considering this is a homework answer site does any personal have knowledge and a answer for this.

The optimal prices are $18 for model A and $25 for model B. The maximum total revenue is $570.

The nonlinear programming formulation of the problem is as follows:

maximize

revenue = PA * NA + PB * NB

subject to

NA = 20 - 0.62PA + 0.30PB

NB = 29 + 0.10PA - 0.60PB

PA, PB >= 0

The decision variables are PA and PB, which are the prices of model A and model B, respectively. The objective function is to maximize the total revenue, which is equal to the product of the price and quantity sold for each model. The constraints are that the quantity sold for each model must be non-negative.

The spreadsheet model for the problem is shown below. The input data is in the range A1:B2. The calculations for the objective function and the left-hand side of the constraints are shown in the range C1:C4.

The Answer Report from Solver is shown below. The optimal prices are $18 for model A and $25 for model B. The maximum total revenue is $570.

The recommendation is to set the prices of model A and model B to $18 and $25, respectively. This will maximize the total revenue from the sale of these products.

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Answer:

1 foot long

Step-by-step explanation:

If this fraction is closer to one it will be close to 16/16. And since 8 is half of 16, any fraction that is around 8/16 is closer to 1/2. 15 is closer 16 so this fraction is closer to one.

The side lengths of the squares is closer to 1 foot when rounded to the nearest foot length

There are basically two rules while rounding up numbers

If the number you are rounding is followed by 0, 1, 2, 3, or 4, round the number down and if the number you are rounding is followed by 5, 6, 7, 8, or 9, round the number up.

Non-zero digits are always significant

Zeros between non-zero digits are always significant

Leading zeros are never significant

Trailing zeros are only significant if the number contains a decimal point

Given data ,

Let the side lengths of the squares after rounding be represented as A

Now , the value of A is

The side lengths of the quilt with square shape be = 15/16 foot

Now , on rounding the value 15/16 , we get

A = 0.9375 feet

And , the value of A is much closer to 1 foot

Therefore , the value of A is 1 foot

Hence , the side lengths of the squares after rounding is 1 foot

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Answer:

Te conozco y sé qué

Como Nuevo de fabrica el otro

The linear equation of the relationship is L = -8t + 40.

The amount Austin paid back each week is: $8.

A linear equation is straight line graph, which can be expressed as y = mx + b, in slope-intercept form. In the slope-intercept form, we have:

Slope = change in y / change in x.

Using two pairs of values from the table given, (1, 32) and (2, 24):

Slope (m) = (32 - 24) / (1 - 2)

m = 8/-1

m = -8.

Find the y-intercept (b) by substituting m = -8 and (x, y) = (1, 32) into y = mx + b:

32 = -8(1) + b

32 = -8 + b

32 + 8 = b

40 = b

b = 40

Substitute b = 40 and m = -8 into L = mt + b:

L = -8t + 40

Using the linear equation, the amount Austin paid back each week is: $8.

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Mr. Knapp initially had 61 stamps.

Given that Mr. Knapp had some stamps,

if he gave 7 stamps to each of his children, now he would have 5 stamps left.  

If he gave 8 stamps to each child, he would need 3 more stamps in order for the children to have an equal number of stamps.  

We need to find that how many stamps did Mr. Knapp had.

Let's solve the problem step by step.

Let's assume Mr. Knapp has "x" stamps initially.

According to the first condition, if he gave 7 stamps to each of his children, he would have 5 stamps left.

This can be expressed as:

x - 7c = 5,

where "c" represents the number of children.

According to the second condition, if he gave 8 stamps to each child, he would need 3 more stamps in order for the children to have an equal number of stamps.

This can be expressed as:

x - 8c = -3.

We now have a system of two equations with two variables:

x - 7c = 5,

x - 8c = -3.

Let's use the elimination method to eliminate "x" from the equations:

(x - 7c) - (x - 8c) = 5 - (-3),

x - 7c - x + 8c = 5 + 3,

c = 8.

Now that we know the value of "c" is 8, we can substitute it back into either of the original equations to find the value of "x."

Let's substitute it into the first equation:

x - 7(8) = 5,

x - 56 = 5,

x = 5 + 56,

x = 61.

Therefore, Mr. Knapp initially had 61 stamps.

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The coefficient of variation (CV) is a measure of relative variability and is calculated by dividing the standard deviation by the mean, and then multiplying by 100 to express it as a percentage.

In this case, the mean weight is 340 grams, and the standard deviation is 5.2 grams.

CV = (Standard Deviation / Mean) * 100

CV = (5.2 / 340) * 100

CV ≈ 1.53%

Therefore, the correct answer is option B: 1.53%.

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Answer:

\(\Huge \boxed{\mathrm{55}}\)

Step-by-step explanation:

\(-7x + 6\)

Put x as -7 and evaluate the expression.

\(-7(-7)+6 \\\\\\ 49+6 \\\\\\ 55\)

Answer:

54

Step-by-step explanation:

Since triangle ABC ~ DEF

Angle A = Angle D

Angle A = 54

Answer:

Step-by-step explanation:

6x + 2y = 26

5x - 2y = 7

11x = 33

x = 3

3(3) + y = 13

9 + y = 13

y = 4

(3,4)

There will be $33434.8 in the account after 9 years

From the question, we have the following parameters that can be used in our computation:

Principal, P = 18000

Time = 9 years

Rate = 7%

Number of times = 2

The formula for calculating the amount in an account is

A = P * (1 + r/2)^(2t)

So, the amount in the account after 9 years will be:

A = $18000 * (1 + 0.07/2)^(2 * 9)

Evaluate

A = $33434.8

Hence, after 9 years there will be $33434.8 in the account.

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The solution to the recurrence relation is Xk = 0 for all values of k. There are no other terms or patterns in the sequence beyond Xk = 0.

To compute the recurrence relation, we'll first determine the characteristic equation and then determine the particular solution.

1: Finding the characteristic equation:

Assume the solution to the recurrence relation is of the form \(Xk = r^k.\)Substitute this form into the recurrence relation:

\(r^(k+2) + r^(k+1) - 6r^k = 2k - 1\)

Divide both sides by \(r^k\) to simplify the equation:

\(r^2 + r - 6 = 2k/r^k - 1/r^k\)

Taking the limit as k approaches infinity, the right-hand side will approach zero. Thus, we have:

r² + r - 6 = 0

2: Solving the characteristic equation:

To solve the quadratic equation r² + r - 6 = 0, we factor it:

(r + 3)(r - 2) = 0

This gives us two roots: r₁ = -3 and r₂ = 2.

3: Finding the general solution:

The general solution to the recurrence relation is of the form:

Xk = A * r₁^k + B * r₂^k

Plugging in the values for r₁ and r₂, we get:

Xk = A * (-3)^k + B * 2^k

4: Determining the particular solution:

To find the values of A and B, we'll use the initial conditions X₀ = 0 and X₁ = 0.

For k = 0:

X₀ = A * (-3)⁰ + B * 2⁰

0 = A + B

For k = 1:

X₁ = A * (-3)¹+ B * 2¹

0 = -3A + 2B

Now, we have a system of equations:

A + B = 0

-3A + 2B = 0

Solving this system of equations, we find A = 0 and B = 0.

5: Writing the final solution:

Since A = 0 and B = 0, the general solution reduces to:

Xk = 0 * (-3)^k + 0 * 2^k

Xk = 0

Therefore, the solution to the recurrence relation is Xk = 0 for all values of k.

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Answer:

c=3/7t

Step-by-step explanation:

did it on khan

Answer:

what do you mean

Step-by-step explanation:

Answer:

6 - 2t < -4

Step-by-step explanation:

:)

Answer: Transversal

Step-by-step explanation:

Altitude is in the triangle as it has vertexes shown by the line, Hypotenuse is the longside of the triangle which is shown, and the legs, every single triangle has legs, which leaves us with transversal which means a straight line that cuts a parrel line. Which isn't shown so that's the answer. Have a good day ;)

Answer:

24 is the answer

Step-by-step explanation:

2a + 5 = 53

     -5      -5

      0      48

2a/2= a

48/2= 24

THEREFORE a=24

The simplified form of the expression is, negative five sixths times x plus eight.

What is word problem?

A math word problem is a mathematical question that is stated as one sentence or more and asks students to use their arithmetic skills in a "real-life" situation. Therefore, in order for kids to understand the word problem, they need to be familiar with the terminology that goes along with the mathematical symbols that they are used to.

Given that:   quantity negative two thirds times x minus 6 end quantity minus quantity negative 14 plus one sixth times x end quantity

It can be write in mathematical form as,

\((-\frac{2}{3}x-6) - (-14+\frac{1}{6}x)\)

Simplifying the parenthesis,

\(= -\frac{2}{3}x-6+14-\frac{1}{6}x\\ = 8 - \frac{15}{18}x\\ = 8 - \frac{5}{6}x\\= -\frac{5}{6}x+8\)

Hence, the simplified form of the expression is, negative five sixths times x plus eight

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The three angle bisector of a triangle intersect at a single point that point of concurrency of the angle of bisectors is called the incenter.

Given:

the 3 angle bisectors of a triangle intersect.

when three angle bisector of a triangle intersect then that point of concurrency is called incenter.

Incenter:

The incenter of a triangle is the intersection point of all the three interior angle bisectors of the triangle. In other words, it can be defined as the point where the internal angle bisectors of the triangle cross. This point will be equidistant from the sides of a triangle, as the central axis’s junction point is the center point of the triangle’s inscribed circle.

Incenter formula:

= (ax1+bx2+x3 / a+b+c  , ay1+by2+y3 / a+b+c).

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Answer:

11/x because split is the same as divide so she split 11 pieces with x people

Step-by-step explanation:

Answer:

$20

Step-by-step explanation:

-34 + 54 = 20

Answer:

$20

Step-by-step explanation:

-34 + 54 = 20

This is because he is adding an extra $54 to the -$34 he already had.

Hope this helps, let me know if you have any questions :)

7/8 = x/56

x = 7 x 7

so, 49/56 = rod

so, 49 pieces will be made

hope it helps :)

Answer:

\(\$3.3\)

Step-by-step explanation:

Given:

Amount paid by a store for a set of spoons = $11

Percentage increase in price = 30%

To find: amount of the mark up

Solution:

To find amount of the mark up, find 30% of (amount paid by a store for a set of spoons)

Amount of the mark up = \(\frac{30}{100} (11)=\$3.3\)

The solution to the equation does not exist

From the question, we have the following parameters that can be used in our computation:

2x - 3 = 0

2x - 3 = 3

Also from the question, we understand that the graph is given as

3 = 0

The above equation is false, and cannot be represented on a graph

This is so because 0 and 3 do not have the same value

Similarly, we have 2x - 3 = 0 and 2x - 3 = 3

By substitution, the equations becomes

0 = 3

Hence, the equation has no solution

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Complete question

Graph of 3=0

Solve the equation 2x - 3 = 0 and 2x - 3 = 3 graphically

According to the given equation,

a) As we have shown that if there exist two solutions x and y in R, then they must be equal.

b) As we have shown that if there exist two solutions x and y in R, then they must be equal.

Part (a) of the problem asks us to prove that the equation a + x = b has a unique solution in R, given that a and b are elements of R. To show this, we need to demonstrate that there exists a solution x in R that satisfies the equation, and that this solution is the only one.

First, we will show that a solution x exists. We can do this by solving for x in terms of a and b: x = b - a. Since R is a ring, both a and b belong to R, and therefore b - a also belongs to R. This means that the equation a + x = b has a solution in R.

Next, we will prove that this solution is unique. Suppose there exist two solutions x and y in R such that a + x = b and a + y = b. Then, we have:

x = x + 0 (since 0 is the additive identity in R)

= x + (a + y - b) (substituting a + y - b for y, which also satisfies the equation)

= (x + a) + y - b (associativity of addition in R)

= (a + x) + y - b (commutativity of addition in R)

= b + y - b (since a + x = b)

= y (cancellation property of addition in R)

Hence, the equation a + x = b has a unique solution in R.

Part (b) of the problem deals with the equation ax = b, where R is a ring with identity and a is a unit (i.e., has a multiplicative inverse). We need to prove that this equation also has a unique solution in R.

To show that a solution exists, we can simply multiply both sides of the equation by a⁻¹, the multiplicative inverse of a in R. This gives us:

a⁻¹ax = a⁻¹b

x = a⁻¹b

Since R is a ring with identity, a⁻¹ and b both belong to R, so x also belongs to R. Hence, the equation ax = b has a solution in R.

To prove that this solution is unique, suppose there exist two solutions x and y in R such that ax = b and ay = b. Then, we have:

x = 1x (since 1 is the multiplicative identity in R)

= a⁻¹ax (multiplying both sides by a⁻¹)

= a⁻¹b (since ax = b)

= a⁻¹ay (multiplying both sides by a⁻¹)

= y (since ay = b)

Hence, the equation ax = b has a unique solution in R.

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To find the value of V*(s'), The Bellman equation relates the Q*(s, a) values to the state-value function V*(s) by taking the maximum Q-value over all possible actions. Given the Q*(s, a) values and the transition information:

V*(s') = max(Q*(s', a)) for all actions a

In this case, the Q* values for state s are:

Q*(s, \(a_{1}\)) = 10

Q*(s, \(a_{2}\)) = -1

Q*(s, \(a_3}\)) = 0

Q*(s, \(a_{4}\)) = 11

Since s' can be reached from s by taking action a1, we consider the Q* values for state s' and select the maximum value:

V*(s') = max(Q*(s', \(a_{1}\)), Q*(s', \(a_{2}\)), Q*(s', \(a_{3}\)), Q*(s',\(a_{4}\) )

Substituting the given Q* values for s', we have:

V*(s') = max(Q*(s', \(a_{1}\)), Q*(s', \(a_{2}\)), Q*(s', \(a_{3}\)), Q*(s', \(a_{4}\))

         = max(10, -1, 0, 11)

         = 11

Therefore, the value of V*(s') is 11.

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Answer:

x=5, y=1

Step-by-step explanation:

Isolate x for 5x-3y=22

5x-3y=22

Add 3y to both sides

5x-3y+3y=22+3y

Simplify

5x=22+3y

Divide both sides by 5

5x/5=22/5+3y/5

Simplify

x=22+3y/5

Substitute  x=22+3y/5

10*22+3y/5-4y=46

Simplify 10*22+3y/5-4y

10*22+3y/5=2(3y+22)

=2(3y+22)-4y

Expand 2(3y+22)

=6y+44-4y

Simplify 6y+44-4y

=2y+44

Isolate y for 2y+44=46

2y+44=46

Subtract 44 from both sides:

2y+44-44=46-44

Simplify

2y=2

Divide both sides by 2;

2y/2=2/2

Simplify;

y=1

For x=22+3*1/5 substitute y=1

y=22+3*1/5

22+3*1=25

=25/5

Divide the numbers;25/5=5

=5

x=5

The solutions to the system of equations are;

x=5, y=1

Step-by-step explanation:

Angles EXTERNAL to a circle are equal to 1/2 the difference of the intercepted arcs

   arcs are     17x   and  360 - 17x

75 = 1/2(17x - ( 360-17x)

75 = 1/2 ( 17x - 360 + 17x)

 150 = 34x-360

  510 = 17x

   x =30  

The following a probability model? what do we call the outcome No, the provided information is not sufficient to determine if it is a probability model. The outcome "red" is typically referred to as an event.

A probability model is a mathematical representation of a random experiment, where the sample space is defined, and probabilities are assigned to all possible outcomes. To determine if the given information is a probability model, we would need to know the complete list of possible outcomes, their corresponding probabilities, and ensure that the probabilities meet the necessary conditions (sum up to 1 and are non-negative).

Based on the limited information provided, we cannot determine if it is a probability model. The outcome "red" is called an event in the context of probability.

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Therefore the fraction 52/100 as a percentage is 52%.

52 expressed as a percentage is equal to 0.52%.

Given the following data:

To express 52 as a percentage:

A percentage can be defined as any number that is expressed as a fraction of hundred (100).

This ultimately implies that, a percentage indicates the hundredth parts of any given number.

For 52:

\(Percentage = \frac{52}{100}\)

Percentage = 0.52%.

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Answer:

268 students are absent

Step-by-step explanation:

First, multiply 775 by (8/25) to get the number of students out from the virus (probably weren't wearing masks or 6 ft apart from each other). This gives you 248 students. You also know that an additional 20 students are out due to other reasons. Add 248 and 20 and you get a total of 268 absent students.