Find the volume of each composite figure to the nearest whole number.
The volume of the composite figure in this problem is given as follows:
76 ft³.
How to obtain the volume of a rectangular prism?The volume of a rectangular prism, with dimensions defined as length, width and height, is given by the multiplication of these three defined dimensions, according to the equation presented as follows:
Volume = length x width x height.
The figure in this problem is composed by two prisms, with dimensions given as follows:
2 ft, 6 ft and 3 ft.2 ft, 4 ft and 8 - 3 = 5 ft.Hence the volume is given as follows:
2 x 6 x 3 + 2 x 4 x 5 = 76 ft³.
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Help!!! I will reward lots of points! QUESTION: At Walmart, 6 apples and 5 oranges cost $11. At Publix, 2 apples and 3 oranges cost $7. Set up a system of two equations which you will solve to find the cost of one apple and one orange. Also step by step
Answer: I do not think this problem is solvable; the cost of apples and oranges at the stores are different
maura runs 5 miles in 1.25 hours ava runs 3 miles in 50 minuets or 0.83 hours who runs faster
Answer:
Maura is the one who runs faster.
Step-by-step explanation:
Maura: 1.25 / 5 = .25 miles a minute
Ava: 0.83 / 3 = .276 or .28
Answer:
Maura runs faster
Step-by-step explanation:
Pls give brainliest im almost lvled up. :) Thx
2. A bag contains 28 colored marbles. There are 5 blue marbles, 9 red marbles, 11 yellow marbles, and 3 clear marbles. What is the ratio of red marbles to yellow marbles?
find a polynomial of degree 4 that has integer coefficients and zeros 3i and 4 multiplicity 2
Answer:
f(x) = x⁴ - 8x³ + 25x² - 72x + 144
Step-by-step explanation:
f(x) = (x-4)²(x+3i)(x-3i)
= (x²-8x+16)(x²+9)
= x⁴ - 8x³ + 25x² - 72x + 144
In recent years, Sheffield Transportation purchased three used buses. Because of the frequent turnover in the accounting department, a different accountant was in charge of selecting the depreciation method for each bus, and various methods have been used. Information concerning the buses is summarized in the table below. Bus 1, Bus 2, Bus 3, For the declining-balance method, the company uses the declining method rate. For units-of-activity method, total miles are expected to be 125,000. Actual miles of use in the first 3 years were 2021, 27,000; 2022, 35,000; and 2023, 33,000.
(a1) For Bus #3, calculate depreciation expense per mile under units-of-activity method.
Under the units-of-activity method, the depreciation expense per mile for Bus #3 is $0.4616.
How is the depreciation expense per mile determined?The units-of-activity method is one of the depreciation methods in use.
Under the units-of-activity method, the depreciation expense per unit is determined by dividing the depreciable amount by the total units of activity.
The depreciation amount (the value of the asset subject to depreciation) is the net of the total cost less the salvage value.
Depreciable amount of Bus #3 = $57,700 ($66,500 - $8,800)
Expected total miles for Bus #3 = 125,000
Depreciation expense per mile for Bus #3 = $0.4616 ($57,700 ÷ 125,000)
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Question Completion:Bus Acquired Cost Salvage Useful Life Depreciation
Value in Years Method
1 1/1/12 $99,100 $7,900 4 Straight-line
2 1/1/12 128,000 11,000 4 Declining- balance
3 1/1/13 66,350 8,800 5 Unit-of-activity
Which multiplication sentences equal to the division sentence?
Answer:
the second option (middle)
Step-by-step explanation:
NO LINKS!! URGENT HELP PLEASE!!!
1. Find an exponential function of the form f(x) = ba^-1 + c that has the given horizontal asymptote and y-intercept and passes through P
y = 33; y-intercept 408; P(2, 93)
Answer:
\(\bold{f(x) = 375(2.5)^{-x}+ 33}\)
Step-by-step explanation:
An exponential function of form f(x) = ba^(-x) + c has a horizontal asymptote of y = c as x approaches infinity, and a y-intercept of (0, b + c). We can use the given information to set up a system of equations and solve for the unknowns.
The horizontal asymptote is given as y = 33, so we have:
c = 33
The y-intercept is given as (0, 408), so we have:
b + c = 408
Substituting c = 33, we get:
b + 33 = 408
b = 375
So the function we're looking for is of the form:
\(\bold{f(x) = 375a^{-x}+ 33}\)
To find a, we use the fact that the function passes through P(2, 93):
93 = 375a^(-2) + 33
60 = 375a^(-2)
a^2 = 375/60
a^2 = 6.25
a = \(\sqrt{6.25 } =2.5\)
Therefore, the exponential function that satisfies the given conditions is:
\(\bold{f(x) = 375(2.5)^{-x}+ 33}\)
1. The tiles shown are placed in a bag. You randomly select one of the tiles,
return it to the bag, and then randomly select another tile. What is the
probability that the first number divided by the second number is greater
than zero?
the numbers:
-2
-1
2
1
Therefore, the probability that the first number divided by the second number is greater than zero is 1/3.
What is probability?In mathematics, probability is a measure of the likelihood or chance of an event occurring. It is a way of quantifying uncertainty and expressing how likely it is that a particular outcome will occur. Probability theory is used in a wide range of fields, including mathematics, statistics, physics, engineering, economics, and social sciences. It is used to model and analyze random phenomena, make predictions, and estimate the likelihood of certain outcomes.
Here,
Since we are returning the first tile to the bag before selecting the second one, the two selections are independent of each other.
There are two cases to consider:
Case 1: We select a positive number on the first draw.
The probability of selecting a positive number on the first draw is 2/3, since there are two positive numbers (-12 and 1) out of a total of three tiles.
Regardless of what number we select on the first draw, there is only one negative number (-2) in the bag, so the probability of selecting a negative number on the second draw is 1/3.
Therefore, the probability of selecting a positive number on the first draw and a negative number on the second draw (which results in a quotient greater than zero) is:
(2/3) x (1/3) = 2/9
Case 2: We select the negative number (-2) on the first draw.
The probability of selecting the negative number (-2) on the first draw is 1/3.
In this case, we must select the positive number on the second draw in order for the quotient to be greater than zero. There is only one positive number (1) in the bag, so the probability of selecting it on the second draw is 1/3.
Therefore, the probability of selecting the negative number (-2) on the first draw and the positive number on the second draw (which results in a quotient greater than zero) is:
(1/3) x (1/3) = 1/9
Since these are the only two cases that satisfy the condition, the overall probability is the sum of the probabilities of these two cases:
2/9 + 1/9 = 3/9 = 1/3
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Please help asap! really important!!
Answer:
4th graph
6th graph
3rd graph
Step-by-step explanation:
Linear = y = x + 3
it is 4th graph
when you substitute x = 0 y is 3
and when y = 0 x is -3
Quadratic = y = 3x^2
It is 6th graph
for both positive and negative values of x, y is rapidly increasing
Exponential = y = 3^x
it is 3rd graph
for x = 0 y value is 1 because 3^0 = 1
for positive values of x, y is exponentially rising
for negative values of x it is nearly almost touches zero
Puan Yani has RM24 700 in her saving account. Her husband has RM75 300 more money than Puan Yani. At the end of May, Puan Yani deposited RM1 300 in her account. What is the total savings they have now?
The total savings that the couple Puan Yani and her husband have now is A) RM126,000.
How the total savings are computed:The total savings of the couple can be determined by addition.
Addition is one of the four basic mathematical operations, including subtraction, divsion, and multiplication.
Let the amount that Puan Yani has in her savings account, a = RM24,700
Let the amount that her husband has than Puan Yani = RM75,300
The total amount that her husband has = a + 75,300
= RM100,000 (R24,700 + RM75,300)
The additional amount that Puan Yani deposited at the end of May = RM1,300
The total amount that Puan Yani has in her savings account at the end of May = RM26,000 (RM24,700 + RM1,300)
The total savings in the couple's accounts = RM126,000 (RM100,000 + RM26,000)
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Can someone please help
Let f be defined as shown.
What is f^-1 (-9)
Explanation:
The inverse undoes whatever f(x) does. So if the input is x = -8 leads to the output y = -9, then the inverse reverses the process. Effectively, the input and output swap. It's essentially asking the question "if f(x) = -9, then what is the value of x?". In this case, the answer would be x = -8
simple ! please show work math experts :) thank you and have a wonderful day
Answer:
1) \(\dfrac78\)
2) \(\dfrac{17}{12} = 1 \frac{5}{12}\)
3) \(\dfrac{53}{12}=4 \frac{5}{12}\)
Step-by-step explanation:
1)
\(\dfrac38+\dfrac12=\dfrac38+\dfrac{1 \times4}{2 \times 4}=\dfrac38+\dfrac48=\dfrac78\)
2)
\(\dfrac23+\dfrac34=\dfrac{2 \times 4}{3 \times 4}+\dfrac{3 \times3}{4 \times3}=\dfrac8{12}+\dfrac{9}{12}=\dfrac{17}{12}=1 \frac{5}{12}\)
3)
First convert mixed number into improper fraction:
\(4 \frac23=\dfrac{3\times4+2}{3}=\dfrac{14}{3}\)
\(\implies 4 \frac23-\dfrac{3}{12}=\dfrac{14}{3}-\dfrac{3}{12}=\dfrac{14\times4}{3\times4}-\dfrac{3}{12}=\dfrac{56}{12}-\dfrac{3}{12}=\dfrac{53}{12}=4 \frac{5}{12}\)
let's define the reverse of an integer x as the number obtained by reversing the order of the digits of x and then moving any leading zeroes to the end of the resulting number. tests input: arr: [7, 234, 58100] expected output: 7 432 18500
Let's see how the while loop functions for n = 2345. Inside the loop, the reversed number is calculated using the formula reverse = reverse * 10 + remainder. n. n != 0.
What is an integer reversal?We only need to flip the most significant digit into the least significant digit and vice versa, the second most significant digit into the third least significant digit and vice versa, and so on to reverse an integer. Return 0 if the input is bigger than the predetermined range (231, 231 1). Regarding two-digit numbers and their opposite, there are two common logics. The two-digit number "ab" can be represented generally as (10 times a) + b. We are aware that swapping the numbers in the TENS and ONES positions will reverse a number. The typical form of its reverse "ba" is thus (10 times "b" times "a") PlusGiven,
arr: [7, 234, 58100]
Expected Output:
7 + 432+ 18500 = 18939
Input:
arr: [0, 100, 220]
Expected Output:
0 + 100 + 220 = 320
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Find the indicated side of the triangle.
b
45°
28
а
[?]
a =
Please help :)
Answer:
28
Step-by-step explanation:
Correct answer gets brainliest
Answer:
D. its a two dimensional object
Answer:
A. It is a polygon
C. It is a one-dimensional object
The shape is a polygon in two dimensions since a polygon must have at least three straight sides.
hellppp................
Answer:
\(B)\)
\((-1,1)(-3,3)\\\frac{3-1}{-3+1} =-1\\1=1+b\\b=0\\y=-x\)
OAmayOHopeO
100 Points! Algebra question. Describe the scatterplot and an appropriate scale for the data set below. Photo attached. Thank you!
The scatterplot for the given data set does not show any clear form, strength, or directionality, and the appropriate scale for the x and y axes could be -20 to 5 and -15 to 15, respectively.
The given data set is:
(x,y)={(2,−5),(3,1),(−4,8),(−6,−1),(y,−3),(1,−13),(3,−1),(−11,12),(−15,−5)}
To create a scatterplot, we need to plot each point on a coordinate plane. The horizontal axis (x-axis) represents the first element in each ordered pair, and the vertical axis (y-axis) represents the second element in each ordered pair.
The scatterplot would show the distribution of the data points in the given set.
Form: From the given data set, it is not clear whether there is any form or pattern in the distribution of data points.Strength: There does not seem to be a strong relationship between the x and y values as there is no clear linear or nonlinear pattern.Direction: There is no specific directionality in the data points.Scale: The scale for the scatterplot should be chosen based on the range of values in the data set. From the given data set, the x values range from -15 to 3, and the y values range from -13 to 12. So, the scale for the x-axis could be -20 to 5 with tick marks at every 5, and the scale for the y-axis could be -15 to 15 with tick marks at every 5.Read more about scatterplots:
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Evaluate the function.
f(x) = -x2 - 4x - 19
Find f(-9)
Help plsss
Given the quadratic function below:
\( \large{f(x)= - {x}^{2} - 4x - 19}\)
To find f(-9), simply substitute x = -9 in the function.
\( \large{f( - 9) = - {( - 9)}^{2} - 4( - 9) - 19} \\ \large{f( - 9) = - 81 + 36 - 19} \\ \large{f( - 9) = - 100 + 36 \longrightarrow \large \boxed { \purple{f( - 9) = - 64}}}\)
Answer
f(-9) = -64Let me know if you have any doubts regarding the function.
A Galapagos tortise can walk 1/5 mile in an hour. How many hours would it take for the tortise to walk 1/6 mile?
Answer:
0.834 hours
Given that,
A Galapagos tortoise can walk 1/5 mile in an hour.
We need to find time would it take the tortoise to walk 1/6 mile.
1/5 mile = 1 hour
1 mile = 1/1/5 = 5 hours
For 1/6 mile = 1/6 *5 = 0.834 hours
It will take 0.834 hours to walk 1/6 mile.
Evaluate 3+11t -9 when t=9 and u=11
Answer:
is the U missing from the equation
Step-by-step explanation:
A new computer graphics company employs 10 programmers. The company decides to expand into digital animation and needs to transfer 3 of the programmers into the new department. How many different combinations of 3 programmers can be chosen to transfer to the new department?
A. 3
B. 30
C. 120
D. 840
There are 120 different combinations of 3 programmers that can be chosen to transfer to the new department
How to determine the ways of selection?From the question, we have
Total number of programmers, n = 10
Numbers to programmers to select, r = 3
The number of ways of selection could be drawn is calculated using the following combination formula
Total = ⁿCᵣ
Where
n = 10 and r = 3
Substitute the known values in the above equation
Total = ¹⁰C₃
Apply the combination formula
ⁿCᵣ = n!/(n - r)!r!
So, we have
Total = 10!/(7! * 3!)
Evaluate
Total = 120
Hence, the number of ways is 120
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Multiply 58*7 enter your answers in the boxes to complete the area model
We will get 406 after multiplication .
What does multiply mean?
Multiplying in math is the same as adding equal groups. The number of items in the group grows as we multiply. A multiplication issue has two factors, a product, and two factors. The factors in the multiplication problem 6 x 9 = 54 are the numbers 6 and 9, and the product is the number 54.Calculating the outcome of adding a number several times is known as multiplication in elementary algebra. Each of the numbers and is referred to as a factor of the product, which is the outcome of a multiplication.58 * 7 = 406
We will get 406 after multiplying .
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find the missing side. round to the nearest tenth
The required angle is 24.5°.
Given is a right triangle with perpendicular side 16 and the base = 35 we need to find an acute angle in it,
To find the acute angle in a right triangle given the lengths of the perpendicular side and the base, you can use the tangent function.
The tangent of an angle is defined as the ratio of the length of the perpendicular side to the length of the base side.
In this case, the perpendicular side is 16 and the base is 35.
Let's denote the acute angle as θ.
Using the tangent function, we can set up the equation:
tan(θ) = perpendicular side / base
tan(θ) = 16 / 35
To find the value of θ, we can take the inverse tangent of both sides:
θ = tan⁻¹(16 / 35)
θ = 24.5°
Hence the required angle is 24.5°.
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Name an acute angle and give its measure.
Angle: ______ Measure: _____
Name an obtuse angle and give its measure. (2 points)
Angle: _____ Measure: _____
Name one right angle. (1 point
Name one straight angle. (1 point)
11. Angle KEF = 40°, Angle KEJ = 50°
12. Angle HEF = 115°, Angle KED = 140°
13. Angle JEF = 90°, Angle KEF = 90°
14. Angle DEF = 180°
Define the term geometry?The study of points, lines, and shapes in two and three dimensions, as well as their properties and relationships, is the focus of the mathematical discipline known as geometry.
11. Acute angles: Those angles are less than 90 degree angles.
Angle KEF = 40°
Angle KEJ = 50°
Angle KEH = 75°
Angle JEH = 25°
Angle HED = 65°
12. Obtuse angles: Those angles are more than 90 degree angles.
Angle HEF = 115°
Angle KED = 140°
13. Right angle: Those angles are 90 degree angle.
Angle JEF = 90°
Angle KEF = 90°
14. Straight angle: Those angles make 180 degree angle.
Angle DEF = 180°
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−28 = 7b
Solve for b
Tell what you did to find b
Answer:
b= -4
Step-by-step explanation:
ABCD is a quadrilateral.
a
b) When ABCD is drawn to scale, would
the lines AD and BC be parallel or not? A
You must justify your answer without
using a scale drawing.
Justify your answer
Yes/No
The value of x is 45 in the provided assertion, and the Centerior angles do sum up to 180°, indicating that AD and BC are parallel.
We have,
Parallel in mathematics refers to two lines which never cross one another; picture an equal symbol. Three close pals' parallel lives could be depicted in a tale.
(a)
3x + x + 2x + 90 = 360
6x = 360 - 90
6x = 270
x = 45
(b) The answer will be yes, they would be parallel.
We can justify this using co-interior angles, which state that 2 angles subtended by parallel lines add up to 180°
We can check this with both angles 3x & x, or 2x & 90°.
If AD and BC are parallel, then 3x + x = 180, and since you already found the value of x we can substitute this in:
3(45) + (45) = 180
135 + 45 = 180
180 = 180
So the co-interior angles do add up to 180°, which means that AD and BC are parallel.
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HELP ME PLEASE!!!!!!
ZEARN!!!!
The expression 1 2/5 + 2 2/3 using fifteenths is 3 + 6/15 + 10/15
How to rewrite the expression using fifteenthsFrom the question, we have the following parameters that can be used in our computation:
1 2/5 + 2 2/3
3 + 2/5 + 2/3
To rewrite the expression using fifteenths, we multiply the numerator and the denominator of the fractions by the same number
In this case, we use 3 and 5
So, we have
3 + 2/5 * 3/3 + 2/3 * 5/5
Evaluate the products
3 + 6/15 + 10/15
Hence, the expression using fifteenths is 3 + 6/15 + 10/15
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SOME ONE PLEASE ANSWER ASAP NEED EXPLAIN FULL STEPS
Answer:
\({ \tt{( \frac{ - 4}{9} \times \frac{63}{28}) - ( \frac{33}{66} \times \frac{ - 51}{17} ) + ( \frac{5}{8} \times \frac{4}{10)} }} \\ \\ = { \tt{( \frac{ - 4}{28} \times \frac{63}{9}) - ( \frac{1}{2} \times \frac{ - 3}{1} ) + ( \frac{5}{10} \times \frac{4}{8} )}} \\ \\ { \tt{ = ( - 1) - ( - \frac{3}{2} ) + ( \frac{1}{4}) }} \\ \\ = { \tt{ \frac{3}{4} }}\)
Answer:
\(\sf \dfrac{3}{4}\)
Step-by-step explanation:
Given expression:
\(\implies \sf \left(\dfrac{-4}{9} \times \dfrac{63}{28}\right)-\left(\dfrac{33}{66} \times \dfrac{-51}{17}\right)+\left(\dfrac{5}{8} \times \dfrac{4}{10}\right)\)
\(\textsf{Apply the fraction rule} \quad \dfrac{a}{b} \times \dfrac{c}{d}=\dfrac{a \times b}{c \times d}:\)
\(\implies \sf \left(\dfrac{-4\times63}{9\times28} \right)-\left(\dfrac{33 \times -51}{66 \times 17}\right)+\left(\dfrac{5\times4}{8\times10} \right)\)
Multiply the numbers:
\(\implies \sf \left(\dfrac{-252}{252} \right)-\left(\dfrac{-1683}{1122}\right)+\left(\dfrac{20}{80} \right)\)
Reduce the fractions:
\(\implies \sf -1-\left(\dfrac{-3}{2}\right)+\left(\dfrac{1}{4} \right)\)
\(\textsf{Apply rule}\quad \:a-\left(-b\right)=a+b:\)
\(\implies \sf -1+\dfrac{3}{2}+\dfrac{1}{4}\)
Adjust the fractions based on the LCM of 4:
\(\implies \sf \dfrac{-4}{4}+\dfrac{6}{4}+\dfrac{1}{4}\)
\(\textsf{Apply the fraction rule} \quad \dfrac{a}{c}+\dfrac{b}{c}=\dfrac{a+b}{c}:\)
\(\implies \sf\dfrac{-4+6+1}{4}\)
Add the numbers in the numerator:
\(\implies \sf \dfrac{3}{4}\)
3
It takes 9 minutes to fill an empty aquarium to a depth of
5
meters.
What is the unit rate in minutes per meter?
Write your answer in simplestorm.
Answer:
The rate is 15 minutes per meter.
Step-by-step explanation: please give brainliest