How many GRAMS of aluminum sulfate can be made from 1.18 grams of aluminum

Answer:

The d-block and transition metal are not interchangeable terms because the d-block elements are a subset of the transition metal elements. The transition metals are defined as the elements that have partially filled d orbitals, which includes the d-block elements as well as other elements that have partially filled d orbitals in other blocks, such as lanthanides and actinides. Therefore, while all d-block elements are transition metals, not all transition metals are d-block elements.

The tank's CO₂ density is 1.84 g/L.

Use the ideal gas law to solve for the density of CO₂:

PV = nRT

where:

P = pressure = 760.0 torr

V = volume = 5.20 L

n = moles of CO2 (we don't know this yet)

R = gas constant = 0.08206 L·atm/K·mol

T = temperature = 39.0°C + 273.15 = 312.15 K

First, convert torr to atm:

760.0 torr ÷ 760 torr/atm = 1 atm

Rearrange the ideal gas law to solve for n:

n = PV/RT

n = (1 atm)(5.20 L)/(0.08206 L·atm/K·mol)(312.15 K)

n = 0.217 mol

Use the mass of CO₂ and the volume of the tank to find the density:

mass = n × molar mass

mass = 0.217 mol × 44.01 g/mol

mass = 9.57 g

density = mass/volume

density = 9.57 g/5.20 L

density = 1.84 g/L

Therefore, the density of CO₂ in the tank is 1.84 g/L.

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Answer:

n = 3.0 moles

V = 60.0 L

T = 400 K

From PV = nRT, you can find P

P = nRT/V = (3.0 mol)(0.0821 L-atm/K-mol)(400 K)/60.0L

P = 1.642 atm = 1.6 atm (to 2 significant figures)

Explanation:

Answer:

Ca2+

Explanation:

don't really know what to explain here, thats just the ion name.

Answer:

65.0 K

Explanation:

To find the temperature, you need to use the Ideal Gas Law:

PV = nRT

In this equation,

-----> P = pressure (pKa)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (8.31 L*kPa/mol*K)

-----> T = temperature (K)

You can plug the given values into the equation and simplify to find the temperature.

P = 202.65 pKa                          R = 8.31 L*kPa/mol*K

V = 2.0 L                                     T = ? K

n = 0.75 moles

PV = nRT

(202.65 pKa)(2.0 L) = (0.75 moles)(8.31 L*kPa/mol*K)T

405.3 = (6.2325)T

65.0 K = T

The degree of dissociation gives the amount of the substance that dissociated into the products. The value of Kc for water is 1.28 x 10⁻³.

The equilibrium constant, Kc is the equilibrium concentration of the products over the reactants that are raised by the powers of their stoichiometry coefficient.

The reaction is shown as:

H₂​O(l) ⇋ H₂​O(g)

Kp = pressure of water = 0.03131579 atm

\(\rm Kp = Kc(RT)^{\Delta n}\)

Here Δ n = 1

Solving further,

Kp = Kc(RT)

0.03131579 = Kc(0.0821 × 298.15)

Kc =1.28 x 10⁻³

Therefore, Kc is 1.28 x 10⁻³.

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The partial pressure of hydrogen is 0.98 atm while the partial pressure of water is 0.02 atm. The total pressure of the system is 1 atm.

We have seen the reaction as it has been shown in the equation that is attached to the question above. Now, we must have to find the number of moles of the hydrogen that was obtained.

Number of moles of sodium =  1.90 g/23 g/mol = 0.08 moles

2 moles of sodium produces 1 mole of hydrogen

0.08 moles of sodium would produce 0.08 moles * 1 mole/ 2 moles

= 0.04 moles

Given that;

P = pressure

V = volume

n = Number of moles

R = gas constant

T = temperature

PV = nRT

P = nRT/V

P = 0.04 * 0.082 * 298/1

P = 0.98 atm

The partial pressure of the hydrogen = 0.98 atm

The partial pressure of the water = SVP of water at 18°C = 0.02 atm

Total pressure of the system =  0.98 atm +  0.02 atm = 1 atm

The system has a total pressure of 1 atm.

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To find the density of the unknown piece of metal, we can use the formula:

Density = mass / volume.

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With a 27.7 mL sample of a 0.400 M aqueous hypochlorous acid solution  titrated with a 0.335 M aqueous potassium hydroxide solution, the pH value is mathematically given as

pH=12.90

Moles of HClO=0.329*21.5

Moles of HClO=7.0735

and

Moles of KOH=0.456*23.3

Moles of KOH=10.6248

Hence

The net mole of KOH=10.6248-7.0735

The  net mole of KOH=3.5513

Volume of solution=21.5+23.3

Volume of solution=44.8ml

Generally, the equation for the  Concentration of KOH is mathematically given as

CKOH=mole/volume

Therefore

CKOH=3.5513/44.8ml

CKOH=0.07927M

In conclusion,

pOH=-log{OH-}

pOH=-log{0.07927}

pOH=1.10

pH=14-110

pH=12.90

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Answer:∆H reactants = 1 mol x 0 kJ/mol + (1mol x -393.5 kJ/mol) = -393.5 kJ ∆H rxn = -221 kJ - (-393.5 kJ) = 172.5 kJ The molar enthalpy (in kJ/mol) for this reaction is 172.5 kJ/mol

Explanation:

Answer:

M= ml - 45301 - 11.59M.

Explanation:

Answer:

Molarity of HCl solution = 0.25 M

Explanation:

Given data:

Volume of NaOH= V₁ = 25.0 mL (25/1000 = 0.025 L)

Molarity of NaOH solution=M₁ = 0.185 M

Volume of HCl solution = V₂ = 0.0200 L

Molarity of HCl solution =  M₂= ?

Solution:

M₁V₁   =  M₂V₂

0.185 M ×0.025 L =  M₂ × 0.0200 L

M₂  = 0.185 M ×0.025 L / 0.0200 L

M₂  = 0.005M.L /0.0200 L

M₂  =  0.25 M

Answer: 3.32060434 × 10^-23

Explanation: Divide the number of atoms (20) by 6.023 x 10^23 (Avogadro’s number) to get the number of moles.

The molarity of the magnesium chloride solution is 1.47 mol/L.

Molarity is defined as number of moles of compounds present in a unit liter of volume of the solution

Given ;

Formula used ;

Molarity = Number of Moles / Volume of solution (Ltr)

Therefore, Putting values ;

Molarity = 7.37 moles / 4.30 L

              = 1.71 mol/ltr

The molarity of the given magnesium chloride solution is 1.71 mol/ltr

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In the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

The ideal gas law states that the pressure of ideal gas is directly proportional to the absolute temperature of the gas.

PV = nRT

where;

The temperature of the gas is determined as follows;

\(T = \frac{PV}{nR}\)

Thus, we can conclude that in the ideal gas law, the temperature of the hydrogen gas determined if the volume and pressure of the gas is known.

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The factor that  doesn’t change the resistance of a wire is pressure. option A.

Resistance is a conductor's capacity to thwart the passage of current. It is controlled by the interplay of the applied voltage and the electric current passing through it. The amount of opposition any object applies to the flow of electric current is referred to as resistance.

The ohm, a unit of measurement for resistance, is represented by the Greek letter omega. According to Ohm's law, the voltage across two places is precisely proportional to the current flowing through a conductor between them.

Hence option A is correct.

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missing part;

The pressure

The length of the resistor.

The thickness of the resistor.

The temperature of the conductor.

The evidence in figure 2 and table 1 which describes the changes in the rock after a year is the presence of a round edge.

This is referred to as the breaking down or dissolving of rocks and minerals on Earths surface through elements such as wind, water etc.

In the diagram given, the rock previously had a sharp edge but as time went on there was breakdown of the edges which resulted in it becoming round and is therefore the evidence that weathering most likely occurred in the rock.

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Answer:

Щоб обчислити кількість молей у 4,31 x 10^12 молекулах сахарози C12H22O11, ми можемо використати число Авогадро таким чином:

Кількість молей = кількість молекул / число Авогадро

Кількість молей = 4,31 x 10^12 / 6,022 x 10^23

Кількість молей = 7,17 x 10^-12 молей

Отже, 7,17 x 10^-12 моль сахарози C12H22O11 міститься в 4,31 x 10^12 молекул.

Explanation:

Answer:

To find the empirical formula of the compound, we need to determine the simplest whole-number ratio of atoms in the molecule.

First, we can assume that we have 100 grams of the compound, and calculate the number of moles of each element present in it:

Carbon: 40.8 g / 12.011 g/mol = 3.398 mol

Hydrogen: 5.8 g / 1.008 g/mol = 5.753 mol

Oxygen: 53.4 g / 15.999 g/mol = 3.337 mol

Next, we divide each of these values by the smallest one, which is 3.337, to get the mole ratio:

Carbon: 3.398 mol / 3.337 mol = 1.019

Hydrogen: 5.753 mol / 3.337 mol = 1.723

Oxygen: 3.337 mol / 3.337 mol = 1.000

Rounding these values to the nearest whole number, we get the empirical formula: C1.0H1.7O1.0, which can be simplified to CH1.7O.

To find the molecular formula, we need to know the actual molecular mass of the compound. We can estimate it by adding the atomic masses of the elements in the empirical formula:

Carbon: 1 x 12.011 = 12.011

Hydrogen: 1.7 x 1.008 = 1.714

Oxygen: 1 x 15.999 = 15.999

Total = 29.724 g/mol (approx.)

The molecular mass is close to 180 g/mol, which suggests that the actual molecular formula is a multiple of the empirical formula. Dividing 180 by 29.724, we get a value of about 6.05. Multiplying the subscripts in the empirical formula by this value, we get the molecular formula: C6H10.2O6, which can be further simplified to C3H5.1O3.

The compound with the empirical formula CH1.7O and the molecular formula C3H5.1O3 is commonly known as glyoxylic acid.

part a.)

The initial concentration in solution of the Fe3+ and SCN- is:

moles of Fe3+ = (2.00 x 10^-3 M) x (5.00 x 10^-3 L) = 1.00 x 10^-5 mol

moles of SCN- = (2.00 x 10^-3 M) x (5.00 x 10^-3 L) = 1.00 x 10^-5 mol

part b)

The equilibrium constant for the reaction is 1.54 x 10^10.

Fe(NO3)3(aq) + 3KSCN(aq) ⇌ Fe(SCN)3(aq) + 3KNO3(aq)

b)

Therefore, the equilibrium concentration of Fe(SCN)2+ is also 1.40 x 10^-4 M.

Applying law of mass action, the equilibrium constant expression for the reaction is:

Kc = [Fe(SCN)2+] / ([Fe3+] [SCN-]3)

Kc = (1.40 x 10^-4) / [(1.00 x 10^-5) (1.00 x 10^-5)^3]

Kc = 1.54 x 10^10

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A = 2.86 x \(10^{23\) molecules of  \(KMnO_4\)

B = 323.76 grams of Al

C = 1.53 moles of Au

D = 7.71 x \(10^{23\) molecules of \(H_3PO_4\)

E = 4.52 x \(10^{23\) total atoms

According to Avogadro, a single mole of any substance contains 6.022 x \(10^{23\) molecules or atoms of the substance.

Also, the mole of a substance is the ratio of the mass of the substance and the molar mass of the substance. In other words;

mole = mass/molar mass

These theories are what we need to solve the outlined problems.

       Mole of 75 g of \(KMnO_4\):

       mass/molar mass = 75/158

                                     = 0.4747 mol

        Since 1 mole = 6.022 x \(10^{23\) molecules

         0.4747 mole = 0.4747 x 6.022 x \(10^{23\)

                                = 2.86 x \(10^{23\) molecules

       Since 1 mole =  6.022 x \(10^{23\) molecules or atoms

        7.23 x \(10^{24\) atoms = 7.23 x \(10^{24\) / 6.022 x \(10^{23\)

                                     = 12 moles

        Mass of 12 moles Al = 12 x 26.98

                                          =  323.76 grams    

                                    = 1.53 moles

                                   = 1.28 moles

         1.28 moles = 1.28 x 6.022 x \(10^{23\)

                            = 7.71 x \(10^{23\) molecules

                                        = 4.52 x \(10^{23\) atoms

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Answer:

760 mm of Hg

Explanation:

If the gases A , B and C are non reacting , then according to Dalton's Law of Partial Pressure the total pressure exerted is equal to sum of individual partial pressure of the gases .

If there are n , number of gases then ,

\( P_{total}= P_1+P_2+P_3+\dots +P_n\)

Here ,

Hence the total pressure exerted is ,

\( P_{total}= P_{Gas\ A }+P_{Gas\ B }+P_{Gas\ C }\)

Substitute ,

\(P_{total}=( 400 + 220 + 140 )mm\ of \ Hg \)

Add ,

\(P_{total}= 760\ mm\ of \ Hg\)

Hence the total pressure exerted by the gases is 760 mm of Hg.

I hope this helps.

We know that there are 24 hours in 1 day. We will use that conversion to go from days to hours.

1 day = 24 hours

half life = 8 days = 8 days * 24 hours/(1 day)

half life = 192 hours

Answer: the half-life for I-131 is 192 hours.

Considering the reaction stoichiometry, the total number of moles of NO produced from 0.25 moles of O₂ is 0.2 moles.

The balanced reaction is:

4 NH₃ + 5 O₂ → 4 NO + 6 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

Then you can apply the following rule of three: if by stoichiometry 5 moles of O₂ produce 4 moles of NO, 0.25 moles of O₂ will produce how many moles of NO?

\(amount of moles of NO= \frac{0.25 moles of O_{2} x4 moles of NO}{5 moles of O_{2} }\)

amount of moles of NO= 0.2 moles

Finally, the total number of moles of NO produced from 0.25 moles of O₂ is 0.2 moles.

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Answer:

A its has 63 protons

B mass number is also 124

C Atomic number of x is 63

Explanation:

An operational definition is the statement of procedures the researcher is going to use to measure a specific variable.

Researchers can explain in detail what they mean when they use a phrase by using an operational definition. Operational definitions are typically measurable and concrete. This method of defining variables enables others to assess the validity of the study. Operationalization is the procedure in question.

The variables you'll utilize as indicators and the methods you'll employ to observe or measure them are both included in your operational definitions. No matter how solid your conceptual definition may be, you need an operational definition since without one, you cannot measure anything.

Operational variables, also known as operationalizing definitions, describe how you'll quantify and define a particular variable when it's applied to your research. This makes it possible for a different psychologist to duplicate your findings and is crucial in establishing.

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