emily is hiking in the mountains. she takes a break to look out at the horizon and notices the mountains in the distance are blurry and appear to have a blue tint. what is this called?

Answer:

1.  to relate the type of box material to the temperature of the air within the box

2. Question is incomplete

3. scatterplot

Explanation:

1. The only thing done differently in this experiment is the type of material used in making the boxes, hence the experiment must be about that. Before proceeding to answering this question, we must have this at the back of our minds.

We can gather from the experiment that the boxes are of the same size and were subjected to sunlight for an hour (the same time duration for both). Hence, the temperature of the air inside the box will only be affected by the type of material the box is made of since the boxes have the same size and were subjected to sunlight for the same duration.

From the options provided, the best description for this experiment is; to relate the type of box material to the temperature of the air within the box.

2. The question is incomplete. The value for speed/velocity needed to calculate the average time is missing.

However, the formula needed here is velocity = distance ÷ time

3. There are two variables in this experiment; distance and time

The type of graph that shows two variables on it (of the options provided) is the scatterplot.

Answer:

It is cold at saturn and far away

Explanation:

Answer:

because liquid and solid states of water possesses intermolecular force of attraction which held the molecules of water in fixed

The speed of the ball just before it strikes the ground is 22.8m/s.

An object's power as a result of motion is known as kinetic energy. A force must be applied if we want to accelerate an object. We must exert effort in order to use force. Once the work is finished, the object will be moving at a new, constant speed because energy has been transferred to it.

When the ball is about to hit the ground, its speed

Ki + Ui = Kf + Uf

1/2m\(v_{i} ^{2}\) + mg\(h_{i}\) = 1/2m\(v^{2} _{f}\) + mg\(h_{f}\)

1/2 \(v_{i} ^{2}\) + g\(h_{i}\)  = 1/2 \(v^{2} _{f}\) + g\(h_{f}\)

\(v^{2} _{f}\) =  \(v_{i} ^{2}\) + 2g (\(h_{i}\) - \(h_{f}\))

\(v^{2} _{f}\) = 10.6 + 2(9.8)(20.8 - 0)

\(v_{f}\)= 22.8m/s

f stands for frictional force, s for distance, and the minus sign denotes that the frictional force is doing the work 57.3° above the horizontal and in part (b) the initial velocity makes an angle of 57.3°.

Since the initial velocity creates an angle of because of part (a),

The horizontal, and as a result, part (distance )'s from the ground is greater than part (b's).

As the distance in part (a) increases, so does the impact of air resistance. Therefore, more effort should be made to overcome the air resistance. The ball's final speed is lowered as a result.

Since the distance is shorter in part (b), the impact of air resistance is also smaller. Therefore, less effort should be made to overcome the air resistance. As a result, the ball's final speed is increased.

Less work should be done in part (b) than in part (a) because the distance in part (b) is shorter than the distance in part (a) (a). As a result, part (b) has a higher final ball speed than part (a).

The amount of work done directly relates to the distance. The amount of work done increases with distance.

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Answer:

Zero

Explanation:

Zero....  Inertia states a body in motion will remain in motion unless acted on by external forces.... no friction forces means it needs no force to keep going

Answer:

Explanation:

Field characteristics

The strength of the field at the Earth's surface ranges from less than 30 microteslas (0.3 gauss) in an area including most of South America and South Africa to over 60 microteslas (0.6 gauss) around the magnetic poles in northern Canada and south of Australia, and in part of Siberia.

Answer:

divide the number of times the event occurs by the length of time.

Explanation:

The gravitational force of attraction between them is 3.56 * 10⁻⁴ N

F = G*M1M2/d²,

where G = 6.67 * 10⁻¹¹ Nm²Kg⁻²,

M1 = 8000Kg and M2 = 1500 Kg,

F =  6.67 * 10⁻¹¹ * 8000 * 1500 / (1.5)² F = 3.56 * 10⁻⁴ N

The gravitational force of attraction between them is 3.56 * 10⁻⁴ N.

The universal gravitational law of Newton. According to this law, every body in the universe is attracted to every other body with a force that is inversely proportional to the square of the distance between them and proportional to the product of their masses.

Therefore, The gravitational force of attraction between them is 3.56 * 10⁻⁴ N.

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The approximate average force exerted by the pogo stick on the ground during the landing is 1960 N.

To calculate this force, we can use the principle of conservation of mechanical energy. The potential energy at the high point of the jump is converted into kinetic energy as the pogo stick descends.

The potential energy at the high point is given by the formula:

PE = m * g * h,

where m is the mass (80 kg), g is the acceleration due to gravity (approximately 9.8 m/s²), and h is the height (2.0 mm = 0.002 m).

PE = 80 kg * 9.8 m/s² * 0.002 m.

Next, we calculate the change in potential energy as the pogo stick descends:

ΔPE = PE_initial - PE_final,

where PE_initial is the potential energy at the high point and PE_final is the potential energy at the lowest point.

ΔPE = (80 kg * 9.8 m/s² * 0.002 m) - (80 kg * 9.8 m/s² * 0.0015 m).

The change in potential energy is converted into work done by the average force exerted on the ground. Since work is the product of force and distance, we can write:

ΔPE = F_avg * d,

where F_avg is the average force and d is the distance over which the force is applied.

Substituting the values:

(80 kg * 9.8 m/s² * 0.0015 m) = F_avg * (0.004 m).

Solving for F_avg:

F_avg = (80 kg * 9.8 m/s² * 0.0015 m) / (0.004 m).

F_avg ≈ 1960 N.

Therefore, the approximate average force exerted by the pogo stick on the ground during the landing is 1960 N.

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To calculate the time required for a radioactive isotope with a half-life of 16.9 min to decay from a 3.27 mCi sample to -351 mCi, we need to use the equation for exponential decay. By rearranging the formula and solving for time, we can find the desired duration.

The decay of a radioactive isotope follows an exponential decay model. The equation for the decay is given by N = N₀ * (1/2)^(t/t₁/₂), where N is the final amount, N₀ is the initial amount, t is the time elapsed, and t₁/₂ is the half-life.

In this case, we want to find the time it takes for the sample to decay from 3.27 mCi to -351 mCi. Let's denote the initial amount as N₀ = 3.27 mCi and the final amount as N = -351 mCi.

To find the time, we can rearrange the equation as t = t₁/₂ * log₂(N/N₀). Substituting the values, we have t = 16.9 min * log₂((-351 mCi)/(3.27 mCi)).

By evaluating this expression, we can determine the number of minutes it will take for the 3.27 mCi sample to decay to -351 mCi.

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Answer:

Centripetal force and Centrifugal force.

» similarities

• Both these forces act on a body moving in circular path ( circular motion )

• Both these forces can occur in a simple harmonic motion. ( S.H.M )

» differences

• Centripetal force acts towards the centre of circular path while centrifugal force acts away from the centre.

• Centripetal force is inversely proportional to radius of circular path while Centrifugal force is directly proportional to radius of the circular path.

Explanation:

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Answer:The difference between air temperature and dew point is less than 4.5 degrees Fahrenheit when fog can form.

Explanation:This can occur because of added moisture or falling air temperatures. The difference between air temperature and dew point is less than 4.5 degrees Fahrenheit when fog forms.

Answer:true

Explanation:\(U\)

Answer:

The times are equal

Explanation:

The current in the circuit is  ≈ 2.07 amperes (A)

A current circuit is a closed path through which electric current can flow. It typically consists of a power source, such as a battery or generator, a load, such as a light bulb or motor, and conductive wires or other components that connect the power source and load to form a complete path for the current to flow.

The current in the circuit can be calculated using the formula:

current = charge / time

In this case, the charge moved around the circuit is 60 coulombs and the time taken is 29 seconds. Thus, the current in the circuit is:

current = 60 coulombs / 29 seconds

current ≈ 2.07 amperes (A)

Therefore, The current in the circuit is  ≈ 2.07 amperes (A)

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Answer:

C. answer pa brailest need lang po please

D. Resource Supply this would be directly affected first then the rest would follow after a period of time.

Answer:

Ally has a harder time

ally takes more time

juan is quick

juan is more experienced

if none of those are awnser choices what are the awnser choices?

Explanation:

The acceleration is the same, if the initial velocity is the same, the times of going up and down are the same.

If the initial velocity is the same for both processes, the acceleration is the same and the times are the same.

The relationship between the net force, the masses, and the acceleration of the bodies is established by Newton's second law.  

∑ F = m a

In the image of the block moving up and down the ramp in the attached, a free-body can be observed; in this example, the x-axis is parallel to the ramp and the y-axis is perpendicular. The reference system is a coordinate system with respect to which the forces are depicted.

Sinθ =  Wₓ/W

Cosθ =  W_y/W

Wₓ = WSinθ

W_y = Wcosθ  

Newton's second law for each axis.

Case 1. Block slides down on x-axis

Wₓ = ma

mg sinθ = ma

a = g sin θ

Case 2. Block rises

X-axis

- Wₓ = m a

- mgsin θ = a

a = - g sin θ

Acceleration is equal in both cases, if the block has the same initial speed, the rise and fall time is the same.

y = v₀ t - ½ a t²

y = ½ a t²

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Your question is incomplete, most probably the full question is this:

(b) The block takes time tup to slide up the ramp a distance x The block then takes time down to slide back down to the bottom of the ramp, where it has speed up. Is flows greater than equal to

or less tup?

tdown >tup -tdown = tup .tdown In a clear, coherent paragraph-length response that may also contain figures and/or equations, explain your reasoning. If you need to draw anything other than what you have shown in part (a) to

assist in your response, use the space below. Do NOT add anything to the figures in part (a).

Answer: If mass remains constant and you double the force you will double the acceleration.

Answer:

It has producer-consumer relationship with sugar-maple trees because it gets food from the trees.

Explanation:

The mourning bird is primarily a seed eater and not an insect eater. Since it is a seed eater, it will directly from the sugar-maple tree which is the producer.

In an ecosystem, the producers are plants which can trap energy directly from the sun during photosynthesis. This energy is passed on to the consumers.

Hence, the mourning bird has producer-consumer relationship with sugar-maple trees because it gets food from the trees.

Scientists think the most likely reason is that it was heated by tidal forces from Jupiter.

This is known as the gravitational effect that stretches an object along the line towards the center of mass of another object as a result of gradient in gravitational field from the other body.

The moon Ganymede having a magnetic field, indicating that its interior was at least partly melted and warm was however as a result of tidal forces from Jupiter which caused the heating.

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The correct answer is linear momentum is converted to angular momentum. When the skater hops onto one end of the board, they introduce a force that causes the board to move and rotate.

This force changes the linear momentum of the board and the skater, which is then converted into angular momentum as the board starts to rotate.

In this situation, the correct answer is: e. Linear momentum and angular momentum are both conserved.

The skater and the board together can be treated as an isolated system since there is no external force acting on them due to the frictionless ice.
In an isolated system, linear momentum and angular momentum are conserved separately.
When the skater hops onto the board, their linear momentum is transferred to the board, causing it to slide. This means the total linear momentum before and after the hop remains the same.
Simultaneously, as the skater hops onto one end of the board, they apply a torque to the board, causing it to rotate. Since there is no external torque acting on the system, the total angular momentum is also conserved.

Therefore, option a is the correct answer. The other options are not applicable in this situation as there is no conservation of kinetic energy or translational kinetic energy. However, angular momentum is conserved in this situation.

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To solve this problem, we can use the continuity equation, which states that the mass flow rate (the rate at which mass flows through a point in a system) must be constant throughout the system. In other words, the mass flow rate at point 1 must equal the mass flow rate at point 2.

The mass flow rate is equal to the density of the fluid times the flow rate (also known as the volume flow rate). The flow rate is equal to the cross-sectional area of the tube times the velocity of the fluid. Therefore, we can write the continuity equation as:

density \(${ }^*\left(\right.$\) cross-sectional area \(${ }^*$\) velocity )=constant

We can rearrange this equation to solve for the velocity at each point:

velocity = constant  (density* cross-sectional area)

At point 1 , the velocity can be calculated as follows:

\($\mathrm{V} 1=$\)constant\($/\left(\right.$\) density\($\left.{ }^* \mathrm{~A} 1\right\))= constant \($/\left(\right.$\) density \($\left.* 1.00 \mathrm{~cm}^{\wedge} 2\right)$\)

At point 2, the velocity can be calculated as follows:

V 2 = constant\($/($ density $* A 2)\)= constant \($/\left(\right.$\) density \($\left.* 4.00 \mathrm{~cm}^{\wedge} 2\right)$\)

We can find the value of the constant by using the pressure difference between the two points and the ideal gas law:

\($$\mathrm{P} 1-\mathrm{P} 2=\left(\text { density }^* \text { velocity }^{\wedge} 2\right) / 2$$\)

Substituting the known values, we have:

\($$9.45 \mathrm{kPa}=\left(\text { density }{ }^* \mathrm{~V} 1^{\wedge} 2\right) / 2$$\)

Note that the density of glycerin is not given, so we cannot calculate the exact values of V1 and V2. However, we can still determine the relationships between the velocities at the two points. Specifically, we can see that the velocity at point 2 is half the velocity at point 1 .

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The value that we get by solving the equation is 3. This we get by solving the equation and with the help of given values of u and t.

In mathematical formulas, the equals sign is used to indicate that two expressions are equal. The meaning of the word equation and its cognates might vary slightly depending on the language. For example, an equation in English is defined as any properly expressed formula that consists of two expressions connected by the equals sign, whereas an equation in French is defined as having one or more variables.

According to the question, the given values are :

u = 11 and,

t = 9.

The given equation is :

3 + 11 t - 9 u

Substitute the given values of u and t in the equation :

3 + 11 (9) - 9 (11)

= 3

Hence, after solving the equation, the value we get is 3.

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You can prevent a mask from fogging under water by lowering the surface tension of the water.

Surface tension is the measure of how strongly the molecules of a liquid are attracted to each other at the surface.

When the surface tension of water is high, it causes water molecules to form a cohesive layer, which can trap air and lead to fogging on surfaces like a diving mask. To prevent this, an anti-fog solution or spray can be applied to the inside of the mask's lenses.

These solutions work by reducing the surface tension of the water droplets that form on the lens, allowing them to spread out and form a thin, uniform layer that is less likely to fog up.

A well-fitting mask can also help prevent water from seeping in, which can contribute to fogging.

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Answer:  

-not fully submerging the object when doing the fluid displacement procedure

-water that is left behind in the collection container when it is transferred for measurement

-water that soaks into the materials of the balls, affecting the mass in repeated trials

-water in the bucket, approximated to the closest 10 mL due to surface tension at the top of the bucket

Answer:

A, B, C, E

Explanation:

According to potential energy, the height of the object is 2.296 meters.

We need to know about potential energy to solve this problem. The potential energy is the object's energy caused by its position. Potential energy can be determined as

PE = m . g . h

where PE is potential energy, m is mass, g is the gravitational acceleration (9.8 m/s²) and h is height.

From the question above, we know that

PE = 342 joules

m = 15.2 kg

By substituting the given parameters, we can calculate the height

PE = m . g . h

342 = 15.2 . 9.8 . h

148.96 h = 342

h = 2.296 meters

Hence, the height of the object from the ground is 2.296 meters.

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By substituting the appropriate values and performing the calculations, you can determine the final pressure (Pf) in the tank.

To determine the final pressure in the tank, we can use the ideal gas law, which states:

PV = nRT

where:

P is the pressure,

V is the volume,

n is the number of moles,

R is the ideal gas constant, and

T is the temperature in Kelvin.

Let's assume the number of moles in each tank is represented by n1 and n2 for the initial and final states, respectively.

For the first tank:

Initial temperature, T1 = 20°C = 293.15 K

Initial pressure, P1 = 600 kPa

For the second tank:

Initial temperature, T2 = 30°C = 303.15 K

Initial pressure, P2 = 150 kPa

Volume, V2 = 0.5 m^3

Both tanks reach thermal equilibrium at 15°C = 288.15 K.

Since the tanks are connected and the valve is opened, the total number of moles remains constant. Therefore, we can write the equation:

n1 * R * T1 / V1 = n2 * R * T2 / V2

Since the tanks are rigid, the volumes (V1 and V2) remain constant. Thus, the equation simplifies to:

n1 * T1 = n2 * T2

We can solve for n2 by rearranging the equation:

n2 = n1 * T1 / T2

Now, let's calculate n2:

n2 = n1 * T1 / T2

   = P1 * V1 / (R * T1) * T1 / T2

   = P1 * V1 / (R * T2)

Substituting the values:

n2 = (600 kPa * V1) / (R * 293.15 K)

Now, we can calculate the final pressure (Pf) in the tank using the ideal gas law:

Pf * V2 = n2 * R * T3

where T3 is the final temperature of the system, which is 15°C = 288.15 K.

Solving for Pf:

Pf = (n2 * R * T3) / V2

  = [(600 kPa * V1) / (R * 293.15 K)] * (R * 288.15 K) / 0.5 m^3

The ideal gas constant R is approximately 8.314 J/(mol·K). Substituting this value:

Pf = [(600 kPa * V1) / (8.314 J/(mol·K) * 293.15 K)] * (8.314 J/(mol·K) * 288.15 K) / 0.5 m^3

By substituting the appropriate values and performing the calculations, you can determine the final pressure (Pf) in the tank.

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The final pressure in the tank is 433.5 kPa.

Given:

Rigid tank containing hydrogen at 20°C and 600 kPa.

Rigid tank containing hydrogen at 30°C and 150 kPa.

Temperature of surroundings is 15°C.

The first law of thermodynamics can be applied to a closed system such as this one:ΔU = Q - W

Where U is the internal energy of the system, Q is the heat transferred to the system, and W is the work done by the system.

In this case, since the tanks are rigid, there is no expansion or compression of the hydrogen, so no work is done:

W = 0

Also, since the system is allowed to come to thermal equilibrium with its surroundings, the heat transfer Q can be assumed to be equal to the heat absorbed by the surroundings, which can be expressed as:

Q = mCΔT

where m is the mass of the system, C is the specific heat capacity of hydrogen, and ΔT is the change in temperature of the system.

Since there is no information given about the masses of hydrogen in the tanks, we can instead work with the ideal gas law:PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature. Rearranging this equation gives:

n = PV/RT

We can then solve for n in both tanks and add them together to get the total number of moles of hydrogen in the system:

n1 = P1V1/RT1

n2 = P2V2/RT2

n = n1 + n2

= P1V1/RT1 + P2V2/RT2

Using the ideal gas law again, we can solve for the final pressure of the system:

P = nRT/(V1 + V2)

We can now substitute the given values and solve for the final pressure:

P = (P1V1/RT1 + P2V2/RT2)RT/(V1 + V2)

= (600 kPa * 0.5 m3)/(8.314 J/mol K * 293 K) + (150 kPa * 0.5 m3)/(8.314 J/mol K * 303 K)(8.314 J/mol K * 294 K)/(0.5 m3 + 0.5 m3)

P = 433.5 kPa

Therefore, the final pressure in the tank is 433.5 kPa.

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Answer:

exothermic reaction

Explanation:

Exothermic reactions are reactions or processes that release energy, usually in the form of heat or light. In an exothermic reaction, energy is released because the total energy of the products is less than the total energy of the reactants.