Answers
Mass is the measure of the amount of matter in an object and remains constant regardless of location, measured in units like kilograms or grams, while weight represents the gravitational force exerted on an object, varying with the strength of the gravitational field and measured in units like newtons or pounds.
Mass and weight are distinct concepts in physics, differing in their definitions, units of measurement, how they are measured, and what they depend on. Here's a breakdown of their differences:
Mass:
Definition: Mass refers to the amount of matter in an object. It is an intrinsic property and remains constant regardless of the object's location or gravitational environment.
Units of measurement: The standard unit of mass in the International System of Units (SI) is the kilogram (kg). Other common units include grams (g) and metric tonnes (t).
Measurement: Mass can be measured using various techniques, including balances and scales. These instruments compare the unknown mass to known masses and determine the equilibrium or balance point.
Dependence: Mass is independent of gravity and remains the same regardless of the gravitational force acting on the object.
Weight:
Definition: Weight is the force exerted on an object due to the gravitational pull of a celestial body (usually Earth). It represents the measure of the object's gravitational attraction towards that body.
Units of measurement: The standard unit of weight in the SI system is the newton (N). However, weight is commonly expressed in units of force, such as pounds (lb) or kiloponds (kp).
Measurement: Weight is typically measured using a spring scale or a device known as a weighing scale. These instruments rely on the deformation or stretching of a spring to determine the gravitational force acting on an object.
Dependence: Weight depends on the strength of the gravitational field where the object is located. The weight of an object will vary depending on the celestial body it is interacting with, as gravitational forces differ.
Therefore, mass refers to the amount of matter in an object and is measured in units like kilograms or grams. It remains constant regardless of location and is determined using balances or scales. Weight, on the other hand, represents the gravitational force exerted on an object and is measured in units like newtons or pounds. It varies based on the strength of the gravitational field and is measured using spring scales or weighing instruments.
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Related Questions
In a distant galaxy, whose light is just arriving from 10 billion light years away, our spectroscope should reveal that the most common element is
Answers
Answer:
In a distant galaxy, whose light is just arriving from 10 billion light years away, our spectroscope should reveal that the most common element is HELIUM
in coming to a stop, an old truck leaves skid marks 45 m long on the highway. assuming a deceleration of 6m/s2 , estimate the speed of the truck just before braking.
Answers
The speed of the truck just before braking is 23.24 m/s.
What is the speed of the clock before braking?
The speed of the truck before braking is calculated by applying the third kinematic equation as shown below.
v² = u² - 2as
where;
v is the final velocity of the truck when it stopsa is the acceleration of the trucks is the distance travelled by the truckWhen the truck stops, the final velocity = 0
0 = u² - 2as
u² = 2as
u = √2as
u = √ ( 2 x 6 x 45 )
u = 23.24 m/s
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In a five paragraph essay, the ________ is the main idea you're trying to prove.
Answers
discuss how devastating a 7.7 - magnitude earthquake is.
Answers
Answer:
Explanation:
It’s devastating because when a earthquake is 7.7 magnitude the
4:01HOMEWORKThe parallel plates of a vacuum capacitor are 5mm apart and have 2m ^ 2 in area. A potential difference of 10,000 V (10.0 kV) is applied across the capacitor. Calculate a) the capacitance, b) the charge on each plate, and c) the magnitude of the electric field in the space between them.
Answers
RESPUESTA
a) C = 3.54 x 10⁻⁹ F = 3.54 nF
b) Q = 35.4 x 10⁻⁶ C = 35.4 μC
c) E = 2,000,000 V/m
EXPLICACIÓN
a) La capacitancia de un capacitor de placas paralelas se define como la razón entre la magnitud de la cantidad de carga en cada placa y la diferencia de potencial aplicado. A su vez, ésta depende de la geometría del capacitor. La ecuación que la define es:
\(C=\epsilon_0\cdot\frac{A}{d}\)donde C es la capacitancia, A es el área de las placas y d es la distancia que separa las placas. Además ε0 es la permitividad del vacío. En general la fórmula también incluye la permitividad relativa del material dielétrico (el material entre las placas del capacitor) pero en este problema no nos interesa, dado que el material entre las placas de este capacitor es el vacío.
De esta manera, si reemplazamos los datos de este problema:
• ε0 = 8.85 x 10⁻¹² F/m
,• A = 2 m²
,• d = 5 mm
Nota que tanto la permitividad como el área de las placas tienen unidades de metros, pero la distancia de separación entre placas está en milímetros, por lo tanto debemos convertirla a metros:
\(d=5\operatorname{mm}=0.005m\)Ahora sí, reemplazamos en la ecuación de arriba y obtenemos la capacitancia:
\(C=8.85\cdot10^{-12}\frac{F}{m}\cdot\frac{2m^2}{0.005m}=3.54\cdot10^{-9}F\)Cuando escribimos una cantidad en notación científica, y el exponente del 10 es -9 podemos no escribir esta parte y usar el prefijo nano. De esta manera, decimos que la capacitancia es de 3.54 nF.
b) La carga de las placas podemos obtenerla de la otra ecuación para definir la capacitancia:
\(C=\frac{Q}{V}\)C es la capacitancia que encontramos en el punto a), V es la diferencia de potencial aplicada y Q lo que estamos buscando, la carga de las placas. Del enunciado, tenemos que la diferencia de potencial es V = 10,000V. Reemplazando y resolviendo para Q:
\(\begin{gathered} 3.54\times10^{-9}F=\frac{Q}{10,000V} \\ Q=3.54\times10^{-9}F\cdot10,000V \\ Q=3.54\times10^{-5}C \end{gathered}\)Si movemos el punto decimal un lugar hacia la derecha tenemos: 35.4 x 10⁻⁶ C, que puede llevar el prefijo de micro. Para el prefijo micro usamos la letra griega mu (μ). Entonces la carga de las placas es 35.4 μC
c) Finalmente, para encontrar la magnitud del campo eléctrico, utilizaremos la relación entre la diferencia de potencial y la distancia entre las placas:
\(E=\frac{V}{d}\)Reemplazando con V = 10,000V y d = 0.005m, el campo eléctrico es:
\(E=\frac{10,000V}{0.005m}=2,000,000\frac{V}{m}\)h. If the mass of an object is 390 g and its volume is 50 cm?, then its density is ....... g/cm' or ....... kg/m”.
- The relative density of the object in part "h" is
Edit: nvm I'm an idiot I remembered this but thanks anyway
Answers
Answer: See explanation
Explanation:
The density would like be calculated by dividing the mass by volume. This will be:
Density = Mass / Volume
Density = 390 / 50
Density = 7.8g/cm
BIDEN WON MY RIGHTS ARENT GONNA BE TAKEN AWAY ‼️
Answers
Which statement describes the process shown?
2H
4He
3H
neutron
A. The process is nuclear fission, in which one nucleus splits apart to
form two smaller nuclei.
B. The process is nuclear fusion in which one nucleus splits apart to
form two smaller nuclei.
C. The process is nuclear fission, in which two smaller nuclei
combine to form one larger nucleus.
D. The process is nuclear fusion, in which two smaller nuclei
combine to form one larger nucleus.
Answers
2H
4He
3H
neutron
This process involves the combination of two hydrogen nuclei (2H) to form a helium nucleus (4He), which also releases a neutron and a significant amount of energy. This process is an example of nuclear fusion, in which smaller nuclei combine to form a larger nucleus.
Therefore, the correct statement that describes the process shown is:
D. The process is nuclear fusion, in which two smaller nuclei combine to form one larger nucleus.
How much work is done when 425 N of force is applied for 60.0m
Answers
Answer:
Workdone = 25500Nm
Explanation:
Given the following data
Force = 425N
Distance = 60m
To find the workdone
Workdone = force *distance
Substituting into the equation, we have
Workdone = 425*60
Workdone = 25500Nm
Based on the passage, how do the boys resolve their conflict?
They decide to fight to the death.
They decide not to care who the winner is.
They decide to fight a rematch.
They decide to end their friendship.
Answers
the answer is B
i jus took the assement
Answer:
B
Explanation:
Explain why it’s much colder at the bottom of the pool than at the top. also describe what heat transfer processes is taking place
Answers
Heat transfer by radiation and convection causes the surface water of the pool to be warm which decreases with depth.
Why is it colder at the bottom of the pool than the top of the pool?
There are two heat transfer process responsible for variation in temperature of water at different depth of a pool, they include;
Heat transfer by radiationHeat transfer by convection Heat transfer by radiationThe surface of the water absorbs heat from the air and the sun. The heat from the sun is transferred to the pool through radiation.
Heat transfer by convectionThe heat from the air is transferred to the pool through convection.
Thus, these two heat transfer processes causes the surface water of the pool to be warm which decreases with depth.
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if the mass of the paper is 0.003 kg, what force does the boxer except on it?
Answers
Answer:
1.15 N
Explanation:
You want to know the force exerted on a mass of 0.003 kg to accelerate it from 0 to 23 m/s in a period of 0.06 s.
AccelerationThe acceleration of the mass is the change in velocity divided by the change in time:
a = ∆v/∆t
a = ((23 -0) m/s)/(0.06 s) = 1150/3 m/s²
ForceThe force applied is the product of mass and acceleration:
F = ma
F = (0.003 kg)(1150/3 m/s²) = 1.15 kg·m/s² = 1.15 N
The applied force is 1.15 newtons.
what are the very small particles that make up matter
Answers
Hope this helps!!
Answer:
The very small particles that make up matter are I) Atoms
Matter - Anything that have mass and occupies space is called matter . it is made up of atoms and molecules
Atoms - The smallest part of matter is called atom.
Molecule - Group of atoms combine together to form a molecule.
More to know - Atom is made up of even smaller particles called neutron, proton and electron. Electron moves around nucleus ( nucleus is made up of neutron and proton) Different types of atom combine and form molecule ( Nitrogen dioxide No2 has 1 atom of nitrogen and 2 atoms of oxygen)she incorrect? Select all that apply.
because electromagnetic waves can only travel in gases
А
B
because electromagnetic waves can only travel through solids
С
because electromagnetic waves only come from the Sun
D
because electromagnetic waves are not created using force on a medium
m
because electromagnetic waves are created using accelerating charges
F
because electromagnetic waves require a medium to travel
Answers
electromagnetic waves can travel not only through air and solid materials, but also through the vacuum of space.
hope it helps...!!!
The axis of the earth is
Tilted about 23.5 degrees
Vertical
Vertical
Answers
Answer:
The axis of rotation of the Earth is tilted at an angle of 23.5 degrees away from vertical, perpendicular to the plane of our planet's orbit around the sun. The tilt of the Earth's axis is important, in that it governs the warming strength of the sun's energy.
Explanation:
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A wheel with radius 41.5 cm rotates 5.13 times every second.
Find the period of this motion.
What is the tangential speed of a wad of chewing gum stick to the rim of the wheel?
Answers
The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.
Let suppose that the wheel rotates at constant angular speed (\(\omega\)), in radians per second, the tangential speed of a wad of chewing gum to the rim of the wheel (\(v\)), in centimeters per second, is:
\(v = 2\pi\cdot r\cdot f\) (1)
Where:
\(r\) - Radius of the wheel, in centimeters\(f\) - Frequency, in hertzIf we know that \(f = 5.13\,hz\) and \(r = 41.5\,cm\), then the tangential speed of the chewing gum is:
\(v = 2\pi\cdot (41.5\,cm)\cdot (5.13\,hz)\)
\(v \approx 1337.659\,\frac{cm}{s}\)
The tangential speed of a wad of chewing gum to the rim of the wheel is approximately 1337.659 centimeters per second.
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What is the best description of the relationship between emerging scientific ideas and open-mindedness?
HURRY !
Answers
Answer: C ON EDGE 2021
Explanation:
What do you mean by infracture of business?
Answers
Answer: Infrastructure is the general term for the basic physical systems of a business, region, or nation. and it involves the production of public goods
Explanation:
how to calculate your reaction time with a ruler
Answers
Record the point at which you caught the ruler, to the nearest cm. Measure from the bottom of your thumb. You can use this table to convert the measurement on the ruler into your reaction time in seconds. The less time it takes you to catch the ruler, the faster your reaction.
Sit or stand with your arm stretched out in front of you. Hold out your thumb and your first finger.
Your partner needs to hold the ruler from the 30cm end and position the 0cm end just above the gap between your outstretched thumb and first finger. Make sure you aren’t touching the ruler!
Without giving you a warning, your partner needs to drop the ruler.
Catch the ruler, as quickly as you can, using just your thumb and finger. If you miss, make sure you watch out for your face or toes! And then have another go.
Record the point at which you caught the ruler, to the nearest cm. Measure from the bottom of your thumb.
You can use this table to convert the measurement on the ruler into your reaction time in seconds. The less time it takes you to catch the ruler, the faster your reaction.
A car has 10,800 kg m/s of momentum as it collides with a trash dumpster AT REST.
How much TOTAL MOMENTUM will the car and dumpster have after collision?
Answers
Answer:
10800 kg m/s
Explanation:
Since the dumpster was initially at rest, its momentum before collision equal to zero. So that the total momentum of the car and dumpster before collision is 10800 kg m/s.
The principle of conservation of linear momentum states that: in a system of colliding bodies, total momentum is conserved. Therefore, the total momentum of the car and dumpster after collision is 10800 kg m/s.
short note on how to measure with Metre rule Micrometre screw gauge Vernier Caliper
Answers
Hold the measurement target between the screw gauge's anvil and spindle while applying light pressure. the main size reading of the a circular scale just before zero.
How are a vernier caliper and screw gauge used?Vernier calipers can be used for alike external and internal measurements, while screw gauges can only be used for external measurements. A vernier caliper has a minimum count of 0.001 cm while a screw gauge has a minimum count of 0.01 cm.
What is the purpose of a metre ruler?This metre ruler, commonly known as a metre stick, is used to measure short distances and lengths up with one metre. It is a measuring tool used to determine distances and rule straight lines in engineering drawings, geometry, engineering, printing, and construction.
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A graph of the net force on an object is shown as a function of position as the object travels 3 meters. Which of the following conclusions about the object's motion can be drawn from the graph? a. The object’s kinetic energy changes by is 18 J.b. The object’s momentum changes by 18 kg•m/s.c. The acceleration of the object is 4 m/s^2.d. The speed on the object is 4 m/s.e. The power delivered to the object is 4 W.
Answers
We know that in a force-position graph the area under the graph is equal to the work done by the force.
In this case the area under the graph is a triangle with base 3 and height 12, then the work done is:
\(\begin{gathered} W=\frac{1}{2}(3)(12) \\ W=18 \end{gathered}\)Now, we also know that the work is equal to the change of kinetic energy, that is:
\(\Delta K=W\)Then:
\(\Delta K=18\)Therefore, we can conclude from the graph that the object's kinetic energy changes by 18 J and that the asnwer is a.
A small car with mass 0.610 kg
travels at constant speed on the inside of a track that is a vertical circle with radius 5.00 m
If the normal force exerted by the track on the car when it is at the top of the track (point B
) is 6.00 N
, what is the normal force on the car when it is at the bottom of the track (point A
)?
Express your answer with the appropriate units.
Answers
The normal force on the car when it is at the bottom of the track is 8.84 N.
At the top of the track (point B), the normal force (N) acting on the car is equal to the weight of the car (mg) plus the centrifugal force (mv²/r) acting outwards:
N = mg + mv²/r
where m is the mass of the car, g is the acceleration due to gravity, v is the speed of the car, and r is the radius of the track.
Since the car is traveling at constant speed, its acceleration is zero, so the centrifugal force is balanced by the force of gravity, and we have:
N = mg
Substituting the given values, we get:
6.00 N = (0.610 kg)(9.81 m/s²)
Solving for g, we get:
g = 9.68 m/s²
At the bottom of the track (point A), the normal force acting on the car is equal to the weight of the car minus the centrifugal force acting downwards:
N = mg - mv²/r
Substituting the known values, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)(v²/5.00 m)
Since the car is traveling at constant speed, we can use the fact that its kinetic energy is equal to its gravitational potential energy to solve for v:
mg(2r) = (1/2)mv²
where 2r is the total distance traveled by the car (i.e., the circumference of the circle), so 2r = 2πr = 31.4 m. Solving for v, we get:
v = sqrt(2gr)
Substituting the known values, we get:
v = sqrt(2(9.68 m/s²)(5.00 m)) = 6.19 m/s
Substituting this value of v into the equation for N, we get:
N = (0.610 kg)(9.81 m/s²) - (0.610 kg)((6.19 m/s)²/5.00 m) = 8.84 N
Therefore, the normal force on the car when it is at the bottom of the track is 8.84 N.
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how much power an appliance uses
Answers
Answer:
it depends on the appliance
Explanation:
bigger appliances will use more power, smaller appliances will use a lesser amount
what is the speed of light in quartz
Answers
Answer:
1.95 x 10^8 m/s.
Explanation:
Answer:
the answer is 1.95 x 10^8 m/s
Explanation:
Which object has the greatest kinetic energy?
A. a truck with a mass of 3,500 kg moving at 30 m/s
B. a fast pitched baseball with a mass of .5 kg moving at 46.9 m/s
C. a locomotive engine with a mass of 205,000 kg moving 5 m/s
D. a person with a mass of 73 kg running 6 m/s
Answers
The object with the greatest kinetic energy is the locomotive engine (option C)
How do I know which object has the greatest kinetic energy?To know the object with the greatest kinetic energy, we shall determine the kinetic energy of each objects. Details below:
For truck:
Mass (m) = 3500 KgVelocity (v) = 30 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 3500 × 30²
KE = 1575000 J
For baseball:
Mass (m) = 0.5 KgVelocity (v) = 46.9 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 0.5 × 46.9²
KE = 549.90 J
For locomotive:
Mass (m) = 205000 KgVelocity (v) = 5 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 205000 × 5²
KE = 2562500 J
For person:
Mass (m) = 73 KgVelocity (v) = 6 m/sKinetic energy (KE) =?KE = ½mv²
KE = ½ × 73 × 6²
KE = 1314 J
From the above calculations, we can see that the locomotive has the greatest kinetic energy. Thus, the correct answer is option C
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Which of these statements describes a species? Group of answer choices
A. A species is a group of organisms that are closely related and produce fertile offspring
B. A species is a group of organisms that are closely related.
C. A species is a group of organisms that live in the same habitat
D. A species is a group of organisms that live in an area and interact.
Answers
Electric field is always perpendicular to the equipotential surface.
a. True
b. False
Answers
Answer:
a: true.
Explanation:
We can define an equipotential surface as a surface where the potential at any point of the surface is constant.
For example, for a punctual charge, the equipotential surfaces are spheres centered at the punctual charge.
Or in the case of an infinite plane of charge, the equipotential surfaces will be planes parallel to our plane of charge.
Now we want to see if the electric field is always perpendicular to these equipotential surfaces.
You can see that in the two previous examples this is true, but let's see for a general case.
Now suppose that you have a given field, and you have a test charge in one equipotential surface.
So, now we can move the charge along the equipotential surface because the potential in the surface is constant, then the potential energy of the charge does not change. And because there is no potential change, then there is no work done by the electric field as the charge moves along the equipotential surface.
But the particle is moving and the electric field is acting on the particle, so the only way that the work can be zero is if the force (the one generated by the electric field, which is parallel to the electric field) and the direction of motion are perpendiculars.
Then we can conclude that the electric field will be always perpendicular to the equipotential surfaces.
The correct option is a.
ʕ•ᴥ•ʔhi how are you ？
Answers
Answer:
I’m not okay . Me and my bf are bickering once again
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
Answers
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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