Help please! I'm in Algebra class and I'm stuck on solving this tricky problem. I would be very grateful to anyone who could offer an answer.

Answer:

A. Which Sibling received the most money

(Sibling B)

the least money ? (Sibling A)

which Sibling spends money at the fastest rate?

(Sibling B)

the slowest rate?

(Sibling A)

which Sibling runs out of money first?

(Sibling C) and Last? (Sibling A)

Step By Step Explanation?

a. We can know from the graph. A received so dollars.

Assuming that B y=ax+b

100=a+b. a= -25

→

175 = 2a+b b=125

- B₁ y=-25x+125

:. B received 125 dollars.

C+ y = -22.5x +90 : C C received dollars.

125> 90 80

B received the most money. A received the least money.

b. Assuming that A: M= ax+b

$ 0= -15 40+b=20 1 b = 80 y=-15x+80

• Y₁ = -25x+125, Y₁ = -22.5 mx +90

1-151 <1-22.5) <1-251 {The steeper the slope, the steeper the line}

B spends money at the fastest rate

A spends money at the slowest rate.

C. MA=-15x + 80 when Y₁ = 0 . x = 15

Y₁ = -25x+125, when y₁=0₁ x = 12/5/² = 5 35

Y₁ = -22.5 x +9°, when y₁=0₁ x = 12/2²/5 = 4 9⁰

:: C runs out of money first

A runs out of money last

Answer:

1.B

2.A

3.B

4.A

5.C

6.A

Step-by-step explanation:

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