find the ph of a buffer that consists of 0.60 m hcooh and 0.44 m hcoona. (pka of hcooh = 3.74)

25 ml of the round bottom flask is better

M.W. of cyclohexanol is 100.158 g/mol

density = 0.962 g/cm3

5.2 ml of cyclohexanol = 5.2×0.962/100.158 = 0.05 mole

0.05 mole × 100.158 = 5.008 g

in solvent-free reaction 25 ml is easy to distill

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double-replacement reaction

The equation for the hydrolysis of glyceryl triethanoate is C3H5(OH)3 + 3CH3COOH = C3H3(OCOCH3)3 + HOCH2CH(OH)CH2OH

Hydrolysis is a chemical reaction which water molecule break down one or more chemical bonds. This is use for substitution, elimination, and solubility.

Hydrolysis depend on the pH, solubility and chemical constituent of the substance.

Therefore, The equation for the hydrolysis of glyceryl triethanoate is C3H5(OH)3 + 3CH3COOH = C3H3(OCOCH3)3 + HOCH2CH(OH)CH2OH

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Answer:

ta da

Explanation:

The balanced molecular reaction for the reaction between HNO₂ and Ca(OH)₂ is:

2HNO₂(aq) + Ca(OH)₂(aq) -> 2H₂O(l) + Ca(NO₂)₂(aq)

The balanced molecular reaction for the combination of a weak acid with a strong base involves the neutralization reaction between the acid and the base. In this case, the weak acid is nitrous acid (HNO₂) and the strong base is calcium hydroxide (Ca(OH)₂).

When the two compounds are mixed together, the hydroxide ions (OH⁻) from the base react with the hydrogen ions (H+) from the acid to form water. However, since nitrous acid is a weak acid, it only partially dissociates in water to form hydrogen ions and nitrite ions (NO₂⁻). Therefore, the reaction requires the use of two molecules of HNO₂ to react with one molecule of Ca(OH)₂.

Thus balanced equation for the reaction is:

2HNO₂(aq) + Ca(OH)₂(aq) -> 2H₂O(l) + Ca(NO₂)₂(aq)

This means that two molecules of HNO₂ react with one molecule of Ca(OH)₂ to produce two molecules of water and one molecule of calcium nitrite (Ca(NO₂)₂). The balanced equation shows that the number of atoms of each element is the same on both sides of the equation, which means that the reaction is balanced and follows the law of conservation of mass.

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Answer: 8 electrons

Explanation:

Answer: 8 valence electrons

Explanation: This is because the maximum electron an energy level can hold is 8 making it a stable atom

Answer:

I'm sorry but there is not enough context to answer your question.

Explanation:

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

Answer:

see explanation

Explanation:

Given:  MgF₂  +  Li₂CO₃  =>  MgCO₃ + 2LiF

simple balance ... just add coefficient of '2' before LiF

Answer:

There is nothing we can do to reduce the amount of trash we throw away.

Explanation:

We can reuse and recycle the trash that we throw away, so we can do something to reduce the amount of trash that we throw

The most nearly mass of combustion products produced is 41 g (Option C).To determine the mass of combustion products, we need to calculate the moles of propane and oxygen consumed in the reaction and then use the stoichiometry to determine the moles and mass of the combustion products.

Propane (C3H8) has a molecular weight of 44 g/mol. The balanced chemical equation for the combustion of propane is:

C3H8 + 5O2 → 3CO2 + 4H2O

From the equation, we can see that for every mole of propane, 5 moles of oxygen are consumed.

Given that we have 11 grams of propane, we can calculate the moles of propane:

Moles of propane = Mass of propane / Molecular weight of propane

Moles of propane = 11 g / 44 g/mol = 0.25 mol

Since the stoichiometric ratio between propane and oxygen is 1:5, the moles of oxygen consumed will be:

Moles of oxygen = Moles of propane * 5 = 0.25 mol * 5 = 1.25 mol

Next, we can determine the moles and mass of the combustion products. From the balanced equation, we see that for every mole of propane, we get 3 moles of carbon dioxide (CO2) and 4 moles of water (H2O).

Moles of CO2 = Moles of propane * 3 = 0.25 mol * 3 = 0.75 mol

Moles of H2O = Moles of propane * 4 = 0.25 mol * 4 = 1.00 mol

To calculate the mass of the combustion products, we need to multiply the moles of each product by their respective molecular weights:

Mass of CO2 = Moles of CO2 * Molecular weight of CO2 = 0.75 mol * 44 g/mol = 33 g

Mass of H2O = Moles of H2O * Molecular weight of H2O = 1.00 mol * 18 g/mol = 18 g

Finally, we can add up the masses of CO2 and H2O:

Mass of combustion products = Mass of CO2 + Mass of H2O = 33 g + 18 g = 51 g

Therefore, the mass of combustion products produced is closest to 51 g, which corresponds to option (D).

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A balanced chemical equation always obeys law of conservation of mass.

A  balanced chemical equation generally obeys to law of conservation of mass. As per this regulation the mass of items should be equivalent to the mass of reactants. A response is supposed to be adjusted when the complete mass of particles on the two sides of the substance response is equal.According to the law of conservation of mass, the mass of the items in a synthetic response should rise to the mass of the reactants.

The law of conservation of mass is helpful for various computations and can be utilized to tackle for obscure masses, such how much gas consumed or delivered during a reaction.They should submit to the Law of conservation of Mass that expresses that matter can't be made or obliterated, it is saved. The mass of the reactants should rise to the mass of the products.Thus, the mass of substances created in a synthetic response is consistently equivalent to the mass of responding substances. Consequently, you really want to have a similar number of each kind of component on each side of a synthetic condition. This is the entire reason for adjusting a synthetic condition.

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The vapor pressure of carbon disulfide at 35 °C is approximately 528.37 mmHg.

To calculate the vapor pressure of carbon disulfide (CS2) at 35 degrees Celsius, we can use the Clausius-Clapeyron equation:

ln(P2/P1) = (ΔHvap/R) * (1/T1 - 1/T2)

where:

P1 is the vapor pressure at temperature T1,

P2 is the vapor pressure at temperature T2,

ΔHvap is the heat of vaporization,

R is the ideal gas constant (8.314 J/(mol·K)),

T1 is the initial temperature,

and T2 is the final temperature.

T1 = 46 °C + 273.15 = 319.15 K (normal boiling point)

T2 = 35 °C + 273.15 = 308.15 K

ΔHvap = 26.8 kJ/mol = 26,800 J/mol

Converting the temperature and heat of vaporization to Kelvin and Joules, respectively, we can substitute the values into the equation:

ln(P2/P1) = (26,800 J/mol / (8.314 J/(mol·K))) * (1/319.15 K - 1/308.15 K)

Simplifying the equation:

ln(P2/P1) = 3227.9 * (0.003134 - 0.003247)

ln(P2/P1) = 3227.9 * (-0.000113)

ln(P2/P1) = -0.3645

Taking the exponential of both sides:

P2/P1 = e^(-0.3645)

P2/P1 = 0.6948

Solving for P2, the vapor pressure at 35 °C:

P2 = P1 * 0.6948

Substituting the normal boiling point vapor pressure of carbon disulfide (P1 ≈ 760 mmHg or 101.3 kPa):

P2 ≈ 760 mmHg * 0.6948 ≈ 528.37 mmHg

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Answer:

volume = 13097674418.528dm³

Explanation:

n = (3.52)*10^32/(6.02)*10^23)

n = (584717607.97)

n = volume /molar volume

molar volume at stp = 22.4dm³

volume= 584717607.97 x 22.4

volume = 13097674418.528dm³

Answer:

chalk bubbles with vinegar

Answer:

Measure its mass

Measure its volume

Measure its number of moles

Explanation:

The answers include the following:

This is referred to as the largest organ in the body which has a rich network of nerves and blood vessels and is responsible for protecting the body from pathogens and other foreign bodies.

Living organisms such as humans have different skin colors and is based on the amount of the protein known as melanin present in it .The color of the skin of a chicken wing ranges from white to yellow and is attached to the subcutaneous tissue.

This type of tissue is responsible for connecting the skin to the muscles and bones which are present in the body so as to perform functions necessary for the survival of the animal.

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CrO and Cr₂O₃ make up the simplest chromium oxide formula.

What name does Cr₂O₃ use?

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The correct options are:1.

Conditional probability that the selected compound actually has an impurity is 0.74.2.

Conditional probability that the selected compound is actually free of an impurity is 0.0185.3.

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Here, we need to find out the probability that a selected compound has an impurity given that the test indicates an impurity is present.

P(A) = probability that a compound has impurity = 0.15

P(B) = probability that the test indicates an impurity is present

= 0.15 x 0.9 + 0.85 x 0.05

= 0.14 + 0.0425

= 0.1825P

(B|A) = probability that the test indicates an impurity is present given that the compound has impurity = 0.9

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / P(B)

         = 0.9 * 0.15 / 0.1825

         = 0.7370

         ≈ 0.74

Conditional probability that the selected compound actually has an impurity is 0.74.10.

Here, we need to find out the probability that a selected compound is actually free of an impurity given that the test indicates an impurity is not present.

P(A) = probability that a compound has impurity = 0.15

P(B) = probability that the test indicates an impurity is not present = 0.85 x 0.95 + 0.15 x 0.1 = 0.8075

P(B|A) = probability that the test indicates an impurity is not present given that the compound has impurity

          = 0.1

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / P(B)

          = 0.1 * 0.15 / 0.8075

          = 0.0185

Conditional probability that the selected compound is actually free of an impurity is 0.0185.11.

Here, we need to find out the probability that the selected roll is from Process I given that it is defective.

Let A denote the event that a roll is from Process I and B denote the event that a roll is defective.

Then, we need to find out P(A|B).

P(A) = probability that a roll is from Process I = 0.6

P(B|A) = probability that a roll is defective given that it is from Process I = 0.03

P(B|A') = probability that a roll is defective given that it is from Process II = 0.01

P(A'|B) = probability that a roll is from Process II given that it is defective

Therefore, by Bayes' Theorem,

P(A|B) = P(B|A) * P(A) / [P(B|A) * P(A) + P(B|A') * P(A')]

= 0.03 * 0.6 / (0.03 * 0.6 + 0.01 * 0.4)

= 0.6429

≈ 0.64

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

Hence, the correct options are:1.

Conditional probability that the selected compound actually has an impurity is 0.74.2.

Conditional probability that the selected compound is actually free of an impurity is 0.0185.3.

Conditional probability that the selected roll is from Process I given that it is defective is 0.64.

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Answer:

37

Explanation:

( 98.6 - 32 ) × 5(100c) ÷ 9(180f) = 37

Gamma radiation are the most dangerous type of radioactive emission as they are the most energetic and can penetrate the human body and damage cells. Alpha particles can cause both short-term and long-term health effects, such as cancer.

Out of alpha, beta and gamma radiation, the most dangerous type of radioactive emission is gamma radiation. This is because gamma rays are penetrating, high-energy rays that can easily penetrate the human body and cause damage to cells and DNA. Gamma radiation, unlike alpha and beta radiation, can penetrate the body's skin and tissue, exposing internal organs to radiation. When gamma rays are absorbed by living cells, they can ionize atoms and molecules, causing damage to DNA and other genetic material in the cell. High doses of gamma radiation can cause immediate symptoms such as radiation sickness and even death. Gamma radiation is frequently emitted by unstable radioactive atoms like uranium and plutonium, which are used in nuclear power plants and nuclear weapons. Workers in these industries and anyone exposed to a nuclear accident or bomb are at a higher risk of exposure to gamma radiation. Alpha radiation is a type of ionizing radiation that is emitted by certain types of unstable atoms. Alpha particles are relatively large and have a short range, so they can be stopped by a sheet of paper or the outer layer of human skin. Beta radiation is a type of ionizing radiation that is emitted by certain types of unstable atoms. Beta particles are much smaller than alpha particles, and they can travel through the human body farther than alpha particles. Gamma radiation is a type of electromagnetic radiation, similar to X-rays, but with higher energy and frequency. Gamma rays are produced by the decay of unstable atomic nuclei and are highly penetrating, meaning they can easily pass through solid objects.

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The formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

To determine the limiting reagent and the maximum amount of iron(II) oxide that can be produced, we need to compare the moles of each reactant and their stoichiometric ratios in the balanced equation.

The balanced equation for the reaction is:

4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)

From the balanced equation, we can see that the stoichiometric ratio between iron and oxygen is 4:3. This means that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron(II) oxide.

Moles of iron(II) oxide = min (0.270 moles of Fe, (0.579 moles of O₂) × (2 moles of Fe₂O₃ / 3 moles of O₂))

To determine the limiting reagent, we compare the moles of iron and oxygen and choose the reactant that produces the lesser moles of iron(II) oxide. In this case, we have:

Moles of iron(II) oxide produced from 0.270 moles of Fe = 0.270 moles × (2 moles of Fe₂O₃ / 4 moles of Fe) = 0.135 moles

Moles of iron(II) oxide produced from 0.579 moles of O₂ = 0.579 moles × (2 moles of Fe₂O₃ / 3 moles of O₂) = 0.386 moles

Since 0.135 moles of iron(II) oxide is less than 0.386 moles, the limiting reagent is iron.

Therefore, the formula for the limiting reagent is Fe, and the maximum amount of iron(II) oxide that can be produced is 0.135 moles.

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The following solutions has an osmolarity of 4.0 is given as: 2.0 M KBr .

osmolarity = molarity × n ( number of dissociate particles)

a) 0.3 M NaCl

NaCl ----->   Na   + Cl

osmolarity = 0.3 × 2

                  = 0.2 osmol

b) 2.0 M KBr

KBr --->  K  +   Br

osmolarity = 2 × 2

                  = 4 osmol

c) 1.0 M Fe₂O₃

Fe₂O₃   ----->   2Fe³⁺    +    3O²⁻

osmolarity = 1 × 5

                  = 5 osmol

d) 1 M MgCl₂

MgCl₂   ----->   Mg²⁺    +   2Cl⁻

osmolarity = 1 × 3

                  = 3 osmol

e) 1.5  M AlCl₃

AlCl₃    ---->    Al³⁺   +  3Cl⁻

osmolarity = 1.5 × 4

                  = 6

Thus, The following solutions has an osmolarity of 4.0 is as: 2.0 M KBr .

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Answer:

The correct answer is 14 cm³.

Explanation:

Based on Archimedes Principle at rest when a body is completely or partially immersed within a fluid, it encounters a vertical thrust, which is equivalent to the weight of the fluid that the body displaces. In the mentioned case, the fluid is water. Thus, the rock being denser will result in the displacement of water, making the level of water to ascend in the cylinder.  

Thus, if V₁ or the initial volume is 20 ml or 20 cm³, and after insertion of the rock, the rise in the level of water becomes V₂ as 34 ml or 34 cm³. Then the volume of the rock will be,  

V = V₂ -V₁ = 34 - 20 = 14 cm³.  

Answer:

Preparation of Bases

By the direct union of a metal with oxygen Some metals when heated in air or oxygen form the oxides of the metals. ... By the action of water or steam on some active metals Some active metals like sodium and potassium react with cold water to form hydroxides with the evolution of hydrogen gas.