Exercise releases chemicals in our bodies called

Answers

Answer 1

Answer:

endorphins

Explanation:


Related Questions

What is the economic term for the act of sacrificing one good or service to purchase or produce another?

Answers

Answer:

Trade-off. sacrificing one good or service to purchase or produce another.

The curved section of a horizontal highway is a circular unbanked arc of radius 550 m. If the coefficient of static friction between this roadway and typical tires is 0.30, what would be the maximum safe driving speed for this horizontal curved section of highway?

Answers

Answer:

The value is \(v = 40.20 \ m/s\)

Explanation:

From the question we are told that

The radius is  \(r = 550 \ m\)

  The coefficient of static friction is \(\mu = 0.30\)

   Generally the maximum safe driving speed is mathematically represented as

        \(v = \sqrt{\mu * r * g }\)

=>     \(v = \sqrt{ 0.30 * 550 * 9.8 }\)

=>     \(v = 40.20 \ m/s\)

At t=3s, Bob was at x=9. If Bob has an average velocity of -4/s, what is his velocity at 11s?

Answers

The velocity of Bob at 11 seconds is 4.27 m/s.

What is the velocity of Bob at 11 seconds?

The velocity of Bob at 11 seconds is calculated by applying average velocity formula as shown below.

v = ( total displacement ) / ( total time )

v = ( X₃ + X₁₁ ) / ( 3 + 11 )

where;

X₃ is the displacement at 3 secondsX₁₁ is the displacement at 11 secondsv is the average velocity = 4 m/s

4 = ( 9 + 11u ) / ( 14 )

where;

u is the velocity at 11 s

The velocity of Bob at 11 seconds is calculated as;

4 = ( 9 + 11u ) / 14

9 + 11u = 56

11u = 56 - 9

11u = 47

u = 47 / 11

u = 4.27 m/s

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NEED HELP ASAP PLEASE

NEED HELP ASAP PLEASE

Answers

Answer:

It is Nice A since it's temp increases slower

Explanation:

hope this helped

A 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

Answers

Answer:

132 N

Explanation:

Given that a  1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

From Newton 2nd law of motion,

Change in momentum = impulse.

Change in momentum = m( V - U )

Substitute all the parameters into the formula

Change in momentum = 1.1 ( 4.5 - 1.5 )

Change in momentum = 1.1 × 3

Change in momentum = 3.3 kgm/s

Impulse = Ft

That is,

Ft = 3.3

Substitute time t into the formula above

F × 0.025 = 3.3

F = 3.3 / 0.025

F = 132 N

Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.

How many days are required for a radioactive sample, with a half-life of 5.7 days and an initial activity
of 1.07 × 105 Bq, to decay to an activity of 100 Bq?

Answers

It takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

The formula for radioactive decay is \(A = A0 * (1/2)^{(t/t1/2)}\) where: A is the final activity A0 is the initial activity is the time elapsed t1/2 is the half-life of the sample

In this problem, the initial activity A0 is given as 1.07 x 105 Bq and the final activity A is given as 100 Bq.

The half-life of the sample is given as 5.7 days.

Substituting these values into the formula, we get: \(100 = 1.07 \times 105 * (1/2)^{(t/5.7)}\)

Dividing both sides by 1.07 x 105, we get:

\(0.000934579 = (1/2)^{(t/5.7)}\)

Taking the natural logarithm of both sides, we get:\(-7.072737 = (t/5.7) * ln(1/2)\)

Dividing both sides by ln(1/2), we get:

\(t = -7.072737 \div ln(1/2) * 5.7t \approx 28.3\) days

Therefore, it takes approximately 28.3 days for the radioactive sample to decay from an initial activity of 1.07 x 105 Bq to an activity of 100 Bq.

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On Earth, we experience lunar and solar eclipses. what types of eclipses (if any) would an inhabitant of the moon experience? Explain.

Answers

Answer:

However, those astronauts would experience a second spectacle: A solar eclipse caused by the Earth – the Sun disappearing behind the dark disc of the Earth. When Earth inhabitants witness a lunar eclipse, Moon inhabitants would, simultaneously be witnessing a solar eclipse.

If the Moon did not rotate at the same rate that it revolved, which of the following would be true?​

If the Moon did not rotate at the same rate that it revolved, which of the following would be true?

Answers

Answer:

There will be no tides

Explanation:

How far does a car travel in 4 s if its initial velocity is 3 m/s and its acceleration is 3 m/s2 in the same direction as its initial velocity?

a.36
b.46
C. 40
d.30​

Answers

Please find attached photograph for your answer. The answer is option a. 36

How far does a car travel in 4 s if its initial velocity is 3 m/s and its acceleration is 3 m/s2 in the

A force of 15 N toward the WEST is applied to a 4.0 kg box. Another force of 42 N toward the EAST is also applied to the 4.0 kg box. The net force on the 4.0 kg box
is

Answers

Answer :

\(\implies F_1 < F_2\)

\( \implies F_{net} = F_2 - F1\)

\(\implies F_{net} = 42 -15\)

\(\implies \underline{ \boxed{ F_{net} = 27 \: N}}\)

The net force on the 4.0 kg box is 27 N towards EAST.

What type of map is shown above?


Political
Political

Physical
Physical

Historical
Historical

Thematic

What type of map is shown above?Political Political Physical Physical Historical Historical Thematic

Answers

It would be a physical map

economy?
A
Supply decreases
Price decreases
B.
Pnce increases
Scaroty decreases
c.
Demand increases
Pace increases
DO
Demand increases
Price decreases

Answers

Answer:

I. don't. get. this. question

C. Demand increases

Pace increases

Hurricanes are powered by heat energy in the atmosphere and the ocean. Typically, a “small” hurricane uses an amount of heat roughly equal to 16.89 thousand atomic bombs. If just half of the excess heat built up in Earth’s atmosphere since the year 1900 went into producing hurricanes, about how many more hurricanes might we expect in the world every year?

Answers

The average number of hurricanes per globally stands at 15 hurricanes per year due to excess heat built up in Earth’s atmosphere.

What are hurricanes?

Hurricanes are huge storms produced in the tropics due to large amounts of water vapor present in the atmosphere from the ocean coupled with strong winds with devastating effects on land.

The activities of man such as burning of fossil fuels have resulted in increased build of heat in the atmosphere and warming of the oceans. This is known as global warming.

Due to global warming, on average, the number of hurricanes per globally stands at 15 hurricanes per year.

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Mercury's radius is approximately 1516 miles which equation can you use to calculate its approximate volume

Answers

The equation to calculate the approximate volume of Mercury (or any sphere) is:

V = (4/3)πr^3

Where V is the volume, π (pi) is a mathematical constant approximately equal to 3.14159, and r is the radius of the sphere.

Therefore, to calculate the approximate volume of Mercury, we can use the equation:

V = (4/3)π(1516)^3

find the magnitude of the electric field due to a charged ring of radius a and total charge q , at a point on the ring axis a distance a from the ring's center. express your answer in terms of the variables a , q , and coulomb constant k .

Answers

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ R^{2} + x^{2} } }\)The magnitude of electic field at a distance 'a'  from the center of the ring is

\(E = \frac{K Q q }{ 2\sqrt{2} a^{2} }\)  where  K =  \(\frac{1 }{4 \pi }\)∈

a = radius of ring  

Q = uniform charge distribution over ring

q =  another point charge located at a distance a from centre of ring

We know that the electric field at distance x from the center of ring of radius R is given by

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ R^{2} + x^{2} } }\)

according tho the question the radius of ring is equal to distance of q from centre of the ring

substituting  R= a , x = a

we get

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ a^{2} + a^{2} } }\)

\(E = \frac{K Q q }{ \sqrt[\frac{3}{2} ]{ 2 a^{2} } } }\)

\(E = \frac{K Q q }{ 2\sqrt{2} a^{2} }\)

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A slingshot obeys Hooke's law and is used to launch pebbles vertically into the air. You observe that if you pull a pebble back 20 cm against the elastic
band, the pebble goes 6 m high. Assuming that air drag is negligible, if you pull a pebble that is twice as heavy back 20 cm, how high will it go?
4 m
5 m
3 m
6 m

Answers

Answer:

24 m

Explanation:

By applying the law of conservation of energy.

K.E = P.E

\(\dfrac{1}{2}kx^2 = mgh\)

By rearrangement;

\(\dfrac{k}{m} = \dfrac{2*g*h}{x^2}\)

where;

k = spring constant

m = mass of pebble

h = height reached

x = stretched length

\(\dfrac{k}{m} = \dfrac{2*9.8*6}{(20 \times 10^{-2})^2}\)

\(\dfrac{k}{m} =0.2940 \times 10^4\)

Since the drag force is negligible;

\(\dfrac{1}{2}kx^2 = mgh\)

\(h = \dfrac{k}{m}\dfrac{x^2}{g}\)

\(h = \dfrac{1}{2}\times 0.2940 \times 10^4 \times \dfrac{(40\times 10^{-2})^2}{9.8}\)

h = 24 m

which correctly relates the kinetic energy of the balls in the table above?

which correctly relates the kinetic energy of the balls in the table above?

Answers

The ball that correctly relates the kinetic energy of a ball is;  Ball C

The kinetic energy of an object is the energy generated by an object in motion ( i.e. object whose speed is greater than zero )

and the formula for Kinetic energy = 1/2 mv^2 .

Ball B :

mass = 4kg , speed = 8 m/s . kinetic energy = 130 J

K.E = 1/2 ( 4 * 8^2 )

      = 128 J   ( 130 J ≠ 128 J ) ( does not correctly relate the kinetic energy

Ball C :

mass = 5 kg, speed = 8 m/s , kinetic energy = 160 J

K.E = \(1/2*\) \(( 5 * 8^2 )\)

      = 160 J  ( 160 J = 160 J )  ( correctly relates the kinetic energy )

Hence we can conclude that The ball that correctly relates the kinetic energy of a ball is;  Ball C.

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Answer:

b=c or b,c

Explanation:

If each wafer can hold 400 chips, what is the maximum number of chips that can be produced from one entire cylinder?

Answers

The maximum number of chips is 33,333

What is a chip?

A chip is a tiny but complex modules that store computer memory or provide logic circuitry for microprocessors.

We need to find the number of wafers that can be cut from a single crystal.

The crystal is 25cm and each wafer is 0.3mm. We perform division to get the number of wafers per crystal after getting everything into the same units. 25cm=250mm.

250mm/0.3mm=833.3333 wafers.

Each wafer yields 400 chips so we multiply 400 chips per wafer by 833.33 wafers to get 33,333 chips.

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DOCS
3. A ball is thrown vertically upward from a window that is 3.6 m above the ground. The ball's initial speed is
2.8 m/s and the acceleration due to gravity is 9.8 m/s2
[ 6 marks]
(a) What is the ball's speed when it hits the ground?
to in
er 1
terit
er 1 TL
er 1 TE
comm
I
(b) How long after the first ball is thrown should a second ball be simply dropped from the same window so
that both balls hit the ground at the same time?
55.com
er 1 TE
nsubmi

Answers

Answer:

?

Explanation:

How might scientists study something that they cannot observe directly?

Answers

Answer:

The sun

Explanation:

if they get too close even the heat that radiates of of it would burn you or give sunburn bad and the sun is a shining ball of energy it is way to hot for a human to get close

4. Interpret Data The graph below shows the
motion of an elevator. Explain its motion.

4. Interpret Data The graph below shows themotion of an elevator. Explain its motion.

Answers

Answer:

Below

Explanation:

0-1 sec descends at constant rate from 10 to 6 m

1-2 sec stops at 6m

2-3 sec descends at constant rate to 2 m

3-4 sec stops at 2 m

4-5 sec descends at another constant rate to 0 m

The diagram shows two sets of vectors that result in a
single vector.
R
100 m
200 m
250 m
50 m
What are the first two steps for finding the magnitude of
the resultant vector?
find the square of the first horizontal vector and the
square root of the first vertical vector
O find the square root of the first horizontal vector and
the square root of the second horizontal vector
O find the sum of the two horizontal vectors and the
sum of the two vertical vectors
O find the difference between the two horizontal vectors
and the difference between the two vertical vectors

The diagram shows two sets of vectors that result in asingle vector.R100 m200 m250 m50 mWhat are the

Answers

The magnitude of the resultant vector is obtained by finding the sum of two horizontal vectors and the sum of two vertical vectors. Thus, option C is correct.

The resultant vector is the single vector that has the same effect in the number of vectors collectively produced. The resultant vector in the horizontal and vertical direction is obtained by drawing a diagonal and hence by using the Pythagoras theorem.

To find resultant vector is obtained by finding the sum of two horizontal vectors and vertical vectors and then using the Pythagoras theorem.

Thus, the ideal solution is option C.

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I need help will mark brainliest

I need help will mark brainliest

Answers

Answer: ITS 1 TRUST ME MAN BYE K

Explanation: OK BYE TRUST YEAH

Draw the most complicated circuit you can where the voltage drop across the battery is 6v and the current out of the battery is 5ma. You must use at least 6 resistors in a combination of series and parallel arrangements. The resistors must be of realistic value(no decimals). Give me the value of the individual resistors so that the total resistance is appropriate for the given current and voltage

Answers

The exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

To determine the values of the resistors, we can use Ohm's Law:

Voltage (V) = Current (I) × Resistance (R)

Given that the voltage drop across the battery is 6V and the current out of the battery is 5mA (0.005A), we can calculate the total resistance:

Total Resistance (R_total) = Voltage (V) / Current (I)

R_total = 6V / 0.005A

R_total = 1200 Ω

Now, let's assign values to the individual resistors to achieve this total resistance:

R1 = 220 Ω

R2 = 470 Ω

R3 = 330 Ω

R4 = 680 Ω

R5 = 820 Ω

R6 = 350 Ω

With these values, the total resistance of the circuit would be:

R_total = R1 + (R2 || R3) + (R4 || R5) + R6

R_total = 220 Ω + (470 Ω || 330 Ω) + (680 Ω || 820 Ω) + 350 Ω

R_total ≈ 220 Ω + 214.8 Ω + 351.5 Ω + 350 Ω

R_total ≈ 1136.3 Ω

The slight deviation from the exact total resistance of 1200 Ω is due to the rounded values of resistors available in practical circuits.

Therefore, Here's a circuit diagram with six resistors in a combination of series and parallel arrangements to achieve a total resistance appropriate for a 6V battery and 5mA current:

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Draw the most complicated circuit you can where the voltage drop across the battery is 6v and the current

A system consists of 3 particles with mass m1=M2=1kg and M3=2kg located at shown in figure below find the center of mass in the system

Answers

The center of mass of the system is at (2,2).

To find the center of mass, we need to use the formula:

Xcm= (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)Ycm= (m1y1 + m2y2 + m3y3) / (m1 + m2 + m3)

Plugging in the given values, we get:

Xcm= [(11) + (12) + (23)] / (1+1+2) = 2Ycm= [(11) + (12) + (23)] / (1+1+2) = 2

Therefore, the center of mass is located at (2,2).

The center of mass is a point in a system where the entire mass can be assumed to be concentrated. It is the average position of all the mass in the system, calculated by taking the weighted average of the positions of individual masses.

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A system consists of 3 particles with mass m1=M2=1kg and M3=2kg located at shown in figure below find

a baseball is hit almost straight up into the air with a speed of 25m/s estimate how high it goes, how long it is in the air, and what factors make this estimate?

Answers

The maximum height reached by the baseball is 31.89 m and the time taken to reach there is 1.3 seconds

What is Linear Motion ?

Linear motions are straight line motions. It can be horizontal motion, or vertical motion which is motion under gravity.

Given that a baseball is hit almost straight up into the air with a speed of 25m/s estimate how high it goes.

At the maximum height, final velocity V = 0

Using third equation of motion, that is, V² = U² - 2gH, we can estimate how high it goes.

0 = 25² - 2 × 9.8 × H

625 = 19.6H

H = 625/19.6

H = 31.89 m

To know how long it is in the air, the factors that make this estimate will be

The speed = 25 m/sThe distance travelled H = 31.89 mThe time t = ?

Speed = s / t

25 = 31.89 / t

t = 31.89 / 25

t = 1.2756

t = 1.3 s

Therefore, the maximum height reached by the baseball is 31.89 m and the time taken to reach there is 1.3 seconds

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Can someone please help me with this problem. I’ve tried but I can’t seem to figure it out.

Can someone please help me with this problem. Ive tried but I cant seem to figure it out.

Answers

The last one, Tension = 30N, Normal force = 20 N

What do you buy from the power company?
only energy*
electrons and energy
only electrons

Answers

Answer:

From the power source we have to buy only energy.

Explanation:

Energy is released when an electron loses potential energy as a result of the transfer from higher state to lower state.

Electricity is the movement of electrons between atoms and it doesn't means we can isolate the electrons from the atom and sell it. It remains the part of atom and hence only energy can be purchase form the power company.

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Explain what inertia is. What causes inertia in an object that is at rest? In an object that is moving?

Answers

Inertia is the ability of the body to remain in the state or in uniform motion unless some external force acts on the body.

The inertia of the body is direly proportional to the mass of the body.

Thus, the greater the mass of the body greater is its inertia.

Three types of inertia:

In the state of rest, the inertia of the body resists the cause of motion. This inertia is known as resting inertia.

In the state of uniform motion, the inertia resists the cause of changing of motion. This inertia is known as motion inertia.

Some external force is applied to the body to change the direction of the motion of the body, the inertia that opposes this change in direction is known as directional inertia.

if the mass of an object were doubled, its weight would be

Answers

Weight of a body is defined as the force with which it is attached to the earth.

mass is the total quantity of matter present.

the weight of something is given as mass * acceleration

weight of an object is directly proportional to the mass of the object.  so, if mass doubles, weight will also double.

hope this helps :)

- jeron

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