At what time t2 will the water be completely frozen so the temperature can begin to fall below 0∘C ?
Express your answer numerically in seconds.

During an earthquake, it is important to take appropriate steps to ensure safety

(i) When you are in the classroom

Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.

Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.

Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.

(ii) When you are out of danger:

Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.

Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.

Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.

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Answer:

The resistance of the unknown resistor is 5.75 Ω

Explanation:

We have a circuit containing two resistors connected in parallel.

One resistor is 13 Ω and the other resistor's resistance is unknown.

Both resistors are connected in parallel to an emf source of 23 V.

The current through the unknown resistor is measured with an ammeter to be 4 A.

Recall that in a parallel circuit the voltage across resistors remains the same but the current flowing through them is different.

So it means that the voltage across the unknown resistor is 23 V.

Since we already know the current flowing through the unknown resistor then using the Ohm's law

\(V = IR \\\\R = V/I \\\\R = 23/4 \\\\R = 5.75 \: \Omega \\\\\)

Therefore, the resistance of the unknown resistor is 5.75 Ω

Answer:

gamma

Explanation:

x rays are often used in hospitals

gamma rays :

are highly penetrating

have highly energetic ionizing radiation

frequency is higher

wavelengths are shorter rays

can attack DNA and break the strands of that essential biological molecule

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Answer:

The change in momentum of an object is equal to the impulse applied to it. Impulse is the product of force and time, or J = FΔt.

In this case, the force acting on the rocket is 500 N, and the time it is applied is 600 s, so the impulse is:

J = FΔt = (500 N) * (600 s) = 300000 Ns

The impulse applied to the rocket causes a change in momentum, which is given by the formula:

Δp = J

So the change in momentum of the rocket is 300000 Ns.

We know, \(1\ rpm = \dfrac{2\pi}{60} \ rad/s\) .

\(64\ rpm\ is = \dfrac{2\pi}{60}\times 64\ rad/s\\\\= \dfrac{32\pi}{15}\ rad/s\)

We know, kinetic energy is given by :

\(K.E = \dfrac{I\omega^2}{2}\\\\I = \dfrac{2(K.E)}{\omega^2}\\\\I = \dfrac{2\times 10^6}{\dfrac{32}{15}\times \pi}\\\\I = 298415.52 \ kg \ m^2\)

Hence, this is the required solution.

Answer:

Significant figures have a few rules about 0s and you should research but simply, for example say round 27.879 to 3 significant figures you round up until you have 3 numbers that aren't 0s so it would be 27.9.

SI units are the international system of units.

Answer:

SI units refer to the International System of Units. These are the standard units that measurements are typically given in. For example, the SI unit for time is seconds, meters for distance, kg for mass, etc.

Significant figures are the number of notable digits given for a measurement. For example, let's say you measured a piece of metal to be exactly 3.00 meters long. The value 3.00 has three significant figures, where as 3 only has one significant figure. Larger amounts of significant figures indicate a more precise measurement. In this case, by writing 3.00 instead of 3, you're telling me that you measured that piece of metal to be precisely 3.00 meters long.

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer:

in what experements

Explanation:

The following is how Kirchhoff's voltage law is used to analyze a circuit, Assume the circuit's current will flow in a certain direction. (The right path is preferred but not required.) Assign voltage polarities to all resistors that the current passes through using the direction of the current as a guide.

Therefore, on conclusion we can said as, Kirchhoff's Voltage Law (KVL), is concerned with energy conservation in a closed circuit channel. According to his voltage law, the algebraic total of all the voltages around any closed loop in a circuit is equal to zero for a closed loop series path.

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Answer:

The correct answer is option A: 3.00 × 10^(-11) m.

Explanation:

To find the wavelength of a gamma ray with a frequency of about 10^19 s^(-1), we can use the equation:

wavelength = speed of light / frequency

Given:

Speed of light (c) = 3.00 × 10^8 m/s

Frequency (f) = 10^19 s^(-1)

Substituting the values into the equation:

wavelength = (3.00 × 10^8 m/s) / (10^19 s^(-1))

To simplify the expression, we can rewrite the denominator as (1 / 10^(-19)) s:

wavelength = (3.00 × 10^8 m/s) / (1 / 10^(-19)) s

To divide by a fraction, we multiply by its reciprocal:

wavelength = (3.00 × 10^8 m/s) × (10^(-19) s)

Applying the properties of exponents, we can add the exponents when multiplying with the same base:

wavelength = 3.00 × 10^(-11) m

Therefore, the wavelength of the gamma ray is approximately 3.00 × 10^(-11) m.

Answer:

O Adenine and guanine

Explanation:

i think tell me if im rong

Guanine and cytosine are complementary base pairs for DNA, hence option B is correct.

Adenine and thymine are joined by two hydrogen bonds, whereas guanine and cytosine are joined by three hydrogen bonds.

Base pair of DNA. The nitrogen-containing bases adenine (A), thymine (T), and cytosine (C), as well as guanine (G), the couple together under normal conditions. The structure of DNA is created by the binding of these base pairs.

In order to construct the helical structure of DNA, complementary base pairing is crucial because it enables the base pairs to be placed in the most energetically advantageous manner.

Therefore, due to the fact that it permits semiconservative replication, it is also crucial in replication.

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Answer:

40 m/s

Explanation:

First, we need to calculate the velocity after 8 seconds, so we will use the following equation:

v₂ = v₁ + at

Where v₁ is the initial velocity, so v₁ = 0 m/s, a is the acceleration a = 3 m/s² and t is the time, so t = 8s. Replacing the values, we get:

v₂ = 0 m/s + (3 m/s²)(8s)

v₂ = 0 m/s + 24 m/s

v₂ = 24 m/s

Then, it accelerates for another 8 seconds with a = 2 m/s², so the acquired velocity v₃ is equal to:

v₃ = v₂ + at

v₃ = 24 m/s + (2 m/s²)(8 s)

v₃ = 24 m/s + 16 m/s

v₃ = 40 m/s

Therefore, the acquired velocity of the bike is 40 m/s

During a 10-second period, a car travels 80 meters. This car typically travels at a speed of 8 m/s.

For instance, if it takes a person 40 minutes to travel 20 miles north, 20 miles south, and finally 20 miles in between, their average speed is 40 miles divided by 40 minutes, or 1 mile per minute. Instead of distance, average velocity takes into account total displacement.

The total displacement must be divided by the total time elapsed in order to determine the average velocity.

average velocity= total displacement/ total time

avg velocity=80/10=8m/s

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In final state, every metal sphere carries 1 unit of negative charge.

Hence, In final state, every metal sphere carries 1 unit of negative charge.

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The ratio of the primary turns to the secondary turns is 1/3

The correct answer to the question is Option A. 1/3

From the question given above, the following data were obtained:

Ratio = Nₚ/Nᵣ

Nₚ/Nᵣ = 225 / 675

Nₚ/Nᵣ = 1/3

Therefore, the ratio of the primary turns to the secondary turns is 1/3

Complete question:

See attached photo

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Answer:

v' = -18 m/s

Explanation:

       \(p_{o} = p_{f} (1)\)

       \(m_{b} * v_{b} -M_{c}*V_{c} = m_{b} * 18 m/s + (-M_{c}* 20 m/s) (2)\)

        \(-(m_{b} * v'_{b}) + M_{c}*V'_{c} (3)\)

       \(-(m_{b} * v'_{b}) +(- M_{c}*V_{c}) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (4)\)

       \(m_{b} * 18 m/s + (-M_{c}* 20 m/s) = -(m_{b} * v'_{b}) + (-M_{c} * 20 m/s) (5)\)

Answer:d. 109N/C

Explanation: The atomic electric field, the field between the atomic nucleus and the surrounding electron cloud, should possess information about the atomic species, local chemical bonding, and charge redistributions between bonded atoms.

The interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

To determine the interval between the first and second echo, we need to consider the time it takes for sound to travel from the student to the first cliff, and then from the first cliff to the second cliff, and finally back to the student.

Let's break down the distances and calculate the time for each part of the journey:

Distance from the student to the first cliff: 330 meters

Time taken: t₁ = distance / speed = 330 m / 330 m/s = 1 second

Distance from the first cliff to the second cliff: 990 meters

Time taken: t₂ = distance / speed = 990 m / 330 m/s = 3 seconds

Distance from the second cliff back to the student: 990 meters

Time taken: t₃ = distance / speed = 990 m / 330 m/s = 3 seconds

Now, we can calculate the total interval between the first and second echo by adding up the individual times:

Interval between first and second echo = t₁ + t₂ + t₃ = 1 s + 3 s + 3 s = 7 seconds

Therefore, the interval between the first and second echo is 7 seconds. This means that after the initial sound wave reaches the first cliff, it takes a total of 7 seconds for the sound to travel to the second cliff and then return to the student as the second echo.

It's important to note that this calculation assumes a straight path for the sound waves and neglects factors such as air temperature and wind that can affect the speed of sound. Additionally, it assumes perfect reflection of sound waves off the cliffs, which may not be the case in real-world scenarios.

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Note the complete questions is:

A student stands 330m from a tall cliff which is 990m from another tall cliff. If the speed of sound between the cliffs is 330m/s.What is the interval between the first and second echo?

The potential energy of the roller coaster is 176,400 J (joules).

The potential energy of an object is given by the formula PE = mgh, where PE is the potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height or vertical position of the object.

In this case, the roller coaster is at a peak of 20m and has a mass of 900kg. The acceleration due to gravity, g, is approximately 9.8 \(m/s^2\).

Using the formula, we can calculate the potential energy:

PE = mgh

= (900 kg)(9.8 \(m/s^2\))(20 m)

= 176,400 J

Therefore, the potential energy of the roller coaster is 176,400 J (joules).

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Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

Answer:

Must include: 21

Explanation:

Answer:

=55.21 is the answer.........

The quarterback is getting hit with a force of 100 Newtons.

We can use Newton's second law of motion:

Force = Mass * Acceleration

Given that the mass of the defensive lineman is 100 kg and the acceleration is 1 m/s², we can substitute these values into the equation:

Force = 100 kg * 1 m/s²

Force = 100 N

Therefore, the quarterback is getting hit with a force of 100 Newtons.

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Answer:

Probeware and computer

Explanation:

Computers are more powerful and better than a graphing calculator for this situation.

are the tools he must use.

Answer:

R ≈ 15 ohms

Explanation:

Using ohm's law equation,

I = V/R, to solve for the resistance of the heating coil.

R = V/I

Known:

V = 220 v = 220 kgm^2s^-3A^-1

I = 15 A

Unknown:

R =?

Solution:

R = (220 kgm^2s^-3A^-1)/ 15.0 A

R = 14.6 kgm^2s^-3A^-2

R ≈ 15 kgm^2s^-3A^-2

R ≈ 15 ohms

Answer:

The angular speed of the blade is of 166.67 rad/min

If a radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm then the angular speed of the blade would be 104.72 rad/seconds.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object. The unit of speed is a meter/second. The generally considered unit for speed is a meter per second.

The mathematical expression for speed is given by

speed = total distance /Total time

As given in the problem If a radial saw has a blade with a 9-in. radius. Suppose that the blade spins at 1000 rpm then we have to find the angular speed of the blade,

the angular speed of the blade (ω) = 2πN/60

                                                          =2×π×1000/60

                                                          = 104.72 rad/seconds

Thus, the angular speed of the radial saw would be 104.72 rad/seconds

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Answer:

Explanation:

the distance have the following relation:

d = (1/2)gt2

D=32.0 m

t =√ (2D/g) = √(2*32.0m/9.8m/s2) = 2.56s

it take 2.56s from the glasses to hit the ground

when the glasses hit the ground, the pen only travel Δt =2.56s - 2.00s = 0.56s

x = (1/2)g(Δt)2 = 0.5*9.8m/s2*(0.56s)2 = 1.54 m

the pen only travel 1.54m

so the pen is above the ground 32.0m - 1.54m = 30.46m

The pen is 30.46m above the ground. when the glasses hit the ground. It is represented by x.

Height is a numerical representation of the distance between two objects or locations on the vertical axis.

The height can refer to a physical length or an estimate based on other factors in physics or common use. |

The given data in the problem is;

h is the height from the top of a stadium = 32.0 m

t is the time period when the pen is dropped later =  2.00 s

x is the height above the ground

a is the air resistance. a = -g = -9.81 m/s²

From the second equation of motion;

\(\rm H =ut+\frac{1}{2} gt^2 \\\\ \rm H =\frac{1}{2} gt^2 \\\\ \rm t = \sqrt{\frac{2H}{g} } \\\\ \rm t = \sqrt{\frac{2 \times32.0 }{9.81} } \\\\ \rm t =2.56\ sec\)

When the glasses fall to the ground, the pen only travels a short distance;

\(\rm \triangle t = 2.56 -2.00 \\\\ \rm \triangle t = 0.56 \ sec\)

So the pen travel the distance;

\(\rm h= \frac{1}{2} g \triangle t^2 \\\\ \rm h= \frac{1}{2} \times 9.81 (0.56)^2 \\\\ h=1.54 \ m\)

The pen above the ground is found as;

\(\rm x = H-h \\\\ \rm x = 32.0-1.54 \\\\ \rm x =30.46 \ m\)

Hence the pen is 30.46m above the ground. when the glasses hit the ground.

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Answer:

An electrical component that can disconnect or connect the conducting path in an electrical circuit.