How many moles in 2.33E25 molecules of NO?
0.0258 mol
3.87E20 mol
38.7 mol
2.58E48 mol
please show work ​

Answer:

When the Earth rotates on its axis, the Sun moves across the sky, causing objects to cast shadows. So, how does a sundial work? As the Sun changes relative positions in the sky over the day, the position of the shadow cast by the gnomon changes to align with the different times around the outside of the circular plate. This way you can tell the time by looking at where the shadow is cast, using the markings around the edge of the sundial base.

Answer:

The first sundial built by man is an obelisk that was probably invented in ancient Egypt, and it was used starting around 3,500 BC. With the movement of the sun in the sky, the shadow cast by the large cone moves. The path described by the shadow was divided in advance into a fixed scale, which allowed people to more easily notice the passage the time.

Explanation:

The second answer is also correct! Hope I helped and have a good day!

Answer:

hello

Bromate is a bromine oxoanion and a monovalent inorganic anion. It is a conjugate base of a bromic acid.

Explanation:

thanks

The neutralization reaction between pyridine and propanoic acid produces two products, 2-pyridin-3-ylpropanoic acid and ammonium propanoate. The structure of 2-pyridin-3-ylpropanoic acid is shown below:

                                         H

                                         |

                             C-C-C-C-O-C-N-H

                                         |

                                         H

The structure of ammonium propanoate is shown below:

                                         H

                                         |

                             C-C-C-C-O-N-H+

                                         |

                                         H

A Lewis structure, named after Gilbert N. Lewis, is an arrangement of atoms in a molecule or ion that shows the number of electrons that are shared between atoms and is used to explain the bonding and molecular structure of a compound.

In a Lewis structure, the electrons are represented by dots or lines and the atoms are represented by the chemical symbols of each element.

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As a result, the 50 gramme sample's estimated end temperature is around 37.57°C.

The amount of energy in a system that is available to perform beneficial work at a constant temperature is shown by the Helmholtz free energy equation, often known as the thermal equilibrium equation (F = U - TS). The Helmholtz free energy (F), internal energy (U), absolute temperature (T), and entropy are the variables in the Helmholtz equation (S).

Two items are said to have the same temperature when they are in thermal equilibrium. Heat, a kind of energy, is transmitted between the objects as they approach thermal equilibrium.

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Answer:

Explanation:

Here, we want to get the mass of the anhydrous compound in the given hydrate

To get this, we have to divide the molar mass of the hydrate part by the molar mass of the whole hydrate and write it as a percentage

The molar mass of the water part is (5 * 18 g/mol = 90 g/mol: The molar mass of 1 mol of water is 18 g/mol)

The molar mass of CuSO4 is 160 g/mol

The percentage by mass is thus:

Petroleum is a naturally occurring liquid mixture of hydrocarbons, which is usually referred to as crude oil. It is a non-renewable resource that is extracted from the ground by drilling wells.

Petroleum is a complex mixture of various components, and it is refined into different products for use in different industries. There are various products obtained from petroleum. These products include gasoline, diesel fuel, heating oil, jet fuel, kerosene, asphalt, lubricants, and petrochemicals. Each of these products has its own unique properties and uses.

1. Gasoline: Gasoline is the most commonly used petroleum product. It is a liquid fuel that is used in internal combustion engines in cars, trucks, and other vehicles. Gasoline is a mixture of various hydrocarbons that have been refined from crude oil.

2. Diesel Fuel : Diesel fuel is another liquid fuel that is obtained from petroleum. It is used in diesel engines in trucks, buses, and other heavy-duty vehicles. Diesel fuel is made up of hydrocarbons that are heavier than those in gasoline.

3. Heating Oil :Heating oil is a liquid fuel that is used to heat homes and buildings. It is similar to diesel fuel but is refined to have a higher boiling point.

4. Jet Fuel: Jet fuel is a type of kerosene that is used to power jet engines in airplanes. It is refined to have a low freezing point and a high energy content.

5. Kerosene: Kerosene is a liquid fuel that is used for lighting, heating, and cooking. It is similar to jet fuel but is refined to have a higher boiling point.

6. Lubricants: Lubricants are oils that are used to reduce friction between moving parts in engines and machinery. They are made from refined petroleum and can be used in a variety of applications.

7. Petrochemicals: Petrochemicals are chemicals that are derived from petroleum. They are used in a wide range of products, including plastics, synthetic fibers, rubber, and detergents.

Overall, petroleum is an important resource that is used to produce a wide range of products that we use in our daily lives. The products obtained from petroleum have a significant impact on the economy, transportation, and various industries.

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The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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Layer 1 because it is closest to the surface

When an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

During transition from n=2 to n=1 in a hydrogen atom, the electron emits energy in the form of photon. We know that when electron absorb energy, it moves from lower level to higher level and vice versa.

So we can conclude that when an electron moves from n = 2 to n = 1, it emits a photon of ultraviolet light.

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Answer:

i would say 10, so the anser is A.

Explanation:

because there are the same number of protons and electrons, therefore for a regular O, you are supposed to have only 8 protons, but it is charged, thus, whatever the charge is will be taken into consideration into how much the proton and electron doe it have. Thus, for this case, it has 10, because the charge is negative and you have 8 electron plus 2 = 10.

a. Nitrogen number 2 in guanine typically acts as a hydrogen bond acceptor.

b. N2, N2-dimethylguanine (N2-meG) is less favorable in forming base pairs with cytosine than typical guanine-cytosine (G-C) base pairs because the methylation at nitrogen number 2 changes its properties, causing a decrease in the number of hydrogen bonds and stability of the base pair.

The methyl group disrupts the hydrogen bonding potential of nitrogen number 2, reducing the number of hydrogen bonds formed between N2-meG and cytosine. This leads to a decrease in the stability of the N2-meG: cytosine base pair compared to a typical G-C base pair.

Methylation is the addition of a methyl group (-CH3) to a molecule, and is a common pattern of modification in RNA molecules. One specific pattern of methylation is the double methylation of nitrogen number 2 in guanine to form N2, N2-dimethylguanine (N2-meG). In a typical guanine-cytosine (G-C) base pair, nitrogen number 2 acts as a hydrogen bond acceptor, forming two hydrogen bonds with the nitrogen atoms in the cytosine ring.

However, the formation of a base pair between N2-meG and cytosine is less favorable than the typical G-C base pair due to the effect of the added methyl groups. The methyl groups disrupt the hydrogen bonding potential of nitrogen number 2, reducing the number of hydrogen bonds that can be formed between N2-meG and cytosine. As a result, the stability of the N2-meG: cytosine base pair is lower compared to the G-C base pair.

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Answer:

I don’t mnow

Explanation:

Answer:

Anode half reaction;

Co(s) ----> Co^2+(aq) + 2e

Cathode half reaction;

2Ag^+(aq) + 2e-------> 2Ag(s)

Explanation:

A voltaic cell is an electrochemical cell that spontaneously produces electrical energy from chemical reactions. A voltaic cell comprises of an anode (where oxidation occurs) and a cathode (where reduction occurs). The both electrodes are connected with a wire . A salt bridge ensures charge neutrality in the anode and cathode compartments. Electrons flow from anode to cathode.

For the cell referred to in the question;

Anode half reaction;

Co(s) ----> Co^2+(aq) + 2e

Cathode half reaction;

2Ag^+(aq) + 2e-------> 2Ag(s)

Answer: Divergent boundaries are where two of those plates are moving away from each other. They are called constructive plates because when they move apart, magma rises up in the gap- this forms volcanoes and eventually new crust.

Explanation:

Two layers must have been separated in some way if they are not attached.

The two networks are single layer perceptron networks, in other words. A line is produced by each perceptron. We may infer from the fact that only two lines are needed to represent the decision border that there will be two hidden neurons in the first hidden layer. We have one hidden layer and two hidden neurons up until this moment.

These are "hidden" since the training dataset's nodes' actual values aren't known. Indeed, all we know is the input and output. There is at least one hidden layer in every neural network. It is not a neural network if it is not.

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Answer:

Phosphorus(P) and Oxygen(O)=Covalent bond

Chlorine(Cl) and Sodium(Na) = Ionic bond

Silver (Ag) and Silver (Ag)= Metallic bond

The kind of wave that is formed when a transverse wave and a longitudinal wave combine is surface wave.

A surface wave is a mechanical type of wave that propagates along the boundary between two different media.

When a mechanical wave travels at the interface between two media, a transverse wave and a longitudinal wave can combine to form a surface wave.

An example can be seen in ocean waves.

Thus, the kind of wave that is formed when a transverse wave and a longitudinal wave combine is surface wave.

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Answer:

5.81 moles

Explanation:

To find the number of moles (n) in 3.5 x 10²⁴ molecules of methane gas, we divide the number of molecules by Avagadro's number (nA). That is,

n = number of molecules ÷ 6.02 × 10²³

According to this question, 3.5 x 10^24 molecules of methane gas was given, hence,

n = 3.5 × 10²⁴ ÷ 6.02 × 10²³

n = 3.5/6.02 × 10(24 - 23)

n = 0.5814 × 10¹

n = 5.81 moles

Explanation:

it changes colour it gives blue black colour

parts per million (ppm), parts per billion (ppb) and parts per trillion (ppt) are the most commonly used terms to describe very small amounts of substances. a ppm of a chemical in water means that, in a million units of water, there would only be one unit of the chemical.

The mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

The half-life of a radioactive isotope is the amount of time it takes for one-half of the radioactive isotope to decay.

The half-life of a specific radioactive isotope is constant; it is unaffected by conditions and is independent of the initial amount of that isotope.

The number of half lives in 27 days;

n = 27 days/14 days

n = 1.929

The mass of P-32 remaining after 27 days, if the initial mass is 40g;

mass remaining = 40 g / (2^1.929)

mass remaining = 40 g / 3.808

mass remaining = 10.5 g

Thus, the mass of P-32 remaining after 27 days, if the initial mass is 40g is 10.5 g.

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The question is incomplete, the complete question is;

Why was it necessary to make sure that some solid was present in the main solution before taking the samples to measure Ksp? Select the option that best explains why. Choose... A. To make sure no more sodium borate would dissolve in solution. B. To ensure the dissolution process was at equilibrium. C. To make sure the solution was saturated with sodium and borate ions. D. All of the above

Answer:

B. To ensure the dissolution process was at equilibrium.

Explanation:

The solubility product is a term used in chemistry to describe the equilibrium between the dissolved, dissociated and undissolved solute of a relatively low solubility ionic solid.

For an ionic solid MX, the solubility product is given as ;

MX(s) ----> M^n+(aq) + X^n-(aq)

If Ksp indeed scribes an equilibrium process for dissolution, it then implies that some undissolved solute must be present before samples are taken to measure the Ksp of a sample. This ensures equilibrium between dissolved and undissolved solute.

B. To provide the dissolution process was at equilibrium and assure equilibrium between dissolved and then undissolved solute.

The solubility product is a representation accustomed in chemistry to describe the equilibrium between the dissolved, dissociated, and as they are undissolved solutes of a relatively low solubility ionic solid.

For an ionic solid MX, the solubility product is given as;

Then, MX(s) ----> M^n+(aq) + X^n-(aq)

If Ksp scribes an equilibrium process for dissolution, it then means that some undissolved solute must be attending before samples are taken to measure the Ksp of a sample.

This confirms equilibrium between dissolved and also undissolved solute between dissolved and undissolved solute.

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The question is incomplete, the complete question is;

Why was it necessary to make sure that some solid was present in the main solution before taking the samples to measure Ksp? Select the option that best explains why. Choose... A. To make sure no more sodium borate would dissolve in solution. B. To ensure the dissolution process was at equilibrium. C. To make sure the solution was saturated with sodium and borate ions. D. All of the above

There are approximately \(2.76 * 10^{24\) ammonia molecules in the given sample.

To calculate the number of ammonia molecules in the sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia \((NH_3)\) can be calculated by adding up the atomic masses of nitrogen (N) and hydrogen (H):

Molar mass of \(NH_3\) = (1 x atomic mass of N) + (3 x atomic mass of H)

              = (1 x 14.01 g/mol) + (3 x 1.01 g/mol)

              = 14.01 g/mol + 3.03 g/mol

              = 17.04 g/mol

Now, we can calculate the number of moles of ammonia in the sample using the formula:

Number of moles = Mass of the sample / Molar mass

Number of moles = 78.25 g / 17.04 g/mol

              ≈ 4.5865 mol (rounded to four decimal places)

Finally, we can use Avogadro's number, which represents the number of particles (atoms, molecules, etc.) in one mole of a substance. Avogadro's number is approximately \(6.022 * 10^{23\) particles/mol.

Number of ammonia molecules = Number of moles x Avogadro's number

Number of ammonia molecules ≈ 4.5865 mol x (\(6.022 * 10^{23\) molecules/mol)

                           ≈ \(2.76 * 10^{24\) molecules (rounded to two significant figures)

Therefore, the provided sample contains roughly \(2.76 * 10^{24\) ammonia molecules.

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The number of ammonia molecules in the sample is approximately 2.764 x \(10^{24}\) molecules.

To calculate the number of ammonia molecules in a given sample, we need to use Avogadro's number and the molar mass of ammonia.

The molar mass of ammonia (NH3) is calculated as follows:

Molar mass of N = 14.01 g/mol

Molar mass of H = 1.01 g/mol

Total molar mass of NH3 = 14.01 g/mol + (3 * 1.01 g/mol) = 17.03 g/mol

Now, we can calculate the number of moles of ammonia in the sample:

Number of moles = Mass of sample / Molar mass of NH3

Number of moles = 78.25 g / 17.03 g/mol = 4.594 moles

Next, we use Avogadro's number, which states that there are 6.022 x \(10^{23}\) molecules in one mole of a substance.

Number of molecules = Number of moles * Avogadro's number

Number of molecules = 4.594 moles * 6.022 x \(10^{23}\) molecules/mol = 2.764 x \(10^{24}\) molecules

Therefore, there are approximately 2.764 x \(10^{24}\) ammonia molecules in the given sample of 78.25 g.

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The amount of energy that is required to change 20.0 g of an unknown substance from -15.0 °C to 7.0 °C is q = +49.65 kJ.

Energy is the ability to do tasks. It can exist in various forms, including potential, kinetic, thermal, electrical, chemical, and nuclear.

At -15°c, it will be solid, to increase the amount of heat to raise

temp from -15°C to 40°C.

(20.0) (3.3J/g°c) x 15°C) = 330 J.

At -10°C, it is in which phase transformation takes place from sold to wound.

ΔHfue = 0.945 J/gx 20g = 18.93.

After that, it will be in want and it will be in liquid form 40°C.

To 7°C, then.

922 m Cgas 47

=(20g) (1455/g°c) (17)

493005.

Total Energy = q1 + ΔHfus  + q2

47 = 7.0°C - 10°C) = 14°C -

2 330J18.95 + 49300J

q = 49648.9 3. 9

q = +49.65 KJ

Therefore, the amount of energy is q = +49.65 KJ.

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Xeriscaping is a landscaping approach that focuses on conserving water by using drought-tolerant plants and efficient irrigation techniques. The goal is to create a visually appealing and sustainable garden while minimizing water usage.

Successful xeriscaping projects involve several key elements. Firstly, careful plant selection is crucial, opting for species that can thrive in arid conditions without excessive watering. Mulching is used to reduce evaporation and retain soil moisture.

Proper soil preparation, such as improving drainage and adding organic matter, promotes healthier plant growth. Efficient irrigation systems, like drip irrigation or soaker hoses, deliver water directly to plant roots, minimizing wastage.

Additionally, controlling erosion through the use of retaining walls or terracing is important. Lastly, regular maintenance, including appropriate pruning and weed control, ensures the longevity and vitality of the xeriscape garden. Overall, a successful xeriscaping project harmonizes sustainable practices with a beautiful outdoor environment.

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In the balanced equation \(2C_{2} H_{6}\) + \(7 O_{2}\) --> \(4 CO_{2}\) + \(6H_{2}O\) if 21 g of \(C_{2} H_{6}\) reacts with 32 g O₂, C₂H6 is the limiting reactant.

To determine the limiting reactant, we need to compare the amount of each reactant to the stoichiometric ratio in the balanced equation.

Let's calculate the number of moles for each reactant using their molar masses:

For \(C_{2} H_{6}\) (ethane):

Molar mass of \(C_{2} H_{6}\) = 2(12.01 g/mol) + 6(1.01 g/mol) = 30.07 g/mol

Number of moles of C₂H6 = 21 g / 30.07 g/mol ≈ 0.698 mol

For O₂ (oxygen):

Molar mass of O₂ = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O₂ = 32 g / 32.00 g/mol = 1.00 mol

Next, we compare the moles of each reactant to the stoichiometric ratio in the balanced equation:

2 moles of \(C_{2} H_{6}\) react with 7 moles of O₂ to produce 4 moles of CO₂ and 6 moles of H₂O.

From the given amounts, we have:

0.698 mol \(C_{2} H_{6}\) and 1.00 mol O₂.

Using the stoichiometric ratio, we can calculate the expected amount of CO₂ and H₂O produced for each reactant:

For C₂H6:

Expected moles of CO₂ = 0.698 mol C₂H6 * (4 mol CO₂ / 2 mol C₂H6) = 1.396 mol CO₂

For O₂:

Expected moles of CO₂ = 1.00 mol O₂ * (4 mol CO₂ / 7 mol O₂) ≈ 0.571 mol CO₂

Comparing the expected moles, we see that the calculated amount of CO₂ is greater when used \(C_{2} H_{6}\) as the limiting reactant. Therefore, the limiting reactant in this reaction is \(C_{2} H_{6}\).

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The molecules of Li₂O that would produce if you used up 6 atoms of Li(s) is 3.

It is an unstable inorganic and radical compound, used in the manufacture of glass and ceramic.

The balanced equation

\(\rm 6 Li(s) + O_2(g) \rightarrow 3 Li_2O(s)\)

If the atoms of lithium moves up to 6 the lithium oxide molecules will be 3, as you can see in the equation.

Thus, the molecules of Li will be 3.

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Answer:

The answer is

Explanation:

HCL is a strong acid and therefore undergo complete dissociation

We have

The concentration of Hydrogen ion is also 0.415 M

The pH of a solution can be found by using the formula

\(pH = - log( {H }^{ + } ) \)

So we have

\(pH = - log(0.415) \\ = 0.381951903...\)

We have the final answer as

Hope this helps you

The mass of the solid aluminum that forms are 192.73 grams

To determine the mass of solid aluminum that forms, we need to use stoichiometry and the balanced chemical equation for the reaction between magnesium and aluminum nitrate.

The balanced chemical equation is:

3 Mg + 2 Al(\(NO_{3}\))3 → 3 Mg(\(NO_{3}\))2 + 2 Al

The equation shows that 3 moles of magnesium react with 2 moles of aluminum to produce 2 moles of aluminum nitrate.

To calculate the mass of solid aluminum, we need to know the amount of magnesium used. Given that the volume of the magnesium is 150.0 mL and its density is 1.738 g/cm³, we can calculate the mass of magnesium using the formula:

Mass = Volume × Density

Mass of magnesium = 150.0 mL × 1.738 g/cm³ = 260.7 g

Now, using the molar mass of magnesium (24.31 g/mol) and the molar ratio from the balanced equation, we can determine the moles of magnesium used:

Moles of magnesium = Mass of magnesium / Molar mass of magnesium

= 260.7 g / 24.31 g/mol

= 10.72 mol

According to the stoichiometry of the balanced equation, the ratio of moles of magnesium to moles of aluminum is 3:2. Therefore, the moles of aluminum formed will be:

Moles of aluminum = (2/3) × Moles of magnesium

= (2/3) × 10.72 mol

= 7.15 mol

Finally, we can calculate the mass of solid aluminum using its molar mass (26.98 g/mol):

Mass of aluminum = Moles of aluminum × Molar mass of aluminum

= 7.15 mol × 26.98 g/mol

= 192.73 g

Therefore, the mass of the solid aluminum that forms is approximately 192.73 grams.

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