Notice that both strings have the same length, so they form an isosceles triangle, which means the angles they make with the ceiling are congruent.
If this angle has measure θ, then the angle between the two strings T₁ and T₂ has measure 180° - 2θ. This is because the interior angles of any triangle sum to 180°.
By the law of cosines, we have
(1 m)² = (0.87 m)² + (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)
Solve for θ :
(1 m)² = 2 (0.87 m)² - 2 (0.87 m)² cos(180° - 2θ)
(1 m)² / (2 (0.87 m)²) = 1 - cos(180° - 2θ)
cos(180° - 2θ) = 1 - (1 m)² / (2 (0.87 m)²)
cos(180° - 2θ) ≈ 0.3394
180° - 2θ = arccos(0.3394)
180° - 2θ ≈ 70.159°
2θ ≈ 109.841°
θ ≈ 54.9205° ≈ 55°
What is the mass of a truck if it produces a force of 13,607 N while accelerating at a rate of 2.9 m/s²?
Newton's Second Law.
We have the following data, provided in the exercise:
Mass (m) = ?
Force (F) = 13607 N
Acceleration (a) = 2.9 m/s²
To calculate the mass, we solve the following formula:
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{F=m*a \ \ < ====Formula \ clear==== > \ \frac{F}{a}=\frac{m*\not{a}}{\not{a}} } \end{gathered}$}}\)\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{\frac{F}{a}=m \ \iff \ Address \ is \ changed \Rightarrow \ m=\frac{F}{a} } \end{gathered}$}}\)
We substitute the data in the clear formula.
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ N}{2.9 \ \frac{m}{s^{2} } } } \end{gathered}$} }\)
We break down the units of Newton = Kg * m/s².
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=\frac{13607 \ Kg*\not{\frac{m}{s^{2}} } }{2.9 \not{\frac{m}{s^{2}} } } } \end{gathered}$} }\)
\(\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{m=4692.07 \ Kg } \end{gathered}$} }\)
The mass of the truck is: 4692.07 Kilograms (Kg).A metallic ring of mass 1 kg has moment of inertia 1 kg m² when rotating about one of its diameters. It is molten and
remoulded into a thin uniform disc of the same radius. How much will its moment of inertia be, when rotated about its own
axis.
Answer:
The moment of inertia of disc about own axis is 1 kg-m².
Explanation:
Given that,
Mass of ring m= 1 kg
Moment of inertia of ring at diameter \((I_{r})_{d}=1\ kg\ m^{2}\)
The radius of metallic ring and uniform disc both are equal.
So, \(R_{r}=R_{d}\)
We need to calculate the value of radius of ring and disc
Using theorem of perpendicular axes
\((I_{r})_{c}=2\times (I_{r})_{d}\)
Put the value into the formula
\((I_{r})_{c}=2\times1\)
\((I_{r})_{c}=2\ kg\ m^2\)
Put the value of moment of inertia
\(MR_{r}^2=2\)
\(R_{r}^2=\dfrac{2}{M}\)
Put the value of M
\(R_{r}^2=\dfrac{2}{1}\)
So, \(R_{r}^2=R_{d}^2=2\ m\)
We need to calculate the moment of inertia of disc about own axis
Using formula of moment of inertia
\(I_{d}=\dfrac{1}{2}MR_{d}^2\)
Put the value into the formula
\(I_{d}=\dfrac{1}{2}\times1\times2\)
\(I_{d}=1\ kg\ m^2\)
Hence, The moment of inertia of disc about own axis is 1 kg-m².
The displacement (in meters) of a particle moving in a straight line is given by the equation of motion:
s = 4/t^2, where t is measured in seconds.
Required:
Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3.
Answer:
At \(t = 1\; \rm s\), the particle should have a velocity of \(-8\; \rm m \cdot s^{-1}\).At \(t = 2\; \rm s\), the particle should have a velocity of \(-1\; \rm m \cdot s^{-1}\).At \(t = 3\; \rm s\), the particle should have a velocity of \(\displaystyle -\frac{8}{27}\; \rm m \cdot s^{-1}\).For \(a > 0\), at \(t = a \; \text{second}\), the particle should have a velocity of \(\displaystyle -\frac{8}{a^3}\; \rm m \cdot s^{-1}\).
Explanation:
Differentiate the displacement of an object (with respect to time) to find the object's velocity.
Note that the in this question, the expression for displacement is undefined (and not differentiable) when \(t\) is equal to zero. For \(t > 0\):
\(\begin{aligned}v &= \frac{\rm d}{{\rm d}t}\, [s] = \frac{\rm d}{{\rm d}t}\, \left[\frac{4}{t^2}\right] \\ &= \frac{\rm d}{{\rm d}t}\, \left[4\, t^{-2}\right] = 4\, \left((-2)\, t^{-3}\right) = -8\, t^{-3} =-\frac{8}{t^3}\end{aligned}\).
This expression can then be evaluated at \(t = 1\), \(t = 2\), and \(t = 3\) to obtain the required results.
What is the cost per month to operate an A.C. 10hours per day whose power is 3kW and 1KWH cost 79francs
The cost of operation for an A.C for 10 hours per day for a month will be 71,100 francs.
What is Power?Power is the amount of energy transferred or converted per unit time. The unit of power is the watt, equal to one joule per second. Power is a scalar quantity.
Cost of operation for 10 hours a day;
Daily consumption = 3kW x 10 hours
Daily Consumption = 30kW
Since 1kWH = 79 francs;
Daily consumption amount = 30 x 79 francs
Daily consumption amount = 2,370 francs
Therefore, the monthly consumption (using 30days) will be;
2,370 francs x 30 = 71,100 francs
In conclusion, 71,100 francs will be spent in a month (30 days) to run the 3kW rated A.C for 10 hours a day at 1kWH.
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In which of the following situations would it NOT be wise to estimate?
a.
the number of miles per gallon an automobile can provide
b.
the time it would take to walk to the grocery store from home
c.
the amount of food to prepare for twelve people
d.
the amount of medicine to give a patient
A guitar string transmits waves at
315 m/s, and oscillates at 370 Hz.
What is the length of the string?
(Unit = m)
Answer:
The wavelength of the waves on the string is found using v = λf:
λ = v/f = 315/370 = 0.85135m
The first harmonic (fundamental) standing wave formed on the string has nodes only at the ends (see diagram in link) so:
String length = λ/2 = 0.85135/2 = 0.426m (to 3 sig. figs.)
In the formulas for latent heat of fusion and latent heat of vaporization, what does Q represent?
Answer:
Q is the amount of energy released or absorbed during the change of phase of the substance (in kJ or in BTU), m is the mass of the substance (in kg or in lb), and. L is the specific latent heat for a particular substance (kJ kg−1 or in BTU lb−1), either Lf for fusion, or Lv for vaporization.
I hope this helps∪ω∪
Answer:
A
Explanation:
Which description tells two processes scientists think move Earth's lithospheric plates?
Responses
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
friction between the plate and the asthenosphere and pressure of magma on the edge of the plate
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and convection in the mantle
gravity acting on the edges of plates and friction between the plate and the asthenosphere
gravity acting on the edges of plates and friction between the plate and the asthenosphere
convection in the mantle and pressure of magma on the edge of the plate
The description that tells two processes that scientists think move Earth's lithospheric plates is convection in the mantle and pressure of magma on the edge of the plate.
What is the Earth's lithosphere?The Earth's lithosphere is the rocky outer part of Earth which is made up of the brittle crust and the top part of the upper mantle.
The Earth's lithosphere deflects the convections and as the convections churn clockwise of anticlockwise, they drag the lithosphere with it via friction an this is what is stipulated to cause tectonic plate movements.
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Answer: convection in the mantle and pressure of magma on the edge of the plate
Explanation: I took the unit test
In the diagram, the distance OP is the focal length of the converging lens. One ray of light from O
is shown.
Through which point will this ray pass, after refraction by the lens?
The point through which this ray will pass, after refraction by the lens is point D.
What is refraction of light?The refraction of light refers to the bending or change in direction that occurs when light passes from one medium to another. It is a phenomenon that happens due to the difference in the speed of light in different substances.
From the ray diagram given, after the light incident from point O, it will pass the converging at point D which is the focal length of the lens after refraction.
Thus, based on the converging lens given in the ray diagram, we can conclude that, the point through which this ray will pass, after refraction by the lens is point D.
So point D is the correct answer.
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Which of the following is true of the Jovian planets?A) They have more satellites than the terrestrial planets.B) They have thick atmospheres.C) They have more hydrogen and helium than the terrestrial planetsD) They are much larger than the terrestrial planets.
The Jovian planets, or gas giants, are a group of planets in our solar system that share certain characteristics.
The correct option is D
One of the defining characteristics of Jovian planets is that they are much larger than terrestrial planets, with diameters several times that of Earth. They are composed mainly of hydrogen and helium and have thick atmospheres that extend far into space. These atmospheres are rich in gases such as methane, ammonia, and water vapor, giving the planets their distinct colors and cloud bands. The Jovian planets are also known for having a large number of satellites (moons), with Jupiter having over 80 known moons and Saturn having over 80 as well. In contrast, the terrestrial planets have fewer satellites and smaller atmospheres.
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draw a graph of the voltmeter reading versus ammeter readings.
The VI graph helps us to find Resistance.
It was used by Ohm which is well known as ohms law.
Which team sport utilizes judges to determine the points earned?
Answer:
Rhythmic Gymnastics
Explanation:
A 500 g squirrel with a surface area of 895 cm2 falls from a 5.6-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the squirrel can be
approximated as a rectanglar prism with cross-sectional area of width 11.3 cm and length 22.6 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. Give the squirrel's
terminal velocity, not it's velocity as it hits the ground.)
x m/s
What will be the velocity of a 50.0 kg person hitting the ground, assuming no drag contribution in such a short distance?
x m/s
8.3 m/s is the terminal velocity of the squirrel can be calculated using the equation for terminal velocity and 10.8 m/s is the velocity of a 50.0 kg person hitting the ground.
What is velocity?
Velocity is a measure of the speed of an object's motion in a particular direction. It is a vector quantity, meaning it has both magnitude and direction. Velocity is usually measured in meters per second (m/s).
The terminal velocity of the squirrel can be calculated using the equation for terminal velocity of an object in a fluid, which is given by Vt = (2×m×g)/(ρ×Cd×A). Here, m is the mass of the object, g is the acceleration due to gravity, ρ is the density of the fluid, Cd is the drag coefficient, and A is the reference area of the object. The drag coefficient for a horizontal skydiver is 0.8, and the density of air is 1.225 kg/m^3. Therefore, the terminal velocity of the squirrel can be calculated as Vt = (2×500×9.8)/(1.225×0.8×895) = 8.3 m/s.
The velocity of a 50.0 kg person hitting the ground can be calculated using the equation for the velocity at the end of a fall, which is given by Vf = sqrt(2×g×h). Here, g is the acceleration due to gravity and h is the height of the fall. Therefore, the velocity of the person hitting the ground can be calculated as Vf = sqrt(2×9.8×5.6) = 10.8 m/s.
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A person looks horizontally at the edge of a swimming pool. If its length is 5 m, and the pool is filled to the surface, to what depth (in m) could the observer see
Answer:
The observer could see to a depth of 4.38 m
Explanation:
Please check attachment for diagram.
Mathematically, from Snell law;
n1sin theta = n2 sin theta
1 * sin 90 = n2 * sin θR
where n2 = 1.33
1/1.33 = sin θR
Sin θR = 0.7519
θR = arc sin 0.7519
θR = 48.76
Now to get the height, we use the triangle
Using trigonometric ratio;
Tan( 90- θR) = H/5
H = 5 Tan( 90 - θR)
H = 5 Tan( 90-48.76)
H = 5 Tan41.24
H = 4.38 m
FILL IN THE BLANK recall the portion of the video in which the girl pushes her brother on the sled at constant velocity. the pushing force she exerts on the sled is ___the frictional force the ground exerts on the sled.
The pushing force she exerts on the sled is equal to the frictional force the ground exerts on the sled.
In the video, the girl pushed her brother on the sled at a constant velocity, which means the forces acting on the sled must have balanced. Therefore, the pushing force the girl exerted must have been equal to the frictional force that the ground exerted on the sled.
This is because, according to Newton's Third Law of Motion, for every action there is an equal and opposite reaction. In this case, the action is the girl pushing the sled, and the reaction is the frictional force exerted by the ground on the sled. Since the sled is moving at a constant velocity, this means that the forces acting on it are balanced, and therefore the pushing force and the frictional force must be equal.
In equation form, this can be represented as:
F_push = F_friction
Where F_push is the pushing force exerted by the girl, and F_friction is the frictional force exerted by the ground.
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what is the work done on the box from x = 0m to 16m
Answer:
Explanation:
The Workdone is the product of force and distance, Hence, the Workdone on the box from distance x = 0 meters and x = 16 meters is 0 Joules.
Using the graph given :
The work done from x = 0 to x = 16 metres ;
The distance can be split evenly into :
(x = 0 to x = 8) and (x = 8 to x = 16)
Workdone = Force × distance
Workdone from ; x = 0 to x = 8 ;
Force at a distance of 8 meters = - 40N
Workdone = - 40N × 8 m = -320 Nm
Workdone from ; x = 8 to x = 16 ;
Force at a distance of 16 meters = 40 N
Workdone = 40 N × 8 m = 320 Nm
The total workdone :
(-320 + 320) Nm = 0 J
.
Therefore, the Workdone ls 0 Joules.
What three forms of energy are represented when a match is lit?
Answer:
Three forms of energy when a match is being lit are potential, kinetic and thermal.
hope this helps! :)
Explanation:
Answer:
Potential Energy
Kinetic Energy
Thermal Energy
Explanation:
What do you think is happening when you touch objects in your home
Answer:
I feel like static electricity is happening when we touch objects in our home
I need help, please!
Answer:
can u send pictures again it's unclear.
the distance between an object and its real image is 40 cm, if the magnification is 3, calculate the object and image distance if the focal length of the lens is 15 cm
The object distance of the lens is 10 cm and the image distance of the lens is 30 cm.
What is the image and object distance?The object and image distance formed by the lens is calculated by applying the following lens formula.
v + u = 40 ------- (1)
v/u = 3 ------------ (2)
v = 3u
Substitute v into equation (1);
3u + u = 40
4u = 40
u = 40/4
u = 10 cm
The image distance = 3u
= 3 x 10 cm
= 30 cm
Thus, the object distance is 10 cm and the image distance is 30 cm.
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1. Determine the kinetic energy of a 625-kg roller coaster car that is moving with a speed of 18.3 m/s,
Answer:
104653.13J
Explanation:
Given parameters:
Mass of roller coaster = 625kg
Speed = 18.3m/s
Unknown:
Kinetic energy = ?
Solution:
The kinetic energy is the energy due to the motion of a body.
Kinetic energy = \(\frac{1}{2}\) x m x v²
m is the mass
v is the speed
Kinetic energy = \(\frac{1}{2}\) x 625 x 18.3² = 104653.13J
Q.4. What is the kinetic energy of a 10 kg car that is moving 4 m/s?
a) 20 joules
b) 80 joules
c) 160 joules
d) 40 joules
An object of mass \($10 \mathrm{~kg}$\) is moving with a uniform velocity of \($4 \mathrm{~ms}^{-1}$\). The kinetic energy possessed by the object is \($80 \mathrm{~J}$\).
Given:
Mass of an object \($=10 \mathrm{~kg}$\)
Velocity \($=4 \mathrm{~ms}^{-1}$\)
Kinetic Energy \($=1 / 2 \times$\) Mass of Object \($\times(\text { Velocity })^{2}$\)
\($\Rightarrow$\) Kinetic Energy \($=1 / 2 \times 10 \times 4 \times 4$\)
\($\Rightarrow$\)Kinetic Energy \($=\underline{80 \mathbf{J}}$\)
What is Kinetic Energy?
In physics, an object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity. The body retains its kinetic energy after gaining it during acceleration until its speed changes.Kinetic energy is present in a speeding bullet, a walking human, and electromagnetic radiation such as light. The energy associated with the continual, random bouncing of atoms or molecules is another type of kinetic energy.Learn more about kinetic energy https://brainly.com/question/12669551
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if the body is floating in a liquid then can we say that the rise in the level of the liquid is equal to the height of the body
Yes, if a body is floating in a liquid, the rise in the liquid level is equal to the body height. This phenomenon is known as Archimedes' principle.
Archimedes' principle says when a body is immersed in a fluid (liquid or gas), it experiences an upward buoyant force equal to the weight of the fluid displaced by the body. Buoyant forces act in the opposite direction to gravity.
When a body floats in a liquid, it displaces a volume of liquid equal to its volume. As a result, the liquid level rises by an amount equal to the height of the submerged part of the body.
This principle holds for objects that float or are partially immersed in a liquid, such as a buoyant boat or a floating object. However, if the body sinks completely into the liquid, the liquid level rise will no longer be equal to its height. Instead, it depends on the density and volume of the submerged object.
In the Roman soldier model for refraction, what happens to the first soldier who hits the muddy stream?
A. They slow down and keep going straight
B. They slow down and turn slightly
C. They speed up and keep going straight
D. They speed up and turn slightly
In the Roman soldier model for refraction, the first soldier who hits the muddy stream would slow down and turn slightly. Option B is correct.
The Roman soldier model is a simplified model used to explain the behavior of light when it passes from one medium to another. In this model, a group of Roman soldiers is marching across a field towards a muddy stream. The soldiers represent light rays, and the muddy stream represents the boundary between two media with different refractive indices.
When the first soldier hits the muddy stream, they slow down because the speed of light decreases when it passes from a medium with a lower refractive index to a medium with a higher refractive index. Additionally, the soldier turns slightly because the direction of the light ray changes as it passes through the boundary between the two media. This change in direction is called refraction, and it occurs because the speed of light changes when it passes through a medium with a different refractive index.
The amount of refraction that occurs depends on the angle at which the light ray hits the boundary between the two media and the difference in refractive indices between the two media. The Roman soldier model is a useful tool for understanding the basics of refraction, but it has limitations and cannot fully explain all aspects of the phenomenon. Option B is correct.
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$3.49/ gallon and other is $1.25/L which container of milk is a better deal
Valid Expressions are; t = ∛(d²/va), a = d/t², a = √(vd/t³), v = at
while the Invalid expressions are; v = a/t and d = at
Explanation:
Given expressions
1) v = a/t
2) t = ∛(d²/va)
3) d = at
4) a = d/t²
5) a = √(vd/t³)
6) v = at
First we get our units of parameters
V = m/s, t = sec, d = m, a = m/s²
so
1)
v = a/t
we substitute in our units of parameters
v = m/s² / s = m/s² × 1/s = m/s³
v ≠ m/s³
therefore it is false
2)
t = ∛(d²/va)
we substitute
t = ∛(m² / m/s × m/s²)
t = ∛(m² / m²/s³)
t = ∛(s³)
t = s
correct, the expression is true
3)
d = at
we substitute
d = m/s² × s
d = m/s² × s/1 = ms/s² = m/s
d ≠ m/s (because d = m)
so expression is false
4)
a = d/t²
we substitute
a = m / s² = m/s²
correct
the expression is true
5)
a = √(vd/t³)
we substitute
a = √(m/s×m / s³) = √(m²/s / s³) = √(m²/s × 1/s³) = √(m²/s⁴) = m/s²
so a = m/s²
correct
the expression is true
6)
v = at
we substitute in the units
v = m/s² × s = m/s² ×s/1 = ms/s² = m/s
v = m/s
correct
the expression is correct
Which of the following is a vector quantity
weight
temperature
acceleration
distance
Answer:
weight, acceleration
Explanation:
weight = mass x gravity(meaning the direction of the mass)
acceleration = v-u/t
v-u is the change in velocity
8. Before leaving the ground an airplane traveling with constant acceleration makes a run on the
runway of 1800 meters in 12 seconds. Determine:
a. Acceleration
b. Speed at which it leaves the ground
c. Distance traveled during the first and twelfth seconds
Answer:
\(\color{Blue}\huge\boxed{Answer} \)
B. Speed at which it leaves the groundYou can hear sounds transmitted through alr, water, or steel but not through the empty vacuum of space. What type of wave carries sound?
gravity
light
mechanical
electromagnetic
A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)
Answer:
Explanation:
F = k * q * lambda * R * π * (1 - √2/2)
Substituting the given values of q, lambda, R, and k, we get:
F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)
F ≈ 8.58 x 10^-4 N
Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.
when the direction of acceleration is opposite to the direction of velocity
Answer:
If acceleration points in the same direction as the velocity, the object will be speeding up. And if the acceleration points in the opposite direction of the velocity, the object will be slowing down.