Given the characteristic equation: s2 + 3 + 5 = 0 for v(t), what is the value of the sinusoidal angular frequency (w) in the underdamped expression: v(t) = e -*[Acos(w)t + Bsin(w)t] ? Notes on entering solution: . Enter your solution to two decimal places Do not include units in your answer You are finding (W)

Using the analemma, the latitude with subsolar points ( vertical rays of the sun ) on the following dates is:

1. January 10 = 23.5 degrees south.

2. June 21 = 23.5 degrees north.

3. March 6 = 0 degrees.

4. December 21 = 23.5 degrees south latitude.

1. January 10: The subsolar point is near the Tropic of Capricorn, which is located at approximately 23.5 degrees south latitude. So, the latitude with the subsolar point on January 10 would be around 23.5 degrees south.

2. June 21: The subsolar point is near the Tropic of Cancer, which is located at approximately 23.5 degrees north latitude. So, the latitude with the subsolar point on June 21 would be around 23.5 degrees north.

3. March 6: On this date, the subsolar point is shifting towards the northern hemisphere from the equator. The exact latitude depends on the tilt of the Earth's axis and the position of the Sun. On average, the subsolar point on March 6 is approximately at the equator (0 degrees latitude).

4. December 21: On this date, the subsolar point is shifting towards the southern hemisphere from the equator. The exact latitude depends on the tilt of the Earth's axis and the position of the Sun. On average, the subsolar point on December 21 is approximately at the Tropic of Capricorn (23.5 degrees south latitude).

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The correct answer is "electrons."

Atoms can form molecules or compounds with each other. Atoms can achieve this by sharing, gaining, or losing electrons. These interactions between atoms are known as chemical bonds. In addition, atoms form compounds in order to achieve stability and fill their outermost energy level with electrons.

A negatively charged subatomic particle known as an electron can be free (not bound) or attached to an atom. One of the three main types of particles within an atom is an electron that is bonded to it; the other two are protons and neutrons. The nucleus of an atom is made up of protons and electrons together. The positive charge of a proton balances the negative charge of an electron. An atom is in a neutral condition when it contains the same amount of protons and electrons.

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To compress the coiled spring by 0.0508 m, a force of 236.27 N is required. The spring constant for this unit is 4682.2 N/m.

The force needed to compress the spring can be calculated using Hooke's Law, which states that the force required to stretch or compress a spring is directly proportional to the distance of deformation from its equilibrium position.

Using F = kx, where F is the force, k is the spring constant, and x is the distance of deformation from its equilibrium position, we can calculate the value of the spring constant for this unit.

Given that a force of 89.0 N is required to compress the spring by 0.0191 m, we can calculate the spring constant as follows:

k = F/x = 89.0 N/0.0191 m = 4660.73 N/m

Now, to find the force needed to compress the spring by 0.0508 m, we can use the same formula:

F = k x = 4660.73 N/m x 0.0508 m = 236.27 N

Therefore, the force needed to compress the coiled spring by 0.0508 m is 236.27 N, and the value of the spring constant for this unit is 4682.2 N/m.

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The measure of the chord-chord angle is 175.5.

A circle's chord is the line segment that connects any two locations on the circle's circumference. It should be remembered that a circle's diameter is defined as the lengthiest chord that runs across the center of the circle.

An angle is a figure created by two rays or lines that have the same termination in plane geometry. The Latin word "angulus," which meaning "corner," is where the term "angle" originates. The common terminal of the two rays—known as the vertex—is referred to as an angle's sides.

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Answer: Earthquakes

The movement of the tectonic plates causes earthquakes. There are different kinds of plate interactions, but basically it's like a rubber band being stretched then the energy is released in the form of the ground shaking.

Answer:

a) El trabajo realizado es de 274,680 J

b) La potencia de la carretilla elevadora es de 4578 Watts.

c) La energía cinética del montacargas es de 3.888.\(\overline 8\) J

d) La energía potencial del montacargas es de 274.680 Joules.

e) La energía mecánica de la carretilla elevadora 278,568.\(\overline 8\) J

Explanation:

a) Los parámetros dados son;

La velocidad de la carretilla elevadora, v = 12 km / h = 10/3 m / s

La masa que debe levantar la carretilla elevadora, m = 700 kg

La altura a la que se levantará la masa, h = 40 m

El trabajo realizado, W = Fuerza, F × Distancia, h

 La fuerza, F aplicada = El peso de la carga = Masa, m × Gravedad, g

Donde 'g' es la aceleración debida a la gravedad ≈ 9,81 m / s²

∴ Trabajo realizado, W = 700 kg × 9,81 m / s² × 40 m = 274,680 J

b) El tiempo que se tarda en subir 40 m = 1 minuto = 60 segundos

∴ Potencia = Trabajo / tiempo

Por lo tanto, la potencia del montacargas, P = 274,680 J / (60 s) = 4578 Watts

c) Energía cinética, K.E. = 1/2 · m · v²

La energía cinética de la carretilla elevadora, K.E. se da como sigue;

Carretilla elevadora K.E. = 1/2 × 700 kg × (10/3 m / s) ² = 3.888.\(\overline 8\) J

d) La energía potencial del montacargas a 40 m, P.E. = m · g · h

∴ P.E. = 700 kg × 9,81 m / s² × 40 m = 274,680 Julios

e) La energía mecánica, M.E. = P.E. + K.E.

∴ M.E. = 3.888.\(\overline 8\) J + 274,680 J = 278,568.\(\overline 8\) J

La energía mecánica de la carretilla elevadora, M.E.= 278,568.\(\overline 8\) J.

Answer:

Resultant horizontal force  :  16 N

Resultant vertical force :   4 N

Explanation: Force acting on left : 3N

                      Force acting on left : 1 N

                      Forces acting on left : 3N + 1N = 4N

                       Force acting on right : 12 N

                       Resultant horizontal force  : 12 N - 4 N = 16 N

                      Force acting upwards : 4 N

                      Force acting upwards : 2 N

                      Forces acting upwards : 4 N + 2 N = 6 N

                       Force acting downwards : 10 N

                        Resultant vertical force : 10 N - 6N = 4 N

Given :

A 1200 kg car initially traveling at 20 m/s increases its speed to 28m/s.

To Find :

How much work did the cars engine have to do to cause this change.

Solution :

We know, work done is given by :

Work Done = Final Kinetic Energy - Initial Kinetic Energy

\(Work \ Done = \dfrac{mv_f^2}{2} - \dfrac{mv_i^2}{2}\\\\Work \ Done = \dfrac{1200 \times 28^2}{2} - \dfrac{1200\times 20^2}{2}\\\\Work \ Done = 230400\ J\\\\Work \ Done = 230.4 \ kJ\)

Therefore, work done by car engine is 230.4 kJ.

The current is 3.33A, the resistance is 36.03 Ohm, and the peak voltage is 169.68V.

Given information:

The power rating of the resistive element (P) = 400 W

Voltage supplied by the outlet (V) = 120 VAC (RMS)

a) To find the current flowing through the element, the formula:

Power (P) = Voltage (V) × Current (I)

Current (I) = Power (P) / Voltage (V)

Substituting the given values:

Current (I) = 400 W / 120 VAC

= 3.33 A

b) To find the resistance of the element, Ohm's Law can be used :

Resistance (R) = Voltage (V) / Current (I)

Resistance (R) = 120 VAC / 3.33A

= 36.03 Ohm

c) To find the peak voltage, it is required to convert the RMS voltage to peak voltage. For an AC voltage, the relationship between RMS voltage (\(V_{rms\)) and peak voltage (\(V_{peak\)) is given by:

\(V_{peak} = V_{rms} \times \sqrt2\)

Substituting the given RMS voltage:

Peak voltage  = \(120 \times \sqrt2\)

= 169.68 V

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Answer: false

Explanation: because if one car is at 2 m/s and the other at 1 m/s one would be farther away from the stating point

The x-component of A vector is - 2.39 unit.

The y-component of A vector is  - 4.02  unit.

Vector is a colloquial term  that refers to some quantities that cannot be expressed by a single number (a scalar) or to elements of some vector spaces.

The magnitude of A vector is 4.68 unit.

The  direction of A vector is 30.7° to the left of the negative y-axis.

So, A vector is in 3rd co-ordinate.

Hence, the x-component of A vector is = - Asin30.7°

= - 4.68 × sin30.7°

= - 2.39 unit.

Hence, the y-component of A vector is = - Acos30.7°

= - 4.68 × cos30.7°

= - 4.02  unit.

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Answer: C. They are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere

Explanation:

Sunspots appear dark because they are regions in which strong magnetic fields make it difficult for fresh supplies of hot, ionized gas to reach the photosphere.

Sunspots are typically cooler than their surroundings. For example, the temperature of a large sunspot can be about 4,000 Kelvin which is lower than the temperature of the photosphere around it which is about 5,800 Kelvin.

The length of the highlighted arc is (4/3)π.

Based on the given information, we have the following:

1. Circle with center Q

2. QR = 3

3. Area of shaded sector = 2π

To find the length of the arc, we need to first determine the central angle (θ) of the shaded sector.

We can do this using the formula for the area of a sector:

Area of sector = (1/2) × r² × θ

where r is the radius and θ is the central angle in radians.

In this case, r = QR = 3 and the area of the sector = 2π. 2π = (1/2) × 3² × θ

Solve for θ: θ = 2π / (9/2) = 4π/9

Now, to find the length of the arc, we can use the formula: Arc length = r × θ

Substitute the values of r and θ: Arc length = 3 × (4π/9) Arc length = (4/3)π

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The car's acceleration is -1.3 meters per the second square

To solve this, use the first equation of motion v=u+at

where, v = final velocity(meters per second )

           u = initial velocity(meters per second )

           a = acceleration(meters per second square)

           t = time (seconds)

According to the question,

Initial velocity(u) of the car = 28 meters per second

Final velocity(v) of the car  = 15 meters per second

Time  (t) = 10 seconds

Acceleration of the car(a) =?

Substituting the values in equation v =u+at

v= u+at

15 = 28 + ax10

15-28 = 10a

-13 = 10a

a = -13/10

a = -1.3 meters per second square

The car's acceleration is =  -1.3 meters per second square

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The acceleration of this car is equal to -1.3 meters per seconds square (m/s²).

Mathematically, the acceleration of this car can be calculated by using this mathematical expression:

a = (V - U)/t

Where:  

Substituting the given parameters into the acceleration formula, we have;

Acceleration, a = (15 - 28)/10

Acceleration, a = -13/10

Acceleration, a = -1.3 m/s².

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Answer:

Ammonia, \((NH_{3})\)

Explanation:

If a Rac variant, in which the residue at position 61 was replaced with an alanine (Rac-61A), was synthesized. Also, Wild-type Rac and Rac-61A were incubated separately with VopC.

In order to obtain data to support that VopC modifies Rac at residue 61, the samples should be analyzed for the presence of Ammonia (\(NH_{3}[\tex]) compound.

In chemistry, the Vanadyl Phthalocyanine (VopC) comprises of a catalytic domain that activates host cells GTPase Rac irreversibly, through the deamide side chain of the residue existing at position 61.

Also, we know that a deamidation reaction gives off Ammonia, \((NH_{3})\) and as such when ammonia is present in the sample containing Wild-type Rac but not in Rac-61A, this simply proves or provide the data to support that VopC modifies Rac at residue 61.

Additionally, deamidation can be defined as the chemical conversion (hydrolysis) of an amide functional group such as glutamine, asparagine, in a polypeptide to another functional group such as glutamic acid or isoaspartic acid respectively by treating it with a strong acid (deamidate, transamidase).

In conclusion, Galileo's observation and Newton's explanation demonstrate that, in the absence of air resistance, heavy and light objects fall in the same way due to the constant force of gravity acting on them.

Galileo observed that, under the assumption that air resistance can be neglected, heavy objects fall in the same way as lighter objects. Newton explained this observation by noting that the force of gravity acting on an object is directly proportional to its mass.
According to Newton's second law of motion, the force acting on an object is equal to its mass multiplied by its acceleration. In the case of free fall, the only force acting on the object is gravity.
Since the force of gravity is the same for both heavy and light objects near the Earth's surface, their accelerations will be the same. This means that they will fall with the same rate of acceleration, regardless of their mass.
In conclusion, Galileo's observation and Newton's explanation demonstrate that, in the absence of air resistance, heavy and light objects fall in the same way due to the constant force of gravity acting on them.

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Answer:

It would lift the object to the same height than before you move it 3 centimeters to the left. You see, the height doesn't change if you move the inclined plane horizontally, because height is a vertical variable.

Therefore, if the inclined plane has a height of 1 meters, then the object will be lifted 1 meters up, no matter if you move the inclined plane 50 meters horizontally, it won't change its height.

Answer:

P.E = 4.398 Joules.

Explanation:

Given the following data;

Spring constant, k = 71.8N/m

Displacement, x = 0.35m

To find the elastic potential energy;

The elastic potential energy of an object is given by the formula;

\( P.E = \frac {1}{2}kx^{2}\)

Substituting into the equation, we have;

\( P.E = \frac {1}{2}*71.8 *(0.35)^{2}\)

\( P.E = 35.9 * 0.1225 \)

Elastic potential energy = 4.398 Joules.

Therefore, the elastic potential energy of the spring is 4.398 Joules.

"If the darts are thrown at the same speed then (B) Projectile that travels along trajectory B was projected earlier and (C) Second dart must be projected at angle, such that 0 + 0,8 = 90° is correct."

Initial speed of dart A = u'

Angle of dart A = θ'

Initial speed of dart B = u''

Angle of dart B = θ''

Both darts start out at the same speed,

Thus, u' = u'' = u

The darts are launched one at a time from the same location A, but not simultaneously. However, they cover the same horizontal distance and arrive at B simultaneously.

Since both darts' horizontal ranges are equal,

= [ u²sin(2θ') / g ] =  [ u²sin(2θ'') / g ]

= sin(2θ') = sin(2θ'')

Although θ' is not equal to θ", we can infer that θ" >θ' from the figure.

Since both are acute angles,

= sinθ'' > sinθ'

Multiplying both sides by 2u/g, we get,

= [ 2u X sinθ'' / g ] > [ 2u X sinθ' / g ]

so that the two darts' respective trajectories are as follows:

= T'' > T'.

Thus, statement B and C are correct options.

The given question is incomplete. The complete question is '(A) Projectile that travels along trajectory A was projected earlier (B) Projectile that travels along trajectory B was projected earlier. (C) Second dart must be projected at angle e, such that 0 + 0,8 = 90° (D) Second dart must be projected at angle , >, STA​.'

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At the time of the summer solstice, the noontime altitude of the sun is at its highest point, around 90°.

Altitude is the height above sea level. It is typically measured in either metres or feet. In aviation, altitude can also refer to the vertical distance between an aircraft and a certain reference point on the ground. Altitude can be used to determine the air pressure, temperature, and density of the air. Altitude can also be used to calculate the distance a plane can travel without refueling. Altitude can play an important role in the weather of an area, as air pressure and temperature tend to decrease with altitude. Altitude can also affect the type of vegetation found in an area. In mountain regions, the altitude can have a dramatic effect on the climate, creating distinct areas of vegetation and wildlife. Altitude can also affect the types of crops that can be grown in an area, depending on the air pressure, temperature, and precipitation.

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The bug has the greater acceleration because it has the smaller mass

The bug has a greater change in velocity (acceleration) due to experiencing equal force as a much smaller mass.

The rate at which the speed and direction of a moving object vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

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Answer: To grow strong seedlings, the light should be placed close to the tray, and raised as the plants grow taller.  The Independent variable of this experiment is the light that enter the plant. The Dependent variable is the height of the plant.

Explanation:

Answer:

\(Vg=200mile/hr\)

\(\theta=153 \textdegree\)

Explanation:

From the question we are told that:

Plane airspeed \(v_p=190mil/h\)

Plane direction \(\angle=150 \textdegree\)

Wind current speed \(V_w=30mil/h\)

Wind direction \(\angle=150 \textdegree\)

Generally the vector form of the forces is mathematically given by

For plane

\(\angle Q_p=90-150 \textdegree\)

\(V_p=170(cos60 \textdegree ,sin60 \textdegree)\)

\(V_p=(85,-147.224)\)

For wind

\(\angle Q_w=90-170 \textdegree\)

\(V_w=30(cos-80 \textdegree ,sin-80 \textdegree)\)

\(V_w=(5.2,-29.54)\)

Generally the equation for resultant force is mathematically given by

\(v_r=V_a+V_w\)

\(v_r=(85,-147.224)+(5.2,-29.54)\)

\(v_r=(90.21,-176.76)\)

\(v_r=198.45\angle -63\)

Therefore ground speed

\(V_g=198.5miles/hr\)

\(Vg=200mile/hr\)

Direction

\(\theta=(90+63)=153 \textdegree\)

\(\theta=153 \textdegree\)

Answer:

Their velocity is 0m/s because the first box was only 10 kg and the second box was double the weight

Answer:

Red I'm pretty sure

Explanation:

Vocanic ash and sunsets. Volcanic eruptions can inject millions of tonnes of dust and gaseous sulfur dioxide into the stratosphere. ... The dust and aerosol produce vivid sunset and twilight effects like the intense yellow-red horizon and purple-pink glows of the photograph.

The sky is a Dark Black.

Explanation:

The smoke from the volcano fills the sky with black smoke

The magnitude of the magnetic field at the center of a 63-turn circular coil with a radius of 18.1 cm and current 3.21 A is 70.165×10⁻⁵T.

Given information,

Number of turns, n =63

radius, r = 18.1 cm = 18.1 × 10⁻² m

current, I = 3.21 A

The field that is generated by a moving charge, or a field around a magnet, is called a Magnetic field.

S.I. unit - Tesla (T).

The Magnetic field due to the circular current-carrying coil,

B = μNI/2r

B =  (4π × 10⁻⁷×63×3.21)/18.1 × 10⁻²×2

​B = 70.165×10⁻⁵T

Hence, the magnitude of the magnetic field at the center of a 63-turn circular coil with a radius of 18.1 cm is 70.165×10⁻⁵T

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