discovery of mineral perchlorate on mars by the phoenix lander was significant because group of answer choices

Answer:

the lava is and burning like liquid that is from a volcano when it erupt lava

The net force on particle q3 is 112.11 N

The electrostatic force F between two charged objects placed distance apart is directly proportional to the product of the magnitude of charges and inversely proportional to the square of the distance between them.

F = kq₁q₂/r²

where k = 9 x 10⁹ N.m²/C²

The Particles q1 = -53.0 uc, q2 = +105 uc, and q3 = -88.0 uc are in a line. Particles qı and q2 are separated by 0.50 m and particles q2 and q3 are separated by 0.95 m.

The net force F3 = F13 + F23

Substitute the values, we get the force F on q3 as

F3 = 9 x 10⁹x53.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.5+0.95)² + 9 x 10⁹x105.0 x 10⁻⁶x 88.0 x 10⁻⁶ / (0.95)²

F3 = 112.11 N

Thus, the magnitude of the force on charge q3 is 112.11 N.

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First we must calculate the current power the curling iron can handle:

where

I = current

V = tension

Then:

For the hair dryer we get:

Lets suppose all appliances are working in parallel together. The total current must be:

As we can see the appliances are drawning all current from the outlet fused.

Answer: the current that can be safely drawn from the outlet fused is zero.

Answer:

Play tennis, nothing can train you better for the sport than the sport itself. However, tennis is one of those unique sports that combine nearly all components of fitness including power, agility, speed, flexibility, reaction time, balance, coordination, cardiovascular endurance and muscular endurance.

Explanation:

The value of the charge on each particle is \(1.05 x 10^-8 C\).

Coulomb's law is a fundamental principle of electrostatics that describes the interaction between electric charges. It states that the force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. We can use Coulomb's law to solve this problem. Mathematically,

\(F = k(q1q2)/r^2\)

where F is the force of attraction or repulsion between the two charged particles,\(q1\) and \(q2\) are the magnitudes of the charges on the two particles, r is the distance between them, and k is Coulomb's constant, which has a value of \(9.0 x 10^9 Nm^2/C^2.\)

In this problem, we know that the charges are equal and the distance between them is 10.0 cm. We also know that the force between them is 0.5 N. Therefore,

\(0.5 N = k(q^2)/(0.1 m)^2\)

Solving for q, we get:

\(q = \sqrt{[(0.5 N)(0.1 m)^2/k]}\)

\(q = \sqrt{(0.5 N)(0.01 m)/(9.0 x 10^9 Nm^2/C^2)}\)

\(q = 1.05 x 10^-8 C\)

Therefore, the value of the charge on each particle is \(1.05 x 10^-8 C.\)

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Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

Given:

Apparent power (S) = 10 KVA = 10,000 VA

Line voltage (V) = 380 V

Frequency (f) = 50 Hz

Xd = 12 ohms

Xq = 8 ohms

Ra = 1 ohm

Power factor (pf) = 0.8 lagging

Load angle (δ) = 16.15 degrees

(i) Armature current's direct axis and quadrature axis components

We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:

S = 3Vphase Iphase cos(φ)

Iphase = S / (3Vphase cos(φ))

For a lagging power factor, cos(φ) = 0.8, so

Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A

The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current.  Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:

Id = (VL - IaRa) / Xd

Iq = (VL - IaRa) / Xq

where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,

Ia = Iphase / √3 = 10.46 / √3 = 6.03 A

Substituting the given values:

Id = (380 - 6.03 x 1) / 12 = 30.28 A

Iq = (380 - 6.03 x 1) / 8 = 46.92 A

(ii) Excitation voltage of the generator:

The excitation voltage (E) of the generator is given by:

E = Vphase + IqXq

Substituting the given values:

E = 380 + 46.92 x 8 = 765.36 V

Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.

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Answer:

90

Explanation:

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Answer:

The diameter is \(d = 8.18*10^{-19} \ m\)

Explanation:

From the question we are told that

   The value of one atomic mass unit is \(u = 1.66 *10^{-27} \ kg\)

    The density of the proton is  \(\rho = 5.8 *10^{27} \ kg/m^3\)

Generally the volume of the proton (sphere)is mathematically represented as

     \(V = \frac{4}{3} * \pi * r^3\)

Generally this volume can also be evaluated as

      \(V = \frac{u}{\rho}\)

=>   \(V = \frac{1.66 *10^{-27}}{5.8*10^{27}}\)  

=>   \(V = 2.862 *10^{-55} \ m^3\)

So

\(2.862 *10^{-55} = \frac{4}{3} * 3.142 * r^3\)

=>   \(r^3 = 6.832 *10^{-56}\)

=>  \(r = 4.088 *10^{-19} \ m\)

Now the diameter is mathematically represented as

    \(d = 2 * r\)

=> \(d = 2 * 4.088 *10^{-19}\)

=> \(d = 8.18*10^{-19} \ m\)

The ranking is based on the tilt of the Earth's axis and its orbit around the Sun. The figure at 40°N in June receives the most daylight because it is located at a high latitude during the summer solstice in the Northern Hemisphere. The Earth's axis tilts towards the Sun, resulting in longer days and shorter nights. The figure at 40°S in December receives a moderate amount of daylight as it is located at a lower latitude during the summer solstice in the Southern Hemisphere.

The figure at 40°N in December experiences less daylight because it is located at a high latitude during the winter solstice in the Northern Hemisphere, with shorter days and longer nights. Lastly, the figure at 40°S in June receives the least amount of daylight as it is located at a lower latitude during the winter solstice in the Southern Hemisphere, where the days are shortest and the nights are longest. Based on the information given, the ranking of figures based on the amount of daylight they experience in a 24-hour period, from most to least.

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As per the given scenario, in this case, the coefficient of friction () is half and the coefficient of restitution (e) is zero.

Identify the body's starting velocity:

We may use the equation of motion to get the body's initial velocity (u)

\(v^2 = u^2 + 2as\)

\(0 = u^2 + 2(-9.8)m/s^2 * h\)

\(u^2 = 19.6h\)

u = √(19.6h)

The body's initial velocity (u) and initial relative velocity (u_rel) are the same.

The body's horizontal velocity immediately following the collision, which is zero, is the final relative velocity (v_rel).

\(e = v_{rel }/ u_{rel}\)

e = 0 / u_rel = 0 / u

Now, one can investigate the forces affecting the body: When a body is on an inclined plane.

There are two main forces at work on it: the frictional force that prevents the body from moving and the gravitational force that pulls it downward (mg).

The gravitational force has two components that act perpendicular to and parallel to the inclined plane, respectively: m*g*cos(45°) and m*g*sin(45°).

Determine the conditions for the body to stop:

μ * N = m * g * sin(45°)

μ * (m * g * cos(45°)) = m * g * sin(45°)

μ * cos(45°) = sin(45°)

(1/2) * cos(45°) = sin(45°)

Simplifying further, we have:

√2 / 4 = √2 / 2

Thus, the body will come to rest following the collision if the equation is valid.

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a higher energy than an electron near the nucleus

In an electron cloud, an electron that is farther away from the nucleus has a higher energy than an electron near the nucleus. Thus, the correct option is C.

An electron cloud is the region which is surrounding an atomic nucleus in which there is a very high probability of an electron being located in an atom. The probability of finding an electron is greater than the more dense regions of the electron cloud in the atom.

One way in which the elements differ from each other is the structure of the electron cloud in each of the element's atoms in an electron cloud and the electrons which is farther from the nucleus has a higher energy than an electron near the nucleus of the atom.

Therefore, the correct option is C.

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The minimum value of h is 3.75 meters.

To determine the minimum value of h, we need to consider the geometry of the situation.

From the given information, we know that the observer's eye is 1 m from the wall and 1.5 m above the ground. The vertical post-PQ is 3 m tall and located 4 m behind the observer. The observer can see the whole image of the post in the mirror.

Since the observer can see the entire image of the post, we can conclude that the line of sight from the top of the post to the observer's eye must be parallel to the line of sight from the bottom of the post to the observer's eye. This is because the mirror reflects light rays at equal angles of incidence and reflection.

Let's denote the height of the observer's eye from the ground as x. We can set up a proportion to find the height of the image of the post in the mirror:

(Height of post-PQ) / (Distance from observer to post) = (Height of the image in the mirror) / (Distance from mirror to image)

Using the given values, we have:

3 m / 4 m = h / (4 m + 1 m)

Simplifying the equation:

3/4 = h/5

Cross-multiplying:

4h = 15

h = 15/4 = 3.75 m

Therefore, the minimum value of h is 3.75 meters.

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Answer:

the answer is B i hope it helps :)

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B. The energy required to force two nuclei to undergo nuclear fusion. ✅

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Answer:

s = 14.3 ft

Explanation:

First we need to calculate the distances traveled by both the cars. We use third equation of motion for that:

2as = Vf² - Vi²

where,

a = acceleration

s = distance

Vf = Final Velocity

Vi = Initial velocity

FOR CAR A:

Vi = Va = (40 mph)(5280 ft/1 mile)(1 h/3600 s) = 58.66 ft/s

Vf = 0 ft/s

a = aA = - 22 ft/s²

s = sa = ?

Therefore,

2(- 22 ft/s²)(sa) = (58.66 ft/s)² - (0 ft/s)²

sa = 78.2 ft

FOR CAR B:

Vi = Vb = (45 mph)(5280 ft/1 mile)(1 h/3600 s) = 66 ft/s

Vf = 0 ft/s

a = aB = - 20 ft/s²

s = sb = ?

Therefore,

2(- 20 ft/s²)(sb) = (66 ft/s)² - (0 ft/s)²

sb = 108.9 ft

Since, the car A was initially 45 ft ahead of car B. Therefore,

sa = 45 ft + 78.2 ft = 123.2 ft

Now, the distance between the cars will be:

s = sa - sb

s = 123.2 ft - 108.9 ft

s = 14.3 ft

Answer:

A is the best character that defines an electron.

Answer:

C. Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.

Explanation:

edge 2020 Brainliest would be appreciated

Answer:

Wanda's waist circumference indicates that she is not at risk, but her BMI indicates that she underweight. She should develop a plan to move her BMI into the normal range.

Explanation:

I just did the Cumulative Exam Review

Answer:

When drugs are taken in are body are brain release dopamine: which make us feel so pleasure and good, and for this some people are addicted to drugs which makes them feel good. on other hand damaging their health.

Answer:

The resistance of 4/0 coated copper conductors is given as 0.0626 ohms per 1000 feet. To find the total resistance of the three 4/0 conductors installed in parallel, we can use the formula for combining resistances in parallel.

Since the total length for each of the three conductors is 323 feet, the resistance of each conductor can be calculated as follows:

Resistance of one conductor = (0.0626 ohms / 1000 feet) * 323 feet

To find the total resistance when the conductors are in parallel, we use the formula:

1/Total Resistance = 1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3

Total Resistance = 1 / (1/Resistance of Conductor 1 + 1/Resistance of Conductor 2 + 1/Resistance of Conductor 3)

Substituting the values, we get:

Total Resistance = 1 / (1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet) + 1/((0.0626 ohms / 1000 feet) * 323 feet))

Simplifying the expression will give us the total resistance of the three 4/0 conductors installed in parallel.

Answer:

If the particles of the medium vibrate in a direction parallel to the direction of propagation of the wave, it is called a longitudinal wave. In longitudinal waves, the particle movement is parallel to the direction of wave propagation.

Explanation:

Answer:

its 24 hours

Explanation:

12 hours during the night and 12 hours during the day

Yes that's right...did anyone tell you something else?

Answer:

(a) the work required to pump all of the water out is 1.0584 x 10⁶ J

(b) the depth of the remaining water in the tank is 1.87 m

Explanation:

Given;

length of trough, L = 8m

height of the isosceles triangle, h = 3m

width of the isosceles triangle, w = 3m

length of spout, b = 2m

The center mass of isosceles triangle is given by;

\(\frac{1}{3} \ of \ height \ of \ the \ triangle = \frac{1}{3} *3 = 1 \ m\) (this is the height below the top of the trough)

The total height water will be pumped, H = 1m + b

H = 1m + 2m = 3m

Determine the volume of the trough;

Volume of the trough = area of the triangle x length of the trough

Volume of trough =  \(\frac{1}{2}*3*3*(8) = 36 \ m^3\)

(a) The work done in pumping all of the water out;

The work done in pumping all of the water out = potential energy of water at that height, H;

W = mgH

where;

m is mass of water

m = ρV

m = (1000 kg/m³) x (36 m³)

m = 36,000 kg

The work done = mgH

                          = 36,000 x 9.8 x 3

                          = 1.0584 x 10⁶ J

(b) after 4 × 10⁵ J of work has been done, the energy required to pump out the remaining water is given by;

ΔE = 1.0584 x 10⁶ J - 4 × 10⁵ J = 658,400 J

The depth of the remaining water is calculated as

658,400 J = mgh

where;

h is the height of the remaining water

658,400 = (36,000 x 9.8)h

658,400 = 352,800h

h = 658,400 / 352,800

h = 1.87 m

Answer: D

Explanation: because

Answer:

M v^2 / R = centripetal force

For Red: M v^2 / R = 5 * 9^2 / 1.5 = 270

For Blue M v^2 / R = 270 = 25 * 1.8^2 / Rb

So Rb = 25 * 1.8^2 / 270 = .3 m

When a  woman walks south at a speed of 2.0mph for 60 minutes. She then turns around and walks north at a distance of 3000m in 25 minutes. then the woman's average speed during her entire motion would be  73.15 meters /minute.

The total distance covered by any object per unit of time is known as speed.

the mathematical expression for speed is given by

speed = total; distance /total time

As given in the problem a woman walks south at a speed of 2.0mph for 60 minutes

60 min = 1 hour

1 mile = 1.60934 km

The distance covered by her southwards  =  speed ×time

                                                                      =2 mph × 60 minutes

                                                                      = 3.218 km

She then turns around and walks north at a distance of 3000m in 25 minutes

The distance covered northward is 3000m

speed = total distance /total time

          =(3218 +3000) /(60+25)

          =73.15 meters /minutes

Thus, The average speed of the woman would be 73.15 meters /minute.

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Average velocity of man is 2 m/s

Given that;

Distance between tree and house = 16 m

Time taken = 8 seconds

Find:

Average velocity

Computation:

Average velocity = Total distance cover / Time taken

Average velocity = Distance between tree and house / Time taken

Average velocity = 16 / 8

Average velocity = 2 m/s

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The result of the ratio of the displacement module of the second body at the point of meeting is 0.5.

To determine the ratio of the displacement of the first body to the displacement of the second body at the moment of their meeting, use the equation of motion:

d = vt + 1/2at²

where d is the displacement, v is the initial velocity, t is the time, and a is the acceleration.

Since the bodies are moving simultaneously towards each other, then assume that their initial velocities are zero. Also, at the moment of their meeting, their displacement will be the same, d₁ = d₂.

Assume that the time at which they meet is t, then:

d₁ = 1/2 * 2.4t²

And the equation for the displacement of the second body:

d₂ = 1/2 * 4.8t²

If d₁ = d₂

then, 1/2 * 2.4t² = 1/2 * 4.8t²

Solving this equation for t and substituting it into the equation for d₁ or d₂, the ratio of the displacement of the first body to the displacement of the second body: d₁/d₂ = 2.4/4.8 = 0.5 or 1/2

So, at the moment of their meeting, the displacement of the first body is half of the displacement of the second body.

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Answer: \(f=3.125 Hz\)

Explanation:

frequency = 1 / period

\(f=\frac{1}{T}\)

\(f=\frac{1}{0.32}=3.125Hz\)

Therefore, the frequency of the wave is 3.125 Hz.

The size of the umbra and penumbra are determined by the angle of the sun's rays relative to the Earth and moon. A small change in the distance between Earth and the moon would cause a small change in the angle of the sun's rays, resulting in a small change in the size of the umbra and penumbra.

Answer:

T = 1733.16 s = 28.88 min

Explanation:

The orbital velocity of a satellite about Earth is given as follows:

\(v = \sqrt{\frac{GM}{R}}\)

where,

v = orbital speed = ?

G = Gravitational Constant = 6.67 x 10⁻¹¹ Nm²/kg²

M = Mass of Earth = 5.982 x 10²⁴ kg

R = Orbit Radius = 3.117 x 10⁶ m

Therefore,

\(v = \sqrt{\frac{(6.67\ x\ 10^{-11}\ Nm^{2}/kg^{2})(5.982\ x\ 10^{24}\ kg)}{(3.117\ x\ 10^{6}\ m)}}\\\\v = 11.3\ x\ 10^{3}\ m/s\)

but the velocity is given as:

\(v = \frac{distance}{time}\)

for distance = circumference = 2πR

time = time period = T = ?

Therefore,

\(11.3\ x\ 10^{3}\ m/s = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{T}\\\\T = \frac{2\pi(3.117\ x\ 10^{6}\ m)}{11.3\ x\ 10^{3}\ m/s}\\\\\)

T = 1733.16 s = 28.88 min