Answer:
a). whenever the ball is at it's highest on either side (it stops, so kinetic energy is 0)
b). whenever the ball is at the bottom (A) - it cannot go lower, so potential energy is 0.
c). whenever the ball accelerates, so when it's going down from either side before reaching A (at that point it's going up and thus slowing down).
d). whenever the ball is ascending, so when it's goind up from A to either side
Explanation:
Kinetic energy is based on velocity
\(E_K = \frac{mv^2}{2}\)
mass is constant, so we need to find a point where v = 0 to solve a), and points where v is increasing to solve b).
Potential energy is based on height vs "the bottom" (here, the minimum altitude is "the bottom").
\(E_P = mgh\)
mass and gravitational acceleration are constant, so we need to find a point where h = 0 to solve b) and the points where h is increasing to solve d).
A thin wire was wound 30 times closely over a boiling tube .The total length of the windings was found to be 9.3 mm .Calculate the radius of the wire?
The radius of the wire is 0.0156 mm.
Radius of a wireTo calculate the radius of the wire, we need to use the following formula:
Total length of wire = (2 x π x r) x number of turns
where r is the radius of the wire.
Substituting the given values, we have:
9.3 mm = (2 x π x r) x 30r = 9.3 mm / (2 x π x 30) = 0.0156 mmTherefore, the radius of the wire is 0.0156 mm.
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Order these space notes in the bass clef from highest space to lowest space?
1) E
2)C
3)A
4)G
Answer:
g e c a
Explanation:
Hope I helped!
which is a form of potential energy
As a speaker, I should know my purpose and method of delivery before giving my speech so...
Explanation:
I will prepare my speech first and then I will give a speech on it.
What is the acceleration of the car between 2 and 5 seconds? hint: acceleration is a change in speed and direction! 15 m/s2 15 m/s 2 0 m/s2 0 m/s 2 5 m/s2 5 m/s 2 30 m/s2
The acceleration of the car between 2 and 5 seconds is 0m/\(s^{2}\).
How can the velocity time graph be used to determine the acceleration?
Calculating acceleration involves dividing the change in velocity, expressed in meters per second, by the time required for the change, expressed in seconds. The acceleration is measured in m/\(s^{2}\).
As we are aware, velocity = distance / time.
And acceleration = velocity / time.
The linear graph shows that the distance travelled at the time interval of 2 seconds is 10 m. Hence the velocity(\(v_{1}\)) =10/2 = 5m/s.
The graph shows that the distance travelled is 25 m at time interval of 5 seconds. Hence the velocity (\(v_{2}\)) =25/5 = 5m/s.
Acceleration between 2 and 5 seconds is now calculated as
(\(v_{1}\)-\(v_{2}\)) / (\(t_{2}\)-\(t_{1}\)) = (5-5)/(5-2) = 0 m/\(s^{2}\)
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some time later, kid a was spinning with the same speed that kid c had originally. what would kid a's centripetal acceleration be if his distance from the center of the merry-go-round was r
Centripetal refers to “center-seeking” Quantifies the change in directionof the velocity The acceleration is directed toward the center of the circle of motion.
The magnitude of the centripetal acceleration is given by V^2/r, the direction is toward the center of the circle. The tangential component of the acceleration is due to changing speed. The centripetal component of the acceleration is due to changing direction.
When an object is rotating at a constant angular velocity, the whole object has a constant angular velocity. Therefore, every mint on the turntable has the same, constant angular velocity.
The acceleration which causes the tangential velocity to change direction is called Centripetal acceleration. Centripetal acceleration is always in toward the center of the circle.
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The moon completes one (circular) orbit of the earth in 23.7 days. The distance from the earth to the moon is 3.84×10^8m. Calculate the centripetal acceleration.
Given that distance of moon from the earth is, R= 3.84 x 10^8 m
Also, time taken to complete one revolution is, T= 23.7 days = 2047680 seconds
Mass of the moon is, m= 7.347 Kg
To find the centripetal acceleration,
\(a_c=\frac{m4\pi^2R}{T}\)Substituting the values, we get
\(undefined\)Three small masses are positioned as follows: 12.0 kg at (0.0 m, 0.0 m), 8.0 kg at (2.0 m, 0.0 m), and 4.0 kg at (2.0 m, 3.0 m). determine the coordinates of the center of mass (or center of gravity) of this system.
The coordinates of the center of mass (or center of gravity) of this system at co-ordinate (x,y) = (-3.0 m,-6.0 m), as shown below, so that the center of mass of the 3 mass system is at the origin.
Let Xc and Yc, be the co-ordinates of the center of mass of the system.
Then from the problem statement (that center of mass is at origin), Xc=Yc=0.
Now, Xc can be found by taking moments of all the masses about the y-axis as
Xc= (Sum of moments of all individual masses about the Y-axis)/(Total mass of the system)
Thus, Xc=(3*0+4*x+1*12)/(3+4+1)=(0+4x+12)/8=(4x+12)/8
But Xc=0
Hence, (4x+12)/8=0
or 4x+12=0 => 4x=-12 => x=-3
Similarly, Yc can be found by taking moments of all the masses about the x-axis
Yc=(Sum of moments of all individual masses about the X-axis)/(Total mass of the system)
Thus, Yc=(3*8+4*y+1*0)/(3+4+1)=(24+4y+0)/8
But Yc=0
Hence, (24+4y)/8=0
or 4y+24=0 => 4y=-24 => y=-6
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which of the following statements about stars is true?; if the sun is white-yellow, which of the following is a reasonable approximation of its temperature?; immediately above the sun's photosphere is the _______, which is the sun's lower atmosphere.; which of the following statements about the sun is true?; which of the following lists stars in order of increasing size?; betelgeuse star
From around 6500 K at the bottom to 4000 K at the top, the photosphere's temperature changes (11,000 and 6700 degrees F, 6200 and 3700 degrees C). Granulation covers a large portion of the photosphere.
The results of these many techniques indicate that the Sun's surface actually has a temperature of about 5,800 kelvin (9,980 degrees Fahrenheit [5,520 degrees Celsius]). The photosphere contains areas of darkness known as sunspots, where the temperature is comparatively lower—about 3800K. The photosphere is therefore the layer that is the coldest. It is 15 million K inside the sun (27 million degrees Fahrenheit). It is 5780 K at the surface (9900 degrees Fahrenheit).
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Need help ASAP
Thanks+ BRAINLIST only for correct answers it’s due in 10 mins I really need help
1.what is the order if visible light in increasing energy?
-violet, indigo, blue, green, yellow, orange, red
-red, orange, yellow, green, blue, indigo, violet
2.visible light is a mixture of
-refraction and reflection
-atoms and molecules
-many colors
-ultra violet and non violet rays
Explanation:
1A. The visible light portion of the electromagnetic spectrum shows the rainbow of colors, with violet and blue having shorter wavelengths, and therefore higher energy. At the other end of the spectrum toward red, the wavelengths are longer and have lower energy.
so its option 2
2A. Atom and molecules
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a mineral that can be cut, polished, and sold for profit is a gemstone. t/f
The given statement "a mineral that can be cut, polished, and sold for profit is a gemstone." is True because a mineral that can be cut, polished, and sold for profit is commonly referred to as a gemstone.
Gemstones are minerals or rocks that possess desirable qualities such as beauty, rarity, and durability. They are valued for their aesthetic appeal and are often used in jewelry and decorative purposes.
Gemstones are typically cut and polished to enhance their appearance and maximize their beauty. The cutting and polishing processes involve shaping the raw mineral into facets, giving it a desired shape, and creating smooth surfaces that reflect light to showcase its brilliance and color.
The value of gemstones can vary widely depending on factors such as the type of gemstone, its quality, size, color, and rarity. Precious gemstones like diamonds, rubies, emeralds, and sapphires are highly sought after and can command high prices in the market.
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suppose the interference pattern shown in the figure below is produced by monochromatic light passing through a diffraction grating, that has 260 lines/mm, and onto a screen 1.60 m away. what is the wavelength of light if the distance between the dashed lines is 155 cm?
To solve this problem, we can use the formula for the spacing between interference maxima on a diffraction grating:
d sinθ = mλ
where d is the spacing between adjacent lines on the grating, θ is the angle between the incident light and the normal to the grating, m is the order of the interference maximum, and λ is the wavelength of the light.
In this case, we are given the value of d (260 lines/mm), the distance to the screen (1.60 m), and the distance between the dashed lines on the interference pattern (155 cm). We can use these values to find the angle θ:
tanθ = (155 cm) / (1.60 m) = 0.96875
θ = tan⁻¹(0.96875) = 43.11°
Next, we can use the equation above to solve for λ:
d sinθ = mλ
(260 lines/mm) * sin(43.11°) = mλ
(260 * 10⁶ lines/m) * sin(43.11°) = mλ
λ = (260 * 10⁶ lines/m) * sin(43.11°) / m
To find the value of m, we can count the number of interference maxima between the dashed lines on the pattern. Let's say there are 10 maxima. Then:
m = 10λ = (260 * 10⁶ lines/m) * sin(43.11°) / 10
λ = 5.90 * 10⁻⁷ m = 590 nm
Therefore, the wavelength of the monochromatic light passing through the diffraction grating is 590 nm.
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2. What is the potential energy of a 3 kg ball that is on the ground?
The potential energy of a 3 kg ball that is on the ground is zero.
What is the potential energy of a ball on the ground?Zero ,It will have no kinetic energy since it is not moving, and because it is laying on the ground, it will also have no potential energy. This is equivalent to the ground's zero potential energy.energy potential = massHeight, 9.8 m/s of gravity3 kilogrammes is the size of you. I think you need to increase this by 9.8 and then convert this to grammes (3000g). Since the ball is on the ground and you are at zero height, your potential energy is also zero.A 3 kilogramme body on a planet's surface has 54 joules of potential energy.To learn more about potential energy refer to:
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I need helpppp :((((((
Answer: c. The electric force increases
Explanation:
If the distance between two charged particles decreases, the electric force between them increases.
According to Coulomb's Law, the electric force between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. Mathematically, the equation can be represented as:
F = k * (q1 * q2) / r^2
Where:
F represents the electric force between the particles.
k is the electrostatic constant.
q1 and q2 are the charges of the particles.
r is the distance between the particles.
As the distance (r) between the particles decreases, the denominator of the equation (r^2) becomes smaller, causing the overall electric force (F) to increase. Conversely, if the distance between the charged particles increases, the electric force between them decreases. This inverse relationship between the distance and electric force is a fundamental characteristic of the electrostatic interaction between charged objects.
The specific heat capacity of aluminium block is 9130 per kg per °C and its
temperature is increased by 10 °C. 4565 J of energy is transferred. Calculate the
mass of the aluminium block.
Answer:
Q
Explanation: you don't need to convert °°C to K Temperature difference is the same on both scales
Seventh grade QQ.4 Commas with coordinate adjectives 5L5
Insert one comma to separate the coordinate adjectives.
Typical golf caddie responsibilities include carrying clubs, cleaning balls,
calculating distances and scores, and even replacing the divots-pieces of
grass and dirt that have been cut loose by the swift forceful strikes of golf
clubs.
Answer:
Typical golf caddie responsibilities include carrying clubs, cleaning balls,
calculating distances and scores, and even replacing the divots - pieces of
grass and dirt that have been cut loose by the swift, forceful strikes of golf
clubs.
is atmosphere pressure at high altitudes is less than the pressure at ground, true or false
Answer:
The answer is true I guess!!!
This is because the more you go up to less air it is and the pressure also gets less!!!!!!!!
Explanation:
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A driver speeds along a curved road and sees a fallen tree on the road. He applies the brakes but is unable to stop in time. When the car hits the tree, it slows down from 6 meters/second to 0 meters/second. What was the change in velocity during this time?
Answer:
It's -6 meters/seconds.
Explanation:
Answer:
-6
Explanation:
A generator is operating with 5% droop primary control. The generator is rated for 100 kW. Its secondary power command at this point in time (in other words, the power commanded to produce at 60 Hz) is 67 kW. The grid frequency is currently 59.9 Hz. What is the generator power
The generator power will be 59 kW. Power drop is the main factor for finding the generated power.
What is the power rating?The maximum power input allowed to pass through a piece of equipment is known as the equipment's power rating.
Power drop = 5%
The relation of the frequency change with the power drop is;
\(\rm \frac{df}{dp} =5\%\\\\ \frac{f_{rated-f_1}}{P_{rated}-P_1}=0.05\\\\ \frac{f_{rated-60}}{100-61}=0.05\\\\ f_{rated}=61.95\)
For the grid frequency, 59.9 Hz
\(\rm \frac{f_{rated-f_2}}{P_{rated}-P_2}=0.05\)
\(\rm \frac{61.95-f_2}}{100-P_2} =0.05\\\\ 100-P_2 =20(61.95-59.9)\\\\P_2=100-41 \\\\ P_2=59 \ kW\)
Hence, the generator power will be 59 kW.
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What happens to the freezing point when a nonvolatile solute is added to a pure solvent?
Every time a non-volatile solute is added to a pure solvent, a solution's vapour pressure decreases.
What is nonvolatile solute in a solvent?A nonvolatile solute is a material that is difficult to evaporate. Additionally, when dissolved in the solvent, it does not raise its vapor pressure of a solution. Nonvolatile liquids have a high melting point and a low vapor pressure as traits.
Is sugar an inert solute?Volatile substances are ethanol and pentane, while nonvolatile ones include sodium chloride and sugar. As comparison to a vapor pressure of the pure solvent, the presence of a solute results in a colloquial property known as the "reduction of a vapor pressure of the solution."
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a 900 kg car driving 20 m/s collides with a 1,100 kg truck going 15 m/s. The vehicle bounce off each other and the car moves back 18 m/s. Whats the velocity of the truck after the collision?
Answer: The velocity of the truck after the collision is 18.2 m/s.
Explanation:
Step 1: Determine the total momentum of the two vehicles before the collision.
Momentum is equal to mass multiplied by velocity (p = mv). The momentum of the car before the collision was 900 kg x 20 m/s = 18,000 kg m/s. The momentum of the truck before the collision was 1,100 kg x 15 m/s = 16,500 kg m/s. The total momentum of the two vehicles before the collision was 34,500 kg m/s.
Step 2: Determine the total momentum of the two vehicles after the collision.
After the collision, the car moves back 18 m/s so the momentum of the car is now 900 kg x (-18 m/s) = -16,200 kg m/s. The momentum of the truck after the collision is not given, so we will use the letter "v" to represent this. The total momentum of the two vehicles after the collision is then -16,200 kg m/s + (1,100 kg x v).
Step 3: Use the law of conservation of momentum to solve for the velocity of the truck.
The law of conservation of momentum states that the total momentum of two objects before a collision is equal to the total momentum of two objects after the collision. This means that 34,500 kg m/s = -16,200 kg m/s + (1,100 kg x v), or 34,500 kg m/s = -16,200 kg m/s + 1,100v. Since we know all of the values on the right side of the equation, we can solve for v by rearranging the equation. We get v = (34,500 kg m/s + 16,200 kg m/s) / 1,100 kg = 18.2 m/s.
Therefore, the Step 1: Determine the total momentum of the two vehicles before the collision.
Momentum is equal to mass multiplied by velocity (p = mv). The momentum of the car before the collision was 900 kg x 20 m/s = 18,000 kg m/s. The momentum of the truck before the collision was 1,100 kg x 15 m/s = 16,500 kg m/s. The total momentum of the two vehicles before the collision was 34,500 kg m/s.
Step 2: Determine the total momentum of the two vehicles after the collision.
After the collision, the car moves back 18 m/s so the momentum of the car is now 900 kg x (-18 m/s) = -16,200 kg m/s. The momentum of the truck after the collision is not given, so we will use the letter "v" to represent this. The total momentum of the two vehicles after the collision is then -16,200 kg m/s + (1,100 kg x v).
Step 3: Use the law of conservation of momentum to solve for the velocity of the truck.
The law of conservation of momentum states that the total momentum of two objects before a collision is equal to the total momentum of two objects after the collision. This means that 34,500 kg m/s = -16,200 kg m/s + (1,100 kg x v), or 34,500 kg m/s = -16,200 kg m/s + 1,100v. Since we know all of the values on the right side of the equation, we can solve for v by rearranging the equation. We get v = (34,500 kg m/s + 16,200 kg m/s) / 1,100 kg = 18.2 m/s.
Therefore, the velocity of the truck after the collision is 18.2 m/s.
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Approximate how many times greater Saturn's mass is than Mercury's.
Mass of the saturn = 5.683 × 10^26 Mass of the mercury = 3.285 × 10^23
Answer:
Planet Mass (in kilograms)
Saturn 5.685 · 1026
Planet Mass (in milligrams)
Saturn 5.685 · 1032
Explanation:
Why the car floated before it started to sink? Explain.
a spring whose equilibrium length is 6 m is compressed to a length of 1/2 m when a force of 15 n is applied. find the work done by the spring force while it is compressed to a length of 5 m.
A spring whose equilibrium length is 6 m is compressed to a length of 1/2 m when a force of 15 n is applied. 187.5 mJ is the work done by the spring force while it is compressed to a length of 5 m.
compression in spring x = 5m.
spring constant = 15 n/m
Magnitude of work done = Potential energy stored in spring W = 1/2 kx²
= 1/2 × 15 × 5 × 5
= 187.5 mJ
The spring's natural length is its length without any mass attached. We suppose that the spring obeys Hooke's law: if the spring's length is modified by an amount L from its natural length, the spring produces a force
Fs = kL,
where,
k is a positive quantity known as the spring constant.
F = -kx.
The spring constant is the proportional constant k. It is a measure of the stiffness of the spring. When a spring is stretched or compressed by an amount x from its equilibrium length, it produces a force F = -kx in the direction of its equilibrium position.
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(b) The cabin and passengers have a total mass of 800 kg. The vertical distance between
B and C is 50 m.
Calculate the increase of gravitational potential energy of the cabin and passengers when they
move from B to C.
energy =
Answer:
392 kJ
Explanation:
Given that,
The total mass of the cabin and the passengers = 800 kg
The vertical distance between B and C is 50 m.
We need to find the increase of gravitational potential energy of the cabin and passengers when they move from B to C. It can be given by the relation as follows :
\(E=mgh\\\\E=800\times 9.8\times 50\\\\E=392000\ J\\\\\text{or}\\\\E=392\ kJ\)
So, the increase in gravitational potential energy is 392 kJ.
A kid does 308J of work on a sled. She walks 12m up hill. What is her force exerted on sled?
To determine the force exerted by the kid on the sled, we can use the formula:Work = Force × Distance .
Given that the work done by the kid is 308J and she walks a distance of 12m uphill, we can rearrange the formula to solve for force:Force = Work / DistanceSubstituting the given values:Force = 308J / 12m = 25.67N (rounded to two decimal places)Therefore, the force exerted by the kid on the sled is approximately 25.67 Newton. Work is defined as the product of force and distance. In this case, the work done by the kid on the sled is given as 308J, and the distance she walks uphill is 12m. By rearranging the formula for work, we can find the force exerted on the sled. Dividing the work (308J) by the distance (12m) gives us the force of approximately 25.67N. This means that the kid exerted a force of 25.67 Newtons on the sled while walking uphill.
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Pls help me with this thing.
Will mark brainliest!!!
Why is it that an object can accelerate while
traveling at constant speed, but not at constant velocity?
For the same reason that you can skate around a curve at constant speed but not with constant velocity.
The DIRECTION you're going is part of your velocity, but it's not part of your speed.
If the DIRECTION changes, that's a change of velocity.
The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.
And any change of velocity is called acceleration.
Question 2 (2 points)
Energy Equation is a way to assess your body size by taking your height and weight into account.
Question 2 options:
True
False
The energy equation is a way used to assess the body size by taking the height and weight into account. Thus, the given statement is true.
What is Energy equation?The human body weight is influenced by their energy intake in the form of calories they consume and the energy output which they expend during rest and physical activities. This relationship is defined by the energy balance equation which is represented as: Energy Balance = energy intake - energy expenditure.
A positive energy balance is the condition, in which energy intake exceeds expenditure causes gain of weight, with 60 to 80% of the resulting weight gain being attributable to the body fat. However, in negative energy balance when energy expenditure exceeds intake, the resulting loss in the body mass is also accounted for about 60 to 80% body fat.
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If an astronaut weighs 148 N on the Moon and 893 N on Earth,
then what is his mass on Earth?
Answer:
91 kg
Explanation:
F = m a
893 = m *9.81 m/s^2
91 kg
If an astronaut weighs 148 N on the Moon and 893 N on Earth, his terrestrial mass is 91 kg
What is mass?The mass of a physical body is the total amount of matter in it. This term also refers to the resistance of the body to acceleration when a net force is applied. The mass of an object influences its gravitational pull on other bodies. The SI base mass unit is the kilogram. Mass is a quantitative measure of inertia in physics, which is a fundamental property of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force. The terms "mass" and "weight" are frequently used interchangeably, but they have very different meanings.Therefore,
F = m a
893 = m × 9.81 m/s^2
91 kg
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