An Astronaut on the Moon drops a rock straight downward from a height of 1.25 meters. If the acceleration of gravity on the Moon is 1.62 meters per second squared, what is the speed of the rock just before it lands?

F - f = ma

The sum of forces on the x-axis = ma (since it is not stated that the forces are in equilibrium)

By resolving the Free Body

Simplifying the equation above, we have:

F - f = ma

The magnitude of the force exerted on this object is 1.2 Newton.

Given the following data:

In Science, the impulse that is experienced by an object is always equal to the change in momentum of the object, due to the force acting on an object.

Mathematically, impulse is given by this formula:

\(Impulse = change\;in\;momentum\\\\Force \times time = m \Delta V\)

Substituting the given parameters into the formula, we have:

\(Force \times 10=12\\\\Force =\frac{12}{10}\)

Force = 1.2 Newton.

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In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.

This relationship is described by the equation for the generated emf in a DC generator:

Emf = Φ * N * A * Z / 60

Where:

Emf is the generated electromotive force (in volts),

Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),

N is the number of turns in the armature winding,

A is the effective area of the armature coil (in square meters),

Z is the total number of armature conductors, and

60 is a constant representing the conversion from seconds to minutes.

From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.

The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.

The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.

Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.

By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.

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If a wave has an amplitude of 0.0800 m and is moving 7.33 m/s. The

wavelength of the wave is 1.69m.

The wavelength of a wave can be determined using the equation:

Wavelength = velocity / frequency

To determine the frequency we need to calculate the reciprocal of the time it takes for one complete oscillation.

frequency = 1 / time

frequency = 1 / 0.230

frequency ≈ 4.35 Hz

Substitute the values into the wavelength equation:

wavelength = velocity / frequency

wavelength = 7.33 / 4.35

wavelength ≈ 1.69m

Therefore the wavelength of the wave is approximately 1.69 meters.

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Answer:

Explanation:

2.5+*a*t= 14 m/s

2.5+ a*3 =14

a*3 =14-2.5

a = 11.5/3

a=3.8333  m/\(s^{2}\)

The size of the angle θ of a point object moving from point A to point B along a circular path is 2πR / L.

To understand this, consider a simple example. Suppose that a point object that moves from point A to point B along a circular path with a radius of 1 meter. The distance between points A and B is also 1 meter. Therefore, the size of the angle θ is equal to 2π × 1 / 1 = 2π radians.

In general, the size of the angle θ = ratio of the circumference of the circle to the distance between points A and B. The circumference of the circle is equal to 2πR, where R = radius of the circle. Therefore, the size of the angle θ is equal to 2πR / L.

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Complete question:

A point object moves from point A to point B along a circular path with a radius R. What is the size of the angle θ?

1. By Newton's second law,

F = m a

so the slope of the line would represent the mass of the object.

2. If all the forces are balanced, then the object is in equilibrium with zero net force, which in turn means the object is not accelerating. So the object is either motionless or moving at a constant speed.

Answer:

5. An object of mass m = 2 kg, moving with velocity Vi1 = 12 m/s, collides head-on with a stationary object whose mass is m2 = 6 kg. The velocities of the objects after the collision are vj1 -6 m/s and Vr2 = 6 m/s.

Explanation:

We can use the conservation of momentum and kinetic energy to solve for the final velocities of the two objects.

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and v1 are the mass and velocity of object 1 before the collision, and m2 and v2 are the mass and velocity of object 2 before the collision.

Plugging in the values:

(2 kg)(12 m/s) + (6 kg)(0 m/s) = (2 kg)(v1f) + (6 kg)(v2f)

Simplifying:

24 kg m/s = 2 kg v1f + 6 kg v2f

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

Plugging in the values:

(1/2)(2 kg)(12 m/s)^2 + (1/2)(6 kg)(0 m/s)^2 = (1/2)(2 kg)(v1f)^2 + (1/2)(6 kg)(v2f)^2

Simplifying:

144 J = 1 kg v1f^2 + 3 kg v2f^2

Now we have two equations with two unknowns (v1f and v2f). Solving for v1f in terms of v2f in the first equation:

v1f = (24 kg m/s - 6 kg v2f)/2 kg = 12 m/s - 3v2f

Plugging this into the second equation:

144 J = 1 kg (12 m/s - 3v2f)^2 + 3 kg v2f^2

Simplifying and solving for v2f:

144 J = 1 kg (144 m^2/s^2 - 72 v2f + 9 v2f^2) + 3 kg v2f^2

144 J = 144 J - 72 kg m/s v2f + 9 kg m^2/s^2 v2f^2 + 3 kg v2f^2

6 kg v2f^2 - 72 kg m/s v2f + 144 J = 0

Dividing by 6 kg:

v2f^2 - 12 kg m/s v2f + 24 J/kg = 0

Using the quadratic formula:

v2f = [12 kg m/s ± sqrt((12 kg m/s)^2 - 4(1)(24 J/kg))]/(2)

v2f = [12 kg m/s ± sqrt(96) m/s]/2

v2f = 6 kg m/s ± 2sqrt(6) m/s

v2f ≈ 9.90 m/s or v2f ≈ 2.10 m/s

Plugging these values into the equation we found for v1f:

v1f = 12 m/s - 3v2f

v1f ≈ -16.70 m/s or v1f ≈ 38.70 m/s

Since the negative velocity doesn't make physical sense, the final velocities of the two objects are:

v1f ≈ 38.70 m/s and v2f ≈ 2.10 m/s

Answer: 129.5 m

Explanation:

310 + 115 + 25 + 68 = 518

518 / 4 = 129.5 m

i think. Sorry if this is wrong

:)

Answer:

Energy in carriage (Potential energy) = 4,116 J

Explanation:

Given:

Mass of baby = 20 kg

Height = 21 m

Find:

Energy in carriage (Potential energy)

Computation:

The energy accumulated in an object as a result of its location relative to a neutral level is known as potential energy.

In carriage accumulated energy is potential energy.

Energy in carriage (Potential energy) = mgh

Energy in carriage (Potential energy) = (20)(9.8)(21)

Energy in carriage (Potential energy) = 4,116 J

Answer:

well in the pot there is conventional heat, the pot itself is giving off conductable heat, and the radiational heat is coming from the stove.

Answer:

the velocity of their combined weight after they collide is 0.39 m/s

Explanation:

From the information given, the kid and granny moved together after collision with a combined velocity. This means that the collision is inelastic. Given that momentum is conserved, for an inelastic collision, we would apply the formula;

m1u1 + m2u2 = (m1 + m2)V

where

m1 is the mass of the skateboard

v1 is the velocity of the skateboard

m2 is the mass of the granny

v2 is the velocity of the granny

V is the velocity of the combined weight

From the information given,

m1 = 13

u1 = 4

m2 = 120

u2 = 0(the granny was at rest)

By substituting these values into the formula, we have

13 x 4 + 120 x 0 = (13 + 120)V

52 = 133V

V = 52/133

V = 0.39 m/s

Explanation:

it will move to thr left?

The net force on the airplane window of area 1800 cm² is 3469.47 Pa.m² .

Given:

Pressure inside the cabin: 0.95 atm

Pressure outside the cabin: 0.76 atm

Area of the airplane window: 1800 cm²

Now to find the net force on the airplane window, we can calculate the pressure difference between the inside and outside of the cabin and to calculate the pressure difference, we subtract the outside pressure from the inside pressure.

Pressure Difference = Pressure inside - Pressure outside

Pressure Difference = 0.95 atm - 0.76 atm

Pressure Difference = 0.19 atm

The area of the airplane window is given as 1800 cm². To simplify calculations in SI unit we convert the area to square meters:

Area in m² = (Area in cm²) / 10,000

Area in m² = 1800 cm² / 10,000

Area in m² = 0.18 m²

As we know,

Net Force = Pressure Difference * Area

Net Force = 0.19 atm * 0.18 m²

Net Force = 0.0342 atm·m²

To convert the net force to pascals (Pa), we use 1 atm = 101325 Pa. Multiplying the net force by 101325 Pa, we get

Net Force = 3469.47 Pa·m²

Therefore, the net force on the airplane window is approximately 3469.47 pascals times square meters (Pa.m²).

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We have that the speed of the spaceship must be

\(V=2.47m/s\)

From the Question we are told that

Mass \(8.7*10^{17} kg\)

Positive charge of 4400 C

Spaceship mass m_s=3.3* 10^5 kg

Solar wind has given their spaceship a charge of -1.2 C.

Diameter d=8300-km-diameter

Generally the equation for the force of attraction   is mathematically given as

\(v^2=\frac{Gm}{r}+\frac{kQq}{rm}\\\\v^2=\frac{6.67*10^{-11}*8.7*10^{17}}{9.5*10^5}}+\frac{9*10^9*4400*-1.2}{9.5*10^5*3.3*10^{15}}\)

\(V=2.47m/s\)

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The speed will be "6.98 m/s". A complete solution is provided below.

The given values are:

Mass of asteroid,

Mass of spaceship,

Charge,

As we know,

→ \(F_G +F_E = \frac{mv^2}{R}\)

or,

→ \(\frac{GMm}{R_2} +\frac{kq_1 q_2}{R_2}=\frac{mv^2}{R}\)

By putting the given values, we get

→ \(\frac{6.67\times 10^{-11}\times 8.7\times 10^{17}\times 3.3\times 10^5}{\frac{8.3\times 10^6}{2} } +\frac{9\times 10^9\times 4400\times 1.2}{\frac{8.3\times 10^6}{2} } = 3.3\times 10^5\times v^2\)

→                                                                   \(v=6.98 \ m/s\)                                                                                                                                                      

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The magnitude of the force P provided that the stress in the part AB is two times that of BC part is 0.8 kN.

The magnitude of the force P provided that the stress in the part AB is two times that of BC part is calculated as follows;

Take moment about the joint to determine the magnitude of the force along part BC.

120 kN x 750 mm  =  F x 1000 mm

F = ( 120 kN x 750 mm ) / ( 1000 mm )

F = 90 kN

Stress is given as force divided by area. The following equation can be used to determine the magnitude of force P.

Stress in AB = 2 times stress in BC

P/A₁  = 2F/A₂

where;

A₁ =  πd²/4  =  π(50 x 10⁻³)²/4

A₁ = 1.96 x 10⁻⁵ m²

A₂ = πd²/4  =  π(75 x 10⁻³)²/4

A₂ = 4.42 x 10⁻³ m²

P/A₁ = 2F/A₂

P = (2F x A₁) / (A₂)

P = (2 x 90 kN x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = (2 x 90,000 N x 1.96 x 10⁻⁵ m² ) / ( 4.42 x 10⁻³ m² )

P = 798.2 N

P = 0.798 kN

P ≈ 0.8 kN

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Answer:

B. 36 lb

Explanation:

m = 160/9.8 = 16.3 kg

16.3 kg ( 2.205 lb/kg) = 36 lb

Answer:

A. Brain patterns

Explanation:

Got it right on the quiz.

Answer:

Brain Patterns

Explanation:

This was correct

The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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(a) The amplitude of the wave is 0.2 m.

(b) The period of the wave is  4 s.

(c) The wavelength of the wave is 100 m.

(a) The amplitude of the wave is the maximum displacement of the wave.

amplitude of the wave = 0.2 m

(b) The period of the wave is the time taken for the wave to make one complete cycle.

period of the wave = 5.5 s - 1.5 s = 4 s

(c) The wavelength of the wave is calculated as follows;

λ = v / f

where;

f = 1/t = 1 / 4s = 0.25 Hz

λ = ( 25 m/s ) / 0.25 Hz

λ = 100 m

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Answer:The net force causing the acceleration is

F = ma = 39.5 * 0.521 = 20.58N

So now you can get how much was used to overcome the opposing force of the friction.

Explanation:

Answer:

Distance: 21km

Displacement: ~16.76km

Answer:

D

Explanation:

D is the most likely answer because as we become more modernized as a whole we will progressively need to fill more positions in support specialty fields.

The boat must have moved, despite not being seen to move, because its relative position to the dock has changed. This phenomenon is known as relative motion .

Everything is always in motion, but the way we perceive it depends on our frame of reference.

In this scenario, the dock was the frame of reference for the initial position of the boat. When the boat moved to the cove, its position relative to the dock changed, and the dock was no longer an appropriate frame of reference. The boat's motion is now relative to the cove instead.

It is important to note that relative motion depends on the chosen frame of reference. If we were to choose the boat as the frame of reference, then it would be the dock that appears to move, not the boat. This is because motion is always relative to a chosen frame of reference.

In conclusion, the boat must have moved because its position relative to the dock changed. The concept of relative motion reminds us that motion is always relative to a chosen frame of reference, and that the way we perceive motion depends on our chosen frame of reference.

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Cancer cells are cells that divide relentlessly, forming solid tumors or flooding the blood with abnormal cells. Cell division is a normal process used by the body for growth and repair.

The primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

A primary difference between an electromagnetic wave and a mechanical wave is the medium through which they propagate.

Electromagnetic waves can propagate through a vacuum or empty space without requiring a material medium. They are generated by the oscillation and interaction of electric and magnetic fields.

Examples of electromagnetic waves include radio waves, microwaves, infrared, visible light, ultraviolet, X-rays, and gamma rays. These waves can travel through space, air, or other materials, as they do not rely on physical particles to transmit energy.

On the other hand, mechanical waves require a physical medium to propagate. They are disturbances that travel through a material medium, transferring energy from one location to another. Mechanical waves rely on the interaction and displacement of particles within the medium to transmit energy.

Examples of mechanical waves include sound waves, water waves, seismic waves, and waves on a string. These waves cannot travel through a vacuum as they depend on the physical presence and interaction of particles within the medium.

In summary, the primary difference is that electromagnetic waves can propagate through a vacuum or empty space, while mechanical waves require a physical medium to transmit energy.

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Given,

Light passes from material A, which has an index of refraction of 4/3 into material B, which has an index of refraction of 5/4.

To find: Find the ratio of the speed of light in material B to the speed of light in material A.

Solution:

The refractive index is inversely proportional to the speed of the light in the material.

Thus, the ratio of the speed of light in the material B to the speed of light in material A is

The diameter of a copper conductor is equal to 21.30 meters.

Given the following data:

To calculate the diameter of a copper conductor:

First of all, we would determine the resistance of the copper conductor by using the formula:

\(Resistance = \frac{Voltage }{Current} \\\\Resistance =\frac{8}{500}\)

Resistance = 0.016 Ohms

Next, we would determine the area of the copper conductor:

\(Resistance = \frac{\rho l}{Area} \\\\Area = \frac{\rho l}{Resistance}\\\\Area = \frac{0.019 \times 300}{0.016}\)

Area = 356.25 \(m^2\)

For the diameter:

From the area of a circle, diameter is given by the formula:

\(Area = \frac{\pi d^2}{4} \\\\d=\sqrt{\frac{4A}{\pi} } \\\\d=\sqrt{\frac{4 \times 356.25}{3.142} }\\\\d=\sqrt{453.53}\)

Diameter, d = 21.30 meters

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Answer:

kinetic energy = 0.1168 J

Explanation:

From Hooke's law, we know that ;

F = kx

k = F/x

We are given ;

Mass; m = 1.95 kg

Spring stretch; d = x = 0.0865

So, Force = mg = 1.95 × 9.81

k = 1.95 × 9.81/0.0865 = 221.15 N/m

Now, initial energy is;

E1 = mgL + ½k(x - L)²

Also, final energy; E2 = ½kx² + ½mv²

From conservation of energy, E1 = E2

Thus;

mgL + ½k(x - L)² = ½kx² + ½mv²

Making the kinetic energy ½mv² the subject, we have;

½mv² = mgL + ½k(x - L)² - ½kx²

We are given L=0.0325 m

Plugging other relevant values, we have ;

½mv² = (1.95 × 9.81 × 0.0325) + (½ × 221.15(0.0865 - 0.0325)² - ½(221.15 × 0.0865²)

½mv² = 0.62170875 + 0.3224367 - 0.82734979375

½mv² = 0.1168 J

The acceleration of the car when Vₓ = 16.7 m/s  is 8.05 m/s² .

In the question ,

it is given that ,

east ward component of the the car's velocity is Vₓ(t) = (0.970 m/s³)t²

To find the acceleration of the car, we differentiate velocity with respect to t ,

We get ,

aₓ = dVₓ/dt = d/dt (0.97 m/s³)t²

aₓ = (2 × 0.97 m/s³)t

aₓ = (1.94 m/s³)t    ...equation(1)

given that Vₓ = 16.7 m/s .

So , 16.7 = (0.97 m/s³)t²

t² = 16.7/0.97

t = 4.15 sec .

Substituting, time t = 4.15 in the  equation(1) , we get

aₓ = 1.94 × 4.15

= 8.05 m/s²

Therefore , the requires acceleration is 8.05 m/s²  .

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