Exposure to ultraviolet light darkens skin by stimulating synthesis of:.

Question:

What do you think will happen to the people in the airplane if their location is unknown?

My opinion:

I mean what are the circumstances? Is it just a rogue pilot that takes a random plane with all the passengers Hostage or is It bad whether an they lose connection to the airport? I Mean either way, If I was on a plane being held hostage, or the plane crashing, I Would be a in a panic type state of mind. I Would be worried about what will happen when the plane crashes, I would worry about my friends or family that is aboard the plane with me, I Would be scared for my life because I Don't know if i would make it out alive.

Also:

How would they know their location is unknown wouldn't the Pilot be the only one to know exactly where there with their navigating system, But then again there was this time I headed to Florida an They had mini tv's on the seats of each chair, where you could: Watch movies, listen to music, an Also see exactly where you are in the world. It was really amazing actually.

Answer:

1. chemical energy --> electrical energy --> light energy

2. Electrical Energy --> Mechanical Energy

3. Electrical Energy --> Heat Energy

4. Chemical Energy --> Thermal Energy  --> Mechanical Energy

5. Nuclear Energy --> Light energy and thermal energy

6. Mechanical Energy --> Electric Energy

7. Chemical Energy --> Electrical Energy --> Sound Energy

8. Mechanical Energy --> Sound Energy

Explanation:

Answer:

gravity

Explanation:

this is the answer because gravity is the force that pulls things down because gravity is what is trying to pull things down to the center core of the earth

Answer:

the force of gravity

Explanation:

edge 2021

Explanation:

there are 8 groups of the periodic table

group number one is of the alkali metals

group number two use of the alkaline Earth metals

group number three is known as group (III)

group number for is known as group IV

group number V is known as group V group number six is known as group VI

group number seven is known as halogens

and group number eight is of the noble gases

the periodic table does not have 18 groups as the elements between group III and group IV all known as the transition metals.

The final velocity of both the balls after collision is 2.17m/s and direction of movement is 45°.

mass of the the first clay ball = 28gm =0.028 kg

initial velocity of the first clay ball = u1 =3.4m/s

mass of the the second clay ball = 34gm =0.034g

initial velocity of the second clay ball = u2= 2.8m/s

Now, Initial momentum of the first ball: p1 = m1 × u1

p1 = (0.028)(3.4)

p1 = 0.0952 kg-m/s

Initial momentum of the second ball: p2 = m2 × u2

p2 =(0.034)(2.8)

p2 = 0.0952 kg-m/s

Resultant of initial momentum of both the balls:

Pi = √(Pxi² + Pyi²)

Pi = √{(0.0952)² + (0.0952)²}

Pi = 0.1346 kg-m/s

Finding final velocity by applying conservation of momentum-

Pi = Pf

mv = 0.1346

v = 0.1346 / 0.062

v = 2.17 m/s

Finding direction of the two balls's velocity-

tanθ = Pyi/Pxi

tanθ = 0.0952/0.0952

tanθ = 1

θ = 45°

Therefore, the final velocity of both the balls after collision is 2.17m/s and direction of movement is 45°.

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Answer:

They get air inside

Explanation:

bananas turn brown when air is inside

The force required to tip the cube is equal to the coefficient of static friction times the weight of the cube.

fx=μs * 87 kg * 9.8 m/s^2

Generally, The cube will start to tip when the net torque about the point of contact between the cube and the floor is equal to zero. The torque is given by:

torque = force x distance from axis of rotation

The distance from the axis of rotation is half the edge length of the cube (0.475m), and the force is the force applied by the person (). Therefore, the torque is:

torque = fx x 0.475

For the cube to tip, the torque due to the person's force must be greater than the maximum torque the friction can provide, which is the friction force times the distance from the axis of rotation.

The maximum torque provided by friction is:

friction torque = friction force x 0.475

Since the friction force is equal to the normal force (mg) multiplied by the coefficient of static friction (μs), the maximum torque provided by friction is:

friction torque = μs * mg * 0.475

where m is the mass of the cube, g is the acceleration due to gravity and μs is the coefficient of static friction between the cube and the floor.

So, we can find the force needed to tip the cube by equating the torque due to the force with that of the friction torque.

Fx*0.475 = μs * m * g * 0.475

Fx= μs * m * g

Fx= μs * 87 kg * 9.8 m/s^2

Note: The coefficient of static friction (μs) is a dimensionless quantity between 0 and 1, it varies depending on the surfaces in contact.

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9.27 a series rlc bandpass filter has half-power frequencies at 1 kHz and 10 kHz. if the input impedance at resonance is 6 , Then

the values of R, L, and C are:

R = 0 Ω

L = 22.17 mH

C = 4.057 µF

Half-power frequencies f1 = 1 kHz, f2 = 10 kHz

Input impedance at resonance Z = 6 Ω

We know that the half-power frequencies of a series RLC bandpass filter are given by the following formula:

f1,2 = (1/2π) × √(1/(LC) - R²/(4L²))

At resonance, the impedance is purely resistive, and is given by:

Z = R

Substituting the given values into the above equations, we can solve for the unknowns:

f1 = 1 kHz, f2 = 10 kHz

Z = 6 Ω

f1,2 = (1/2π) × √(1/(LC) - R²/(4L²))

f1 = (1/2π)× √(1/(LC) - R²/(4L²))

f2 = (1/2π) × √(1/(LC) - R²/(4L²))

Z = R

Substituting the values of f1 and f2, we get:

1 kHz = (1/2π) × √(1/(LC) - R²/(4L²))

10 kHz = (1/2π)× √(1/(LC) - R²/(4L²))

Dividing the second equation by the first equation, we get:

10/1 = √[(1/(LC) - R²/(4L²)) / (1/(LC) - R²/(4L²))]

10/1 = 1

This means that R²/(4L²) = 0, and thus R = 0.

Substituting R = 0 into the first equation, we get:

1 kHz = (1/2π) × √(1/(LC))

Squaring both sides, we get:

(1 kHz)² = 1/(4π²LC)

LC = 1/(4π²(1 kHz)²)

LC = 4.057 µF

Substituting this value of LC into the equation for f1 or f2, we get:

1 kHz = (1/2π) ×√(1/(4.057 µF× L))

Squaring both sides and solving for L, we get:

L = 22.17 mH

Therefore, the values of R, L, and C are:

R = 0 Ω

L = 22.17 mH

C = 4.057 µF

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No atomic  model is a picture of an atom but only helps explain the behavior of one

We know that the atom is the smallest particle of a substance that is able to take part in a chemical reaction. We know that in the atom there are certain smaller particles that we can be able to refer to as the subatomic particles.

In this case, we are talking about the different models that we can be able to use to show the atom. None of these models can be said to show the atom exactly but can approximate how the atom behaves.

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Answer:

physics answers everything to understand biology you need to understand chemistry which is connected to physics which is connected to mechanics like fluid mechanics or quantum mechanics which is connected to math and all of that is science not particularly physics but physics can answer all of the questions you asked and more.

Explanation:

Answer:

sorry im only in fifth grade

Explanation:

Note: If the question asked for work done by the car, then it will be equal to the kinetic energy of the body.

Answer:

65x2=130

that's what she does

If the woman in the first photo lifts a plant 2 meters with a force of 65 Newtons, then the total work done by the woman would be 130 Newton meters.

The total amount of energy transferred when a force is applied to move an object through some distance.

The work done is the multiplication of applied force with displacement.

As given in the problem we have to find out the work done if a woman in the first photo lifts a plant 2 meters with a force of 65 Newtons,

The work done by the woman = force × displacement of the plant

                                                   =65 ×2

                                                   =130 Newton meter

Thus, the total work done by the woman would be 130 Newton meters.

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Answer:

SD

Explanation:

Answer:

the answer for the question is the last option

The summary of the interview with Steve Okamoto a roller coaster designer highlighted how he developed a fascination for rollercoasters and how he successfully learned how to build them.

The summary of the interview with Steve Okamoto is given below.

In an interview with Steve Okamoto, a roller coaster designer, he explained that his fascination with roller coasters began at a young age, and his interest in finding out how they worked led him to study mechanical engineering and product design. As a roller coaster designer, Okamoto's work involves studying site maps, designing how the parts of the ride will work together, and fitting coasters around existing rides and buildings. He also has to consider marketing goals and concerns in his designs, as most parks have some kind of theme. Okamoto recommends that students interested in designing roller coasters should focus on studying math and science, and understanding how energy is converted from one form to another as the cars move along the track.

Overall, Okamoto's work as a roller coaster designer involves a combination of mechanical engineering, product design, and consideration for marketing goals and existing park infrastructure. To design a successful roller coaster, he relies on his knowledge of math, science, geometry, and physics to calculate speeds, accelerations, and the coaster's curves, loops, and dips. His advice for students interested in designing roller coasters is to focus on studying math and science, and understanding how energy is converted throughout the coaster's track.

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Answer:

applications of density measurements. The densities of brass and aluminum will be calculated from mass and volume measurements.

Explanation:

Mechanical ptosis of the left and right eyelids is reported with code(s) H02.413.

Ptosis, also called Blepharoptosis is characterized by the drooping of eyelids due to any abnormality associated with the structures that keep the eyelids elevated.

Ptosis is classified into congenital, aponeurotic, neurogenic, and mechanical ptosis. The illness results in drooping of the upper eyelid due to weight or mass.

It is also caused by many syndromes such as Horner's syndrome and Myasthenia Gravis.

The ICD-10 code is H02.413 which comes under the eye and adnexa category under the WHO. Thus, option A is correct.

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This absorption occurs because the black cloth's molecules absorb the light's energy, transforming it into other forms of energy, such as heat.

As a text-based AI, I am unable to create or insert images directly into my response. However, I can describe the process and provide you with guidelines on how to create the diagram yourself.
i. A material that will absorb light: Black cloth
ii. To create a diagram representing a light wave being absorbed, follow these steps:
1. Draw a light wave with a sinusoidal pattern (alternating peaks and troughs) approaching the black cloth.
2. Draw the black cloth as a rectangular shape.
3. Show the light wave entering the black cloth and fading away within the material, indicating absorption.
iii. Label your diagram "Light Wave Absorbed."
iv. Brief description of the interaction: When the light wave comes into contact with the black cloth, the material absorbs the light's energy, causing the wave to dissipate within the cloth. As a result, the light wave does not pass through or reflect off the material, and it appears black to the human eye. Remember to create the diagram, label it "Light Wave Absorbed," and include the brief description below the image.

The molecules can be organised as follows, with oxygen, water, carbon dioxide, amino acids, glucose, starch, and protein being the smallest at the top. The compounds mentioned, oxygen, protein, amino acids, glucose, carbon dioxide, and starch,The following chemicals' molecular weights are listed 18 g/mol water

blood glucose level: 180.2 g/mol

glucose (2 or more) starch 360 g/mol

44 g/mol of carbon dioxide

Protein 20,000 g/mol

(Glycine) amino acid 75 g/mol

oxygen 16 g/mol

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Answer: Its the last one: The position of the block will change

Explanation: Since the forces are unbalanced, one side of the block will be stronger, therefore making the block move.

Answer:portion of the block will change

Explanation:

Between visible light and microwave is where infrared falls. Infrared has a higher energy than radio but a lower energy than gamma rays.

The term "infrared" refers to electromagnetic waves that exist within the electromagnetic spectrum at frequencies slightly below those of red visible light and just above those of microwaves. According to the California Institute of Technology, the wavelengths of infrared radiation are longer than those of visible light (Caltech).

The majority of the radio portion of the electromagnetic spectrum (EM spectrum) is found between 1 cm and 1 km, or 30 GHz and 300 kHz in frequency. The EM spectrum's radio region is relatively vast. Astronomers usually employ wavelength in the infrared and optical spectrum.

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The  quantum of work done to move a 1 kg mass from the  face of the earth to a point 10 ⁵ km from the centre of the earth is4.92 x 10 ⁸J.    

The  quantum of work done to move 1 kg mass from the  face of the earth to a point 10 ⁵ km from the centre of the earth can be calculated using the gravitational implicit energy formula.

The gravitational implicit energy is the  quantum of work done by an external force in bringing an object from  perpetuity to a point in space where it can be  told  by  graveness. When an object is moved from the  face of the earth to a point 10 ⁵ km from the centre of the earth, the gravitational implicit energy of the object increases.  

The formula for gravitational implicit energy is given by  U = - GMm/ r  where U is the gravitational implicit energy  G is the universal gravitational constant  M is the mass of the earth  m is the mass of the object  r is the distance between the object and the centre of the earth.  

We know that the mass of the object is 1 kg,  the mass of the earth is    and the distance from the centre of the earth to a point 10 ⁵ km down is           Plugging these values into the formula, we get         thus, the  quantum of work done to move a 1 kg mass from the  face of the earth to a point 10 ⁵ km from the centre of the earth is 4.92 x 10 ⁸J.

the mass of the earth is \(5.97 * 10^2^4 kg\),

and the distance from the centre of the earth to a point 10⁵ km away is:

\(= 6.38 * 10^6 + 10^5 km\)

\(= 6.48 * 10^6 km\)

\(= 6.48 * 10^9 m\).

Plugging these values into the formula, we get

\(U = -6.67 * 10^-^1^1 * 5.97 * 10^2^4 * 1 / 6.48 * 10^9\)

   \(= -4.92 * 10^8 J\)

Therefore, the amount of work done to move a 1 kg mass from the surface of the earth to a point 10⁵ km from the centre of the earth is 4.92 x 10⁸ J.

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The pattern produced by monochromatic light passing through two parallel slits in a screen and falling on a piece of film is an example of interference pattern. This pattern is a result of the superposition of two waves of the same wavelength and amplitude that originate from the two slits.

As the waves pass through the slits, they diffract and spread out, forming circular waves. These circular waves then overlap and interfere with each other, resulting in areas of constructive interference where the waves reinforce each other and areas of destructive interference where the waves cancel each other out. This interference pattern is a characteristic feature of waves, and it is commonly observed in various fields such as optics, acoustics, and quantum mechanics.

This phenomenon is a result of the wave nature of light and is specifically called Young's double-slit experiment. The interference pattern consists of alternating bright and dark bands, which are called fringes, formed due to constructive and destructive interference of light waves from the two slits.

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The conservation of angular momentum is the reason that (nearly) all of them rotate in the same direction.

The nebular hypothesis is regarded as the most widely accepted theory of planetary creation. According to this theory, a massive molecular cloud several light-years across gravitationally collapsed to create the Solar System 4.6 billion years ago.

The nebular hypothesis states that our solar system arose at the same period as our Sun. The nebular hypothesis proposes that a spinning cloud of dust called a nebula, composed primarily of light elements, flattened into a protoplanetary disk and developed into a solar system made up of a star with orbiting planets .

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Answer:

True

Explanation:

Im healthy and have a slightly higher BMI

Answer:

8.0 I mean for 10,  10 is wrong

Explanation:

Multiplying the force on the object by the time over which the force acts, multiplying the mass of the object by the velocity change of the object

Answer:

\(10\; {\rm kg \cdot m\cdot s^{-1}}\).

(Assume that there are no other unbalanced force on this object.)

Explanation:

When an object of mass \(m\) travels at a velocity of \(v\), the momentum \(p\) of that object would be \(p = m\, v\).

In this question, the \(m = 6.0\; {\rm kg}\) object was initially at a velocity of \(v = 3.0\; {\rm m\cdot s^{-1}}\). The initial momentum of this object would be:

\(\begin{aligned} p &= m\, v \\ &= (6.0\; {\rm kg})\, (3.0\; {\rm m\cdot s^{-1}}) = 18\; {\rm kg\cdot m\cdot s^{-1}}\end{aligned}\)

The question states that the external force is "resistive". In other words, this force opposes the motion of this object. Hence, while the magnitude of this force is \(40\; {\rm N}\), the vector value of this force would be \((-40)\; {\rm N}\).

To find the impulse \(P\) that a force \(F\) has exerted, multiply the force vector by the duration \(\Delta t\) over which this force was applied.

For example, the \((-40)\; {\rm N}\) force in this question was applied over a period of \(\Delta t = 0.20\; {\rm s}\). This force would have exerted an impulse \(J\) of:

\(\begin{aligned}J &= F\, \Delta t \\ &= (-40\; {\rm N})\, (0.20\; {\rm s}) = (-8.0)\; {\rm N\cdot s}\end{aligned}\).

Note that \(1\; {\rm N}\) is equivalent to \(1\; {\rm kg\cdot m\cdot s^{-2}}\). Therefore, the unit of impulse \({\rm N\cdot s}\) would be equivalent to \({\rm (kg\cdot m\cdot s^{-2})\cdot s}\), which simplifies to \({\rm (kg\cdot m\cdot s^{-1})}\).

Thus, the impulse on this object \((-8.0)\; {\rm N\cdot s}\) would be equivalent to \((-8.0)\; {\rm kg\cdot m\cdot s^{-1}}\).

The total impulse on an object is also equal to the change in the momentum of the object. Assuming that there are no other unbalanced force on this object, the total impulse on this object would be \((-8.0)\; {\rm kg\cdot m\cdot s^{-1}}\). The momentum of this object would become:

\(\begin{aligned}& 18.0\; {\rm kg \cdot m\cdot s^{-1} + (-8.0)\; {\rm kg\cdot m\cdot s^{-1}} \\ =\; & 10\; {\rm kg\cdot m\cdot s^{-1}} \end{aligned}\).

The linear acceleration of the bucket as it falls is \(13.5 m/s^2\)

To find the linear acceleration of the bucket as it falls, we need to use the free-body diagram and the equations of motion.

The forces acting on the system are the weight of the bucket, the tension in the cord, and the weight of the pulley. Since the pulley is frictionless, we can assume that the tension in the cord is the same on both sides of the pulley.

The weight of the bucket can be calculated as:

F_b = m_b * g

where m_b is the mass of the bucket and g is the acceleration due to gravity.

The weight of the pulley can be calculated as:

F_p = m_p * g

where m_p is the mass of the pulley.

The tension in the cord can be calculated from the torque equation:

τ = F * r

where τ is the torque, F is the tension in the cord, and r is the radius of the pulley.

The torque on the pulley can be calculated as:

τ = I * α

where I is the moment of inertia of the pulley and α is the angular acceleration of the pulley.

Since the pulley is rolling without slipping, the linear acceleration of the pulley is related to its angular acceleration as:

a = r * α

where a is the linear acceleration of the pulley.

To find the linear acceleration of the bucket, we can use the equations of motion for the system:

F_t - F_b - F_p = m_total * a

where F_t is the tension in the cord, F_b is the weight of the bucket, F_p is the weight of the pulley, m_total is the total mass of the system, and a is the linear acceleration of the bucket.

Substituting the torque equation and the linear acceleration of the pulley, we get:

F_t - F_b - F_p = m_total * (F_t / (m_b + m_p + I/r²))

Substituting the given values, we get:

F_t - 15 N - 39.2 N = (1.5 kg + 4.0 kg + (1/2)(4.0 kg)(0.33 m)²/(0.33 m)²) * (F_t / (1.5 kg + 4.0 kg + (1/2)(4.0 kg)(0.33 m)²/(0.33 m)²))

Simplifying, we get:

F_t - 54.2 N = (5.0 kg) * (F_t / 6.5 kg)

Solving for F_t, we get:

F_t = 35.2 N

The linear acceleration of the bucket can now be calculated from the equation:

F_t - F_b = m_b * a

Substituting the given values, we get:

35.2 N - 15 N = 1.5 kg * a

Solving for a, we get:

a = 13.5 \(m/s^2\)

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Answer:

Nanomagnetic chips.

Explanation:

In a computer, the hard disk drive chips are magnetic.

A non-volatile data storage device is a computer hard disk drive (HDD). Non-volatile storage devices are those that retain data even after being turned off. HDDs are merely one form of storage device, yet they are required by all computers.

Desktop computers, mobile phones, consumer gadgets, and enterprise storage arrays in data centers are frequently equipped with HDDs. They can use magnetic disks to store operating systems, applications, and other things.

Hence, Hard disk drive is belongs to one of those chips which at magnetic in nature.

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While there is no direct relationship between speed and thinking distance, higher speeds can result in longer thinking distances due to the increased reaction time needed by the driver.

The relationship between speed and thinking distance is not a direct one, as thinking distance is primarily influenced by the driver's reaction time rather than the actual speed of the vehicle. Thinking distance refers to the distance traveled by a vehicle during the driver's reaction time after perceiving a hazard.

However, there is an indirect relationship between speed and thinking distance in the sense that higher speeds generally result in longer thinking distances. When a vehicle is traveling at a higher speed, the driver needs more time to process information, make decisions, and react to potential hazards. Therefore, a higher speed can lead to a longer thinking distance.

It is important to note that thinking distance is just one component of the total stopping distance, which also includes braking distance. Braking distance is directly influenced by the speed of the vehicle. Higher speeds require longer braking distances to bring the vehicle to a stop.

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The elastic potential energy stored in the compressed spring is determined as 11.6 J.

The elastic potential energy of the spring is the energy stored in the spring and the magnitude is calculated as follows;

U = ( ¹/₂kx² )

where;

The given parameters include the following;

the spring constant, k = 580 N/m

the extension of the spring, x = 0.2 m

Substitute the given parameters and solve for the elastic potential energy stored in the spring based on the compression produced by the two blocks.

U = ( ¹/₂kx² )

U = ( ¹/₂ ( 580 N/m ) ( 0.2 m )² )

U = 11.6 J

Thus, the elastic potential energy stored in the compressed spring is a function of the spring constant and extension of the spring.

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