Hydrogen fusion in the sun requires a temperature (in kelvin) of:_____.

Answer:

F = K Qa Qb / R^2

The forces are equal - the same on each sphere

Suppose the force was repulsive, for simplicity, obviously a string holding them together would have the same tension in both directions

From around 6500 K at the bottom to 4000 K at the top, the photosphere's temperature changes (11,000 and 6700 degrees F, 6200 and 3700 degrees C). Granulation covers a large portion of the photosphere.

The results of these many techniques indicate that the Sun's surface actually has a temperature of about 5,800 kelvin (9,980 degrees Fahrenheit [5,520 degrees Celsius]). The photosphere contains areas of darkness known as sunspots, where the temperature is comparatively lower—about 3800K. The photosphere is therefore the layer that is the coldest. It is 15 million K inside the sun (27 million degrees Fahrenheit). It is 5780 K at the surface (9900 degrees Fahrenheit).

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Answer:

The law of momentum conservation can be stated as follows. For a collision occurring between object 1 and object 2 in an isolated system, the total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.

Answer: 18.64114

Explanation:

Answer:

Explanation:

Use the one-dimensional equation for displacement:

Δx = v₀t + \(\frac{1}{2}at^2\) where Δx is the displacement, v₀ is the initial velocity (which is 0 since someone had to be holding the penny still before it was dropped), t is the time it takes to travel a certain distance (which is given as 4 seconds), and a is the acceleration due to gravity which is -9.8 m/s/s. Filling in:

Δx = \((0\frac{m}{s})(4s)+\frac{1}{2}(-9.8\frac{m}{s^2})(4s)^2\) I'm going to expand this first so you can see how the units work out. First of all, anything times 0 is 0, so what is right in front of the plus sign goes to 0 and I'm going to leave it out. How this looks expanded without doing any of the actual math yet is:

Δx = \(\frac{1}{2}(-9.8\frac{m}{s^2})(4^2s^2)\) which makes it apparent that the seconds-squared cancel each other out, leaving us with the meters only. NOW doing the math and rounding to 2 sigfig's even though there's only 1 in the number 4:

Δx = 78 m(the negative would only be used if the question we were answering was how far the penny had to fall, which would then use the negative sign to indicate that the penny is falling to a point that is below th point from which it was released. Since height is a distance measurement, it will never be negative. Keep in mind, asking how far the penny fell is not the same thing in physics as asking how tall the building was that the penny fell from.)

Answer:

Explanation:

Radius of first spherical ball =

2

2

​

cm=1cm

Radius of second spherical ball =

2

2

3

14.5

​

​

cm=

3

14.5

​

cm

Let the radius of the third ball be r cm.

Radius of the main spherical ball =

2

5

​

cm=2.5cm

Volume of main spherical ball = Volume of spherical ball  1+Volume of spherical ball 2+ Volume of spherical ball 3

Volume of a sphere =

3

4

​

πr

3

So,  

3

4

​

π×2.5

3

=

3

4

​

π1

3

+

3

4

​

π(

3

14.5

​

)

3

+

3

4

​

πr

3

⇒2.5

3

=1

3

+(

3

14.5

​

)

3

+r

3

⇒r

3

=15.625−1−14.5

⇒r

3

=0.125=0.5×0.5×0.5

⇒r=0.5

Answer: D

Explanation:

Frank’s Furniture trains all of its employees to use computers is an example of an improvement in human capital.

the atomic radius get bigger.

this is because as you add more electrons to an anion the electrons get farther apart.

they do this because they don't like each other so when you add more they need more space to stay away from each other

Answer:

100 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 5 kg

Acceleration (a) = 20 m/s

Force (F) =?

Force is simply defined as the product of mass and acceleration. Mathematically, it can be expressed as:

Force (F) = mass (m) × acceleration (a)

F = ma

With the above formula, we can obtain the force need to move the object. This can be obtained as follow:

Mass (m) = 5 kg

Acceleration (a) = 20 m/s

Force (F) =?

F = ma

F = 5 × 20

F = 100 N

Therefore, a force of 100 N is needed to move the object.

Answer:

\(F_w=1000Hz\)

Explanation:

From the question we are told that:

Frequency \(F=1200\)

Speed \(V_w= \frac{1}{5}*343=>68.6m/s\)

Where speed of sound \(V_s=343m/s\)

Generally the equation for frequency  that echo from the cliff wall is mathematically given by

\(F_w=\frac{V_s-V_0}{Vs+V_w}*F\)

\(F_w=\frac{343-0}{343+68.6}*1200\)

\(F_w=1000Hz\)

Answer:

10 N

Explanation:

Given that,

A man pushes against a tree with a force of 10 newtons.

We need to find the amount of force exerted by the tree on the man.

The force exerted by the tree on the man will be equal to the force that the man exert on the tree as per Newton's third law of motion.

It means the tree exert 10 N force on the man. Hence, the correct option is (c) i.e. 10 N.

Answer:

Carbon dioxide concentrations are rising mostly because of the fossil fuels that people are burning for energy.

The change in temperature of the wire is 60.2°C.

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When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.

When a 9.0 V battery is connected to a bulb and 0.1 A of current flows through the bulb, we can calculate the resistance of the bulb using Ohm's Law. Ohm's Law states that the current flowing through a conductor is directly proportional to the voltage applied across it and inversely proportional to its resistance.

To find the resistance, we can rearrange Ohm's Law equation (V = IR) to solve for R, where V is the voltage, I is the current, and R is the resistance.

First, let's plug in the given values:

V = 9.0 V (voltage)
I = 0.1 A (current)

Now, we can rearrange the equation to solve for R:

R = V / I

Substituting the given values:

R = 9.0 V / 0.1 A

Dividing 9.0 V by 0.1 A, we get:

R = 90 ohms

Therefore, the resistance of the bulb is 90 ohms.

In summary, when a 9.0 V battery is connected to a bulb and 0.1 A of current flows through it, the resistance of the bulb is 90 ohms.

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Answer:

n = 4 x 10¹⁸ photons

Explanation:

First, we will calculate the energy of one photon in the radiation:

\(E = \frac{hc}{\lambda}\\\\\)

where,

E = Energy of one photon = ?

h = Plank's Constant = 6.625 x 10⁻³⁴ J.s

c = speed of light = 3 x 10⁸ m/s

λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m

Therefore,

\(E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}\)

E = 3.505 x 10⁻¹⁹ J

Now, the number of photons to make up the total energy can be calculated as follows:

\(Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\\)

n = 4 x 10¹⁸ photons

Explanation:

Plastics with a density less than or equal to 1.025 g/mL will float in seawater, while plastics with a density greater than 1.025 g/mL will sink.

Here are some examples of plastic densities:

Polyethylene terephthalate (PET) has a density of approximately 1.38 g/mL, so it will sink in seawater.

Polypropylene (PP) has a density of approximately 0.9 g/mL, so it will float in seawater.

High-density polyethylene (HDPE) has a density of approximately 0.95 g/mL, so it will float in seawater.

Polystyrene (PS) has a density of approximately 1.05 g/mL, so it will sink in seawater.

Based on the above examples, we can see that plastics such as polypropylene and high-density polyethylene will definitely float in seawater, while others such as polyethylene terephthalate and polystyrene will definitely sink. Other types of plastics with densities close to 1.025 g/mL may float or sink depending on their exact density and the conditions of the water, such as temperature and salinity.

Answer:

For metric-system conversions, follow this method: Sound travels at about 340 m/s, so multiply the number of seconds you counted by 340, and you'll know how many meters away lightning struck. A three-second count, then, would place the lightning strike about 1,020 m away, or roughly 1 km.

Explanation:

hope it hep and if it doesnt sorry

The distance struck by the lighting flashes is 680 m.

The given parameters;

The distance struck by the lighting is calculated by applying the principle of echo as follows;

\(v = \frac{2d}{t} \\\\2d = vt\\\\d = \frac{vt}{2} \\\\d = \frac{340 \times 4}{2} \\\\d = 680 \ m\)

Thus, the distance struck by the lighting flashes is 680 m.

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Answer:

0.7kg

Explanation:

Given parameters:

Force on the rock  = 8.68N

Acceleration  = 12.4m/s²

Unknown:

Mass of the rock  = ?

Solution:

From newton's second law of motion, the net force on a body is the product of mass and acceleration

  Net force  = mass x acceleration

Now insert the parameters and solve the problem;

         8.68  = mass x 12.4

          mass = \(\frac{8.68}{12.4}\)  = 0.7kg

Object is Placed at Infinity; Object is Placed between Infinity and Optical Center ; Image is virtual

Answer:it’s 400 meters

Explanation:

The characteristic of electromagnetic waves from the given options is: C) They can travel with or without a medium.

Electromagnetic waves are waves that consist of oscillating electric and magnetic fields. They can travel through a vacuum, such as empty space, where no medium is present. This is in contrast to mechanical waves, such as sound waves, which require a material medium to propagate.

The ability of electromagnetic waves to travel through a vacuum is a unique feature that sets them apart from other types of waves. It means that electromagnetic waves can propagate in the absence of particles or matter, allowing them to travel through space and reach us from distant celestial objects, such as stars and galaxies.

Furthermore, electromagnetic waves can also travel through a medium if one is present. For example, light waves can propagate through air, water, glass, and other transparent substances. In such cases, the electromagnetic waves interact with the atoms or molecules of the medium, causing them to absorb, transmit, or reflect the waves.

This ability of electromagnetic waves to travel with or without a medium is fundamental to many applications and technologies. It enables the transmission of radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays through various mediums or across vast distances in space. Option C

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Explanation:

Force is push or pull on a body.

Contact force is a force that requires contact. It acts between two body that touches on another.

Examples are pushing a car, ringing a bell, kicking a ball.

Non contact forces are forces applied to another object without contact. The action of this force is usually through a targeted force field.

Examples are magnetic force, gravitational force

Answer:

No, It hasn't acceleration because it doesn't change the velocity with respect to time.

Hardness, color , and luster.

But since you can pick one, I would say hardness

A positive charge and a negative charge held a certain distance apart are released. as they move, the force on each particle increases

The most common charge carriers are the positively charged proton and the negatively charged electron. The movement of any of these charged particles constitutes an electric current

When there are more or fewer protons in an atom than electrons, the substance has an electric charge. Protons have a positive charge, while electrons have a negative charge. If a substance has more protons than electrons, it is positively charged; if it has more electrons, it is negatively charged.

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Answer:

i) b. 14.3 Hz

ii) d. 0.4625 m/s

Explanation:

f = c / λ

f = frequency

c = speed

λ = wavelength

first question:

the given values,

λ = 2.17 m

c = 31 m/s

f = c / λ

f = 31 / 2.17

f = 14.28

∴ f = 14.3 Hz

second question:

given,

λ = 0.25 m

f = 1.85 Hz

f = c / λ

rearranging,

c = f × λ

c = 1.85 × 0.25

c = 0.4625

∴ c = 0.4625 m/s

(love your username, btw.)

Answer:

(b) 102 kg

Explanation:

95 +15/4- 9/4+11/2 = 102 kg

Answer: A

Explanation:

The particle's location vector at time t is given by: r(t) = t³ + t² + 1

As per the question, we have the velocity of the particle in polar coordinates, but we need to find the position of the particle at time t. To do this, we need to integrate the velocity vector to obtain the position vector.

Let's consider the given velocity vector:

v(t) = (3t² + 2t)i + (2t² + 3t)j

To integrate this velocity vector, we need to find the corresponding position vector. Since the velocity vector is given in polar coordinates, we can express it in terms of polar variables:

v(t) = r'(t) + r(t)θ'(t)

where r'(t) and θ'(t) are the radial and angular components of the velocity vector, respectively.

By comparing the given velocity vector with the above equation, we can write:

r'(t) = 3t² + 2t

θ'(t) = (2t²+ 3t)/r(t)

Integrating r'(t) with respect to t, we get:

r(t) = t³ + t² + C

where C is the constant of integration.

To determine the value of C, we need to use the initial condition given in the problem. The particle starts at the position r = 1 and θ = π/4 at time t = 0. This implies:

r(0) = 1

θ(0) = π/4

Substituting these values in the equation for r(t), we get:

1 = 0 + 0 + C

C = 1

Therefore, the position vector of the particle at time t is given by:

r(t) = t³ + t² + 1

To find the value of θ at time t, we integrate θ'(t) with respect to t:

θ(t) = ∫(2t² + 3t)/r(t) dt

= ∫(2t² + 3t)/(t³ + t² + 1) dt

This integral is not trivial to solve analytically. Therefore, the position of the particle at time t can be expressed as:

r(t) = (t³ + t² + 1)i + f(t)j

where f(t) is the solution of the above integral for θ(t).

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