element that is the "best" at removing electrons from other atoms.

Answer:

Explanations:

Answer:

\(\% O=27.6\%\)

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

\(n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2} =0.218molC\)

- Moles of hydrogen are contained in the 3.922 grams of water:

\(n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH\)

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

\(m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO\)

Finally, we compute the percent by mass of oxygen:

\(\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%\)

Regards.

Answer:

Chemical rocket engines use a fuel (something to burn) and an oxidiser (something to react with the fuel). ... As the propellant reacts inside a combustion chamber, the chemical reaction produces hot gases. It is the ejection of these rapidly expanding hot gases at high speed from the rocket nozzle that

( I found this on a website called Science Learning. Full credit to them and their work. Check it out for more information)

The aldol condensation is an organic addition reaction for carbonyl compounds. propanal  undergo aldol addition with other propanal molecule producing the alpha-beta unsaturated aldehyde.

Aldol condensation is an organic reaction of carbonyl compounds taking place in presence of a base to produce beta-hydroxy carbonyl compound. Aldehydes and ketones undergo this type of reaction.

The mechanism of aldol reaction of propanal with 2,2 dimethyl propanal is given here. In the first step, the the base abstract the proton from the aldehyde.

The O- attack the carbonyl carbon of another aldehyde and form a bet-hydroxy aldehyde. This further undergo dehydration forming the alpha-beta unsaturated aldehyde.

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Answer:

b. (CH3CH2)2C(CH3)OH

Explanation:

Hello,

In this case, since the order of reactivity of alcohols is intimately related with their degree of substitution, being the tertiary alcohols the most reactive and the primary alcohols the least reactive since the adjacent substituents promote the -OH substitution or elimination, among the options, b. (CH3CH2)2C(CH3)OH which is a tertiary alcohol due to the presence of the OH at the central carbon atom bonded with two ethyl radicals and one methyl radical will react more rapidly with HBr than the other ones which are primary and secondary.

Best regards.

Answer:

d

Explanation:

higher no of particles are in CaCl2 solution

The depression in freezing point, elevation in boiling point, etc. are known as colligative particles. Here the CaCl2 solution has the higher boiling point and the NaCl solution has the lower freezing point. The correct option is D.

The properties of a dilute solution which depend only on the number of solute particles present in a given amount of solvent, and not in any way upon the nature of the solute particles are called colligative properties.

The elevation in boiling point is:

ΔTb = i × Kb × m

Here 'i' is the Van't Hoff factor, Kb is constant and 'm' is the molality.

The boiling point depends on the number of ions present in the electrolyte and the concentration. The number of ions in CaCl₂ is 3 whereas the number of ions in NaCl is 2.

ΔTb of CaCl₂ = 3 × 0.25 = 0.75

ΔTb of NaCl = 2 × 0.25 = 0.5

Similarly the freezing point depends on the number of particles of the electrolyte.

So CaCl₂ has boiling point and NaCl has low freezing point.

Thus the correct option is D.

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1) Diesel has a higher viscosity than petrol.

2) Petrol is more flammable than diesel.

3) The formula will be C₁₀H₂₂.

4) The equation is; 2C8H18+25O2→16CO2+18H2O.

Depending on the precise composition and temperature, the viscosity of gasoline and diesel can change. In general, diesel is more viscous than gasoline. Higher viscosity fluids are thicker and flow more slowly than lower viscosity fluids because viscosity relates to the resistance of a fluid to flow.

Diesel is less flammable than gasoline. The lowest temperature at which gasoline can evaporate and turn into an ignitable combination in air is known as its flash point, and it is lower for gasoline. Compared to diesel fuel, petrol vapors are much more flammable and can ignite at lower temperatures.

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Answer:

                                                                2CO(g) + O2(g) ⇌ 2CO2(g)

Increasing the concentration of CO -         ↓         ↓                 ↑

Increasing the concentration of CO2 -       ↑         ↑                 ↓

Explanation:

The given reaction is

2CO(g) + O2(g) ⇌ 2CO2(g)

a) When the concentration of CO is increased, the stress is relieved as the reaction that consumes the added CO occurs more rapidly than its reverse reaction, for example., the forward reaction rate increases. The equilibrium will shift in favor of the product. However, the concentration of reactants (CO and O2) decreases and product concentration (CO2) increases.

b) When the concentration of CO2 is increased, the stress is relieved as the reaction that consumes the added CO2 occurs more rapidly than its reverse reaction, for example., the rate of backward reaction increases. The equilibrium will shift in favor of the reactant. Therefore, the concentration of reactants (CO and O2) increases, and the product concentration (CO2) decreases.

Hope this helps!

There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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The concentration of H3O+  of 0.25 M NH4 Cl is calculated as 1.13 × 10⁻⁵ M.

Hydronium ion concentration is found from pH by reverse of the mathematical operation that is employed to find pH.

NH4Cl + H2O → NH4+ + Cl- + H2O

NH4+ + H2O → H3O+ + NH3

Ka = [H3O+][NH3] / [NH4+]

[NH4+] = 0.25 M - x

At equilibrium, the concentration of NH3 will also be equal to x (since NH4+ and NH3 are in a 1:1 ratio). The concentration of H3O+ will also be equal to x (since NH4+ donates a proton to form H3O+).

5.6 × 10-10 = (x)(x) / (0.25 - x)

x = 1.13 × 10⁻⁵ M

Therefore, the concentration of H3O+ is 1.13 × 10⁻⁵ M.

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Answer:

To determine the change in mass of A over the given time period, we need to find the difference between the initial mass of A and the final mass of A.

From the given table, we can see that the initial mass of A at t = 0 (start time) is 12.4 g and the final mass of A at t = 60 minutes (end time) is 6.2 g.

Therefore, the change in mass of A over 60 minutes is:

Final mass of A - Initial mass of A

= 6.2 g - 12.4 g

= -6.2 g

The negative sign indicates that the mass of A decreased over time, which means that A underwent some kind of reaction or process that caused it to lose mass.

The change in mass of A over 60 minutes is -6.2 grams.

To determine the change in mass of A over 60 minutes, we need to compare the initial mass to the final mass.

From the given information, we can see that the mass of A decreases over time.

Let's calculate the change in mass.

Initial Mass of A: 12.4 g

Final Mass of A: 6.2 g

Change in Mass of A = Final Mass of A - Initial Mass of A

= 6.2 g - 12.4 g

= -6.2 g

The change in mass of A over 60 minutes is -6.2 grams.

Note that the negative sign indicates a decrease in mass.

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Answer:B: Which type of backpack do students purchase most often

Explanation:   The right answer is B. because its a question you can graph informational data about, unlike any other answer. Hope this helped!

    ~Emilie Greene

Answer:

first choice

Explanation:

energy is written on the left side is its absorbed

2 elements came together so bonds are formed.

Answer:

\(\boxed {\boxed {\sf 333 \ grams}}\)

Explanation:

We are asked to find the mass of a sample of metal. We are given temperatures, specific heat, and joules of heat, so we will use the following formula.

\(Q= mc \Delta T\)

The heat added is 4500.0 Joules. The mass of the sample is unknown. The specific heat is 0.4494 Joules per gram degree Celsius. The difference in temperature is found by subtracting the initial temperature from the final temperature.

The sample was heated from 58.8 degrees Celsius to 88.9 degrees Celsius.

Now we know three variables:

Substitute these values into the formula.

\(4500.0 \ J = m (0.4494 \ J/g \textdegree C)(30.1 \textdegree C)\)

Multiply on the right side of the equation. The units of degrees Celsius cancel.

\(4500.0 \ J = m (13.52694 J/g)\)

We are solving for the mass, so we must isolate the variable m. It is being multiplied by 13.52694 Joules per gram. The inverse operation of multiplication is division, so we divide both sides by 13.52694 J/g

\(\frac {4500.0 \ J }{13.52694 J/g}= \frac{m (13.52694 J/g)}{13.52694 J/g}\)

The units of Joules cancel.

\(\frac {4500.0 \ J }{13.52694 J/g}= m\)

\(332.6694729 \ g =m\)

The original measurements have 5,4, and 3 significant figures. Our answer must have the least number or 3. For the number we found, that is the ones place. The 6 in the tenth place tells us to round the 2 up to a 3.

\(333 \ g \approx m\)

The mass of the sample of metal is approximately 333 grams.

The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.

Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.

The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.

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Answer: b) calcium sulfide

Explanation:

Answer:

See explanation

Explanation:

If we look at the structure of X, we will discover that X is an organic compound. The compound will certainly have a much lower melting point than sand.

This is because, sand is composed of high melting point inorganic materials.

Hence, even though the researcher accidentally spilled some sand into the the beaker containing the crystalline substance X, he does not need to be perturbed since the melting point of X is much lower than that of sand

Equation is known to be balanced when the number of moles of element at the reactant is equal to that of product.

Aluminum = Al

Hydrochloric acid = HCl

The reaction formed by Aluminum and hydrochloric acid is expressed as:

The balanced form of the reaction will be expressed as:

The balanced equation  \(K_{2}Cr_{2}O_{7}\) oxidizes KI in the presence of \(H_{2}SO_{4}\)can be represented as

6 KI + \(K_{2}Cr_{2}O_{7}\) + 7 \(H_{2}SO_{4}\) → 4 \(K_{2}Cr_{2}O_{7}\) + \(Cr_{2}(SO_{4})_{3}\) + 3 \(I_{2}\)\(I_{2}\) + 7 \(H_{2}O\)

The balanced equation for the oxidation of KI (potassium iodide) by \(K_{2}Cr_{2}O_{7}\)(potassium dichromate) in the presence of \(H_{2}SO_{4}\)(sulfuric acid) can be represented as follows:

6 KI + \(K_{2}Cr_{2}O_{7}\) + 7 \(H_{2}SO_{4}\) → 4 \(K_{2}Cr_{2}O_{7}\) + \(Cr_{2}(SO_{4})_{3}\) + 3 \(I_{2}\)\(I_{2}\) + 7 \(H_{2}O\)

In this equation, \(K_{2}Cr_{2}O_{7}\) is the oxidizing agent, and KI is the substance being oxidized. The sulfuric acid (\(H_{2}SO_{4}\)) serves as a catalyst and provides the necessary acidic conditions for the reaction to occur.

The products of the reaction are potassium sulfate (\(K_{2}SO_{4}\)), chromium(III) sulfate (\(Cr_{2}(SO_{4})_{3}\)), iodine (), and water (\(H_{2}O\)).

Note that this equation represents a stoichiometrically balanced equation, ensuring that the number of atoms of each element is the same on both sides of the equation.

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31). 1.088 L of oxygen gas will react with sodium to produce 3.87g of magnesium oxide.

32.) 4.93 grams of magnesium is produced when 3.96 grams of sodium reacts with magnesium chloride.

33). 9.52 grams of potassium chloride is produced when 4.7 L of chlorine reacts with 8.7g of potassium.

34). 90.35 grams of HCl is produced from the reaction of 47.3 L of chlorine with 2.50 g of hydrogen (H₂) as the limiting reactant.

31.) To determine the volume of oxygen gas (O₂) that will react with sodium to produce 3.87g of magnesium oxide (MgO), we first need to balance the chemical equation:

4Na + O₂ → 2Na₂O

From the balanced equation, we can see that the molar ratio between O₂ and MgO is 1:2. The molar mass of MgO is 40.31 g/mol. Using these values, we can calculate the number of moles of MgO produced:

moles of MgO = (3.87 g MgO) / (40.31 g/mol MgO) = 0.096 mol MgO

Since the molar ratio between O₂ and MgO is 1:2, we know that 0.096 mol of MgO requires 0.048 mol of O₂.

Now, we can use the ideal gas law to find the volume of O₂ at standard temperature and pressure (STP) conditions (0°C and 1 atm):

PV = nRT

V = (nRT) / P

= [(0.048 mol)(0.0821 L·atm/(mol·K))(273 K)] / (1 atm)

= 1.088 L

32). To determine the mass of magnesium (Mg) produced when 3.96 grams of sodium reacts with magnesium chloride (MgCl₂) to produce sodium chloride (NaCl), we need to balance the chemical equation:

2Na + MgCl₂ → Mg + 2NaCl

From the balanced equation, we can see that the molar ratio between sodium (Na) and magnesium (Mg) is 2:1. The molar mass of Mg is 24.31 g/mol. Using these values, we can calculate the number of moles of Mg:

moles of Mg = (3.96 g Na) / (22.99 g/mol Na) * (1 mol Mg / 2 mol Na) * (24.31 g/mol Mg)

= 4.93 g Mg

33). In the reaction where 4.7 L of chlorine (Cl₂) reacts with 8.7g of potassium (K), the balanced equation is:

2K + Cl₂ → 2KCl

From the balanced equation, we can see that the molar ratio between potassium (K) and potassium chloride (KCl) is 2:2 or 1:1. The molar mass of KCl is 74.55 g/mol. Using these values, we can calculate the number of moles of KCl produced:

moles of KCl = (8.7 g K) / (39.10 g/mol K) * (1 mol KCl / 2 mol K) * (74.55 g/mol KCl)

= 9.52 g KCl

34. To determine the limiting reactant and the mass of HCl produced, we need to compare the amount of HCl that can be formed from each reactant and identify the reactant that produces the lesser amount of HCl.

The balanced equation for the reaction is:

H₂ + Cl₂ → 2HCl

From the balanced equation, we can see that the molar ratio between H₂ and HCl is 1:2. This means that 1 mole of H₂ produces 2 moles of HCl.

First, let's calculate the number of moles of HCl that can be produced from 47.3 L of Cl₂ using the ideal gas law at STP conditions:

PV = nRT

n = (PV) / RT

= (1 atm)(47.3 L) / (0.0821 L·atm/(mol·K))(273 K)

= 2.10 mol Cl₂

Since the molar ratio between Cl₂ and HCl is 1:2, we know that 2.10 moles of Cl₂ can produce 2.10 * 2 = 4.20 moles of HCl.

Next, let's calculate the number of moles of HCl that can be produced from 2.50 g of H₂:

moles of H₂ = (2.50 g H₂) / (2.02 g/mol H₂)

= 1.24 mol H₂

Since the molar ratio between H₂ and HCl is 1:2, we know that 1.24 moles of H₂ can produce 1.24 * 2 = 2.48 moles of HCl.

Mass of HCl produced from 2.50 g of H₂:

mass of HCl = (2.48 mol HCl) * (36.46 g/mol HCl)

= 90.35 g HCl

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Answer:

give me brainliest

Explanation:

The shielding effect sometimes referred to as atomic shielding or electron shielding describes the attraction between an electron and the nucleus in any atom with more than one electron. The shielding effect sometimes referred to as atomic shielding or electron shielding describes the attraction between an electron and the nucleus in any atom with more than one electron.

Answer:

The shielding effect can be defined as a reduction in the effective nuclear charge on the electron cloud

Explanation:

i am not sure but i hope it will help you

Answer:

88.46%

Explanation:

Percentage yield is actual/theoretical * 100

138/156 * 100 = 88.4615385

Answer:

B

Explanation:

"I think my bike is making a scraping noise because the bearings are not lubricated."

The net ionic equation for this gas evolution reaction is H+(aq) + SO32-(aq) SO2(g) + H2O, while the balanced molecular equation is 2HBr(aq) + K2SO3(aq) SO2(g) + 2H2O(l) + 2KBr(aq) (l).

The reaction's chemical formula is K2CO3(aq)+2HBr(aq)2KBr(aq)+CO2(g)+H2O. (l) Strong electrolytes in the process, K2CO3, HBr, and KBr totally dissociate in water to generate their corresponding ions.

A salt (the KBr) and water will be created when the HBr and KOH interact. While balancing this equation, make careful to count both hydrogen atoms on the reactants side.

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Yes, a research in 2012 called the ENCODE project showed that about 75% of noncoding DNA or Junk DNA do get transcribed.

The term "Junk DNA" is often used to refer to regions of the DNA that do not appear to code for functional genes, and their function or lack thereof is still a subject of active research and debate in the scientific community.

While it was once believed that these non-coding regions of DNA were "junk" and had no functional role, recent research has shown that some of these regions may have important regulatory functions, such as controlling gene expression or modulating chromosome structure.

In 2012, the ENCODE project determined that around three-quarters of the noncoding DNA in the human genome did undertake transcription and that almost half of the genome was accessible to proteins involved in genetic control such as transcription factors.

Some scientists, however, have questioned these findings, claiming that the accessibility of these genomic sequences to transcription factors does not necessarily imply that they have any biochemical significance or that transcription of the segments is favorable in terms of evolution.

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The mass of the water that could be brought to the boiling point is equal to 4481.35 g. Therefore, option (C) is correct.

The specific heat capacity of a substance is defined as the quantity of heat required to increase the temperature in one unit of substance by one-degree Celcius.

Whenever the energy is lost or absorbed the temperature of the substance will be changed:

Q = mCΔT

Given, the amount of energy transferred, Q = 1500 Kj

The change in the temperature = 100 -20 = 80°C

The specific heat capacity of the water, C = 4.184 J/g°C

The mass of the water for the given change in temperatures can be calculated as:

1500 KJ = m × (4.184 J/g°C) × 80°C

m = 4481.35 g

Therefore, the mass of the water is 4481/35 grams.

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Nickel has 28 electrons, its electron configuration is:

Ni2+ has lost 2 electrons, which means that the resulting configuration would be:

Nevertheless, since 4s electrons are further from the nucleus, they are lost resulting in a more stable ion, then, the actual configuration of Ni2+ is:

It means that this ion has 16 valence electrons.

Answer:

The forces that keep liquid particles together are called intermolecular forces of attraction.

A change in the substrate's oxidation state occurs during redox reactions. Oxidation is the process of losing electrons or increasing an element's oxidation state.

Gaining electrons or lowering the oxidation state of an element or its constituent atoms are both examples of reduction.

An oxidation-reduction (redox) reaction is a chemical process in which two compounds exchange electrons. Any chemical process in which a molecule, atom, or ion suffers a change in its oxidation number as a result of acquiring or losing an electron is known as an oxidation-reduction reaction.

An oxidizing agent is a substance that "accepts" or "receives" an electron from a reducing agent in a redox chemical process. Therefore, an oxidant is any chemical that oxidizes another substance.

An electron is "donated" to an electron acceptor by a chemical species known as a reducing agent. Chemicals that are often used as reducing agents include the Earth metals, formic acid, oxalic acid, and sulfite compounds.

Pb gets oxidized.

Manganese (Mn) gets reduced.

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