It's proven that \(m \angle COD=72\)° using the Vertical Angle Theorem and property of linear pairs.
What is Vertical Angle Theorem?
According to the Vertical Angle Theorem, the opposing angles of two crossing lines must have the same value or be congruent. The angles opposed to each other will always be congruent, or equal in value, no matter how or where two straight lines intersect.The Vertical Angle Theorem states that when two straight lines cross, they create two linear pairs. Due to the fact that their angles sum up to 180 degrees, the neighboring angles created when two lines intersect are said to be supplementary angles.Here, it is given that \(m \angle AOB=42\)° and \(m \angle EOF=66\)°
Using the Vertical Angle Theorem, we know that \(\angle BOC\) is congruent to \(\angle EOF\)
\(\implies m\angle BOC =m \angle EOF = 66\)°
And, using the property of adjacent angle, we get
\(m\angle AOC =m \angle AOB + m \angle BOC\\\implies m\angle AOC = 42 + 66\\\)
\(\implies m\angle AOC =108\)°
Now, using the property of linear pair (supplementary angles), we get
\(m \angle AOC + m \angle COD = 180\)°
\(\implies 108+ m \angle COD = 180\\ \implies m \angle COD = 180 - 108\)
\(\implies m \angle COD =72\)°
Therefore, it is proven that \(m \angle COD=72\)° using linear pair property and the Vertical Angle Theorem
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Airbus A300-S600 Max fuel load: 143,000 pounds Burn rate: 14,000 pounds per hour (equivalent to MPG in an automobile) Panel 2: Scenario You are the UPS station manager at Louisville International Airport. You have an Airbus A300-S600 on the ground being loaded with cargo. It has 35,000 # of fuel on board. It is outbound to Salt Lake City (SLC) when loading is complete. Flight time to SLC is 4.5 hours. Federal Aviation Administration (FAA) has a fuel mandate for all commercial flights. ALL aircraft must have sufficient fuel on board at departure to arrive at destination airport with an on-board reserve of 10% of the aircraft's total fuel capacity. Panel 3: Your task You must calculate the amount of fuel to be added so that this aircraft arrives at SLC with the FAA mandated reserve on board - no more, no less. Show your work.
The amount of fuel to be added is = 42,300 pounds.
The aircraft is currently loaded with 35,000 pounds of fuel and is outbound to Salt Lake City, which is a 4.5 hour flight. The FAA mandates that all commercial flights must have sufficient fuel on board at departure to arrive at the destination airport with an on-board reserve of 10% of the aircraft's total fuel capacity.
Given that the fuel capacity is 143,000 pounds and the aircraft has 35,000 pounds of fuel on board at present time. The reserve fuel required is 10% of the total fuel capacity.
Reserve fuel required = 10% of the total fuel capacity= 10/100 × 143,000= 14,300 pounds
Therefore, the total fuel required for the journey from Louisville International Airport to Salt Lake City is given by the sum of fuel required to fly to SLC plus the required reserve:
Total fuel required = Fuel required to fly to SLC + Reserve fuel required= 4.5 × 14,000 + 14,300= 77,300 pounds
To arrive at SLC with the FAA mandated reserve on board, the aircraft must be loaded with 77,300 pounds of fuel. Therefore, the amount of fuel to be added is 77,300 – 35,000 = 42,300 pounds.
The amount of fuel that needs to be added to the Airbus A300-S600 in order for it to arrive at Salt Lake City with the FAA mandated reserve on board is 42,300 pounds.
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For f(x) =2x, find a formula for the Riemann sum obtained by dividing the interval [2.5] subintervals and using the right hand endpoint for each ck. Simplify the sum and take the limit as n--> infinity to calculate the area under the curve over [2,5]
please show all of your work as be as descriptive as you can I appreciate your help thank you!
The area under the curve over [2,5] is 24.
Given function is f(x) = 2xIntervals [2, 5] is given and it is to be divided into subintervals.
Let us consider n subintervals. Therefore, width of each subinterval would be:
$$
\Delta x=\frac{b-a}{n}=\frac{5-2}{n}=\frac{3}{n}
$$Here, we are using right-hand end point. Therefore, the right-hand end points would be:$${ c }_{ k }=a+k\Delta x=2+k\cdot\frac{3}{n}=2+\frac{3k}{n}$$$$
\begin{aligned}
\therefore R &= \sum _{ k=1 }^{ n }{ f\left( { c }_{ k } \right) \Delta x } \\&=\sum _{ k=1 }^{ n }{ f\left( 2+\frac{3k}{n} \right) \cdot \frac{3}{n} }\\&=\sum _{ k=1 }^{ n }{ 2\cdot\left( 2+\frac{3k}{n} \right) \cdot \frac{3}{n} }\\&=\sum _{ k=1 }^{ n }{ \frac{12}{n}\cdot\left( 2+\frac{3k}{n} \right) }\\&=\sum _{ k=1 }^{ n }{ \frac{24}{n}+\frac{36k}{n^{ 2 }} }\\&=\frac{24}{n}\sum _{ k=1 }^{ n }{ 1 } +\frac{36}{n^{ 2 }}\sum _{ k=1 }^{ n }{ k } \\&= \frac{24n}{n}+\frac{36}{n^{ 2 }}\cdot\frac{n\left( n+1 \right)}{2}\\&= 24 + \frac{18\left( n+1 \right)}{n}
\end{aligned}
$$Take limit as n → ∞, so that $$
\begin{aligned}
A&=\lim _{ n\rightarrow \infty }{ R } \\&= \lim _{ n\rightarrow \infty }{ 24 + \frac{18\left( n+1 \right)}{n} } \\&= \boxed{24}
\end{aligned}
$$
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Given function f(x) = 2x. The interval is [2,5]. The number of subintervals, n is 3.
Therefore, the area under the curve over [2,5] is 21.
From the given data, we can see that the width of the interval is:
Δx = (5 - 2) / n
= 3/n
The endpoints of the subintervals are:
[2, 2 + Δx], [2 + Δx, 2 + 2Δx], [2 + 2Δx, 5]
Thus, the right endpoints of the subintervals are: 2 + Δx, 2 + 2Δx, 5
The formula for the Riemann sum is:
S = f(c1)Δx + f(c2)Δx + ... + f(cn)Δx
Here, we have to find a formula for the Riemann sum obtained by dividing the interval [2.5] subintervals and using the right hand endpoint for each ck. The width of each subinterval is:
Δx = (5 - 2) / n
= 3/n
Therefore,
Δx = 3/3
= 1
So, the subintervals are: [2, 3], [3, 4], [4, 5]
The right endpoints are:3, 4, 5. The formula for the Riemann sum is:
S = f(c1)Δx + f(c2)Δx + ... + f(cn)Δx
Here, Δx is 1, f(x) is 2x
∴ f(c1) = 2(3)
= 6,
f(c2) = 2(4)
= 8, and
f(c3) = 2(5)
= 10
∴ S = f(c1)Δx + f(c2)Δx + f(c3)Δx
= 6(1) + 8(1) + 10(1)
= 6 + 8 + 10
= 24
Therefore, the Riemann sum is 24.
To calculate the area under the curve over [2, 5], we take the limit of the Riemann sum as n → ∞.
∴ Area = ∫2^5f(x)dx
= ∫2^52xdx
= [x^2]2^5
= 25 - 4
= 21
Therefore, the area under the curve over [2,5] is 21.
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-4x - 2 (12x - 12) = 10 (12 - 2x) for x
Show work/ say the steps plz.
Determine the intercepts of the line.
Do not round your answers.
y=6x+13y=6x+13
Answer: X= -2.1667 Y= 13
considerastandard normal random variable z. what is the value ofzif the area to the right ofzis 0.2643?
To determine the value of the standard normal random variable z for which the area to the right of z is 0.2643, we can use the standard normal distribution table or a statistical software.
The value of z corresponding to an area to the right of z can be obtained by subtracting the given area from 1 since the area to the right is complementary to the area to the left. Therefore, the area to the left of z would be 1 - 0.2643 = 0.7357.
By referring to the standard normal distribution table or using a statistical software, we can find the z-value associated with an area of 0.7357. In this case, the z-value is approximately 0.611, indicating that the value of z for which the area to the right is 0.2643 is approximately 0.611.
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How Ex: A. Price of an item F is 280000L.L. After the discount the price is 235,000 1 item F 1x Calculate the percentage of discount d2=d1×3 ) if you buy 2 items of F 2 items of F the discount d₂=d₁ x 3 Calculate the price of F₁, F₂ 3) Adam had 1,000,000 L.L. How much he had after purchasing F1,F2
1) The discount percentage is 16.07%.
2) The discounted price of F₁, F₂ is $470,000
3) The amount that Adam had after purchasing F₁, F₂ is $530,000.
What is the discount percentage?The discount percentage is a product of the discount amount divided by the original cost, multiplied by 100.
Price of item F = $280,000
Discounted price = $235,000
Discount amount = $45,000 ($280,000 - $235,000)
Discount rate = 16.07% ($45,000/$280,000 x 100)
Discounted price of F₁, F₂ = $470,000 ($235,000 x 2)
The amount that Adam had before the purchase = $1,000,000
The amount he had after purchasing F₁, F₂ = $530,000 ($1,000,000 - $470,000).
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the population of a town was 9342 in 2010 and it is growing at 3.2% each year. in what year will the towns population reach 20000?
Answer:
By 2035 the town's population should be 20,532.
how many strings of length four can be formed using the letters abcde if repetitions are not allowed?
There are 120 strings of length four that can be formed using the letters abcde if repetitions are not allowed.
Since repetition is not allowed, we can use the counting principle to determine how many chains of four can be formed from the letters abcde.
The primary position has five choices (a, b, c, d, or e). For the second position, he has 4 choices (because he cannot use the letter he chose for the first position).
The third position has three choices and the fourth position has two choices.
Utilizing the increase guideline, able to multiply the number of choices for each position to urge the overall number of conceivable strings.
5x4x3x2 = 120
So, if repetition is not allowed, there are 120 strings of length 4 that can be formed using the characters abcde.
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Solve for x.
z=(x-h)k
Show work!!
Answer:
Step-by-step explanation: {
h=x−
k
z
,
k
=0
z=0 and k=0
x
=h
z=0 and x=h
z=(x−h)k
z=(x−h)k
Use the distributive property to multiply x−h by k.
z=xk−hk
Swap sides so that all variable terms are on the left hand side.
xk−hk=z
Subtract xk from both sides.
−hk=z−xk
The equation is in standard form.
(−k)h=z−kx
Divide both sides by −k.
−k
(−k)h
=
−k
z−kx
Dividing by −k undoes the multiplication by −k.
h=
−k
z−kx
Divide z−xk by −k.
h=x−
k
z
In the diagram AB/BC = AD/DE
Substitute the known values into the proportion and solve for DE
Answer: 9
Step-by-step explanation:
\(\frac{2}[3}=\frac{6}{DE}\\\\\frac{3}{2}=\frac{DE}{6}\\\\DE=9\)
Find a general solution to the following first-order differential equation for y(x): dy/dx - y/x = x^2
The general solution of the following first-order differential equation for \(y(x) : \frac{dy}{dx}-\frac{y}{x}=x^{2}\) is \(x^{3}+cx\).
We have to find the general solution of the given first order differential equation.
Let y = u*v, where u and v are functions of x.
Hence,
dy/dx = u*dv/dx + v*du/dx
Putting this in the given equation, we get,
\(u\frac{dv}{dx}+v\frac{du}{dx}-\frac{uv}{x}=x^{2}\\\\ u\frac{dv}{dx}+v(\frac{du}{dx}-\frac{u}{x} )=x^{2}\\\)
Putting the v term as 0, we get
du/dx - u/x = 0
du/dx = u/x
du/u = dx/x
Integrating both sides, we get
\(\int {\frac{1}{u} } } \, du=\int {\frac{1}{x} } \, dx\\\\\)
ln(u) = ln(x) + p
Let p = ln(k)
Hence,
ln(u) = ln(x) + ln(k)
ln(u) = ln(kx)
u = kx
Putting u = kx in the differential equation with v term 0 , we get
\((kx)\frac{dv}{dx} =x^{2}\\\\(k)dv=\frac{x^{2}dx}{x} \\\\(k)dv=(x)dx\\\\ \int {k} \, dv=\int {x}dx\\\\kv = x^{2}+c\\\\v=\frac{x^{2}+c}{k}\)
Putting v in y = uv, we get
\(y=kx*(\frac{x^{2}+c}{k} )\\\\y=x(x^{2}+c)\\\\y=x^{3}+cx\)
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Martin is driving to his uncle’s farm, which is 240 mi. from home. If he drives at a constant rate of 60 mph, how long will it take Martin to get to the farm? A. 2 hr. B. 4 hr. C. 5 hr. D. 6 hr.
Answer:
4 hours
Step-by-step explanation:
240 divided by 40
Answer:
4 hours
240 divided by 60
Step-by-step explanation:
Hope it helps
Opal is buying chocolates and flowers for valentine's day. She pays $15 for each bouquet and $5.80 for each box of chocolates. Her total bill comes out to $218.20 and she bought a total of 17 items. How bouquets and how many boxes of chocolates did she buy?
will list you brainlest please hurry
Answer:
0- -3 1/4+1 3/4
Step-by-step explanation:
i belive this is the answer, but im not 100% sure sry if im wrong
Jorge asked each of the 24 students in his class if they play a musical instrument. He also asked each student if they play a sport. He gathered the following results:
6 students play both a musical instrument and a sport.
3 students play neither a musical instrument nor a sport.
14 students in total play a sport.
Can you help Jorge organize the results into a two-way frequency table?
negative one fifth times the quantity 3 minus 12 timws the quantity one third squared end quantity end quantity
The expression - 1/5× ( 3 - 12 × (1/3)² is simplified to -1/3
What is a fraction?A fraction can be described as the part of a whole element, number or variable.
The types of fractions are;
Complex fractionsProper fractionsMixed fractionsImproper fractionsSimple fractionsFrom the information given, we have that;
- 1/5× ( 3 - 12 × (1/3)²
find the square
- 1/5 × ( 3- 12 × 1/9)
multiply the values
-1/5 × ( 3 - 4/3)
expand the bracket
- 1/5 × (9 -4 /3)
- 1/5 × 5/3
-5/15
- 1/3
Hence, the value is -1/3
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Line segment AB has endpoints A(−5,−8) and B(2,6). What are the coordinates of the point that partitions AB according to the part-to-part ratio 4:3?
O (-1, 0)
O (-2, -2)
O (-4, -6)
O (0, -1)
Line segment BA has endpoints B(−6,1) and A(4,6).
What are the coordinates of the point that partitions BA
according to the part-to-part ratio 2:3?
O (4, 0)
O (-2, 3)
O (3, -2)
O (0, 4)
Line segment AB has endpoints A(−1,6) and B(5,−6).
What are the coordinates of the point that partitions AB
according to the part-to-part ratio 1:5?
O (4, 0)
O (0, 4)
O (-4, 4)
O (4, -4)
Please help, asap! I have been stuck on this, and I really need to get it done. TYSM to whoever lends a hand.
BRAINLIEST, 5 STARS AND THANKS ONLY TO BEST/CORRECT ANSWERS!
For all 3 questions, we will use the section formula.
1) \(\left(\frac{(4)(2)+(3)(-5)}{7}, \frac{(4)(6)+(3)(-8)}{7} \right)=\boxed{(-1, 0)}\)
2) \(\left(\frac{(2)(4)+(3)(-6)}{5}, \frac{(2)(6)+(3)(1)}{5} \right)=\boxed{(-2, 3)}\)
3) \(\left(\frac{(1)(5)+(5)(-1)}{6}, \frac{(1)(-6)+(5)(6)}{6} \right)=\boxed{(0, 4)}\)
abc corporation issued $100,000 of 10%, 5-year bonds on january 1, year 1, for $92,280. the market interest rate when the bonds were issued was 12%. interest is paid semi-annually on january 1 and july 1. using the effective-interest amortization method, how much cash will abc pay bondholders on july 1, year 2
The cash that ABC Corporation will pay bondholders on July 1, year 2 can be calculated by using the effective-interest amortization method.
The first step is to determine the total interest expense for the year 2, which is the second semi-annual period of the bond. The total interest expense can be calculated by multiplying the carrying value of the bond, which is the initial issue price adjusted for any amortization of bond discount or premium, by the effective interest rate, which is the market rate at the time of issuance. Then, the semi-annual interest payment can be calculated by dividing the total interest expense by two.
Using the given information, the initial issue price of the bond is $92,280 and the market interest rate is 12%. The effective-interest rate can be calculated by using the present value of an annuity formula, which results in 6.52%. Therefore, the total interest expense for year 2 is $6,000, calculated as follows: $92,280 x 6.52%. The semi-annual interest payment is $3,000, calculated as follows: $6,000 ÷ 2. Thus, ABC Corporation will pay bondholders $3,000 in cash on July 1, year 2.
In summary, using the effective-interest amortization method, ABC Corporation will pay bondholders $3,000 in cash on July 1, year 2. This is calculated by first determining the total interest expense for the year 2, which is the second semi-annual period of the bond, by multiplying the carrying value of the bond by the effective interest rate. Then, the semi-annual interest payment is calculated by dividing the total interest expense by two.
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which set of coordinates satifies the equations 3x-2y=15 and 4x-y=20
Answer:
(5, 0) is the set of coordinates that satisfies the equations 3x - 2y = 15 and 4x - y = 20
Step-by-step explanation:
The two equations form a system of equations and solving the system will allow us to determine the set of coordinates that satisfies the equations:
Method: Elimination:
We can eliminate the ys first by multiplying the second equation by -2:
-2(4x - y = 20)
-8x + 2y = -40
Now we can add the two equations to solve for x:
3x - 2y = 15
+
-8x + 2y = -40
---------------------------
-5x = -25
x = 5
Now we can plug in 5 for x in any of the two equations to find y. Let's use the first equation:
3(5) - 2y = 15
15 - 2y = 15
-2y = 0
y = 0
Thus (5, 0) is the set of coordinates that satisfies the equations.
Check the validity of the answer:
We can check that our answer is correct by plugging in 5 for x and 0 for y in both equations and seeing if we get 15 on both sides for the first equation and 20 on both sides for the second equation:
Checking that x = 5 and y = 0 satisfy the first equation:
3(5) - 2(0) = 15
15 - 0 = 15
15 = 15
Checking that x = 5 and y = 0 satisfy the second equation:
4(5) - (0) = 20
20 - 0 = 20
20 = 20
Thus, our answer is correct.
When a set of coordinates satisfies a system of equations, it also means that the set of coordinates is the point where the two equations intersect. I attached a picture from Desmos that shows how the coordinates (5, 0) is the point where 3x - 2y = 15 and 4x - y = 20 intersect
the value of x from step 2 into the second equation:4(5) - y = 20y = 4(5) - 20y = 0Therefore, the set of coordinates that satisfies the given equations is (5,0).
The given equations are:3x - 2y = 154x - y = 20We are supposed to find out the set of coordinates that satisfies the given equations. In order to do that, we can use the method of substitution. The steps are given below:Rearrange the second equation in order to isolate y:4x - y = 20y = 4x - 20Substitute the value of y from step 1 into the first equation:3x - 2(4x - 20) = 153x - 8x + 40 = 15-5x = -25x = 5Substitute the value of x from step 2 into the second equation:4(5) - y = 20y = 4(5) - 20y = 0Therefore, the set of coordinates that satisfies the given equations is (5,0).
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help me pls I would aprreciate it
Answer:
b
Step-by-step explanation:
The distance between home plate and first base on a baseball diamond is 90 ft.
Home plate to second base is located at a distance of 90√2 feet.
A square is a rectangle in which each side is the same length. The distance separating the square's opposing vertices is known as the diagonal. The Pythagoras Theorem can be used to compute the diagonals:
Diagonal² = Side² + Side²
Diagonal² = 2 Side²
Diagonal = √2 Side
The answer to the question is that it is 90 feet from home plate to first base.
This is the length of the side that makes up the baseball diamond's square shape. The diagonal of the square is the distance from home plate to second base.
Diagonal = √2 Side
Diagonal = 90√2
Hence, home plate to second base is located at a distance of 90√2 feet.
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The question is incomplete. The complete question will be -
"A baseball diamond is square. The distance from home plate to first base is 90 feet. In feet, what is the distance from home plate to second base?"
Prove that the points P(-1,1) ,Q(2,3) and R(2,1) are the vertices of a salence triangle. Plz ans fast.
Step-by-step explanation:
P(-1,1), Q(2,3), R(2,1)
Let P(-1,1)be x1and y1
Q(2,3)be x2 and y2
therefore, by distance formula
d(PQ)= root (x2-x1)^2+(y2-y1)^2
= root[ 2-(-1)] + (3-1)
=root (2+1)^2+2^2
= root (3square +2square )
= root 9+4
d( PQ) = root 13.........(1)
Now find distance QR and PR then prove that the three sides are not equal and therefore it is a scalene triangle
2nd also do the same.
I’m literally gonna go insane from this TwT
G(Q) = 5 + 3Q + 202 - Q2 C2(Q) = 3 + 4Q + 2 1. Find the MC function for both C1(Q) AND C2(Q). 2. Find AVC function for both Ci(Q) AND C2(Q). 3. Find AFC function for both C1(Q) AND C2(Q). 4. Find AC function for both Ci(Q) AND C2(Q). 5. Find ATC function for both Ci(Q) AND C2(Q).
For C1(Q) = 3 - 2Q.
For C2(Q) = 4.
2. The AVC function
For C1(Q) = 5/Q + 3 + 20/Q - Q.
For C2(Q) = 3/Q + 4 + 2/Q.
3. The AFC function
For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)
For C2(Q) = 0.
4. To find the AC function
For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).
For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.
5.To find the ATC function
For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)
For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.
Find the ATC functions for C1(Q) and C2(Q) given the provided cost functions?
1. To find the MC function, we take the derivative of the cost functions with respect to Q.
For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.
For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.
2. To find the AVC function, we divide the cost functions by Q.
For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.
For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.
3. To find the AFC function, we subtract the AVC function from the ATC function.
For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)
= 5/Q - 20/(5 + 3Q + 20/Q - Q).
For
C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.
4. To find the AC function, we add the AVC function to the AFC function.
For
C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).
For
C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.
5. To find the ATC function, we divide the AC function by Q.
For
C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q
= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).
For
C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q
= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.
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7y-5x=17 in slope-intercept form
7y-5x = 17
7y = 5x+17
y = (5/7)x+(17/7)
Scientists found an animal skull during an excavation and tested the amount of carbon-14 left in it. They found that 55 percent of the carbon-14 in the skull remained. How many years ago was the animal buried? round your answer to nearest whole number. (hint: a = a0e-0. 000124t. ).
Scientists found an animal skull during an excavation and tested the amount of carbon -14 left in it. They found that 55 percent of the carbon-14 in the skull remained.
55% of the Carbon is left in the skull.
If A₀ was the original amount of Carbon, the amount of Carbon that is remaining will be 55% of A₀ which equals 0.55A₀
Using the given equation:
\(A = A_{o}e^{-0.000124t}\\\\ 0.55A_{o} = A_{o}e^{-0.000124t}\\ \\0.55 = e^{-0.000124t}\\\\In(0.55) = In(e^{-0.000124t})\\\\In(0.55) = -0.000124t*In(e)\\\\In(0.55) = -0.000124t\\\\\)
\(t = \frac{In(0.55)}{-0.000124} \\\\t = 4821\)
Rounding of to nearest year, we can conclude that the animal was buried 4821 years ago.
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If a figure is a square, its diagonals divide it into isosceles triangles.
p: A figure is a square.
q: A figure's diagonals divide into isosceles triangles.
Which represents the converse of this statement? Is the converse true?
The converse of the statement "If a figure is a square, its diagonals divide it into isosceles triangles" would be:
"If a figure's diagonals divide it into isosceles triangles, then the figure is a square."
The converse statement is not necessarily true. While it is true that in a square, the diagonals divide it into isosceles triangles, the converse does not hold. There are other shapes, such as rectangles and rhombuses, whose diagonals also divide them into isosceles triangles, but they are not squares. Therefore, the converse of the statement is not always true.
Therefore, the converse of the given statement is not true. The existence of diagonals dividing a figure into isosceles triangles does not guarantee that the figure is a square. It is possible for other shapes to exhibit this property as well.
In conclusion, the converse statement does not hold for all figures. It is important to note that the converse of a true statement is not always true, and separate analysis is required to determine the validity of the converse in specific cases.
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Factorise
4a(3a-b)+2b(3a-b)
Answer:
moi moi on that beat
Step-by-step explanation:
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find the solution to the system of equations? 4x-3y-z=3 , -3x+5y+z=9, x+2z=6
Answer:
is this the one?
Step-by-step exExplanation:
Adding third equation to first one,
7
x
+
5
y
+
z
+
x
−
6
y
−
z
=
0
−
18
or
8
x
−
y
=
−
18
.
(
1
)
Adding 2 times of third one to second one,
−
x
+
3
y
+
2
z
+
2
⋅
(
x
−
6
y
−
z
)
=
16
−
2
⋅
18
or
x
−
9
y
=
−
20
(
2
)
Substracting 8 times of
(
2
)
from
(
1
)
,
8
x
−
y
−
8
⋅
(
x
−
9
y
)
=
−
18
−
8
⋅
(
−
20
)
71
y
=
142
, so
y
=
2
Hence,
x
−
9
⋅
2
=
−
20
or
x
−
18
=
−
20
, so
x
=
−
2
Thus,
7
⋅
(
−
2
)
+
5
⋅
2
+
z
=
0
or
z
−
4
=
0
, so
z
=
4Explanation:
Adding third equation to first one,
7
x
+
5
y
+
z
+
x
−
6
y
−
z
=
0
−
18
or
8
x
−
y
=
−
18
.
(
1
)
Adding 2 times of third one to second one,
−
x
+
3
y
+
2
z
+
2
⋅
(
x
−
6
y
−
z
)
=
16
−
2
⋅
18
or
x
−
9
y
=
−
20
(
2
)
Substracting 8 times of
(
2
)
from
(
1
)
,
8
x
−
y
−
8
⋅
(
x
−
9
y
)
=
−
18
−
8
⋅
(
−
20
)
71
y
=
142
, so
y
=
2
Hence,
x
−
9
⋅
2
=
−
20
or
x
−
18
=
−
20
, so
x
=
−
2
Thus,
7
⋅
(
−
2
)
+
5
⋅
2
+
z
=
0
or
z
−
4
=
0
, so
z
=
4planation:
2x + 5 = 2x - 3 how many solutions ??
Answer:
-8
Step-by-step explanation:
Subtract 5 from both sides of the equation:
2+5=2−3
2+5−5=2−3−5
Simplify:
2=2−8
Subtract 2 from both sides of the equation:
2=2−8
2−2=2−8−2
Simplify:
0=−8
The solution to the algebraic expression has no solutions.
What is an algebraic expression?An algebraic expression comprises numbers, variables, and arithmetic operations with the aim of determining and finding a solution to the variables.
From the given expression, we have:
2x + 5 = 2x - 3
subtract 2x from both sides, we have:
2x -2x + 5 = 2x -2x - 3
5 = -3
Therefore, the solution algebraic equation has no solution since we don't have a variable to solve.
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