Halogenated compounds are particularly easy to identify by their mass spectra because chlorine and bromine occur naturally as mixtures of two abundant isotopes. Chlorine occurs as 35Cl (75.8%) and 37Cl (24.2%); Bromine occurs as 79Br (50.7%) and 81Br (49.3%); Boron compounds also stand out owing to the two isotopes 10B (19.9%) and 11B (80.1%). For the compound Bromomethane, CH3Br: At what masses do the molecular ions occur

Answer:

HfCl3

Explanation:

Step 1:  Find the compounds relative atomic mass

Step 2: Divide the percentage given by the relative atomic mass

Hf = 62.2/178.5         CI = 37.4/35.5

  Hf = .348                 CI = 1.054

Step 3: Divide every given number by its lowest ratio. (0.348)

Hf - .348/.348          CI - 1.054/.348

    Hf= 1                           CI = 3

This means, the empirical formula for this compound would end up being

HfCI3.

Hope this helps!

Answer:

0.436 ⇒ 0.44

9.000 ⇒ 9.0

Concept:

Significant figures are where each of the digits of a number are used to express it to the required degree of accuracy, starting from the first nonzero digit.

Therefore, in the context of this question, two significant figure means that two digits of numbers are kept, from left to right, starting from the first nonzero digit.

Solve:

0.436 has 3 significant digits in total starting from left to right

Thus, the last digit should be rounded up / down

Since the last digit is 6, it is greater than 5, so it should be rounded up.

Therefore, a rounded 0.436 is \(\Large\boxed{0.44}\)

9.000 has 4 significant digits in total starting from left to right

Thus, the last two digits should be rounded up / down

Since the last two digits are 0, it is less than 5, so it should be rounded up (or remained).

Therefore, a rounded 9.000 is \(\Large\boxed{9.0}\)

Hope this helps!! :)

Please let me know if you have any questions

To determine the universal gas constant (R), we can use the ideal gas law equation: PV = nRT, where P is the total pressure, V is the volume of gas, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.

Barometric pressure of the room: To find the barometric pressure in atm, we convert 766.86 mmHg to atm by dividing it by 760 mmHg/atm, giving us 1.0089 atm.Vapor pressure of water at room temperature (PH2O).The vapor pressure of water at 23.0°C is 0.0313 atm.

Mass difference of butane lighter:The mass difference is calculated by subtracting the initial mass (54.24 g) from the final mass (54.01 g), resulting in a difference of 0.23 g.

Moles of butane gas collected:To find the moles of butane gas, we can use the equation n = m/M, where n is the number of moles, m is the mass, and M is the molar mass of butane (58.12 g/mol). Thus, n = 0.23 g / 58.12 g/mol = 0.003959 mol.

Partial pressure of butane gas:The partial pressure of butane gas is calculated by multiplying the moles of butane gas (0.003959 mol) by the ideal gas constant (R) and the converted temperature (23.0°C + 273.15 K). Let's assume the converted temperature is 296.15 K.

Converted volume of gas collected:The volume of gas collected is given as 100.0 mL, which needs to be converted to liters by dividing it by 1000, resulting in 0.1 L.

Experimental value of R:The experimental value of R can be determined by rearranging the ideal gas law equation to solve for R: R = (P - PH2O) * V / (n * T).

Accepted value of R:The accepted value of R is 0.0821 Latm/molK.

The percent error can be calculated using the formula: (|Experimental value - Accepted value| / Accepted value) * 100.

Factors contributing to percent error could include experimental error in mass measurements, inaccurate temperature measurements, and loss of gas during collection or transfer.

If the gas had not been corrected for the partial pressure of water, the value of R would be lower because the partial pressure of water would contribute to the total pressure, resulting in a smaller value for P in the ideal gas law equation.

To increase accuracy and decrease percent error, the experiment could be repeated multiple times to obtain an average value, use more precise measuring instruments, conduct the experiment in a controlled environment, and ensure accurate calibration of equipment.

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A polarimeter fundamental working principle entails the following: By passing light via a polarizer, one can produce light with a precisely prepared linear polarisation state.

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The center of gravity is the same for all passenger vehicles no it is different

The center gravity is the point through which the force of gravity acts on an object or system then in the mechanics problem the gravitational field is assumed to be uniform and the center of gravity is then in exactly the same position as the center of mass and the the center of gravity is the same for all passenger vehicles no it is different because the thermotical point where the sum of all of the masses of each of its individual components effectively act and the center of gravity is low then the stability of vehicle and passenger are more

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Answer:

Metamorphic rocks are formed from pre-existing rock and sediment materials. They are formed when igneous, sedimentary, or other pre-existing metamorphic rocks are exposed to the heat and pressure as well as super-heated mineral-rich fluids. They are compacted together to form a new rock altogether. Metamorphism does not include the melting or liquefaction of the pre-existing rock. Instead, it compacts them and crushes them, pushing them together at extreme heat and pressure to form a new rock altogether composed of sedimentary, igneous, and other metamorphic rock. It's the rock hybrid of the geologic world.

Metamorphism is similar to when you squish playdough together, it doesn't form a new playdough color (unless you REALLY mixed that poor playdough together). It forms an amalgamation of different colors and patterns made from the other rock.

Taken from a paper I once wrote I explained this again:

"Metamorphic rocks are formed when pre-existing rocks and their minerals are compressed and altered by Earth’s internal processes; interior pressure, temperature (heat), and chemical reactions. The minerals and pre-existing rock necessary for the creation of metamorphic rock must then also be located deep underground if such processes are expected to make an impact and create a metamorphic rock."

Answer:

I used Chat GPT to answer the question here is the answer

Assuming the gas behaves ideally, the answer is (C) The average kinetic energy stays the same.

According to the ideal gas law, PV = nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the ideal gas constant, and T is temperature. If the temperature is held constant, then nR is also constant. Therefore, for a given amount of gas, if V increases, P must decrease (and vice versa) to maintain the same value of PV.

The average kinetic energy of gas molecules is proportional to temperature, so if the temperature is held constant, the average kinetic energy of the gas molecules stays the same. The changes in volume and pressure only affect the density and distribution of the gas molecules, but not their average kinetic energy.

How many grams of sodium chloride are there in 2.34 moles of sodium chloride (NaCl)?

To find the mass that we have in 2.34 moles of NaCl, we need the molar mass of NaCl. To get the molar mass of NaCl we have to look for the atomic mass of Na and Cl in the periodic table:

Na: 22.99 amu Cl: 35.45 amu

Using those values we can calculate the molar mass of NaCl:

molar mass of NaCl = 22.99 + 35.45

molar mass of NaCl = 58.44 g/mol

Now that we know the mass of 1 mol of NaCl, we can find the mass of NaCl that there are in 2.34 moles of it.

mass of NaCl = number of moles of NaCl * molar mass of NaCl

mass of NaCl = 2.34 moles * 58.44 g/mol

mass of NaCl = 136.75 g

Answer: There are 137 g of NaCl in 2.34 moles of it.

14.92 grams of hydrochloric acid are needed to react with 20.0 grams of iron (II) sulfide ore containing 10.0% inert material.

The balanced chemical equation for the reaction between iron (II) sulfide and hydrochloric acid:

FeS + 2HCl → FeCl₂ + H₂S

From the equation, we can see that 1 mole of FeS reacts with 2 moles of HCl. We can use this information to calculate the number of moles of HCl needed to react with 20.0 grams of FeS ore.

First, we need to calculate the mass of pure FeS in the sample of ore. Since the ore contains 10.0% inert material, we know that only 90.0% of the sample is pure FeS:

mass of pure FeS = 20.0 grams x 0.90 = 18.0 grams

The number of moles of FeS in the pure sample is:

molar mass of FeS = 55.85 + 32.06 = 87.91 g/mol

moles of FeS = 18.0 grams / 87.91 g/mol = 0.2047 moles

Since 1 mole of FeS reacts with 2 moles of HCl, we need twice as many moles of HCl as FeS to ensure that all of the FeS reacts:

moles of HCl = 2 x 0.2047 moles = 0.4094 moles

Finally, we can calculate the mass of HCl needed using the molar mass of HCl:

molar mass of HCl = 1.01 + 35.45 = 36.46 g/mol

mass of HCl = 0.4094 moles x 36.46 g/mol = 14.92 grams

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In the balanced equation \(2C_{2} H_{6}\) + \(7 O_{2}\) --> \(4 CO_{2}\) + \(6H_{2}O\) if 21 g of \(C_{2} H_{6}\) reacts with 32 g O₂, C₂H6 is the limiting reactant.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation.

Let's calculate the number of moles for each reactant using their molar masses:

For \(C_{2} H_{6}\) (ethane):

Molar mass of \(C_{2} H_{6}\) = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Number of moles of C₂H6 = 21 g / 30.07 g/mol ≈ 0.698 mol

For O₂ (oxygen):

Molar mass of O₂ = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O₂ = 32 g / 32.00 g/mol = 1.00 mol

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation:

2 moles of \(C_{2} H_{6}\) react with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O.

From the given amounts, we have:

0.698 mol \(C_{2} H_{6}\) and 1.00 mol O₂.

Using the stoichiometric ratio, we can calculate the expected amount of CO₂ and H₂O produced for each reactant:

For C₂H6:

Expected moles of CO₂ = 0.698 mol C₂H6 * (4 mol CO₂ / 2 mol C₂H6) = 1.396 mol CO₂

For O₂:

Expected moles of CO₂ = 1.00 mol O₂ * (4 mol CO₂ / 7 mol O₂) ≈ 0.571 mol CO₂

Comparing the expected moles, we see that the calculated amount of CO₂ is greater when used \(C_{2} H_{6}\) as the limiting reactant. Therefore, the limiting reactant in this reaction is \(C_{2} H_{6}\).

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The waves that  has the greatest wavelength is Wavelength shown with 1 wavelength stretched over a long distance.

A wave could be a disturbance or variety that voyages through a medium or space, carrying vitality without transporting matter. Waves can take different shapes and happen totally different sorts of waves, counting mechanical waves and electromagnetic waves.

Mechanical waves require a medium to propagate, meaning they require a substance like water, discuss, or a strong fabric to transmit the wave. Illustrations of mechanical waves incorporate water waves, sound waves, and seismic waves. In these waves, particles of the medium sway or vibrate in a design, exchanging energy from one molecule to another.

Electromagnetic waves, on the other hand, don't require a medium and can travel through vacuum, such as in space. Electromagnetic waves comprise of electric and attractive areas swaying opposite to each other and to the heading of wave engendering. Illustrations of electromagnetic waves incorporate obvious light, radio waves, microwaves, infrared waves, bright waves, X-rays, and gamma beams.

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Answer:

4.25 g of magnesium.

Explanation:

What is given?

moles of Na2CO3 = 0.0877 moles.

molar mass of Mg (magnesium) = 24.3 g/mol.

Step-by-step solution:

First, let's state the chemical equation between Mg (magnesium) and Na2CO3:

You can see that 1 mol of Na2CO3 reacts with 2 moles of Mg, so let's see how many moles of Mg are being produced by 0.0877 moles of Na2CO3:

And the final step is to convert from 0.175 moles of Mg to grams using its molar mass. The conversion will look like this:

The answer is that there is 4.25 g of magnesium dissolved in the solution of 0.0877 moles of Na2CO.

Helen takes 35 nights to knit a total of 175 centimeters of scarf. Hence, she will take 36 nights to knit 180 centimeters of scarf.

Length is a basic measurement in for an object which is basically taken in meters or centimeters. The basic unit of length in American standard is meters (m) and in CGS system it is centimeters.

It is given that, Helen knit a total of 175 centimeters of a scarf over 35 nights. Then, the length she knit in one nigh is calculated as:

175/35 = 5 cm.

Therefore, the number of nights required to complete 180 cm is :

180 /5 = 36

Thus, she will take 36 nights to knit a total of 180 cm of scarf.

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Answer: The pressure in the container is 1949.5 torr when the volume is 7.20 liters and the temperature is 71.0 °C

Explanation: To solve this problem, we can use the combined gas law, which relates the initial and final conditions of pressure (P), volume (V), and temperature (T) for an ideal gas:

(P1 × V1) / T1 = (P2 × V2) / T2

where P1, V1, and T1 are the initial pressure, volume, and temperature, and P2, V2, and T2 are the final pressure, volume, and temperature.

We can plug in the given values:

P1 = 740.5 torr

V1 = 10.8 L

T1 = 23.0 °C + 273.15 = 296.15 K

V2 = 7.20 L

T2 = 71.0 °C + 273.15 = 344.15 K

(P1 × V1) / T1 = (P2 × V2) / T2

(740.5 torr × 10.8 L) / 296.15 K = (P2 × 7.20 L) / 344.15 K

Solving for P2:

P2 = (740.5 torr × 10.8 L × 344.15 K) / (296.15 K × 7.20 L)

P2 = 1949.5 torr

Therefore, the pressure in the container is 1949.5 torr when the volume is 7.20 liters and the temperature is 71.0 °C.

The volume of air you might inhale (and exhale) in 8.00 hours is approximately 1903.2 liters.

To calculate the volume of air you might inhale (and exhale) in 8.00 hours, we need to determine the total number of breaths you take in that time and then multiply it by the volume of each breath.

First, let's calculate the number of breaths in 8.00 hours:

Number of breaths per minute = 13

Number of breaths per hour = 13 breaths/minute * 60 minutes/hour = 780 breaths/hour

Number of breaths in 8.00 hours = 780 breaths/hour * 8.00 hours = 6240 breaths

Now, let's calculate the volume of air in liters:

Volume of each breath = 0.305 liters

Volume of air inhaled and exhaled in 8.00 hours = Volume of each breath * Number of breaths in 8.00 hours

Volume of air inhaled and exhaled in 8.00 hours = 0.305 liters/breath * 6240 breaths = 1903.2 liters

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The scientist needs to create 45 soil mixtures in order to test all possible combinations of the 10 soil types. Option B.

To calculate the number of unique soil mixtures, we can use the formula for the number of combinations of n objects taken k at a time, which is given by:

C(n,k) = n! / (k! * (n-k)!)

In this case, we have 10 soil types and we want to take 2 at a time to create unique mixtures. Thus, we substitute n=10 and k=2:

C(10,2) = 10! / (2! * (10-2)!)

= 10! / (2! * 8!)

= (10 x 9) / 2

= 45

In other words, the scientist needs to create 45 soil mixtures in order to test all possible combinations of the 10 soil types.

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Answer:

The three major differences are: atmosphere (vacuum in space), radiation (high level of dangerous particles), and gravity (weightlessness in space). The first difference between the Earth and space is the atmosphere.Jan

The only significant differences from living on Earth are that they operate in the confined space of the Space Shuttle orbiter cabin and that they, and all objects inside the cabin, float.

Explanation:

mark branliest

Answer: Atoms are the smallest particles of an element.

A solution contains 43 mEq/L of CI and 11 mEg/L of HPO,2-. The Na concentration in mEq/L is 54 mEg/L. The correct option is d.

A solution is a mixture of a solute and solvent.

The solution contains only Na+ cation.

The anions are Cl- and HPO₄²⁻

The equivalent of ion = number of moles x valence

So, the solution will contain 43 mEq/L of Cl- and 11 mEq/L of HPO₄²⁻

The total mEq of anions in the solution = 43 mEq/L + 11 mEq/L = 54 mEq/L

we know, mEq of anions in the solution neutralize by mEq of cations in the solution

The number of mEq anions = the number of mEq cations. The solution contains 54 mEq of cations, i.e. 54 mEq/L of Na+ concentration.

Thus, the Na concentration in mEq/L is 54 mEg/L. The correct option is d.

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Answer: 291.3 g of CaCl2 would be necessary to prepare the solution given. The best option to answer the question is the last one (letter E, 291 g)

Explanation:

The question reuquires us to determine the mass of CaCl2 necessary to prepare 0.00175× 10^6 mL of a 1.50 M solution.

We can use the following equation, which corresponds to the definition of molarity, to calculate the number of moles of CaCl2 necessary to prepare the solution:

Where M is the molarity of the solution (given in mol/L or M), n is the number of moles of solute (in mol) and V is the volume of solution (in L).

Note that we'll need to convert the volume given (0.00175× 10^6 mL) from mL to L:

Next, we can rearrange the equation for molarity in order to calculate the number of moles of CaCl2:

And, applying the values given by the question:

Therefore, 2.62 moles of CaCl2 would be necessary to prepare the solution.

We can use the following equation to convert the number of moles calculated (2.62 mol) to the mass required, considering the molar mass of CaCl2 given (MM = 110.98 g/mol):

Where n corresponds to the number of moles (in mol), m is the mass of the sample (in grams) and MM corresponds to the molar mass of the compound (in g/mol).

Applying the molarity given by the question and the number of moles calculated, we'll have:

Therefore, 291.3 g of CaCl2 would be necessary to prepare the solution given. The best option to answer the question is the last one (letter E, 291 g).

Answer:Favorable

Explanation:um I know That it is Favorable sorry!

Answer

At the crust

Explanation:

Mantle is far away from it unless its in a ocean.

Answer:

A mountain would form on the continental crust

Explanation:

Typically, a convergent plate boundary—such as the one between the Indian Plate and the Eurasian Plate—forms towering mountain ranges, like the Himalaya, as Earth’s crust is crumpled and pushed upward.

Answer:

f = 0.534×10⁻² Hz

Explanation:

Given data:

Frequency of wave= ?

Wavelength of wave = 5.62×10¹⁰ m

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3×10¹⁷ nm/s

λ  = 5.62×10¹⁰m×10⁹  nm/1 m = 5.62×10¹⁹ nm

Now we will put the values in formula.

3×10¹⁷ nm/s = 5.62×10¹⁹ nm ×  f

f = 3×10¹⁷ nm/s  / 5.62×10¹⁹ nm

f = 0.534×10⁻² s⁻¹   or

f = 0.534×10⁻² Hz

Answer: what?

Explanation:

Answer: Huh?

Explanation:

Answer:

\(\boxed {\boxed {\sf 2 K + Cl_2 \rightarrow 2KCl}}\)

Explanation:

The law of conservation of mass states that mass cannot be created or destroyed. The mass of the reactants must equal the mass of the products. Basically, the number of atoms at the beginning is the same as the end.

Count up the atoms on the left and right sides of the arrow. Remember to account for coefficients and subscripts.

1. 2Fe+3O₂⇒Fe₂O₃

Right: 2Fe + 3O₂

Left: Fe₂O₃

2. 2H₂+ O₂ ⇒ 2H₂O₂

Right: 2H₂+O₂

Left: 2H₂O₂

3. 2K+Cl₂⇒ 2KCl

Right: 2K + Cl₂

Left: 2KCl

4. C+O₂ ⇒ 2CO

Right: C+O₂

Left: 2CO

The only balanced equation that follows the conservation of mass is choice 3: 2K+Cl₂ ⇒2KCl

Answer:

6598 mL = 6598 cm^3

Explanation:

Cubic centimeters (cc) and milliliters (mL) are both units of volume measurement. They are equivalent, meaning that 1 mL is equal to 1 cm^3. To convert from mL to cm^3, we simply multiply the volume in mL by 1.

To convert 6598 mL to cubic centimeters, we can use this conversion factor:

1 mL = 1 cm^3

Therefore, we can multiply 6598 mL by 1 to get the equivalent volume in cubic centimeters.

6598 mL x 1 cm^3/mL = 6598 cm^3

So, 6598 mL is equal to 6598 cm^3.

Answer:

Explanation:

1.one atom pulls an electron from another atom

2. Forming bonds releases energy and is exothermic

3.pull electrons away from other elements

4.additional bonds require more energy to break, so the bond energy is higher

5. -153

As  Bond energy is between carbon and oxygen the is 358 for a single bond of C-0 and 745 for a double bond is the  c=0.

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Answer:

8

Explanation:

The solubility of a substance, such as sugar, depends on several factors, including temperature, pressure, and the presence of other solutes. In this case, the student adds the same amount of sugar and tea bag to the same amount of hot water every day, but the temperature of the water could vary from day to day, affecting how much sugar dissolves.

According to the graph, the least amount of sugar dissolved on day 3, while the most sugar dissolved on day 5. The difference in temperature on these days could explain this variation. On day 3, the water may have been cooler, making it more difficult for the sugar to dissolve. On the other hand, on day 5, the water may have been hotter, which could have increased the solubility of the sugar.

To increase the amount of sugar that dissolves in the tea, the student could try using hotter water or stirring the sugar more vigorously to distribute it evenly throughout the water. Alternatively, the student could try adding the sugar gradually while stirring to give it more time to dissolve before adding more.

Answer:

I'm not 100% sure on this because mine hasn't been graded yet, but here are the answers I submitted.

Explanation:

Which day the least sugar dissolved and which day the most sugar dissolved:

Day 4 is when the least sugar dissolved, and Day 2 is when the most sugar dissolved.

What could have caused less sugar to dissolve on some days:

The temperature of the tea could have caused the sugar not to dissolve on some days.

What the student could do to his drink to make more sugar dissolve.

The student would need to add the sugar to the tea as soon as it's done boiling.  The Sugar will dissolve faster in a warmer tea due to more energy of movement.  

Be sure to stir the tea as you add the sugar.  Stirring the sugar into the tea speeds up the rate of dissolving by helping distribute the sugar particles throughout the tea.  

If the student were to use granulated sugar, those are smaller particles and have greater surface area.  Greater surface area allows for more contact between the tea and the sugar.