, 0.66 atm, and 0.74 atm, respectively

Mole fraction is a unitless quantity used to express the ratio of the number of moles of a particular substance to the total number of moles in a mixture. It is defined as the ratio of the number of moles of a component in a mixture to the total number of moles of all components in the mixture. The mole fraction of a component can range from 0 to 1, and the sum of the mole fractions of all components in a mixture is always equal to 1.

First, we need to calculate the mole fractions of each gas component:
The mole fraction of NO2 = 0.300 (given)
The mole fraction of O2 = 0.330 (given)
The mole fraction of N2 = 0.368 (given)
The mole fraction of trace gases = 0.002 (calculated as 1 - sum of other mole fractions)
Next, we can calculate the partial pressures of each gas component:
The partial pressure of NO2 = 2.00 atm x 0.300 = 0.60 atm
The partial pressure of O2 = 2.00 atm x 0.330 = 0.66 atm
The partial pressure of N2 = 2.00 atm x 0.368 = 0.74 atm
Therefore, the partial pressures of NO2, O2, and N2 are 0.60 atm, 0.66 atm, and 0.74 atm, respectively.

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The dissociation reaction for the salt AB3 is:

AB3(s) ↔ A3+(aq) + 3B-(aq)

Let's assume the solubility of AB3 in water at 25 °C is x mol/L. Then, the equilibrium concentrations of A3+ and B- can be expressed as x and 3x, respectively.

The Ksp expression for AB3 is:

Ksp = [A3+][B-]^3 = x(3x)^3 = 27x^4

The molar mass of AB3 is 305 g/mol, so the number of moles in 4.30 g (the solubility) is:

n = 4.30 g / 305 g/mol = 0.0141 mol/L

Therefore, the solubility of AB3 at 25 °C is:

x = 0.0141 mol/L

Substituting this into the Ksp expression:

Ksp = 27x^4 = 27(0.0141)^4 = 5.6 x 10^-9

Therefore, the Ksp of AB3 at 25 °C is 5.6 x 10^-9.

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Answer:

640 grams

Explanation:

look up Solubility table in wikipedia for potassium nitrate (KNO3)

32 grams of potassium nitrate (KNO3) water solubility at 20 degrees celsius (room temperature) can be dissolved in 100 milliliters (0.1 L) of water.

2 liters = 2000 milliliters

32 grams / 100 milliliters = x grams / 2000 milliliters

cross-multiply

100 * x = 32 * 2000

x = (32 * 2000) / 100

x ≈ 640 grams

chatgpt

Answer:

water and a salt

Explanation:

Answer:

The correct answer to the following question will be "1.76 g/L".

Explanation:

The given values are:

P₁ = 15 kPa

Solubility of water, C₁ = 0.66 g/L

P₂ = 40.0 kPa

C₂ = ?

Now,

According to Henry's Law,

⇒  \(\frac{P_{1}}{P_{2}}=\frac{C_{1}}{C_{2}}\)

⇒  \(C_{2}=\frac{C_{1}\times P_{2}}{P_{1}}\)

On putting the estimated values, we get

⇒       \(=\frac{0.66\times 40}{15}\)

⇒       \(=\frac{26.4}{15}\)

⇒       \(=1.76 \ g/L\)

The specific heat capacity of a substance is the amount of energy required to raise the temperature of 1g of the substance by 1K.

Calculating the change in temperature:

By substituting what we are given into the equation to solve for the unknow x we have;

Answer: Energy needed is 449.35J

Answer:

I'm pretty sure the ionic structure is C, sorry this is only one answer tho : , (

Explanation:

Answer:

B. Dispose of pH paper in the trash.

C. Dump the cabbage indicator solution down the drain.

D. Ask your teacher to neutralize the acids and bases before disposal.

Explanation:

Safe disposal of waste means disposal of waste in such a way that it does not pose a threat to the environment.

When pH paper is properly disposed in the trash, it does not constitute any risk to the environment.

When a cabbage indicator solution is disposed down the drain it does not contaminate the environment. It moves directly into the sewers and is properly disposed.

When acids and bases are properly neutralized before disposal, they don't lead to acid or base contamination of the environment.

The balanced net reaction for the Sn (s) | SnCl2 (aq) || AlBr3 (aq) | Al (s) chemical cell is: 3Sn (s) + 2AlBr3 (aq) → 3SnBr2 (aq) + 2Al (s).

The given cell notation represents a redox reaction occurring in an electrochemical cell. The left half-cell consists of solid tin (Sn) in contact with an aqueous solution of tin(II) chloride (SnCl2). The right half-cell contains an aqueous solution of aluminum(III) bromide (AlBr3) and solid aluminum (Al).

To determine the balanced net reaction, we need to consider the transfer of electrons between the species involved. The oxidation half-reaction occurs at the anode, where tin (Sn) undergoes oxidation and loses electrons:

Sn (s) → Sn2+ (aq) + 2e-

The reduction half-reaction takes place at the cathode, where aluminum(III) bromide (AlBr3) is reduced and gains electrons:

2Al3+ (aq) + 6Br- (aq) → 2Al (s) + 3Br2 (aq) + 6e-

To balance the overall reaction, we need to multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2 to ensure that the number of electrons transferred is equal:

3Sn (s) → 3Sn2+ (aq) + 6e-

4Al3+ (aq) + 12Br- (aq) → 4Al (s) + 6Br2 (aq) + 12e-

By adding the balanced half-reactions together, we obtain the balanced net reaction for the cell:

3Sn (s) + 2AlBr3 (aq) → 3SnBr2 (aq) + 2Al (s)

To determine the cell potential, additional information such as the standard reduction potentials of the species and the Nernst equation would be required. Without this information, it is not possible to calculate the cell potential accurately.

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In Lei's experiment, one step of the procedure requires her to bring some water to a boil. Lei should use OC.a Bunsen burner and a balance.

Because it can operate with a variety of gases, has a single flame, and allows for adjustable heat output, the Bunsen burner is crucial in laboratories. Scientists utilize a variety of beakers in the lab. Scientists mix and track the responses of various compounds within them.

The following are three general safety guidelines when using a Bunsen burner: Never leave the lab with the burner on and never leave open flames unattended. Once the gas has been used up, turn it off. Before handling the burner, allow it to cool. Before leaving the lab, make sure the main gas valve is closed.

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Answer:The structure of solids can be described as if they were three-dimensional analogs of a piece of wallpaper. Wallpaper has a regular repeating design that extends from one edge to the other. Crystals have a similar repeating design, but in this case the design extends in three dimensions from one edge of the solid to the other.

We can unambiguously describe a piece of wallpaper by specifying the size, shape, and contents of the simplest repeating unit in the design. We can describe a three-dimensional crystal by specifying the size, shape, and contents of the simplest repeating unit and the way these repeating units stack to form the crystal.

The simplest repeating unit in a crystal is called a unit cell. Each unit cell is defined in terms of lattice points--the points in space about which the particles are free to vibrate in a crystal.

Answer:

Synthetic clothes can easily build up static electricity. It also easily can catch up on fire and when it does, it melts and can fuse to your skin.

Explanation:

Answer:

Explanation:

Synthetic fibres like Polyester catches fire very easily and melts. After melting It sticks to the body of the person wearing it causing severe burns. Hence it is advised not wear synthetic clothes while working in the Kitchen. Its advised to wear Apron or cotton clothes while cooking in Kitchen.

Answer: The correct option is C) 1.68 mol/L

Explanation:

Molarity is defined as the amount of solute expressed in the number of moles present per liter of solution. The units of molarity are mol/L. The formula used to calculate molarity:

\(\text{Molarity of solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (L)}}\) .....(1)

Given values:

Given mass of \(C_6H_{12}O_6\) = 150 g

Molar mass of \(C_6H_{12}O_6\) = 180 g/mol

Volume of the solution = 0.50 L

Putting values in equation 1, we get:

\(\text{Molarity of solution}=\frac{150}{180\times 0.50}\\\\\text{Molarity of solution}=1.68M\)

Hence, the correct option is C) 1.68 mol/L

Answer:

A and C

Explanation:

I think it's A and C but I could be wrong

Answer:

Explanation:

Here, we want to know when heat transfer takes place

Heat as a form of energy can flow from one point or end to another

The driving force for this flow is the temperature gradient

When there is a difference in temperature between 2 ends or points, heat will flow by any of the methods of heat transfer applicable

Answer: yes

Explanation: Petroleum solvents are hydrocarbon mixtures which can be grouped into three broad categories on the basis of their boiling ranges and solvent strengths, as follows: special boiling range solvents, boiling range, 30-160 oC; white spirits, 130-220 oC; and high-boiling aromatic solvents, 160-300 oC.

The molar concentration of a 12% sodium chloride solution is approximately 2.05 M.

To determine the molar concentration of a 12% sodium chloride solution, we need to convert the given percentage concentration into molarity.

First, we need to understand that the percentage concentration refers to the mass of the solute (sodium chloride) relative to the total mass of the solution.

In this case, a 12% sodium chloride solution means that there are 12 grams of sodium chloride in 100 grams of the solution.

To convert this into molar concentration, we need to consider the molar mass of sodium chloride, which is 58.5 g/mol.

We can start by calculating the number of moles of sodium chloride in 12 grams:

Moles of sodium chloride = mass of sodium chloride / molar mass of sodium chloride

Moles of sodium chloride = 12 g / 58.5 g/mol = 0.205 moles

Next, we calculate the volume of the solution in liters using the density of the solution. Since the density is not provided, we assume a density of 1 g/mL for simplicity:

Volume of solution = mass of solution / density

Volume of solution = 100 g / 1 g/mL = 100 mL = 0.1 L

Finally, we calculate the molar concentration (Molarity) by dividing the number of moles by the volume in liters:

Molar concentration = moles of solute / volume of solution

Molar concentration = 0.205 moles / 0.1 L = 2.05 M

Therefore, the molar concentration of a 12% sodium chloride solution is approximately 2.05 M.


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In the saline solution, sodium has a molarity of 0.154 M.

A saline solution is created by combining salt and water. The sodium content of blood and tears is similar to that of normal saline solution, which has a sodium chloride (salt) level of 0.9%. Normal saline is the name given to saline solution most often, but it can also be referred to as physiological or isotonic saline.

The saline solution is 0.9% NaCl, we can convert this to a mass concentration of 0.9 g

NaCl per 100 mL of solution

we need to first convert the mass of NaCl to moles

0.9 g NaCl / 58.44 g/mol = 0.0154 mol NaCl

100 mL/1000mL/L= 0.1 L

Molarity of Na+ in saline solution = 0.0154 mol / 0.1 L = 0.154 M

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The addition of ammonia increase the solubility of slightly soluble salt AgCl as : ammonia forms very soluble complex ion by coordinating to Ag and removing it from solution. This shifts the solubility equilibrium to right.

When ammonia (NH₃) is added to a solution containing AgCl, it can coordinate with silver ions (Ag+) to form a complex ion called [Ag(NH₃)₂]+, which is highly soluble in water. This complex ion removes the Ag+ ions from the solution, thereby decreasing the concentration of Ag+ in the solution. According to Le Chatelier's principle, this will shift the equilibrium of AgCl dissolution reaction to the right, resulting in increase in the solubility of AgCl.

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Answer:

C. 22 grams because mass cannot be created or destroyed

Explanation:

In this reaction and in any chemical reaction, mass is expected to always be conserved.

According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed but can be changed from one form to another".

Answer:

1. Crush the sugar into powder.

2. Heat the water.

3. Dissolve it by stirring continuously

Explanation:

1. Crushing the sugar into powder increases surface area. So it increases the changes of dissolving

2. Heating the water increases the capacity of water to dissolve sugar.

3. Stirring continuously increases randomness of particles so eases mixing up thus increasing dissolving tendency.

1.37 × 10⁻²¹ mol C

Math

Pre-Algebra

Order of Operations: BPEMDAS

Chemistry

Atomic Structure

Step 1: Define

825 atoms C

Step 2: Identify Conversions

Avogadro's Number

Step 3: Convert

\(\displaystyle 825 \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C} )\) = 1.36998 × 10⁻²¹ mol C

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.36998 × 10⁻²¹ mol C ≈ 1.37 × 10⁻²¹ mol C

Answer:

Cooper (||) nitrate

Explanation:

I got it right in edmentum

The chemical name of the compound Cu ( NO₃ ) ₂ copper ( II ) nitrate. Therefore, option C is correct.

Any member of the family of inorganic compounds with the formula  Cu ( NO₃ ) ₂ x is referred to as copper(II) nitrate. Blue solids make up the hydrates. At 150–200 °C, anhydrous copper nitrate sublimes into blue–green crystals. Hemipentahydrate and trihydrate are typical hydrates.

A bluish-green, tasteless, crystalline substance that resembles sand is cupric nitrate. It is employed in pyrotechnics, electronics, electroplating, textile dyeing, medicines, electroplating, insecticides, and light-sensitive materials.

Some pyrotechnics contain copper nitrates. Chemical voltaic cell reactions are frequently demonstrated using it in educational laboratories. It is an ingredient in various metal patinas and ceramic glazes.

Thus, option C is correct.

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BOD = (14.8 - DO2) x 0.125 = 211.3 mg/LDO2 = 12.175 mg/LHence, the Biochemical Oxygen Demand (BOD) of the sample is 13.825 mg/L.

The given terms in the question are,211.3 mg/ LQ.6: 100 ml waste water sample was diluted with 800 ml of water. Initial dissolved oxygen level (DO:) was found to be 14.8 mg/1. After 5 days of incubation, the final dissolved oxygen level (DO) was found.In order to calculate the Biochemical Oxygen Demand (BOD) of a sample, the difference between the initial dissolved oxygen level (DO:) and the final dissolved oxygen level (DO) needs to be found.The formula for Biochemical Oxygen Demand is:Biochemical Oxygen Demand (BOD) = (Initial Dissolved Oxygen level) - (Final Dissolved Oxygen Level)BOD = DO1 - DO2BOD = 14.8 - DO2BOD = 14.8 - DO2.

To determine the value of DO2, first the dilution factor needs to be found.Dilution Factor = Volume of initial sample / Total VolumeDilution Factor = 100 / 800Dilution Factor = 0.125Since the initial sample was diluted by a factor of 0.125, the BOD can be calculated as follows:BOD = (DO1 - DO2) x Dilution Factor211.3 mg/L is the value of LQ, which is the conversion factor to convert milligrams per liter of oxygen to BOD value.

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Answer:

i think 3 is the answer cuz i search it up