Explanation:
When the skater is dropped onto the ramp from above, the potential energy decreases and the kinetic energy increases.
Every time the skater bounces from the impact, thermal energy is gained, and both potential and kinetic energy are lost.
460miles per hour with the wind nd 420 per hour gainst the wind
The speed of the wind is 20 miles per hour.
To solve this problem, we can use the formula:
Speed = Distance/Time
Let's assume that the speed of the wind is x miles per hour.
With the wind, the plane travels at a speed of 460 miles per hour. This means that its speed relative to the ground is the sum of its airspeed and the speed of the wind:
460 = Airspeed + x
Against the wind, the plane travels at a speed of 420 miles per hour. This means that its speed relative to the ground is the difference between its airspeed and the speed of the wind:
420 = Airspeed - x
We can solve this system of equations to find the airspeed of the plane:
460 = Airspeed + x
420 = Airspeed - x
Adding the two equations gives:
880 = 2Airspeed
Dividing both sides by 2 gives:
Airspeed = 440 miles per hour
Now that we know the airspeed of the plane, we can find the speed of the wind by substituting this value into one of the equations we obtained earlier:
460 = Airspeed + x
460 = 440 + x
x = 20
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when air mass is caught between two cold fronts the result is a _______ front.
Answer choices
A.occluded
B.warm
C.cold
D.stationary
Gerry max does great effort to stay awake studying all night long. he decides to make a cup of coffee by first placing a 200W electric immersion heater in 0.32kg of water. How much energy is needed to totally vaporize the water being heated
After considering all the given data we conclude that the the amount of energy needed to vaporize the water completely is 722.24 kJ.
The energy needed to vaporize water is reffered to as the heat of vaporization. The heat of vaporization of water is 2257 kJ/kg³.
Here we have to apply the principles of vaporization to derive a formula to evaluate the energy needed to vaporize 0.32 kg of water,
Then
Energy = Heat of vaporization x Mass of water
Energy = 2257 kJ/kg x 0.32 kg
Energy = 722.24 kJ
Then, the energy needed to totally vaporize the water being heated is 722.24 kJ.
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A student heated 50mL of water from zero degree Celsius to 60 degree Celsius. How much energy did she use to heat the water? Remember cal = m x delta T
Answer:
Q = 12.5 kJ
Explanation:
Given that,
Mass of water, m = 50 mL = 0.05 kg
The temperature changes from 0 degree Celsius to 60 degree Celsius.
We need to find how much energy she use to heat the water. The energy required to heat the water is given by :
\(Q=mc\Delta T\)
Where c is specific heat of water, c = 4186 J/kgºC
\(Q=0.05\times 4186 \times (60-0)\\\\=12558\ J\)
or
Q = 12.5 kJ
So, the energy used to heat th water is 12.5 kJ.
a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with coefficient of kinetic friction uk 0.15. The block makes it up the incline to a second flat frictionless surface. What is the work done by friction? What is the velocity of the block at point C? The incline is 2.2m long at an angle 0=15
44.4 is the work done by friction 14.4 s the velocity of the block at point C . Correct Option a)
What is friction and example?Friction is the force that prevents solid surfaces, fluid layers, and material components from moving against each other. There are various kinds of friction.
Dry friction is the force that resists the relative lateral motion of two in touch solid surfaces. Dry friction is further classified as static friction ("stiction") between non-moving surfaces and kinetic friction ("stiction") between moving surfaces. Dry friction, with the exception of atomic or molecular friction, is caused by the interplay of surface characteristics known as asperities . Fluid friction explains the friction that occurs between sliding segments of a thick fluid.
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Full Question: In the figure below, a block of mass 5.0 kg starts at point A with a speed of 15.0 m/s on a flat frictionless surface. At point B, it encounters an incline with a coefficient of kinetic friction uk = 0.15. The block makes it up the incline to B a second flat frictionless surface. The incline is 22 m long at an angle = 15° What is the total work done in joules when the block goes from A to C and what is the speed of the block at point C in m/s? (fist value is work, second is speed) A) 44.4; 14.4 B) 44.4, -14.4 C) 14.4, 44.4 D) 44.4, 14.4 E) 44.4, 44.4
What must be the diameter of a cylindrical 120-m long metal wire if its resistance is to be ? The resistivity of this metal is 1.68 × 10-8 Ω • m.
Answer:
The diameter is \(d = 6.5 *10^{-4} \ m\)
Explanation:
From the question we are told that
The length of the cylinder is \(l = 120 \ m\)
The resistance is \(\ 6.0\ \Omega\)
The resistivity of the metal is \(\rho = 1.68 *10^{-8} \ \Omega \cdot m\)
Generally the resistance of the cylindrical wire is mathematically represented as
\(R = \rho \frac{l}{A }\)
The cross-sectional area of the cylindrical wire is
\(A = \frac{\pi d^2}{4}\)
Where d is the diameter, so
\(R = \rho \frac{l}{\frac{\pi d^2}{4 } }\)
=> \(d = \sqrt{ \rho* \frac{4 * l }{\pi * R } }\)
\(d = \sqrt{ 1.68 *10 ^{-8}* \frac{4 * 120 }{3.142 * 6 } }\)
\(d = 6.5 *10^{-4} \ m\)
77. A drag racing vehicle travels from 0 to 100 mph in 5 seconds north. What is the acceleration?
a).004
s2
b).0056 m/s2 c).0079"
d).01 m/s2
M
m
Answer:
a
Explanation:
i just took the test
how much work is done on a 300-newton suitcase to lift it 0.50 meter?
The work done by lifting the suitcase is equal to 150 J.
What is the work?Work can be explained as the energy utilized when a definite force is applied to move an object through a fixed displacement. The work done can be described as both the exerted force on the object and the displacement moved by the object.
The applied force is moved an object in the direction of the applied force over a displacement 'd'.
W= F × d
Given, the force applied on the suitcase to lift, F = 300N
The displacement of the suitcase, d = 0.50 m
The work done can be calculated as:
W = F.d
W = 300 × 0.50
W = 150 J
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Two long, charged, thin-walled, concentric cylindrical shells have radii of 3.0 cm and 6.0 cm . The charge per unit length is 5 . 0 × 10 - 6 on the inner shell and - 7 . 0 × 10 - 6 on the outer shell. What are the (a) magnitude E and (b) direction (radially inward or outward) of the electric field at radial distance r=4.0 cm ? What are (c) E and (d) the direction at r=8.0 cm ?
The electric field in the direction is 4.5×10^5 N/C.
We denote the inner and outer cylinders with subscripts i and o, respectively.
(a) Since r_i<r=4.0cm<r_o,
E(r)= λ_i / 2πϵ_0r = 5.0×10^−6C/m / 2π(8.85×10^−12C^2/N.m)(4.0×10^−2m) = 2.3×10^6 N/C
(b) The electric field E(r) points radially outward.
(c) Since r>r_o,
E(r=8.0cm)= λ_i+λ _o / 2πϵ_0r = 2π(8.85×10^−12 C/N.m 2)(8.0×10^2m)
5.0×10^−6C/m−7.0×10^−6C/m =−4.5×10^5 N/C
or ∣E(r=8.0cm)∣=4.5×10^5 N/C.
(d) The minus sign indicates that E(r) points radially inward.
An electric field is a physical phenomenon that arises from the presence of charged particles. When a charged particle, such as an electron or a proton, is placed in a region of space, it creates an electric field that permeates that space. The electric field is a vector field, meaning it has both magnitude and direction, and is represented by electric field lines. The strength of the electric field is proportional to the magnitude of the charge that created it and inversely proportional to the distance from the charge.
Electric fields play a crucial role in many aspects of physics and engineering, including electronics, electrostatics, and electromagnetism. They are responsible for many everyday phenomena, such as the attraction and repulsion of magnets, the operation of electric motors and generators, and the functioning of electronic devices like smartphones and computers.
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At low pressures and high temperatures, the density of a gas
Answer:
Higher denisty
Explanation:
High pressure=high denisty
What is the origin of a warm, wet air masses.
A. over land in polar regions
B. over water in polar regions
C. over land in tropical areas
D. over water in tropical zones
Answer:
An air mass acquires these characteristics above an area of land or water known as its source region. When the air mass sits over a region
Question 18 (2 points)
Which statement is TRUE about the relationship between magnetic fields and
electric charges.
A. Moving electric charges (electrons in a circuit) creates a magnetic field and
a magnetic field can cause an electric charge to move (electricity).
B. Moving electric charges (electrons in a circuit) creates an electric field and
a magnetic field can cause static electricity.
C. Static (not moving) electric charges creates a magnetic field and a magnetic field
can cause electricity to stop flowing.
Answer:
A.Moving electric charges (electrons in a circuit) creates a magnetic field and
a magnetic field can cause an electric charge to move (electricity).
Explanation:
A crate with a mass of 1000 kg is being pulled along greased tracks by a winch. The winch is exerting a force of 2000 N
in the horizontal direction along the tracks. The coefficient of kinetic friction between the crate and the tracks is 0.2.
20. What is the net force acting on the crate in the horizontal direction?
21.
Using Newton's second law, calculate the crate's acceleration.
Coefficient of Kinetic Friction = 0.2
Mass of the crate = 1000 kg
Force applied = 2000 N
Net force Acting on the crate in the Horizontal Direction:Normal Force applied on the Crate:Normal force is the force applied on the object by the surface. It is equal and opposite to the force of gravity
So, we can say that Normal force = | Gravitational Force |
Normal Force = | mg |
Normal Force = 1000 * 9.8
Normal Force = 9800 N
Finding the Frictional Force:We know that:
coefficient of Kinetic friction = Friction force / Normal force
replacing the known values
0.2 = Friction force / 9800
Friction Force= 0.2 * 9800
Friction Force = 1960 N
Net force acting on the Crate:
We know that a force of 2000 N is being applied on the crate in the Horizontal direction
Frictional force is always opposite to the horizontal force. So, we can say that:
Applied force - Friction Force = Net Force
replacing the variables
2000 - 1960 = Net force
Net Force = 40N
Therefore, a net force of 40N is being applied on the Crate
Acceleration of the Crate:From newton's second law of motion:
F = ma
replacing the variables
40 = 1000 * a
a = 40/1000
a = 0.04 m/s²
Hence, the crate will have an acceleration of 0.04 m/s²
A cyclist increases his speed from 10 m/s to 20 m/s in 5s.
Calculate his average speed over this time interval.????
The average speed of the cyclist over the time interval is 6m/s.
How to calculate average speed?Average speed in physics is the total distance traveled by the object in a particular time interval. The average speed is a scalar quantity. It is represented by the magnitude and does not have direction.
The formula to calculate average speed is as follows;
S = ∆V/t
where
S equals the average speed∆V equals change in velocityt = timeAccording to this question, a cyclist increases his speed from 10 m/s to 20 m/s in 5s. The average speed is calculated as follows:
S = (20 - 10)/5
S = 30/5
S = 6m/s
Therefore, 6m/s is the average speed.
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What is energy ? Use in your own words.
Answer:
the potential for causing changes
Explanation:
A person stands on a scale in an elevator. The maximum and minimum scale readings are 908.9 N and 494.7 N, respectively. The acceleration of gravity is 9.8 m/s 2 . Assume the magnitude of the acceleration is the same during starting and stopping, and determine the acceleration of the elevator. Answer in units of m/s 2 .
The acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
The change in the person's weight can be used to calculate the elevator's acceleration.
The change in weight is: 908.9 N - 494.7 N = 414.2 N
Since weight is equal to mass times acceleration (W = m * a), we can rearrange the equation to solve for acceleration:
a = W / m
Where m is the mass of the person, which can be calculated using the acceleration due to gravity:
m = W / g = 414.2 N / 9.8 m/s^2 = 42.3 kg
Substituting the mass into the equation for acceleration:
a = 414.2 N / 42.3 kg = 9.8 m/s^2
So the acceleration of the elevator is 9.8 m/s^2, which is equal to the acceleration due to gravity.
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A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the air pressure and temperature inside the vessel are 20 atm and 300K, respectively: What is the mass of air stored in the vessel
Answer:
The mass of air stored in the vessel is 235.34 kilograms.
Explanation:
Let supossed that air inside pressure vessel is an ideal gas, The density of the air (\(\rho\)), measured in kilograms per cubic meter, is defined by following equation:
\(\rho = \frac{P\cdot M}{R_{u}\cdot T}\) (1)
Where:
\(P\) - Pressure, measured in kilopascals.
\(M\) - Molar mass, measured in kilomoles per kilogram.
\(R_{u}\) - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.
\(T\) - Temperature, measured in Kelvin.
If we know that \(P = 2026.5\,kPa\), \(M = 28.965\,\frac{kg}{kmol}\), \(R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K}\) and \(T = 300\,K\), then the density of air is:
\(\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}\)
\(\rho = 23.534\,\frac{kg}{m^{3}}\)
The mass of air stored in the vessel is derived from definition of density. That is:
\(m = \rho \cdot V\) (2)
Where \(m\) is the mass, measured in kilograms.
If we know that \(\rho = 23.534\,\frac{kg}{m^{3}}\) and \(V = 10\,m^{3}\), then the mass of air stored in the vessel is:
\(m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})\)
\(m = 235.34\,kg\)
The mass of air stored in the vessel is 235.34 kilograms.
PLEASE HELP I WROTE THIS LIKE 200 TIMES
Plate boundaries represent parts of the Earth where plates come in contact with one another. There are different ways in which these plates can move and interact. In this assignment, you will identify each type of plate movement and create an illustration to represent this.
Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.
Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.
Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.
Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.
To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.
For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.
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4. You currently have TWO 9 volt batteries connected to a 82 resistor. How
much current is flowing through the circuit? *
1.125 A
5 A
72 A
2.25 A
Back
Next
Never submit passwords through Gon
Explanation:
Total voltage = 9 × 2 = 18v
Resistance = 82 Ω
Ohm's law::
V = IR
18v = 82 Ω × I
18v /82 /Ω = I
18/82 Ampere is the current
three laws of mechanics and
Answer:
In the first law, an object will not change its motion unless a force acts on it. In the second law, the force on an object is equal to its mass times its acceleration. In the third law, when two objects interact, they apply forces to each other of equal magnitude and opposite direction.
HELPPP BESTIESSS An astronomer is studying two stars that have about the same size and brightness. From the Earth, one of the stars appears very bright in the night sky. The other star appears very faint and dim.
Why does one star appear to be brighter than the other?
A. The Earth is moving toward the brighter star.
B. The Earth is moving toward the dimmer star.
C. The Earth is farther from the brighter star.
D. The Earth is closer to the brighter star.
Answer:
If the stars are about the same size and brightness then the earth must be nearer to the stat that appears brighter, The stars movement, nearer or farther, would only effect the frequency received (redshift).
Answer:
D- The earth is closer to the bright star
Explanation:
If two stars have SAME brightness and size then that means the only point of difference is distance . Earth should be closer to the brighter star for the star to be bright.
I hope im right!!
knowing that the velocity of block b after the impact is observed to be 2.2 m/s to the right, determine the coefficient of restitution between the two blocks. the coefficient of restitution between the two blocks is
The coefficient of restitution between two objects is a measure of the elasticity of the collision between them.
It is defined as the ratio of the relative velocity of separation to the relative velocity of approach between the two objects.
In this problem, the velocity of block b after the impact is observed to be 2.2 m/s to the right. Let us assume that block a is moving to the left with a velocity of v1 just before the impact. According to the law of conservation of momentum, the total momentum of the two blocks before the impact is equal to the total momentum of the two blocks after the impact. Therefore:
\(m1v1 + m2v2 = m1v1' + m2v2'\)
where m1 and m2 are the masses of block a and block b, respectively, v1 and v2 are the velocities of block a and block b just before the impact, and v1' and v2' are their velocities just after the impact.
Since block b is moving to the right after the impact, we can take v2' = 2.2 m/s. We also know that the two blocks stick together after the impact, so v1' = v2'. Therefore, we can simplify the above equation to:
\(m1v1 + m2v2 = (m1 + m2)v1'\)
Solving for v1', we get:
\(v1' = (m1v1 + m2v2)/(m1 + m2)\)
The coefficient of restitution (e) is defined as the ratio of the relative velocity of separation (v2' - v1') to the relative velocity of approach (v1 - v2) between the two blocks. Since the two blocks stick together after the impact, the relative velocity of separation is zero. Therefore:
\(e = (v2' - v1')/(v1 - v2) = 0/(v1 - v2) = 0\)
Hence, the coefficient of restitution between the two blocks is zero.
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William was swimming at a speed of 3 m/s when he started to slow down. He slowed to a stop in 2 seconds. What is his acceleration?
Answer:
\(-1.5\;\rm m \cdot s^{-2}\) on average.
Explanation:
The acceleration of an object is the rate of change in its velocity. The average acceleration of an object is equal to the change in velocity over the time required for that change to take place.
For the William in this question:
The initial speed of William is \(3\; \rm m \cdot s^{-1}\). Because William came to a complete stop after \(2\; \rm s\), his speed at that time would be \(0\; \rm m \cdot s^{-1}\).Had William not came to a complete stop, it would be necessary to consider whether there is a change to his orientation. However, because in this question William came to a stop, the change in his velocity would be:
\(\begin{aligned} &\text{Change in velocity} \\&= \text{Final velocity} - \text{Initial velocity}\\ &= 0\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1} = -3\; \rm m \cdot s^{-1}\end{aligned}\).
That change in velocity happened over \(2\; \rm s\). Therefore, the average acceleration would be:
\(\begin{aligned}&\text{Average Acceleration} = \frac{\text{Change in velocity}}{\text{Time taken}} = \frac{-3\; \rm m \cdot s^{-1}}{2\; \rm s} \approx -1.5\; \rm m \cdot s^{-1}\end{aligned}\).
the radiation that is least damaging to humans is
The radiation that is least damaging to humans is non-ionizing radiation.
What is non ionizing radiationNon-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.
Examples of non ionizing radiation include radio waves, microwaves, visible light and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.
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what do you mean by mass of object is 7 kg
Explanation:
Mass=7 kg means that it weights 7 kg while measuring on beam balance .
Graph. See text version for more detail.
The graph above represents the nuclear decay of a radioactive element, measured using a radiation-detecting device. What is the half-life, in days, of this hypothetical element?
If the half-life of a given substance is 65 days, how long will it take for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining?
If a sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams, what is the half-life of the isotope? Hint: First, determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.
If a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years, what is the half-life of technetium-99?
The half-life of hypothetical element technetium-99 is 210,936 years.
Half-life of the hypothetical element From the graph provided in the question, the half-life of the hypothetical element can be obtained by finding the time taken for the element to reduce to half its original quantity. Here, it can be seen from the graph that the quantity of the element reduces from 40 to 20 on day 4. Therefore, the half-life of the hypothetical element is 4 days.2. Time taken for a sample to decay from 100 grams to 25 gramsIf the half-life of a given substance is 65 days, then the quantity of the substance reduces to half every 65 days. From 100 grams to 50 grams, it takes one half-life cycle. From 50 grams to 25 grams, it will take another half-life cycle.
Therefore, it will take two half-life cycles, which is 2 × 65 = 130 days, for a 100-gram sample of the substance to decay until there is only 25 grams of the radioactive material remaining.3. Half-life of a sample that decays from 200 grams to 50 grams in 60 minutesIt is given that the sample of radioactive isotopes takes 60 minutes to decay from 200 grams to 50 grams. To find the half-life, we need to determine how many times the sample has lost half of its mass, which tells you how many half-life cycles have occurred.At 30 minutes, the sample reduces to half its original quantity, which is 100 grams. At 45 minutes, it reduces to 50 grams, which is half of 100 grams. Therefore, it takes two half-life cycles to reduce from 200 grams to 50 grams in 60 minutes. Hence, the half-life of the isotope is 15 minutes.4. Half-life of technetium-99 that decays from 500.0 g to 62.5 g in 639,000 yearsIt is given that a 500.0 g sample of technetium-99 decays to 62.5 g of technetium-99 remaining in 639,000 years. We can use the half-life formula to find the half-life of technetium-99.t1/2 = (t × log2) / log(N0 / Nt) Where,t1/2 = half-life of the substanceN0 = initial quantity of the substance Nt = quantity of the substance left after time t (in years)t = time (in years)From the given data,t1/2 = (639000 × log2) / log(500.0 / 62.5)t1/2 = 210,936 years.
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How high will a 2 kg block be launched from a 100,000 N/m spring that was compressed by 0.01 m
Answer:
Explanation:
The spring potential energy will be converted to gravity potential energy
mgh = ½kx²
h = kx²/2mg
h = 100000(0.01²) / 2(2)(9.8)
h = 0.25510... m
Round as you feel appropriate, although with only one significant digit for several of the input numbers, the answer should be rounded to one significant digit as well h = 30 cm
Find the magnitude and direction of a force between a 25.0 coulomb charge and a 40.0coulomb charge when they are separated by a distance of 30.0cm
Answer:
95.0 colomb
Explanation:
Make sure to understand the concept
a roller coaster start at a height of 40Meters and reached a height of 20meter. does mechanical energy change
Mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
When a roller coaster starts at a height of 40 meters and reaches a height of 20 meters, mechanical energy changes. In physics, mechanical energy is the sum of potential and kinetic energy that is present in the objects. When an object is moved, it gains or loses energy, thus the mechanical energy changes. There are two forms of mechanical energy, namely kinetic energy and potential energy. Kinetic energy is the energy that a moving object possesses due to its motion, while potential energy is the energy that an object possesses due to its position or shape.
In the case of a roller coaster, when it starts at a height of 40 meters, it has potential energy that is equal to its mass multiplied by the acceleration due to gravity multiplied by its height. As it moves down the track, the potential energy gets converted into kinetic energy, which is the energy of motion. When the roller coaster reaches a height of 20 meters, it has a lower potential energy compared to when it started. The difference in potential energy is equal to the amount of work done by the force of gravity in bringing the roller coaster down from a height of 40 meters to a height of 20 meters. At the same time, the roller coaster has a higher kinetic energy than when it started, as it gained speed during the descent.
Therefore, in summary, mechanical energy changes when a roller coaster starts at a height of 40 meters and reaches a height of 20 meters. The potential energy decreases, while the kinetic energy increases.
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How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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