Answer:
Domain: (-∞,∞)
Range: -1
Step-by-step explanation:
Domain means the x-coordinates covered:
(-∞,∞)
Range means the y-coordinates covered:
Only -1 because there are no other existing y-coordinates.
Hi can any one teach me this constant difference
The constant differences between the consecutive terms are 2 (a); 2 (b), -3 (c), 7 (d), 1(e), and 6(f).
How do you find the constant difference in a sequence of numbers?In math, the constant difference can be defined as the number that defines the pattern of a sequence of numbers. This means that number that should be added or subtracted to continue with the sequence.
Due to this, to determine the constant difference it is important to observe the pattern and find out the number that should be added. For example, if the sequence is 2, 4, 6, 8, there is a difference of 2 between each of the numbers and this is the constant difference.
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need help.please.
\(4y \times 2\)
ignore the 4y×2 i need gelp with whats in the picture
The value of x are:
(A) = 10
(B) = 39
(C) = 56
(D) = 8
(E) = 99
(F) = 12
What is the arc length of a circle?The arc length of a circle is the distance between two points on the curve of the circle.
We have,
The angle formed by two chords inside a circle:
= 1/2 x the sum of the intercepted arc.
Straight line angle = 180°
Now,
(A)
180 - 129 = 51
51 = 1/2 x (4x - 4 + 5x + 16)
51 = 1/2 x (9x + 12)
51 x 2 = 9x + 12
102 = 9x + 12
90 = 9x
x = 10
(B)
47 = 1/2 x (x + 20 + x - 4)
47 x 2 = 2x + 16
94 = 2x + 16
78 = 2x
x = 39
(C)
Arc length = 2 x angle subtended at the circle by the arc length.
2(x-3) = 106°
2x - 6 = 106
2x = 112
x = 56
(D)
40 = 1/2 x (6x + 4x)
40 = 1/2 x 10x
80 = 10x
x = 8
(E)
180 - x = 1/2 x (95 + 67)
180 - x = 1/2 x 162
180 - x = 81
180 - 81 = x
99 = x
x = 99
(F)
2(6x - 1) = 360 - (152+ 66)
12x - 2 = 142
12x = 142 + 2
12x = 144
x = 12
Thus,
The value of x are:
(A) = 10
(B) = 39
(C) = 56
(D) = 8
(E) = 99
(F) = 12
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Solve the following system of linear equations.x + 2y + z = - 32x - 3y - 3z = 173x - 2y + 4z = - 23Answerx =y =z =
ANSWER
\(\begin{gathered} x=1 \\ y=1 \\ z=-6 \end{gathered}\)EXPLANATION
We want to solve the given system of linear equations:
\(\begin{gathered} x+2y+z=-3 \\ 2x-3y-3z=17 \\ 3x-2y+4z=-23 \end{gathered}\)From the first equation, make x the subject of the formula:
\(x=-2y-z-3\)Substitute the equation above into the second and third equations:
\(\begin{gathered} 2(-2y-z-3)-3y-3z=17 \\ -4y-2z-6-3y-3z=17 \\ \Rightarrow-7y-5z=23 \end{gathered}\)and:
\(\begin{gathered} 3(-2y-z-3)-2y+4z=-23 \\ -6y-3z-9-2y+4z=-23 \\ \Rightarrow-8y+z=-14 \end{gathered}\)Now, we have a system of two equations with two variables:
\(\begin{gathered} -7y-5z=23 \\ -8y+z=-14 \end{gathered}\)From the second equation, make z the subject of the formula:
\(z=8y-14\)Substitute the equation above into the first equation and solve for y:
\(\begin{gathered} -7y-5(8y-14)=23 \\ -7y-40y+70=23 \\ \Rightarrow-47y=23-70=-47 \\ \Rightarrow y=\frac{-47}{-47} \\ y=1 \end{gathered}\)Substitute the value of y into the equation for z:
\(\begin{gathered} z=8(1)-14=8-14 \\ z=-6 \end{gathered}\)Finally, substitute the values of y and z into the equation for x:
\(\begin{gathered} x=-2(1)-(-6)-3 \\ x=-2+6+3 \\ x=1 \end{gathered}\)Hence, the solution to the system of linear equations is:
\(\begin{gathered} x=1 \\ y=1 \\ z=-6 \end{gathered}\)Use the Laws of logarithms to rewrite the expression
The expression log₃(x²∛y²) using the laws of logarithms is 2log₃(x) + 2/3log₃(y)
Rewriting the expression using the laws of logarithmsFrom the question, we have the following parameters that can be used in our computation:
log₃(x²∛y²)
The product law of logarithms states that
log(ab) = log(a) + log(b)
Using the above as a guide, we have the following:
log₃(x²∛y²) = log₃(x²) + log₃(∛y²)
The power law of logarithms states that
log(aᵇ) = blog(a)
Using the above as a guide, we have the following:
log₃(x²∛y²) = 2log₃(x) + 2/3log₃(y)
This means that the values of A and B are A = 2 and B = 2/3
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MAX POINTS PLEASE HELP Will make Brainliest
What is the period and frequency of the function graphed and how would the equation be written
\(\qquad\qquad\huge\underline{{\sf Answer}}♨\)
The required equation is :
\(\qquad \sf \dashrightarrow \:a \cos(bx) + k\)
Now, let's find the required values :
period (p) = 6
[distance between any successive Crest or trough]
a = - 4 (flipped)
b = 2π/p = 2π/6 = π/3
k = -2
Distance of starting position from origin = k
Now, plug in the values ~
\(\qquad \sf \dashrightarrow \: - 4 \cos( \frac{\pi}{3} x) - 2\)
Not passing through origin (it's cosine)
Period:-
Difference between any two crests |-3-3||-6|6Now
Frequency:-
\(\\ \rm\dashrightarrow \nu=\dfrac{1}{T}\)
\(\\ \rm\dashrightarrow \nu=\dfrac{1}{6}\)
\(\\ \rm\dashrightarrow \nu=0.167Hz\)
Joyce paid $154.00 for an item at the store that was 30 percent off the original price. What was the original price?
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4. Is the following relation linear, quadratic or cubic? If it is linear, find the equation. Explain your reasoning and include all your work in your final answer; P = {(x, y), (1 ,3), (2,9), (3,17), (4,27) ,(5,39) ,(6,53)}
The following relation P = {(x, y), (1 ,3), (2,9), (3,17), (4,27) ,(5,39) ,(6,53)} is a quadratic relation by virtue of its second differences.
Quadratic relationThe kind of function which is defined by the pair of coordinates as given in the task content can be determined by assessing the first, second or third differences in y-values at a constant increment of x.
Hence, for the pair of coordinates given, we have;
P = {(x, y), (1 ,3), (2,9), (3,17), (4,27) ,(5,39) ,(6,53)}
First differences are; +6, +8, +10, +12, +14.
Hence, since the differences are not constant, we must check for the second differences;
Second differences; +2, + 2, +2, +2.
On this note, since the second differences are constant, it follows that the relation in discuss represents a quadratic function.
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There are 9 players on a youth baseball team. To create the lineup, the coach chooses three players to play pitcher, catcher, and first base. How many ways can the coach choose these three positions?
Step-by-step explanation:
how many ways can the coach make out the batting order? 9! = 9 · 8 · 7 · 6 · 5 ·4 · 3 · 2 · 1 = 362,880 .
Please answer quick and just write explanation quick pls hurry quick for brainlessly uu
Answer:
35 (C)
Step-by-step explanation:
Answer:
B) 30
Step-by-step explanation:
This is a pretty tricky question. If you draw the line of best fit and go to 9 salespeople, it would be closer to 30 compared to any of the other choices.
David and Ken took part in a cycling race. Both of them did not change their speed throughout the race. David completed the race in 5 hours while Ken took 7 hours. Ken's average speed was 9.8 km/h less than David's average speed.
A) What was David average speed
B)What was the distance of the cycling race?
Let's assume David's average speed is S km/h.
A) To find David's average speed, we can use the formula: Speed = Distance / Time.
David completed the race in 5 hours, so his speed is S km/h. Therefore, we have:
S = Distance / 5
B) Ken's average speed is 9.8 km/h less than David's average speed, which means Ken's average speed is (S - 9.8) km/h.
Ken took 7 hours to complete the race, so we have:
S - 9.8 = Distance / 7
Now, we can solve the system of equations to find the values of S and Distance.
From equation (1): S = Distance / 5
Substitute this into equation (2):
Distance / 5 - 9.8 = Distance / 7
Multiply both sides of the equation by 35 to eliminate the denominators:
7 * Distance - 35 * 9.8 = 5 * Distance
7 * Distance - 343 = 5 * Distance
Subtract 5 * Distance from both sides:
2 * Distance - 343 = 0
Add 343 to both sides:
2 * Distance = 343
Divide both sides by 2:
Distance = 343 / 2 = 171.5 km
Therefore, the distance of the cycling race is 171.5 kilometers.
To find David's average speed, substitute the distance into equation (1):
S = Distance / 5 = 171.5 / 5 = 34.3 km/h
So, David's average speed was 34.3 km/h.\(\)
Answer:
A) 34.3 km/h
B) 171.5 km
Step-by-step explanation:
Since Ken's average speed is said to be 9.8km/h less than David's average speed, and we know that Ken's average speed is dependent on him traveling for 7 hours, then we have our equation to get the distance of the cycling race:
\(\text{Ken's Avg. Speed}=\text{David's Avg. Speed}\,-\,9.8\\\\\frac{\text{Distance}}{7}=\frac{\text{Distance}}{5}-9.8\\\\\frac{5(\text{Distance})}{7}=\text{Distance}-49\\\\5(\text{Distance})=7(\text{Distance})-343\\\\-2(\text{Distance})=-343\\\\\text{Distance}=171.5\text{ km}\)
This distance for the cycling race can now be used to determine David's average speed:
\(\text{David's Avg. Speed}=\frac{\text{Distance}}{5}=\frac{171.5}{5}=34.3\text{ km/h}\)
Therefore, David's average speed was 34.3 km/h and the distance of the cycling race was 171.5 km.
Alex learned 80 new vocabulary words for his English exam. The following function gives the number of words he remembers after t days: W(t) = 80(1 - 0.1t)^3 What is the instantaneous rate of change of the number of words Alex remembers after 5 days? Choose 1 answer: A. 10 days B. 10 words per day C. -6 days D. -6 words per day
The instantaneous rate of change is -6 words per day,
the number of words Alex remembers after 5 days, option (D).
What is the instantaneous rate of change ?
An instantaneous rate is the rate at some instant in time. An instantaneous rate is a differential rate: -d[reactant]/dt or d[product]/dt. We determine an instantaneous rate at time t: by calculating the negative of the slope of the curve of concentration of a reactant versus time at time t.
Have given,
Alex learned 80 new vocabulary words
and after t days he learned,
W(t) = \(80 (1-0.1t)^{3}\)
differentiate respect of t
W'(t) = \(80 \frac{d}{dt} (1-0.1t)^{3}\)
W'(t) = \(80 * 3(1-0.1t)^{2} \frac{d}{dt}(1-0.1t)\)
W'(t) = \(240(1-0.1*5)^{2} (0.1)\)
W'(t) = 6
That's mean , the instantaneous rate of change is -6 words per day.
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How does 899,451 compare to 756,451
899,452 is greater than 756,451
899,452 > 756,451
Given,
899,451
756,451
We need to compare these numbers.
What is the place value of a large number?Consider 967543
3 - ones
4 - tens
5 - hundreds
7 - thousands
6 - ten thousands
9 - hundred thousands
Find the highest place value in 899,452.
- 8 hundred thousands
We can read this as eight hundred ninety-nine thousand four hundred fifty-two.
Find the highest place value in 756,451.
- 7 hundred thousands
Seven hundred fifty-six thousand four hundred fifty one
Thus,
899,452 is greater than 756,451
899,452 > 756,451
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Help plz
For khan academy
Answer:
-18y =1
It is simple addition
The mean length of 4 childrens' index finger is 8.7cm.
The mean length of 11 adults' index finger is 13.4cm.
What is the mean length (rounded to 2 DP) of these 15 people's index finger?
The mean length (rounded to 2 DP) of these 15 people's index finger is 12.15 cm.
What is mean?It is defined as the single number that represents the mean value for the given set of data or the closed value for each entry given in the set of data.
It is given that:
The mean length of 4 children's index fingers is 8.7cm.
The mean length of 11 adults' index fingers is 13.4cm.
The mean of 15 people = [8.7x4 + 13.4x11]/15
The mean of 15 people = [34.8 + 147.4]/15
= 182.2/15
= 12.1466 cm
= 12.15 cm
Thus, the mean length (rounded to 2 DP) of these 15 people's index fingers is 12.15 cm.
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K mola ofkg o okdgmbo9k
Answer: c
Step-by-step explanation:
4. Solve the equation using square roots.
x2 + 10 = 9
Answer:
+1/-1
Step-by-step explanation:
assuming the original phrase is x^2
x^2 + 10 = 9
x^2 = 1
x = +/- 1
find the surface area
The Surface area of Triangular Prism is 132 cm².
We have have the dimension of prism as
Sides = 3 cm, 4 cm, 5 cm
and, l = 10 cm
and, b= 4 cm
Now, Surface area of Triangular Prism as
= (sum of sides) l + bh
= (3 + 4 + 5)10 + 4 x 3
= 12 x 10 + 12
= 120 + 12
= 132 cm²
Thus, the Surface area of Triangular Prism is 132 cm².
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y
4
Solve for y.
Then, find the side lengths of the
largest triangle.
Fill in the green blank.
8
X
2
+
2
8
y
y
[?]
X
Enter
Help
Skip
Answer:
y = 4\(\sqrt{5}\) , ? = 10
Step-by-step explanation:
using Pythagoras' identity on the smallest right triangle
x² = 4² + 2² = 16 + 4 = 20 ( take square root of both sides )
x = \(\sqrt{20}\) = \(\sqrt{4(5)}\) = \(\sqrt{4}\) × \(\sqrt{5}\) = 2\(\sqrt{5}\)
using Pythagoras' identity on the middle right triangle
y² = 8² + 4² = 64 + 16 = 80 ( take square root of both sides )
y = \(\sqrt{80}\) = \(\sqrt{16(5)}\) = \(\sqrt{16}\) × \(\sqrt{5}\) = 4\(\sqrt{5}\)
using Pythagoras' identity on the largest right triangle
?² = x² + y² = (2\(\sqrt{5}\) )² + (4\(\sqrt{5}\) )² = 20 + 80 = 100
Take square root of both sides
? = \(\sqrt{100}\) = 10
A car dealership sold 212 cars in 4 months. At what rate did the dealership sell cars in cars per month?
Answer: 59 cars per month
Step-by-step explanation:
please answer and explain
Answer:
Trapezoid
Step-by-step explanation:
It's a quadrilateral and it only has one pair of parallel sides.
P(-3,-5) and Q(1.–3) represent points in a coordinate plane. Find the midpoint of Pe.
By formula,
Midpoint between two points PQ =
\((\frac{x_2+x_1}{2},\text{ }\frac{y_2+y_1}{2})\)\(\begin{gathered} (\frac{1+-3}{2},\text{ }\frac{-3+\text{ -5}}{2}) \\ \\ \frac{-2}{2},\text{ }\frac{-8}{2}\text{ = (-1,-4)} \\ \\ \end{gathered}\)So, (-1,-4) (option 3)
The recipe for beef stew calls for 1/4 teaspoon of pepper for every 3 potatoes. If 9 potatoes are used, how much pepper is needed?
Which proportion represents this problem?
Answer:
3/4 pepper
Step-by-step explanation:
if you add 1/4 3 time you get the answer
Answer:
Since 9 is 3 times the denominator of the first ratio, multiply the numerator of the first ratio by 3 to get the numerator of the second ratio. The amount of pepper is 3/4 teaspoon.
OKJZ IOEAFQWKEJSIERRA CARDEKSAMXCQEQEWKDSXMZ
Answer:
\((4f)^3 = 64*f^3\)
\((-\frac{3}{2}t^2)^2 = \frac{9}{4}t^4\)
Step-by-step explanation:
Solving (a):
\((4f)^3\)
Apply law of indices:
\(x^3 = x * x * x\)
So, we have:
\((4f)^3 = 4f * 4f * 4f\)
Rewrite as:
\((4f)^3 = 4 * 4 * 4*f*f*f\)
\((4f)^3 = 64*f^3\)
Solving (b):
\((-\frac{3}{2}t^2)^2\)
Apply law of indices:
\(x * x = x^2\)
So, we have:
\((-\frac{3}{2}t^2)^2 = (-\frac{3}{2}t^2) * (-\frac{3}{2}t^2)\)
Remove brackets
\((-\frac{3}{2}t^2)^2 = -\frac{3}{2}t^2 * -\frac{3}{2}t^2\)
Rewrite as:
\((-\frac{3}{2}t^2)^2 = -\frac{3}{2}*-\frac{3}{2}*t^2 * *t^2\)
\((-\frac{3}{2}t^2)^2 = \frac{3}{2}*\frac{3}{2}*t^4\)
\((-\frac{3}{2}t^2)^2 = \frac{9}{4}*t^4\)
\((-\frac{3}{2}t^2)^2 = \frac{9}{4}t^4\)
A summary of the two stocks is shown.
Name of Stock Symbol Closing Price Day 1 Closing Price Day 2 Closing Price Day 3
Metropolis, Ltd MTP 17.95 18.25 18.28
Suburbia, Inc SBR 5.63 4.98 5.25
Suppose you purchase 65 shares of Metropolis stock and 50 shares of Suburbia stock on Day 1 at the closing price. Which day, during the following two days, would be the best to sell both stocks and by how much?
Day 2 is the best by $13.00.
Day 3 is the best by $13.00.
Day 2 is the best by $2.45.
Day 3 is the best by $2.45.
The day, from the following two days, which would be the best to sell both stocks with the closing price is day 3 by an amount of $2.45.
Given are the closing prices of two stocks in three days.
If you purchase 65 shares of Metropolis stock and 50 shares of Suburbia stock on Day 1 at the closing price,
Amount invested = (65 × 17.95) + (50 × 5.63) = $1448.25
If the stock is sold in day 2,
Amount received = (65 × 18.25) + (50 × 4.98) = $1435.25
Profit = $1435.25 - $1448.25 = -$13
If the stock is sold in day 3,
Amount received = (65 × 18.28) + (50 × 5.25) = $1450.7
Profit = $1450.7 - $1448.25 = $2.45
The profit is more for day 3 than day 2.
Hence it is best to sell on day 3 by $2.45.
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shop A sells egg at $1.50 percenthalf dozen where as shop B sells eggs of the same size and quality at $2.40 per dozen.which shop isselling eggs at a cheaper rate?
Answer:
Shop B
Step-by-step explanation:
\(Shop\ A\ sells\ eggs\ at\ $1.50\ per\ half\ dozen,\ so\ it\ sells\ egg\ at\ $1.50\times2\ per\ dozen,\ which\ means\ $3.00\ per\ dozen.\)
\(\left\{$3.00\ is\ more\ than\ $2.40\right\}\)} \(Shop\ B\ sells\ eggs\ cheaper\ than\ Shop\ A.\ So\ we\ should\ buy\ the\ eggs\ from\ shop\ B\)
I hope this helps you
:)
A box of chocolate contains 6 milk chocolates, 5 dark chocolates and
3 white chocolates. You randomly choose three chocolates to eat.
What is the probability of first pulling a milk chocolate, second pulling
a white chocolate, and then lastly choosing a milk chocolate?
Write your answer ar a percentage and round the the nearest tenth.
0 4.6%
04%
03.3%
04.1%
Answer:
i think is 3.3 but i dont know
Step-by-step explanation:
What’s the equation of a line with an undefined slope passing through (-1,7)
Answer:
y=7
Step-by-step explanation:
if two differnt people are randomly selected, without replacement, from the 884 subjects, find the probability that they are both women. Round to four decimal places.O 0.00003906O 3274O 2500O 3276
The probability of randomly selecting two women from 884 subjects is 1.
The probability of randomly selecting two women from 884 subjects can be calculated using the following formula: P(A and B) = P(A) x P(B). In this case, A is the event of randomly selecting a woman from 884 subjects and B is the event of randomly selecting a second woman from the remaining 883 subjects.
Therefore, P(A) = 884/884 = 1 and P(B) = 883/883 = 1. Thus, P(A and B) = 1 x 1 = 1. Then, the probability of randomly selecting two women from 884 subjects is 1. To round to four decimal places, the probability is 0.0000.
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The sides of a triangle measure a meters
and 2a meters. What are the possible
side lengths for the third side in terms
of a? Show your work.
Answer: any values between a and 3a
Step-by-step explanation:
To determine the possible side lengths for the third side of the triangle, we need to use the Triangle Inequality Theorem. This theorem states that for any triangle, the sum of the lengths of any two sides must be greater than the length of the third side.
Let's call the length of the third side x. Then, based on the Triangle Inequality Theorem, the following two inequalities must be true:
a + 2a > x (the sum of the first and second sides is greater than the third side)
a + x > 2a (the sum of the first and third sides is greater than the second side)
2a + x > a (the sum of the second and third sides is greater than the first side)
Solving the first inequality for x gives us:
x < 3a
Solving the second inequality for x gives us:
x > a
Solving the third inequality for x gives us:
x > -a
Combining these three results, we find that the possible values for the third side length x are:
a < x < 3a
So, the possible lengths for the third side in terms of a are any values between a and 3a, inclusive.
Question 3
34° Celsius is equal to
o
Fahrenheit
Hi
Below the formulas to convert Celsius into Fahrenheit.
9/5 C +32 = degree in fahrenheit.
Where C is the degree in celsius. So have a try and find the answer.