-2/3y-3/4=5
What is the answer i need to show my work please

Answer:

6.5 or

Step-by-step explanation:

i believe thats the answer but im not the best with this

type of math so umm i tried  but i just added them simplified

Answer:

  (a)  10x^2−x−21

Step-by-step explanation:

The area of a rectangle is given by the formula ...

  A = LW . . . . . where L is the length, and W is the width

__

The area of the given rectangle will be ...

  A = (2x -3)(5x +7)

This product is simplified using the distributive property to eliminate parentheses. Then like terms are combined.

  A = 2x(5x +7) -3(5x +7)

  = (2x)(5x) +(2x)(7) -3(5x) -3(7)

  = 10x^2 +14x -15x -21

  A = 10x^2 -x -21

The expression 10x^2 -x -21 represents the area of the rectangle in square inches.

Answer:

To calculate how many packages Marcella has wrapped, you need to first calculate how many packages each roll of wrapping paper can be used for. Since Marcella uses 1/2 of a roll of wrapping paper for every 3 packages, it follows that she can wrap 3 packages for every 1/2 roll of wrapping paper. Therefore, 2 1/2 rolls of wrapping paper can be used to wrap 15 packages.

A rectangle's length is 5 inches greater than its width. if the perimeter of the rectangle is 42 inches, then the length is 13 inch.

A rectangle is a quadrilateral with four right angles. It can also be defined as: an equiangular quadrilateral, since equiangular means that all of its angles are equal; or a parallelogram containing a right angle. A rectangle with four sides of equal length is a square.

here, we have,

a rectangle's length is 5 inches greater than its width.

if the perimeter of the rectangle is 42 inches

let, width = x

then, length = x+5

so, perimeter= 2(x+5 +x)

                      = 4x+10

ATQ, 4x+10 = 42

solving we get,

x=8

the length = 13

Hence, A rectangle's length is 5 inches greater than its width. if the perimeter of the rectangle is 42 inches, then the length is 13 inch.

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Step-by-step:

2 | 3x + 1 | -4 = 6

2 | 3x + 1 | = 10

| 3x + 1 | = 5

| 3x + 1 | = ±5

Solve for both: 3x + 1 = -5 AND 3x + 1 = 5

3x + 1 = - 5

3x = - 6

x = -2

3x + 1 = 5

3x = 4

x = 4/3

x = -2, 4/3

Answer:

3

Step-by-step explanation

Answer:

The sum of the two numbers is 12.5

Step-by-step explanation:

First we write a system of equations.

One number is 4 times larger than the other.

y = 4x

The sum of their reciprocals is 1/2

1/x + 1/y = 1/2

Substitute

1/x + 1/4x = 1/2

1 + 1/4 = 1/2x

x = 2.5

Solve for other number

y = 4(2.5)

y = 10

The inverse of x is 2/5 or 4/10, and the inverse of y is 1/10. When added the sum is 5/10 or 1/2.

Answer:

The answer is D!! Trust me I have took this quiz and got it right.

Step-by-step explanation:

Have a good time on your test!

Answer:

The answer is B! trust me

Step-by-step explanation:

Answer:

Right isosceles

Step-by-step explanation:

AB = BC

∠ABC = 90°

An isosceles triangle with a right angle is known as an isosceles right triangle

Note: complementary angles are two angles whose sum is 90⁰

Answer:

52 degrees

Step-by-step explanation:

Complementary angles have a sum of 90. This means when added they will equal 90. So to solve had the 2 expressions and set them equal to 90.

This looks like, \((2x+18)+(6x-8)=90\). Then, isolate the variable and solve.

2x +18 +6x -8 =90

8x +10 =90

8x = 80

x=10

Finally, plug 10 in for x in the expression for angle b. This equals 52 degrees.

Answer:

-3

Step-by-step explanation:

-9u+9u is 0 so all you are left with is -3

Answer:

-3

Step-by-step explanation:

-9u + 9u - 3

-9u and 9u cancel out, so it simplifies to -3

Answer:

RQ = RS = 3

Step-by-step explanation:

Since RQ and RS are radii of the circle then they are congruent

let RQ and RS be x , then

Using Pythagoras' identity in right triangle QRS

x² + x² = (3\(\sqrt{2}\) )²

2x² = 18 ( divide both sides by 2 )

x² = 9 ( take the square root of both sides )

x = \(\sqrt{9}\) = 3

Thus RQ = RS = 3

Answer:

7 nickels

20 dimes

5 quarters

Step-by-step explanation:

n=nickels. d=dimes. q=quarters

n+d+q=32

0.05n+0.1d+0.25q=3.60

d=8+n+q

Solve for number of dimes:

d-8=8-8+n+q

d-8=n+q

d-d-8=n+q-d

-8=n+q-d

  32=n+q+d

-  (-8=n+q-d)

32 - (-8) = n-n + q-q + d-(-d)

32 + 8 = d + d

40 = 2d

d = 20  => simplify

20=8+n+q  ==> substitute 20 for d (d=8+n+q)

20-8 = 8-8+n+q

n+q = 12

0.05n+0.1(20)+0.25q=3.60  ==> substitute 20 for d

0.05n + 2 + 0.25q = 3.60

(0.05n + 2 + 0.25q = 3.60)*100 ->remove the decimals by multiplying by 100

5n + 200 + 25q = 360

5n + 200 - 200 + 25q = 360 - 200

5n + 25q = 160

Solve for number of quarters:

(5n + 25q)/5 = 160/5  ==> simplify the equation

  n + 5q = 32

- (n + q = 12)

n-n + 5q-q = 32-12

0 + 4q = 20

4q = 20

q = 5  ==> simplify

Solve for number of nickels:

n+20+5=32  ==> plug in 20 for d and 5 for q  (n+d+q=32)

n+25=32

n+25-25=32-25  ==> solve for n

n=7 ==> simplify

n=7: 7 nickels

d = 20: 20 dimes

q = 5: 5 quarters

The value of `new_list` will be [1, 4, 9, 16].  In the given code, a new list `new_list` is created using a list comprehension.

The list comprehension iterates over each element `i` in the original list `my_list` and computes the square of each element using the expression `i**2`. The resulting squared values are then added to the new list.

Therefore, for each element in `my_list`, the corresponding squared value is appended to `new_list`. Since `my_list` contains the elements [1, 2, 3, 4], the squared values would be [1**2, 2**2, 3**2, 4**2], which simplifies to [1, 4, 9, 16]. Hence, the value of `new_list` is [1, 4, 9, 16].

The correct option is d. [1, 4, 9, 16].

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Answer:

17%

Step-by-step explanation:

Answer:

i think

i think it is not complete please tell the complete the question

Step-by-step explanation:

Answer:

You can get approximate values by drawing a graph,

Step-by-step explanation:

Answer:3 $,9$,36$

Step-by-step explanation:

Since he bought a cup of plain coffee which costs 1$ and he is carrying 4$ with him he has saved 3$ he would have used to buy a latte.If he does it continously for 3 times a week his saving per day i.e 3$ ×3,a month which is 3$×3(for a week)×4week which makes a month which is 32$.So the answers are 3$,9$ and 36$

The average value of \(\(f(x)\)\) over the interval \(\([0, 1]\) is \(-\frac{2}{3}\)\) and The values of \(\(c\)\) that satisfy the Mean Value Theorem for Integrals are \(\(c = \frac{3 + \sqrt{3}}{3}\)\) and \(\(c = \frac{3 - \sqrt{3}}{3}\).\)

To find the average value of the function \(\(f(x) = -2x^2 + 4x - 2\)\) over the interval \(\([0, 1]\)\), we need to calculate the definite integral of \(\(f(x)\)\) over that interval and divide it by the length of the interval.

The average value of \(\(f(x)\) over \([0, 1]\)\) is given by:

\(\[\text{Average} = \frac{1}{b - a} \int_{a}^{b} f(x) \, dx\]\)

In this case, \(\(a = 0\) and \(b = 1\),\) so the average value becomes:

\(\[\text{Average} = \frac{1}{1 - 0} \int_{0}^{1} (-2x^2 + 4x - 2) \, dx\]\)

Simplifying the integral:

\(\[\text{Average} = \int_{0}^{1} (-2x^2 + 4x - 2) \, dx\]\\\\\\\\\\{Average} = \left[-\frac{2}{3}x^3 + 2x^2 - 2x\right]_{0}^{1}\]\\\\\\\{Average} = \left(-\frac{2}{3}(1)^3 + 2(1)^2 - 2(1)\right) - \left(-\frac{2}{3}(0)^3 + 2(0)^2 - 2(0)\right)\]\\\\\\\\text{Average} = \left(-\frac{2}{3} + 2 - 2\right) - \left(0\right)\]\\\\\\text{Average} = -\frac{2}{3} + 2 - 2\]\\\\\\text{Average} = -\frac{2}{3}\]\)

Therefore, the average value of \(\(f(x)\)\) over the interval \(\([0, 1]\) is \(-\frac{2}{3}\).\)

Now, let's find the values of \(\(c\)\) that satisfy the Mean Value Theorem for Integrals. According to the Mean Value Theorem for Integrals, there exists a value \(\(c\)\) in the interval \(\([a, b]\)\) such that the average value of \(\(f(x)\)\) over \(\([a, b]\)\) is equal to \(\(f(c)\).\)

In this case, the average value of \(\(f(x)\)\) over \(\([0, 1]\) is \(-\frac{2}{3}\).\) We need to find the value(s) of \(\(c\)\) such that \(\(f(c) = -\frac{2}{3}\).\)

The function \(\(f(x) = -2x^2 + 4x - 2\)\) is a quadratic function, and we need to find the value(s) of \(\(c\)\) where \(\(f(c) = -\frac{2}{3}\).\)

Setting \(\(f(x)\)\) equal to \(\(-\frac{2}{3}\):\)

\(\[-2x^2 + 4x - 2 = -\frac{2}{3}\]\)

Multiplying both sides by \(\(-3\)\) to clear the fraction:

\(\[6x^2 - 12x + 6 = 2\]\)

Rearranging the equation:

\(\[6x^2 - 12x + 4 = 0\]\)

Dividing the equation by \(\(2\)\) to simplify:

\(\[3x^2 - 6x + 2 = 0\]\)

We can now solve this quadratic equation using the quadratic formula:

\(\[x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\]\)

In this case, \(\(a = 3\), \(b = -6\), and \(c = 2\).\)

Plugging in these values into the quadratic formula:

\(\[x = \frac{-(-6) \pm \sqrt{(-6)^2 - 4(3)(2)}}{2(3)}\]\[x = \frac{6 \pm \sqrt{36 - 24}}{6}\]\[x = \frac{6 \pm \sqrt{12}}{6}\]\[x = \frac{6 \pm 2\sqrt{3}}{6}\]\[x = \frac{3 \pm \sqrt{3}}{3}\]\)

Therefore, the values of \(\(c\)\) that satisfy the Mean Value Theorem for Integrals are \(\(c = \frac{3 + \sqrt{3}}{3}\)\) and \(\(c = \frac{3 - \sqrt{3}}{3}\).\)

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Therefore , the solution of the given problem of triangle comes out to be the relationship between s,t and u is u²= t²+s².

Given that it has three sides and three vertices, a triangle qualifies as a polygon. It is a fundamental geometric figure. Triangle ABC is the term used to refer to a triangle containing the vertices A, B, and C. When the three points are not collinear, a unique plane and triangle in Euclidean geometry are discovered. Triangles are polygons because they have three sides and three corners. The points where the three sides of the triangle converge are referred to as the triangle's corners. Three triangle angles are multiplied to yield 180 degrees.

Here,

Given : Triangle STU is a right triangle.

Thus,

We find :

sides s,t and u

the relationship between them is :

As it is a right triangle

So,

According to the pythagoras theorem,

=>u²= t²+s²

Therefore , the solution of the given problem of triangle comes out to be the relationship between s,t and u is u²= t²+s².

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The probability of drawing an ace from the second deck is 1/13. Given that an ace was drawn from the second deck, the conditional probability that an ace was transferred is 1/17.

Probability that the second card is an ace:

There are initially 4 aces in the second deck.

The total number of cards in the second deck is 52.

Therefore, the probability of drawing an ace is 4/52.

Probability = Number of favorable outcomes / Total number of outcomes

Probability = 4/52

Probability = 1/13

Conditional probability that an ace was transferred, given that an ace was drawn from the second deck:

Since an ace was drawn from the second deck, we know that the second card is one of the four aces.

There was initially one card transferred from the first deck to the second deck, so there are now 51 cards left in the second deck.

Out of these 51 cards, only 3 are aces (since one ace has already been drawn).

Conditional Probability = Number of favorable outcomes / Total number of remaining outcomes

Conditional Probability = 3/51

Conditional Probability = 1/17

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Answer:

i think the answer would be A

The probability of a Type II error is represented by beta. Thus, the correct answer is option B.

Beta represents the probability of failing to reject the null hypothesis when it is false.

On the other hand, Type I error (alpha) represents the probability of rejecting the null hypothesis when it is true. A Type II error occurs when a false null hypothesis is not rejected. Hence, beta is the probability of making a Type II error.

The null hypothesis is rejected when the p-value is less than or equal to the level of significance, not exceeds it.

The p-value is the probability of obtaining a result as extreme as or more extreme than the observed result when the null hypothesis is true. If the p-value is less than the level of significance, the null hypothesis is rejected, and vice versa.

Hence, the statement "The null hypothesis is rejected when the p-value exceeds the level of significance" is false.

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Answer:

\(P = 56\sqrt2\)

Step-by-step explanation:

We can find the perimeter of a square given its diagonal by modeling the square as two congruent right triangles and using the Pythagorean Theorem to solve for the square's side lengths.

The Pythagorean Theorem states that...

\(a^2+b^2=c^2\), where \(a\) and \(b\) are the right triangles legs, and \(c\) is its hypotenuse.

However, since we are working with a square, we know that the right triangles' legs are congruent. Thus, the theorem becomes:

\(a^2 + a^2 = c^2\)

\(2 \cdot a^2 = c^2\)

Using this formula, we can solve for the square's side lengths, inputting the given hypotenuse length of 28.

\(2 \cdot a^2 = 28^2\)

↓ simplify the exponent

\(2 \cdot a^2 = 784\)

↓ divide both sides by 2

\(a^2 = 392\)

↓ take the square root of both sides

\(a = \sqrt{392}\)

↓ simplify the square root

\(a = \sqrt{2^3 \cdot 7^2}\)

\(a = (2\cdot 7)\sqrt{2}\)

\(a=14\sqrt2\)

Finally, we can multiply the side length by 4 to get the square's perimeter (since a square has 4 sides).

\(P = 4 \cdot a\)

\(P = 4 \cdot 14\sqrt2\)

\(\boxed{P = 56\sqrt2}\)

\(\boxed{P \approx 79.2}\)

The distances between each pair of points are as follows:

1. (1, -4.6) and (3, -7): 3.12 (rounded to two decimal places)

2. (-6, -5) and (2, 0): √89 (exact value)

M = (-12, -1) and M = (4, 0): √257 (exact value)

4. (0, -8) and (3, 2): √109 (exact value)

3. (-1, 4) and (1, -1): √29 (exact value)

We may use the distance formula to calculate the separation between each pair of points:

d = √((x₂ - x₁)² + (y₂ - y₁)²),

where the two points' coordinates are represented by (x1, y1) and (x2, y2), respectively.

Let's determine the separation between each pair of points:

1. (1, -4.6) and (3, -7):

d = √((3 - 1)² + (-7 - (-4.6))²)

= √(2² + (-2.4)²)

= √(4 + 5.76)

= √9.76

= 3.12 (rounded to two decimal places)

2. (-6, -5) and (2, 0):

d = √((2 - (-6))² + (0 - (-5))²)

= √(8² + 5²)

= √(64 + 25)

= √89 (exact value)

M = (-12, -1) and M = (4, 0):

d = √((4 - (-12))² + (0 - (-1))²)

= √(16² + 1²)

= √(256 + 1)

= √257 (exact value)

4. (0, -8) and (3, 2):

d = √((3 - 0)² + (2 - (-8))²)

= √(3² + 10²)

= √(9 + 100)

= √109 (exact value)

3. (-1, 4) and (1, -1):

d = √((1 - (-1))² + (-1 - 4)²)

= √(2² + (-5)²)

= √(4 + 25)

= √29 (exact value)

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Answer:

5

Step-by-step explanation:

Binding constraints directly influence the optimal solution in a linear Programming problem, whereas constraints with positive slack are non-binding and do not directly impact the solution.

binding constraints and positive slack in the context of linear programming. In a linear programming problem, we aim to find the optimal solution for an objective function, given a set of constraints. The terms "binding constraints" and "positive slack" are related to these constraints.

1. Binding constraints: These are constraints that directly impact the optimal solution of the problem. In other words, they "bind" the feasible region (the area where all the constraints are satisfied) and affect the maximum or minimum value of the objective function. Binding constraints are active constraints, as they influence the final solution.

2. Positive slack: Slack is the difference between the left-hand side and right-hand side of a constraint when the constraint is satisfied. If this difference is positive, it means that there is some "extra" or "unused" resource in that constraint. Positive slack indicates that the constraint is non-binding, meaning it does not directly impact the optimal solution. It shows that there is some room for the constraint to be further tightened without affecting the final outcome.

In summary, binding constraints directly influence the optimal solution in a linear programming problem, whereas constraints with positive slack are non-binding and do not directly impact the solution. Knowing the difference between these terms can help you better understand and analyze linear programming problems.

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Answer: 1200 milliliters.

Step-by-step explanation: 1 liter has 100 milliliters of milk in it. So you have to multiply 1.2 by 100 to get 1200.