Give one term to the description;the tables that contain reduction half reaction​

The tank contains 200 gallons of brine solution with 3 lb of salt. At t = 0, another solution is poured at 6 gal/min, leaving the tank at the same rate. The incoming rate of salt is 18 lb/gal, and the outgoing rate is 6 gal/min. The solution's volume remains constant.

Given that,Initially, the tank holds 200 gallons of brine solution containing 3 lb of salt.At t = 0, another brine solution containing 3 lb of salt per gallon is poured into the tank at the rate of 6 gal/min.The mixture leaves the tank at the same rate.The volume of the tank remains constant.

Now, let's assume that x(t) be the amount of salt in the tank at time t.Therefore,x(0) = 3 lb.

Now, let's find the differential equation that x(t) follows.

In the tank, the incoming rate of salt = 3 lb/gal x 6 gal/min = 18 lb/min.The outgoing rate is 6 gal/min.

The volume of the tank is constant, and it is equal to 200 gallons.∴ (d/dt)x(t) = (18 - 6x(t)/200) lb/min = (9 - 3x(t)/100) lb/min (On dividing by 2)Separating the variables and integrating, we get:

∫(1/9 - x/300) dx = ∫dt Let u = x/300,

then du = (dx/300)Hence,

∫(1/9 - x/300) dx = ∫\(dt(u/2 - u^2/2)\) = t + C [Where C is the constant of integration]

x/600 - x^2/600 = t + C

Now, we need to find the value of C.

\(C = x(0)/600 - x(0)^2/600C\)

3/600 - 9/360000C = -1/2000

Hence,

\(x/600 - x^2/600 = t - 1/2000\)

Multiplying by 600 on both sides, we get,

\(x - x^2 = 600t - 0.3\)...(1)

Now, we need to find the value of t at which the mixture in the tank contains 6 lb of salt.Substituting x = 6 in equation (1), we get:6 - 6^2 = 600t - 0.3...5 = 600t...t = 5/600 = 0.00833 hours = 0.5 minutes

Therefore, the time at which the mixture in the tank contains 6 lb of salt is 0.5 minutes (approximately).Hence, the correct option is 0.02 min.

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Moles of carbon dioxide(co2) will you make only 0.0115 mol was produced.

we know the ideal gas equation,

PV = nRT

PV/RT=n

n=(1.04 atm)(1.00 L) /L atm (0.0821 )(1100 K) mol K

n=0.0115 moles of CO2.

The moles ofCaCO3 = 50.0 g/100.09 g/mol = 0.500 mol CaCO3 .If the reaction had gone to completion, 0.500 mol of CO2 would have been produced.  The two different experiments (one with 50.0 g of CaCO3 and one with 100.0 g of CaCO3) reached the same constant, final pressure of 1.04 atm.

Since increasing the amount of reactant did not produce more product, there is no way that all of the CaCO3 reacted. Instead, an equilibrium condition has been achieved and there must be some solid CaCO3 in the container.

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Answer:

0.0522 mol NaSo4

Explanation:

3.148 x 10^22 Formula units NaSo4 * 1 mol NaSo4 / 6.02 x 10^23 Formula units NaSo4   = 0.0522 mol NaSo4

Since water does not have charged particles, water is a non-conductor. When some solutes dissolve in water they allow an electric current to flow through the water and the solution conducts electricity. These solutes are called electrolytes. ... Non-electrolytes like sugar dissolve to form molecules in solution.

The anode of the Downs cell, you would expect the half-reaction of the oxidation of chloride ions (Cl-) to chlorine gas Cl2. This is because the anode is where oxidation reactions occur in electrolysis, and in the electrolysis of molten sodium chloride, the chloride ions are present in the electrolyte and are more easily oxidized than the sodium ions.

The chloride ions will lose electrons and form chlorine gas at the anode. happy to help with your question. In the Downs cell, an industrial cell used for electrolysis of molten sodium chloride, the half-reaction at the anode is the oxidation of chloride ions to produce chlorine gas. Here's the half-reaction:2Cl⁻l → Cl₂ g + 2e⁻At the anode, the chloride ions Cl⁻ lose electrons and form chlorine gas Cl₂, releasing two electrons in the process.

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The term “INTERmolecular forces” is used to describe the forces of attraction between atoms, molecules, and ions when they are placed close to each other.

In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles.

In a liquid, intermolecular attractive forces hold the molecules in contact, although they still have sufficient KE to move past each other. Intermolecular attractive forces, collectively referred to as van der Waals forces, are responsible for the behaviour of liquids and solids and are electrostatic in nature.

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Chlorine in group 17 in the periodic table and includes halogens (also fluorine, bromine, and iodine)

Electron configuration of Cl : [Ne] 3s² 3p⁵

From this configuration, it can be seen that to obtain stability like the noble gas Ar - [Ne] 3s² 3p⁶, Chlorine will need one more electron so that its configuration is the same as Ar( become anion-Cl⁻)

Then it is said that Cl is reactive

And the Cl element is included in the non-metal group because it attracts electrons (electronegative)

The elements that include non-metals are halogens, noble gases, and 7 elements H, C, N, O, P, S, Se.

Answer: The air molecules move closer together.

Explanation:

Answer:

Physical change

Explanation:

No new substances were produced so it is physical change.

Answer:

Physical Change

Explanation:

Since only the temperature is changing not the structure of tea its a physical change. Good luck ;)

Answer:

The blood circulatory system (cardiovascular system) delivers nutrients and oxygen to all cells in the body. It consists of the heart and the blood vessels running through the entire body. The arteries carry blood away from the heart; the veins carry it back to the heart. The system of blood vessels resembles a tree. The smallest arteries end in a network of tiny vessels known as the capillary network.

There isn't just one blood circulatory system in the human body, but two, which are connected, The systemic circulation provides organs, tissues and cells with blood so that they get oxygen and other vital substances. The pulmonary circulation is where the fresh oxygen we breathe in enters the blood.

Explanation:

Using Bohr's equation for the energy levels of the electron in the Hydrogen atom, determine the energy in J of an electron in the n=4 level.

According to Boh'rs equation we can calculate the energy using this equation:

En = - 2.18 * 10⁻¹⁸ J / (n²)

So if we want to find the energy we only have to replace n by 4 and solve that calculation:

since n = 4

En = - 2.18 * 10⁻¹⁸ J / 4²

En = - 2.18 * 10⁻¹⁸ J / 16

En = -1.36 * 10⁻¹⁹ J

So the answer is option D

Answer:

c.  

Fluorine

Explanation:

Answer:

Colloids are mixtures in which one or more substances are dispersed as relatively large solid particles or liquid droplets throughout a solid, liquid, or gaseous medium.

Answer:

Colloids are mixtures in which one or more substances are dispersed as relatively large solid particles or liquid droplets throughout a solid, liquid, or gaseous medium.

Explanation:

I got the answer first

The respective hybridization of the imine nitrogen and carbonyl carbon of the CPV B - state as it is depicted in the passage is sp2 and sp2.

Generally, the hybridization depends upon the amount and type of bonds of the atom analyzed has in the molecule.

Let's consider some examples:

A Carbon atom bonded to 4 Hydrogen atoms has a sp3 hybridization.

A Carbon atom bonded to 2 Hydrogen atoms and to 1 Carbon with a double bond (like in ethene) has a sp2 hybridization

A Carbon bonded to 1 Hydrogen and 1 Carbon with a triple bond (like in ethyne) has a sp hybridization.

We will be able to determine the hybridization by analyzing the type and amount of unions of the nitrogen and the carbonyl.

Basically, in the imine, the Nitrogen atom has a double bond to a Carbon atom and a single bond with two other Carbon atom, with addition to the lone pair of electrons (counts as a bond) so it will have a sp2 hybridization.

And in the carbonyl, the Carbon has two simple bonds to other Carbon and a double bond to an oxygen atom. Therefore, it will also have a sp2 hybridization.

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Therefore, the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M hydrosulfuric acid solution are pH = 7.78 and [S²⁻] = 2.31x10⁻¹¹ M.

Hydrosulfuric acid (H₂S) is a weak acid that dissociates in water to produce hydrogen ions (H⁺) and bisulfide ions (HS⁻). H₂S(aq) + H₂O(l) ⇌ H₃O⁺(aq) + HS⁻(aq)

The bisulfide ions (HS⁻) in turn reacts with water to produce hydronium ions (H₃O⁺) and sulfide ions (S²⁻).

HS⁻(aq) + H₂O(l) ⇌ H₃O⁺(aq) + S²⁻(aq) Ka1

= 1.0x10⁻⁷,

Ka2 = 1.0x10⁻¹⁹

To calculate the pH and the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we must first determine if H₂S(aq) is a strong or weak acid.

It has Ka1 = 1.0x10⁻⁷, which is a very small value; thus, we can conclude that H₂S(aq) is a weak acid.

To calculate the equilibrium concentration of S²⁻ in a 6.89x10⁻² M H₂S(aq) solution, we need to use the Ka2 value (Ka2 = 1.0x10⁻¹⁹) and a chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0Change -x +x +x

Equilibrium (6.89x10⁻² - x) x xKa2 = [H₃O⁺][S²⁻]/[HS⁻]1.0x10⁻¹⁹

= x² / (6.89x10⁻² - x)

Simplifying: 1.0x10⁻¹⁹ = x² / (6.89x10⁻²)

Thus: x = √[(1.0x10⁻¹⁹)(6.89x10⁻²)]

x = 2.31x10⁻¹¹ M

Thus, [S²⁻] = 2.31x10⁻¹¹ M

To calculate the pH of the solution, we can use the Ka1 value and the following chemical equilibrium table.

[H₂S] = 6.89x10⁻² M[H₃O⁺] [HS⁻] [S²⁻]

Initial 0 0 0

Change -x +x +x

Equilibrium (6.89x10⁻² - x) x x

Ka1 = [H₃O⁺][HS⁻]/[H₂S]1.0x10⁻⁷

= x(6.89x10⁻² - x) / (6.89x10⁻²)

Simplifying: 1.0x10⁻⁷ = x(6.89x10⁻² - x) / (6.89x10⁻²)

Thus: x = 1.66x10⁻⁸ M[H₃O⁺]

= 1.66x10⁻⁸ M

Then, pH = -log[H₃O⁺]

= -log(1.66x10⁻⁸)

= 7.78 (rounded to two decimal places)

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Atomic radius is1.349*10-23

hcp unit cell you can see that that the spheres touch each other along

so 2rMg = a where rMg is the radius of a Mg ion and = 0.6745*10^-23

There are three levels of atoms in the hcp structure.

Six atoms form a hexagonal arrangement in the top and bottom layers, while a seventh atom sits in the centre of the hexagonal arrangement.

Three atoms in the intermediate layer are tucked away in the top and bottom plane's triangular grooves.

Mg hcp c/a = 1.635

hcp is close-packed example ABABAB etc

V = sin(60)*a*a*1.635 a

V = 1.635 *0.866*a^3

V = 1.887*a^3 cm3

Z = 2 (atoms inside unit cell)

Mass inside unit cell is = (2 * 24.305)/(6.022*10^23) = 8.071*10^-23 g

D =M/V

1.74 = 8.071*10^-23/1.887*a^3

a^3 = 8.071*10^-23/1.887*1.74 = 2.458*10^-23

a = 1.349*10^-23

Hence Atomic radius is 1.349*10^-23

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Answer:

6.022  ×10(index 23) / 7.5 = 0.8293 ×10(index 23)

Explanation:

molar mass of C =  12gmol

therefore in 12g of C there is one mole or an amount of 6.022 ×10(index 23)

∴12g/6.02210(index 23) ×1.6g

Answer:

If the same index fossil is found in different areas, the strata in each area were likely deposited at the same time. Thus, the principle of faunal succession makes it possible to determine the relative age of unknown fossils and correlate fossil sites across large discontinuous areas.

The given statement is true. Scientists who use logic to determine whether or not a drug is safe. These researchers are using the classical model of decision making.

A logical and methodical approach to decision-making is the classical model of decision-making. This model proposes that decision-makers gather all relevant data, thoroughly evaluate the alternatives, then select the alternative that maximises their utility or produces the desired result. This model makes the supposition that decision-makers have full knowledge of all available options, are unbiased and logical in their assessment, and make choices free from prejudice or emotional influence. It employs a sequential procedure that involves recognising the issue, specifying the decision criteria, allocating weight to each, producing alternatives, assessing the alternatives, and selecting the best option.

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If you were to spill a little benzoic acid as you mix it with the lauric acid, the calculated molecular weight would be too high.

This is because the amount of benzoic acid would be greater than the amount of lauric acid, and the molecular weight of benzoic acid is higher than the molecular weight of lauric acid.

The molecular weight of a substance is the sum of the atomic weights of the atoms that make up the substance. Benzoic acid has a molecular weight of 122.12 g/mol, while lauric acid has a molecular weight of 200.32 g/mol.

If you were to spill a little benzoic acid, the total amount of benzoic acid and lauric acid would be greater than the amount of lauric acid that would be present if no benzoic acid were spilled.

This would cause the calculated molecular weight to be higher than the actual molecular weight of lauric acid.

To avoid this, it is important to be careful when mixing benzoic acid and lauric acid. It is also important to use a balance that is accurate to at least 0.01 g to measure the amounts of benzoic acid and lauric acid.

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Answer:

1. Chief executive officer = Nucleus.

2. Power house = Mitochondrion.

3. Maintenance team = Lysosomes.

4. Functional managers = Chromosomes.

5. Assembly line workers = Ribosomes.

6. Assembly line = Endoplasmic Reticulum.

7. Security and support = Cytoskeleton.

8. Drivers or messengers = Vesicles.

9. Packaging unit = Golgi apparatus.

10. Gate man/procurement unit = Cell membrane.

Explanation:

A cell can be defined as the structural, fundamental, biological and functional unit of life. Cells are found in all living organisms because they are the basic unit of life.

Generally, cells have the ability to independently replicate themselves. These cells can be compared to the kind of structures found in a business or factory, where you have different workers performing different functions.

In a cell, the "workers" that perform various functions or tasks for the survival of the living organism are referred to as organelles.

Factory worker = Cell organelle.

1. Chief executive officer = Nucleus.

The nucleus controls all the activities taking place in the cell and the synthesis of proteins.

2. Power house = Mitochondrion.

The mitochondria provides all the energy required in the cell by transforming energy forms.

3. Maintenance team = Lysosomes.

They are responsible for absorbing materials and breaking the materials taken in by the cells.

4. Functional managers = Chromosomes.

They give sets of instructions for the synthesis of products.

5. Assembly line workers = Ribosomes.

They are involved in the build up of proteins.

6. Assembly line = Endoplasmic Reticulum.

This is where the ribosomes perform their tasks.

7. Security and support = Cytoskeleton.

They help to maintain and support the shape of the cells.

8. Drivers or messengers = Vesicles.

They ensure proteins are properly transported to the right and exact location.

9. Packaging unit = Golgi apparatus.

Prepares the protein for export by chemically tagging them.

10. Gate man/procurement unit = Cell membrane.

It is the wall of the cell and typically controls what leaves and enters the cell.

475.021, f.s., refers to the Florida Statute (f.s.) for driver's license suspensions and revocations. This particular statute deals with the suspension of licenses for drivers who fail to pay court fines, costs, and fees.

The statute states that failure to pay the required court fees within 30 days will result in the suspension of the driver's license.

After 90 days, the suspension becomes permanent until the fees are paid. In summary, the mysterious glyph is trying to tell you about the legal statute in Florida regarding the suspension of driver's licenses for non-payment of court fees, fines, and costs.

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Answer:

Chemistry, physics, astronomy and earth science.

Explanation:

The potential offspring will consist of two females who are carriers of incontinentia pigmenti and two males who are unaffected by the condition.

The Punnett square reveals four potential combinations of the X chromosome in the offspring:

XIPX: Female offspring will inherit the XIP allele from the mother and will be heterozygous for incontinentia pigmenti.

XIPY: Male offspring will inherit the XIP allele from the mother, but since they receive the Y chromosome from the father, they will not exhibit the IP trait.

XX: Female offspring will inherit the normal X allele from the father and the XIP allele from the mother, making them heterozygous for IP.

XY: Male offspring will inherit the normal X allele from the father and the Y chromosome, making them normal and not affected by incontinentia pigmenti.

Therefore, the predicted offspring from a normal male and a heterozygous incontinentia pigmenti affected female would consist of both males and females.

Half of the female offspring will be heterozygous carriers for IP (XIPX), and the other half will be normal (XX). All male offspring will be normal (XY) and will not exhibit the IP trait.

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Answer:

B) mitochondria

Explanation:

Answer

A

Explanation

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