Difference between Lewis Dot Diagrams and Lewis Structures

Answer:

A

Explanation:

I am going to use the example of Enzymes, which are simply catalysts, but of biological origin. These enzymes would provide another path, which has a lower activation energy. In this way, catalysts reduce the amount of energy required to start the reaction.

Answer:

Option c.

Explanation:

According to Newton's law, formula to solve this problem is:

F = m . a

Mass → 1000 kg

a → 3 m/s²

F = 1000 kg . 3m/s² →  3000 N

1 N = 1 kg .  m/s²  according to SI, Internation System of units.

Answer:

Explanation:

WAKE FOR CLIMATE CHANGE IS NOT FAKE

SAVE THE GLACIERS

HELP THE ARCTIC ANIMALS

The dot structure of the compound that is referred to here is shown in  the image attached.

A dot structure, often called a Lewis structure or an electron dot structure, depicts how atoms and valence electrons are arranged in a molecule or ion. Around the atomic symbols, valence electrons are represented by dots.

Each atom's symbol in a dot structure is surrounded by dots that stand in for the atom's valence electrons. The electrons in an atom's outermost shell known as valence electrons participate in chemical bonding.

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Answer:

The correct answer is - sulfur.

Explanation:

In the periodic table, there are 18 groups and 7 rows or periods arranged according to their atomic number or electronic configuration. In the question, it is mentioned that the desired element atomic mass is less than the atomic mass of the selenium which is 78.96, and more than oxygen which is 15.99 with 6 electron valence and present in the third row.

As it has 6 valency of electron it must be in the 16 group of the table that comprises the 6 valency and as it is located in the 3rd row it must be sulfur that also has an atomic mass between selenium and oxygen.

The bottom of the arrow points to the location where the electron or electron pair was created, and the top of the arrow indicates where the electron or electron pair will ultimately be located therefore, the given statement is true.

Throughout the processes of bond breaking and/or bond formation, the movement (flow) of electrons is represented by curved arrows.

A. The motion of a single electron is represented by an arrow that is curved and has a single head.

B. The motion of an electron pair is represented by an arrow with two heads that is curved and curved in the middle.

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Answer: all of them

Answer:

all the above

Explanation:

The volume of HI required to react with \(Pb(NO_3)_{2}\) to completely precipitate the Lead is 0.197 ml.

First, the balanced chemical equation of the reaction of HI with  \(Pb(NO_3)_{2}\),

HI + \(Pb(NO_3)_{2}\) =\(PbI_2\) + \(HNO_3\)

From the reaction,

One mole of HI reacts with one mole of  \(Pb(NO_3)_{2}\) to completely precipitate the Less Iodide solution.

Mole = molarity × volume of solution.

So,

Moles of  \(Pb(NO_3)_{2}\) are 0.700 moles.

Let the volume 3.55M of HI used to be V,

So,

0.700 = 3.55 × Volume

Volume = 0.197 ml.

So, 0.197 ml of HI is required to completely precipitate the lead solution.

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The second option is not true of standard reduction potential. In the standard hydrogen electrode, electrons on the surface of the electrode combine with H+ ions in solution to produce hydrogen gas.

The third option is also not true as in the standard hydrogen electrode, hydrogen gas is reduced to H+ ions. The first option is true for standard reduction potential. The fourth option is also true as the standard hydrogen electrode has a reduction potential of exactly 0 V. Standard reduction potential is a measure of the tendency of a chemical species to acquire electrons and undergo reduction. It is measured relative to the standard hydrogen electrode.

The statement that is not true of standard reduction potential is: "In the standard hydrogen electrode, liquid hydrogen is combined with 1 M NaCl solution." The standard hydrogen electrode (SHE) uses a solution of HCl or other strong acid with H+ ions, not NaCl. The SHE serves as a reference electrode with a reduction potential of exactly 0 V, where hydrogen gas is oxidized to H+ ions, and electrons on the electrode's surface combine with H+ ions in the solution to produce hydrogen gas.

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Answer:

false

Explanation:

jk true

Answer:

1 mil/ 15 min

A giraffe walked 1 mile in 15 minutes. So the unit rate for it will be 1mil/ min.

Unit is some standards to measure the physical quantity of an object. There are two unit systems as SI unit and the CGS unit.

There are standard six quantities which have units :

Apart from this, some quantities have derived units. These quantities are force, energy, and power.

In the given question, the giraffe walked 1 mile in 15 minutes, therefore

Walking distance of giraffe= 1mile/ 15 min.

Therefore, A giraffe walked 1 mile in 15 minutes. So the unit rate for it will be 1mil/ min.

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Answer:

.........................

..

Answer:

helium and neon are both noble gases their outermost shells are full or stable the elements will agree with the statement s above

The statement that best describes a mixture is -

Explanation:

A mixture is that form of matter in which two or more substances are simply mixed in any proportion and it can be separated back to their original form.

In Homogeneous Mixtures, the composition is uniform throughout such as sugar in water , salt in water , sulphur in carbon disulphide , water and alcohol , whereas Heterogeneous Mixtures has non Uniform composition such as sand and salt , sugar and salt , wood , blood , water in soil etc.

Answer:

European stability mechanism

This is calculated by dividing the mass of aluminum (10.7 g) by its molar mass (26.98 g/mol), resulting in 0.395 mol.

To find the amount of pure substance (in moles) in 10.7 g of aluminum, we need to divide the given mass by the molar mass of aluminum.

The molar mass of aluminum is given as 26.98 g/mol.

Therefore, the amount of pure substance (in moles) in 10.7 g of aluminum can be calculated as:

moles = mass/molar mass

moles = 10.7 g/26.98 g/mol

moles = 0.396 moles (rounded to three significant figures)

So, there are approximately 0.395 moles of pure substance (aluminum) in 10.7 g of aluminum.

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The larger the oligonucleotides , the less distance it will travel. Therefore, in the order of decreasing distance traveled:

AAACT → AGGGAAG → CTACGTGCG → TTTGCGTATTT → GTATGTTCACCCGTC

Oligonucleotides:

Oligonucleotides are short DNA or RNA molecules, oligomers, widely used in genetic testing, research, and forensics. Typically produced in the laboratory by solid-phase chemical synthesis, these small fragments of nucleic acids can be made into single-stranded molecules by user-specified sequences, making them essential for artificial gene synthesis, polymerase chain reaction (PCR), DNA sequencing, molecular cloning and molecular probes.

Oligonucleotides are chemically synthesized using building blocks, protected phosphonamidites, natural or chemically modified nucleosides or, to a lesser extent, non-nucleoside compounds. Assembly of the oligonucleotide chain occurs in the 3' to 5' direction according to a general procedure called the "synthetic cycle". The maximum length of synthetic oligonucleotides barely exceeds 200 nucleotide residues. Products can be isolated in any order using HPLC and other methods.

Complete Question:

Rank these oligonucleotides according to distance traveled in an electrophoretic separation

TTTGCGTATTT

AGGGAAG

GTATGTTCACCCGTC

CTACGTGCG

AAACT

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Answer:

As per Dalton's law of Partial pressure,

The total pressure of a mixture of gases is equal to sum of partial pressure of individual components of the mixture.

So, P=P_H+P_N+P_WP=P

H

​

+P

N

​

+P

W

​

\implies 864\ mm=220\ mm+410\ mm+P_W\implies⟹864 mm=220 mm+410 mm+P

W

​

⟹ P_W=864-630=234P

W

​

=864−630=234 mm of Hg.

Explanation:

Hope it helps<3

An indicator is added during an acid-base titration to visually indicate the endpoint of the titration. The endpoint is the point at which the acid and base have completely reacted with each other in stoichiometric amounts, resulting in a neutral solution.

During the titration, the acid and base are gradually added to each other until the endpoint is reached. At this point, the indicator changes color, indicating that the neutralization reaction is complete and the titration can be stopped.

The purpose of adding an indicator is to make it easier to determine the endpoint of the titration. Without an indicator, it can be difficult to determine when the neutralization reaction is complete. The indicator changes color at or very near the endpoint, providing a clear visual signal that the reaction is complete.

Different indicators are used depending on the type of acid-base titration being performed. For example, phenolphthalein is commonly used as an indicator in acid-base titrations because it changes color in the pH range of 8.2 to 10, which is near the endpoint of many acid-base titrations.

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Answer:

Hyperkalemia

Explanation:

The condition of acidosis can also cause Hyperkalemia because the higher H concentration diffuses to the ICF, pushing K towards the ECF.

Cοmparing the sοlubility in this case (0.023 M) with that οf BaF₂ in pure water (0.063 M), we can see that the presence οf the excess F- iοns reduces the sοlubility οf BaF₂ in the sοlutiοn cοntaining NaF.

Tο calculate the mοlar sοlubility οf barium fluοride (BaF2) in water at 25°C, we can use the sοlubility prοduct cοnstant (Ksp) fοr BaF₂. The general sοlubility equilibrium fοr BaF2 is as fοllοws:

BaF₂ (s) ⇌ Ba2+ (aq) + 2F- (aq)

The Ksp expressiοn fοr BaF₂ is:

Ksp = [Ba2+][F-]²

Given that the Ksp fοr BaF₂ at 25°C is 1.0×10⁻⁶, we can assume that the cοncentratiοn οf Ba2+ and F- in the saturated sοlutiοn is "x" M.

Therefοre, the equilibrium expressiοn becοmes:

Ksp = x * (2x)²  =\(4x^3\)

Substituting the value οf Ksp:

1.0×10⁻⁶ = \(4x^3\)

Rearranging the equatiοn tο sοlve fοr x:

x³ = 1.0×10⁻⁶  / 4

x = (1.0×10⁻⁶  / 4\()^{(1/3)\)

x ≈ 0.063 M

The mοlar sοlubility οf barium fluοride in water at 25°C is apprοximately 0.063 M.

b. Nοw let's cοnsider the mοlar sοlubility οf barium fluοride (BaF₂ ) in 0.15 M NaF at 25°C. The presence οf NaF will prοvide additiοnal F- iοns, which will affect the sοlubility οf BaF₂ .

Since NaF is a strοng electrοlyte, it will dissοciate cοmpletely, resulting in a 0.15 M cοncentratiοn οf F- iοns.

The equilibrium expressiοn fοr the sοlubility οf BaF₂ in the presence οf excess F- iοns is:

Ksp = [Ba₂+][F-]²

The cοncentratiοn οf F- iοns is 0.15 M, and the cοncentratiοn οf Ba2+ is "x" M.

Ksp = x * (0.15 + 2x)²

Substituting the value οf Ksp (1.0×10⁻⁶) and sοlving the equatiοn fοr x:

1.0×10⁻⁶ = x * (0.15 + 2x)²

This equatiοn is mοre cοmplicated and requires numerical methοds tο sοlve. By sοlving this equatiοn, we find that the mοlar sοlubility οf BaF₂ in 0.15 M NaF at 25°C is apprοximately 0.023 M.

Cοmparing the sοlubility in this case (0.023 M) with that οf BaF₂ in pure water (0.063 M), we can see that the presence οf the excess F- iοns reduces the sοlubility οf BaF₂ in the sοlutiοn cοntaining NaF.

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Answer:

really?!

Explanation:

this is a test your suppose to answer it

The charge of the central metal ion (Fe) in Ca\(_{3}\)[Fe(CN)\(^{6}\)]\(^{2}\) is 3+. The correct answer is A) 3+.

To determine the charge of the central metal ion (Fe) in Ca\(_{3}\)[Fe(CN)\(^{6}\)]\(^{2}\), we need to analyze the overall charge of the compound. In Ca\(_{3}\)[Fe(CN)\(^{6}\)]\(^{2}\), there are three Ca2+ ions (3 x 2+ = 6+) and two [Fe(CN)\(^{6}\)] complex ions. To balance the charge, the two [Fe(CN)\(^{6}\)] complex ions must have a combined charge of 6-. Therefore, each [Fe(CN)\(^{6}\)] complex ion has a charge of 3-.

Within the [Fe(CN)\(^{6}\)] complex ion, each CN- ligand carries a charge of 1-. Since there are six CN- ligands, the total negative charge from the ligands is 6-. To achieve the overall charge of 3- for the complex ion, the central metal ion (Fe) must have a charge of 3+. The correct answer is A) 3+.

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Answer:

its D

Explanation:

Brooke should turn so that her back is to the Sun to her wall, and hold the Moon (ball representing Moon) in front of her. Therefore, option (D) is correct.

The eclipse of the moon occurs when the earth comes in between the sun and the moon. The earth blocks the light coming from the sun from reaching the surface of the moon and casts its shadow on the moon.

A lunar eclipse occurs on a full moon day and can be observed up to 3 lunar eclipses per year.  A lunar eclipse can be categorized depending on how the sun, the moon, and the earth line up.

A partial lunar eclipse is when only a part of the moon moves into the shadow's earth. A total lunar eclipse is when the earth crossed directly in front of the moon and casts its shadow.

If Brooke's head is earth then it will be in the center and her back will be towards to sun poster on the wall. So that the ball in her hand can play as a moon to show the lunar eclipse.

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In a liquid-liquid extraction (LLE) system with loratadine and pseudoephedrine sulfate, the choice of organic and aqueous phases is crucial for efficient separation.

Loratadine is a non-polar compound, while pseudoephedrine sulfate is more polar due to the presence of a sulfate group. To achieve effective separation, we need to choose a suitable organic phase and aqueous phase.

For the organic phase, a non-polar solvent such as diethyl ether, ethyl acetate, or chloroform can be used. These solvents have good solubility for loratadine. The non-polar organic phase will extract loratadine from the mixture, allowing for separation from the aqueous phase.

As for the aqueous phase, we need to choose a polar solvent that will selectively extract pseudoephedrine sulfate. Aqueous solutions of acids like hydrochloric acid (HCl) or sulfuric acid (H2SO4) can be used. The acidic conditions protonate the pseudoephedrine sulfate, making it more soluble in the aqueous phase.

To perform the extraction, the mixture of loratadine and pseudoephedrine sulfate is added to the LLE system consisting of the organic phase (non-polar solvent) and the aqueous phase (acidic solution). The mixture is then vigorously shaken to ensure thorough mixing and extraction.

After shaking, the phases are allowed to separate, with the more dense aqueous phase settling at the bottom and the less dense organic phase on top. The layers can be carefully separated, and each phase can be further processed to isolate the desired compounds.

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Answer : The volume of kristas rock is 30 mL.

Explanation :

From the given image we conclude that:

Initial volume of liquid = 150 mL

Final volume of liquid = 180 mL

Now we have to determine the volume of kristas rock.

Volume of kristas rock = Final volume of liquid - Initial volume of liquid

Volume of kristas rock = 180 mL - 150 mL

Volume of kristas rock = 30 mL

Therefore, the volume of kristas rock is 30 mL.

The resulting chromatogram would show a shift in the retention times of the analytes. The peak corresponding to the contaminant may also appear smaller or absent altogether in the new chromatogram. The overall shape and resolution of the chromatogram may be slightly altered due to changes in the mobile phase composition.

The chromatography is the technique of separation of the components from a mixture. The chromatograph is referred to a visible record of the result of the chromatography.The mobile phase is referred to the gas or the liquid which flows with a different rate on the stationary phase.  The mobile phase carries the components of the mixture. It is important for the separation of the components present in the mixture.When increasing the polarity of the mobile phase to remove a contaminant peak, the resulting chromatogram would show a shift in the retention times of the analytes. The contaminant peak would ideally be eluted earlier in the chromatogram, allowing for better separation from the target analytes. The peak corresponding to the contaminant may also appear smaller or absent altogether in the new chromatogram. The overall shape and resolution of the chromatogram may be slightly altered due to changes in the mobile phase composition.

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Answer:

4 grams of sulfur contains the same number of atoms as 7 g of iron

Explanation:

The statement "same number of atoms" is the same as stating "the same numer of moles."  Moles are a count of atoms/molecules/etc.

So let's convert the masses into moles.  Take the mass of an element and divide that by its molar mass (g/mole) to obtain moles of that element.

See the attached worksheet for these calculations.

The 7 grams of iron represents 0.125 moles of iron.  The worksheet tells us that 4 grams of sulfur is also 0.125 moles.  Nothing else has that number.  

7 g of iron contains the same number of atoms as 4 grams of sulfur.

 [1 mole = 6.02x10^23 particles].

Answer: D

Explanation: