. Draw a schematic circuit with two cells placed in parallel providing powerto a single light controlled by a switch drawn in the closed position. Includea voltmeter to read the potential difference across one light. Indicate bothconventional current in blue arrows and electron flow in black arrows.

a) The average force with which the woman pushed the man is 210 N.

b.  the woman's recoil speed is still 3.68 m/s

c.  If  she now throws her 2.50-kg purse at him at a 20.0° angle, the speed is 0.

We first calculate  the Momentum  = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

0 = (70.0 kg)(0 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s) - (70.0 kg)(-1.50 m/s)

v = 3.68 m/s

Δp = (70.0 kg)(1.50 m/s) - (70.0 kg)(0 m/s) = 105 kg·m/s

The average force exerted on the man by the woman is:

Average force =   Δp / Δt

Average force  = 105 kg·m/s / 0.500 s

Average force  = 210 N

b) The woman's recoil speed is :

0 = (70.0 kg)(-1.50 m/s) + (55.0 kg)(v) + (2.50 kg)(-1.50 m/s)

v = 3.68 m/s

c) If the woman throws her 2.50-kg purse at the man at a 20.0° angle, we apply the conservation of momentum equation in two dimensions and get the speed as 0.

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Answer: B. It decreases the quality

Explanation: Signal noise is any unwanted or random variation in a signal that interferes with the transmission or reception of information. Noise can be caused by various factors, such as electrical interference, thermal fluctuations, atmospheric disturbances, or defects in the transmission medium.

In the case of the wave shown in the graph above, which appears to be an optical signal transmitted through a fiber optic cable, noise can affect the quality of the wave by distorting its shape, amplitude, frequency, or phase. This can result in errors or loss of data at the receiver end, as the original signal becomes harder to distinguish from the noise.

The quality of a signal can be measured by its signal-to-noise ratio (SNR), which is the ratio of the power of the signal to the power of the noise. A higher SNR means a better quality signal, while a lower SNR means a worse quality signal. Noise can reduce the SNR of a signal by adding unwanted variations to its power.

Therefore, noise decreases the quality of the wave shown in the graph above.

Hope this helps, and have a great day! =)

The magnetic field vectors at points 2 through 5 due to the moving charge are B₂ = -1.3 x 10⁻⁹ T into the paper, B₃ = 0, B₄ = 0, and B₅ = 1.3 x 10⁻⁹ T out of the paper.

To determine the magnetic field vectors B₂ through B₅ at points 2 through 5 due to the moving charge, we need to use the Biot-Savart Law. The Biot-Savart Law gives the magnetic field at a point due to a current-carrying wire or a moving charge.

The Biot-Savart Law is given by:

dB = μ₀/4π (I x dℓ x ẑ) / r²

where;

Considering the velocity of the charge, the magnetic field at each point:

B₂ = μ₀/4π (q vᵧ / r²)sin(90°) = μ₀/4π(q vᵧ / r²)

B₃ = μ₀/4π (q vᵧ / r²)sin(180°) = 0

B₄ = μ₀/4π(q vᵧ / r²)sin(180°) = 0

B₅ = μ₀/4π(q vᵧ / r²)sin(90°) = μ₀/4π(q vᵧ / r²)

where;

Using the given distance of 1.0 mm, we can calculate the magnetic field magnitudes at each point:

B₂ = μ₀/4π(q vᵧ / r²)

The velocity of the charge is calculated as;

B₁ =  μ₀/4π(q vᵧ / r²)

1.3 x 10⁻⁹ = (1.26 x 10⁻⁶ Tm/A)/4π)(1.6 x 10⁻¹⁹ C)(v)/(0.001)²

v = 1.02 x 10⁵ m/s

B₂ = (1.26 x 10⁻⁶ Tm/A)/4π)(1.6 x 10⁻¹⁹ C)(1.02 x 10⁵ m/s) / (0.001 m)²

B₂  = 1.3 x 10⁻⁹ T

B₃ = 0 (since sin(180°) = 0)

B₄ = 0 (since sin(180°) = 0)

B₅ = μ₀/4π(q vᵧ / r²)

B₅ = (1.26 x 10⁻⁶ Tm/A)/4π)(1.6 x 10⁻¹⁹ C)(1.02 x 10⁵ m/s) / (0.001 m)²

B₅ = 1.3 x 10⁻⁹ T

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Answer:

resultant force = 59 N

Explanation:

we know the formula: Force = mass * acceleration

                                    Force = 25 kg  *   2.36 m/s²

                                    Force = 59 N

(3a) The maximum possible static frictional force on the object is 53.9 N.

(3b) The actual static frictional force on the object is 28.9 N.

(4) The experimental condition to ensure that the block is in equilibrium in order to determine the coefficient of kinetic friction is that the block must be at rest.

Static frictional force is a force that keeps an object at rest. This is the minimum force that needs to be overcame before the object begins to the move.

The static frictional force is calculated by applying Newton's second law of motion as follows;

Fs = μFn

where;

The normal force of the object depends on the weight of the object.

The maximum possible static frictional force on the object

Fs = μFn

Fs = μmg

Fs = 0.22 x 25 x 9.8

Fs = 53.9 N

Actual static frictional force on the object when external force of 25 N acts on it horizontally.

Fs = 53.9 N - 25 N

Fs = 28.9 N

An object at equilibrium position has equal forces acting on it in corresponding directions.

The experimental condition to ensure that the block is in equilibrium in order to determine the coefficient of kinetic friction is that the block must be at rest before you apply a force to push it down the inclined plane.

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The final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

The given parameters:

The final velocity of the cannon ball when it strikes the earth is calculated by applying the principle of conservation of energy as follows;

\(P.E_i + K.E_i = P.E_f + K.E_f\\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = g(0) + \frac{1}{2} v_f^2\\\\2gh_i + v_i^2 = v_f^2\\\\v_f = \sqrt{2gh_i + v_i^2 } \\\\v_f = \sqrt{(2 \times 9.8 \times 50) \ \ + \ \ 30^2} \\\\v_f = 43.36 \ m/s\)

Thus, the final velocity of the cannon ball when it strikes the earth is 43.36 m/s.

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Answer:

Explanation:

Convert all lengths to meters:

Refer to the diagram attached (not to scale.) Assuming that the screen is parallel to the line joining the two slits. The following two angles are alternate interior angles and should be equal to each other:

These two angles are marked with two grey sectors on the attached diagram. Let the value of these two angles be \(\theta\).

The path difference between the two beams is approximately equal to the length of the segment highlighted in green. In order to produce the first dark fringe from the center of the screen (the first minimum,) the length of that segment should be \(\lambda / 2\) (one-half the wavelength of the light.)

Therefore:

\(\displaystyle \cos \theta \approx \frac{\text{Path difference}}{\text{Slit separation}} = \frac{\lambda / 2}{3.00\times 10^{-5}\; \rm m}\).

On the other hand:

\(\begin{aligned} \cot \theta &\approx \frac{\text{Distance between central peak and first minimum}}{\text{Distance between the screen and the slits}} \\ &= \frac{3.70\times 10^{-2}\; \rm m}{5.20\; \rm m} \approx 0.00711538\end{aligned}\).

Because the cotangent of \(\theta\) is very close to zero,

\(\cos \theta \approx \cot \theta \approx 0.00711538\).

\(\displaystyle \frac{\lambda /2}{3.00\times 10^{-5}\; \rm m} \approx \cos\theta\approx 0.00711538\).

\(\begin{aligned}\lambda &\approx 2\times 0.00711538 \times \left(3.00\times 10^{-5}\; \rm m\right) \\ &\approx 4.26 \times 10^{-7}\; \rm m = 426\; \rm nm\end{aligned}\).

If the path difference is increased by one wavelength, then the intersection of the two beams would move from one bright fringe to the next one.

On the other hand, if the distance between the maximum and the center of the screen is much smaller than the distance between the screen and the filter, then:

\(\begin{aligned}&\frac{\text{Distance between image and center of screen}}{\text{Distance between the screen and the slits}} \\ &\approx \cot \theta \\ &\approx \cos \theta \\ &\approx \frac{\text{Path difference}}{\text{Slit separation}}\end{aligned}\).

Under that assumption, the distance between the maximum and the center of the screen is approximately proportional to the path difference. The distance between the image (the first minimum) and the center of the screen is \(3.70\; \rm cm\) when the path difference is \(\lambda / 2\). The path difference required for the first maximum is twice as much as that. Therefore, the distance between the first maximum and the center of the screen would be twice the difference between the first minimum and the center of the screen: \(2 \times 3.70\; \rm cm = 7.40\; \rm cm\).

Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

The work done by gravity is 1081.9J with a mass of 10 kg and a height is 12m with acceleration due to gravity.

Work done due to gravity equals the product of mass, height, and acceleration due to gravity. Gravity is the force that attracts an object toward the Earth. If the object is freely falling toward the earth, gravitational force accelerates the object and it speeds up the object 10m for every second. Thus, Work done (W) = mghcosθ, where m is the mass, g is the acceleration due to gravity, and h is the height.

From the given,

mass of box(m) = 10kg

height (h) = 12m

Acc. due to gravity (g) = 9.8 m/s²

W = 10×9.8×12×cos(23)

  = 1081.9 J

Thus, the work done by gravity is 1081.9 J.

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Tidal energyis the name one other way of generating electricity that uses the movement of water.

The rush of ocean waters during tide changes is what generates tidal energy. A renewable energy source is tidal energy.

In places with a wide tidal range—the distance between high tide and low tide—engineers devised methods to harness tidal movement to generate power during the 20th century. Each technique turns tidal energy into electricity using specialized generators.

Hydroelectric and wave power both use the movement of water to drive a turbine and produce electricity but Tidal energyis the name one other way of generating electricity that uses the movement of water.

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To find

What does the displacement time wave graph determine?

Explanation

The slope of a displacement-time graph gives us velocity.

So the displacement-time wave graph is used to determine the wave velocity of a wave.

Conclusion

Displacement -time wave graphs can be used to determine the wave velocity of a wave

Geologic map: The correct label as placed in the respective boxes are as follows- is attached to the answer.

A geologic map is a scientific illustration that depicts the physical features of a geographic area and the underlying geology. It is used to help interpret the geologic history of a region. Geologic maps are created by geologists and contain information about the distribution of different rock types and other subsurface features. This information is used to interpret the area’s geologic history, understand the resources available in the area, and plan for development and management of the area. Geologic maps include information such as the age and type of rocks, their structures and minerals, faults and folds, and the presence of any surface features such as rivers, lakes, and soils. Geologic maps are used by geologists, engineers, planners, and other professionals to help understand the underlying geology and make decisions about how to use the land.

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The position of their center of mass is also shown. the square cuboids is the most stable. Hence option B is correct.

A cuboid is a six-sided solid known as a hexahedron in geometry. Quadrilaterals make up its faces. Cuboid is short for "like a cube". A cuboid is similar to a cube in that a cuboid may become a cube by varying the lengths of the edges or the angles between the faces.

The square cuboid has its center of mass on the center of square, the masses are uniformly distributed about it.

Hence option B is correct.

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The ship will end up moving 26.6 degrees east of north.

The ship is initially moving in the north direction, and the ocean current deflects it towards the east direction. To find the resulting direction, we can use the Pythagorean theorem.

The northward velocity of the ship = 12.0 m/s

The eastward velocity caused by the ocean current = 6.00 m/s

Let's call the resulting velocity v.

Using Pythagoras theorem, we have:

v² = (12.0 m/s)² + (6.00 m/s)²

v² = 144 m²/s² + 36 m²/s²

v² = 180 m²/s²

v = sqrt(180 m²/s²)

v = 13.4 m/s (to two significant figures)

Therefore, the ship will end up moving in a direction that is a combination of north and east, with a resulting velocity of 13.4 m/s. We can find the angle of this direction using trigonometry:

tan(theta) = (6.00 m/s) / (12.0 m/s)

theta = atan(0.5)

theta = 26.6 degrees east of north

So the ship will end up moving in a direction that is 26.6 degrees east of north.

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the force the woman exerts to do a push-up at constant speed is 333 N.

the work the woman does is 152 J.

her useful power output is 76 W.

(a) To calculate the force the woman exerts to do a push-up, we need to use torque methods. The woman is doing a push-up at constant speed, which means that the net torque on her body is zero. The only torque acting on her body is due to her weight W, which acts at the center of mass of her body. The distance between her center of mass and her hands is 0.76 m, and the angle between her body and the horizontal is 45 degrees.

The torque due to her weight about her hands is given by:

τ = r x W = (0.76 m) x (cos 45°)(W)

where r is the distance between her hands and her center of mass and cos 45° is the component of the distance perpendicular to the weight vector. Since the woman is at constant speed, the torque she exerts about her hands must be equal and opposite to the torque due to her weight. Therefore:

τ = (0.76 m)(cos 45°)(W) = (1/2)(W)(0.76 m)

Solving for W, we get:

W = 2(τ/0.76 m) = 2[(0.5)(mg)(0.76 m)/(0.76 m cos 45°)] = 333 N

Therefore, the force the woman exerts to do a push-up at constant speed is 333 N.

(b) The work the woman does is equal to the change in her potential energy as her center of mass rises. The woman's mass is not given, so we will assume a value of 60 kg. The gravitational potential energy of the woman is given by:

U = mgh

where m is the mass of the woman, g is the acceleration due to gravity (9.81 m/s^2), and h is the height her center of mass rises (0.26 m). Therefore:

U = (60 kg)(9.81 m/s^2)(0.26 m) = 152 J

Therefore, the work the woman does is 152 J.

(c) The useful power output of the woman is the work she does per unit time, taking into account the work done in lowering her body. Each push-up involves two phases: lifting her body and lowering her body. When she lowers her body, the work done is negative, as the force she exerts is in the opposite direction to the displacement. The work done in lowering her body is equal to the work done in lifting her body, so the total work done in one push-up is zero.

The woman does 30 push-ups in 1 minute, which means she does one push-up every 2 seconds. Therefore, the useful power output of the woman is:

P = (152 J)/(2 s) = 76 W

Therefore, her useful power output is 76 W.

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After considering the given data and information we come to the conclusion that overall magnitude of the carts' common final velocity is 3.6 m/s, under the condition that a cart with mass m subscript 1 equals 0.25 space k g is at rest on a track.

Then, we can apply the law of conservation of momentum to evaluate the common final velocity of the carts.

The law of conservation of momentum projects that the total momentum of an isolated system stays constant if no external forces act on it. For this required case, the system is the two carts.

Before the collision, the first cart is in the rest and the second cart has a velocity of 6.17 m/s. Hence, the total momentum of the system before the collision is

p = m₁v₁ + m₂v₂

Here,

m1 and m2 are the masses of the carts and `v1` and `v2` are their velocities.

Staging the given values,

p = (0.25 kg)(0 m/s) + (0.35 kg)(6.17 m/s)

Applying simplification this expression

p = 2.16 kgm/s

Post the event of collision, the two carts stick along each other and move with a common final velocity `v`. The total momentum of the system after the collision is

p = (m₁ + m₂)v

Staging the given values, and evaluate for v

v = p / (m₁ + m₂)

Staging the given values

v = (2.16 kgm/s) / (0.25 kg + 0.35 kg)

v = 2.16/0.6

Applying simplification this expression

v ≈ 3.6 m/s

Then, the overall magnitude of the carts' common final velocity is approximately 3.6 m/s.

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These scientists are known  to study different aspects of science. The study they engage are;

a. Geologists - study the physical structure and composition of the Earth, including rocks, minerals, and natural resources.

b. Zoologists - study animals, their behavior, physiology, evolution, and distribution.

c. Anthropologists - study human societies, cultures, and behavior across time and space.

d. Botanists - study plants, their physiology, structure, ecology, and evolution.

e. Chemists - study the composition, properties, and behavior of matter and the chemical changes it undergoes.

f. Physicists - study the fundamental principles that govern the behavior of matter and energy in the universe, including mechanics, thermodynamics, electromagnetism, quantum mechanics, and relativity.

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Answer:

support lights as a wave

Explanation:

In the model of light as a particle, the experimenter would expect to see one small hole of light emerging on the wall. However, as the light spreads out, it behaves much like a wave that diffracts when going through a small hole.

Answer:

57m

Explanation:

speed = 5.7m/s

or 57/10 m/s

so definitely the time taken will be 10 secs

so speed = distance/time taken

5.7= distance/10

distance = 5.7× 10

Distance = 57m

The ratio of the cubes of any two planets' average distances from the sun (r) to their squares representing their periods (T) is equal to one.

First Law: The sun is at the center of elliptical planetary orbits.

Second Law: Equal areas are covered in equal amounts of time by the radius vector from the sun to a planet.

Third Law: For every planet, the ratio of the cube of the ellipse semimajor axis to the square of the period of revolution is the same.

The third law of Kepler, also referred to as the Law of Harmonies, states that the ratio of any two planets' squared periods to their squared average distances from the sun is equal to one. The third law compares a planet's orbital radius and period to those of other planets.

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Answer:

To perform hands-only CPR, you want your non-dominant hand on top of your dominant hand and interlocking fingers, and push right under the breast bone 30 times. A good way to remember how fast you should perform CPR, listen to the beat of "Staying Alive." If the hands don't work after 30 times, pinch their nose, tilt their head back and blow two big breaths into their mouth, then do the chest pushing again. Keep repeating these steps until they respond, you feel a pulse, or 911 arrives.

Explanation:

I actually just learned how to do CPR this week it is really cool!

May I have Brainliest please? My next rank will be the highest one: A GENIUS! Please help me on this journey to become top of the ranks! I would really appreciate it, and it would make my day! Thank you so much, and have a wonderful rest of your day!

Answer:

In economics, the marginal cost of production is the change in total production cost that comes from making or producing one additional unit.

Explanation:

This is the right answer bc i did it!!

Marginal cost is the correct answer.

"The marginal cost of production is the change in total production cost that comes from making or producing one additional unit. To calculate marginal cost, divide the change in production costs by the change in quantity".

For the given question,

The increase in total costs required to produce one additional unit of output is referred to as marginal cost.

Hence we can conclude that marginal cost is the correct answer.

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Net work done  on student B by the Ferris wheel in moving from the top to the bottom  is mathematically given as

net work done on A =0.

Generally the equation for the work energy theorem is mathematically given as

net work done on A = change in kinetic energy of A.

Where, angular velocity is constant.

change in kinetic energy = 0.

Hence, from work energy theorem,

net work done on A =0.

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T = (m g) + (m a), where "g" denotes the acceleration caused by gravity of any objects the rope is supporting and "a" denotes any additional acceleration on any such objects, can be used to represent the tension in a given rope.

An object's velocity can change based on how rapidly, slowly, or which way it is moving. As examples of acceleration, consider a falling apple, the moon orbiting the earth, or a car coming to a complete stop.

The velocity of a displacement affects how quickly it changes. Acceleration is the term used to describe how quickly a velocity changes.

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Answer:

Which feature is created when a block of rock dropped down in relation to the block of rock beside it?

Explanation:

Grabens drop down relative to adjacent blocks and create valleys. Horsts rise up relative to adjacent down-dropped blocks and become areas of higher topography.

A student slides a block on a surface by applying a force of 11 newtons (N) toward the left. The friction force on the block is 4 N and which is in right direction. the Net force acting on the box is 11-4 = 7N.( towards left)

Force is responsible for the motion of an object. it produces acceleration in the body. According to newton's second law force is mass times acceleration i.e. F =ma. Its SI unit is N which is equivalent to kg.m/s². There are two types of forces, balanced force and unbalanced force. Balanced forces are those forces which are opposite in direction and equal in magnitude. When Net force acting on a body is zero then we call it as balanced force. Balanced force is not responsible for the motion of the body. ex. when two persons pulling rope on both end with equal magnitude which cause them to be balanced force have 0 net force. Unbalanced forces are those when resultant of all the forces is not equal to zero is called as unbalanced force. unbalanced force is responsible for the motion of the body.

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Complete Question

The diagram illustrating this question is shown on the first uploaded image

Answer:

The value is \(\theta = 27^o\)

Explanation:

Generally the distance covered by the ball thrown at angle 45° that did not bounce is mathematically represented as

\(D = v cos (45) * t\)

Here t is the total time duration which is mathematically represented as

\(t = \frac{v sin (45)}{g}\)

This distance distance is also mathematically represented as

\(D = vcos(\theta)* t_1 + \frac{v}{2} cos(\theta )*t_2\)

Here \(\theta\) the angles made as shown in the diagram

Here \(t_1\) is the time before the first bounce which is mathematically represented as

\(t_1 = \frac{v sin (\theta )}{g}\)

\(t_1\) is the time duration before the final point which is mathematically represented as

\(t_2 = \frac{\frac{v}{2} * sin (\theta )}{g}\)

So

\(v cos (45) * \frac{v sin (45)}{g} = vcos(\theta)* \frac{v sin (\theta )}{g} + \frac{v}{2} cos(\theta ) * \frac{\frac{v}{2} * sin (\theta )}{g}\)

=> \(cos (45) sin(45) = cos(\theta)sin(\theta ) + cos(\theta )sin(\frac{\theta}{4})\)

=> \(0.5 = \frac{5}{8} * sin(2\theta )\)

=> \(\theta = 27^o\)

Answer:

B Electrons are negatively charged while protons are positively charged