Answers
Answer:
the force acting on the car is 3600 N
Explanation:
The computation of the force acting on the car is shown below:
As we know that
Force = mass × acceleration
= 1200 kg × 3.0 ms/^2
= 3600 N
hence, the force acting on the car is 3600 N
Related Questions
The velocity time graph of an object mass 50 g is shown in figure study graph and answer
1)calculate force acting on object in time interval 0-3 seconds
2)calculate the force acting on the object in the time interval 6-10 seconds
3)Is there any time interval in which no force acts on object.Justify
Answers
1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.
2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.
3) There is no time interval in which no force acts on the object.
(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.
In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.
Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2
Acceleration, a = slope= 20/3 m/s^2
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.
Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.
(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.
The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:
Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)
Mass of the object, m = 50 g = 0.05 kg
∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.
Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.
(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.
Therefore, there is no time interval in which no force acts on the object.
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What is the density of a sample of charcoal with a mass of 3.0 g and a volume of 10 cm³?
A. 0.3 g/cm³
B. 3.3 g/cm³
C. 7 g/cm³
D. 30 g/cm³
Answers
The carbon has a mass of 3.0 g and a volume of 10 cm³. So we will calculate the density. The formula to calculate its density is:
d = m/v
We substitute the data in the formula and solve:
d = 3.0 g/10 cm³
d = 0.3 g/cm³
Therefore the density of the carbon sample is 0.3 g/cm³. Opction "A".
Skandar
Consider a converging lens with focal length 9.56 cm. The distance between an object and
a real image of the object created by the lens is 59.6 cm. Find the distance between the
object and the lens if the lens is closer to the object than it is to the image. Answer in cm
Answers
The object's distance from the lens is 11.4 cm.
Calculation-The thin lens equation can be used to determine how a converging lens's object distance (p), image distance (q), and focal length (f) relate to one another:
1/p + 1/q = 1/f
where p denotes the distance to the object, q is the distance to the picture, and f is the focal length.
Let's solve for the object distance using the thin lens equation:
1/p + 1/59.6 = 1/9.56
Combining both sides with p59.69.56 results in:
59.69.56 + p9.56 = p*59.6
Adding and subtracting:
570.176 + 9.56p = 59.6p
50.04p = 570.176
p = 11.4 cm
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A small homemade electromagnet has a lifting force of 3.6 N. If the current through the coil is doubled and the number of loops is tripled, what will the lifting force become?
Answers
We will determmine the lifting force as follows:
\(F=\frac{NI\mu}{L}\)Now, using tthe equation for the magnetic force we will have the following scenario:
\(F=\frac{3N\cdot2I\mu}{L}\Rightarrow F=6\cdot\frac{NI\mu}{L}\)\(\Rightarrow F=3.6\cdot6\Rightarrow F=21.6\)Thus:
\(F\approx22\)So, the lifting force will be exactñy 21.6N, that is approximately 22N.
Quantum mechanics is used to describe the vibrational motion of molecules, but analysis using classical physics gives some useful insight. In a classical model the vibrational motion can be treated as SHM of the atoms connected by a spring. The two atoms in a diatomic molecule vibrate about their center of mass, but in the molecule HIHI, where one atom is much more massive than the other, we can treat the hydrogen atom as oscillating in SHM while the iodine atom remains at rest.
Part A
A classical estimate of the vibrational frequency is f = 7.0 x 1015 Hz. The mass of a hydrogen atom differs little from the mass of a proton. If the HI molecule is modeled as two atoms connected by a spring, what is the force constant of the spring? Express your answer to two significant figures and include the appropriate units. k= 320 N
Part B
The vibrational energy of the molecule is measured to be about 5 x 10-20 J. In the classical model, what is the maximum speed of the H atom during its SHM? Express your answer to one significant figure and include the appropriate units. v = 8000
Part C
What is the amplitude of the vibrational motion? Express your answer to one significant figure and include the appropriate units. • Ea ? I HÀ A = 3.4.1018 • • m
Part D
How does your result compare to the equilibrium distance between the two atoms in the HI molecule, which is about 1.6 x 10-10 m? Express your answer using one significant figure. IVO AQ R O 2 ? equilibrium distance = 2.25 • 10-2
Answers
Answer:
o my god how big is the question
There are two space ships traveling next to each other. The first one is 500
Kg and the second one is 498 Kg. Since they are 35 meters apart, what is
the force of gravity between the two space ships?
Answers
This question involves the concept of Newton's law of gravitation.
The force of gravity between the two spaceships is "1355.78 N".
Newton's Law Of GravitationAccording to Newton's Law of Gravitation:
\(F=\frac{Gm_1m_2}{r^2}\)
where,
F = force of gravity between ships = ?G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²m₁ = mass of first ship = 500 kgm₂ = mass of second ship = 498 kgr = distance between ships = 35 mTherefore,
\(F=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(500\ kg)(498\ kg)}{(35\ m)^2}\\\\\)
F = 1355.78 N = 1.356 KN
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Two space ships traveling next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.
It is given that the First spaceship's weight (\(m_{1}\)) is 500 kg,
The second spaceship's weight (\(\rm m_{2}\)) is 498 kg.
The distance between spaceships (r) is 35 meters.
It is required to find the Force of gravity between these spaceships.
What is Gravitational force?It is defined as the force which attracts any two masses in the universe.
By Newton's law of Gravitation:
\(\rm F= \frac{Gm_1m_2}{r^2}\) , Where
\(\rm F = The\ force \ of \ gravity \ between \ the \ spaceships\\\rm G= Universal\ Gravitational \ Constant = 6.67 \times 10^{-11} N.m^2/kg^2\)
Putting values in the above formula:
\(\rm F = \frac{(6.67\times 10^{-11} N.m^2/kg^2)(500kg)(498kg)}{(35m)^2}\)
F = 1355.78 N = 1.356 KN
Thus, Two spaceships travel next to each other. The first one is 500 kg and the second one is 498 kg. They are 35 meters apart, the Force of gravity between the two spaceships is 1355.78 N.
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Which image best illustrates diffraction?
Answers
Answer:
The answer is A the photo of the sun
Explanation:
A 6 kg blue ball rolls across the ground and collides with a stationary 1 kg red ball.
Before the collision the blue ball moved right with a speed of 4 m/s, and after the
collision it moved left with a speed of 1 m/s. If the red ball was not moving before the
collision, how fast is it moving after the collision?
Answers
The final velocity of the red ball is 18 m/s.
What is momentum?The term momentum has to do with the product of the mass and the velocity of an object We know that the momentum is always conserved in accordance with the Newton third law. Also it is clear that the momentum before collision is equal to the total momentum after collision and we are going to apply this principle here.
Then;
Mass of the blue ball = 6 kg
Mass of the red ball = 1 kg
Initial velocity of the blue ball = 4 m/s
Initial velocity of the red ball = 0 m/s
Final velocity of the red ball = ??
Final velocity of the blue ball = 1 m/s
We now have;
(6 * 4) + (1 * 0) = (1 * v) + (6 * 1)
24 = v + 6
v = 24 - 6
v = 18 m/s
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A 75-W light source consumes 75 W of electrical power. Assume all this energy goes into emitted light of wavelength 600 nm. (a) Calculate the frequency of the emitted light. (b) How many photons per second does the source emit? (c) Are the answers to parts (a) and (b) the same? Is the frequency of the light the same thing as the number of photons emitted per second? Explain.
Answers
If we rearrange the circuit so that the inductor and capacitor were connected in series,the impedance would be Decreased and the resonant frequency would be unchanged.
What is frequency?Frequency is the rate at which something occurs over a particular period of time or in a given sample.
Sol-An LC circuit is made up of an inductor (L) and a capacitor (C). At the resonance condition of the LC circuit, the inductive reactance XL. becomes equal to the capacitive reactance Xc.
It is defined as-
XL= 2πfL
Xc= 1/2πfC
So when reactances are equal we have-
XL=Xc
2πfL= 1/2πfC
f^2=1/4π^2LC
f=1/2π√LC
The resonance condition is the same for both the parallel and series LC circuit, so the resonance frequency will not change.
The impedance of a parallel LC circuit is:
Z(w)= jL w^2-w^2•/w
In a series LC circuit, when w
, the impedance becomes equal to 0.
Therefore the impedance of a series LC circuit will decrease and the resonant frequency will remain the same.
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Any magnet has two ends, each one called a(n)
Answers
Problem B.2: Escaping a Star (6 Points) It takes many years for a photon produced in a star's centre to reach its surface and escape into space. This is due to its constant interaction with other particles. To estimate the time it takes for a photon to escape a star's interior, we assume that the photon is deflected in equal time intervals into a random direction in a two-dimensional space (i.e., a random walk): At each step i, the photon moves a constant distance in an angle, thus changing its position: cos(4) sin(y) Ai, - c (a) Determine the distance R(n) from the centre (0,0) after n steps.
Answers
Answer:
This problem involves the concept of a random walk, which is a mathematical model of a path consisting of a succession of random steps.
The question asks for the distance, R(n), from the center of a star after n steps of a photon, assuming a 2D random walk.
The random walk in two dimensions has a step length of A_i and the direction of the steps is uniformly distributed in [0, 2π). The change in position after each step can be written in Cartesian coordinates (Δx, Δy), where Δx = A_i cos(θ_i) and Δy = A_i sin(θ_i).
The displacement from the center after n steps is given by the vector sum of all the individual steps. This vector sum can be written in terms of its Cartesian coordinates, (X, Y), where X = Σ Δx and Y = Σ Δy. This sum over n random vectors is itself a random variable. The net displacement R(n) from the center of the star after n steps is given by the magnitude of the net displacement vector:
R(n) = √(X² + Y²)
Because each step is independent and has a random direction, the expected value of the cosine and sine for any step is zero. This means that the expected values of X and Y are both zero.
However, the mean square displacement is not zero. Because the steps are independent, the mean square displacement in each direction is additive. For a 2D random walk:
<X²> = Σ <(Δx)²> = n <(A cos θ)²> = n A²/2
<Y²> = Σ <(Δy)²> = n <(A sin θ)²> = n A²/2
Because <X²> = <Y²>, we can write:
<R²> = <X²> + <Y²> = n A²
So, the root mean square distance (the square root of the mean square displacement) after n steps is:
R(n) = √(<R²>) = √(n) * A
Therefore, the distance R(n) that the photon is expected to be from the center of the star after n steps grows as the square root of the number of steps, with each step having a length A. Please note that this result holds for a 2D random walk. A real photon in a star would be performing a 3D random walk, which would have slightly different characteristics.
If you can run 10.43 m in 14.22 s. How fast are you running?
Answers
Answer:
I am 15th in my state for 55m hurdles with a time of 10.4 seconds
Explanation:
BAM
Answer: 44 m per minute
Explanation:
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
Answers
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Two objects are dropped from a bridge, an interval of 1.0 s apart, and experience no appreciable air resistance. As time progresses, the DIFFERENCE in their speeds
a.
increases.
b.
remains constant.
c.
decreases.
d.
increases at first, but then stays constant.
e.
decreases at first, but then stays constant.
Answers
Answer: a
Explanation:
Question 3 of 10
What is the primary means by which heat is transferred through fluids?
O A. Direct contact of particles
OB. Radiation
OC. Electromagnetic waves
OD. Convection currents
Answers
The primary means by which heat is transferred through fluids is convection currents (option D).
What is convection current?Convection is the transmission of heat in a fluid by the circulation of currents.
Heat can be transferred by different methods depending on the medium. Fluids like gases and liquids transfer heat through the process of convection.
Therefore, the primary means by which heat is transferred through fluids is convection currents.
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What force has to be overcome in order for your balloon car to start to move? Once it is moving and all the air is expelled why does your car keep moving? What causes it to stop?
Answers
It has to overcome friction and air resistance in order for your balloon car to start to move
What is a balloon car?
For balloon-powered car, the contracting balloon pushes the air in the balloon backwards. That means the air in the balloon is pushing balloon forwards. The balloon is joined to car, so the car rolls. The motion is nothing to do with pushing on the air behind car.
There are two main forces acting on balloon rocket car: Friction and Air resistance. The friction force is resistance between two objects sliding against each other. While building your car identify places where objects will be rubbing against each other creating friction. In order to get car to move, we need an unbalanced force. In other words, the force of air coming out of balloon must overcome the forces acting on the car. We will want to reduce friction and air resistance to help your car move.In the case of balloon car, the action is the air rushing out of the balloon, pushing against air behind the car. The opposite or equal reaction is that the air behind car pushing against the car with the same force, causing the car to propel forwards.The weight of car is too great and nothing moves: As the car weight increases, friction between axle and straw, wheel and axle, and wheel and floor increase. There comes a point where the forces from friction are greater than the force from air blowing out the balloon.Learn more about balloon car at https://brainly.com/question/13293570
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You're 6.0 m from one wall of a house. You want to toss a ball to your friend who is 6.0 m from the opposite wall. The throw and catch each occur 1.0 m above the ground.(Figure 1) Assume the overhang of the roof is negligible, so that you may assume the edge of the roof is 6.0 m from you and 6.0 m from your friend.
What minimum speed will allow the ball to clear the roof?
At what angle should you toss the ball?
Please explain for 5stars
Answers
The ball needs to go at least speed is 13 m/s per second to be able to clear the ceiling.
angle should you toss the ball 46.26°.
From the query, we learn that
We are 6.0 metres away from one home wall.
who is 6.0 metres from the wall across from you.
Both the throw and the catch take place one metre above the ground.
Assume that you and your companion are both 6.0 metres from the edge of the roof.
The Newtons equation for the distance is typically expressed numerically as
\(s=v*t+\frac{a}{2}*t^{2}\\5=0*t+4.9*t^{2}\\t=1.04\)
Therefore
\(2*t = 2.0s\)
Where
\(18=V_{x} *2.0\\V_{x} =8.9\)
And
\(5=V_{y} *1.04-4.9*1.04^{2}\\V_{y} =9.8\)
Therefore
\(V=\sqrt{V_{y}^{2}+V_{x} ^{2} } \\V=\sqrt{(9.8)^{2}+(8.9)^{2}} \\\V=13m/s\)
In order to determine the angle at which you should toss the ball, you must first calculate the distance between you and your friend. This is done by using the Pythagorean Theorem to calculate the hypotenuse of the right triangle formed by the two walls and the distance between you and your friend:
\(C = \sqrt (6.0m)^2 + (6.0m)^2 \\ = 8.485m\)
Now you can calculate the angle using trigonometry. Since the triangle is a right triangle, you can use the inverse tangent function to calculate the angle:
tan⁻¹\((\frac{6.0m}{8.485m})\) = 46.26°
Therefore, you should toss the ball at an angle of 46.26°.
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Lower frequencies (red) move _____ in a glass prism than higher frequencies.
Answers
Lower frequencies (red) move faster in a glass prism than higher frequencies.
Light of all colors moves at the same speed in a vacuum. However, light travels at different speeds in many media, including water.
Red light moves through glass at the fastest speed, whereas violet light moves at the slowest speed.
Red light bends the least of all the colors because it moves at the fastest speed, whereas violet light moves at the slowest speed and bends the most.
Wavelength and speed are directly proportional. Speed also rises with increasing wavelength. Light that has a maximal wavelength therefore moves at its fastest.
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15)
The Celsius temperature equal to 86° Fahrenheit is:
T(F) = 9/5T(C) + 32
T(C) = 5/9 ( T(F) - 32)
A)
16°C
B)
30°C
C)
212°C
D)
190°C
Answers
Answer:
letter b
Explanation:
30 degrees Celsius equals 86 degrees Fahrenheit add me plesse mark brainiest
what can you infer from the statement, velocity is an object is zero?
Answers
Explanation:
a.Object is in linear motion with constant velocity.
b.Object is moving at a constant speed.
c.Object is either at rest or it returns to the initial point.
d.Object is moving in a straight line without changing its direction.
hope it helps you
HI PLEASE HELP ON QUESTION ASAP I ALREADY KNOW ANSWER =75 IF ANSWER IS CORRECT, ILL RATE YOU FIVE STARS, A THANKS AND MAYBE EVEN BRAINLIEST!
BUT how do i work it out in an exam so exam marker knows what your doing
2)the mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. What is the number that was removed?
Answers
The mean of 6 numbers is 25. If one of the remaining numbers is removed, the average of the remaining numbers is 15. The number that was removed is 75.
To solve this problem, we can use the concept of the mean (average) and apply it to the given information. Let's go through the steps to determine the number that was removed.
Step 1: Find the sum of the 6 numbers.
Since the mean of the 6 numbers is 25, we can multiply the mean by the total number of values to find the sum. In this case, 25 * 6 = 150.
Step 2: Find the sum of the remaining numbers.
To find the sum of the remaining numbers, we need to subtract the number that was removed from the original sum. Let's denote the number that was removed as "x". Therefore, the sum of the remaining numbers is 150 - x.
Step 3: Determine the number of remaining numbers.
Since one number was removed, the total number of remaining numbers is 6 - 1 = 5.
Step 4: Calculate the average of the remaining numbers.
We are given that the average of the remaining numbers is 15. To find the sum of the remaining numbers, we can multiply the average by the number of remaining numbers. Therefore, 15 * 5 = 75.
Step 5: Set up the equation and solve for the removed number.
Now we can set up the equation using the information from Steps 2 and 4. We have the equation: 150 - x = 75.
Step 6: Solve the equation.
To find the value of x, we can solve the equation. Subtracting 75 from both sides gives us 150 - 75 = x, which simplifies to x = 75.
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Which physical law most directly describes the motions of objects that are acted on by forces?
A.
Newton's law of universal gravitation
B.
Newton's second law of motion
C.
Coulomb's law of electrostatic interaction
D.
the conservation of mass law
Answers
Answer: Newton's second law of motion
Explanation:
The work-energy theorem states that the change in the kinetic energy of an object is equal to what?
Answers
The work-energy theorem states that the change in the kinetic energy of an object will be equal to the net work done on the object.
Mathematically, it can be expressed as;
ΔKE = W
Where; ΔKE represents the change in kinetic energy of the object,
W represents the net work done on the object.
This theorem states that when work is done on an object, it results in a change in its kinetic energy. If work is done on an object, its kinetic energy increases, and if work is done by an object, its kinetic energy decreases.
This theorem is a fundamental principle in physics that relates the concepts of work and energy, and it is often used to analyze the motion and behavior of objects in various physical systems.
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A cap 6.000 cm in diameter plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure. The container is submerged to a depth of 10.00 ft in water. Assume the plug is planar and the pressure over the container is equalized. The force needed to remove the plug is closest to?
Answers
The force needed to remove the plug that is 6.000 cm in diameter which plugs an opening in a spherical container 1.000 m in diameter at atmospheric pressure is 85 N
P = F / A
P = ρ g h
P = Pressure
F = Force
A = Area
ρ = Density
g = Acceleration due to gravity
h = Height
ρ = 1000 kg / m³
g = 9.8 m / s²
h = 10 ft = 3.048 m
A = π r²
d = 6 cm = 0.06 m
r = d / 2 = 0.06 / 2
r = 0.03 m
A = 3.14 * 0.03 * 0.03
A = 0.002826 m²
Equating both formulae of P,
F / A = ρ g h
F = 1000 * 9.8 * 3.048 * 0.002826
F = 85 N
Therefore, the force needed to remove the plug is closest to 85 N
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Which is the correct representation of the right-hand rule for a current flowing to the right?
Answers
Answer:
The third image
Explanation:
The one with the thumb pointing to the right
Answer:
3, correct on Edge 2020
if the Periodic time of an oscillating object Triples then its frequency will?
Answers
Answer:
it would decrease
Explanation:
f=1/T
Cecelia dropped a ball from a height of 2 m. The ball fell in a straight path down to the ground.
According to Newton’s universal law of gravitation, which would change the path of the ball so it traces out the widest curved path possible?
tossing it horizontally at a slower speed
tossing it horizontally at a faster speed
dropping it from a shorter distance
dropping it from a greater distance
Answers
4. Answer the following questions in terms of a wave's frequency, wavelength, amplitude, and
energy.
a. Describe the characteristics of a high pitch wave.
b. Describe the characteristics of a high-volume wave.
Answers
a. A high-pitch wave is characterized by a high frequency and a short wavelength. The frequency determines the pitch of the sound, with higher frequencies corresponding to higher pitches.
The wavelength is the distance between two consecutive peaks or troughs of the wave and is inversely proportional to the frequency. Therefore, a high-pitch wave has a shorter wavelength.
The amplitude of the wave, which is the height of the peak or the depth of the trough, is not directly related to the pitch of the sound, but it does determine the volume or intensity of the sound.
b. A high-volume wave is characterized by a high amplitude and a relatively long wavelength. The amplitude determines the volume or intensity of the sound, with higher amplitudes corresponding to louder sounds.
The wavelength of the wave does not directly affect the volume of the sound, but it can affect how the sound is perceived in different environments.
In general, longer wavelengths are more effective at traveling through obstacles such as walls and are better at penetrating long distances, whereas shorter wavelengths are more easily scattered and attenuated in the atmosphere.
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When does acceleration due to gravity equal 9.8 m/s downward?
Select one:
a. always
b. when an object has been dropped downward
c. when an object has been thrown upward
d. at the peak of a thrown object's flight
Answers
Answer:
b
Explanation:
i took the quiz i think its right
Find the focal length of a concave mirror that produces four times larger real image of an object held at 5cm from the mirror.
Answers
Answer:
6.67 cm
Explanation:
Given
h (image) = 4 x h (object)Finding magnification
m = h (image) / h (object)m = 4 x h (object) / h (object)m = + 4.0Finding image distance
m = - (image distance / object distance)4 = - (v / 5)4 = -v/5v = -20v = -20 cmMirror formula
1/f = 1/v + 1/uSolving
1/f = 1/-20 + 1/51/f = -1 + 4/201/f = 3/20f = 20/3 cmf = 6.67 cm