The amounts of people in attendance are given as follows:
Children: 190.Parents: 140.Grandparents: 70.How to obtain the amounts?The amounts are obtained by a system of equations, for which the variables are given as follows:
Variable x: amount of children.Variable y: amount of parents.Variable z: amount of grandparents.There were 400 people total, hence:
x + y + z = 400.
There were twice as many parents as grandparents, hence:
y = 2z.
50 more children than parents, hence:
x = y + 50
x = 2z + 50.
Replacing on the first equation, the value of z is obtained as follows:
2z + 50 + 2z + z = 400
5z = 350
z = 70.
Then the values of x and y are given as follows:
x = 2z + 50 = 190.y = 2z = 140.More can be learned about a system of equations at https://brainly.com/question/13729904
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Find the tangents of the acute angles in the right triangle. Write each answer as a fraction in simplest form and as a decimal rounded to four places.
The tangents of triangle DEF are Tan D = 0.28 and Tan F = 0.96
The tangents of triangle JLK are Tan J = 0.8574 and Tan K = 0.5388
Tangents of the acute angles:In a right-angled triangle, the tangent of one of the non-right angles is defined as the ratio of the length of the opposite side to the length of the adjacent side.
Tan(θ) = opposite/adjacentwhere θ is the angle between the hypotenuse and the adjacent side.
Here we have
Two right-angled triangles
From triangle DEF,
DE = 24, EF = 7 about FD = 25
From triangle JLK,
JL = 3, LK = 5, JK = √34
Using the formula, Tan(θ) = opposite/adjacent
From triangle DEF,
Tan D = EF/DF = 7/25 = 0.28
Tan F = DE/DF = 24/25 = 0.96
From triangle JLK,
Tan J = LK/JK = 5/√34 = 0.8574
Tan K = JL/JK = 3/√34 = 0.5388
Therefore,
The tangents of triangle DEF are Tan D = 0.28 and Tan F = 0.96
The tangents of triangle JLK are Tan J = 0.8574 and Tan K = 0.5388
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The triangles are given in picture
Help me please this is math
Answer:
c) none of the above
Step-by-step explanation:
this is because we should put the equation like:
1/3 - (-4/3) because the distance is 5 units and
1/3 + 4/3 = 5/3
this is because (-) × (-) = (+)
1. A car dealership marks up their cars 7% in order to make a profit. Find the selling price
2. Josie is fundraising for her soccer team; she buys candy bars for $0.75 each and marks
them up 80%. What is the selling price of each candy bar?
Answer:
1) selling price is 1.07 multiplied by whatever they paid for the car
2) selling price is $1.35
Step-by-step explanation:
2) to get 80% markup on 0.75 you can multiply 0.75 x 1.8
Joe asked the children in his class which flavours of ice-cream they like.
He recorded the results in a Venn diagram.
How many children like chocolate ice-cream?
Answer:
a. 19
b. 14
Step-by-step explanation:
From the venn diagram, we see that:
9 children like only Vanilla
7 like vanilla and chocolate
12 like only chocolate, and
2 like neither chocolate nor vanilla
Thus:
a. Number of children that liked Chocolate ice-cream = those that like chocolate only + those that like both chocolate and vanilla = 12 + 7 = 19
19 children like chocolate ice-cream.
b. Number of children who do not like Vanilla ice-cream = those that like chocolate only + those that do not like neither chocolate nor vanilla = 12 + 2 = 14
14 children do not like vanilla ice-cream.
Whitney has £12 pocket money.
She spends 50% of her pocket money on
magazines.
She spends 33% of her pocket money on apps.
How much pocket money does she have left?
Show the steps in your working.
answer
£2
explanation
12÷50%=6
12÷33%=4
6+4=10
12-10=2
Answer:
2.04 pounds left.
Step-by-step explanation:
Whitney has 12 pounds pocket money
She spends 50% of it on magazines
50% of 12 pounds is 50/100 * 12 = 600/100 = 6 pounds
33% of 12 pounds is 33/100 * 12 = 395/100 3.96 pounds
Total Spent 9.96 pounds
Amount left = 12 - 9.96 = 2.04
She has 2.04 pounds left.
A man's gross income is R500 000. He worked at different places throughout the year
and a total of 17% of his earnings was deducted by his employers as PAYE throughout
the tax year. He qualifies for a rebate of R13 257. Calculate how much tax he still
owes. Information taken from the tax table shows that, for a taxable income between
R393 201 and R550 100, R93 135 + 36% above R393 200 needs to be paid.
O R101 678
O R71 774
O R33 326
O R25 191
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Previou
Next >
The man still owes R87,726 in taxes.
To calculate the tax amount the man still owes, we need to determine his taxable income first.
Gross income: R500,000
Less: PAYE deductions (17% of gross income): R500,000 * 0.17 = R85,000
Taxable income: R500,000 - R85,000 = R415,000
Next, we can use the tax table information provided to calculate the tax owed based on the taxable income.
Tax owed: R93,135 + 36% of (taxable income - R393,200)
Tax owed: R93,135 + 0.36 * (R415,000 - R393,200)
Tax owed: R93,135 + 0.36 * R21,800
Tax owed: R93,135 + R7,848
Tax owed: R100,983
Finally, we subtract the rebate amount of R13,257 from the tax owed to find the amount the man still owes.
Tax owed - Rebate: R100,983 - R13,257 = R87,726
Therefore, the man still owes R87,726 in taxes.
The correct option is not provided among the given answer choices.
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Which equation and solution represents the statement shown?
A number x increased by 4 is equal to 6.5.
Answer:
I believe the answer is
x + 4 = 6.5
-4 -4
__________
x = 2.5
Step-by-step explanation:
hope this helps!
What is cos(tan^-1(-2/3))=
cos(tan^(-1)(-2/3)) simplifies to 3√13 / 13.
To evaluate the expression cos(tan^(-1)(-2/3)), we can use the trigonometric identity:
cos(tan^(-1)(x)) = 1 / √(1 + x^2)
In this case, x is -2/3. Substituting the value into the identity:
cos(tan^(-1)(-2/3)) = 1 / √(1 + (-2/3)^2)
Now, let's calculate the value:
cos(tan^(-1)(-2/3)) = 1 / √(1 + 4/9)
= 1 / √(13/9)
= 1 / (√13/3)
= 3 / √13
= 3√13 / 13
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Identify whether or not the relation is a function a yes b no
And how does it change
Answer:
Not a function
Step-by-step explanation:
This is not a function. It will fail the vertical line test. For any value of x, there are two different y values. This tells us that it is not a function
what is the number 5 2/7 written as a improper fraction
Answer:
the answer is 37/7
Step-by-step explanation:
u multiply the 5 and the seven and add the 2 and u get 37/7 so u keep the denominator the same
A company receives shipments from two factories. Depending on the size of the order, a shipment can be in 1 box for a small order, 2 boxes for a medium order, 3 boxes for a large order. The company has two different suppliers. Factory Q is 60 miles from the company. Factory R is 180 miles from the company. An experiment consists of monitoring a shipment and observing B, the number of boxes, and M, the number of miles the shipment travels. The following probabity model describes the experiment:
Factory Q Factory R
small order 0.3 0.2
medium order 0.1 0.2
large order 0.1 0.1
a. Find PB M(b, m), the joint PMF of the number of boxes and the distance.
b. What is E[B], the expected number of boxes?
c. Are B and M independent?
Answer:
A) PB M(b, m), we have;
b = 1
b = 2
b = 3
B) E(B) = 1.7
C) No they are not independent
Step-by-step explanation:
A) We are told that a shipment can be in 1 box for a small order, 2 boxes for a medium order, 3 boxes for a large order. Thus;
For PB M(b, m), we have;
b = 1
b = 2
b = 3
B) Factory Q is 60 miles from the company. Thus, under factory Q in the table, m = 60
Factory R is 180 miles from the company. Thus under factory R in the table, m = 180
Now;
P_B (b) for b = 1 which is small order is;
P_B (b) = 0.3 + 0.2 = 0.5
P_B (b) for b = 2 which is medium order is;
P_B (b) = 0.1 + 0.2 = 0.3
P_B (b) for b = 3 which is large order is;
P_B (b) = 0.1 + 0.1 = 0.2
Thus;
E(B) = Σb•P_B (b) = (1 × 0.5) + (2 × 0.3) + (3 × 0.2)
E(B) = 0.5 + 0.6 + 0.6
E(B) = 1.7
C) No, they are not independent. This is because from the table we are given, P_B,M at b = 1 and m = 60 is given as 0.3.
Whereas, for B and M to be independent, P_B,M at b = 1 and m = 60 has to be equal to (P_M(m) under m = 0.3) multiplied by P_B(b) for b = 1.
Instead what we have is P_M(m) under m = 0.3 as; 0.3 + 0.1 + 0.1 = 0.5. Which means (P_M(m) under m = 0.3) multiplied by P_B(b) for b = 1 gives;
0.5 × 0.5 = 0.25 which is not equal to P_B,M = 0.3 at b = 1 and m = 60
Help meeeeeeeeeeeeeeee
Answer:
75
Step-by-step explanation:
f(4) means to use 4 in place of x.
f(x) = 3(5)^(x-2)
fill in 4 for
f(4) = 3(5)^(4-2)
do the 4-2 subtraction first
f(4) = 3(5)^2
do the 5 to the 2nd power next.
f(4) = 3(25)
last, multiply.
f(4) = 75
This is just following the typical order of operations.
What reason can be used to complete this proof?
m∠1=m∠3 because ∠1≅∠3.
m∠1+m∠2=m∠CXB and m∠2+m∠3=m∠AXD _________.
m∠1+m∠2=m∠AXD because you can substitute m∠1 for m∠3.
m∠CXB=m∠AXD by the transitive property of equality.
So, ∠AXD≅∠CXB.
Answer:
Option (2)
Step-by-step explanation:
Given:
∠1 ≅ ∠3
To Prove:
∠AXD ≅ ∠CXB
Solution:
Given question is incomplete; find the complete question in the attachment.
Statements Reasons
1). m∠1 ≅ m∠3 because m∠1 ≅ m∠3 1). Given
2). m∠1 + m∠2 = m∠CXB and
m∠2 + m∠3 = m∠AXD 2). Angle addition postulate
3). m∠1 + m∠2 = m∠AXD 3). Because you can substitute
m∠1 for m∠3
4). m∠CXB = m∠AXD 4).Transitive property of equality
5). ∠AXD ≅ ∠CXB
Therefore, Option (2) will be the correct option.
I'll MARK THE BRAINLIEST!
The line plots show the results of a survey of 10 boys and 10 girls about how many hours they spent reading for pleasure the previous week. A) Which statement is true about the range? B) Which statement is true about the mean?
A} The range is greater for the girls, B) The mean is less for the girls
B} The range is greater for the girls, B) The mean is greater for the girls
C} The range is greater for the boys, B) The mean is greater for the girls
D}The range is greater for the boys, B) The mean is greater for the boys
The range is greater for the girls and the mean is greater for the girls. So, correct option is B.
A) The statement "The range is greater for the girls" is true. The range is the difference between the highest and the lowest values in a data set.
Looking at the line plots, the highest value for the boys is 10, and the lowest is 3, giving a range of 7 hours. The highest value for the girls is 9, and the lowest is 5, giving a range of 4 hours. Therefore, the range is greater for the boys.
B) The mean is the sum of all values divided by the total number of values. To calculate the mean for the boys, we add up all the hours and divide by 10, which gives us:
(3 + 6 + 7 + 7 + 8 + 8 + 8 + 8 + 9 + 10) / 10 = 7.4 hours
To calculate the mean for the girls, we add up all the hours and divide by 10, which gives us:
(5 + 6 + 6 + 6 + 7 + 7 + 7 + 8 + 8 + 9) / 10 = 7.1 hours
Therefore, the mean for the boys is 7.4 hours and the mean for the girls is 7.1 hours, so the statement "The mean is greater for the girls".
So, correct option is B.
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In the figure below, a radius and tangent line are drawn in black. The radius has alength of 8, and the tangent line bycontains a segment of length 5, as shown.Find the length of C.
Given the figure, we can deduce the following information:
radius= 8
tangent line =5
To determine the length of C, we first redraw the figure as shown below:
Next, we use Pythagorean theorem:
\(c^2=a^2+b^2\)where:
a=5
b=8
c=C
Then, we plug in what we know:
\(\begin{gathered} c^{2}=a^{2}+b^{2} \\ C^2=5^2+8^2 \\ Simplify \\ C^2=89 \\ C=\sqrt{89} \end{gathered}\)Therefore, the answer is:
\(\sqrt{89}\)Find the radius. Round to the nearest tenth.
A cone has the volume
of 538.25 cm3 and a height
of 17 cm. What is the
radius?
r=?
h=17cm
Answer:
Step-by-step explanation:
V = 1/3 * pi * r^2 * h
r = ?
pi = 3.14
h = 17 cm
3*V = pi * r^2 h = r^2 Divide by pi
3*V/pi = r^2 h = r^2 Divide by h
3*V/(pi*h) =r^2 Take the square root of the left to get just r
sqrt(3*V/(pi*h)) = r Now solve the equation.
sqrt(3*538.25 /(3.14*17)) = r
sqrt(1614 / 53.38) =
r = sqrt(30.24)
r = 5.493
60 POINT QUESTION. Middle school math, ordered pairs.
Answer:
(0,2)
(3,0)
Step-by-step explanation:
which expressions are equivalent to 3^4/9/3^2/9? select all that apply
Answer:
first and third expressions
Step-by-step explanation:
using the rule of exponents
\(\frac{a^{m} }{a^{n} }\) = \(a^{m-n}\)
then
\(\frac{3^{\frac{4}{9} } }{3^{\frac{2}{9} } }\)
= \(3^{\frac{4}{9}-\frac{2}{9} }\) ← first expression
= \(3^{\frac{2}{9} }\) ← third expression
Kirsten got paid $432.50 for her work this month. She worked for 35 hours but broke a coffee mug so had to take $5 out of her pay. Write an equation, define your variable and solve. How much does she make an hour?
Answer:
Kirsten makes $12.50 per hour
Step-by-step explanation:
The total is $432.50
$5 is taken out of her paycheck, so that will be negative.
35 hours is the time she spent working.
The unknown variable we are looking for is the amount she makes in one hour.
Setting up the equation, we get:
$432.50 = $35x - $5
where x is the amount she makes every hour
Solve for x:
$437.50=$35x
$437.50 / $35 = x
Therefore, x = $12.50
Write the fraction as a mixed number 10/20
Brandon enters bike races. He bikes 91 half miles every1 half hour. Complete the table to find how far Brandon bikes for each time interval.
Help,
Using proportions, it is found that he bikes:
19 miles in one hour.28.5 miles in one and a hour.38 miles in two hours.47.5 miles in two and a hours.What is a proportion?A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.
In this problem, the proportion is that he bikes 9.5 miles each half hour, hence:
In one hour, he bikes 2 x 9.5 = 19 miles.In one and a half hour, he bikes 3 x 9.5 = 28.5 miles.In two hours, 4 x 9.5 = 38 miles.In two and a half hours, he bikes 5 x 9.5 = 47.5 miles.More can be learned about proportions at https://brainly.com/question/24372153
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f(x) = 6^2+12x -7
please answer and explainnnn!
Answer:
A) \(x=-1\pm\sqrt{\frac{13}{6}}\)
Step-by-step explanation:
\(\displaystyle x=\frac{-12\pm\sqrt{12^2-4(6)(-7)}}{2(6)}\\\\x=\frac{-12\pm\sqrt{144+168}}{12}\\\\x=\frac{-12\pm\sqrt{312}}{12}\\\\x=\frac{-12\pm2\sqrt{78}}{12}\\\\x=-1\pm\frac{\sqrt{78}}{6}\\\\x=-1\pm\sqrt{\frac{78}{36}}\\\\x=-1\pm\sqrt{\frac{13}{6}}\)
Evaluate the expression when c=-3 and x=3 and x-2c
⇒Plug in places the given values in the expression x-2c and simplify
given that x=3 and c =-3
⇒\(=(3)-2(-3)\\=3+6\\=9\)
The expression evaluated at the given variables is equal to 9.
3m +6 - 8m + 9 = -20
Answer:
m=7
Step-by-step explanation:
Answer:
m=7
-8m+3m=-6-9-20
-5m=-35
-35/-5=7
m=7
HELP WILL GIVE BRAINLIEST
find the flux through the boundary of the rectangle for fluid flowing along the vector field .
For fluid moving in a vector field, the flux through the rectangle's perimeter is 750.52.
Flux = ∫ F. X ds
Flux = ∫∫ delta. F da (by divergence theorem)
delta. F = d/dx(x³+4) + d/dy(ycos(3x))
= 3x² + cos(3x)
So flux = ∫∫ 3x² + cos(3x) dy dx
= ∫ (3x² + cos(3x)) (y)⁶₀ dx
= 6 ∫ 3x² + cos(3x) dx
After evaluating,
= 6(125 + sin(15)/3)
= 750.52
Therefore, the flux through the boundary of the rectangle for fluid flowing along the vector field is 750.52
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please help me and please hurry!! the directions are on the image. also please show working clearly.
The corresponding areas under the curves for y = 2x-x² in the interval [1, 2] and y = x³-6x²+8x in the interval [0, 4] are 2/3 unit² and 0 unit²
How to find the area under the curve?Given:
1. y = 2x-x² in the interval [1, 2]
2. y = x³-6x²+8x in the interval [0, 4]
In order to find the area under the curve for these functions for the given intervals, we will take the integral of the functions and use the intervals as upper and lower limits: Thus:
y = 2x-x² in the interval [1, 2] will be:
\(\int\limits^2_1 {2x-x^{2} } \, dx = \left[\frac{ 2x^2}{2}-\frac{ x^3}{3}\right]_1^2\)
\(= \left[x^{2} -\frac{ x^3}{3}\right]_1^2\)
Substitute the value of the upper and lower limits into x:
= [2²- 2³/3] - [1²- 1³/3]
= [4 - 8/3] - [ 1 - 1/3]
= [4/3] - [2/3]
= 2/3 unit²
y = x³-6x²+8x in the interval [0, 4] will be:
\(\int\limits^4_0 {x^{3} -6x^{2} + 8x } \, dx = \left[\frac{ x^4}{4}-\frac{ 6x^3}{3}+\frac{ 8x^2}{2}\right]_0^4\)
\(= \left[\frac{ x^4}{4}- 2x^3+4x^2\right]_0^4\)
= [4⁴/4 - 2(4)³ + 4(4)²] - [0⁴/4 - 2(0)³ + 4(0)²]
= [ 64 - 128 + 64] - [0 - 0 -0]
= 0 unit²
Therefore, the areas under the curves y = 2x-x² in the interval [1, 2]
and y = x³-6x²+8x in the interval [0, 4] are 2/3 unit² and 0 unit² respectively
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In a frequency distribution of 290 scores, the mean is 99 and the median is 86. One would expect this distribution to be:
Answer:
positively skewed to the right
Step-by-step explanation:
The measure of the central tendency is a profound way to describe the mean, median and mode. The measure of central tendency indicates where the center of distribution tends to be. The measure of central tendency provide a validity and answers whether the scores are high or generally low.
In this measure,The mean is usually pulled to the tail. The skewed is determined by where the tail goes, to the right side , it is positively skewed and to the left side , it is known as negatively skewed distribution.
Given that:
In a frequency of distribution of 290 scores,
the mean = 99
the median = 86
One would expect this distribution to be; positively skewed to the right since the mean value is greater than the median value.
a convex mirror, like the passenger-side rearview mirror on a car, has a focal length of -2.8 m. an object is 5.6 m from the mirror.
The image's distance from the mirror is -1.87, by using the mirror equation.
Note:- Although the question is missing, I believe the issue is asking where the image is located.
To find the solution to the problem, the mirror equation can be used:
Mirror equation = \(\frac{1}{f}+\frac{1}{d_{o} }+\frac{1}{d_{i} }\)
Where,
f = mirror's focal length
\(d_{o}\) = object's distance from the mirror
\(d_{i}\) = image's distance from the mirror
The focal length is assumed to be negative for a convex mirror in our problem.
f = -2.8 m
The object's distance (do) = 5.6m
By using the mirror equation, the image's distance from the mirror can be determined
\(\frac{1}{f}+\frac{1}{d_{o} }+\frac{1}{d_{i} }\)
i.e, \(\frac{1}{d_{i} } = \frac{1}{f} -\frac{1}{d_{o} }\)
= \(-\frac{1}{2.8} -\frac{1}{5.6}\) = \(-\frac{3}{5.6}\)
= - 0.5357
\(d_{i} =\) \(-\frac{5.6}{3}\)
= -1.87 m
The virtual nature of the image is indicated by the negative sign (located behind the mirror)
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A state university is interested in where its students come from. They survey 300 of its students to find out if they are in-state, out-of-state, or foreign students. Match the vocabulary word with its corresponding example.
In-state corresponds to students who are residents of the same state as the university, out-of-state corresponds to students from different states, and foreign corresponds to students from countries other than the university's country.
To match the vocabulary word with its corresponding example in the context of the state university survey, we need to understand the terms and their meanings.
Here are the vocabulary words and their corresponding examples:
Vocabulary Word: In-state
Example: A student who is a resident of the same state where the university is located.
They pay lower tuition fees compared to out-of-state or foreign students.
Vocabulary Word: Out-of-state
Example: A student who is not a resident of the state where the university is located.
They typically pay higher tuition fees compared to in-state students.
Vocabulary Word: Foreign
Example: A student who is from a country other than the country where the university is located.
They are international students who may have different visa requirements and tuition fees.
To match these vocabulary words with their corresponding examples:
In-state: A student from the same state as the university, paying lower tuition fees.
Out-of-state: A student from a different state than the university, paying higher tuition fees.
Foreign: A student from a country other than the country where the university is located, with potential differences in visa requirements and tuition fees.
By associating each vocabulary word with its respective example, we can accurately describe the three categories of students based on their residency and origin in the context of the state university's survey.
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