draw the lewis structure for co with an arrow representing the dipole moment. refer to figure 10.10 to estimate the percent ionic character of the co bond.

1

Explanation:

because they period two

Answer:

1

Explanation:

The  statement best describes the effect of low ionization energies and low electronegativities on metallic bonding is : Delocalization of the valence electrons is simple.

What is  ionization energy ?

Ionization energy, also known as ionization potential, is the amount of energy needed to remove an electron from an isolated atom or molecule in physics and chemistry.

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Answer:

C

Explanation:

C

Answer: it's C

204/82PB

ASTM C1602 outlines the standards for making and curing cementitious specimens. A concrete sample should reach a minimum compressive strength of 2,500 psi (17.2 MPa) after 28 days of curing.  Therefore, YES is the answer.

The compressive strength of cement is the measurement of its capability to resist pressure and is critical in the design of structural components. The water-cement ratio is the ratio of the weight of water to the weight of cement utilized in a concrete mixture. The lower the ratio, the better the concrete’s strength and durability.

In evaluating the suitability of non-potable water available at the job site for mixing concrete, six standard mortar cubes (2 in × 2 in) were made using that water and six others using potable water. After seven days of curing, the cubes were tested for compressive strength and produced the following loads to failure (in pounds): Solution:The non-potable water has a compressive strength of 2660 psi, and the potable water has a compressive strength of 2640 psi.The compressive strengths of the samples are very close, so the water appears to be acceptable for mixing concrete according to ASTM C1602. Therefore, YES is the answer.

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Answer:

atom is the smallest unit of matter that has the characteristic properties of a chemical element. 

The value of x in ZnSO4⋅xH2O is 5.87.

The value of x in ZnSO4⋅xH2O can be determined by a simple calculation. First, we need to determine the mass of anhydrous ZnSO4, which can be done by subtracting the mass of the precipitate (0.8223 g) from the mass of the sample (1.013 g).

This yields 0.1907 g of anhydrous ZnSO4. Since ZnSO4⋅xH2O is composed of ZnSO4 and x moles of H2O, we can divide the mass of anhydrous ZnSO4 (0.1907 g) by the molar mass of ZnSO4 (179.45 g/mol) to determine the moles of ZnSO4 present.

Then, we can subtract this from the moles of ZnSO4⋅xH2O present in the original sample (1.013 g) to obtain the moles of H2O. Dividing this by the molar mass of H2O (18.02 g/mol) gives us the value of x, which is 5.87.

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The average atomic mass of the element is 116.70 u. To calculate the average atomic mass of an element with two naturally-occurring isotopes with mass numbers 115.00 u and 117.00 u, and natural abundances of 15% and 85%, respectively, follow these steps:

1. Convert the natural abundances into decimals: 15% = 0.15 and 85% = 0.85.

2. Multiply the mass number of each isotope by its corresponding abundance: (115.00 u × 0.15) and (117.00 u × 0.85).

3. Add the products from step 2 together: (115.00 u × 0.15) + (117.00 u × 0.85).

4. Round the result to 2 decimal places.

Calculating the values: (115.00 u × 0.15) = 17.25 u; (117.00 u × 0.85) = 99.45 u; 17.25 u + 99.45 u = 116.70 u. The average atomic mass of the element is 116.70 u.

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The pH of the buffer solution is approximately 12.51.

To determine the pH of the buffer solution based on the solubility of Mg(OH)₂, we need to consider the equilibrium reaction that occurs when Mg(OH)₂ dissolves in water:

Mg(OH)₂ ⇌ Mg²⁺ + 2OH⁻

In water, Mg(OH)₂ dissociates into Mg²⁺ and OH⁻ ions. The solubility of Mg(OH)₂ can be related to the concentration of the Mg²⁺ and OH⁻ ions. Specifically, for every 1 mol of Mg(OH)₂ that dissolves, it produces 1 mol of Mg²⁺ ions and 2 mol of OH⁻ ions.

Given that the solubility of Mg(OH)₂ is 0.95 g/L, we need to convert this to moles per liter (M). The molar mass of Mg(OH)₂ is 58.33 g/mol, so:

0.95 g/L ÷ 58.33 g/mol ≈ 0.0163 mol/L

From the equilibrium reaction, we know that for every 1 mol of Mg(OH)₂, we have 1 mol of Mg²⁺ ions. Therefore, the concentration of Mg²⁺ ions is also approximately 0.0163 mol/L.

Now, we need to consider the OH⁻ concentration. Since we have 2 mol of OH⁻ ions for every 1 mol of Mg(OH)₂, the concentration of OH⁻ ions is:

2 × 0.0163 mol/L = 0.0326 mol/L

The pH of a solution can be related to the concentration of the hydroxide ions (OH⁻) through the equation:

pOH = -log[OH⁻]

Since the solution is basic due to the presence of OH⁻ ions from the Mg(OH)₂, we can use the pOH to find the pH. Assuming complete dissociation, we can calculate the pOH as:

pOH = -log(0.0326) ≈ 1.49

Finally, we can find the pH by subtracting the pOH from 14 (pH + pOH = 14):

pH ≈ 14 - 1.49 ≈ 12.51

Therefore, the pH of the buffer solution is approximately 12.51.

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Answer:

solid

decrease

smaller

Explanation:

f

Answer:

False.

Explanation:

Dimensional analysis is a way of converting quantities. The study of space and time is cosmology.

The equilibrium constant for the dissociation of potassium hydrogen tartrate (KHT) in water is equal to the square of the bitartrate concentration due to the stoichiometry of the dissociation reaction.

When KHT (potassium hydrogen tartrate) dissolves in water, it undergoes dissociation according to the following equilibrium reaction:

KHT ⇌ K⁺+ HT⁻

The equilibrium constant for this reaction, denoted as K, is defined as the ratio of the concentrations of the products ( K⁺ and HT⁻) to the concentration of the reactant (KHT).

K = [ K⁺] [HT⁻] / [KHT]

Now, let's consider the dissociation of HT⁻ (hydrogen tartrate) ion further:

HT⁻ ⇌ H⁺ + T²⁻

In this reaction, HT⁻dissociates into a hydrogen ion (H^+) and a bitartrate ion (T²⁻). Since KHT dissociates to produce one HT⁻ ion, we can say that the concentration of HT⁻ is equal to the concentration of KHT.

Therefore, [HT⁻] = [KHT]

Now, substituting this expression into the equilibrium constant equation:

K = [K⁺][HT⁻] / [KHT]

K  = [K⁺][KHT] / [KHT]

K = [K⁺]

Hence, the equilibrium constant, K, for the dissociation of KHT in water is equal to the concentration of K⁺ ions.

Now, since HT⁻ is equal to KHT in concentration, we can rewrite the equilibrium constant equation as:

K = [K⁺][HT⁻]

K  = [K⁺][KHT]

The concentration of bitartrate ions (T²⁻) is equal to half the concentration of HT⁻ ions (KHT), due to stoichiometry:

[T²⁻] = 0.5[HT⁻]

K⁺+ HT⁻ = 0.5[KHT]

Substituting this expression into the equilibrium constant equation:

K = [K⁺][KHT]

K  = [K⁺](0.5[KHT])

K= 0.5[K⁺][KHT]

From this equation, we can see that the equilibrium constant K is equal to the square of the bitartrate concentration ([T²⁻]).

The equilibrium constant for the dissociation of KHT in water is equal to the square of the bitartrate concentration because the stoichiometry of the dissociation reaction shows that the concentration of bitartrate ions is equal to half the concentration of HT^- ions, and the equilibrium constant is proportional to the product of the concentrations of the ions involved in the reaction.

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The equilibrium constant for the KHT dissociating in water is equal to the square of the bitartarate concentration because of the stoichiometry of the reaction.In the reaction of KHT dissociating in water, KHT donates one hydrogen ion (H+) to water to form tartrate ion (T2-) and hydronium ion (H3O+).

This reaction is represented as:KHT(aq) + H2O(l) ⇌ T2-(aq) + H3O+(aq)This reaction has one mole of KHT reacting with one mole of water to produce one mole of tartrate ion and one mole of hydronium ion. At equilibrium, the concentration of KHT, water, tartrate ion, and hydronium ion will be constant. Let the initial concentration of KHT be ‘x’.

After reacting with water, let the concentration of KHT be ‘x – y’ and the concentration of tartrate ion and hydronium ion be ‘y’.

Therefore, the equilibrium expression for this reaction can be written as:KHT(aq) + H2O(l) ⇌ T2-(aq) + H3O+(aq)[T2-(aq)][H3O+(aq)]/[KHT(aq)][H2O(l)]Now, the concentration of water is assumed to be a constant since it is in large excess with respect to KHT.

Therefore, the equilibrium expression can be written as:[T2-(aq)][H3O+(aq)]/[KHT(aq)]The square of the bitartarate concentration is used in this expression because two moles of bitartarate are obtained from one mole of KHT.

Hence, the equilibrium constant (Kc) expression can be written as:Kc = [T2-(aq)][H3O+(aq)]/[KHT(aq)] = [y]2/[(x – y)]where,‘x’ is the initial concentration of KHT, and‘y’ is the amount of KHT that has reacted to form tartrate ion.

Therefore, the equilibrium constant for the KHT dissociating in water is equal to the square of the bitartarate concentration.

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Extensive property is dependent on mass. Intensive property is property that depends only on the type of matter rather than the amount. Hense, Volume is an example of Extensive property and Density is an example of Intensive property.

Hope this helps :)

Answer:Sarcastic with..

Explanation:none

A resistor is shown with a zig zag, so D is the resistor

Answer:

letter D

Explanation:

letter A represent the battery

letter B represent the key

letter C represent nothing

letter D represent the resistance

Answer:

The largest of the volcanoes in the Tharsis Montes region, as well as all known volcanoes in the solar system, is Olympus Mons. Olympus Mons is a shield volcano 624 km (374 mi) in diameter (approximately the same size as the state of Arizona), 25 km (16 mi) high, and is rimmed by a 6 km (4 mi) high scarp.

Explanation:

Answer:

This is a mixture.

Explanation:

While you can no longer see the salt when it's dissolved, it's still there! It's just in tiny, tiny, invisible to the eye molecules. It's now a mixture of H20 molecules and NaCl molecules in a solution :)

The water doesn't bond to the salt, so it's not a compound.

It's not just one element, it's a mixture of many!

It's not a pure substance since it's NaCl AND H2O.

Answer:

6 valence electrons

Explanation:

The atom you have given is a sulfur atom. It has 6 valence electrons.

Answer:

Molarity=number of moles÷volume(L)

a) The molar mass of NH4ClO4 can be calculated by adding up the atomic masses of its constituent elements:

M(NH4ClO4) = (M(N) + 4 * M(H) + M(Cl) + 4 * M(O))

From the given atomic masses:

M(N) = 14.01 g/mol

M(H) = 1.008 g/mol

M(Cl) = 35.45 g/mol

M(O) = 16.00 g/mol

Plugging in these values:

M(NH4ClO4) = (14.01 + 4 * 1.008 + 35.45 + 4 * 16.00) g/mol

M(NH4ClO4) = 144.49 g/mol

The molar mass of NH4ClO4 is 144.49 g/mol.

(b) To determine the number of grams of oxygen (O) in 1.0 mol of NH4ClO4, we need to calculate the molar mass of oxygen in the compound.

The molar mass of O is 16.00 g/mol.

Since NH4ClO4 contains four oxygen atoms, the mass of oxygen in 1.0 mol of NH4ClO4 is:

Mass of O = 4 * M(O)

Mass of O = 4 * 16.00 g/mol

Mass of O = 64.00 g

There are 64.00 g of oxygen in 1.0 mol of NH4ClO4.

(c) (i) To balance the reaction equation for the electrolysis of aluminum oxide, we need an equal number of atoms on both sides of the equation.

The balanced equation is:

2Al2O3(l) + 3C(s) → 4Al(l) + 3CO2(g)

(ii) From the balanced equation, we can determine the stoichiometric ratio between the formation of aluminum and the production of CO2. According to the equation, 3 moles of CO2 are produced for every 2 moles of aluminum (Al).

Given that 8.00 kg of aluminum is produced in 1 hour, we can calculate the number of moles of aluminum produced using its molar mass:

M(Al) = 26.98 g/mol

Number of moles of Al = mass of Al / M(Al)

Number of moles of Al = 8000 g / 26.98 g/mol

Number of moles of Al = 296.81 mol

Using the stoichiometric ratio, we can calculate the number of moles of CO2 produced:

Number of moles of CO2 = (3/2) * Number of moles of Al

Number of moles of CO2 = (3/2) * 296.81 mol

Number of moles of CO2 = 445.22 mol

Now, we can use the ideal gas law to calculate the volume of CO2 produced under given conditions:

PV = nRT

Assuming P = 1.00 atm, T = 60.0 °C (convert to Kelvin: 60.0 + 273.15 = 333.15 K), and R = 0.0821 L·atm/(mol·K), we can rearrange the equation to solve for V (volume):

V = (n * R * T) / P

V = (445.22 mol * 0.0821 L·atm/(mol·K) * 333.15 K) / 1.00 atm

V ≈ 12,715.8 L

Approximately 12,715.8 liters of CO2 gas will be formed during this hour.

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Answer:

The combination of the polymer opening up and the water molecules sticking to it make a solution of the hydrogel get thicker and more viscous (sticky). Disposable nappies make use of the ability of hydrogels to take up and retain water, even under pressure.

Explanation:

Answer:

Volumen = 65.199 metro cúbico

Explanation:

Tal como lo conocemos

P1V1 = P2 V2

Aquí

P1 = 1,9 atmósferas

V1 = (pi) * r ^ 2 * h

Sustituyendo los valores dados, obtenemos

V1 = 3.14 * 2.8 * 2.8 * 4.6 = 113.241 metros cúbicos

V2 = por determinar

P2 = 3.3 atmósferas

Sustituyendo los valores dados y derivados en la fórmula principal, obtenemos -

1.9 atm * 113.241 metros cúbicos = 3.3 atm * V2

V2 = 1.9 atm * 113.241 metros cúbicos / 3.3 atm

V2 = 65.199 metro cúbico

Answer:

Explanation:

\(\frac{P1V1}{T} = \frac{P2V2}{T2} = \frac{3.3 *15}{299} = \frac{1050*V}{760*350}\)

v= 41.9 L

b)  using the same formula as above \(P1= \frac{P2V2*T1}{T2 * V1}= \frac{36*2*338}{308*28} = 2.8 atm\)

hope it helps

Answer:

By far the most abundant volcanic gas is water vapor, which is harmless. However, significant amounts of carbon dioxide, sulfur dioxide, hydrogen sulfide and hydrogen halides can also be emitted from volcanoes.

To calculate the grams of oxygen, we need to know the mass of 100 molecules of oxygen, which is 3.2 grams. Therefore, 100 grams of oxygen will react with 20 molecules of C3H8.

To balance the equation: C3H8 + 5O2 -> 3CO2 + 4H2O, we need 5 molecules of oxygen to react with 1 molecule of C3H8. So, to react with 20 molecules of C3H8, we would need 100 molecules of oxygen (20 x 5).

Using the balanced equation C3H8 + 5O2 -> 3CO2 + 4H2O, we can see that 5 moles of oxygen are required to produce 3 moles of carbon dioxide. We can convert the given 100 grams of oxygen to moles, which is 3.125 moles. Then, we can calculate the number of moles of carbon dioxide produced, which is (3.125/5) x 3 = 1.875 moles. Finally, we can convert moles to grams using the molar mass of CO2, which is 44 g/mol. Therefore, 1.875 moles of CO2 is equivalent to 82.5 grams.

The balanced equation C3H8 + 5O2 -> 3CO2 + 4H2O tells us that for every 1 molecule of C3H8, we get 4 molecules of water. Therefore, to produce \(3.42*10^{24}\) particles of water, we would need \((3.42*10^{24})/4 = 8.55*10^{23}\) molecules of C3H8. Then, we can convert this number of molecules to atoms by multiplying by the number of atoms per molecule of C3H8, which is 10 (3 carbon atoms and 8 hydrogen atoms). Therefore, the number of atoms of C3H8 we started with is \(8.55*10^{23} * 10 = 8.55*10^{24}\) atoms.

To calculate the number of particles of water produced from 15 grams of oxygen, we first need to convert the mass of oxygen to moles. The molar mass of O2 is 32 g/mol, so 15 grams of oxygen is equivalent to 15/32 = 0.46875 moles. Using the balanced equation C3H8 + 5O2 -> 3CO2 + 4H2O, we can see that for every 5 moles of oxygen, we get 4 moles of water. Therefore, 0.46875 moles of oxygen will produce (4/5) x 0.46875 = 0.375 moles of water. Finally, we can convert moles to particles by multiplying by Avogadro's number (\(6.022*10^{23}\)), giving us \(0.375 * 6.022*10^{23} = 2.256*10^{23}\) particles of water.

From the balanced equation C3H8 + 5O2 -> 3CO2 + 4H2O, we can see that for every 5 moles of oxygen, we get 4 moles of water. Therefore, to produce 115 grams of water, we need to calculate the number of moles of water required, which is 115/18 = 6.39 moles (using the molar mass of water, which is 18 g/mol). Then, we can calculate the number of moles of oxygen required, which is (5/4) x.

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The mass of oxygen gas produced, given that 15.8 g of potassium permanganate is heated until no more oxygen gas is given off is 1.6 g

From the question given, the following data were obtained:

The mass of oxygen gas produced from the reaction can be obtained as follow:

Mass of potassium permanganate = Mass of remaining substance + mass of oxygen

Inputting the given parameters, we have:

15.8 = 14.2 + mass of oxygen

Collect like terms,

Mass of oxygen = 15.8 - 14.2

= 1.6 g

Thus, we can conclude that the mass of oxygen gas produced from the reaction is 1.6 g

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Answer:

Explanation: 10.05 mL

To determine the volume of the object using water displacement, we subtract the initial volume (measurement 1) from the final volume (measurement 2).

Volume = Measurement 2 - Measurement 1

Volume = 19.20 mL - 9.15 mL

Volume = 10.05 mL

Therefore, the volume of the object, as determined by water displacement, is 10.05 mL.

Answer:

a) 600 J

b) 75 W

Explanation:

Force= 400 N, distance = 150 cm = 1.5 m, time= 8s

a) Work is the product of force acting on an object and distance (or displacement). The S.I unit of work is the joules.

Work = force × distance = 400 × 1.5 = 600 J

b) Power is the amount of energy transferred per unit time. It is the ratio of work to time. The S.I unit of power is watt

Power = work/time = 600 / 8 = 75 W

The total change in enthalpy of this reaction is A, 25 KJ

The total change in enthalpy of the reaction is equal to the difference between the enthalpy of the products and the enthalpy of the reactants.

From the potential energy diagram, so see that the enthalpy of the products is 55 kJ and the enthalpy of the reactants is 30 kJ.

Therefore, the total change in enthalpy is:

ΔH = enthalpy of products - enthalpy of reactants

ΔH = 55 kJ - 30 kJ

ΔH = 25 kJ

So the answer is 25 kJ.

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Answer:

In 7.3288, digit is on first place after decimal, so its place value will be tenths. Digit is on second place after decimal, so its place value will be hundredths. Bold digit is on third place after decimal, so its place value will be thousandths.