Describe how the process of nucleation and growth can be used to control microstructure.
Answers
Nucleation and growth processes can be controlled to tailor the microstructure of a material to meet specific performance requirements.
Nucleation and growth are important processes in the control of microstructure in materials science.
Nucleation refers to the initial formation of a new phase, while growth refers to the increase in size and volume of that phase. These processes can be controlled to tailor the microstructure of a material to meet specific performance requirements.
In general, nucleation and growth can be controlled by manipulating factors such as temperature, pressure, and chemical composition. For example, in the production of metals, the rate of cooling can be controlled to control nucleation and growth.
Rapid cooling will result in small nucleation sites and slow growth, leading to a fine-grained microstructure. Slower cooling rates result in larger nucleation sites and faster growth, leading to a coarser-grained microstructure.
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Related Questions
Units of Planck's constant are {{c1::J s}}
Answers
The units of Planck's constant are Joule seconds (J*s).
Planck's constant is a fundamental physical constant that plays a crucial role in quantum mechanics. It relates the energy of a photon to its frequency through the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The unit of energy is Joules (J), and the unit of frequency is Hertz (Hz), so the unit of Planck's constant is J*s.
The significance of Planck's constant lies in its ability to bridge the gap between classical physics and quantum mechanics. It helps explain phenomena such as wave-particle duality, where particles can behave as waves and vice versa. Additionally, it is used in calculations related to atomic and subatomic particles, including the energy levels of electrons in atoms and the behavior of photons in lasers.
Overall, the units of Planck's constant demonstrate its importance as a fundamental constant in the field of quantum mechanics and its role in bridging the gap between classical physics and the mysterious realm of the subatomic world.
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If constant horizontal forces are exerted over the same distance on the cannon and on the marble after the launch, which object would require a force with a greater magnitude to completely stop it
Answers
The cannon would require a force with a greater magnitude to completely stop it compared to the marble after the launch.
When the same horizontal force is exerted on both the cannon and marble after the launch over the same distance, the cannon will require a greater force magnitude to completely stop it. This is because the cannon has a greater mass compared to the marble.The momentum of an object depends on its mass and velocity. The momentum of an object is calculated using the formula:p = mvp=mvwhere p is the momentum of the object, m is its mass, and v is its velocity. Since the cannon has a greater mass compared to the marble, it has a greater momentum. This means that to completely stop the cannon, a force with a greater magnitude is required compared to the marble.
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5. A child rides a pony on a circular track with a radius of 5 m Find the distance traveled and the placement
after the child has gone halfway around the track (8) Does the distance traveled increase, decrease, or stay the
same when the child completes one circuit of the track? Does the displacement increase, decrease, or stay the
same? Explain. (C) Find the distance and displacement ter a complete circuit of the track
Answers
The answer are :
A. Distance = 15.71 m , The displacement = 10 m
B. distance traveled will increase, displacement will decrease
C. The distance = 31.42 m , Displacement = 0
Difference between Distance and DisplacementDistance is a scalar quantity, while displacement is a vector quantity. Displacement is the distance travelled in a specific direction.
Given that a child rides a pony on a circular track with a radius of 5 m, after the child has gone halfway around the track
(A)
The distance traveled will be = 2\(\pi\)r / 2
The distance = πr
The distance = 22/7 x 5
The distance = 15.71 m
The displacement = 2r
The displacement = 2 x 5
The displacement = 10 m
(B) The distance traveled will increase as the child completes one circle of the track but the displacement will decrease because the displacement in one cycle of a circular motion is zero since it is a vector quantity.
(C) The distance after a complete circuit of the track = 2πr
The distance = 2 × 22/7 × 5
The distance = 31.42 m
The displacement after a complete circuit of the track will be zero.
That is;
Displacement = 0
Therefore, the distance traveled and the displacement after the child has gone halfway around the track are 15.7 m and 10 m respectively. While the distance and displacement after a complete circle of the track are 31.42 m and 0 respectively.
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A 32 kg object has a momentum of 480 kg m/s northward. What is the
object's velocity?
O A. 15,360 m/s
B. 15 m/s
O C. 448 m/s
OD. 0.067 m/s
Answers
Answer:
B. 15 m/s
Explanation:
p = m × v
480 = 32 × v
32v = 480
v = 480/32
v = 15 m/s
Answer:
B. 15 m/s
Explanation:
P=MV
480=32×v
v=15m/s
The general form of Gauss's law describes how a charge creates an electric field in a material, as well as in vacuum:∫ E. dA = qin/ε where ε = kε₀ is the permittivity of the material.(a) A sheet with charge Q uniformly distributed over its area A is surrounded by a dielectric. Show that the sheet creates a uniform electric field at nearby points with magnitude E= Q/2A ε.
Answers
The sheet with charge Q uniformly distributed over its area A creates a uniform electric field at nearby points with magnitude E = Q/2Aε.
To show this, we can use Gauss's law, which states that the electric flux through a closed surface is equal to the charge enclosed divided by the permittivity of the material.
Considering a Gaussian surface in the shape of a cylinder surrounding the charged sheet, with one end of the cylinder inside the dielectric and the other end outside, we can see that the electric field lines passing through the curved surface of the cylinder are perpendicular to the surface and have equal magnitudes, resulting in the same electric flux through each end of the cylinder.
The charge enclosed by the Gaussian surface is Q, and the area of each end of the cylinder is A. Therefore, the electric flux through each end of the cylinder is Q/ε.
Since the electric field is uniform, the magnitude of the electric field at nearby points can be found by dividing the electric flux by the area of the end of the cylinder, which is A. Therefore, E = Q/2Aε, indicating a uniform electric field created by the charged sheet.
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what payment rules apply when the patient sees an out-of-network physician
Answers
When a patient sees an out-of-network physician, the payment rules depend on the type of insurance plan the patient has.
In general, out-of-network care is not covered or is only partially covered by insurance plans, and the patient may be responsible for paying the difference between the amount charged by the out-of-network physician and the amount that the insurance plan covers.
For example, in a preferred provider organization (PPO) plan, patients may have some coverage for out-of-network care, but they will generally have to pay higher copays, coinsurance, and deductibles.
In a health maintenance organization (HMO) plan, out-of-network care may not be covered at all, except in emergency situations.
In some cases, out-of-network physicians may be willing to accept the insurance plan's payment as payment in full, but this is not guaranteed, and patients should check with their insurance plan and the physician's office to understand their financial responsibility.
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Flossie blew a tire 5 minutes into the second leg, up to that point she had traveled 10 km making her speed 2 km/m. It took 2 minutes to fix her tire. Flossie had to finish within 2 minutes in order to stay even with the evil Mabel. If Flossie had 8 km left what speed will she need to win?
Answers
Answer:
4km/m
Explanation:
She was going at 2km/m, so 2 kilometers per minute. She has 2 minutes therefore she needs to double her rate to 4 kilometers per minute.
A student drops two metallic objects into a 120 g steel container holding) 150 g of water at 25°C. One object is a 253 g cube of copper that is initially at 85°C, and the other is a chunk of aluminum that is initially at 5°C. To the surprise of the student, the water reaches a final temperature of 25°C, its initial temperature. What is the mass of the aluminum chunk? (please add an explanation)
Answers
Answer: 0.326kg
Explanation:
Given the following :
Mass of copper (Mc) = 253g
Initial temperature of copper (t1) = 85°C
Mass of aluminium(Ma)=?
Initial temperature of aluminum(t1) = 5°C
Specific heat capacity of aluminum(Ca) = 900
Specific heat capacity of copper (Cc) = 387
Final temperature(t2) = 5°C
Q = mc(t2 - t1)
Ma × Ca × (t2 - t1)a = Mc × Cc × (t2 - t1)c
Ma × 900 × (25 - 5) = 0.253 × 387 × (25 - 85)
Ma × 900 × 20 = 0.253 × 387 × 60
Ma × 18000 = 5874.66
Ma = 5874.66 / 18000
Ma = 0.32637
Ma = 0.326kg
The mass of the aluminum chunk dropped into the water is 325.5 g.
The given parameters;
mass of the steel, = 120 gmass of water = 150 ginitial temperature of water = 25 °Cmass of copper = 253 ginitial temperature of the copper = 85 °Cinitial temperature of the aluminum = 5 °Cfinal temperature of water = 25 °CSpecific heat capacity of aluminum = 0.9 J/gC Specific heat capacity of copper = 0.386 J/gCApply the principle of conservation of energy, the heat gained by the aluminum is equal to heat lost by the copper;
\(M_a C_a (t- t_a) = M_c C_c (t_c - t)\\\\M_a\times 0.9 \times (25-5) = 253 \times 0.386 \times (85-25)\\\\18 M_a = 5859.48\\\\M_a = \frac{5859.48}{18} \\\\M_a = 325 .5 \ g\)
Thus, the mass of the aluminum chunk dropped into the water is 325.5 g.
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When acceleration and velocity are in opposing directions, the speed will
Answers
Answer:
If the velocity and acceleration are in the same direction (both have the same sign - both positive or both negative) the object is speeding up. If the velocity and acceleration are in opposite directions (they have opposite signs), the object is slowing down.
Please mark my answer brainliest for further answers :)Two protons (each with rest mass M = 1. 67 × 10-27 kg) are initially moving with equal speeds in opposite directions. The protons continue to exist after a collision that also produces an ? particle. The rest mass of the ??ís m 9. 75 10-28 kg. (a) If the two protons and the ?? are all at rest after the collision, find the initial speed of the protons, expressed as a fraction of the speed of light. (b) What is the kinetic energy of each proton? Express your answer in MeV. (c) What is the rest energy of the n", expressed in MeV? (d) Discuss the relationship between the answers to parts (b) and (c)
Answers
The initial speed of the protons is approximately 0.166 times the speed of light. the kinetic energy of each proton is 2.10 MeV.the rest energy of the particle is approximately 18.3 MeV. we can see that the kinetic energy of the protons and the rest energy of the particle are related through the conservation of energy in the collision process.
(a) Let the initial speed of each proton be v. According to conservation of momentum, the total momentum of the system before the collision is zero (since the protons are moving in opposite directions with the same speed). After the collision, the total momentum is also zero since the particles are all at rest. Therefore, we can write:
2mv = (m + 2m)v
where m is the rest mass of each proton and v is the speed of the particle. Solving for v, we get:
v = (m/3m)c
where c is the speed of light.
Substituting the given values, we get:
v = (9.75 × 10\(^-28\) / (3 × 1.67 × 10\(^-27\))) × 3.00 × \(10^8\) m/s ≈ 0.166c
Therefore, the initial speed of the protons is approximately 0.166 times the speed of light.
(b) The kinetic energy of each proton can be found using the formula:
K.E. = (1/2)m\(v^2\)
Substituting the values of m and v from part (a), we get:
K.E. = (1/2) × 1.67 ×\(10^-27\) × (0.166c\()^2\) = 2.10 MeV
Therefore, the kinetic energy of each proton is 2.10 MeV.
(c) The rest energy of the particle can be found using the formula:
E = \(mc^2\)
Substituting the given value of m, we get:
E = 9.75 × \(10^-28\) × (3.00 × \(10^8)^2\)/ (1.60 × \(10^-13\)) ≈ 18.3 MeV
Therefore, the rest energy of the day particle is approximately 18.3 MeV.
(d) The sum of the kinetic energies of the two protons is equal to the difference between the total energy (rest energy + kinetic energy) of the protons before the collision and the total energy of the particles after the collision. Mathematically, we can write:
2K.E. = (2m)\(c^2\) - (m + 2m)\(c^2\)
Substituting the given values, we get:
2K.E. = (2 × 1.67 ×\(10^-27\))\(c^2\) - (2 × 9.75 × \(10^-28\))\(c^2\) ≈ 4.20 MeV
On the other hand, the rest energy of the particle is equal to the difference between the total energy of the system after the collision and the kinetic energy of the protons after the collision. Mathematically, we can write:
E = (m + 2m)\(c^2\)- 2K.E.
Substituting the given values, we get:
E = (2 × 9.75 × \(10^-28\))\(c^2\) - 2(2.10 MeV) ≈ 14.1 MeV
Therefore, we can see that the kinetic energy of the protons and the rest energy of the particle are related through the conservation of energy in the collision process.
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What is the equation that shows the inverse relationship between wavelength and frequency?
Answers
Answer:
V = f * λ velocity equals frequency * wavelength
If f is increased then λ must decrease for the velocity to remain constant.
i need help please answer
what is the activity in 2053 if in 2017 was 25kBq and the half life is 12?
Answers
Answer:
half or time for half the nuclei to decay.
Explanation:
How much force must be applied to a 60 N bowling ball to accelerate it straight upward at a rate of 3.5 m/s²?
Answers
F = ma
F is the force to be applied to a mass, m
m = Kilograms of the object to be accelerated mass
a = The force's acceleration, expressed in meters per second squared.
Consequently, the net force, or simply the total force applied to mass m:
F = ma
F = (60kg)(3.5 m/s^2)
F = 210 kg m/s^2
The unit of force commonly used in classical mechanics is Newtons, or F = 210 N.
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10 m/s^2 is an example of which vocabulary word?
Answers
Answer:
Acceleration.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
\(a = \frac{v - u}{t}\)
Where,
a is acceleration measured in \(ms^{-2}\)
v and u is final and initial velocity respectively, measured in \(ms^{-1}\)
t is time measured in seconds.
The S.I unit for measuring acceleration is meters per seconds square (m/s²).
Hence, 10 m/s^2 is an example of acceleration.
with what force will Annabella’s car hit a tree if her car has a mass of 5000 kg and an acceleration of 2 m/s2
Answers
Answer:
F=10,000N
Explanation:
F=ma
m=5000kg
a=2m/s^2
\(F=(5000kg)*(2m/s^{2} )\\\\\\\\F=10000N\)
Answer:
\(\boxed {\boxed {\sf 10,000 \ Newtons}}\)
Explanation:
We are asked to find the force of Annabella's car when it hits a tree.
According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, it is calculated using the following formula:
\(F=ma\)
The mass of the car is 5000 kilograms and the acceleration is 2 meters per second squared.
m= 5000 kg a= 2 m/s²Substitute the values into the formula.
\(F= (5000 \ kg)(2 \ m/s^2)\)
Multiply.
\(F= 10,000 \ kg*m/s^2\)
Convert the units. 1 kilogram meter per second squared is equal to 1 Newton, so our answer of 10,000 kg*m/s² is equal to 10,000 Newtons.
\(F= 10,000 \ N\)
Annabella's car hits the tree with a force of 10,000 Newtons.
What happens when a sound wave passes from water into air
Answers
Answer:
Explanation:
Sounds travel faster in object having high density proportion or matter. This is because particles vibrates and causing the other particle near to as well vibrate. Hence, when sound is moving from a higher dense medium like Water, the rate of traveling is high compare to it moving in air with less dense.
Examples
A Spiral Spring is compressed by 0.0am. Calculate the
energy stored in
ed in the Spring
Spring, ift
ng, if the force Constant is toor
solution
Answers
A spiral spring is compressed by 0.5 cm. The energy stored in the spring can be calculated using the formula \(E=1/2*k*x^2\). Given that the force constant is 200 N/m, we can calculate the energy stored in the spring to be 0.00025 J.
A spiral spring is compressed by 0.5 cm. Calculate the energy stored in the spring if the force constant is 200 N/m.The energy stored in the spring can be calculated using the formula: \(E=1/2*k*x^2\), where E is the energy stored, k is the force constant, and x is the displacement of the spring from its equilibrium position. Given that the spring is compressed by 0.5 cm, which is 0.005 m, and the force constant is 200 N/m, we can calculate the energy stored in the spring as follows: \(E = 1/2 * 200 N/m * (0.005 m)^2\) E = 0.00025 JTherefore, the energy stored in the spring is 0.00025 J. This means that when the spring is released, it will convert this energy into kinetic energy as it returns to its equilibrium position.For more questions on spring
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A 30-g car rolls from a hill 12 cm high and is traveling at 154 cm/s as it travels along a 275 cm horizontal track. What is the momentum of the car?.
Answers
The momentum of the car, given the data d from the question is 0.0462 Kg.m/s
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed as
Momentum = mass × velocity
With the above formula, we can determine the momentum of the car. Details below
How to determine the momentum of the carThe momentum of the car can be on rained as follow:
Mass of car = 30 g = 30 / 1000 = 0.03 KgVelocity of car = 154 cm/s = 154 / 100 = 1.54 m/sMomentum of car = ?Momentum = mass × velocity
Momentum of car = 0.03 × 1.54
Momentum of car = 0.0462 Kg.m/s
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The electric current through a wire varies with time as shown
The total charge flown across any cross section of the wire in time interval 0-T is
Answers
The total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.
option (2) is the correct answer.
What is the total current flowing in the wire?The total charge flown across any cross section of the wire in time interval 0-T is calculated as follows;
The total charge flowing = area under the curve
area under the curve = ¹/₂ x base of the triangle x height of the triangle
area under the curve = ¹/₂ x T x i₀
area under the curve = ¹/₂i₀T
Thus, the total charge flown across any cross section of the wire in time interval 0-T is determined from the area under the curve as ¹/₂i₀T.
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Sodium-24 has a half-life of 15 hours. after 45 hours, how much sodium-24 will remain of an original 50.0-g sample? 5.56 g 6.25 g 16.7 g 25.0 g
Answers
Answer:
6.25 gm
Explanation:
1 /2 * 1/2 * 1/2 = 1/8th of the original
50/8 = 6.25 gm
Answer:
its b
Explanation:
trust
A hydraulic system contains 3 pistons. The input piston has an area of 0.625 in2, one of the output pistons ( piston A ) has an unknown area and the other piston ( Output Piston ) has a diameter of 3.75 inches. If system pressure is 1,440 psi, and Piston A is supporting 20,000 lb, what is the area of Piston A
Answers
The area of Piston A is 13.88 in^2
What is a hydraulic system?
The hydraulic system functions by using pressurized fluid. The power of liquid fuel in hydraulics is significant and as a result, they are commonly used in heavy equipment.
Hydraulic system simply means a mechanical function that operates through the force of liquid pressure.
Here
A hydraulic system contains 3 pistons.
Pressure, P = 1440 psi
for piston A:
Area, A= 0.625 in^2
Force, F = 20,000 lb
We know that,
Force = Pressure x Area
F = P x A
Area ( piston A) = F / P
A = 20,000 / 1440
A = 13.88 in^2
Hence,
The area of Piston A is 13.88 in^2
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A ball is thrown horizontally at a height of 1.6 metres above the ground, with initialspeed 14 m s^-1a)Find the time of flight of the ball, giving the answer as a fraction.b)Find the range of the ball.
Answers
Given:
The initial height of the ball, h=1.6 m
The initial speed of the ball, u=14 m/s
To find:
a) The time of flight of the ball.
b) The range of the ball.
Explanation:
As the ball is thrown horizontally, the ball will have no vertical component of the initial velocity. The velocity of the ball is completely horizontal.
Thus the vertical component of the initial velocity of the ball is u_y=0 m/s.
The horizontal component of the initial velocity of the ball is u_x=u=14 m/s.
a)
From the equation of motion,
\(h=u_yt+\frac{1}{2}gt^2\)Where g is the acceleration due to gravity and t is the time of flight of the ball.
On substituting the known values,
\(\begin{gathered} 1.6=0+\frac{1}{2}\times9.8\times t^2 \\ \implies t=\sqrt{\frac{2\times1.6}{9.8}} \\ =0.57\text{ s} \end{gathered}\)b)
The range of the ball is given by,
\(R=u_xt\)On substituting the known values,
\(\begin{gathered} R=14\times0.57 \\ =7.98\text{ m} \end{gathered}\)Final answer:
a) The time of flight of the ball is 0.57 s
b) The range of the ball is 7.98 m
Draw a free-body diagram for the ear of a person properly wearing a mask. You may wish to refer to the figure
below to aid you. Note that when properly worn, the mask will pull at an angle below the horizontal. Improper
usage, such as shown in the image on the right, may result in a completely horizontal pull (the arrows in the figure
are not force arrows), but we wish to avoid this. Choose your own labels for the forces but use the angle the
mask force makes with the horizontal.
Include your free-body diagram in your reply. Also, using the math editor, write the component equations of
equilibrium relative to vertical and horizontal axes. Use the labels for your forces, as well as the angle. You may
substitute for the force of gravity, using the mass of the ear.
Answers
Answer:
Rₓ - F cos θ = 0 , R_y - Fsin θ - W = 0
Explanation:
For this exercise we have a static equilibrium problem,
∑ F =0
In the attachment we have the forces involved, the weight (W) with vertical direction, the force towards the mask (F) and the reaction force of the ear that we will approximate by its vertical and horizontal components (Rₓ and R_y)
Let's use trigonometry to decompose the force F
sin θ = Fₓ / F
cos θ = F_y / F
Fₓ = F sin θ
F_y = F cos θ
we write the equations of equilibrium
X axis
Rₓ - F cos θ = 0
Y axis
R_y - Fsin θ - W = 0
In _________, atrial contraction occurs at such a rapid rate that discrete P waves separated by a flat baseline cannot be seen
Answers
In atrial flutter, atrial contraction occurs at such a rapid rate that discrete P waves separated by a flat baseline cannot be seen.
A current of 2 A flows through a resistor. The voltage across the resistor is 18 V.
pls I need this
Answers
Answer:
\(R=9\ \Omega\)
Explanation:
Given that,
Current, I = 2 A
Voltage across the resistor, V = 18 V
We need to find the value of resistance of the resistor. Let the resistance be R. We can find it using Ohm's law i.e.
V = IR
Where
R is the resistance of the resistor
\(R=\dfrac{V}{I}\\\\R=\dfrac{18}{2}\\\\R=9\ \Omega\)
So, the resistance of the resistor is equal to \(9\ \Omega\).
Question 15 of 25
which type of reaction will usually happen fastest?
a. combustion
b. tarnishing
c. rusting
d. milk going bad
submit
Answers
An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms voltage across the alternating source is 442 v. Calculate the rms current
Answers
An electric motor has an effective resistance of 29. 4 ω and an inductive reactance of 42. 6 ω. When working under load. the rms voltage across the alternating source is 442 v. The rms current will be 8.54 A
AC stands for “Alternating Current,” meaning voltage or current that changes polarity or direction, respectively, over time. AC electromechanical generators, known as alternators, are of simpler construction than DC electromechanical generators.
RMS or root mean square current/voltage of the alternating current/voltage represents the D.C current/voltage that dissipates the same amount of power as the average power dissipated by the alternating current/voltage. For sinusoidal oscillations, the RMS value equals peak value divided by the square root of 2.
I (RMS) = RMS voltage / \(\sqrt{R^{2}+ X_{L} { ^{2} }\)
= 442 / \(\sqrt{29.4^{2} + 42.6^{2} }\)
= 442 / \(\sqrt{864.36 + 1814.76}\)
= 442 / \(\sqrt{2679.12}\)
= 8.54 A
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pls help brainliest if correct
Answers
Hmm lets see.. I think its
Mechanical---->Mechanical---->Electrical
So mechanical from the water, Then mechanical again from the wheel then through the wire which is electrical and it turns the fan on.
(D) The potential energy of a particle at a location is the potential at that location times the charge.
In this case, the potential is kQ/d + kQ/d = (2kQ/d)
The figure above shows two particles, each with a charge of +Q, that are located at the opposite corners of a square of side d.
What is the potential energy of a particle of charge +q that is held at point P ?
Answers
For the two charges with charge +Q placed at opposite corners of the square, the potential at the point p is determined as (2kQ) / d V.
The electric potential is the work done in bringing the unit positive charge from one point to another. It equals the charge and distance between the charges. The potential is directly proportional to the charges and inversely proportional to the distance of separation of charges.
The potential is defined as, V = kQ/ r. In a square at a point p, the potential due to charge Q₁ is V₁ = kQ / d (where d is the side length of the square) and due to charge Q₂ is V₂ = kQ / d.
The net electric potential is,
V = V₁ + V₂
= (kQ / d) + (kQ / d)
= 2 (kQ/d)
The potential at a point p in a square is V = 2 (kQ/d) V.
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Which will a positively charged object attract