a) G = 1/(s+1) and H = (s-1)/(s+2): The system is stable for all values of K.
b) G(s) x H(s) = (s^2+2s+2)/(s^2(s-1)): The system is unstable for K > 2.
To determine the values of K for which the system is unstable, we need to use the characteristic equation and analyze the closed-loop transfer function.
a) For G = 1/(s+1) and H = (s-1)/(s+2), the closed-loop transfer function is given by:
T(s) = G(s) * H(s) / (1 + G(s) * H(s))
T(s) = (1/(s+1)) * ((s-1)/(s+2)) / (1 + (1/(s+1)) * ((s-1)/(s+2)))
To find the stability, we analyze the characteristic equation:
1 + G(s) * H(s) = 0
1 + (1/(s+1)) * ((s-1)/(s+2)) = 0
Solving this equation for s, we find that the system is stable for all values of K since there are no positive real parts of s.
b) For G(s) x H(s) = (s^2+2s+2)/(s^2(s-1)), the closed-loop transfer function is given by:
T(s) = G(s) * H(s) / (1 + G(s) * H(s))
T(s) = (s^2+2s+2)/(s^2(s-1)) / (1 + (s^2+2s+2)/(s^2(s-1)))
To find the stability, we analyze the characteristic equation:
1 + G(s) * H(s) = 0
1 + (s^2+2s+2)/(s^2(s-1)) = 0
Solving this equation for s, we find that the system is unstable when the poles of the denominator have a positive real part. In this case, the denominator is:
s^3 - s^2 + s^2 - s - 2 = s^3 - s - 2
Using the Routh-Hurwitz criterion, we find that the system is unstable when there is a change in the sign of the coefficients in the first column of the Routh array. For this cubic polynomial, the system is unstable when K > 2.
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Water flows over Niagara Falls at the average rate of 2,400,000 kg/s, and the average height of the falls is about 50 m. Knowing that the gravitational potential energy of falling water per second = mass (kg) × height (m) × gravity (9.8 m/s2), what is the power of Niagara Falls? How many 15 W LED light bulbs could it power?
Explanation:
It is given that,
Water flows over Niagara Falls at the average rate of 2,400,000 kg/s
The average height of the falls is 50 m
We need to find the power of Niagara Falls.
The gravitational potential energy of falling water is given by :
P = mgh
Power is rate of doing work i.e.
\(P=\dfrac{W}{t}\\\\P=\dfrac{mgh}{t}\\\\P=\dfrac{m}{t}\times gh\)
We have, m/t = 2,400,000 kg/s
So,
\(P=2400000\times 9.8\times 50\\\\P=1.176\times 10^9\ W\)
If the number of bulbs are n that could power 15 W LED, the,
\(n=\dfrac{1.176\times 10^9}{15}\\\\n=78400000\ \text{bulbs}\)
1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm. Half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The cylinder changes volume to maintain constant pressure. What is the volume in the final system?
The volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
How to calculate volume?The volume of a given amount of gas can be calculated by using the combined gas law formula as follows;
P1V1/T1 = P2V2/T2
Where;
P1 = initial pressureP2 = final pressureT1 = initial temperatureT2 = final temperatureV1 = initial volumeV2 = final volumeAccording to this question, 1.0 mole of a gas is enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm.
However, half of the gas is removed, leaving 0.50 mole in the cylinder and the system is warmed to 900 K. The volume in the final system can be calculated as follows:
2 × 12.3/300 = 2 × V2/900
0.082 = 2V2/900
73.8 = 2V2
V2 = 73.8 ÷ 2
V2 = 36.9L
Therefore, the volume in the final system that was initially enclosed in a 12.3 liter cylinder with a moveable piston at 300 K and 2.0 atm is 36.9L.
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Answer:
Explanation:
it's 18.45, my sister just got the guestion right! hope it helps :)
.The C-C stretching vibration of ethylene can be treated as a harmonic oscillator.
a. Calculate the ratio of the fundamental frequencies for ethylene and deuterated ethylene
b. Putting different substituents on the ethylene can make the C-C bond longer or shorter. For a shorter C-C bond, will the vibrational frequency increase or decrease relative to ethylene? Why?
c. If the fundamental vibrational frequency for the ethylene double bond is 2000 cm^-1,
what is the wavelength in nm for the first harmonic vibration frequency?
A. The ratio of the fundamental frequencies for ethylene and deuterated ethylene is 1.07.
b. It should be noted that the vibrational frequency increase relative to ethylene?
c The wavelength in nm for the first harmonic vibration frequency is 2500nm
WHat is a wavelength?Wavelength is the distance between two consecutive peaks or troughs in a wave. It is usually denoted by the Greek letter lambda (λ) and is measured in meters (m) or other units of length.
Wavelength is an important characteristic of all types of waves, including electromagnetic waves (such as light and radio waves) and mechanical waves (such as sound waves).
The calculation is attached.
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What is generally true of atoms with relatively large atomic radii?
A. Large atoms hold their electrons very tightly.
B. Large atoms tend to have a low ionization energy and a low electron affinity.
C. Large atoms tend to be found on the right side of their period on the periodic table.
D. Large atoms are usually found at the top of their group on the periodic table.
Answer:
B. Large atoms tend to have a low ionization energy and a low electron affinity.
Explanation:
Atomic radii can be defined as a measure of the size (distance) of the atom of a chemical element such as hydrogen, oxygen, carbon, nitrogen etc, typically from the nucleus to the valence electrons. The atomic radius of a chemical element decreases across the periodic table, typically from alkali metals (group one elements such as hydrogen, lithium and sodium) to noble gases (group eight elements such as argon, helium and neon). Also, the atomic radius of a chemical element increases down each group of the periodic table, typically from top to bottom (column).
Generally, atoms with relatively large atomic radii tend to have a low ionization energy and a low electron affinity. Ionization energy can be defined as the minimum energy required to remove or detach an electron from a neutral atom in a gaseous state. Electron affinity can be defined as the ability of an atom of a chemical element to accept or accommodate an electron.
Michael Faraday is known for his discovery of _______ .
Michael Faraday discovered electromagnetic induction. This discovery changed the field of electrical power generation and transmission, shaping modern electrical technologies.
How many molecules are in 5.13 moles of CH4
Answer:
1 mole = 6.02 × 10^23 molecules
5.13 moles = x
x = 5.13/1 × 6.02 × 10^23
= 3.088 × 10^24 molecules
the chemical equation shown is an exothermic process. 2so2(g) o2(g)↽−−⇀2so3(g)exothermic
The given chemical equation is an exothermic process. Exothermic processes are those processes that release energy as heat or light.
In these reactions, the energy of the products is less than the energy of the reactants; hence, energy is released. The given chemical equation is:2SO2 (g) + O2 (g) → 2SO3 (g). This equation represents the reaction between sulfur dioxide (SO2) and oxygen (O2) to form sulfur trioxide (SO3). This reaction is exothermic because it releases heat.
The products, SO3, have a lower energy than the reactants, SO2 and O2. As a result, energy is released, and the temperature of the system increases. This is evident from the fact that the reaction is represented by an arrow pointing to the right-hand side (the products) and has a negative sign above the arrow indicating a negative change in energy.
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For the following reaction, to get the rate of consumption of o2, what must we multiply the rate of consumption of nh3 by? 4NH3+5O2→4NO+6H2OReport your answer as a fraction.
The rate of consumption of O2 can be given by (5/4) × (rate of consumption of NH3).
The compound condition for the given response is 4NH3 + 5O2 → 4NO + 6H2O. As per stoichiometry, 5 moles of O2 respond with 4 moles of NH3. Thus, the pace of utilization of O2 can be connected with the pace of utilization of NH3 utilizing stoichiometry.
To find the pace of utilization of O2, we want to increase the pace of utilization of NH3 by the stoichiometric coefficient of O2, which is 5/4. In this manner, the pace of utilization of O2 can be given by (5/4) × (pace of utilization of NH3).
This connection between the paces of utilization of reactants and items can be gotten from the decent substance condition and the law of preservation of mass, which expresses that the complete mass of the reactants rises to the all out mass of the items in a compound response.
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Choose the pair of concentrations thatcannot be in a given aqueous solution at25°C.a. [H+] = 10-3 M, [OH-] = 10-11 Mb. [H+] = 10-7 M, [OH-] = 10-7 Mc. [H+] = 10-13 M, [OH-] = 1 Md. [H+] = 10 M, [OH-] = 10-15 Me. All of these can exist
All of these can exist as the pair of concentrations in a given aqueous solution at25°C.(E)
At 25°C, the product of the concentrations of hydrogen ions and hydroxide ions in water, known as the ion product constant (Kw), is equal to 1.0 x 10^-14. This means that for any aqueous solution at 25°C, the product of [H+] and [OH-] must equal 1.0 x 10^-14.
Using this information, we can calculate the [OH-] concentration for option A, B, C and D as follows:
A) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-3 = 1.0 x 10^-11 M
B) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-7 = 1.0 x 10^-7 M
C) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-13 = 1.0 x 10^-1 M
D) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10 = 1.0 x 10^-13 M
We can see that all of the given concentrations, except for option E, satisfy the condition that the product of [H+] and [OH-] must equal 1.0 x 10^-14. Option E violates this condition and therefore cannot exist in an aqueous solution at 25°C.
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How much heat is required to change 500 mL of water at 100°C to steam at 100°C? Assume 1 mL of water is = to 1 g of water.
The heat required to change 500 mL of water at 100°C to steam at 100°C is 1.13 ×10⁶J.
What is the latent heat capacity?The latent heat can be defined as the amount of heat required during the phase change of a substance.
The mathematical formula for latent heat can be expressed as:
Q = mL
Given, the mass of water, m = 500 ml = 500 g
The change in temperature of the water, ΔT = 100 - 100 = 0
The latent heat of water, C = 2260 J/g
The heat required to change the temperature of the water can be calculated as:
Q = m ×L
Q = 500 × 2260
Q = 1.13 ×10⁶J
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A group of students conducted an experiment to determine the effect of heat on the germination(sprouting) of sunflower seeds. Which of the variables listed below is the least important to control in this experiment?
a
the temperature of which the seeds are heated
b
the length of time the seeds are heated
c
the type of soil used
d
the amount of moisture in the soil
what grade is this because apparently i like to know what grade it is before i solve it
What numbers do I put on the right side?
The leftovers of \(C_2H_2\) will be 6 moles while the leftover of \(O_2\) will be zero.
Mole ratio of reactantsIn the originally balanced equation of the reaction, 2 moles of \(C_2H_2\) and 5 moles of \(O_2\) react completely to produce 4 moles of \(CO_2\) and 2 moles of \(H_2O\). This equation is balanced with no reactant left.
Now, 8 moles of \(C_2H_2\) were made to react with 5 moles of \(O_2\) in the second reaction. The mole ratio of the two reactants for complete reactions is 2:5. Thus, \(C_2H_2\) has been supplied in excess.
Since only 5 moles of \(O_2\) is available, only 2 moles of \(C_2H_2\) will be consumed. Thus, 6 moles of \(C_2H_2\) will be left while the oxygen will be completely consumed. That is, the amount of \(O_2\) left would be zero.
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Question 8
I need help
Answer:A
Explanation: Since the boiling point is 212. As salt keeps getting added the boiling temperature keeps going up. Meaning it will boil at a high temp.
Which information best supports the idea that the universe began with rapid expansion?
O Measurements of cosmic microwave background radiation
O Measurements of rates of decay
O Calculation of the temperature and brightness of stars
Calculations of the distance from the sun to each planet
if the pco2 in the plasma increases, what effect will this have on plasma ph?
When the partial pressure of carbon dioxide (pCO2) in the plasma increases, this leads to a decrease in plasma pH, resulting in a more acidic environment. The relationship between pCO2 and pH is described by the Henderson-Hasselbalch equation, which helps predict the acid-base balance in the body.
An increase in pCO2 levels indicates that more CO2 is being produced or less is being eliminated. As CO2 dissolves in the plasma, it forms carbonic acid (H2CO3), which subsequently dissociates into hydrogen ions (H+) and bicarbonate ions (HCO3-). The increase in H+ ions is what causes the decrease in pH, signifying a more acidic environment.
This change in pH can disrupt the body's normal homeostasis and is commonly referred to as respiratory acidosis. The body's response to this imbalance involves various buffering systems, such as the bicarbonate buffer system, to help restore pH to a normal range.
In conclusion, an increase in plasma pCO2 levels leads to a decrease in plasma pH, creating a more acidic environment. This can disrupt the body's normal functioning and prompt compensatory mechanisms to restore the acid-base balance.
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A beach ball with a volume of 12.0 L and an initial temperature of 32.0 oC is cooled to -73.0 oC, what is its final volume?
Answer:
-57.12
Explanation:
i used a calculator :)
Answer:
-73
Explanation:
12.0+32.0=44-73.0=-73
Calcule cuántos gramos de magnesio (Mg) son necesarios para reaccionar completamente con 2 moles de oxígeno (O₂), según la reacción: Mg + O₂ → MgO. Dato: mA(Mg = 24) *
En esta reacción, 96 g de magnesio reaccionarán con 2 moles de oxígeno.
Tenemos la ecuación de la reacción como sigue;
2Mg + O₂ → 2MgO. La relación molar como se deduce de la ecuación de reacción balanceada que se muestra arriba es 2: 1.
Por eso;
2 moles de Mg reaccionan con 1 mol de oxígeno
x moles de Mg reacciona con 2 moles de oxígeno
x = 2 moles * 2 moles / 1 mol
= 4 lunares
Masa de magnesio = 4 moles de magnesio * 24 g / mol = 96 g de Mg
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The Case of the Putrid Pond Problem Statement: A very large (500,000 sq. ft. 10 football fields) sludge pond is part of a waste treatment plant. The liquid in the pond is very viscous and sticky. From time to time, unwanted floating objects (dead animals, branches, etc.) appear on the pond and must be removed. Unfortunately, covering the pond is not an option. (a) Devise ways to solve the above-mentioned problem through all the FOUR (4) brainstorming methods and describe it in detail. (15 marks) (b) Draw and describe a fishbone diagram after organizing the ideas generated from (a). (10 marks)
The Case of the Putrid Pond Problem Statement:
1. Brainstorming generated solutions: debris collection nets, manual cleaning, water jets, filtration upgrades, waste management improvements, and regular maintenance.
2. Fishbone diagram: categorizes causes (inflow system, waste management, pond maintenance, environmental factors) and solutions (screening mechanisms, enhanced cleaning schedules).
(a) Devise ways to solve the above-mentioned problem through all the FOUR (4) brainstorming methods and describe it in detail:
1. Brainwriting: In this method, each team member writes down their ideas on sticky notes or a shared document without discussing them with others. The ideas can then be compiled and analyzed collectively. Some possible solutions through brainwriting could include:
- Deploying a large floating debris collection net or barrier around the perimeter of the pond to capture and remove floating objects.
- Implementing regular manual cleaning by workers using long-handled nets or other specialized tools.
- Introducing a system of water jets or pumps to create a flow within the pond, pushing floating objects towards a collection area for easy removal.
2. Reverse Brainstorming: In reverse brainstorming, instead of generating solutions, the focus is on identifying potential causes or factors that contribute to the problem. These causes can then be addressed to find solutions. Possible causes identified through reverse brainstorming might include:
- Inadequate filtration or screening mechanisms in the inflow system, allowing unwanted objects to enter the pond.
- Lack of proper waste management practices upstream, leading to the accumulation of debris in the pond.
- Inefficient or infrequent monitoring and maintenance of the pond, allowing the problem to persist.
3. Starbursting: This technique involves asking specific questions about the problem to prompt idea generation. Questions related to the Putrid Pond problem could be:
- How can we prevent unwanted floating objects from entering the pond in the first place?
- What alternative methods can be used to remove floating objects without covering the pond?
- Are there any environmentally friendly solutions that can be implemented?
4. Mind Mapping: Mind mapping is a visual brainstorming technique that involves creating a diagram with the main problem in the center and branching out ideas around it. Some ideas for solving the problem of the Putrid Pond could include:
- Installing automatic skimmers or surface vacuum systems to continuously remove floating debris.
- Implementing regular maintenance schedules for inspecting and cleaning the pond to prevent accumulation.
- Introducing biological treatment methods that can break down organic matter and prevent foul odors.
(b) A fishbone diagram, also known as a cause-and-effect or Ishikawa diagram, can help organize the potential causes and solutions identified through brainstorming. Here is a description of the fishbone diagram for the Putrid Pond problem:
The main problem, "Unwanted Floating Objects in the Pond," is written in the center of the diagram. The diagram branches out into different categories representing possible causes, such as "Inflow System," "Waste Management Practices," "Pond Maintenance," and "Environmental Factors." Each category contains the specific causes identified through brainstorming. For example, under "Inflow System," causes could include "Inadequate Filtration" and "Lack of Screening Mechanisms." Similarly, under "Pond Maintenance," causes could include "Insufficient Cleaning Procedures" and "Lack of Monitoring."
From the identified causes, further branches are created to suggest possible solutions. These solutions can be linked to the specific causes they address. For instance, under "Inflow System," a solution could be "Upgrading Filtration Systems" or "Implementing Effective Screening Mechanisms." Under "Pond Maintenance," solutions might include "Establishing Regular Cleaning Schedules" or "Enhancing Monitoring Practices."
The fishbone diagram visually represents the cause-and-effect relationships between the problem, its causes, and potential solutions, providing a structured overview of the brainstormed ideas.
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Which one is a single replacement reaction? (Whoever gets it correct first I’ll mark)
The equation that represents a single replacement reaction given the various options is 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)
What is a single replacement reaction?A single replacement reaction, also known as single displacement reaction is a reaction in which elements higher in the electro-chemical series displace or replace elements lower in the electro-chemical series displace from a solution.
The following example illustrates single replacement reaction:
A + BC -> AC + B
From the above reaction, we can see that A has replace/displace B to from AC.
With the above information, we can determine the equation that represents single replacement reaction. Details below:
Equation from the questions:
2Al + 3Cl₂ -> 2AlCl₃2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g)2AlCl₃(aq) -> 2Al + 3Cl₂ AlCl₃ + 3KOH -> Al(OH)₃ + 3KClFrom the above, we can see that only 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) conform to single replacement reaction.
Thus, the correct answer to the question is: 2Al(s) + 6HCl -> 2AlCl₃(aq) + 3H₂O(g) (option 2)
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Which reaction occurs at the anode of a galvanic cell that has a zinc
electrode in an electrolyte with zinc ions and a copper electrode in an
electrolyte with copper ions? The reduction potential for the reduction of Cu2+
= 0.34 V. The reduction potential for the reduction of Zn2+ = -0.76 V.
A. Zn(s) → Zn2+(aq) + 2e
B. Cu(s) → Cu2+(aq) + 2e
C. Zn2+ (aq) + 2e → Zn(s)
D. Cu2+ (aq) + 2e →
Cu(s)
Answer: The reaction that occurs at anode is \(Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-\)
Explanation:
Given : \(E^o_{Zn^{2+}/Zn}=-0.76V\)
\(E^o_{Cu^{2+}/Cu}=+0.34V\)
The substance having highest positive reduction potential will always get reduced and will undergo reduction reaction. Here, copper will undergo reduction reaction will get reduced.
The substance having highest negative reduction potential will always get oxidised and will undergo oxidation reaction. Here, zinc will undergo oxidation reaction will get oxidised.
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
Oxidation half reaction (anode) : \(Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-\)
Reduction half reaction (cathode) : \(Cu^{2+}(aq.)+2e^-\rightarrow Cu(s)\)
. Which of the following statement is false?
D. Metalloids are conductors.
B. The least reactive elements are on the right side of the periodic table.
C. Metals are most reactive on the left hand side of the periodic table.
A. Most metals are solids.
Answer:
B
Explanation:
Answer: hey im here, whats up?
Explanation:
Cu2(s)+O2(g)=Cu2O(g)+SO2(g)
please help urgent will give brainiest
Answer:
2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2
Explanation:
2 Cu2S + 3 O2 = 2 Cu2O + 2 SO2
What is the volume of a weather balloon that has 39 grams of helium with a density 0.017 g/mL?
Answer:
The answer is 235.29 mLExplanation:
The volume of a substance when given the density and mass can be found by using the formula
\(volume = \frac{mass}{density} \\ \)
From the question.
density = 0.017 g/mL
mass = 4 g
We have
\(volume = \frac{4}{0.017} \\ = 235.2941176...\)
We have the final answer as
235.29 mLHope this helps you
Carry out the following conversions.
(a) 1.21 light-years to miles
Answer:
About 5.8 trillion miles is equal to 1 light year
so (5,878,600,000,000 miles)*(1.21 light-years) = 7,113,106,000,000 miles
What could be done to change this carbide ion to a neutral carbon atom? A) remove 2 electrons B) add 2 electrons C) remove 4 electrons D) add 4 electrons
Answer:remove 4 electrons
Explanation:
I took the test just a minute a go
If a convergent boundary involves a continental landmass and an ocean basin, what is the result?
o
A chain of volcanic mountains will form on the edge of the continent or just off shore; a
deep ocean trench will form off shore.
The land will fold and fault, forming high mountain ranges.
O
The land at the edge of the continent will buckle, causing the formation of a trench.
O
There will be frequent earthquakes, but no other evidence of crustal movement.
Answer:
A chain of volcanic
Explanation:
Answer:
A
Explanation:
determine the total mass of 1 pentanol that will dissolve in 110 grams of water to produce a saturated solution
To determine the total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution, we need to use the concept of solubility and molar mass. What is solubility? Solubility refers to the ability of a solute to dissolve in a solvent. It is measured in units of grams per 100 grams of solvent at a specific temperature.
A solution is said to be saturated if it contains the maximum amount of solute that can dissolve in the solvent at a specific temperature. The solubility of a solute depends on factors such as temperature, pressure, and the nature of the solvent and solute. What is molar mass? Molar mass refers to the mass of one mole of a substance. It is measured in units of grams per mole. The molar mass of a compound can be calculated by adding the atomic masses of the elements in the compound. Explanation: Given data: Mass of water = 110 grams To determine: Total mass of 1-pentanol that will dissolve in 110 grams of water to produce a saturated solution Solution: Firstly, let's find out the solubility of 1-pentanol in water. According to the solubility chart, the solubility of 1-pentanol in water at 25°C is 22.5 g/100 ml (or 22.5 g/110 g).So, we can say that 22.5 g of 1-pentanol can dissolve in 100 g of water to produce a saturated solution at 25°C.Now, we can use the proportionality method to calculate the total mass of 1-pentanol that will dissolve in 110 g of water.22.5 g of 1-pentanol dissolves in 100 g of water. So, x grams of 1-pentanol will dissolve in 110 g of water. x = (22.5 × 110) / 100x = 24.75 g Therefore, the total mass of 1-pentanol that will dissolve in 110 g of water to produce a saturated solution is 24.75 grams.
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Rocky is a dog used to help investigate crime scenes involving fire. What is Rocky MOST likely trained to do?
a. he can test the scene for carbon monoxide.
b. He can detect the scent of cigarettes and matches
c. He can find a fire's polnt of origin by sniffing for it.
D. He can smell the scene to find flammable liquids,
Answer:
The answer is D. He can smell the scene to find flammable liquids.
Explanation:
He will smell an object then find the liquid that could of led to it.
Which substance would be the strongest?
carbon
steel
gold
silver
Answer:
steel
Explanation:
Answer:
B. STEEL
Explanation:
Word equation for Silver being added to sulphuric acid
Answer:
See the answer below
Explanation:
When silver is added to dilute sulphuric acid, no reaction would occur. However, silver reacts with hot and concentrated sulphuric acid to produce silver sulphate, sulphur dioxide, and water.
The equation of the reaction is as below:
silver + sulphuric acid --> silver sulphate + water + sulphur dioxide
\(2Ag(s) + 2 H_2SO_4(aq) -->Ag_2SO_4 (s) + 2 H_2O (l) + SO_2 (aq)\)